for a large, top-rated corporation, of employees said the corporation is a great place to work. suppose that we will take a random sample of employees. let represent the proportion of employees from the sample who said the corporation is a great place to work. consider the sampling distribution of the sample proportion . complete the following. carry your intermediate computations to four or more decimal places. write your answers with two decimal places, rounding if needed.

A basis for the subspace of R4 consisting of all vectors perpendicular to v is [-7/9, 1, 0, 0], [-2/9, 0, 1, 0], [1/3, 0, 0, 1].

We can find a basis for the subspace of R4 consisting of all vectors perpendicular to v by solving the homogeneous system of linear equations Ax = 0, where A is the matrix whose rows are the components of v and x is a column vector in R4.

The augmented matrix [A|0] is:

| 9 7 2 -3 | 0 |

||

||

||

||

We can row reduce the augmented matrix using elementary row operations to get it in reduced row echelon form.

| 1 7/9 2/9 -1/3 | 0 |

||

||

||

||

We can write the solution as a parametric vector form:

x1 = -7/9s - 2/9t + 1/3u

x2 = s

x3 = t

x4 = u

where s, t, and u are arbitrary constants.

Therefore, a basis for the subspace of R4 consisting of all vectors perpendicular to v is:

[-7/9, 1, 0, 0], [-2/9, 0, 1, 0], [1/3, 0, 0, 1]

These vectors are linearly independent and span the subspace of R4 perpendicular to v.

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if two triangles have three pairs of congruent angles, then they must be congruent to each other by the Angle-Angle-Angle (AAA) congruence theorem, and thus cannot be non-congruent.

No, it is not possible to make two triangles that are not congruent and have three pairs of congruent angles. This is because if two angles of a triangle are congruent, then the third angle must also be congruent by the Angle Sum Theorem, which states that the sum of the angles in a triangle is always 180 degrees. If two triangles have three pairs of congruent angles, then all three angles in each triangle are congruent, meaning they have the same measure. However, this does not guarantee that the sides of the triangles are congruent. In order for two triangles to be congruent, they must have the same angle measures as well as the same side lengths. Therefore, if two triangles have three pairs of congruent angles, then they must be congruent to each other by the Angle-Angle-Angle (AAA) congruence theorem, and thus cannot be non-congruent.

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Answer:

x <= - 4

x is = -4 or any number less than - 4

I. -6 and -4

Step-by-step explanation:

- 1/2 x + 3 >= 5

- 1/2 x >= 5 - 3

- 1/2 x >= 2 (numerator multiply, denominator divide)

-1x >= 2 * 2

- 1x >= 4

x <= 4/-1 (switch > to < because 1 is negative)

x = -4

There are many ways to find f and g, so the composition of those is  (f o g)(x) = 4/(x² + 9).

A function whose values are obtained from two given functions by first applying one to an independent variable and then using the result to apply the second, and whose domain is made up of those independent variable values for which the first function's result falls within the second function's domain.

Find f and g, so that                        

(f o g)(x)  =  4/x²+9                

Well, there is more than one possibility.                                                  

For instance, It can be:  f(x)  = 4/x  and  g(x) = x² + 9

and then you have                          

(f o g)(x)  =  f[ g(x) ]                    

(f o g)(x)  = 4/g(x)                      

(f o g)(x)  =  4/x²+9                                                      

Another possibility:   f(x)  =  4/x+9    and g(x) = x²

and for those, you get

(f o g)(x)  =  f[ g(x) ]              

(f o g)(x)  =   4/g(x)+9      

(f o g)(x)  =  4/x²+9                                                              

Since f and g can be found in a variety of ways, as you can see above, the composition of those is  (f o g)(x) = 4/(x² + 9).

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Answer:

6.36 years (the .36 repeats), so rounded is 6.4.

Step-by-step explanation:

First, I'm going to convert all measurements to meters.

Since 1000 mm = 1 m, divide 44 by 1000.

44/1000 = 0.044 m

Since 100 cm = 1 m, divide 72 by 100.

72/100 = 0.72 m

Next, I'm going to setup an equation using y = mx + b.

b is the beginning amount which is 0.72.

m in the equation represents the rate which is 0.044.

y represents the total which is 1.

