Find the total surface area of the cylinder
Give your answer to 1 decimal place
Radius= 24cm
length=18cm
Note: Answer must have the units "cm^2"

The best answer regarding the effects of carbon monoxide is option c, CO results in less oxygen loading hemoglobin but unloading is not changed.

Carbon monoxide binds up more tightly to the hemoglobin as compared to the oxygen molecules. This reduces the oxygen-carrying capacity of the blood and results in less oxygen loading onto hemoglobin.

However, once oxygen is already bound to hemoglobin, CO does not significantly affect its release or unloading. Therefore, option c is the most accurate statement among the given choices.

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The total area of the given shape is 71cm².

The size of a section on a surface is determined by its area. Surface area refers to the area of an open surface or the border of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a shape or planar lamina. A shape's area can be calculated by contrasting it with squares of a known dimension. The square meter (abbreviated as m²), which is the area of a square whose sides are one metre long, is the common measure of area in the International System of Units (SI). Three such squares would be the same size as a shape with a three square metre surface.

The following figure can be divided into a rectangle 7cm x 8cm and a triangle of height and base 6 cm and 5 cm respectively.

Area of rectangle= 7*8= 56 cm²

Area of triangle= 1/2* base*height= 1/2*6*5 = 15 cm²

Total area of shape = 56+15= 71 cm²

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Answer:

0.3571

Step-by-step explanation:

Hope this helps!

Answer:

x = 1.5 or 3/2

Step-by-step explanation:

First, expand the equation.

(2x - 3)² = 0

(2x - 3)(2x - 3) = 0

In similar equations, we would solve for both pairs of parenthesis. However, since the equations inside both are the same, we only need to solve for ONE of them, bringing one correct answer.

2x - 3 = 0

Add 3 to both sides.

2x = 3

Divide both sides by 2.

x = 3/2 or 1.5.

Step-by-step explanation:

The equation of the line parallel to the given line is y + 4x = 22

The given line is y= -4x+1

Slope of the line = -4

Slope of the parallel line= -4

Equation of the line parallel to the given line which passes through C(6,4)

y - 6 = - 4 ( x - 4 )

y - 6 = -4x + 16

y + 4x = 22

Hence the equation of the parallel line is y + 4x = 22

One that stretches on all sides and has no width is referred to in geometry as a line. A straight line is, to put it simply, a line without bends. An non-curved line that extends to infinity on both sides is said to be straight.

The general equation for a straight line is y = mx + c, where m stands for the line's slope and c for its y-intercept. The most frequently used straight line equation is one that has to do with geometry.

The equation of a straight line can be written in a number of different ways, such as point-slope form, slope-intercept form, general form, standard form, etc.

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The approximate standard deviation is B) 37.8.

To find the approximate standard deviation of the final exam scores, we can use the properties of the normal distribution and percentiles.

First, let's find the z-value that corresponds to the closest area to 35% in the normal table. From the table, we find that the z-value is approximately -0.385.

Since the percentile corresponds to the area under the normal curve, we know that the score 42 is located at approximately -0.385 standard deviations from the mean.

Similarly, the z-value corresponding to the 70th percentile is approximately 0.525. The score 76 is located at approximately 0.525 standard deviations from the mean.

By subtracting the z-values corresponding to the percentiles, we can find the approximate number of standard deviations between 42 and 76.

0.525 - (-0.385) = 0.91

This means that the distance between 42 and 76 is approximately 0.91 standard deviations.

To find the approximate standard deviation, we divide this distance by the number of standard deviations.

Since we know that 0.91 standard deviations correspond to a range of 34 (76 - 42), we can set up the proportion:

0.91 / x = 34 / x

Solving for x, we find:

x = 34 / 0.91 ≈ 37.36

Therefore, the approximate standard deviation of the final exam scores is approximately 37.36.

Among the given answer choices, the closest option is B. 37.8.

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Answer:

1050

Step-by-step explanation:

We can use a  ratio to solve

First find how many jam

210 - 189 =21

We want to find how many jam for 10500 printed

21 jam              x jam

-----------       = ----------------

210 printed          10500 printed

Using cross products

21 * 10500 = 210x

Divide each side by 210

21*10500/210 =x

1050=x

The length of the model car based on the information is 0.8 feet.

It should be noted that scale simply shows the relationship between a measurement on a model as well as the corresponding measurement on the actual object.

From the information, the model car is constructed with a scale of 1:15.

When the actual car is 12 feet long, the length of the model will be illustrated as x. This will be:

= 1/15 = x / 12

Cross multiply

15x = 1 × 12

15x = 12

Divide

x = 12 / 15

x = 0.8

The length is 0.8 feet.

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This integral can be evaluated using standard techniques of integration, but the result will be a complicated expression.

To evaluate the triple integral ∭exdv over the solid e bounded by the paraboloid x=9y^2+9z^2 and the plane x=9, we will use cylindrical coordinates.

First, we need to determine the limits of integration for each variable.

In cylindrical coordinates, we have x = rcosθ, y = rsinθ, and z = z. The paraboloid x = 9y^2 + 9z^2 can be rewritten in cylindrical coordinates as:

rcosθ = 9r^2sin^2θ + 9z^2

Simplifying this expression, we get:

r = 9sin^2θ + 9z^2cos^2θ

The limits of integration for r are from 0 to 3sinθcosθ, which is the maximum value of r for a given θ that lies on the paraboloid x = 9y^2 + 9z^2.

The limits of integration for θ are from 0 to π/2, since the paraboloid is symmetric about the yz-plane.

The limits of integration for z are from 0 to √((9 - x)/9), which is the equation of the plane x = 9. In cylindrical coordinates, this becomes z = √((9 - rcosθ)/9).

Therefore, the triple integral becomes:

∭e ex dv = ∫0^(π/2) ∫0^(3sinθcosθ) ∫0^√((9 - rcosθ)/9) e(r cosθ, r sinθ, z) dz dr dθ

This integral can be evaluated using standard techniques of integration, but the result will be a complicated expression.

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The visibility requirement is 3 statute miles, and cloud clearance requires maintaining 500 feet below, 1,000 feet above, and 2,000 feet horizontally from clouds during VFR daylight operations over Coopers Town.

The visibility and cloud clearance requirements to operate VFR during daylight hours over the town of Coopers Town between 1,200 feet AGL and 10,000 feet MSL are as follows:

1. Visibility: The minimum visibility required is 3 statute miles.

2. Cloud clearance: Maintain a distance of at least 500 feet below, 1,000 feet above, and 2,000 feet horizontally from clouds.

According to VFR regulations, pilots flying during daylight hours must adhere to certain visibility and cloud clearance requirements for safety. The visibility requirement of 3 statute miles means that the pilot must have a clear horizontal view of at least 3 miles ahead.

This ensures sufficient visual reference to navigate and avoid other aircraft or obstacles.

Regarding cloud clearance, pilots must maintain a safe distance from clouds to ensure visibility and separation from potential hazards. The requirement is to remain at least 500 feet below clouds to avoid inadvertently entering them.

Additionally, pilots must maintain a minimum of 1,000 feet above clouds to prevent the risk of collision or reduced visibility due to cloud turbulence. Lastly, a horizontal separation of 2,000 feet from clouds helps ensure adequate maneuvering space and visual reference in relation to cloud formations.

These visibility and cloud clearance requirements help maintain safety and situational awareness for VFR operations during daylight hours over Coopers Town.

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To find the roots of a third-degree polynomial, also known as a cubic polynomial, we can use a method called factoring or apply the cubic formula.

The first step is to check if there are any common factors that can be factored out. Next, we can use the rational root theorem to determine potential rational roots. By applying synthetic division or long division, we can divide the polynomial by the potential roots to see if they are indeed roots.

If a rational root is found, we can then use synthetic division to factor out the corresponding quadratic equation. Finally, we can solve the quadratic equation using methods like factoring, completing the square, or using the quadratic formula to find the remaining roots.

It's important to note that not all cubic polynomials can be easily factored or solved algebraically. In such cases, numerical methods or approximation techniques may be used to find the roots.

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To find the roots of a third degree polynomial, you can follow these steps: 1) Check for rational roots using the Rational Root Theorem. 2) Use synthetic division to divide the polynomial by a linear factor. 3) Factor the resulting quadratic equation. 4) Solve for the roots by setting each factor equal to zero.

To find the roots of a third degree polynomial, we can follow these steps:

Remember, the Fundamental Theorem of Algebra states that every polynomial equation of degree n has exactly n complex roots, counting multiplicities.

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Answer:

A and C

Step-by-step explanation:

Answer: x= 7191.509 ft

Step-by-step explanation:

Sin9/1 = 1125/x

X/1 = 1125/sin9

Answer:

Ok I gotchu!

5/16 I think-

Step-by-step explanation:

Answer: 7 hundreds are in 700

Step-by-step explanation: because if you divide 700 by 100 it equals 7.

The approximate value for the probability that at least 80 flips are necessary is 0.3897.

Given:

a fair coin is flipped repeatedly until 50 heads are observed

using the central limit theorem, calculate an approximate value for the probability that at least 80 flips are necessary.

P (h>25)=p(h>=26)= 1-p(h<=26)

Assume the situation is approximately normal

u= np =50(1/2)=25 , s=√(npq) = √( 50)(.5)(.5) =√12.5

z=(x-u)/s = ( 26–25)/√12.5 = 0.283

P(z=0.283) =0.1103

Edit p(z>0.283)=0.1103

P(h <= 80)= 0.5+ 0.1103= 0.6103

P(h>=80) 1 - 0.6103 = 0.3897

Hence we get the required answer.

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Answer:

about $45.71

Step-by-step explanation

32/70%

32 x 100/70

32 x 10/7

320/7

$45.71

The original price would be $41.6.

The total cost to operate 5 fluorescent 40w light bulbs for the months of April and May if they are on for 3 hours/day is given as follows:

$1,830.

The total cost is obtained applying the proportions in the context of the problem.

The number of kilowatt hours is given as follows:

Hence:

200 x 61 x 3 = 36,600 kwh.

The cost is of $0.05 per kwh, hence the total cost is given as follows:

0.05 x 36600 = $1,830.

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Based on the given data, the process is out of control.

To determine if the process is still in control, we need to compare the new sample measurements to the control limits established in the X-bar and R control charts.

For the X-bar chart:

The UCL (Upper Control Limit) is calculated as the grand average (X-Double Bar) plus A2 times R-Bar:

UCL = 25 + (0.483 * 5) = 27.415

The LCL (Lower Control Limit) is calculated as the grand average (X-Double Bar) minus A2 times R-Bar:

LCL = 25 - (0.483 * 5) = 22.585

For the R chart:

The UCL (Upper Control Limit) for the R chart is calculated as D4 times R-Bar:

UCL = 2.004 * 5 = 10.020

The LCL (Lower Control Limit) for the R chart is 0.

Given the new sample measurements: 33, 37, 25, 35, 34, and 32, we can determine if any of the measurements fall outside the control limits. If any data point falls outside the control limits, it indicates that the process is out of control.

Upon comparing the new sample measurements to the control limits, we find that the measurement 37 exceeds the UCL of the X-bar chart. Therefore, the process is considered out of control.

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Answer:

All students at the university who participate in the intramural football league

Step-by-step explanation:

just did it

The graph of the system is added as an attachment and a solution is (1, 5)

From the question, we have the following parameters that can be used in our computation:

y ≥ x²

y ≤ x + 6

The above system is a system of inequalities that include

Next, we plot the graph

One of the points in the shaded region is (1, 5)

See attachment for the graph of the inequality

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The result of the recurrence: an=9a n−1 for n≥2 with the initial condition a1=−6. an=  -6 × (-9)n-1

There is the recurrence relation: an = 9an - 1 with the initial condition a1 = -6. The task is to find the solution to the recurrence relation. Let's use the backward substitution method to solve the recurrence relation. In the backward substitution method, we start from the value of an and use the relation an = 9an - 1 to calculate an - 1, then use an - 1 = 9an - 2 to calculate an - 2, and so on until we reach the given initial value.

Here, a1 = -6, so we can start with a2. Using the relation an = 9an - 1, we get:

a2 = 9a1 = 9(-6) = -54

Using the relation an = 9 an - 1, we get:

a3 = 9a2 = 9(-54) = -486

Using the relation an = 9an - 1, we get:

a4 = 9a3 = 9(-486) = -4374

Similarly, we can calculate a5:

a5 = 9a4 = 9(-4374 ) = -39366

So, the result of the recurrence relation with the initial condition a1 = -6 is:

an = -6 × (-9)n-1

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The value of the given logarithm ln(x²y⁵) in terms of u and v will be 2u + 5v thus option (D) is correct.

The exponent indicates the power to which a base number is raised to produce a given number called a logarithm.

In another word, a logarithm is a different way to denote any number.

As per the given expressions,

u = ln x and v = ln y

Take anti-log as

x = \(e^{u}\) and y = \(e^{v}\)

Thus, x² = \(e^{2u}\) and y⁵ = \(e^{5v}\).

Multiply both as

x²y⁵ =  \(e^{2u}\)\(e^{5v}\)

Take logarithms on both sides,

ln(x²y⁵) = ln( \(e^{2u}\)\(e^{5v}\))

By log property that ln(A x B) = lnA + lnB

ln(x²y⁵) = ln  (\(e^{2u}\)) + ln(\(e^{5v}\))

ln(x²y⁵) = 2u ln e + 5v ln e

ln(x²y⁵) = 2u + 5v



Hence "In terms of u and v, the value of the given logarithm ln(x²y⁵) will be 2u + 5v.".

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Thee factory is able to provide 94.38 boxes per hour to the warehouse.

Rate = (2000 - 1245) / 8 = 94.38 boxes per hour

Therefore, the factory is able to provide 94.38 boxes per hour to the warehouse.

Boxes added in 40 hours = rate * time = 94.38 * 40 = 3,775.2

Therefore, the inventory at the end of a 40-hour work week would be:

1245 + 3775.2 = 5020.2 boxes

rate = (50000 - 1245) / time

Simplifying this equation, we get:

time = (50000 - 1245) / rate = 511.64 hours (rounded to two decimal places).

Therefore, it will take approximately 511.64 hours to fill the warehouse to its 50,000 box capacity,

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We are given the following information: HMK Company is producing refining and packaging raw sugar into two different types, (Whity X) and (Browny Y).

The profit equation is given as: Profit equation: 3X + 2YLet's solve the production constraints one by one:

Constraint 1: 10X + 4Y ≤ 20Let's plot this inequality on a graph:

graph{(y(-2/5))[-5,5](-10x+20)/4 [-5,5]}As we can see from the graph, the feasible region for this constraint is the triangular area below the line 10X + 4Y = 20,

and to the left of the y-axis and below the x-axis.

Constraint 2: 4Y ≤ 16Let's plot this inequality on a graph: graph{(y(-4))[-5,5](-10x+20)/4 [-5,5]}

As we can see from the graph, the feasible region for this constraint is the rectangular area to the left of the y-axis and below the line Y = 4.Constraint 3: X ≤ 1

Let's plot this inequality on a graph:

graph{(y(-5))[-5,5]x<=1 [-5,5]}As we can see from the graph, the feasible region for this constraint is the triangular area below the line X = 1,

and to the left of the y-axis and above the x-axis.

Constraint 4: Y ≤ 12.5Let's plot this inequality on a graph: graph {(y(-15))[-5,5]x<=1 [-5,5]}

As we can see from the graph, the feasible region for this constraint is the rectangular area to the left of the y-axis and below the line Y = 12.5.Constraint 5: 9.8 ≤ X ≤ 12.8

Let's plot this inequality on a graph: graph{(y(-15))[-5,5]9.8<=x<=12.8 [-5,5]}As we can see from the graph, the feasible region for this constraint is the rectangular area between the vertical lines X = 9.8 and X = 12.8,

to the left of the y-axis.

Now, let's find the coordinates of the corners of the feasible region (where all the constraints intersect):graph{(y(-15))[-5,5]9.8<=x<=12.8 [-5,5]}

As we can see from the graph, the coordinates of the corners of the feasible region are:(9.8, 0), (10, 1.5), (12.5, 12.5), (12.8, 0)Now, let's calculate the profit for each corner of the feasible region

:Corner 1: (9.8, 0)Profit = 3(9.8) + 2(0) = 29.4Corner 2: (10, 1.5)Profit = 3(10) + 2(1.5) = 32Corner 3: (12.5, 12.5)Profit = 3(12.5) + 2(12.5) = 50Corner 4: (12.8, 0)Profit = 3(12.8) + 2(0) = 38.4

Therefore, the maximum approximate profit that the company can attain is $50. Ans: 50.

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The multi-factor productivity of Cadbury's can be calculated by dividing the output (number of chocolate bars produced) by combined input factors (labor and overhead expenses). Correct answer is (c) 8.3 bars/$.

Multi-factor productivity measures the efficiency with which multiple inputs are used to produce a certain output. In this case, we need to calculate the productivity of Cadbury's by considering the number of chocolate bars produced and the combined input factors of labor and overhead expenses.

The number of chocolate bars produced in a day is given as 5000. Since a day is considered 8 hours, we can calculate the production rate per hour by dividing the total number of bars by the total hours:

5000 bars / 8 hours = 625 bars/hr. Therefore, option (a) 625 bars/hr is incorrect.

The combined input factors include the labor cost and the overhead expense. The labor cost per day is $200, and since there are 4 staff members, each staff member's cost would be $200 / 4 = $50. The overhead expense is given as $400 per day. Therefore, the total input cost is $400 (overhead) + $200 (labor) = $600.

To calculate the multi-factor productivity, we divide the output (number of bars) by the input cost: 5000 bars / $600 = 8.3 bars/$. Hence, the correct answer is (c) 8.3 bars/$, representing the multi-factor productivity of Cadbury's.

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Time intervals = 14/7 = 2

Final Amount = 40(1/2)² = 10

Answer:

3rd option

Step-by-step explanation:

Given

S = 3\(r^{4}\)t  ( isolate t by dividing both sides by 3\(r^{4}\) )

\(\frac{S}{3r^4}\) = t