Answer:
n = 9
Step-by-step explanation:
Here we have the table:
X Y
4 3
6 5
7 6
10 n
First, we want to find the rule.
in the first pair we have:
x = 4
y = 3
We can see that the y-value is one smaller than the x-value
y = 3 = 4 - 1 = x - 1
For the second pair we have:
x = 6, y = 5
We again can see that the y-value is one smaller than the x-value
y = 5 = 6 - 1 = x - 1
For the third pair we have:
x = 7, y = 6
Again, can see that the y-value is one smaller than the x-value.
y = 6 = 7 - 1 = x - 1
We can conclude that the rule is:
y = x - 1
For the last pair, we have:
x = 10, y = n
Then:
n = 10 - 1 = 9
n = 9
Then the table is:
X Y
4 3
6 5
7 6
10 9
Will Give Brainliest, Answer ASAP m∠O =
m∠N =
Answer:
∠ O = 61°, ∠ N = 119°
Step-by-step explanation:
In a parallelogram
Consecutive angles are supplementary
Opposite angles are congruent, thus
x + 2x - 3 = 180
3x - 3 = 180 ( add 3 to both sides )
3x = 183 ( divide both sides by 3 )
x = 61°
Thus
∠ O = ∠ M = x = 61°
∠ N = ∠ P = 2x - 3 = 2(61) - 3 = 122 - 3 = 119°
Psychologist Scully believes that doing meditation or engaging in vigorous exercise leads to better grades. She predicts an interaction between meditation and exercise such that engaging in both activities (meditation and exercise) produces no more benefit than either activity alone. She randomly assigns 80 participants to 4 groups. Twenty participants meditate and exercise, 20 participants meditate but do not exercise, 20 participants exercise but do not meditate and 20 participants neither exercise nor meditate.
Table of Means
Exercise No exercise
Meditation 3.5 3.6
No Meditation 3.8 2.5
a) Sketch a graph of the interaction (a line graph)
b) Then describe whether the results Scully predicted were obtained and put them into your own words, with reference to the graph or the means. Do NOT just list the four groups and their means.
The graph representing the interaction between meditation. Scull’s prediction that engaging in both activities does not produce any more benefit than either activity alone was wrong.
The interaction between exercise and meditation is more pronounced, indicating that it is necessary to engage in both activities to achieve better grades. Students who meditate and exercise regularly received better grades than those who did not meditate or exercise at all. According to the table of means, students who exercised but did not meditate had a mean of 3.6, students who meditated but did not exercise had a mean of 3.5, students who did not meditate or exercise had a mean of 2.5, and students who meditated and exercised had a mean of 3.8.
The mean score for the group who exercised but did not meditate was lower than the mean score for the group who meditated but did not exercise. The mean score for the group that neither meditated nor exercised was the lowest, while the group that meditated and exercised had the highest mean score.
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Adam buys 4 pens and a ruler and pays £4.75 altogether.
Jack buys 2 pens and pays £1.98 altogether
How much does one ruler cost
Answer:
I don't know and I love your mother and what she does to me every night
Answer:
0.79
Step-by-step explanation:
First we need to find the price of one pen:
1.98/2 = 0.99 per pen
Then we find the price of 4 pens and subtract that from 4.75:
0.99 times 4 = 3.96
4.75 - 3.96 = 0.79 per ruler
suppose interstate highways join the six towns a, b, c, d, e, f as follows: i-77 goes from b through a to e; i-82 goes from c through d, then through b to f; i-85 goes from d through a to f; i-90 goes from c through e to f; and i-91 goes from d to e.
These interstates provide vital transportation routes, enabling efficient connectivity between the towns. The highway system allows for convenient travel and transportation of goods and services among the interconnected towns, fostering economic development and regional connectivity.
The specific routes and intersections of these interstates play a crucial role in facilitating travel and supporting the transportation needs of the communities they serve. Interstate highways connect the six towns A, B, C, D, E, and F as follows:
- Interstate 77 (I-77) runs from town B, passes through town A, and continues to town E.
- Interstate 82 (I-82) starts from town C, goes through town D, then passes through town B, and finally reaches town F.
- Interstate 85 (I-85) begins from town D, passes through town A, and ends at town F.
- Interstate 90 (I-90) starts from town C, goes through town E, and terminates at town F.
- Interstate 91 (I-91) runs directly from town D to town E.
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The value of y varies directly with x.
When y=3 , x=1 .
What is the value of y when x is 4 ?
Answer:
12
Step-by-step explanation:
Hello. Y/x = a constant k because y and x are by definition always in the same ratio. (y varies directly as x so if x is doubled y is also doubled etc.)
A digital clock shows hours (between 0 and 23) and minutes (between 0 and 59). Once a minute, it receives a pulse to advance the time. Complete the Clock class, using instance variables for the hours and minutes.
The Clock class can be completed by defining instance variables for hours and minutes.
How can the Clock class be implemented with instance variables for hours and minutes?In order to complete the Clock class, we need to define two instance variables: one for hours and one for minutes. These variables will hold the current time displayed on the digital clock. The hours variable should be an integer between 0 and 23, while the minutes variable should be an integer between 0 and 59.
To advance the time, we can create a method called "advance" that will be triggered once a minute. Inside this method, we can increment the minutes variable by 1. However, if the minutes variable reaches 60, we need to reset it back to 0 and increment the hours variable by 1. If the hours variable reaches 24, we can set it back to 0 to maintain the 24-hour format.
By using these instance variables and implementing the "advance" method, we can simulate the behavior of a digital clock that receives a pulse every minute and updates the time accordingly.
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Solve the following triangles ABC for all the missing parts. Draw a picture of the triangle. Show a set up to a problem and then solve by using your calculator. Round angles and sides to the nearest tenth. Don't forget to label angles and sides with units. (8 points each) a). A = 10°, B = 115°, and b 18 cm b). B = 34º, a = 55 inches, and c = 32 inches
(A) In triangle ABC
Angle A = 10° ,Angle B = 115° ,Angle C = 55° ,Side a = 1.6 in ,Side b = 18 in ,Side c = 17.2 in
(B) In triangle ABC
Angle A = 74.4° , Angle B = 34º, Angle C = 71.6°, Side a = 55 inches, Side b = 33.6 inches Side c = 32 inches
(a) A = 10°, B = 115°, and b = 18 in
The sum of the angles in a triangle is 180°.
C = 180° - A - B
C = 180° - 10° - 115°
C = 55°
The Law of Sines:
a / sin(A) = b / sin(B)
a / sin(10°) = 18 /sin (115°)
a = (18 in × sin(10°)) / sin(115°)
a =1.60 in
Angle A = 10°
Angle B = 115°
Angle C = 55°
Side a = 1.6 in
Side b = 18 in
c / sin(C) = b / sin(B)
c / sin(55°) = 18 in / sin(115°)
c = (18 in × sin(55°)) / sin(115°)
c = 17.2 in
b) B = 34º, a = 55 inches, and c = 32 inches
Using the law of cosine
b = \(\sqrt{a^{2} +c^{2} -2ac(cosB)}\)
b = \(\sqrt{55^{2} + 32^{2} - 2(55)(32)cos34 }\)
b = 33.6 in
a = \(\sqrt{b^{2} +c^{2} -2bc(cosa)}\)
55 = \(\sqrt{33.6^{2} + 32^{2} - 2(33.6)(32)cosA }\)
CosA = 0.405
A = 74.4°
A + B + C = 180
C = 180 - 34 - 74.4
C = 71.6°
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A 5-column table with 6 rows titled Number of cans collected. Column 1 has entries 7, 8, 10, 11, 11, 14. Column 2 has entries 16, 17, 18, 18, 24, 25. Column 3 has entries 28, 29, 30, 30, 35, 37. Column 4 has entries 38, 40, 40, 41, 41, 41. Column 5 has entries 42, 42, 42, 42, 42, 43.
Students from Grover Middle School are recycling aluminum cans. The table shows the total number of cans brought in each school day for a period of six weeks. They collected a total of 862 cans. Use the drop-down menus to define the terms.
Mean:
Median:
Mode:
Range:
Answer:
mean: 28.73
median: 30
Mode: 42
Range: 36
Step-by-step explanation:
Took the test on edge2020
Answer:
Students from Grover Middle School are recycling aluminum cans. The table shows the total number of cans brought in each school day for a period of six weeks. They collected a total of 862 cans. Use the drop-down menus to define the terms.
Mean:
✔ 28.73
Median:
✔ 30
Mode:
✔ 42
Range:
✔ 36
Step-by-step explanation:
Correct answers
What are the values of a and b?
Answer:
Step-by-step explanation:
They are both congruent and they are both the same shape from different angels so the values of a=8 and the value for b=10.
I think this should help.
in a research study, if the obtained mean of the observations is close to the population parameter, then in one sense the sample is considered representative of the target population. group of answer choices true false
The given statement is True because If the sample mean is close to the population parameter, it suggests representative sampling regarding the variable of interest, although other factors should be considered too.
When the sample mean closely approximates the population parameter, it indicates that the sample is capturing the central tendency of the population. The mean is a measure of central tendency that reflects the average value of the variable of interest in the population.
If the sample mean is similar to the population mean, it suggests that the sample is a good representation of the population in terms of that particular variable.
However, it is important to note that representativeness is a relative concept. A sample may be considered representative in one sense but not necessarily in all aspects. Other factors, such as the sampling method, sample size, and sampling bias, also influence the representativeness of a sample.
In summary, when the obtained mean of the observations in a research study is close to the population parameter, it provides evidence that the sample is representative of the target population to some degree, indicating that the sample captures the central tendency of the population for the variable under investigation.
However, representativeness should be assessed in consideration of other factors as well.
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Evaluate the expression when m = 4 and n = 6.
(3m−n)^2+4m
Answer:
yor answer is 52
Step-by-step explanation:
This shape is made up of one half-circle attached to an equilateral triangle with side lengths 20 inches. You can use 3. 14 as an approximation for π
If the shape is made up of one half-circle attached to an equilateral triangle with side lengths 20 inches then, the perimeter of the shape is 91.4 inches.
To find the perimeter of the shape, we need to know the length of the curved boundary (the circumference of the half-circle) and the length of the straight boundary (the perimeter of the equilateral triangle).
The radius of the half-circle is half the length of the side of the equilateral triangle, which is 10 inches. Therefore, the circumference of the half-circle is:
C = πr = π(10) = 31.4 inches.
The perimeter of the equilateral triangle is 3 times the length of one side, which is 20 inches. Therefore, the perimeter of the triangle is:
P = 3s = 3(20) = 60 inches
Finally, the perimeter of the entire shape is the sum of the lengths of the curved and straight boundaries:
Perimeter = C + P = 31.4 + 60 = 91.4 inches.
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Complete Question
This shape is made up of one half-circle attached to a square with side lengths 11 inches. Find the perimeter of the shape.
You can use 3.14 as an approximation for π. help i don't know it.
55 points.
Please simplify it .
Don't answer of your don't know.
Step-by-step explanation:
i) answer =1
ii) 2 -3m + 6n -2 x 3 3-m
Answer:
( i ) \(\boxed{1}\)
( ii ) \(\boxed{2^{6n - 3m - 2}\times 3^{3 - m}}\)
.
Step-by-step explanation:
( Part i )
\(\left(\frac{1}{x^{a - b}} \right)^{a + b}\left(\frac{1}{x^{b + a}} \right)^{b - a}\)
\(= \left(\frac{1}{x^{(a - b)(a + b)}} \right)\left(\frac{1}{x^{(b + a)(b - a)}} \right)\)
\(= \left(\frac{1}{x^{a^2 - b^2}} \right)\left(\frac{1}{x^{b^2-a^2}} \right)\)
\(= \frac{1}{x^{a^2 - b^2 + (b^2 - a^2)}}\)
\(= \frac{1}{x^0}\)
\(= \frac{1}{1}\)
\(= \boxed{1}\)
.
( Part ii )
\(\frac{2^{m + n}\times 3^{2m + 3} \times 4^{2n -1}}{6^{2m + n}\times 12^{m - n}}\)
\(=\frac{2^{m + n}\times 3^{2m + 3} \times 2^{2(2n -1)}}{(2\times3)^{2m + n}\times (3\times 2^2)^{m - n}}\)
\(=\frac{2^{m + n}\times 3^{2m + 3} \times 2^{4n -2}}{2^{2m + n}\times3^{2m + n}\times 3^{m - n}\times 2^{2(m - n)}}\)
\(=\frac{2^{m + n + 4n - 2}\times 3^{2m + 3}}{2^{2m + n + 2m - 2n}\times3^{2m + n + m - n}}\)
\(=\frac{2^{m + 5n - 2}\times 3^{2m + 3}}{2^{4m - n}\times3^{3m}}\)
\(= 2^{m + 5n - 2 - (4m - n)}\times3^{2m + 3 - 3m}\)
\(= \boxed{2^{6n - 3m - 2}\times 3^{3 - m}}\)
.
Happy to help :)
A forest fire which is initially 60 acres grows by 20% each day. firefighters battling the blaze can put out 15 acres of fire per day. what is the recursive rule for the number of an acres at the beginning of the nth day. how many acres are burning at the 8th day?
The recursive rule for the number of acres at the beginning of the nth day in a forest fire that grows by 20% each day and is battled by firefighters who can put out 15 acres per day is given by: A(n) = 1.2 * A(n-1) - 15, where A(n) represents the number of acres at the beginning of the nth day. Using this rule, we can calculate that there are 89.6 acres burning at the beginning of the 8th day.
Explanation: To determine the recursive rule for the number of acres at the beginning of the nth day, we need to consider the given information. The forest fire initially covers 60 acres and grows by 20% each day. This means that the number of acres at the beginning of the next day (n+1) is 1.2 times the number of acres at the beginning of the current day (n). However, the firefighters are able to put out 15 acres of fire per day.
Therefore, to calculate A(n), we start with the initial number of acres, which is 60, and apply the recursive rule. A(n) = 1.2 * A(n-1) - 15. This formula takes into account the growth of the fire by 20% and the reduction of 15 acres due to the firefighters' efforts. By substituting the values, we can calculate the number of acres at the beginning of each day.
To find the number of acres burning at the 8th day, we substitute n = 8 into the recursive rule. A(8) = 1.2 * A(7) - 15. We need to determine A(7) first by substituting n = 7, and so on, until we reach the initial value A(1) = 60. Once we have calculated A(8), we can determine that there are 89.6 acres burning at the beginning of the 8th day
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Write tan 41π/36 in terms of the tangent of a positive acute angle.
tan(41π/36) can be written in terms of the tangent of a positive acute angle as (tan((1/9)π) + tan((37/36)π)) / (1 - tan((1/9)π)tan((37/36)π))
To express tan(41π/36) in terms of the tangent of a positive acute angle, we need to find an angle within the range of 0 to π/2 that has the same tangent value.
First, let's simplify 41π/36 to its equivalent angle within one full revolution (2π):
41π/36 = 40π/36 + π/36 = (10/9)π + (1/36)π
Now, we can rewrite the angle as:
tan(41π/36) = tan((10/9)π + (1/36)π)
Next, we'll use the tangent addition formula, which states that:
tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A)tan(B))
In this case, A = (10/9)π and B = (1/36)π.
tan(41π/36) = tan((10/9)π + (1/36)π) = (tan((10/9)π) + tan((1/36)π)) / (1 - tan((10/9)π)tan((1/36)π))
Now, we need to find the tangent values of (10/9)π and (1/36)π. Since tangent has a periodicity of π, we can subtract or add multiples of π to get equivalent angles within the range of 0 to π/2.
For (10/9)π, we can subtract π to get an equivalent angle within the range:
(10/9)π - π = (1/9)π
Similarly, for (1/36)π, we can add π to get an equivalent angle:
(1/36)π + π = (37/36)π
Now, we can rewrite the expression as:
tan(41π/36) = (tan((1/9)π) + tan((37/36)π)) / (1 - tan((1/9)π)tan((37/36)π))
Since we are looking for an angle within the range of 0 to π/2, we can further simplify the expression as:
tan(41π/36) = (tan((1/9)π) + tan((37/36)π)) / (1 - tan((1/9)π)tan((37/36)π))
Therefore, tan(41π/36) can be written in terms of the tangent of a positive acute angle as the expression given above.
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Write a two-column proof. Given: Triangle ACD is isosceles; <1 is congruent to <3 Prove: Segment AB || Segment CD
Answer:
The answer is explained below
Step-by-step explanation:
Statement Reason
Triangle ACD is isosceles and Given
<1 = <3 (<1 is congruent to <3)
∠3 = ∠4 Isosceles triangle base angles.
∠1 = ∠4 Substitution Theorem
∠1 = ∠4 They are produced by two lines . AB and CD cut by transversal
. line AD
Segment AB || Segment CD Alternate interior angle theorem
The Alternate interior angle theorem states that if two lines cut by a transversal line form congruent alternate interior angles, then the two lines are parallel to each other.
Banneker Middle School has 750 students. Lynn surveys a random sample of 50 students and finds that 27 of them have pet dogs. How many students at the school are likely to have pet dogs.
Answer: 405 students
Step-by-step explanation:
From the question, Banneker Middle School has 750 students and we are told that Lynn surveys a random sample of 50 students and finds that 27 have pet dogs. The number of students at the school that are likely to have pet dogs goes thus:
Since out of 50 students surveyed, 27 have pet dogs, this means we multiply the fraction by 750. This can be mathematically written as:
= 27/50 × 750
= 27 × 15
= 405
This means 405 students are expecting to have pet dogs.
a store sells 8 colors of balloons with at least 29 of each color. how many different combinations of 29 balloons can be chosen?
There are generally \(6.776 x 10^{35}\) particular combinations of 29 inflatables(balloons) that can be chosen from the store.
Given data,
Since there are 8 colors of balloons,
we need to select 29 balloons from each color to
Calculate a total of 29 x 8 = 232 balloons.
We need to find the number of different combinations of 29 balloons
that can be chosen from this set of 232 balloons.
Able to utilize the condition for combinations:
we know that,
C(n, r) = n! / (r! * (n - r)!) ...........(1)
where n is the complete number of things
and C is the combination of given(29) balloons.
r is the number of things to choose.
Substituting the above values into equation (1)
we get
C(232, 29) = 232! / (29! * (232 - 29)!) = \(6.776 x 10^{35}\)
Along these lines, there are generally \(6.776 x 10^{35}\) particular combinations of 29 inflatables(balloons) that can be chosen from the store.
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The ratio of cups of orange juice concentrate to water in a punch recipe is 2 : 5. If Geoffrey used 20 cups of water, how many cups of orange juice concentrate did he use?
Answer:
8
Step-by-step explanation:
if the 5 aka water is equal to 20, then one unit is equal to 4, and multiply 4 by 2 to get 8.
Pls brainliest
If katya takes a trip of 600miles how many gallons of gas would be needed to make the trip
So Katya needs 21.42 gallons of gas for 600 miles.
A Linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept. Occasionally, the above is called a "linear equation of two variables," where y and x are the variables.
Given we have Katya have to take a trip for 600 miles.
Let x be number of gallons of gas y be number of miles driven by Katya
We have an relation from table that 28X = Y and Y we have from table 600
So 28X = 600 and \(X = \frac{600}{28}\)
X= 21.42 gallons .
Therefore Katya needs 21.42 gallons of gas for 600 miles.
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(law of exponent for abelian groups) let a and b be elements of an abelian group and let n be any integer. show that (ab)^n = a^n b^2. is this also true for non-abelian groups?
According to the law of exponent for abelian groups (ab)^n = a^n b^2 is not necessarily true for non-abelian groups.
Using the distributive law repeatedly, we have:(ab)^n = (ab)(ab)...(ab) (n times)
= a(ab)(ab)...(ab) (n-1 times) b
= a(a(ab)(ab)...(ab) (n-2 times) b)b
= a^2 (ab)(ab)...(ab) (n-2 times) b^2
= ...
= a^n b^n
Therefore, (ab)^n = a^n b^n for any abelian group and any integer n.
However, this is not necessarily true for non-abelian groups. For example, consider the dihedral group D4 which is the symmetry group of a square. Let a be a 90 degree clockwise rotation and b be a horizontal reflection. Then (ab)^2 = a(ba)b = ae = e, where e is the identity element. However, a^2 = b^2 = e, so (ab)^2 = e^2 = e, which is not equal to a^2b^2 = e. Hence, the law of exponents does not hold for D4
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Bob's gift shop sold a record number of cards for Mother's Day. One salesman sold 33 cards, which was 2% of the cards sold for Mother's Day. How many cards were sold for Mother's Day?
Answer:
redes sociales fff
ffkr
How many cubes with side lengths of \dfrac12 \text{ cm} 2 1 cmstart fraction, 1, divided by, 2, end fraction, start text, space, c, m, end text does it take to fill the prism? Cubes
Answer:
24
Step-by-step explanation:
Answer
24!
Step-by-step explanation:
Person above me is correct :)
Solve for X: square root 4x-7 - square root 2x = 1
Root x = 2 is an extraneous solution for radical equation √(4 · x - 7) - √(2 · x) = 1, whose roots are 2 and 8, respectively.
How to determine the extraneous solution of a radical equation
In this problem we find the definition of a radical equation, whose roots must be found by combining algebra properties and power properties. A root is an extraneous solution if the result lead to an absurdity. (i.e. 1 = 0).
First, write the complete expression:
√(4 · x - 7) - √(2 · x) = 1
Second, apply algebraic substitution formula u = 2 · x to simplify the model:
√(2 · u - 7) - √u = 1
Third, use algebra properties to clear square roots:
√(2 · u - 7) = 1 + √u
Fourth, square both sides of the expression:
2 · u - 7 = (1 + √u)²
2 · u - 7 = 1 + 2 · √u + u
u - 7 = 1 + 2 · √u
u - 2 · √u - 8 = 0
Fifth, use algebraic substitution k = √u and solve the quadratic-like equation by factorization:
k² - 2 · k - 8 = 0
(k - 4) · (k + 2) = 0
k₁ = 4 or k₂ = - 2
Sixth, find the values of x by reversing algebraic substitutions:
√u₁ = 4 or √u₂ = - 2
u₁ = 4² or u₂ = (- 2)²
2 · x₁ = 4² or 2 · x₂ = (- 2)²
x₁ = 8 or x₂ = 2
Seventh, look for any extraneous solution:
x₁ = 8
√(4 · 8 - 7) - √(2 · 8) = 1
√25 - √16 = 1
5 - 4 = 1
1 = 1
x₂ = 2
√(4 · 2 - 7) - √(2 · 2) = 1
√1 - √4 = 1
1 - 2 = 1
- 1 = 1 (CRASH!)
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Find the area of right triangle ABC.
Answer:
16 sq. unit
Step-by-step explanation:
Area = ½ × base × height
= ½ × 8 × 4
= 16 sq unit
Does anyone know this!? If the answer is correct ill mark you as the best answer!
Answer:
H. Decreasing a y-intercept moves the graph down
Suppose a calculator manufacturer has the total cost function
C(x) = 22x + 6600
and the total revenue function
R(x) = 66x.
(a) What is the equation of the profit function P(x) for the calculator?
P(x) = _________
(b) What is the profit on 2800 units?
P(2800) = $________
Answer:
a) P(x) = R(x) - C(x)
P(x) = 66x - 22x - 6600 =
44x - 6600
b) P(2800) = 44(2800) - 6600 =
$116600
can someone help please?
Answer:
x = 54
Step-by-step explanation:
In this line, I am going to assume lines l and m are parallel.
Each flat surface is half of a circle, therefore it has 180 degrees. We are given one side and told to find the other.
180 - 116 = 64.
The other angle's total value must be 64.
Now, to solve for x, subtract 10 from 64 [inverse operations].
64-10=54
The value of x in this equation is 54 degrees.
\(x^{2} 86\sqrt[n]{x} 765997\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] 886600x_{123} 87686\alpha 86865\)
SOLVE
Answer:not sure
Step-by-step explanation:
just robbing ur points
next time dont do it to me :)
the null hypothesis typically corresponds to a presumed default state of nature. t/f
False. The null hypothesis does not inherently represent a presumed default state of nature but rather serves as a reference point for hypothesis testing.
The null hypothesis does not necessarily correspond to a presumed default state of nature. In hypothesis testing, the null hypothesis represents the assumption of no effect, no difference, or no relationship between variables. It is often formulated to reflect the status quo or a commonly accepted belief.
The alternative hypothesis, on the other hand, represents the researcher's claim or the possibility of an effect, difference, or relationship between variables. The null hypothesis is tested against the alternative hypothesis to determine whether there is enough evidence to reject the null hypothesis in favor of the alternative hypothesis.
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