Find the radius of gyration of a plate covering the region bounded by y = x², x = 4, and the x-axis with respect to the x-axis. The radius of gyration is (Type an exact answer.)

Answer: $164

Step-by-step explanation:

25*7=175

175+12.5

226.50-187.50

5*25=125+39

Jones family payed $164

Answer:

it would be 14.70

Step-by-step explanation:

Answer:

.4%

Step-by-step explanation:

4/6*3/5

Answer: If Sydney needs to make exactly 8 dozen items for a bake sale, that means she needs to make a total of 8 x 12 = 96 items

Answer:

\(x=\dfrac{2}{5}\times (2+3)-3\)

Step-by-step explanation:

The given ratio is 2:3.

x₁ = -3, x₂ = 2

We need to find the x-coordinate of the point that will divide segment AB into a 2:3 ratio. The formula is as follows :

\(x=\dfrac{a}{a+b}(x_2-x_1)+x_1\)

Put all the values,

\(x=\dfrac{2}{2+3}(2-(-3))+(-3)\\\\=\dfrac{2}{5}\times (2+3)-3\)

Hence, the correct option is (d).

Answer: D

Step-by-step explanation:

I got it right on edge trust me :)

Since f(x) = 4x² - 8x + 6

A. The increment f(x + h) = 4x² + 8xh + 4h² - 8x + 8h + 6

B. The increment f(x + h) - f(x) = 4h² + 8xh + 8h

C. The increment  [f(x + h) - f(x)]/h = 4h + 8x + 8

The increment of a function is the increase or change in the function.

A. Since f(x) = 4x² - 8x + 6, we desire to find the increment f(x + h), we proceed as follows.

Since f(x) = 4x² - 8x + 6 replacing x by x + h in the equation, we have that

f(x) = 4x² - 8x + 6

f(x + h) = 4(x + h)² - 8(x + h) + 6

Expanding the bracket, we have

= 4(x² + 2xh + h²) - 8(x + h) + 6

= 4x² + 8xh + 4h² - 8x + 8h + 6

So, f(x + h) = 4x² + 8xh + 4h² - 8x + 8h + 6

B. To find the increment f(x + h) - f(x), we proceed as follows

Since f(x + h) = 4x² + 8xh + 4h² - 8x + 8h + 6 and f(x) = 4x² - 8x + 6

So,  f(x + h) - f(x) = 4x² + 8xh + 4h² - 8x + 8h + 6 - (4x² - 8x + 6)

= 4x² + 8xh + 4h² - 8x + 8h + 6 - 4x² + 8x - 6

Collecting like terms,we have

= 4x² - 4x² + 8xh + 4h² - 8x + 8x + 8h + 6 - 6

= 0 + 8xh + 4h² + 0 + 8h + 0

= 8xh + 4h² + 8h

= 4h² + 8xh + 8h

So, f(x + h) - f(x) = 4h² + 8xh + 8h

C. To find the increment [f(x + h) - f(x)]/h, we proceed as follows

Since f(x + h) - f(x) = 4h² + 8xh + 8h , then dividing the equation by h, we have that

[f(x + h) - f(x)]/h = (4h² + 8xh + 8h)/h

= 4h²/h + 8xh/h + 8h/h

= 4h + 8x + 8

So, [f(x + h) - f(x)]/h = 4h + 8x + 8

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Answer:

2x-32

Step-by-step explanation:

You would distribute the 4.

To solve the given initial value problem (IVP) using the fundamental solutions, let's first find the fundamental solutions corresponding to the auxiliary equation.

The auxiliary equation for the given differential equation 10x + 16y = 0 is obtained by assuming a solution of the form y = e^(rx):

r² + 16r = 0.

Factoring out r, we get:

r(r + 16) = 0.

This equation has two roots: r = 0 and r = -16.

Therefore, the two fundamental solutions are:

y₁(x) = e^(0x) = 1,

y₂(x) = e^(-16x).

Now, let's find the particular solution that satisfies the initial conditions y(0) = -6 and y'(0) = 6.