Plugin the numbers and solve for x.

1 = 0.044x + 0.72

1 - 0.72 = 0.044x + 0.72 - 0.72

0.28 = 0.044x

0.28/0.044 = 0.044x/0.044

6.36 = x

Answer:

24 meters

Step-by-step explanation:

The area of a circle can be found using the following formula.

\(a=\pi r^2\)

We know that the area is 144pi m^2.

\(a= 144\pi m^2\)

Substitute 144pi m^2 in for a.

\(144\pi m^2= \pi r^2\)

We want to find the diameter. First, we must find the radius. We have to get the variable, r,  by itself.

Divide both sides of the equation by pi.

\(144\pi m^2/ \pi = \pi r^2 / \pi\)

\(144\pi m^2/ \pi = r^2\)

\(144 m^2= r^2\)

The variable, r , is being squared. The inverse of a square is the square root. Take the square root of both sides of the equation.

\(\sqrt{144 m^2} =\sqrt{r^2}\)

\(\sqrt{144 m^2} =r\)

\(12 m= r\)

The radius of the circle is 12 meters, but the question asks for diameter. The diameter is twice the radius.

\(d= r*2\)

The radius is 12 m.

\(d= 12 m*2\)

Multiply

\(d= 24 m\)

The diameter of the circle is 24 meters.

The confidence intervals created using the percentile method and the standard error method are not exactly the same for two reasons:

First, the two methods are based on different assumptions about the population distribution of the sample. Second, the percentile method and the standard error method use different formulas to compute the confidence intervals. The standard error method assumes that the population is normally distributed, while the percentile method does not make any assumptions about the distribution of the population. As a result, the percentile method is more robust than the standard error method because it is less sensitive to outliers and skewness in the data. The percentile method calculates the confidence interval using the lower and upper percentiles of the bootstrap distribution, while the standard error method calculates the confidence interval using the mean and standard error of the bootstrap distribution.

Since the mean and percentiles are different measures of central tendency, the confidence intervals will not be exactly the same.

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Answer:

hi sike not helping you but do u know where mama jones is????

Step-by-step explanation:

a. The table value of z 0.99 is given as 2.58.

b. we use σ = 2.30 minutes.

c. The value of Z is given as 0.609.

d. The confidence interval is (23.391, 24.609) minutes.

a) To find the z-score for a 0.99 confidence interval, we need to find the z-score that leaves 0.5% (since it's two-tailed, we split the 1% or 0.01 of the data that's not within the confidence interval into two) in each tail. The z-score for 0.995 (0.5% in the upper tail) is approximately 2.58 in standard normal distribution tables. So, Z_0.99 is 2.58.

b) Therefore, we use σ = 2.30 minutes.

c) The standard error of the mean (SE) is given by σ/√n, where n is the sample size.

Here, σ = 2.30 minutes and n = 95.

Therefore, SE = σ/√n

= 2.30/√95

= 0.236 minutes.

Multiply this by the z-score to find Z * σ/√n.

Therefore, Z * σ/√n = 2.58 * 0.236 ≈ 0.609.

d) The 0.99 confidence interval for μ

Here, x is the sample mean which is 24 minutes.

So the confidence interval is approximately

= (24 - 0.609, 24 + 0.609)  

= (23.391, 24.609) minutes.

This is the range of values we are 99% confident that the true population mean (μ) falls in.

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(a) As we have proved that the difference equation Pₙ = 1/6 (1 – (Pₙ₋₁) + 5.6 Pₙ₋₁

(b) The difference equation to obtain an explicit formula for Pₙ is (1/2) + (1/12)ⁿ⁻¹ (1 - (-1/2)ⁿ)

Consider the first n-1 throws. If the number of sixes thrown in these n-1 throws is even, then to get an even number of sixes in n throws, we need to throw an even number of sixes in the nth throw. This occurs with probability 1/2, as we have an equal chance of getting a six or a non-six.

