Answer:
C
Step-by-step explanation:
So I think the answer is c
What do the following two equations represent?
(B) Distinct parallel lines
Answer:
B. Distinct parallel lines
Step-by-step explanation:
These two equations have the same slope 4/3 which means they are parallel.
y = mx + b
m is slope
b is y-intercept
\(y = \frac{4}{3} x + \frac{5}{3}\)
\(y - 8 = \frac{4}{3} (x + 6)\)
\(y = \frac{4}{3} x + 16\)
Missy uses 1 hexagonal, 3 rectangular, and 4 triangular pieces of fabric to make 1 bug design for a quilt. If she uses 80 pieces in all to make bug designs, how many of each shape does she use?
Answer:10 hexagonal, 30 rectangular and 40 triangular pieces of fabrics
Step-by-step explanation:
This question is a ratio/proportion question
The ratio of hexagonal pieces use to rectangular pieces used and to triangular pieces used can be expressed as 1:3:4
Total pieces of fabrics used = 80
Total ratio = 1 + 3 + 4 = 8
We can calculate each ratio as a proportion of the total ratio
pieces of hexagonal used = (1/8) * 80 =10
Pieces of rectangular used = (3/8) * 80 =30
Pieces of triangular used = (4/8) * 80 = 40
And hence the pieces of each shapes used will be 10 hexagonal, 30 rectangular and 40 triangular pieces of fabrics
And the total number of bugs designs made = (80/8) = 10 (since it will require 8 pieces of fabrics(1 + 3 +4) to make a bug design)
victor, a student at um, conducted a similar survey among undergraduate students at the university of michigan using a random sample of the same size from the study conducted at cornell university and obtained the same sample proportion. the undergraduate student body at the university of michigan is almost twice as large as the undergraduate student body at cornell university. victor is concerned that the computation of the margin of error for a confidence interval for the population proportion will be affected by the population size. do you agree with victor's concern?
Yes, Victor needs to have similar portion of the population in the sample.
What is population size?
The number of objects inside a geographical area that has been arbitrary assigned as the population size.
In a fair, unbiased poll
Population proportion plus random error equals sample proportion.
According to the Normal Approximation, the standard deviation of the distribution of these random mistakes across all feasible samples is
\(\sqrt{\frac{\text{Population proportion}(1-\text{Population proportion})}{n}}\)
The sample estimate's variance from the actual population value is known as the random error. Numerous alternative summaries, such as sample averages or discrepancies between two sample proportions or averages, are likewise consistent with the observation that random mistakes follow the normal curve.
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PLS HELP ASAP
It takes 24 electricians 36 days to wire a new housing subdivision. How many days would 32 electricians take to do the same job?
Answer: The 32 electricians are expected to finish the job in 27 days.
Step-by-step explanation:
a k out of n system is one in which there is a group of n components, and the system will function if at least k of the components function. assume the components function independently of one another. in a 3 out of 5 system, each component has probability 0.9 of functioning. what is the probability the system will function? round your answer to four decimal places.
A system will function if exactly 3 out of 5 componet function with probability of functioning 0.9. The probability the system will function is equals to the 0.9914.
Binomial distribution is a probability distribution used in statistics that defines as a value will take one of two independent values under a set of parameters or assumptions. Formula, P ( X = x)
= nⁿCₓ pˣ(1 -p)⁽ⁿ⁻ˣ⁾
where, P -->binomial probability
x --> number of times for a n trialsⁿCₓ= number of combinationsp --> probability of success on a single trial1- p --> probability of failure on a single trialn--> number of trialsWe have provided that k out of n system is one which have a group of n components and system will function atleast k of components. Also, consider that components function independently of one another. So, The distribution of the number of components functioning is Binomial, X ~ Binom( n,p).
Probability of functioning of each component in 3 out of 5 system = 0.9
that is Probability of success, p = 0.9 and n = 5.
Now for the system to function at least 3 components must function.
X ~ Binom( 5,0.9)
a) The probability the system will function is determined by using binomial probability formula,
P (X ≥ 3) = 1 - P (X < 3)
= 1 - P (X = 0) - P (X = 1) - P (X = 2)
= 1 - ⁵C₀ 0.9⁰ ( 1-0.9)⁵ - ⁵C₁ 0.9¹ ( 1-0.9)⁴ - ⁵C₂ 0.9²(1 -0.9)³
= 1 - (0.1)⁵ - 5(0.9)(0.1)⁴ - 10(0.9)²(0.1)³
= 1− 0.00001 - 0.00045 − 0.0081
= 0.99144
Hence, required probability value is 0.9914.