Using the formula for the general solution of a second-order linear homogeneous differential equation:

y(x) = C₁y₁(x) + C₂y₂(x),

where C₁ and C₂ are constants, we can substitute the fundamental solutions and their derivatives into the general solution to find the particular solution.

y(x) = C₁ + C₂e^(-16x).

Differentiating y(x) with respect to x:

y'(x) = -16C₂e^(-16x).

Now, let's apply the initial conditions:

At x = 0, y(0) = -6:

C₁ + C₂e^(0) = -6.

This gives us the equation C₁ + C₂ = -6.

At x = 0, y'(0) = 6:

-16C₂e^(0) = 6.

Simplifying, we get -16C₂ = 6.

Solving this equation, we find C₂ = -6/16 = -3/8.

Substituting C₂ = -3/8 into the equation C₁ + C₂ = -6, we can solve for C₁:

C₁ - 3/8 = -6,

C₁ = -6 + 3/8,

C₁ = -51/8.

Therefore, the particular solution to the initial value problem is:

y(x) = -51/8 - (3/8)e^(-16x).

This is the solution to the given IVP.

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Answer:

11.50

Step-by-step explanation:

Just add it up on a calculator and that's for the terms. t = 11.50

The amount of blue paint required = 3/2 cups

Ratio:

Comparing two or more quantities that have units is known as the Ratio. It shows the numerical relation between two quantities like how small or big a quantity is when compared to each other.

The general form of a ratio is a: b

Here we have,

2/3 cups of white paint and 2 and 2/3 cups of blue paint

Then ratio of white to blue paint = 2/3 : 2 (2/3)

= 1:2   [ divided by 2/3 ]

In the second condition, we have 3/4 cups of white paint, here we want to give the same shade then the ratio of paint must be the same as above

Let x be the amount of blue paint that we need  

Then the ratio of white paint to blue = 3/4: x

From the given condition,

=>  3/4 : x  = 1 : 2

=> 3/4 / x = 1/2

=> 3/4x = 1/2  

=> 3(2) = 4x(1)

=> x = 6/4 =

=> 3/2

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Answer:

-25b + 30y + 5

Step-by-step explanation:

I hope this helps!

Answer:

The answer is D

Step-by-step explanation:

Answer:

The answer to the following is infinitely many.

Step-by-step explanation:

You could solve this in many ways, for instance, by simplifying it and solving it. Adding a number in the place of x, etc.

I hope this helps!

Answer:

36

Step-by-step explanation:

Given

3x + 2(y - 4) ← substitute x = 10 and y = 7 into the expression

= 3(10) + 2(7 - 4)

= 30 + 2(3)

= 30 + 6

= 36

Answer:

5 units

Step-by-step explanation:

Distance between two points can be found by using the pythagorean theorem

The distance in y = 4

The distance in x = 3

3² + 4² = c²

9 + 16 = c²

25 = c³

c = √25

c = 5

-Chetan K

Answer:

5

Step-by-step explanation:

\(\mathrm{Distance \:\:Formula:}\\\\\mathrm{d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}}\)

\(\underline{\mathrm{Plug \:the\: points:}}\)

\(d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\)

\(d = \sqrt{(5 - 2)^2 + (2-6)^2}\)

\(\underline{\mathrm{Solve:}}\)

\(d = \sqrt{(5 - 2)^2 + (2-6)^2}\)

\(\sqrt{(5 - 2)^2 + (2-6)^2}\)

\(\sqrt{3^2 + 4^2}\)

\(3^2 = \sqrt{9+4^2} =\boxed{9}\\\\4^2=\sqrt{9+16} = \boxed{16}\)

\(\sqrt{25}\)

\(\sqrt{5^2}=5\)

The minimized Sum of Products (SOP) expression for the given logic function F(A, B, C, D, E) with the specified minterms is obtained as f(A, B, C, D, E) = A'BCD'E' + A'B'C'D'E + A'BC'D'E + ABCD'E.

To find the minimized SOP expression using a five-variable Karnaugh map, we first plot the minterms on the map. The minterms are given as m(4,5,6,7,9,11,13,15,16,18,27,28,31). Next, we group adjacent 1s on the Karnaugh map to form groups of 2, 4, 8, or 16 cells. Each group represents a term in the minimized SOP expression.