On the other hand, if the number of sixes thrown in the first n-1 throws is odd, then we need to throw an odd number of sixes in the nth throw to get an even number of sixes in n throws. This also occurs with probability 1/2. Thus, the probability of getting an even number of sixes in n throws is given by the following recursive formula:

Pₙ = 1/2(1 - Pₙ₋₁) + 1/2(5/6 Pₙ₋₁)

The first term corresponds to the case when the number of sixes in the first n-1 throws is odd, and the second term corresponds to the case when it is even. We can simplify this formula as follows:

Pₙ = 1/2(1 - Pₙ₋₁) + 5/12 Pₙ₋₁

= 1/2 - 1/2 Pₙ₋₁ + 5/12 Pₙ₋₁

= 1/2 + 1/12 Pₙ₋₁

Thus, we have obtained a difference equation for Pₙ in terms of Pₙ₋₁. To solve this equation, we can use the method of iteration, which involves plugging in the formula for Pₙ₋₁ repeatedly until we obtain a formula for Pₙ in terms of n only.

Let's start with the base case P₁ = 1/2, since the probability of throwing an even number of sixes in one throw is clearly 1/2. Then, we have:

P₂ = 1/2 + 1/12 P1 = 7/12

P₃ = 1/2 + 1/12 P2 = 11/24

P₄ = 1/2 + 1/12 P3 = 25/48

P₅ = 1/2 + 1/12 P4 = 137/288

and so on.

Thus, we have obtained an explicit formula for Pₙ in terms of n, which is:

Pₙ = (1/2) + (1/12)ⁿ⁻¹ (1 - (-1/2)ⁿ)

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Answer:  C  circle

Step-by-step explanation:

After the cross section effect, a circle was formed and you can see that by looking at the red circle.

Answer:

elipse

Step-by-step explanation:

Answer:

6,309,020 in words is "six million, three hundred nine thousand, twenty."

please make me brainalist

six million three hundred nine thousand twenty

Answer:

A) Yes the 2 triangles are similar by SSS Similarity and SAS Similarity

Step-by-step explanation:

SSS:

ST/SU = SW/SV = WT/VU

60/70 = 48/56 = 30/35

6/7 = 6/7 = 6/7

SAS:

ST/SU = SW/SV = 6/7 (look at SSS proving)

Angle S = Angle S because they are reflexive or the same angles

The first five terms of the given sequence are:

a1 = -2

a2 = -5/11

a3 = 0

a4 = 7/67

a5 = 1/8

Also, given sequence should converge to a limit of 0, since the denominator is growing faster than the numerator.

For given question,

We have been given a sequence \(a_n=\frac{n^2-9}{n^3+3}\)

We need to find the first five terms, a1, a2, a3, a4, a5, of the sequence.

For n = 1,

\(a_1=\frac{1^2-9}{1^3+3} \\\\a_1=\frac{-8}{4} \\\\a_1=-2\)

For n = 2,

\(a_2=\frac{2^2-9}{2^3+3}\\\\ a_2=\frac{-5}{11}\)

For n = 3,

\(a_3=\frac{3^2-9}{3^3+3} \\\\a_3=\frac{0}{30}\\\\ a_3=0\)

For n = 4,

\(a_4=\frac{4^2-9}{4^3+3} \\\\a_4=\frac{7}{67}\)

For n = 5,

\(a_5=\frac{5^2-9}{5^3+3} \\\\a_5=\frac{16}{128}\\\\ a_5=\frac{1}{8}\)

Given sequence should converge to a limit of 0, since the denominator is growing faster than the numerator.

Therefore, the first five terms of the given sequence are:

a1 = -2

a2 = -5/11

a3 = 0

a4 = 7/67

a5 = 1/8

Also, given sequence should converge to a limit of 0, since the denominator is growing faster than the numerator.

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Jon deposits $1,000 at the end of each year for 5 years into a savings account that earns 5% annually. After 10 years, he uses the accumulated amount to purchase a perpetuity that pays P at the end of each year.

The value of P can be calculated using the formula for the future value of an ordinary annuity. The future value of an ordinary annuity formula can be used to determine the accumulated value of a series of equal payments made at regular intervals. In this case, Jon makes deposits of $1,000 at the end of each year for 5 years, earning an annual interest rate of 5%. The future value of this annuity after 5 years can be calculated as follows:

\(FV = P * [(1 + r)^{n - 1}] / r\)

Where FV is the future value, P is the payment amount, r is the interest rate per period, and n is the number of periods. Plugging in the values, we have:

FV = 1000 * \([(1 + 0.05)^{5 - 1}]\) / 0.05

  ≈ 1000 * [1.276281 - 1] / 0.05

  ≈ 1000 * 0.276281 / 0.05

  ≈ 552.562

After 10 years, the accumulated amount will be twice this value, as no further deposits are made. Therefore, the value of the perpetuity, P, is approximately $1,105.12 (twice the calculated value).

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Applying the midsegment theorem, the value of x = 5

Recall:

Thus:

DE = 1/2(AC)

2x - 3 = 1/2(x + 9)

2(2x - 3) = x + 9

4x - 6 = x + 9

4x - x = 6 + 9

3x = 15

x = 5

Therefore, applying the midsegment theorem, the value of x = 5

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Answer:

Step-by-step explanation:

hope it help u

The value of "x" in the expression 5ˣ⁻² = 8; by using the change of base formula is approximately 3.2920.

We have to find the value of "x" in the "logarithmic-expression" : 5ˣ⁻² = 8; for which we have to use the change-of-base formula, which is \(log_{b} (y) = \frac{log(y)}{log(b)}\).

we take "log" on both sides of 5ˣ⁻² = 8;

We get,

⇒ (x-2)log(5) = log(8),

⇒ x-2 = log(8)/log(5),

By using the "change of base formula",

We get,

⇒ x-2 = log₅(8),

⇒ x-2 = 1.2920

⇒ x = 1.2920 + 2;

⇒ x ≈ 3.290,

Therefore, the value of x is approximately 3.2920.

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The given question is incomplete, the complete question is

Find the value of "x" in the expression 5ˣ⁻² = 8 . Using the change of base formula \(log_{b} (y) = \frac{log(y)}{log(b)}\).

Answer:

X = 73, Y = 138

Step-by-step explanation:

When the cloud coverage was 4 percent or less, Glen Sarin took approximately 45 photographs.

Glen Sarin, the photographer, wonders if there is a correlation between the percentage of cloud cover and the number of photographs she captures. She maintains a record that is depicted in the scatterplot below.

When the cloud coverage was 4 percent or less, how many photographs did she take?We can observe that, as the percentage of cloud cover increases, the number of photographs taken by Glen Sarin decreases. As per the scatterplot,  

This can be done by reading the point where the 4% line of cloud cover intersects with the line of best fit and drawing a line perpendicular to the x-axis to see what is the corresponding y-value (which represents the number of photographs)

This can be interpreted as follows: the scatterplot shows a negative correlation between the percentage of cloud cover and the number of photographs taken.

This indicates that as the percentage of cloud cover increases, the number of photographs taken decreases. Glen Sarin may use this information to make informed decisions about when and where to photograph.

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a) X'Y' + X'Y + XY simplifies to X' + Y.

b) A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the functions:

a) Complement is W' + X' + YZ.

b) Complement is (A' + B + C)(A'B' + C' + A'B).

a) To prove X'Y' + X'Y + XY = X' + Y, we can use Boolean algebra identities:

X'Y' + X'Y + XY

= Y'(X' + X) + XY(Distributive Law)

= Y' + XY(X + X' = 1)

= X' + Y(Commutative Law)

Therefore, X'Y' + X'Y + XY simplifies to X' + Y.

b) To prove A'BC' + ABC' + BC'D = BC', we can simplify the expression using Boolean algebra:

A'BC' + ABC' + BC'D

= BC'(A' + A) + BC'D   (Distributive Law)

= BC' + BC'D(A + A' = 1)

= BC'(BC' + BC'D = BC' + BC'(1) = BC')

Hence, A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the given functions:

a) The complement of WX(Y'Z + YZ') + W'X'(Y' + Z)(Y + Z') is W' + X' + YZ.

b) The complement of (A + B' + C')(A'B' + C)(A + B'C') is (A' + B + C)(A'B' + C' + A'B).