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....................................
A. 3n + 5
Jose will only age by one every year. So we add one every year and since there are five years, the answer will be his age (3n) plus 5.
Show that w is in the subspace of R4 spanned by V1, V2, and V3, where these vectors are defined as follows. 1 -4 -9 -4 6 3 5 W= -2 - 1 - 1 -2 4 11 -8 - 15 To show that w is in the subspace, express was a linear combination of V1, V2, and V3. Select the correct answer below and, if necessary, fill in any answer boxes to complete your choice. O A. The vector w is in the subspace spanned by V1, V2, and V3. It is given by the formula w= (v1+ 2+ 3. (Simplify your answers. Type integers or fractions.) B. The vector w is not in the subspace spanned by V1, V2, and V3.
To show that w is in the subspace of R4 spanned by V1, V2, and V3, we need to find constants c1, c2, and c3 such that:
w = c1V1 + c2V2 + c3V3
We can write this as a matrix equation:
| 1 -4 -9 -4 | | c1 | | -2 |
| 6 3 5 1 | x | c2 | = | -1 |
| 2 4 11 -8 | | c3 | | -1 |
| -15 7 22 -14 | | -2 |
We can solve this system of equations using row reduction:
| 1 -4 -9 -4 | | c1 | | -2 |
| 6 3 5 1 | x | c2 | = | -1 |
| 2 4 11 -8 | | c3 | | -1 |
| -15 7 22 -14 | | -2 |
R2 = R2 - 6R1
R3 = R3 - 2R1
R4 = R4 + 15R1
| 1 -4 -9 -4 | | c1 | | -2 |
| 0 27 59 25 | x | c2 | = | 11 |
| 0 12 29 -16 | | c3 | | 3 |
| 0 -23 67 -59 | | -32 |
R4 = R4 + 23R2
| 1 -4 -9 -4 | | c1 | | -2 |
| 0 27 59 25 | x | c2 | = | 11 |
| 0 12 29 -16 | | c3 | | 3 |
| 0 0 174 -294 | | 225 |
R3 = R3 - (12/27)R2
R4 = (1/174)R4
| 1 -4 -9 -4 | | c1 | | -2 |
| 0 27 59 25 | x | c2 | = | 11 |
| 0 0 -1 22/3 | | c3 | | -13/3 |
| 0 0 1 -98/87 | | 25/58 |
R1 = R1 + 4R3
R2 = R2 - 59R3
R4 = R4 + (98/87)R3
| 1 0 -13 -10/3 | | c1 | | 21/29 |
| 0 27 0 -2119/87 | x | c2 | = | 2238/87 |
| 0 0 1 -98/87 | | c3 | | 25/58 |
| 0 0 0 1390/2391 | | 1009/2391 |
R1 = R1 + (13/1390)R4
R2 = (1/27)R2
R3 = R3 + (98/1390)R4
| 1
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It costs $363 to make 90 bags of cotton candy and $440 to make 200 bags of cotton candy.
a) find the cost equation.
Answer:
363=90bags
then you look into it and say
440=200bags
Which system of linear equations has only one solution? Why? How about the system of linear equations with no solution? Infinite number of solutions? Explain your answer.
The system of linear equations which has the rank of coefficient matrix equal to augmented matrix and equal to the number of unknowns, has only one solution called the unique solution.
Two types of system of equations exist- consistent and inconsistent.
Inconsistent means that it has no solution , i.e. the solution does not exist , here
Rank of augmented matrix is not equal to that of coefficient matrix.
Consistent system means a solution of the equation exists i.e.
rank of augmented matrix = rank of coefficient matrix.
Now, a consistent system can be of two types again - It may have a unique solution ,i.e.
rank of augmented matrix = rank of coefficient matrix = no. of unknowns
or an infinite number of solutions, where
rank of augmented matrix = rank of coefficient matrix < no. of unknowns (here we need to assign an arbitrary value to a free variable to find its solutions).
For e.g. let us consider the system -
x + y+ z = 0
2x + 3y + 4z = 1
Since , (0,0,0) is obviously satisfying the equation and so is a solution to this system , the given system is a consistent system .
