For a theoretical yield of 20 g and actual yield of 12 g, calculate the percent yield for a chemical reaction. Answer in units of %.

Please and Thank you!

Answer:

Afom of noble gases can exists independently and form monoatomic molecules like helium neon argon etc so these are monoatomic molecules not compound

Explanation:

Answer:

b or c but I would just pick c

Answer:

C

Explanation:

Sun is an energy source not a matter.

The precipitation of an ionic substance from solution occurs when the ionic product exceeds the value of its solubility product at that temperature. Here the moles of Na₂S₂O₃ needed is

The solubility product of a sparingly soluble salt is defined as the product of the molar concentrations of its ions in a saturated solution of it at a given temperature.

Here the concentration of Ag⁺ ions = √Ksp = √3.3 × 10⁻¹³ = 1.81 × 10⁻¹³.

Moles of Ag⁺ ions: (1.82 x 10⁻¹³ M) x 1.0 L = 1.82 x 10⁻¹³  mol Ag⁺

Use the stoichiometry of the reaction to find the moles of Na₂S₂O₃ needed: 1 mol Na₂S₂O₃ / 2 mol Ag⁺ = 0.5 mol Na₂S₂O₃/mol Ag⁺

Moles of Na₂S₂O₃ required: 0.5 mol Na₂S₂O₃/mol Ag⁺ x 1.82 x 10⁻¹³ mol Ag⁺ = 9.1 x 10⁻¹⁴ mol Na₂S₂O₃

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a) Calculate the density of the block.

The density of any substance is defined as the mass divided the volume.

Density of the block = mass of the block/volume of the block.

We are given the mass of the block.

mass of the block = 5.60 kg

Since the it is an iron cube, we can find its volume.

Side = 20 cm = 0.20 m

Volume of the block = (side)³

Volume of the block = (20 cm)³ = (0.20 m)³

Volume of the block = 8000 cm³ = 0.008 m³

Now that we know the mass and the volume we can find the density of the block.

Density of the block = Mass of the block / Volume of the block

Density of the block = 5.60 kg / 8000 cm³

Density of the block = 0.0007 kg/cm³

Density of the block = 5.60 kg / 0.008 m³

Density of the block = 700 kg/m³

Answer: The density of the block is 0.0007 kg/cm³ or 700 kg/m³

b) Calculate the mass of water displaced:

If we consider that the cube is completely submerged (as the problem says) it will displace some water. How much water does it displace? Archimedes' says: "The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid". That means that the block completely submerged in water (fluid) will displace its volume of water.

volume of water displaced = volume of the block

volume of water displaced = 8000 cm³ = 0.008 m³

Now that we know the volume of water displaced, and since we are given the density of water, we can find the mass of water displaced.

Density of water = mass of water / volume of water

mass of water = volume of water * density of water

mass of water = 0.008 m³ * 1000 kg/m³

mass of water displaced = 8.0 kg

Answer: Supposing that the block is completely submerged it displaces 8.0 kg of water.

Answer:

3Ca(OH)2 + 2C6H8O7 → 6H2O + Ca3(C6H5O7)2

And 0.119M is the concentration of the citric acid.

Explanation:

In an acid-base reaction, the proton H+ and the hydroxil ion OH- reacts producing water. The ions of the acid and base (C6H5O7³⁻ and Ca²⁺ ions produce the respective salt) as follows:

Ca(OH)2 + C6H8O7 → H2O + Ca3(C6H5O7)2

To balance the Calcium ions:

3Ca(OH)2 + C6H8O7 → H2O + Ca3(C6H5O7)2

To balance the C6H5O7³⁻ ions:

3Ca(OH)2 + 2C6H8O7 → H2O + Ca3(C6H5O7)2

And to balance the oxygens of water:

3Ca(OH)2 + 2C6H8O7 → 6H2O + Ca3(C6H5O7)2

And this is the balanced reaction.

The moles of Ca(OH)2 that reacts are:

41.27mL = 0.04127L * (0.108mol/L) = 0.004457 moles Ca(OH)2

Moles of citric acid:

0.004457 moles Ca(OH)2 * (2mol C6H8O7 / 3mol Ca(OH)2) = 0.002971 moles C6H8O7

In 25.00mL = 0.02500L:

0.002971 moles C6H8O7 / 0.0250L =

Answer:

Explanation:

When an electron moves from a higher enrgy level to a lowerenergy level , energy is relesed (often as a light). In this process (emission) the energy of an electron decreases.

Answer:

0.856

Explanation:

Given data:

Feed molar rate ( Fao ) = 10 mol/min

Feed concentration ( Cao ) = 0.4 mol/dm^3

current conversion rate = 80%  

Temperature = 305 K

catalyst = 100 kg

entering pressure = 20 atm

exit pressure = 2 atm

Determine the conversion if the catalyst particle size were doubled and everything else remained the same

The conversion if the catalyst particle size were doubled and other factors remains the same = 0.856

attached below is a detailed solution

Answer:

It's visualization.

Explanation:

Hope this helps :)

We can use the formula:

Q = mcΔT

where Q is the heat absorbed or released, m is the mass, c is the specific heat, and ΔT is the change in temperature.

First, let's calculate the heat absorbed by the crown:

Q1 = mcΔT

Q1 = (1130 g)(0.129 J/g C)(98.8 C - 25.83 C)

Q1 = 107,776.6 J

Next, let's calculate the heat released by the crown into the water:

Q2 = mcΔT

Q2 = (m)(c)(ΔT)

Q2 = (1340 g)(4.184 J/g C)(27.84 C - 25.83 C)

Q2 = 11096.64 J

Since Q1 = -Q2 (heat lost by the crown is equal to heat gained by the water),

mcΔT = -mcΔT

We can then solve for the specific heat of the crown:

c = -(Q2/mΔT)

c = -(11096.64 J)/(1130 g)(27.84 C - 25.83 C)

c = 0.131 J/g C

The specific heat of pure gold is 0.129 J/g C, and the specific heat of the crown is 0.131 J/g C. Since the specific heat of the crown is slightly higher than that of pure gold, it is possible that the crown is not pure gold. However, other factors such as impurities or alloying metals can also affect the specific heat, so further analysis would be necessary to confirm if the crown is pure gold.

Answer:

6.67* 1011 Hz

Explanation:

a p e x

Answer:

Awnser above is correct

Explanation:

a. 6.67

If the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77 and the solution is basic.

To calculate the pOH of a solution, we can use the formula:

pOH = -log[OH-]

Given that the [OH-] concentration is 5.9 x 10^(-M), we can substitute this value into the formula:

pOH = -log(5.9 x 10^(-M))

Calculating this expression, we find:

pOH = -log(5.9 x 10^(-M))

pOH ≈ -log(5.9) + (-log(10^(-M)))

Since log(10^(-M)) is equal to -M, the equation simplifies to:

pOH ≈ -log(5.9) - M

Now, we need the value of M (the exponent) to calculate the exact pOH value. It appears that the value of M is missing in the given information. However, assuming M is a positive value, we can continue the calculation.

If we consider M = 6, for instance, the equation becomes:

pOH ≈ -log(5.9) - 6

Now, we can evaluate the expression:

pOH ≈ 1.23 - 6

pOH ≈ -4.77

Therefore, if the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77.

To determine whether the solution is acidic, basic, or neutral, we can use the relationship between pH and pOH. The sum of the pH and pOH of a solution at 25°C is always equal to 14.

Since pOH = -4.77, the pH would be:

pH = 14 - pOH

pH ≈ 14 - (-4.77)

pH ≈ 18.77

A solution with a pH above 7 is considered basic. In this case, the calculated pH is greater than 7. Therefore, the solution is basic.

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Answer:The amount of product will be higher than the amount of substrate at equilibrium

Explanation:

Recall that the equilibrium constant K depends on the amounts of reactants and products present in the system at equilibrium.

Considering the equation; K = [X]/[Y], as the concentration of X increases above that of Y, the equilibrium constant K becomes very high, hence the answer above.

In the acid-base titration of 50.00 g of NaOH with excess hydrochloric acid, 73.05 g of NaCl are formed.

Titration is a process of chemical analysis in which the quantity of some constituent of a sample is determined by adding to the measured sample an exactly known quantity of another substance with which the desired constituent reacts in a definite, known proportion.

NaOH + HCl ⇒ NaCl + H₂O

According to the balanced equation, the mass ratio of NaOH to NaCl is 40.00:58.44.

50.00 g NaOH × 58.44 g NaCl/40.00 g NaOH = 73.05 g NaCl

In the acid-base titration of 50.00 g of NaOH with excess hydrochloric acid, 73.05 g of NaCl are formed.

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The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. The definition of the standard atmosphere is 101,325 Pa, or the same as 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

If the air pressure at sea level is 1,014 mbar, what would you expect would happen to the air pressure in a hole that is dug 1,000 feet below ground?

"451.5415 psi"

14.7 psi + 1000*(0.445 psi) = 451.5415 psi

As we descend in the atmosphere, there is a greater mass of atmosphere above us, hence it is predicted that the pressure will rise.

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The standard enthalpy change for the reaction 2A+B⇌2C+2D is  664 kJ/mol and The heat that is absorbed when 3.70 mol of A reacts is 2456.8  J

The heat changes that take place as reactants combine to generate a product are measured by the enthalpy of a reaction.

The following formula can be used to determine the enthalpy change of a reaction:

Hess's law states that

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Considering the given reaction: 2A + B ⇌ 2C + 2D  

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Enthalpy of reaction (ΔH°f) = (2 C + 2 D) - (2 * A + B)

Enthalpy of reaction  (ΔH°f)  = {[2(223) + 2(-523)] - [2(-245) + 2(-387)]}

Enthalpy of reaction  (ΔH°f)  = 664 kJ/mol

ΔH = q ÷ n

ΔH = molar enthalpy (heat) of solution

q = amount of energy (heat) released or absorbed

n = moles of solute

so. q = ΔH xn

q = ΔH xn

q = 664 kJ/mol x 3.70 mol

Q= 2456.8  J

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Kb for trimethylamine is 1.0 × 10^-2.5.

We can use the relationship between Kb and Ka for a conjugate acid-base pair:

Kb × Ka = Kw

The pKa is related to the pH :

pKa + pKb = 14.00

pKb = 14.00 - pKa

We can calculate the pKa using the relationship:

pH = pKa + log([base]/[acid])

Therefore, [base] = [acid], and we can simplify equation to:

pH = pKa + log(1)

Therefore, the pKa of trimethylammonium ion is 11.5.

Now :

Kb × Ka = Kw

Kb = Kw ÷ Ka

Since we know that Kw = \(1.0 * 10^{-14\)and Ka =\(10^{-11.5\) (from the pKa value we calculated earlier), we can substitute these values to get:

\(Kb = (1.0 * 10^{-14}) / (10^{-11.5}) = 1.0 * 10^{-2.5\)

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Answer:

a. Cl (g) + KBr (aq) = Br (l) + KCl (aq)

b. Al (s) + I (s) = AlI (s)

c. Mg (s) + HCl (aq) = MgCl (aq) + H2 (g)

Explanation:

The reactants are the elements before the equals sign and the products are the ones after the equals sign that are bolded.

Hope this helps :)

The volume of gas produced at 18 degrees Celsius 34.7 g of carbon dioxide gas creates of 623 mmHg is 0.03 L

The ideal gas equation is as follows;

PV=nRT

P,V,n,R,T are pressure, volume, number of moles, gas constant and temperature respectively

Substituting the values, we get

623xV=34.7/44x0.0821X291

623V=0.78X23.8911

623V=18.635

V=0.03 L

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Speed must a neutron travel to have a wavelength of 25.0 pm.The mass of a neutron is 1.67x10^-27 kg is 3.17 × 10³ m/s.

Given that :

mass of neutron = 1.67 × 10⁻²⁷ Kg

wavelength = 25 pm = 2.5 × 10⁻¹¹m

h = 6.63 × 10⁻³⁴ Js   ( 1 J = Kg m /s² )

using debroglie,s wavelength , we get

λ = h / mv

v =  h / mλ

v = 6.63 × 10⁻³⁴ / ( 2.5 × 10⁻¹¹ × 1.67 × 10⁻²⁷  )

v = 6.63 × 10⁻³⁴ J.s / 20.87 × 10⁻³⁸

v = 3.17 × 10³ m/s

Thus, Speed must a neutron travel to have a wavelength of 25.0 pm.The mass of a neutron is 1.67x10^-27 kg is 3.17 × 10³ m/s.

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The half-life of Po-210 is 140 days. If the initial mass of the sample is 5 kg, 3.5g will remain after 280 days.

Chemical kinetics is a subfield of physical chemistry that studies the speeds of chemical processes. The rate of the reaction may be used to classify it as quick, moderate, or sluggish. Reaction mechanism also enables us to study the effects of temperature and catalyst on reaction rate and rate constant. It informs us about reaction processes and enables us to apply particular rate constants to certain mechanistic stages.

The rate law for first order kinetics is

K=(2.303/T)×log(a/a-x)

half life=0.693/K

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

K=0.693/half life

K=0.693/140

=0.086

0.086=(2.303/ 280)×log( 5 /a-x)

0.086=0.07×log( 136/a-x)

1.22=log( 136/a-x)

136/a-x=16.5

a-x=3.5g

Therefore, 3.5g will be left after 280 days.

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Cu + O2 --->  CuO2 -The first reaction is a combustion reaction

2 HCl + Mg → H2 + MgCl2- The second reaction is a Single replacement reaction

A combustion reaction is a type of chemical reaction that occurs between a fuel and an oxidizer in the presence of heat or light, resulting in the release of energy in the form of heat and light.

In other words, it is a reaction in which a substance reacts with oxygen to produce heat and light.

Combustion reactions are important in many aspects of daily life, including the burning of fossil fuels for energy production, the combustion of wood or other materials for heating or cooking, and the combustion of fuels in internal combustion engines.

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Answer: Internal Temperatures. Similarly, the cardiovascular, integumentary (skin and associated structures), respiratory, and muscular systems work together to help the body maintain a stable internal temperature. If body temperature rises, blood vessels in the skin dilate, allowing more blood to flow near the skin's surface.

Explanation:

The statement, that describes separation technique would most likely be used if a solvent were saved is "distillation separation."

Separation techniques are methods for separating two different states of matter, such as liquid and solid. Methods that employ variations in physical qualities to separate the components of a mixture, such as evaporation, distillation, filtration, and chromatography, can be used to physically separate the components of a mixture.

Simple distillation is a technique for removing a solvent from a solution. Water, for example, can be extracted from salt solution by simple distillation. If a solvent was saved, the separation procedure would most likely be used is distillation.

Hence the correct option is B.

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1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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d.2.93m.CaCl2 is present in the solution with a 2.93m concentration.

The boiling point of a solution is directly related to its concentration. The boiling point elevation of a solution, ΔTb, is equal to the product of the van't Hoff factor (i) and the molality of the solution (m).The quantity of moles of solute per kilogramme of solvent is known as molality.

Therefore, we can solve for the molality of the solution using the following equation:

ΔTb

\(= i *m\\105.3\°C= i * m\\\)

\(m =\frac{ 105.3 \°C }{i}\)

Assuming an ideal van't Hoff factor for CaCl2 (i = 2), the molality of the solution is:

\(m =\frac{ 105.3 \°C }{ 2}\\m = 52.65 m = 52.65 mol/kg\)

The concentration of CaCl2 in the solution is then:

\(C = m * Kb\\C = 52.65 mol/kg * 0.512 \°C/m\\C = 2.93 mol/kg\)

Therefore,The concentration of CaCl2 in the solution is  2.93m.

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complete question:The boiling point at 1.00 atm of an aqueous solution of CaCl2 is 105.3 °C. What is the concentration of CaCl2 in the solution? Kb (H2O) = 0.512 °C/m. Assume an ideal van't Hoff factor for CaCl2.

a.3.45m

b.4.40m

c.8.79m

d.2.93m

Complete Question is attached below

We have that the Chemical is

Salt

From the Question we have options

Salt

Sleep

Sold

Heat

Temperature

Generally among est the options

Salt is the only chemical present as it is made of Sodium and chlorine compound

NaCl joined by an ionic bond

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2 moles of CaSO4 are required to produce 128 g of SO2 in 3CaSO4 + CaS → 4CaO + 4SO2 in this equation.

The term mole is defined as a standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.

1 mole = 6.023 × 10²³ molecules

The balance equation is as follows:

3CaSO4 + CaS → 4CaO + 4SO2

1 mole = 6.023 × 10²³ molecules

1 mole SO₂ = 6.023 × 10²³ molecules

128 mole = ?

Molar mass of SO₂ = 64 gram

The numbers of moles in 128 gram SO₂ = 1 / 64 ×128

= 2 moles

Thus, 2  moles of CaSO4 are required to produce 128 g of SO2.

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The reactive carbon atom in acetaldehyde is bonded to a hydrogen atom, a methyl group, another hydrogen atom, and an oxygen atom.

In the acetyl formation reaction, when ethanol (CH3CH2OH) reacts in the presence of an acid catalyst, the resulting final product is acetaldehyde (CH3CHO). Acetaldehyde contains a reactive carbon atom bonded to different groups on its four sides.

To understand the bonding around the reactive carbon atom in acetaldehyde, let's examine its structure:

      H

      |

H - C - H

|

O

In acetaldehyde, the carbon atom in the center is the reactive carbon atom. It is bonded to four different groups: hydrogen (H), another hydrogen (H), a methyl group (CH3), and an oxygen atom (O).

The four different groups around the reactive carbon atom give acetaldehyde its unique properties. These different groups allow acetaldehyde to participate in various chemical reactions, such as oxidation, reduction, and condensation reactions.

The presence of the oxygen atom in acetaldehyde makes it a carbonyl compound. The carbonyl group (C=O) is highly reactive and determines the chemical reactivity of acetaldehyde. It can undergo addition reactions, nucleophilic attacks, and condensation reactions due to the polarity and reactivity of the carbon-oxygen bond.

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Answer:

Produces Wind Currents

Explanation:

Answer:

produces wind currents

Explanation:

i just took the test and got it right :}

Answer: 62.173%

explanation:

equation for percentage mass of an element in a compound = (Mass of element in compound / mass of the whole compound ) × 100%

% mass = (46.63÷75.00) × 100

= 0.62173 × 100

= 62.173%