Fluid is kept from accumulating in tissue spaces by.

Answer:

Decomposition reaction

Explanation:

2PbO2 → 2PbO + O2

2PbO2 is reactant.

2PbO + O2 is the product.

Definition : -

Decomposition reaction is a chemical reaction in which a single reactant breaks down to simpler products.

Answer:

tty to fin out what happend by redoing it

Answer with Explanation:

A "chemical change" occurs when the structure of the molecules change. If there's no change in structure, it is called a "physical change." This also means that a chemical reaction has to occur for something to be considered a chemical change.

Gasoline when used as a fuel is being transformed into other forms of energy. It undergoes a process called "combustion."

When used as a fuel for cars, the gasoline is being burned to produce heat energy. This energy is then converted into mechanical energy that allows the car to move. Clearly, the gasoline has undergone a chemical change.

Answer:

astronots there already up there so they might as well do it.

Answer:

17

39.21

Explanation:

plz like and give it rating it would help a lot to me

Answer:

NH3

Explanation:

The formula for ammonia gas is NH3. Its appearance is a colorless gas.

Ammonia gas is formed by the balanced chemical reaction between nitrogen and hydrogen elements. The balanced chemical equation for the formation of ammonia gas is as follows:

                       N2+3H => 2NH3

So, Nitrogen and Hydrogen are present in the ration of 2:6 or 1:3.

Answer:

lol

Explanation: lol

Answer:

Joules/sec and watts.

Explanation:

1 Joule/sec is a rate of energy expending every second.  It is equal to a watt, the English term.

Answer:

50000 dollars or 5 e5

Explanation:

Mr. Garibay has \(5.0 * 10^4\) dollars in his bank.

Scientific notation represents the data in the format of expanded number or with e character.

For instance, 5.0 * 10^4 dollars = 50000 dollars or 5 e5

Answer:

When you move the burette slider to the top of a flask and add about 25 mL of NaOH to the flask, you will cause a concentration of OH- molecules. This will make the solution become a basic solution and make the litmus paper blue.

Explanation:

After reading your question, we can see that you are carrying out a test to discover the nature of the pH of a solution. This type of test uses litmus paper, which is an indicator of the presence of acids and bases, being able to determine the pH of a solution. This paper is soaked in organic ink and when placed in an acidic solution, it is red in color. However, when placed in a basic solution it has a blue color.

An acidic solution is one that has a high concentration of H+ atoms and has the ability to donate electrons. The basic solution, on the other hand, has a high concentration of OH- and has the capacity to receive electrons.

When you move the burette slider to the top of a flask and add about 25 mL of NaOH to the flask, you will cause a concentration of OH- molecules. This will make the solution become a basic solution and make the litmus paper blue, that is, the solution has the basic pH.

The concentration of hydroxide ions after a chemical reaction has occurred is  0.1 mol/L.

To calculate the concentration of hydroxide ion after the chemical reaction has occurred, first, consider the reaction between NH₃ and NaOH:

NH₃ + NaOH → NH₄⁺ + OH⁻

4.00g of NaOH is equivalent to (4.00 g / 40.00 g/mol) = 0.1 mol. Since the volume of the solution is 1.00 L, the initial concentration of NaOH is 0.1 mol/L.

As the reaction proceeds, NaOH reacts with NH₃, which is present at 0.50 M. Let's assume x mol of NH₃ reacts with NaOH. Then, the change in the concentration of NH₃ and NaOH is -x and the change in the concentration of NH₄⁺ and OH⁻ is +x.

At equilibrium, the concentrations are as follows:

[NH₃] = 0.50 - x

[NaOH] = 0.1 - x

[NH₄⁺] = 0.50 + x

[OH⁻] = x

Since the reaction goes to completion, the limiting reactant will be NaOH. Thus, x = 0.1 mol/L, and the concentration of hydroxide ion after the chemical reaction has occurred is 0.1 mol/L.

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To solve this problem, we can use the Ideal Gas Law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas. The Ideal Gas Law is expressed as:

PV = nRT

where R is the gas constant.

R = 0.0821 L·atm/mol·K

We can rearrange this equation to solve for pressure:

P = nRT/V

where:

n = 0.500 mol (number of moles of N2 gas)

R = 0.0821 L·atm/mol·K (gas constant)

T = 298 K (temperature)

V = 10.0 L (volume)

Substituting the values:

P = (0.500 mol)(0.0821 L·atm/mol·K)(298 K)/(10.0 L)

P = 12.1 atm

Therefore, the pressure exerted by a 0.500 mol sample of N2 gas in a 10.0 L container at 298 K is 12.1 atm.

Answer:

Gases, liquids, and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. Gas is well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

Explanation:

Answer:

3. nucleus

Explanation:

The nucleus contains all the genetic information.

The final gas volume, O, could be either larger or smaller than 2.96 L, depending on the final pressure and temperature. While heating the gas to a higher temperature, O could be larger than 2.96 L, but it could also be smaller.

The final gas volume, O, could be either larger or smaller than 2.96 L, depending on the final pressure and temperature. To understand why, we can look at the ideal gas law equation, PV = nRT. In this equation, P represents pressure, V represents volume, n represents the number of moles of gas, R is the gas constant, and T represents temperature.

Let's analyze the situation given in the question. We have a sample of xenon gas at a temperature of 306 K and a pressure of 0.847 atm, occupying a volume of 2.96 L. Now, if the pressure of the gas is decreased, while at the same time it is heated to a higher temperature, the final gas volume, O, could be either larger or smaller than 2.96 L.

If we decrease the pressure while keeping the temperature constant, according to Boyle's law, the volume of the gas will increase. So, in this case, O would be larger than 2.96 L. However, if we simultaneously increase the temperature while decreasing the pressure, the situation becomes more complex. The combined effect of the pressure decrease and temperature increase could lead to different outcomes for the final volume.

For example, if the pressure decrease is significant and the temperature increase is relatively small, the volume may still increase, resulting in O being larger than 2.96 L. On the other hand, if the pressure decrease is small and the temperature increase is significant, the volume may actually decrease, resulting in O being smaller than 2.96 L.

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The triple point can be seen from the graph that has been attached here.

The triple point is a special combination of temperature and pressure where the equilibrium of a substance's three phases—solid, liquid, and gas—occurs. The transition between phases happens with no discernible net change in the substance because the solid, liquid, and gas phases are in perfect equilibrium at the triple point.

A crucial reference point in thermodynamics, the triple point is frequently used to specify temperature scales and calibrate thermometers. Each substance has a specified value for temperature and pressure.

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Zinc acetate has been authorized through America FDA for maintenance therapy of person and paediatric Wilson's disorder sufferers.

However also has efficacy in the treatment of pregnant sufferers and pre- symptomatic sufferers from the start. It also has price as adjunctive remedy for the preliminary remedy of symptomatic patients. Zinc is likewise beneficial in coping with Wilson disorder and acts through inhibition of copper absorption, in place of chelation of extra copper in tissue or the move. Zinc has been used as a first line remedy, but is presently endorsed largely as upkeep remedy as soon as chelation of excess copper has been finished.

Zinc is completely effective in controlling copper ranges and toxicity in Wilson's ailment, as are different anticopper marketers. Zinc monotherapy is powerful in Wilson's disease patients with slight liver ailment identified in childhood: a retrospective study.

Zinc acetate is a dietary complement. it's miles a vital thing essential for the proper functioning, increase, and improvement of your body. It helps to enhance immunity, promotes wound healing, and prevents skin infections and zits.

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Arranging the species by their relative molar amounts in a 1.0×10^−6M solution of Ba(OH)2(aq) at 25 °C:

Greatest amount: OH^-

Ba(OH)2

Ba^2+

H2O

H3O^-

In the given solution of Ba(OH)2(aq), the compound dissociates into its constituent ions, Ba^2+ and OH^-. The concentration of OH^- will be twice the concentration of Ba(OH)2 since each Ba(OH)2 molecule produces two OH^- ions. Therefore, OH^- will be present in the greatest amount.

Ba(OH)2 will be the next species in terms of molar amounts, followed by Ba^2+ since they are both present at half the concentration of OH^-. Water (H2O) does not participate in the chemical reaction and remains unchanged in terms of molar amounts. H3O^+ is not mentioned in the given compound Ba(OH)2 and is not present in this solution.

Therefore, based on the relative molar amounts, the arrangement of the species is as follows: OH^- (greatest amount), Ba(OH)2, Ba^2+, H2O, H3O^+ (least amount).

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Answer:

Virus is living due to reproduction and non-living due to crystal appearance.

Explanation:

Characteristics that viruses display is the ability of reproduction in which they increase in population which is a living character and have DNA or RNA which help them to make exact copies of itself. Virus is parasitic in nature because it causes harm to the living host such as humans, animals and plants. Some characteristics that viruses don't display are that they are not like living cells, have no membrane around them, no organelles such as mitochondria, golgi bodies, endoplasmic reticulum and lysosomes etc. Viruses are present in crystal form outside the cell.

a. solar energy

the earth is warmed by the sun, which is solar (or infrared).

The magnitude of the force acting on the body is 4000 Newtons.

To find the magnitude of the force, we can use Newton's second law of motion, which states that the force applied to an object is equal to the product of its mass and acceleration.

The given information includes the mass of the body (80 kg) and the resulting velocity (10 m/s). However, since the time duration (0.2 seconds) is also provided, we can use it to calculate the acceleration of the body.

The formula to calculate acceleration is:

Acceleration = Change in Velocity / Time

The change in velocity can be calculated by subtracting the initial velocity (which is 0 m/s as the body is at rest) from the final velocity:

Change in Velocity = Final Velocity - Initial Velocity

Change in Velocity = 10 m/s - 0 m/s

Change in Velocity = 10 m/s

Now, we can calculate the acceleration:

Acceleration = Change in Velocity / Time

Acceleration = 10 m/s / 0.2 s

Acceleration = 50 m/s²

Finally, we can calculate the magnitude of the force using Newton's second law:

Force = Mass x Acceleration

Force = 80 kg x 50 m/s²

Force = 4000 N

Therefore, the magnitude of the force acting on the body is 4000 Newtons.

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Answer:

cell wall > skeletal system (maybe)

cell membrane > skin (maybe)

nucleus > brain

mitochondria > digestive system

Explanation:

Answer:

(a)57.48 percent (b) 29.45 percent

Explanation:

copper(II) bromide is 29.45 percent copper and 71.54 percent bromine. so the first element percentage composition is always the percentage composition of the compound.

that goes same with sodium hydroxide. it  is 57.48 percent sodium, 40 percent oxygen, and 2.52 percent hydrogen.

The arrangement of atoms ca, br, ge, rb, in order of increasing atomic radius is : Rb > Ca > Ge > Br

Atomic radius is the distance between the nucleus and the outermost shell of an atom. The periodic table indicates a general pattern in the way atomic radius varies across the table. The atomic radius depends on the number of protons, electrons, and neutrons in an atom, as well as the electron configuration and the shielding effect. Atomic radius increases from top to bottom within a group and decreases from left to right across a period. To arrange in the order of atomic radius, we generally follow the above rule also here are the atomic radii of the given atoms, according to the periodic table trends: Ca (calcium): 197 pm, Br (bromine): 115 pm, Ge (germanium): 125 pm, Rb (rubidium): 247 pm. Based on this data, we can arrange the atoms in order of increasing atomic radius as follows:Br > Ge > Ca > Rb

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Answer:

300 K

General Formulas and Concepts:

Atomic Structure

Gas Laws

Ideal Gas Law: PV = nRT

Explanation:

Step 1: Define

Identify variables

[Given] n = 0.5 mol N₂

[Given] V = 6 L

[Given] P = 2 atm

[Given] R = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] T

Step 2: Solve for T

Step 3: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

292.326 K ≈ 300 K

Approximately 1.00 moles of gas are contained in the balloon.

We can use the Ideal Gas Law, PV = nRT, to solve this problem. Here's how:

P = 2.200 atm (the pressure in the balloon)

V = 24.11 L (the volume of the balloon)

T = 27.1 + 273.15 = 300.25 K (convert Celsius to Kelvin)

R = 0.0821 L·atm/mol·K (the gas constant)

We can rearrange the Ideal Gas Law to solve for the number of moles (n) of gas:

n = PV / RT

Substituting the given values into the equation, we get:

n = (2.200 atm) x (24.11 L) / (0.0821 L·atm/mol·K x 300.25 K)

n = 1.00 moles (rounded to two significant figures)

Therefore, there are approximately 1.00 moles of gas in the balloon.

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Answer:

The reactants of photosynthesis are carbon dioxide and water.

Kc = [GSH]2[NADP+]/[GSSG] [NADPH] [H+]= (2.47 × 10^-8)^2 (1.00 × 10^-5)/(3.59 × 10^-5)(1.00 × 10^-4) (1.00 × 10^-7)= 1.073. Hence, the answer is option A. 1.073.

The equilibrium constant for the reaction is given by the ratio of the product of the concentrations of the products raised to their stoichiometric coefficients to the product of the concentrations of the reactants raised to their stoichiometric coefficients.

However, the given reaction is as follows;glutathione + NADPH + H+ ↔ reduced glutathione + reduced glutathione + NADP+The corresponding equilibrium constant expression is,Kc = [GSH]2[NADP+]/[GSSG] [NADPH] [H+]Where;[GSH] = Concentration of glutathione[NADPH] = Concentration of NADPH[H+] = Concentration of hydrogen ions[GSSG] = Concentration of reduced glutathione.

On substitution,Kc = [GSH]2[NADP+]/[GSSG] [NADPH] [H+]= (2.47 × 10^-8)^2 (1.00 × 10^-5)/(3.59 × 10^-5)(1.00 × 10^-4) (1.00 × 10^-7)= 1.073Hence, the answer is option A. 1.073.

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The energy that is associated with the emission line is given as 2.97 x 10^-19 J

The fomula for the energy associated with an electromagnetic wave is given by the equation:

E = h*f

definition of the terms in the definition

we have E = energy

H is the plancks constant. This constant is 6.626 x 10^-34 J*s

F is the frequency

Since f = 4.47x10^14 s^-1.

we have to multiply the values that we have to get the Emission line

This is given as

E = (6.626 x 10^-34 J*s) * (4.47 x 10^14 s^-1)

E = 2.97 x 10^-19 J

Therefore, the energy associated with the emission line is 2.97 x 10^-19 Joules.

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Taking into account the reaction stoichiometry, 22.29 grams of Al₂(SO₄)₃ are formed if 3.52 grams of aluminum completely reacted with H₂SO₄.

The balanced reaction is:

2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 54 grams of Al form 342 grams of Al₂(SO₄)₃, 3.52 grams of Al form how much mass of Al₂(SO₄)₃?

mass of Al₂(SO₄)₃= (3.52 grams of Al× 342 grams of Al₂(SO₄)₃)÷ 54 grams of Al

mass of Al₂(SO₄)₃= 22.29 grams

Finally, 22.29 grams of Al₂(SO₄)₃ are formed.

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