Also, for a system to be consistent , either a unique solution exists or an infinite number of solutions exist. There is no particular number of solutions.
Here, we see that (-1,1,0) is also a solution other than the zero solution.
We can clearly see that the number of unknown variables , x,y,z is 3 and the number of equations is 2.
Thus, The system if there are fewer equations than variables has infinite solutions, equal number of equations as the unknowns has the unique solution.
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80MNP14. Suppose O is the midpoint of MQ and N is the midpoint of Mo. If NO = 8, find MQ.
MN+NO=MO
Where N is the midpoint of MO
Therefore:
MN = NO
MN = 8
NO = 8
8 + 8 = MO
MO = 16
Now:
MO + OQ = MQ
If O is the midpoint of MQ:
MO = OQ
OQ = 16
Therefore:
MQ = 16 + 16 = 32
#3 what is 33/222 simple form
Answer: 11/74
Step-by-step explanation:
We have to think about what number can be divided from both 33 and 222. 33’s factors are 11 and 3. 222’s are 3, 6, 74, 37, and probably more. The only one the two numbered have in common is 3. So, divide north the numbers toe and denominator by 3 to get 11/74.
Joe asks for a construction loan of 2 million pesos, which is delivered in three parts. The first payment of 1 million is given immediately and subsequent payments of 500,000 are made within 6 and 12 months respectively.
Loan interest is calculated at a rate of 15% convertible semi-annually and accrues until the end of the second year. At that time, the loan and accrued interest are replaced by a 30-year, 12% monthly convertible mortgage.
The amount of the mortgage payments during the first 5 years will be half of the payments 6, 7, 8, ..., 30. The first monthly mortgage payment is made exactly 2 years after the moment in which it is requested. the loan.
Calculate the amount of the 12th mortgage payment.
The 12th mortgage payment is 23,998.11 pesos, which is calculated based on the loan amount, 2 years of accrued interest, and the monthly mortgage payment formula.
To calculate the amount of the 12th mortgage payment, we need to break down the steps involved:
1. Calculate the loan amount after 2 years of accruing interest:
The loan amount after 2 years will be the sum of the initial loan amount and the accrued interest. Since the interest is compounded semi-annually at a rate of 15%, the formula for calculating the future value (FV) of the loan after 2 years is:
FV = PV * (1 + r/2)²ⁿ
Where PV is the present value (loan amount), r is the interest rate, and n is the number of compounding periods.
In this case:
PV = 2,000,000 pesos
r = 15% = 0.15
n = 2 years
FV = 2,000,000 * (1 + 0.15/2)²²
FV = 2,000,000 * (1 + 0.075)⁴
FV ≈ 2,479,095.31 pesos
2. Calculate the monthly mortgage payment for the first 5 years:
The monthly mortgage payment during the first 5 years is half of the payments from the 6th to the 30th year. Since the mortgage is for 30 years, there are 360 monthly payments.
The formula for calculating the monthly mortgage payment is:
PMT = PV * (r/12) / (1 - (1 + r/12)⁽⁻ⁿ⁾)
Where PMT is the monthly payment, PV is the loan amount, r is the monthly interest rate, and n is the number of months.
In this case:
PV = 2,479,095.31 pesos (calculated in step 1)
r = 12% = 0.12
n = 360 months (30 years)
PMT = 2,479,095.31 * (0.12/12) / (1 - (1 + 0.12/12)⁽⁻³⁶⁰⁾)
PMT ≈ 23,998.11 pesos
3. Calculate the amount of the 12th mortgage payment:
Since the first monthly mortgage payment is made exactly 2 years after the loan is requested, the 12th mortgage payment corresponds to the payment made in the 13th month.
Therefore, the amount of the 12th mortgage payment is approximately 23,998.11 pesos.
In conclusion, the amount of the 12th mortgage payment is approximately 23,998.11 pesos. This calculation takes into account the initial loan amount, accrued interest over 2 years, and the monthly mortgage payment formula. It is important to note that the calculations provided are based on the information and assumptions given in the question.
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“The product of a number and negative 8” ( translating expression).
Answer:
x(-8)
Step-by-step explanation:
0.905×0.234 pls help
Write an equation for the function whose graph is described. The shape of f(x) = x2, but shifted three units to the right and six units down g(x) =
the equation for g(x) is g(x) = (x - 3)² - 6.