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After applying a log transformation to the Agent Orange data, box plots of the transformed variable show significant differences between the two distributions.

Log Transformation: Take the natural logarithm of the dioxin measurements, excluding the zero values. Use the transformation log.dioxin_c = log(dioxin_c[ dioxin_c > 0 ]).

Box Plots: Create side-by-side box plots of the transformed variable (log.dioxin_c) for the two groups (Display 3 and Display 3.3). Compare the medians, spreads, and presence of outliers to visually assess the differences between the distributions.

T-Test: Conduct a two-sample t-test to compare the means of the transformed variable for Display 3 and Display 3.3. Calculate the p-value, which indicates the statistical significance of the difference between the two distributions.

Confidence Interval: Compute a 95% confidence interval for the difference in mean log measurements between the two groups. Back-transform the interval to the original scale using the exponential function.

Note that due to the addition of 0.5, the back-transformed interval provides an approximate estimate of the ratio of medians rather than exact values. Interpret the interval in terms of the original measurements, considering the potential differences in dioxin levels between the two displays.

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The new steady-state values of K, y, and c are 18.8, 16.977, and 9.885 respectively (rounded to one, three, and three decimal places respectively).

Per-worker production function: y = 4k(0.5) where y is output per worker and k is capital per worker.

National savings: S = 0.20Y where S is national savings and Y is total output. Depreciation rate: d = 0.10 and population growth rate: n = 0.10

Steady-state values of k, y, and c are 16.00, 16.00, and 12.800 respectively. New savings rate: S = 0.30Y. Depreciation rate: d = 0.10 and population growth rate: n = 0.10. Let's calculate the new steady-state value of the capital-labor ratio:

We know that: ∆K = S × Y/L - δK

If we put the given values in the above equation, we get:∆K = (0.30 × 16.00) - (0.10 × 16.00) = 2.80

Therefore, the new steady-state value of the capital-labor ratio K is 18.8 (rounded to one decimal place). Let's calculate the new steady-state value of output per worker:

New output per worker y = 4K(0.5)

Putting the value of K in the above equation, we get:

y = 4(18.8)(0.5) = 16.977(rounded up to three decimal places)

Therefore, the new steady-state value of output per worker y is 16.977 (rounded to three decimal places). Now, let's calculate the new steady-state value of consumption per worker:

New consumption per worker c = (1 - S)Y/L - δK

Putting the given values in the above equation, we get:

c = (1 - 0.30) × 16.977 - (0.10 × 18.8) = 9.885(rounded up to three decimal places)

Therefore, the new steady-state value of consumption per worker c is 9.885 (rounded to three decimal places).

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The graph of the equation is attached below and this can be determined by using the formula of the volume of the cone and the slope-intercept form of the line

Given :

For cones with a radius of 6 units, the equation V=12h relates the height h of the cone, in units, and the volume V of the con, in cubic units.

The volume of the cone is given by the formula:

v = 1/3. π .r².h

Now, substitute the value of r in the above formula.

v = 12πh

Now, compare this equation with a slope-intercept form which is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From comparing the equation, it can be concluded that:

y = V

x = h

c = 0

m = 12

Now, draw the graph of the line that passes through the origin. The graph is attached below.

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The value of finance charge for this loan is, $1205.5.

A quick and easy method of calculating the interest charge on a loan is called a Simple interest.

Given that;

Solomon is taking out loan ( Principal  P)  = 18,320

Time of loan taken (T) = 2 year

Loan with an APR ( R ) = 3.29%

To find Finance charge for this loan ( I ) we can used the formula,

⇒ I = PRT/100

⇒ I = 18,320 × 3.29 × 2 / 100

⇒ I = $1205.5

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Answer:

40%

Step-by-step explanation:

Count the total numbers of tallies. How many tallies you got put over the total number of A&B

Example: A- III B- IIII Total number of the whole chart- IIIII IIIII IIIII

7/15 and then %/100 which would be a number equal to 7/15.

I'm guessing you got the same question as me and my answer was 40%

Answer:

12

Step-by-step explanation: