for a molecule of chlorous acid, the atoms are arranged as hoclohoclo . what is the formal charge on each of the atoms? enter the formal charges in the same order as the atoms are listed.

Boyle's Rule: If the temperature and volume of the ideal gas remain constant in a closed system, the absolute pressure that a given mass of the gas exerts is inversely proportional to the space it takes up.

P1V1 = P2V2

447 × 86.4 = 1240 × V2

V2 = 447 × 86.4 / 1240

V2 = 31.146 mL

At constant temperature (T) and molecular weight (M), volume (V) decreases as pressure (P) increases (n)

PV = nRT

V = nRT/P

V = 4.55 × 0.082 × 285 / 7.32

Where R = ideal gas constant = 0.082 (L) (atm) (mole) -1(K) -1

V is equal to 14.53 L or 14530 cm3.

Charles's Rule: When pressure is held constant, a given mass of gas has a straight relationship between its volume and absolute temperature.

V1T2 = V2T1

1 × 263 = V2 × 310

V2 = 1 × 310 / 263

V2 = 1. 179 L

Volume (V) increases at constant pressure (P) and mole as temperature (T) rises (n)

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Answer:

20 liters of 50% solution and 80 liters of 25% solution

Explanation:

Let x litres be the amount of 50% solution to be used.

Since the amount of 25% solution used is 20 liters less than 5 times the amount of 50% solution used, then the 25% solution would be (5x -20) litres.

Therefore, 50x + 25(5x-20) = 30(x + 5x-20)

50x + 125x - 500 = 30x + 150x - 6 00

175x - 500 = 180x - 600

Collecting like terms

180x - 175x = 600 - 500

5x = 100

x = 20

Therefore, volume of 50% solution needed = 20 litres

Volume of 25% solution needed = (5 * 20) - 20 = 80 litres

20 liters of 50% solution and 80 liters of 25% solution

The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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When deuterium and tritium fuse, the atom produced is helium nucleus, which atomic number 2 and mass number 4.

One deuterium nucleus and one tritium nucleus fuse to produce one helium nucleus, one free neutron, and 17.6 MeV of energy in a process known as deuterium-tritium fusion (also abbreviated as D+T). For fusion devices, it is the type of fusion that is most effective.

Illustration of the fusion reaction between deuterium (D) and tritium (T), which results in the production of helium nuclei (or alpha particles) and high-energy neutrons. The Sun and other stars are propelled by nuclear fusion processes. Two light nuclei combine to form one heavy nucleus during a fusion process.

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Answer:

It contains 0.105 mole cu

Explanation:

Answer:

c

Explanation:

A hydrocarbon consists of only carbon and hydrogen atoms. Combustion occurs when a hydrocarbon reacts with oxygen to form carbon dioxide and water molecules.

The temperature of the food or beverage during consumption affects the volatiles.

The flavor of food or beverages is influenced by the presence of volatile compounds, which are responsible for the aroma and taste. These volatile compounds are released from the food or beverage and interact with our olfactory receptors, contributing to the overall sensory experience. Temperature plays a crucial role in this process.

When food or beverages are heated, the temperature increase leads to an increase in the volatility of certain compounds. Higher temperatures can cause the evaporation of volatile compounds, releasing them into the air and enhancing the aroma and flavor perception. For example, heating coffee can intensify its aroma due to the increased release of volatile coffee compounds.

On the other hand, cold temperatures can also affect flavor perception. Lower temperatures can decrease the volatility of certain compounds, leading to reduced aroma and flavor intensity. This is why some foods or beverages may taste less flavorful when consumed cold compared to when they are warm.

In summary, the temperature of the food or beverage during consumption affects the volatility of compounds, which in turn impacts the flavor perception. Controlling the temperature can play a significant role in enhancing or diminishing the sensory experience of the food or beverage.

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Answer:

A

Explanation:

Answer:

\( \frac{13}{6} \: c\)

Explanation:

The total isotopic mass is 13 (7 neutrons, 6 protons because this is Carbon)

Answer:

Viruses can weaken your immune system. They make you sick. Some could even cause death.

Explanation:

I hope this helped I heard that song I forgot the name lol

Answer:

Momentum is the measure of the motion of an object found by multiplying the objects mass and velocity.

Symbol: p

Units: kg x m/s

Explanation:

......

answer :

this is the structure if you want it

Answer:

The answer is: [Ar]3d6

Explanation:

After the 4 is full we automatically put the remaining six electrons in the 3d orbital.

When a pi bond is formed, one hydrogen is lost from each of the atoms involved in the bond formation. This is because a pi bond is formed when two parallel p orbitals overlap sideways, and each p orbital contains one electron.

Therefore, in order for the electrons to form a bond, one electron from each atom must be involved, leading to the loss of one hydrogen atom from each atom.

When a pi bond is formed, two hydrogen atoms are lost. This occurs because the pi bond involves the sharing of two additional electrons between two atoms, typically carbon, which results in the need to release two hydrogen atoms to maintain proper valence.

Valence is a term used in chemistry and physics to describe the number of electrons that an atom can gain, lose, or share in order to form a chemical bond with another atom. The valence of an atom is determined by the number of electrons in its outermost shell, or valence shell.

