Answers
Hi there!
\(\large\boxed{y = 12, x = 3}\)
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Related Questions
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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The summit of a volcano is 5 kilometers (km) above sea level, as shown below.
If the ocean floor has an elevation of -5 kilometers, which statement describes
the distance of the summit and the ocean floor?
It's not 0 or 5
Answers
Which fraction is equivalent to 6/10
Answers
Answer:
12/20
Step-by-step explanation:
Please help with number 14
Answers
Answer:
the answer is b 4x^2-x+1
Step-by-step explanation:
can i get brainliest?
A group of people are surveyed about whether they prefer to bike or run to exercise, and whether they prefer summer or winter weather. The results are in the table.
bike run
summer 108 212
winter 98
What value could go in the blank cell so that the percentage of people who like to bike and also prefer winter weather is 10%?
Answers
Answer:
10.8
Step-by-step explanation:
An expression is written as m−5(m+3) +7m.
What is the value of the expression when m=x+1?
Answers
(x+1)-5(x+4)
x + 1 - 5x - 20
-4x - 19
Calculate the actual sales since the sales and sales tax were rung up together. Assume sales tax of 6% and total sales of $33,000.
Answers
Answer:
the actual sales be $31,132
Step-by-step explanation:
The computation of the actual sales is as follows:
Let us suppose the actual sales be x
Now the sales tax be 0.06x
Now the total sales would be
x + 0.06x = $33,000
1.06x = $33,000
x = $33,000 ÷ 1.06
= $31,132
hence, the actual sales be $31,132
The same is to be considered by applying the above equation
Answer:
actual sales be $31,132
Step-by-step explanation:
MO
C
15 in
115
The triangle above has the following measures.
Use the 45 45 90 Triangle Theorem to find the
length of the hypolenuse Include correct units
Show all your work
Answers
The length of the hypotenuse of the triangle is b = x√2 units
Given data ,
Let the triangle be represented as ΔABC
And , the triangle is a 45 - 45 - 90 triangle
So , the two legs are congruent to one another and the non-right angles are both equal to 45 degrees
And , the sides are in the proportion x : x : x√2
Now , the length of the sides of the triangle are
The measure of base BC = a units = x
The measure of height AB = c units = x
So , the measure of the hypotenuse of the triangle is = x√2 units
Hence , the triangle is solved and hypotenuse AC = x√2 units
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Solve for x:
7x - 3x + 11 = 27
Answers
4x=16
16/4=x
x=4
Answer:
-10
Step-by-step explanation:
Factorize cos²A+3cosA+2
Answers
Answer:
(cosA+2)(cosA+1)
Step-by-step explanation:
cos^2A+cosA+2cosA+2
=cos(A)(cosA+1)+2(cosA+1)
=(cosA+2)(cosA+1)
1. The mean number of siblings for respondents in a survey is 3.76 with a standard deviation of 3.18. Calculate the Z score associated with 3 siblings. Your answer should be rounded to two decimal places, like 5.43 or 1.30.
2. The mean number of siblings for respondents in a survey is 3.76 with a standard deviation of 3.18. Using the standard normal table, calculate the proportion of respondents who had more than 2 siblings. Your answer should be rounded to two decimal places, like 0.43 or 0.30.
Answers
Answer:
-0.24 ; 0.71
Step-by-step explanation:
Given that :
Mean number of siblings (m) = 3.76
Standard deviation (s) = 3.18
Z score associated with 3 siblings
x = 3
Using the relation :
Zscore = (x - m) / s
Zscore = (3 - 3.76) / 3.18
Zscore = - 0.76 / 3.18
Zscore = −0.238993
Zscore = - 0.24
2.) proportion of respondents with more than 2 siblings
Using the z probability calculator :
X > 2
Obtain the standardized score :
Zscore = (x - m) / s
Zscore = (2 - 3.76) / 3.18
Zscore = - 1.76 / 3.18
Zscore = −0.5534591
Zscore = - 0.55
Using the z table :
P(Z ≥ - 0.55) = 1 - p(Z ≤ - 0.55) ; p(Z ≤ - 0.55) = 0.2912
1 - p(Z ≤ - 0.55) = 1 - 0.2912 = 0.7088 = 0.71
Suppose that $7500 is placed in an account that pays 6% interest compounded each year.
Assume that no withdrawals are made from the account.
Follow the instructions below. Do not do any rounding.
(a) Find the amount in the account at the end of 1 year.
(b) Find the amount in the account at the end of 2 years
Answers
a) The compounded amount in the account at the end of 1 year is $7,950.
b) The compounded amount in the account at the end of 2 years is $8,427.
What is compound interest?Compound interest is the interest added to the principal amount after each period in order to compute the period's interest.
By compounding, we mean that accumulated interest is added to the principal to compute the subsequent interest.
Compound interest is unlike simple interest, which does not compound interest.
The compound interest formula is:
A = P(1 + r/n)^nt
A = Final amount
P = initial principal balance
r = interest rate
n = number of times interest is applied per time period
t = number of time periods elapsed
Since this investment is compounding annually, we can find the final amount at the end of each year using the common formula as follows:
A = P(1 + r)ⁿ
Principal = $7,500
Compound interest rate = 6%
Compounding period = Annually
Amount at the end of Year 1 = $7,950 ($7,500 x 1.06¹)
Amount at the end of Year 2 = $8,427 ($7,500 x 1.06²)
Thus, the compounded amount at the end of year 1 is $7,950 and $8,427 at the end of year 2.
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Given a normal distribution with (mean) μ= 50 and (standard deviation) σ = 4, what is the probability that:__________.
a) x>43
b) x<42
c) x>57.5
d) 42
e) x<40 or x>55
f) 5% of the values are less than what X value?
g) 60% of the values are between what two X values (symmetrically distributed around the mean)?
h) 85% of the values will be above what X value?
Answers
Answer:
a) P(x > 43) = 0.9599
b) P(x < 42) = 0.0228
c) P(x > 57.5) = 0.03
d) P(x = 42) = 0.
e) P(x<40 or x>55) = 0.1118
f) 43.42
g) Between 46.64 and 53.36.
h) Above 45.852.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the zscore of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
\(\mu = 50, \sigma = 4\)
a) x>43
This is 1 subtracted by the pvalue of Z when X = 43. So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{43 - 50}{4}\)
\(Z = -1.75\)
\(Z = -1.75\) has a pvalue of 0.0401
1 - 0.0401 = 0.9599
P(x > 43) = 0.9599
b) x<42
This is the pvalue of Z when X = 42.
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{42 - 50}{4}\)
\(Z = -2\)
\(Z = -2\) has a pvalue of 0.0228
P(x < 42) = 0.0228
c) x>57.5
This is 1 subtracted by the pvalue of Z when X = 57.5. So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{57.5 - 50}{4}\)
\(Z = 1.88\)
\(Z = 1.88\) has a pvalue of 0.97
1 - 0.97 = 0.03
P(x > 57.5) = 0.03
d) P(x = 42)
In the normal distribution, the probability of an exact value is 0. So
P(x = 42) = 0.
e) x<40 or x>55
x < 40 is the pvalue of Z when X = 40. So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{40 - 50}{4}\)
\(Z = -2.5\)
\(Z = -2.5\) has a pvalue of 0.0062
x > 55 is 1 subtracted by the pvalue of Z when X = 55. So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{55 - 50}{4}\)
\(Z = 1.25\)
\(Z = 1.25\) has a pvalue of 0.8944
1 - 0.8944 = 0.1056
0.0062 + 0.1056 = 0.1118
P(x<40 or x>55) = 0.1118
f) 5% of the values are less than what X value?
X is the 5th percentile, which is X when Z has a pvalue of 0.05, so X when Z = -1.645.
\(Z = \frac{X - \mu}{\sigma}\)
\(-1.645 = \frac{X - 50}{4}\)
\(X - 50 = -1.645*4\)
\(X = 43.42\)
43.42 is the answer.
g) 60% of the values are between what two X values (symmetrically distributed around the mean)?
Between the 50 - (60/2) = 20th percentile and the 50 + (60/2) = 80th percentile.
20th percentile:
X when Z has a pvalue of 0.2. So X when Z = -0.84.
\(Z = \frac{X - \mu}{\sigma}\)
\(-0.84 = \frac{X - 50}{4}\)
\(X - 50 = -0.84*4\)
\(X = 46.64\)
80th percentile:
X when Z has a pvalue of 0.8. So X when Z = 0.84.
\(Z = \frac{X - \mu}{\sigma}\)
\(0.84 = \frac{X - 50}{4}\)
\(X - 50 = 0.84*4\)
\(X = 53.36\)
Between 46.64 and 53.36.
h) 85% of the values will be above what X value?
Above the 100 - 85 = 15th percentile, which is X when Z has a pvalue of 0.15. So X when Z = -1.037.
\(Z = \frac{X - \mu}{\sigma}\)
\(-1.037 = \frac{X - 50}{4}\)
\(X - 50 = -1.037*4\)
\(X = 45.852\)
Above 45.852.
mr. g finds a house for $155,000. He meets with the bank and finds a 30 year simple interest mortgage. If mr g accepts the mortgage, he would pay $232,500 in simple interest over the life of his loan. How much is his interest rate?
Answers
The interest rate on the mortgage is 5 %
What is the interest rateLet's begin by using the formula for simple interest:
I = P * r * t
where I is the interest, P is the principal (the amount borrowed), r is the interest rate, and t is the time (in years).
For Mr. G's mortgage, we know that the principal is $155,000 and the time is 30 years. We can use this information to solve for the interest rate, r.
First, we need to calculate the total amount that Mr. G will pay over the life of the loan (the principal plus the interest):
A = P + I
where A is the total amount, P is the principal, and I is the interest.
We know that Mr. G will pay $232,500 in interest, so we can solve for A:
Let's begin by using the formula for simple interest:
I = P * r * t
where I is the interest, P is the principal (the amount borrowed), r is the interest rate, and t is the time (in years).
For Mr. G's mortgage, we know that the principal is $155,000 and the time is 30 years. We can use this information to solve for the interest rate, r.
First, we need to calculate the total amount that Mr. G will pay over the life of the loan (the principal plus the interest):
A = P + I
where A is the total amount, P is the principal, and I is the interest.
We know that Mr. G will pay $232,500 in interest, so we can solve for A:
A = P + I
A = $155,000 + $232,500
A = $387,500
Now we can use the formula for simple interest to solve for the interest rate, r:
I = P * r * t
$232,500 = $155,000 * r * 30
r = $232,500 / ($155,000 * 30)
r = 0.05 or 5%
Therefore, Mr. G's interest rate is 5%.
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Negative 1/3 in decimal form
Answers
Answer:
-0.3333334
Step-by-step explanation:
common sense
Answer:
-0.33
Step-by-step explanation:
At a workshop , each of the 100 participants hugs each other participants once. Find the total number of hugs?
Answers
Answer:
10000
Step-by-step explanation:
100 hugs x 100 hugs
= 10,000 hugs.
A function is shown: f(x)= 2/3x+3
What is the value of f(18)?
Answers
Answer:
15
Step-by-step explanation:
When you see something like f (18), this means 18 needs to be plugged in for x
let's plug in 18
f (18) = \(\frac{2}{3} (18) + 3\)
Let's solve
(18 × 2) ÷ 3 = 12
12 + 3 = 15
f (18) = 15
Find the volume of a cone of radius 3.5cm and vertical height 12 cm.
Answers
Answer:
Volume ≈ 153.93804 cm^3
Rounded to the nearest whole number, the volume of the cone is approximately 154 cm^3.
Step-by-step explanation:
Please help me!! I need help asap
Answers
Newton's Law of Cooling/Warming
21. Suppose a pizza is removed from an oven at 400°F into a kitchen whose
temperature is a constant 80°F. Three minutes later the temperature of the
pizza is found to be 275°F.
(a) What is the temperature T() of the pizza after 5 minutes?
(b) Determine the time when the temperature of the pizza is 150°F.
(c) After a very long period of time, what is the approximate temperature of
the pizza?
Answers
After answering the presented question, we can conclude that As a equation result, the pizza's temperature after 5 minutes is 320°F.
What is equation?In mathematics, an equation is a statement that states the equality of two expressions. An equation consists of two sides separated by an algebraic equation (=). The argument \("2x + 3 = 9," f\)or example, states that the sentence "2x Plus 3" equals the value "9." The goal of solving equations is to find the value or values of the variable(s) that will allow the equation to be true. Equations can be simple or complex, linear or nonlinear, and contain one or more parts. In the equation\("x^2 + 2x - 3 = 0,"\)the variable x is raised to the second power. Lines are used in many areas of mathematics, including algebra, calculus, and geometry.
Let T(t) be the temperature of the pizza at time t, where t is in minutes. Then,
(a) Applying the Newton's Law of Cooling calculation, we get:
(T(0) - 80) / (400 - 80) = k (where k is the proportionality constant) (where k is the proportionality constant)
When we solve for k, we get:
k = (T(0) - 80) / 320
(T(3) - 80) / (400 - 80) = (T(0) - 80) / 320
T(0) = 400 - 320 * (T(3) - 80) / 320 = 400 - (T(3) - 80) = 320 + 80 = 400°F
(T(5) - 80) / (400 - 80) = (T(0) - 80) / 320
(T(5) - 80) / 320 = (400 - 80) / 320
T(5) - 80 = 3 * (400 - 80) / 4
T(5) = 3 * 320 / 4 + 80 = 240 + 80 = 320°F
As a result, the pizza's temperature after 5 minutes is 320°F.
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After completing your analysis of the rating system, you determine that any rating greater than or equal to 3.5 points can be considered a high rating. You also know that Chocolate and Tea considers a bar to be super dark chocolate if the bar's cocoa percent is greater than or equal to 70%. You decide to create a new data frame to find out which chocolate bars meet these two conditions.
Assume the first part of your code is:
best_trimmed_flavors_df <- trimmed_flavors_df %>%
You want to apply the filter() function to the variables Cocoa.Percent and Rating. Add the code chunk that lets you filter the data frame for chocolate bars that contain at least 70% cocoa and have a rating of at least 3.5 points.
What rating appears in row 1 of your tibble?
0 / 1 point
3.75
3.50
4.25
4.00
Answers
As a result, option two (3.50) is correct.
Step-by-step explanation:
The code chunk that allows you to filter the data frame for chocolate bars with at least 70% cocoa and a rating of at least 3.5 pounds is as follows
∴ filter(Cocoa, percent>='70%'&Rating>=3.5)
Therefore, the code you write is facet wrap(Cocoa. Percent). Facet wrap() is a function in this code chunk that allows you to wrap a variable's facets. All of the ingredients are derived from cocoa beans. Cacao solids (the "brown" part, which contains health benefits and the unmistakable chocolatey flavor) and cacao butter (the "white" part, which contains the chocolate's fatty component) are split in proportion.
As a result, 3.5 appears in row 1 of your Tibble.
Other options I (iii), and (iv) are incorrect because the question states that any rating greater than or equal to 3.5 points can be considered a
high rating, and the rating here should be 3.5, not 3.75, 4.25, or 4
So, option (ii) is correct.
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A building casts a shadow of 30ft.
At the same time, a 6ft person casts a shadow of 4ft.
How tall is the building?
Answers
Answer:
45
Step-by-step explanation:
Subtract 89.768 from 201.316
show your work
Answers
Answer:
111.548
-------------------------------
Subtract 201 from 89.
\(201 - 89 = 112\)
we can estimate the answer will be close to 112
Next, work with the decimals. Note that the more you subtract, the bigger the decimal places get.
\(0.768 - 0.316 = 0.452\)
Round 0.452 up from the hundredths place to nearest tenths place.
\(0.452 = 0.5\)
Since the decimal place is bigger, estimate 0.55 instead.
Subtract 0.22
\(0.55 - 0.2 = 0.548\)
Add this number to 112
\(112 + 0.548 = 112.548\)
Subtract 1 because of the estimate.
\(112 - 1 = 111\)
Therefore, we have 111.548 based off of subtracting and estimating in a specific method.
which statement is true about this equation?
y = -3x^2 + 4x - 11
a) it represents a function only
b) it represents a relation only
c) it represents both a relation and a function
d) it represents neither a relation nor not function
Answers
Answer:
C
Step-by-step explanation:
it represents both a relation and a function
Answer:
The correct answer is C. It represents both a relation and a function.
Step-by-step explanation:
I got it right on the Edmentum test.
rewrite 1/12 x^3 y + 5/12 xy^2 using a common factor
1/6 xy(2x2 + 5y)
1/6 x2y(2x + 5y)
1/12 xy(x2 + 5y)
1/12 x3y(y + 5)
Answers
The expression using the common factor is 1/12xy(x² + 5y)
How to rewrite the expression using the common factor?From the question, we have the following parameters that can be used in our computation:
1/12 x^3 y + 5/12 xy^2
Rewrite properly
So, we have
1/12x³y + 5/12xy²
Factor out 1/12 from the expression
So, we have the following representation
1/12(x³y + 5xy²)
Factor out x from the expression
So, we have the following representation
1/12x(x²y + 5y²)
Factor out y from the expression
So, we have the following representation
1/12xy(x² + 5y)
Hence, the expression is (c) 1/12xy(x² + 5y)
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Answer:The expression using the common factor is 1/12xy(x² + 5y)
Step-by-step explanation:
What is the unit digit of 8433165483 x 946621539 x 5514381138
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The value of the unit digit 8433165483 x 946621539 x 5514381138 will be6.
What is the fundamental principle of multiplication?Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.
For getting a number, we will first multiply each digit by its position and then;
8433165483 x 946621539 x 5514381138
Which is;
3 x 9 x 8
= 27 x 8 = 216
Therefore, the unit digit number will be 6.
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Vectors u and v are shown on the graph.
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29. Assertion :7√5, √2+21 are the irrational number. Reason: every integer is an rational number 30.
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The assertion is true. Both 7√5 and √2 + 21 are irrational numbers because they cannot be expressed as fractions.
The assertion is true. Both 7√5 and √2 + 21 are irrational numbers.
An irrational number is defined as a number that cannot be expressed as a fraction of two integers and has an infinite non-repeating decimal representation.
In the case of 7√5, the square root of 5 is an irrational number because it cannot be expressed as a fraction. Multiplying it by 7 does not change its irrational nature.
Similarly, √2 is also an irrational number because the square root of 2 cannot be expressed as a fraction. Adding 21 to √2 does not alter its irrationality.
The reason provided, that every integer is a rational number, is not relevant to the given assertion. While it is true that every integer is a rational number because it can be expressed as a fraction (e.g., 3 can be written as 3/1), it does not contradict the fact that 7√5 and √2 + 21 are irrational numbers.
In conclusion, the assertion is valid, and both 7√5 and √2 + 21 are irrational numbers.
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can anyone help me with this. please
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Answer:
Step-by-step explanation:
using pythagoras theorem
a^2+b^2=c^2
7^2+KL^2=25^2
49+KL^2=625
KL^2=625-49
KL=\(\sqrt{576\)
KL=24
take M as reference angle
using tan rule
tan M=/opposite/adjacent
tan M=KL/ML
tan M=24/7
Can someone please help me please?
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5x-3/x-1