We are given the following equation
\(y=x^5+5\)We are asked to find two different parametric equations for the above equation.
There are many different possibilities to write the parametric equations.
For example:
Let x = t and substitute it into the given equation
\(y=t^5+5\)So, we have got a set of parametric equations
\(x=t\quad and\quad y=t^5+5\)Similarly,
Let x = 2t and substitute it into the given equation
\(y=(2t)^5+5=2^5t^5+5=32t^5+5\)So, we have got another set of parametric equations
\(x=2t\quad and\quad y=32t^5+5\)Can someone help me?
Y=-x+3 is the slope-intercept form equation for the line.
What is meant by slope?The slope or gradient of a line is a numerical representation of a line's steepness and direction in mathematics. The reason for this usage is unknown, although it first appears in English in O'Brien (1844), who wrote "y = mx + b," and in Todhunter (1888), who wrote "y = mx + c." The letter m is widely used to signify slope.
The slope can be calculated by comparing the "vertical change" to "horizontal change" between any two distinct points on a line. In cases when the ratio is expressed as a quotient ("rise over run").
From the above graph,
The line is passing through the points (-1, 4) and (3, 0)
Let the slope intercept form be
y= mx +c
Slope m=(0-4/3+1)
=-4/4
= -1
y= -x+c
The equation is passing through the point (3, 0)
-3+c=0
c=3
y= -x+3
Therefore, y=-x+3 is the slope-intercept form equation for the line.
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The following measurements (in picocuries per liter) were recorded by a set of carbon dioxide detectors installed in a manufacturing facility: 799.2,784.3,803.8,806.8,780.5,794.8 Using these measurements, construct a 95% confidence interval for the mean level of carbon dioxide present in the facility. Assume the population is approximately normal. Step 3 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
(783.806 ; 805.994)
Step-by-step explanation:
Given the sample :
X : 799.2,784.3,803.8,806.8,780.5,794.8
Sample size, n = 6
Sample mean, xbar = Σx / n = 794.9
Sample standard deviation, s = 10.574 ( calculator)
Tcritical at 95%, df = 6 - 1 = 5 equals 2.57
Confidence interval :
Xbar ± standard error
Standard Error = Tcritical * s/√n
Standard error = 2.57 * 10.574/√6 = 11.094
Lower boundary = (794.9 - 11.094) = 783.806
Upper boundary = (794.9 + 11.094) = 805.994
(783.806 ; 805.994)
URGENT! Can someone please help?
a. The missing values of the logarithm expression is log₃(40).
b. The missing values of the logarithm expression is log₅(8).
c. The missing values of the logarithm expression is log₂(1/25).
What is the missing of the logarithm expression?The missing values of the logarithm expression is calculated as follows;
(a). log₃5 + log₃8, the expression is simplified as follows;
log₃5 + log₃8 = log₃(5 x 8) = log₃(40)
(b). The log expression is simplified as;
log₅3 - log₅X = log₅3/8
log₅X = log₅8
X = 8
(c). The log expression is simplified as;
-2log₂5 = log₂Y
log₂5⁻² = log₂Y
5⁻² = Y
1/25 = Y
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Henry loves to read. He reads 90 pages in one hour. How many pages does he read in 5 hours
Answer:
450
Step-by-step explanation: 90x 5 = 450 hoped i helped
If x>7, then |x|>7. |y|>7, so y=7
Valid or invalid?
\(\text{if }x>7\text{, then }|x|>7\) is a valid argument
\(|y|>7\text{, so }y=7\) is not a valid argument
For the first argument: \(\text{if }x>7\text{, then }|x|>7\)
From the definition of absolute value function
\(|x|=x\) if \(x\ge0\)
That is every positive number is its own absolute value. Since
\(x>7\implies x\ge0\),
we can argue that
\(x>7\implies |x|>7\)
so the first argument is valid
For the second argument: \(|y|>7\text{, so }y=7\)
From the definition of absolute value function
\(|y|:=\left \{ {y\text{ if }y\ge0}\atop{-y\text{ if }y<0} }\right\)
This means that
\(|y|>7:=\left \{ {y>7\text{ if }y\ge0}\atop{-y>7\text{ if }y<0} }\right\)
or
\(|y|>7:=\left \{ {y>7\text{ if }y\ge0}\atop{y<-7\text{ if }y<0} }\right\)
no part of the definition allow for the option \(y=7\). So the second argument is not valid.
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Employees at a company produced refrigerators on three shifts. Each shift recorded their quality stats below. A unit was considered defective if it at least one part was assembled wrong or was missing. Management believes that quality depends on the the shift it was produced. Test the claim that shifts are independent of quality using chi-square at alpha = 0.05. SHOW YOUR WORK
Answer:
Step-by-step explanation:
Hello!
So in the refrigerator factory there are three shifts. Each shift records their quality based on the quantity of defective and working parts assembled.
Using a Chi-Square test of independence you have to test the claim that quality and shifts are independent.
The hypotheses are:
H₀: The variables are independent.
H₁: The variables are not independent.
α: 0.05
\(X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~X_{(r-1)(c-1)}\)
r= total number of rows
c= total number of columns
i= 1, 2 (categories in rows)
j=1, 2, 3 (categories in columns)
To calculate the statistic you have to calculate the expected frequencies for each category:
\(E_{ij}= \frac{O_{i.}*O_{.j}}{n}\)
\(O_{i.}\) Represents the marginal value of the i-row
\(O_{.j}\) Represents the marginal value of the j-column
\(E_{11}= \frac{O_{1.}*O_{.1}}{n}= \frac{21*40}{120}= 7\)
\(E_{12}= \frac{O_{1.}*O_{.2}}{n}= \frac{21*40}{120}= 7\)
\(E_{13}= \frac{O_{1.}*O_{.3}}{n}= \frac{21*40}{120}= 7\)
\(E_{21}= \frac{O_{2.}*O_{.1}}{n}= \frac{99*40}{120}= 33\)
\(E_{22}= \frac{O_{2.}*O_{.2}}{n}= \frac{99*40}{120}= 33\)
\(E_{23}= \frac{O_{2.}*O_{.3}}{n}= \frac{99*40}{120}= 33\)
\(X^2_{H_0}= \frac{(7-7)^2}{7} + \frac{(5-7)^2}{7} + \frac{(9-7)^2}{7} + \frac{(33-33)^2}{33} + \frac{(35-33)^2}{33} + \frac{(31-33)^2}{33} = 1.385= 1.34\)
Using the critical value approach, the rejection region for this test is one-tailed to the right, the critical value is:
\(X^2_{(c-1)(r-1);1-\alpha }= X^2_{2; 0.95}= 5.991\)
Decision rule:
If \(X^2_{H_0}\) ≥ 5.991, reject the null hypothesis.
If \(X^2_{H_0}\) < 5.991, do not reject the null hypothesis.
The value of the statistic is less than the critical value, the decision is to not reject the null hypothesis.
At 5% significance level, you can conclude that the shift the pieces were assembled and the quality of said pieces are independent.
I hope this helps!
On average, a furniture store sells four card tables in a week. Assuming a Poisson distribution for the weekly sales, the probability that the store will sell exactly seven card tables in a given week is most nearly Select one: a. 0.11 b. 0.075 c. 0.15 d. 0.060
Answer:
Assuming a Poisson distribution for the weekly sales, the probability that the store will sell exactly seven card tables in a given week is 0.060
Step-by-step explanation:
In order to calculate the probability that the store will sell exactly seven card tables in a given week we would have to calculate the following formula:
probability that the store will sell exactly seven card tables in a given week= e∧-λ*λ∧x/x!
According to the given data furniture store sells four card tables in a week, hence λ=4
Therefore, probability that the store will sell exactly seven card tables in a given week=e∧-4*4∧7/7!
probability that the store will sell exactly seven card tables in a given week=0.060
Assuming a Poisson distribution for the weekly sales, the probability that the store will sell exactly seven card tables in a given week is 0.060
Brandon is going to invest in an account paying an interest rate of 5% compounded quarterly. How much would Brandon need to invest, to the nearest dollar, for the value of the account to reach $490 in 16 years?
Answer:
Brandon wants $490 in 16 years by investing "x" dollars in an account that pays 5% compounded quarterly. How much is "x"?
Principal = Total / [ (1 + (r/n) )^ n * years]
n = 4 (for compounded quarterly)
Principal = 490 / [ (1. + (.05/4)) ^ 4 * 16]
Principal = 490 / [ (1.0125)^ 64]
Principal = 490 / 2.2145324106
Principal = 221.2656710971
So, if we invested 221.27 for 16 years at 5% compounded quarterly interest, we would have a total of $490.00
Step-by-step explanation:
Answer:
221
Step-by-step explanation:
I just know
Prove your answer as to why 2 m, 2 m, and 4 m will or will not form a triangle.
Answer:
yes it is
Step-by-step explanation:
Answer:
Because the triangle with the legs 2 and 2 would need to have a third leg less than 4 and greater than 0 and a triangle with side lengths 2 and 4 would need a third side of less than 6 and greater than 2
Step-by-step explanation:
in January, Jamie pays $2.00 for a tube of toothpaste.
When she buys the same brand and size toothpaste in
February, she pays $2.25. what is the percent increase in the price of the toothpaste from january to february? round to the nearest tenth of a percent?
please hurry
Answer:
12% or 13% rounded
Step-by-step explanation:
.25 of 2.00 is .125 or 12% or 13% rounded
How could you correctly rewrite the equation 4(5 + 3) = 2(22 - 6) using the distributive property?
Answer:
We can correctly rewrite the equation: 4(5+3) = 2(22-6) by distributing each side.
4(5+3) = 2(22-6)
4(8) = 2(16)
32 = 32
Once you finish distributing each side, you can check to see if it is equal on both sides.
Step-by-step explanation:
Step-by-step explanation:
4(5 + 3) = 2(22 - 6)
4(8) = 2(16)
32 = 32
Which expression has a lesser value than -10? a. 8+ (-12)
b. – 14 – 2 + 8
c. 4-(-12)
d. - 2 +(- 12) + 2
please show work!
Answer:
D
Step-by-step explanation:
Which expression has a lesser value than -10?
a. 8+ (-12)= -4
b. – 14 – 2 + 8= -16+8= -8
c. 4-(-12)= 16
d. - 2 +(- 12) + 2 = -12
Answer:
Step-by-step explanation:
a.
8 +(-12) = 8-12 = -4
-4 > -10
b.
14-2+8 = 12+8 = 20
20 > -10
c.
4-(-12) = 4+12 = 16
16 > -10
d.
-2+(-12)+2 = -2-12+2 = -14+2 = -12
-12 < -10
The weight of potato chip bags filled by a machine at a packaging plant is normally distributed, with a mean of 15.0 ounces and a standard deviation of 0.2 ounces. What is the probability that a randomly chosen bag will weigh more than 15.6 ounces
Answer:
0.0013 = 0.13% probability that a randomly chosen bag will weigh more than 15.6 ounces.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 15.0 ounces and a standard deviation of 0.2 ounces.
This means that \(\mu = 15, \sigma = 0.2\)
What is the probability that a randomly chosen bag will weigh more than 15.6 ounces?
This is 1 subtracted by the p-value of Z when X = 15.6. So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{15.6 - 15}{0.2}\)
\(Z = 3\)
\(Z = 3\) has a p-value of 0.9987.
1 - 0.9987 = 0.0013
0.0013 = 0.13% probability that a randomly chosen bag will weigh more than 15.6 ounces.
Find the unit rate. 5/8 mile in 1/4 hour
Write a sine function with an amplitude of 5, a period of
Pi/8,and a midline at y = 7.
f(x) = 4sin(8x) + 5
f(x) = 5sin(16)+7
f(x) = 5sin(16x) + 4
f(x) = 4sin(8x) + 7
Answer:
\(\textsf{B)} \quad f(x) = 5 \sin (16x) + 7}\)
Step-by-step explanation:
The sine function is periodic, meaning it repeats forever.
Standard form of a sine function\(\boxed{f(x) = A \sin (B(x + C)) + D}\)
where:
A is the amplitude (height from the midline to the peak).2π/B is the period (horizontal distance between consecutive peaks).C is the phase shift (horizontal shift - positive is to the left).D is the vertical shift (y = D is the midline).Given values:
Amplitude, A = 5Period, 2π/B = π/8Phase shift, C = 0Vertical shift, D = 7Calculate the value of B:
\(\dfrac{2\pi}{B}=\dfrac{\pi}{8}\implies 16\pi=B\pi\implies B=16\)
Substitute the values of A, B C and D into the standard formula:
\(f(x) = 5 \sin (16(x + 0)) + 7\)
\(f(x) = 5 \sin (16x) + 7\)
Therefore, the sine function with an amplitude of 5, a period of π/8, and a midline at y = 7 is:
\(\Large\boxed{\boxed{f(x) = 5 \sin (16x) + 7}}\)
Can someone help find the surface area, then round the answer to the nearest whole number please?
The Surface Area of cylinders are: 100 yd² , 264 m², 226 mm²
The Surface Area of Can is 219 cm².
We know the formula for Surface Area of Cylinder
= 2πrh
1. Radius = 2 yd
Height = 8 yd
So, Surface Area of Cylinder
= 2πrh
= 2 x 3.14 x 2 x 8
= 100 yd²
2. Radius = 7 m
Height = 6 m
So, Surface Area of Cylinder
= 2πrh
= 2 x 3.14 x 6 x 7
= 264 m²
3. Radius = 3 mm
Height = 12 mm
So, Surface Area of Cylinder
= 2πrh
= 2 x 3.14 x 3 x 12
= 226 mm²
4. Radius = 3.5 cm
Height = 10 cm
So, Surface Area of Can
= 2πrh
= 2 x 3.14 x 3.5 x 10
= 219 cm²
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A 10 kg ball moves at a speed of 15m/s. The ball collides with a wall causing it to rebound in the opposite direction at a speed of 23 m/s.
Calculate the impulse on the ball?
Answer:
The impulse on an object is equal to the change in momentum of the object. In this case, the ball's initial momentum is 10 kg * 15 m/s = 150 kg m/s. After the collision, the ball's final momentum is -10 kg * 23 m/s = -230 kg m/s.
The change in momentum of the ball is: -230 kg m/s - 150 kg m/s = -80 kg m/s.
So, the impulse on the ball is -80 kg m/s.
This question on your unit test is a fill in the blank. Be prepared to type your answer. The graph show how many minutes it takes Ziah to run a certain distance in the city. What is the meaning of the point (4, 6)?
The point (4,6) means it took Ziah 4 minutes to run 6 blocks.
This is because any point is of the form (x,y) where in this case
x = number of minutes
y = number of blocks
What is the area of the square that measures 3.1 m on each side
The area of the square with a side length of 3.1 meters is 9.61 square meters.
To find the area of a square, we need to multiply the length of one side by itself. In this case, the square has a side length of 3.1 m.
Area of a square = side length × side length
Substituting the given side length into the formula:
Area = 3.1 m × 3.1 m
To perform the calculation:
Area = 9.61 m²
It's worth noting that when calculating the area, we are working with squared units. In this case, the side length is in meters, so the area is expressed in square meters (m²). The area represents the amount of space enclosed within the square.
Remember, to find the area of any square, you simply need to multiply the length of one side by itself.
The area of the square with a side length of 3.1 meters is 9.61 square meters.
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Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new matrix with the answers in it H. Then answer the following question: what is the element address H31. Round your answer to tenths place
Answer:
see attached
H31 = -0.2
Step-by-step explanation:
The matrix sum H is the element-by-element sum of corresponding elements of F and G. For example, H31 = F31 +G31 = -4.7 +4.5 = -0.2.
__
For repetitive calculations using the same formula, it is convenient to do them using a spreadsheet.
5. A group of students were asked whether they play a sport and whether
they like physical education class. The results are in the table.
Like Physical Education
Do Not Like Physical
Education
A 28%
B. 16%
c. 15%
Play a Sport
150
To the nearest percent, of students who play a sport, what percent do not
like physical education?
D. 7%
Do Not Play a Sport
Answer: 7
Step-by-step explanation:
The percentage of students who play a sport but do not like physical education = 16%
The correct answer is an option (B)
The complete two way frequency table for given situation would be,
Play a Sport Do not Play a Sport Total
Like Physical Education 150 72 222
Do Not Like Physical Education 28 164 192
Total 178 236 414
Now we find the percentage of students who play a sport, and do not like physical education.
The total number of students who play sport.
n = 178
And the number of students who play a sport but do not like physical education are 28.
Using percentage formula, the required percentgae would be,
P = 28/178 × 100
P = 15.73%
P ≈ 16%
Therefore, the correct answer is an option (B)
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Find the complete question below.
identify the x-values for which f(x)>-2
It should be noted that the expression that can be used to identify the x-values for which f(x)>-2 will be -2 <= x <= 2. This is illustrated in the graph.
How to explain the information?It should be noted that a graph is a diagram that is used to show the relationship that exists between the data presented or the information.
In this case, ut should be noted that the expression that can be used to identify the x-values for which f(x)>-2 will be -2 <= x <= 2. This is illustrated in the graph.
The graph is attached below.
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The equation for line p can be written as y= 9 7 x–9. Line q A line has a slope of
–
5
6
and passes through the point (18,
–
13). Write its equation in slope-intercept form.is perpendicular to line p and passes through (9, – 6). What is the equation of line q?
The equation of the line 'q' perpendicular to the line 'p' is y = - (7/9)x - 5.
What are lines and their slopes?We are aware that there are many types of equations for lines, with the general type being Ax + By + c = 0,
And the slope-intercept form equation is y = mx + b, m is the slope, and b is the y-intercept.
We know, Lines perpendicular to each other have slopes that are negative reciprocals of each other.
Therefore, The line q passing through (9, - 6) has a slope of - (7/9).
Now, - 6 = - (7/9)(9) + b.
- 6 = - 1 + b.
b = -5.
Hence, y = - (7/9)x - 5 is the equation of the line q.
Q. The equation for line p can be written as y= (9/7)x - 9.
Line q is perpendicular to line p and passes through (9, - 6), what is the equation of line q?
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refer to the work hrs.rds dataset. in this problem, we want to examine the effect of an hourly wage (wage), education (educ), and the number of children (nchild) on the hours worked per week by married women (hrswork).
The coefficient values will indicate the change in the dependent variable (hrswork) for a one-unit change in the independent variable (wage, educ, and nchild).
To examine this, we would use a regression analysis to look at the relationship between each of these variables and the hours worked per week. We would create a model with wage, educ, and nchild as the independent variables, and hrswork as the dependent variable. We can then analyze the coefficient of each of these variables to measure the effect they have on the hours worked per week. The coefficient values will indicate the change in the dependent variable (hrswork) for a one-unit change in the independent variable (wage, educ, and nchild).
1. Load the work hrs.rds dataset.
2. Examine the data to identify the independent and dependent variables. In this case, the independent variables are wage, educ, and nchild, and the dependent variable is hrswork.
3. Use a regression analysis to examine the relationship between the independent and dependent variables.
4. Create a model with wage, educ, and nchild as the independent variables, and hrswork as the dependent variable.
5. Analyze the coefficient of each of the independent variables to measure the effect they have on the dependent variable (hrswork).
6. Interpret the results to determine the effect of the independent variables on the dependent variable.
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4.23m 4.27m 3.98m his longest jump was how much longer compared to his shortest jump
Answer:
.29
Step-by-step explanation: Subtract first by last
Answer:
0.29m longer
Step-by-step explanation:
Longest jump = 4.27m
Shortest jump = 3.98m
4.27 - 3.98 = 0.29m
Determine the constant of proportionality in the situation below.
Every bag of peanuts costs $3.55
Answer:
The constant is that every bag costs $3.55
Step-by-step explanation:
When the bag of peanuts costs $3.55 then Constant of proportionality is 3.55
What is constant of proportionality?The constant of proportionality is the ratio between two directly proportional quantities
Here,
Every bag of peanuts costs $3.55
Consider the number of bags = x
Cost of the peanut bag = y
Therefore
y is directly proportional to x
y = kx
Where k is the constant of proportionality
k = \(\frac{y}{x}\)
if the cost of the one bag is $3.55
Then \(k=\frac{3.55}{1}\)
k=3.55
Hence, When every bag of peanuts cost constant of proportionality is 3.55
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This is a parallelogram and I need help finding AB
The lenght of AB side is 4.
To be a parallelogram, the length of parallel sides must be the same. This is a propierty of parallelograms.
In a parallelogram:
\(AB\parallel CD\Rightarrow AB=CD\)Now all we have to do is solve the equation:
\(\begin{gathered} 4Q-8=Q+4 \\ 3Q=12 \\ Q=4 \end{gathered}\)Now we know the value of Q and we can replace it in AB=4Q-8
\(\begin{gathered} AB=4\cdot4-8 \\ AB=8 \end{gathered}\)The lenght of AB is 8.
To be sure we can check what happends when we replace Q in CD=Q+4
\(\begin{gathered} CD=4+4 \\ CD=8 \end{gathered}\)With this, AB=CD and we know we have the correct answer
Gym City charges a $30 sign-up fee, plus a monthly fee of $25. FitnessExpress charges a $20 sign-up fee, plus a monthly fee of $30. How muchmoney would Leslie save in a 6-month period by joining Gym City insteadof Fitness Express? PLSSSS
Answer:
$20
Step-by-step explanation:
Gym city fees are:
Sign up = 30
6 monthly sub = 6 x 25 = 150
Total fees = 30 + 150
FitnessExpress fees are:
Sign up = 20
6 monthly sub = 6 x 30 = 180
Total fees = 20 + 180 = 200
Therefore, the difference between the two is $20
Pls someone help meee!!!!
Answer:
10x
Step-by-step explanation:
Answer:
10 x
Step-by-step explanation:
I think it's the answer
1. a committee consists of 4 chemical engineers and 3 electrical engineers. this committee is to be formed from a group of 6 chemical engineers and 5 electrical engineers. find the number of ways in which this can be done if (a) any ee and any ce can be included. (b) one particular ce must be in the committee. (c) two particular ce cannot be in the same committee.
A) There are 330 possible ways to form the committee if any EE and any CE can be included.
B) There are 210 possible ways to form the committee if one particular CE must be in the committee.
C) The total number of ways to form the committee with two particular CE excluded is 205
In this case, we are given a scenario where a committee is to be formed from a group of chemical and electrical engineers. Let's dive into the details of the problem and explore how probability can be used to solve it.
(a) If any EE and any CE can be included, we need to find the number of ways to form a committee of 7 members from a group of 6 CE and 5 EE. In this case, the order in which the committee members are selected does not matter, so we can use the formula for combinations.
The total number of ways to select 7 members from a group of 11 engineers is given by:
C(11,7) = 11! / (7! * 4!) = 330
(b) If one particular CE must be in the committee, we can first select that CE and then form the rest of the committee from the remaining engineers. The probability of selecting that particular CE is 1/6, since there are 6 CE in total.
Once we have selected that particular CE, we need to select 6 more members from a group of 5 EE and 5 CE (excluding the one we have already selected). The total number of ways to do this is given by:
C(10,6) = 10! / (6! * 4!) = 210
(c) If two particular CE cannot be in the same committee, we can use the principle of inclusion-exclusion to find the total number of ways to form the committee.
First, we find the total number of ways to form the committee without any restrictions. This is given by:
C(11,7) = 330
Next, we find the number of ways to form the committee with both particular CE included. This is given by:
C(9,5) = 126
We subtract this from the total number of ways to form the committee to get the number of ways with at least one of the particular CE excluded:
330 - 126 = 204
However, we have counted the case where both particular CE are excluded twice, so we need to add this back in:
C(7,7) = 1
Therefore, the total number of ways to form the committee with two particular CE excluded is:
204 + 1 = 205
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