The valence of an atom is important because it determines its ability to form chemical bonds with other atoms. Atoms with a low valence (i.e. only a few electrons in their outermost shell) tend to lose those electrons and become positively charged ions, while atoms with a high valence (i.e. many electrons in their outermost shell) tend to gain electrons and become negatively charged ions.

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To determine the mass of Mg(NO3)2 present in the solution, we need to use the formula: Mass = Volume × Concentration × Molar mass. The mass of Mg(NO3)2 present in 129 mL of a 0.450 M solution is approximately 8.613 grams.

Given: Volume of solution = 129 mL. Concentration of Mg(NO3)2 solution = 0.450 M. First, we need to convert the volume of the solution from milliliters (mL) to liters (L): 129 mL = 129/1000 L = 0.129 L. Next, we need to calculate the molar mass of Mg(NO3)2: Molar mass of Mg(NO3)2 = (1 × atomic mass of Mg) + (2 × atomic mass of N) + (6 × atomic mass of O) Molar mass of Mg(NO3)2 = (1 × 24.31 g/mol) + (2 × 14.01 g/mol) + (6 × 16.00 g/mol) Molar mass of Mg(NO3)2 = 148.31 g/mol Now, we can calculate the mass of Mg(NO3)2: Mass = Volume × Concentration × Molar mass Mass = 0.129 L × 0.450 M × 148.31 g/mol Mass = 8.613 g. Therefore, the mass of Mg(NO3)2 present in 129 mL of a 0.450 M solution is approximately 8.613 grams.

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Answer:

Atomic particles

Explanation:

A scanning tunneling microscope is an instrument used to view any surfaces at the levels of an atom. It was invented in the nineteenth century.

The initial mass present is 32000 g.

We know that the half life is the time that is taken for only half of the number of the original radioactive atoms to remain. Now, we have been told in the question that the half life of the atom is 1602 years.

Now we have;

N/No = (1/2)^t/\(t_{\frac{1}{2} }\)

N = Number of atoms at time t

No = Number of atoms originally present

t = time taken

\(t_{\frac{1}{2} }\) = Half life of the sample

Now;

500/No = (1/2)^9612/ 1602

500/No =  (1/2)^6

No = 500/(1/2)^6

No = 32000 g

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Answer:

10 electrons

The d subshell can hold a maximum of 10 electrons.

Explanation:

As a nurse, I would be concerned about Mr. K's urine output of only 50 ml of dark amber urine over four hours after admission to the floor. This may indicate a potential issue with his kidney function, dehydration, or another underlying medical condition.

Dark amber urine can be a sign of concentrated urine, indicating that the body is trying to conserve fluids. However, this may also suggest that the kidneys are not functioning correctly and are unable to properly filter waste from the body. Additionally, low urine output can be a sign of dehydration, which can have serious consequences if left untreated.

As a nurse, I would assess Mr. K's vital signs, review his medical history and medication regimen, and closely monitor his urine output and color. I would also communicate my concerns with the physician and implement interventions to promote hydration, such as encouraging Mr. K to drink more fluids and possibly administering IV fluids if necessary.

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Answer:

Explanation:

????? i am having trouble according this

The correct order in which they occur in glycolysis is:Glucose → glucose-6-phosphate → fructose-1,6-bisphosphate → 3-phosphoglycerate → pyruvate

Glycolysis is the metabolic pathway by which the glucose molecule is converted to two pyruvate molecules with the production of energy-containing ATP and NADH in cells.

Pyruvate is a 3-carbon molecule formed from glucose in glycolysis. It is also a key molecule in the Krebs cycle, which is the second stage of cellular respiration.

Similarly, 3-phosphoglycerate is a 3-carbon molecule found in the Calvin cycle, the first stage of photosynthesis.

Glucose-6-phosphate, on the other hand, is a 6-carbon molecule, which is an intermediate in glycolysis.

Glucose and fructose-1,6-bisphosphate are also 6-carbon molecules that are involved in the glycolytic pathway.

So, the correct order in which they occur in glycolysis would be:

Glucose → glucose-6-phosphate → fructose-1,6-bisphosphate → 3-phosphoglycerate → pyruvateThe table below shows the name of each compound, its carbon content, and its order in glycolysis:

Compound

Carbon Content

Order in Glycolysis

Glucose-6-phosphate6

6Fructose-1,6-bisphosphate63-phosphoglycerate3

Pyruvate3

Therefore, based on the information given in the table, the correct answer to the given problem is:a. 3-phosphoglycerate - 3 carbonsb. Pyruvate - 3 carbons

c. Glucose-6-phosphate - 6 carbons

d. Glucose - 6 carbonse. Fructose-1,6-bisphosphate - 6 carbons

And the correct order in which they occur in glycolysis is:

Glucose → glucose-6-phosphate → fructose-1,6-bisphosphate → 3-phosphoglycerate → pyruvate

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Answer:

oxygen friend

Explanation:

It is generally believed that the Earth's atmosphere did not contain oxygen until around 2500 million years ago (Mya) when oxygen-evolving photosynthetic bacteria arose. At around 800–500 Mya, the oxygen concentration increased sharply to reach the 21% we have today. So, it seems highly likely that life arose as anaerobic organisms, which then evolved to tolerate oxygen and finally, to use it as a terminal acceptor for the energy-producing oxidative processes in the respiration of aerobic bacteria and mitochondria in eukaryotic cells. The respiratory processes employed by typical aerobic organisms today have a wide range of mechanisms to deal with the troublesome side effects of living with a high oxygen concentration.

Using the Clausius-Clapeyron equation, the vapor pressure of carbon disulfide (CS₂) at 35 °C is approximately 1.155 atm.

The Clausius-Clapeyron equation is given by:

ln(P2/P1) = (-ΔHvap/R) x (1/T2 - 1/T1)

Where:

P1 = Vapor pressure at temperature T1

P2 = Vapor pressure at temperature T2

ΔHvap = Enthalpy of vaporization

R = Gas constant (8.314 J/(mol·K))

T1 = Initial temperature in Kelvin

T2 = Final temperature in Kelvin

To solve the problem, we need to convert the given values to the appropriate units and substitute them into the equation.

Given:

Normal boiling point (T1) = 46.3 °C

Enthalpy of vaporization (ΔHvap) = 26.8 kJ/mol

Temperature (T2) = 35 °C

Step 1: Convert temperatures to Kelvin

T1 = 46.3 °C + 273.15 = 319.45 K

T2 = 35 °C + 273.15 = 308.15 K

Step 2: Convert enthalpy of vaporization to J/mol

ΔHvap = 26.8 kJ/mol x 1000 J/kJ = 26,800 J/mol

Step 3: Substitute the values into the Clausius-Clapeyron equation and solve for ln(P2/P1)

ln(P2/P1) = (-ΔHvap/R) x (1/T2 - 1/T1)

ln(P2/P1) = (-26,800 J/mol / (8.314 J/(mol·K))) x (1/308.15 K - 1/319.45 K)

Step 4: Calculate ln(P2/P1)

ln(P2/P1) = (-3227.17) x (-0.000045)

Step 5: Solve for P2/P1

P2/P1 = \(e^{ln(P2/P1)}\)

P2/P1 = (\(e^{-3227.17 X -0.000045}\))

Step 6: Calculate P2 by multiplying P1 with P2/P1

P2 = P1 x (P2/P1)

Note: P1 is the vapor pressure at the boiling point (46.3 °C), which is 1 atm (atmospheric pressure).

P2 = 1 atm x (P2/P1)

Substitute the calculated value of P2/P1 from step 5 into the equation to find P2.

Let's perform the calculations step by step:

Given:

T1 = 46.3 °C = 319.45 K

ΔHvap = 26.8 kJ/mol = 26,800 J/mol

T2 = 35 °C = 308.15 K

R = 8.314 J/(mol·K)

Step 1: Calculate ln(P2/P1)

ln(P2/P1) = (-ΔHvap/R) x (1/T2 - 1/T1)

ln(P2/P1) = (-26,800 J/mol / (8.314 J/(mol·K))) x (1/308.15 K - 1/319.45 K)

ln(P2/P1) = (-3227.17) x (-0.000045)

ln(P2/P1) = 0.145

Step 2: Solve for P2/P1

P2/P1 = \(e^{ln(P2/P1)}\)

P2/P1 = (\(e^{-3227.17 X -0.000045}\))

P2/P1 = \(e^{0.145}\)

P2/P1 = 1.155

Step 3: Calculate P2

P2 = P1 x (P2/P1)

P2 = 1 atm x (1.155)

P2 = 1.155 atm

Therefore, the vapor pressure of carbon disulfide (CS₂) at 35 °C is approximately 1.155 atm.

The correct question is:

The normal boiling point of carbon disulfide (CS₂) is 46.3 °C. Its enthalpy of vaporization is 26.8 kJ/mole. Use the Clausius-Clapeyron equation to determine the vapor pressure at 35 °C. Show all units and conversion factors. Also, include conversions between J and kJ, as well as between °C and K.

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Answer:

helium

Explanation:

The first ionization energy varies in a predictable way across the periodic table. The ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the largest first ionization energy, while francium has one of the lowest.

Answer: 2nd answer " C "

Explanation:

First ionization energy is a periodic trend that increases up and to the right on the periodic table. After looking at the position of these elements on the periodic table, carbon is clearly the best answer-choice (B) aka " C "

Answer: XCl2(aq) + 2 AgNO3(aq) ---> X(NO3)2(aq) + 2 AgCl(s)

Explanation:

Hehe I remembered how...

Temperature is an example of intensive properties because Intensive properties are characteristics of a substance that do not depend on the amount or size of the sample.

Temperature, represents the average kinetic energy of particles and is independent of the amount of the substance.

In contrast, volume mass and amount are examples of extensive properties, as they depend on the quantity or size of the sample. Intensive properties are useful for identifying and characterizing substances because they provide consistent information regardless of the amount of the substance present.

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Answer:

by mixing red and yellow

Explanation:

Answer:

Either the sun or by mixing red and yellow together because they make orange.

Explanation:

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