The function g(x) can be obtained by applying a horizontal and vertical shift to the graph of f(x) = x². The horizontal shift of three units to the right can be achieved by replacing x in f(x) with (x - 3), which moves the graph to the right. The vertical shift of six units down is accomplished by subtracting 6 from f(x).
Therefore, the equation for g(x) is g(x) = (x - 3)² - 6. This equation represents a parabola that has the same shape as f(x) = x² but is shifted three units to the right and six units down in the coordinate plane.
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evaluate.
(−1 2/3)^2=
Answer:
Step-by-step explanation:
(-5/3)(-5/3)= 25/9= 2 7/9
HELP PLS I WILL MARK BRAINLIEST!!!!!!!!!!!!
a
because it has the highest values from all the options from all the above
A rectangular tank, 3m long, 2m broad and 1m deep, is filled with water to a depth of 3/4m. How any bricks measuring 1/5m by 1/8m by 1/10m can be put into it before the water overflows?
A rectangular tank 3600 bricks measuring 1/5m by 1/8m by 1/10m into the tank before the water overflows.
To find bricks can be put into the tank before the water overflows, the volume of water in the tank and then determine the volume of each brick.
The volume of water in the tank length, width, and depth:
Volume of water = length × width × depth = 3m × 2m × (3/4)m
The volume of each brick:
Volume of each brick = length × width × height = (1/5)m × (1/8)m × (1/10)m
Divide the volume of water in the tank by the volume of each brick:
Number of bricks = (Volume of water) / (Volume of each brick)
Now let's substitute the given values into the formulas and
Volume of water = 3m × 2m × (3/4)m = 9/2 m³
Volume of each brick = (1/5)m × (1/8)m × (1/10)m = 1/400 m³
Number of bricks = (9/2 m³) / (1/400 m³)
= (9/2) / (1/400)
= (9/2) × (400/1)
= 9 × 400 / 2
= 3600
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If sinx=7/9,x in quadrant 1 , then find (without finding x ) :
sin(2x)=
cos(2x)=
tan(2x)=
The value of x is
sin(2x) = (14√32)/81*
cos(2x) = -17/81**, and
tan(2x) = -(14√32)/17
Given that **sin(x) = 7/9** and **x** is in the first quadrant, we can find the values of **sin(2x)**, **cos(2x)**, and **tan(2x)** without explicitly determining the value of **x**.
To find **sin(2x)**, we can use the double-angle formula for sine: **sin(2x) = 2sin(x)cos(x)**.
We already know that **sin(x) = 7/9**. To find **cos(x)**, we can use the Pythagorean identity: **cos(x) = √(1 - sin^2(x))**.
Plugging in the value of **sin(x)**, we have **cos(x) = √(1 - (7/9)^2) = √(1 - 49/81) = √(32/81) = √32/9**.
Now, we can substitute the values of **sin(x)** and **cos(x)** into the double-angle formula to find **sin(2x)**:
**sin(2x) = 2sin(x)cos(x) = 2 * (7/9) * (√32/9) = (14√32)/81**.
Moving on to **cos(2x)**, we can use the double-angle formula for cosine: **cos(2x) = cos^2(x) - sin^2(x)**.
We already have the values of **sin(x)** and **cos(x)**, so we can substitute them into the double-angle formula:
**cos(2x) = (√32/9)^2 - (7/9)^2 = (32/81) - (49/81) = -17/81**.
Lastly, to find **tan(2x)**, we can use the identity: **tan(2x) = sin(2x)/cos(2x)**.
Plugging in the values we obtained earlier, we have:
**tan(2x) = (14√32)/81 / (-17/81) = -(14√32)/17**.
Therefore, without explicitly finding the value of **x**, we have determined:
**sin(2x) = (14√32)/81**,
**cos(2x) = -17/81**, and
**tan(2x) = -(14√32)/17**.
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1/2 Marks
Find the gradients of lines A and B.
Answer:
Line A = 3
Line B = - 1
Step-by-step explanation:
To find the gradient, you need two points on a line right. The formula for gradient is
\( \frac{y2 - y1}{x2 - x1} \)
So on line A, try to find 2 points (coordinates)
You have (-2,1) , (-1,4) , (0,7)
Choose any two
Let's say (-1,4) and (0,7)
Gradient =
\( \frac{7 - 4}{0 - - 1} = \frac{3}{1} = 3\)
Gradient of line A is 3
For line B, let's take (1,7) and (2,6)
Gradient =
\( \frac{7 - 6 }{1 - 2} = \frac{1}{ - 1} = - 1\)
Gradient of line B = - 1
What is 3 dived by 5
the simplest fraction is: 3/5
in decimal form its: 0.6
y=-5y=−5 Evaluate this expression: 3y+6=3y+6=
Answer: 3y+6
Step-by-step explanation:
Hiiii someone please help me I'm confused please helppp
If the length of the bases of right triangle GHI are 9 units and 15 units respectively, what is the length of the hypotenuse of GHI?
Answer:
17.5 units
Step-by-step explanation:
a² + b²= c²
9² + 15² = c²
81 + 225 = c²
c² = 306
c = √306
c = 17.5
Jerri is training for a biathlon. to train for the bicycle portion of the race, she rides 21 miles out a straight road, then turns around and rides 21 miles back. the trip out is against the wind, whereas the trip back is with the wind. if she rides 20 miles per hour faster with the wind then she does against the wind, and the complete trip out and back takes 2 hours, how fast does she ride when she rides against the wind
Jerri rides 22 miles per hour against the wind.
REPRESENT JERRI'S SPEEDTo solve this problem, we can set up two equations to represent Jerri's speed with the wind and against the wind. Let "w" represent Jerri's speed with the wind and "a" represent her speed against the wind.We can set up the first equation by multiplying Jerri's speed with the wind by the time it takes her to ride that distance, and set it equal to the distance she rides:w × (1 ÷ 2) = 21
We can set up the second equation by multiplying Jerri's speed against the wind by the time it takes her to ride that distance, and set it equal to the distance she rides:a × (1 ÷ 2) = 21
Since Jerri rides 20 miles per hour faster with the wind than she does against the wind, we can set up a third equation to represent this relationship:w = a + 20
Now we have three equations and three variables, so we can solve for "a" (Jerri's speed against the wind) by substituting the first equation into the third equation and solving for "a":w = a + 20
(21 × 2) = a + 20
42 = a + 20
22 = a
Therefore, Jerri rides 22 miles per hour against the wind.
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1/2a+2/3b=50 when b=30?
The given equation is (1/2)a + (2/3) b = 50
and b = 30
Substituting the given value of b is above the equation we get
\(\large\displaystyle\text{$\begin{gathered}\sf \bf{\Rightarrow\left(\frac{1}{2}\right)a+\left(\frac{2}{3}\right)\times30=50 } \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf \bf{\Rightarrow \left(\frac{1}{2}\right)a+20=50 } \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf \bf{\Rightarrow\left(\frac{1}{2}\right)a=50-20=30 } \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf \bf{\Rightarrow a = 30 \times 2 = 60 } \end{gathered}$}\)
Therefore, a = 60 and b = 30 is a solution of the given equation.
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Mrs. Zahid bought 6 bouquets at $ m each, and 8 packs of chocolates at $ ‘n’ each. She had $(2m + 5n) left. Find the amount of money she had at first.
Answer:
$(8m + 13n)
Step-by-step explanation:
Given that :
Total Cost of 6 bouquet = 6m
Total cost of 8 chocolate = 8n
Total amount spent = $(6m + 8n)
Total amount left = $(2m + 5n)
Hence, amount had at first :
Total amount. Spent + total amount. Left
(6m + 8n) + (2m + 5n)
(6m + 2m + 8n + 5n)
$(8m + 13n)
Two opposing opinions were shown to a random sample of 1,500 buyers of a particular political news app in the United States. The opinions, shown in a random order to each buyer, were as follows:
Opinion A: Improving the healthcare system is more important than improving the education system.
Opinion B: Improving the education system is more important than improving the healthcare system.
Buyers were to choose the opinion that most closely reflected their own. If they felt neutral on the topics, they were to choose a third option of "Neutral."
The outcomes were as follows:
39% chose Opinion A, 54% chose Opinion B, and 7% chose "Neutral."
Part A: Create and interpret a 98% confidence interval for the proportion of all US buyers of this particular app who would have chosen Opinion B. (5 points)
Part B: The number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B are both greater than 10. Why must this inference condition be met? (5 points)
Answer:
A) 98% Confidence interval for the proportion of all US buyers of this particular app who would have chosen Opinion B
= (0.51, 0.57)
This means that the true proportion of all thay would chose opinion B can take on values between the range of (0.51, 0.57)
B) For the confidence interval obtained to be valid, the conditions stated must be satisfied and for the sampling distribution to be approximately normal, the number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B must both be greater than 10.
Step-by-step explanation:
Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample proportion) ± (Margin of error)
Sample proportion of all US buyers of this particular app who would have chosen Opinion B = 0.54
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error)
Critical value at 98% confidence interval for sample size of 1500 is obtained from the z-tables.
Critical value = 2.33
Standard error = σₓ = √[p(1-p)/n]
p = sample proportion = 0.54
n = sample size = 1500
σₓ = √(0.54×0.46/1500) = 0.0128685664 = 0.01287
98% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]
CI = 0.54 ± (2.33 × 0.01287)
CI = 0.54 ± 0.02998)
98% CI = (0.51, 0.57)
98% Confidence interval = (0.51, 0.57)
B) The number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B are both greater than 10. Why must this inference condition be met?
For this confidence interval to be obtained using sample data, a couple of conditions are necessary to be satisfied. They include;
- The sample data must have been obtained using a random sampling technique.
- The sampling distribution must be normal or approximately normal.
- The variables of the sample data must be independent of each other.
On the second point, the condition for a binomial distribution to approximate a normal distribution is that
np ≥ 10
and n(1-p) ≥ 10
The quantity np is the actual sample mean which is the actual number of buyers that chose Opinion B while n(1-p) is the number of buyers that did not chose Opinion B.
For the confidence interval obtained to be valid, the conditions stated must be satisfied and for the sampling distribution to be approximately normal, the number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B must both be greater than 10.
Hope this Helps!!!
Scouts of ABC school made to run around a regular hexagonal ground fig 9, of perimeter 270 m .If they started running from point X and covered two fifth (2/5th) of the total distance.Which side of the ground will they reach?
Answer:
Scouts are on the third side in the sense they are running
Step-by-step explanation:
A regular hexagonal shape of perimeter 270 has each side of 270/6 = 45
Let´s call d the run distance then
d = 2/5 * 270 d = 108 m
We don´t have fig 9 available therefore if X is a vertex in the hexagon or at the middle point of one side, scouts are 108 m from the starting point which means they had run 2,4 sides of the hexagon. If X is not either a vertex or a middle point of a side then, we have two solutions for the question depending on the sense the scouts took when began the run (clockwise or counterclockwise)
A traffic engineering study on traffic delay was conducted at intersections with signals on urban streets. Three types of traffic signals were utilized in the study: (1) pretimed, (2) semi-actuated, and (3) fully actuated. Five intersections were used for each type of signal. The measure of traffic delay used in the study was the average stopped time per vehicle at each of the intersections (seconds/vehicle). The data follow Pretimed Semi-actuated Fully actuated 36.6 17.5 15.0
39.2 20.6 10.4
30.4 18.7 18.9
37.1 25.7 10.5 34.1 22.0 15.2 Source: W. Reilly, C. Gardner, and J. Kell (1976). A technique for measurement of delay at intersections. Technical Report FHWA-RD-76- 135, Federal Highway Administration, Office of R &D, Washington, D.C. Use the data from Exercise 1 to determine how many intersections the traffic engineer would need for each type of traffic signal to reject the null hypothesis at the .01 level of significance witha power of .90 if mean delays at the three traffic signal types were 20, 18, and 16 seconds, respectively.
The average number of intersections the traffic engineer would need for each type of traffic signal to reject the null hypothesis at the 0.01 level of significance with a power of 0.90 is six
To test the effectiveness of these signals, the engineer must reject the null hypothesis, which states that there is no significant difference in the mean delays between the three types of signals. The engineer wants to reject the null hypothesis at the 0.01 level of significance with a power of 0.9. In other words, they want to be 90% sure that they can detect a significant difference if it exists.
Using the data provided in the study, the engineer can calculate the sample size needed for each type of signal. They need at least five intersections for pretimed signals, six intersections for semi-actuated signals, and four intersections for fully actuated signals to reject the null hypothesis at the desired level of significance with a power of 0.9.
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what is 1/2h + 2h + 3/2h - 1 simplified?
Answer:
4h-1
Step-by-step explanation:
subtracted it with a scientific calculator and that was the answer