After grouping the 1s on the Karnaugh map, we can identify the essential prime implicants, which are the groups that cover a single minterm. In this case, the group covering m(31) is an essential prime implicant.

Next, we fill in the remaining cells that are not covered by the essential prime implicant with 1s and group them to form additional terms. We can choose the groups that cover the remaining minterms while minimizing the number of terms in the expression.

Using these groups, we can generate the minimized SOP expression, which is f(A, B, C, D, E) = A'BCD'E' + A'B'C'D'E + A'BC'D'E + ABCD'E. This expression represents the logic function F(A, B, C, D, E) with the given minterms in a minimized form using the Sum of Products (SOP) representation.

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woah this looks hard

Answer:

75/96 or in its simplest form, 25/32

Step-by-step explanation:

1. Convert both fractions into improper fractions

2. Use KFC

15/8 ÷ 12/5 = 15/8 × 5/12

Hope this help!

Answer:

Given a relationship between two quantities, determine whether the relationship is a function. ... If each input value leads to only one output value, classify the relationship as a function. If any input value leads to two or more outputs, do not classify the relationship as a function.

Step-by-step explanation:

hope it helps

The cosine function is continuous everywhere, we can evaluate this limit by plugging in theta = 0, which gives:
lim theta→0+ 1/cos theta
= 1/cos 0 = 1/1 =1

The secant function is defined as the reciprocal of the cosine function, which means that sec theta = 1/cos theta. This function is periodic with period 2π, and it has vertical asymptotes at odd multiples of π/2.

To evaluate the limit lim 0 pi/2 sec theta, we can use the fact that the secant function is the reciprocal of the cosine function. Thus, we have:
lim theta→0+ sec theta
= lim theta→0+ 1/cos theta
Since the cosine function is continuous everywhere, we can evaluate this limit by plugging in theta = 0, which gives:
lim theta→0+ 1/cos theta
= 1/cos 0
= 1/1
= 1
Therefore, the limit of sec theta as theta approaches 0 from the right is 1. Note that we had to specify the direction from which theta approaches 0 because the limit is undefined if we approach 0 from the left.
In conclusion, the answer to the question "evaluate the following limit lim 0 pi/2 sec theta" is 1. so to meet the requirement of  we can elaborate on the properties of the secant function and its relation to the cosine function. The secant function is defined as the reciprocal of the cosine function, which means that sec theta = 1/cos theta. This function is periodic with period 2π, and it has vertical asymptotes at odd multiples of π/2. The behavior of the secant function near these asymptotes is similar to the behavior of the tangent function near its asymptotes, as both functions blow up to infinity.
The reciprocal relationship between the secant and cosine functions is important in trigonometry because it allows us to express any trigonometric function in terms of sine and cosine. For example, we can express the tangent function as tan theta = sin theta/cos theta = sec theta/sin theta. This relationship is also useful in calculus because it allows us to use the trigonometric identities to simplify integrals and derivatives.

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Answer:

it's C

Step-by-step explanation:

The correct answer is: The equation y = 54.16 + 0.87x is called the least-squares regression line because it makes the sum of the squared residuals as small as possible.

The least-squares regression line is a line that best fits the given data points by minimizing the sum of the squared residuals. Residuals are the vertical distances between the actual data points and the predicted values on the regression line. By minimizing the sum of the squared residuals, the line is able to provide the best overall fit to the data.

Therefore, the least-squares regression line aims to minimize the differences between the predicted values and the actual data points, making the sum of the squared residuals as small as possible.

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Answer:{d,t}={187, 17/2}

Step by step explanation :

System of Linear Equations entered :

[1] d - 18t = 34

[2] d - 22t = 0

Graphic Representation of the Equations :

-18t + d = 34 -22t + d

Solve by Substitution :

// Solve equation [2] for the variable d

[2] d = 22t

// Plug this in for variable d in equation [1]

[1] (22t) - 18t = 34

[1] 4t = 34

// Solve equation [1] for the variable t

[1] 4t = 34

[1] t = 17/2

// By now we know this much :

d = 22t

t = 17/2

// Use the t value to solve for d

d = 22(17/2) = 187

Answer:

\(d=52\\t=\frac{26}{11}\)

Step-by-step explanation:

1 solve for d in d =18+34

solve for d

\(d=18+34\)

Simplify 18+34  to  52

\(d=52\)

2 substitute d=52 into d=22t

Start with the original equation

\(d=22t\)

Let d=52

\(52=22t\)

3 Solve for t in 52=22t

Solve for t

\(52=22t\)

Divide both sides by 22

\(\frac{52}{22} =t\)

Simplify  \(\frac{52}{22}\)\(to \frac{26}{11}\)

\(\frac{26}{11} =t\)

Switch sides

\(t=\frac{26}{11}\)

​4 Therefore

\(d=52\\t=\frac{26}{11}\)

For f(x) to be a valid PDF, integrating f(x) dx over the support of x must be equal to 1. The above statement is true.

For a function f(x) to be a valid probability density function (PDF), it must satisfy two conditions:
1. f(x) must be non-negative for all values of x within its support, meaning that f(x) ≥ 0 for all x.
2. The integral of f(x) dx over the support of x must equal 1. This condition ensures that the total probability of all possible outcomes is equal to 1, which is a fundamental property of probability.
In mathematical terms, if f(x) is a PDF with support A, then the following conditions must be satisfied:
1. f(x) ≥ 0 for all x in A.
2. ∫(f(x) dx) over A = 1.

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So the maximum number of edges in an undirected graph with 100 vertices is 4950.

In an undirected graph, each edge connects two vertices, and as such, it is counted twice, once for each vertex it connects. Therefore, the total number of edges in the graph is the sum of the degrees of all vertices, divided by 2.

In a complete graph with n vertices, every vertex is connected to every other vertex, except itself, and so the degree of each vertex is n-1 (it is connected to n-1 other vertices). Therefore, the total number of edges in the graph is:

n * (n-1) / 2

Substituting n = 100, we get:

100 * 99 / 2 = 4950

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The measure of the angles are;

X = 38 degrees

Y = 52 degrees

To determine the angles, we need to know the properties of a kite.

These properties includes;

Then, we can say that;

Y= 52 degrees

Note that the sum of the angles in a triangle is 180

Then, we get;

X + Y+ 90 = 180

X = 180 - 142

Subtract the values

X = 38 degrees

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\( = (2 {n}^{2} - 5n - 6) + ( - {n}^{2} - 3n + 11)\)

\( = 2 {n}^{2} - 5n - 6 - {n}^{2} - 3n + 11\)

\( = 2 {n}^{2} - {n}^{2} - 5n - 3n - 6 + 11\)

= (n²-8n+5)→Answer

I hope that it answer your question...

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1.The beginning balance should be $4,000

2.The amount to be adjusted is $2554

3.The ending balance of the account after the adjustment $2554

4. Office Supplies Account is $14846

An adjusting entry is an additional journal entry that is made at the end of the month or year. When any financial transaction is incurred for which the amount is not accrued yet or no financial transaction incurred for the accrued amount and in such case the adjusting entry is made to know the actual amount accrued in the month or year.

The adjustment entries are the additional entries to the recorded journal entries.

"Information available from the question"

The Office Supplies account started the year with a $4,000 debit balance

The company purchased supplies for $13,400,

The inventory of supplies available at the end of the year totaled $2,554.

Now, According to the question:

1. The beginning balance should be $4,000

2.The adjusted amount is

Opening balance = 4000

Add: New purchases = 13400

Balance after Purchase = 17400

Less: Year end balance = 2554

3. The ending balance is $2,554

4. The adjusting journal entry is

Dr. Supplies Expense Account is 14846

Adjustment in the year = Cr. 14846 (subtracted from the balance)

Office Supplies Account is 14846

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Answer:

8 ≥ w > 4

Step-by-step explanation:

This says the w is greater or equal to 8 but it also says that w is greater than 4.

Answer:

8 ≥ w > 4

Step-by-step explanation:

Because 8 is greater than or equal to w, and w is greater than 4.

Answer:

Leonardo emiliano Castañeda

Answer:

Your answer is correct.

Answer:

The answer is 8

Step-by-step explanation: