Answer:
262.5
Step-by-step explanation:
35 percent * 750 =
(35:100)* 750 =
(35* 750):100 =
26250:100 = 262.5
Answer:
262.5
Step-by-step explanation:
what is the expected value (Lesson 8.3: Unbiased Point Estimation. If X1, of the sample variance S2? a. 1/6 b. 1/36 O c. 6 d. 36 e.60
The correct answer is option b. 1/36 is the expected value (Lesson 8.3: Unbiased Point Estimation. If X1, of the sample variance S2.
In unbiased point estimation, the expected value of the sample variance S2 is a crucial idea. When a sample is drawn from a population repeatedly, an average value of S2 is what is anticipated.
The population variance divided by the sample size represents the expected value of S2. It is, in other words, the population variance divided by n-1, where n is the sample size.
As a result, the expected value of the sample variance S2 for a sample size of 6 is equal to 1/36.
As a result, when a sample is drawn from a population repeatedly, the average value of S2 will be equal to 1/36 of the variance in the population.
Complete Question:
What is the expected value (Lesson 8.3: Unbiased Point Estimation. If X1, of the sample variance S2?
a. 1/6
b. 1/36
c. 6
d. 36
e.60
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Under certain conditions, the number of diseased cells N(t) at time t increases at a rate N'(t) = Ae^kt, where A is the rate of increase at time 0 (in cells per day) and k is a constant.
a. Suppose A = 40, and at 5 days, the cells are growing at a rate of 120 per day. Find a formula for the number of cells after t days, given that 200 cells are present at t = 0.
b. Use your answer from part a to find the number of cells present after 11 days.
The formula for the number of cells after t days, given that 200 cells are present at t = 0 is \(N(t) = 40(3^t - 1) + 200\;ln(3)\), whereas the number of cells present after 11 days is approximately 7,085,864.
The given differential equation \(N'(t) = Ae^{kt}\) describes the rate of increase in the number of diseased cells N(t) at time t, where A is the rate of increase at time 0 and k is a constant. The solution to this differential equation is \(N(t) = (A/k) \times e^{kt} + C,\) where C is an arbitrary constant that can be determined from an initial condition.
a. Using the given information, A = 40 and N'(5) = 120. Substituting these values into the equation \(N'(t) = Ae^{kt}\), we get:
\(120 = 40e^{(5k)}\)
Solving for k, we have:
k = ln(3)
Substituting A = 40 and k = ln(3) into the equation for N(t), and using the initial condition N(0) = 200, we get:
\(N(t) = (40/ln(3)) \times e^{(ln(3)t)} + 200\)
Simplifying this expression, we obtain:
\(N(t) = 40(3^t - 1) + 200ln(3)\)
b. To find the number of cells present after 11 days, we substitute t = 11 into the expression for N(t) that we obtained in part a:
\(N(11) = 40(3^{11} - 1) + 200ln(3)\)
Simplifying this expression, we get:
\(N(11) = 40(177146) + 200ln(3) \approx 7,085,864\)
Therefore, the number of cells present after 11 days is approximately 7,085,864.
In summary, the given differential equation \(N'(t) = Ae^{kt}\) describes the rate of increase in the number of diseased cells N(t) at time t, and the solution to this equation is \(N(t) = (A/k) \times e^{kt} + C,\) where C is an arbitrary constant that can be determined from an initial condition.
We used this equation to find a formula for the number of cells after t days, given A, k, and an initial condition, and used it to find the number of cells present after 11 days.
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At what age do many children have the ability to do simple arithmetic problems?
a. Early childhood
b. Middle childhood
c. Infancy
d. Toddler
Many children develop the ability to do simple arithmetic problems during their early childhood years, typically between the ages of 4 and 6. Correct option is a).
During this time, children start to understand basic mathematical concepts such as counting, addition, and subtraction. They may also begin to recognize and name numbers and use basic math vocabulary. However, it's important to note that every child develops at their own pace and some may show these skills earlier or later than others. It's also important for parents and caregivers to provide opportunities for children to practice and reinforce these skills through activities such as counting objects, playing number games, and solving simple math problems.
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Lesson 5 homework practice simplify algebraic expressions. Identify the terms, like terms, coefficients, and constants in each expression.
1. 4b + 7b + 5 2. 8 + 6t – 3t + t 3. –5x + 4 – x – 1
4. 2z – z + 6 5. 4 + h – 8 – h
Terms are 4b, 7b, 5 coefficient are 4 , 7 and constant = 4, 7 , 5
What are the parts in expression?
An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division. The terms involved in an expression in math are:
Constant: A constant is a fixed numerical value.
Variable: A variable is a symbol that doesn't have a fixed value.
Term: A term can be a single constant, a single variable, or a combination of a variable and a constant combined with multiplication or division.
Coefficient: A coefficient is a number that is multiplied by a variable in an expression.
Given expression:
4b+7b+5
As. term can be a single constant, a single variable, or a combination of a variable and a constant combined with multiplication or division.
Terms are 4b, 7b, 5
Now, coefficient is a number that is multiplied by a variable in an expression.
coefficient are 4 , 7
As a constant is a fixed numerical value,
So, constant = 4, 7 , 5
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Epress the ratio of cooking oil(80ml) to the milk (250 ml) of the recipe
Answer:
8:25
Step-by-step explanation:
Hope this helps!
how to graph x<4. (((((((((((((((((((((((((((
What is 15/27.5 to the nearest hundredth?
The quotient of 15 and 27.5, rounded to the nearest hundredth, is given as follows:
15/27.5 = 0.55.
How to obtain the quotient of 15 and 27.5?The quotient of two amounts is given by the division of the first amount by the second amount.
The amounts in this problem are given as follows:
15 and 27.5.
Hence the division has the result given as follows:
15/27.5 = 0.545454.
To round to the nearest hundredth, we must look at the third digit. It is 5, hence one must be added to the second digit, and the rounded result is given as follows:
15/27.5 = 0.55.
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Simplify (-2)^4.
O-8
O 16
O -16
Answer:
16
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
2*2*2*2=16
OR
2*2=4 2*2=4 4+4=8
what is/are the product(s) of the following acid-base mechanism?
The product(s) of an acid-base mechanism depend on the specific reactants involved. Without knowing the reactants, it is not possible to provide a definitive answer.
However, in general, acid-base reactions involve the transfer of a proton (H+) from an acid to a base, resulting in the formation of a conjugate acid and a conjugate base. The conjugate acid is formed by the acceptance of the proton, while the conjugate base is formed by the donation of the proton.
It is important to note that without specific reactants, it is impossible to determine the exact products of an acid-base mechanism. The nature of the reactants and their acid-base properties determine the specific products formed in a given reaction.
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. solve the problem as an lp, ignoring the integer constraints. b. what solution is obtained by rounding up fractions greater than or equal to 1/2? is this the optimal integer solution? c. what solution is obtained by rounding down all fractions? is this the optimal integer solution? explain. d. show that the optimal objective function value for the ilp (integer linear programming) is lower than that for the optimal lp.
As per the information provided, the answer to all the parts in the question will be as follows:
a. To solve the LP problem by ignoring the integer constraints in Excel using Solver, we can follow the steps below:
Enter the objective function and the constraints in a new Excel worksheet: Objective function: Maximize 15x1 + 2x2 Constraints: 7x1 + x2 <= 23 3x1 - x2 <= 5
Open the Solver add-in by clicking on Data -> Solver in the Excel menu.
Set the objective function to maximize and set the variable cells to x1 and x2. Set the constraints by clicking on Add in the Solver Parameters dialog box.
Set the Solver options to "Assume Linear Model" and "Make Unconstrained Variables Non-Negative". Click Solve. The solution to the LP problem is x1=3, x2=2.714, with an optimal objective function value of 51.714.
b. If we round up fractions greater than or equal to 1/2, the solution becomes x1=3, x2=3, with an objective function value of 51. This is not the optimal integer solution, as we will see in part d.
c. If we round down all fractions, the solution becomes x1=2, x2=2, with an objective function value of 34. This is not the optimal integer solution either, as we will see in part d.
d. To solve the ILP problem in Excel using Solver, we can follow the steps below:
Open the Solver add-in by clicking on Data -> Solver in the Excel menu. Set the objective function to maximize and set the variable cells to x1 and x2. Set the constraints by clicking on Add in the Solver Parameters dialog box. Set the Solver options to "Assume Linear Model" and "Make Unconstrained Variables Non-Negative". Add integer constraints by clicking on Add in the Solver Parameters dialog box, and setting the integer constraints for x1 and x2. Click Solve.
The solution to the LP problem is x1=2, x2=3, with an optimal objective function value of 48.
As we can see, the optimal objective function value for the LP problem (48) is lower than that for the LP problem (51.714), regardless of rounding up or down.
e. The optimal objective function value for the ILP problem is always less than or equal to the corresponding LP's optimal objective function value because the LP problem allows fractional solutions, while the ILP problem only allows integer solutions. Introducing additional constraints that restrict the variables to integers can only reduce the feasible solution space, and thus lead to a lower optimal objective function value. The LP and ILP problems would be equal if the optimal solution for the LP problem happens to be an integer solution.
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Note that the full question is:
Given the following all-integer linear program: (COMPLETE YOUR SOLUTION IN EXCEL USING SOLVER AND UPLOAD YOUR FILE. BE SURE THAT EACH WORKSHEET IN THE EXCEL FILE CORRESPONDS TO EACH QUESTION BELOW ) Max 15x1 + 2x2 s. t. 7x1 + x2 < 23 3x1 - x2 < 5 x1, x2 > 0 and integer a. Solve the problem (using SOLVER) as an LP, ignoring the integer constraints.
b. What solution is obtained by rounding up fractions greater than or equal to 1/2? Is this the optimal integer solution? c. What solution is obtained by rounding down all fractions? Is this the optimal integer solution? Explain. d. Show that the optimal objective function value for the ILP is lower than that for the optimal LP (Eg. Resolve original problem using SOLVER with the Integer requirement). e. Why is the optimal objective function value for the ILP problem always less than or equal to the corresponding LP's optimal objective function value? When would they be equal?
Please help me with this math
Answer:
um I don't understand it pls be more specific and I will help
If 2x2 – 28x = –98, then x could equal which of the following?
The value of x in the quadratic equation is as follows:
x = 7 and x = 7
How to solve quadratic equation?A quadratic equation is a polynomial equation in one unknown that contains the second degree, but no higher degree, of the variable.
The standard form of a quadratic equation is ax² + bx + c = 0, when a ≠ 0.
Let's solve for x in the quadratic equation 2x² – 28x = –98.
2x² – 28x = –98
2x² – 28x + 98 = 0
divide through by 2
x² - 14x + 49 = 0
The two numbers you can add get -14 and multiply to get 49 are -7 and -7.
Hence,
x² - 14x + 49 = 0
x² - 7x - 7x + 49 = 0
x(x - 7) -7(x - 7) = 0
(x - 7)(x - 7) = 0
Therefore,
x = 7 and x = 7
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Rewrite the rational exponent as a radical
Answer:
C OR D
Step-by-step explanation:
can someone help me figure this out?
Answer:
Step-by-step explanation:
i dont know this I am sorry :(
Answer:
Tree C
Step-by-step explanation:
each of the charts/tables/paragraphs are talking about a different tree.
Tree A started with 5 inches, as it says.
Tree B started with 3 inches, as you can see under the 0 months.
Tree C, at the month 0 mark, has a height of 10 inches, so it started with 10.
10>5 and 10>4, so Tree C is the biggest
What is the contrapositive of the conditional statement?
If two variables are directly proportional, then their graph is a linear function.
If two variables are directly proportional, then their graph is not a linear function.
If two variables are not directly proportional, then their graph is not a linear function.
If the graph of two variables is a linear function, then the two variables are directly proportional.
If the graph of two variables is not a linear function, then the two variables are not directly proportional.
The contrapositive of the conditional statement is D. If the graph of two variables is not a linear function, then the two variables are not directly proportional.
What are contrapositives ?"In the event that the graph of two variables fails to exhibit linearity, it can be inferred that the two variables are not directly proportional.
This contrapositive statement provides an alternative perspective on the relationship between variables and the nature of their corresponding graphs.
By examining the contrapositive, we employ an analytical approach that explores the logical implications arising from the negation of the original conditional statement. Consequently, if the graph of two variables deviates from the linear pattern, it leads us to the logical conclusion that the variables themselves are not directly proportional.
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Can someone help me pls ASAP
Help help I don’t really get this???
Answer:
Question 4: \(y=\displaystyle -\frac{4}{5}x\)
Question 5: \(y=-5x-3\)
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: \(y=mx+b\) where m is the slope of the line and b is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).
Question 4
1) Determine the slope (m)
\(\displaystyle m=\frac{y_2-y_1}{x_2-x_1}\) where two points that pass through the line are \((x_1,y_1)\) and \((x_2,y_2)\)
In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:
\(\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}\)
Therefore, the slope of the line is \(\displaystyle -\frac{4}{5}\). Plug this into \(y=mx+b\) as the slope (m):
\(y=\displaystyle -\frac{4}{5}x+b\)
2) Determine the y-intercept (b)
On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (b) is 0. Plug this into \(y=\displaystyle -\frac{4}{5}x+b\):
\(y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x\)
Question 5
1) Determine the slope (m)
\(\displaystyle m=\frac{y_2-y_1}{x_2-x_1}\)
Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:
\(\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5\)
Therefore, the slope is -5. Plug this into \(y=mx+b\):
\(y=-5x+b\)
2) Determine the y-intercept (b)
On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (b) is -3. Plug this into \(y=-5x+b\):
\(y=-5x+(-3)\\y=-5x-3\)
I hope this helps!
What is the vertex of the graph of f x )=[ x 5 ]- 6?
The vertex of the graph of f(x) = |x - 5| - 6 is (5, -6). It lies in the fourth quadrant.
Therefore the answer is (5, -6).
The graph f(x) = |x - 5| - 6 is symmetrical about the axis x = 5.
A vertex of a graph is a node of a graph. For a graph of the form f(x) = a|x - h| + k, the vertex is (h, k). So in this case where f(x) = |x - 5| - 6, a = 1, h = 5 and k = -6. Therefore the vertex of the given graph f(x) is
(5, -6)
--The question is incomplete, answering to the question --
"What is the vertex of the graph of f(x) = |x - 5| - 6?"
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A baseball tournament starts out with 128 teams. After each round, half of the teams are eliminated. After 5 rounds, how many
teams are left?
Answer:
4 teams
Step-by-step explanation:
4 teams are left after 5 rounds
Here are two random variables that are uncorrelated but not independent. Let X and Y have the following joint probability mass function:
The marginal probability mass functions of X and Y are:
P(X = 0) = 0.5, P(X = 1) = 0.5P(Y = 0) = 0.3, P(Y = 1) = 0.4, P(Y = 2) = 0.2In the given scenario, X and Y are two random variables that are uncorrelated but not independent. The joint probability mass function of X and Y is provided as follows:
P(X = 0, Y = 0) = 0.2
P(X = 0, Y = 1) = 0.1
P(X = 0, Y = 2) = 0.1
P(X = 1, Y = 0) = 0.1
P(X = 1, Y = 1) = 0.2
P(X = 1, Y = 2) = 0.1
To obtain the marginal probability mass functions, we sum the probabilities for each value of X and Y.
For X:
P(X = 0) = 0.2 + 0.1 + 0.1 + 0.1 = 0.5
P(X = 1) = 0.1 + 0.2 + 0.1 + 0.1 = 0.5
Therefore, the marginal probability mass function of X is P(X = 0) = 0.5 and P(X = 1) = 0.5.
For Y:
P(Y = 0) = 0.2 + 0.1 = 0.3
P(Y = 1) = 0.1 + 0.2 + 0.1 = 0.4
P(Y = 2) = 0.1 + 0.1 = 0.2
Hence, the marginal probability mass function of Y is P(Y = 0) = 0.3, P(Y = 1) = 0.4, and P(Y = 2) = 0.2.
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write an expression!!
The area of the shaded region in terms of 'x' would be (25-\(x^{2}\)) square inches.
Area of a square = \(side^{2}\) square units
Side of the larger square = 5 inches
Area of the larger square = 5×5 square inches
= 25 square inches
Side of smaller square = 'x' inches
Area of the smaller square = 'x'×'x' square inches
= \(x^{2}\) square inches
Area of shaded region = Area of the larger square - Area of the white square
= 25 - \(x^{2}\) square inches
∴ The expression for the area of the shaded region as given in the figure is (25-\(x^{2}\)) square inches
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in a certain amount of time, a plane traveling at a constant $250$ miles per hour traveled $20,\!000$ feet. in this same amount of time, how many feet would a plane traveling at a constant $400$ miles per hour travel?
At a constant rate of 400 miles per hour travel, the plane would be travelling from 32000 feet above the land.
The speed of an object is the ratio of distance and time it takes for the object to travel that distance.
Mathematically,
S = D/T
where
S is velocity
D is the distance traveled or distance traveled
T is the time it takes to travel that distance
Velocity is considered a scalar quantity. A scalar size only has a size. It does not provide information about the direction of object movement.
If an object moves at a constant speed, it means that the object moves the same distance in the same time interval.
Acceleration of an object is the ratio of velocity and time. vector size. Vector quantities have both magnitude and direction.
Mathematics,
a = v/t
When an object is in motion, its acceleration is never zero.
When an object moves, it moves a constant distance over time. Therefore, body positions cannot be the same from the same coordinate system.
Given in the question:
First the plane was travelling at a constant rate of 250 miles per hour.
Initial height was 20000 feet
Now,
As the speed increases and travels at a constant rate of 400 miles per hour.
Now,
(400 /250 ) × 20000
= 1.6 × 20000
= 32000 feet
Thus, At a constant rate of 400 miles per hour travel, the plane would be travelling from 32000 feet above the land.
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When you submit this form, the owner will see your name and email address.
1
Problem 1.
The force system shown is to be replaced with an equivalent system consisting of a horizontal force applied at b and a vertical force applied to the horizontal leg.
1.1. What is the magnitude of the vertical force, in Newton, applied to the horizontal leg? (rounded-off to the nearest whole number; do not write the unit)
The magnitude of the vertical force applied to the horizontal leg in the equivalent force system.
To determine the magnitude of the vertical force applied to the horizontal leg, we need to find the vertical component of the given force system. Looking at the diagram, we observe that the force system consists of a vertical force at point A and a horizontal force at point B. We can use trigonometry to find the vertical component of the force at point A.
Let's denote the magnitude of the force at point A as F_A and the angle it makes with the horizontal leg as θ. The vertical component of the force can be calculated using the formula: Vertical component = F_A * sin(θ).
Since the vertical component of the force should be equal to the force we are trying to find, we can set up the equation: Vertical component = F_vertical.
Now, we can substitute the given values into the equation and solve for F_vertical. Once we have the value, we can round it off to the nearest whole number, as instructed.
Please note that without specific values or angles provided in the problem statement or accompanying diagram, it is not possible to provide a precise numerical answer.
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The sum of the three angles of
any triangle is [ ? ]0.
A set of average city temperatures in May are normally distributed with a mean of 20.66 ^\circ \text{C}20.66
∘
C20, point, 66, degrees, start text, C, end text and a standard deviation of 2 ^\circ \text{C}2
∘
C2, degrees, start text, C, end text. The average temperature of Singapore is 26 ^\circ \text{C}26
∘
C26, degrees, start text, C, end text.
What proportion of average city temperatures are lower than that of Singapore?
You may round your answer to four decimal places.
Answer:
0.9962
Step-by-step explanation:
The z score shows the number of standard deviations by which the raw score is above or below the mean. If the raw score is above the mean then the z score is positive but if the raw score is less than the mean then the raw score is negative. The z score is given by:
\(z=\frac{x-\mu}{\sigma}\\ \\\mu=mean,\sigma=standard\ deviation, x=raw\ score\)
μ = 20.66°C, σ = 2°C
For x < Singapore temperature, i.e. x < 26
\(z=\frac{x-\mu}{\sigma} =\frac{26-20.66}{2}=2.67\)
From the normal distribution table P(x < 26) = P(z < 2.67) = 0.9962
99. Sports In the 2005 Women's NCAA Championship
basketball game, Baylor University defeated Michigan
State University by a score of 84 to 62. Baylor won by
scoring a combination of two-point field goals, three-
point field goals, and one-point free throws. The number
of two-point field goals was six more than the number of
free throws, and four times the number of three-point field
goals. Find the combination of scores that won the
National Championship for Baylor. (Source: NCAA)
The combination of scores that won the National Championship for Baylor are 18 free throws, 24 two point field goals and 6 three-point field goals.
What is an Equation?An equation is a mathematical statement containing two expressions on either sides which are connected with an equal to sign.
Either sides of an equation is called as left hand side and right hand side.
Given Baylor University defeated Michigan State University by a score of 84 to 62.
Score of Baylor University = 84
Baylor won by scoring a combination of two-point field goals, three-point field goals, and one-point free throws.
Let the number of free throws = x
The number of two-point field goals was six more than the number of free throws.
Number of two point field goals = x + 6
Also, the number of two-point field goals was four times the number of three-point field goals.
Number of two point field goals = 4 (number of three-point field goals)
So, 4 (number of three-point field goals) = x + 6
Number of three-point field goals = (x + 6) / 4
Score for free throw = 1 point × x
Score for 2 point field goal = 2 points × (x + 6)
Score for 3 point field goal = 3 points × [(x + 6)/4]
[1 × x] + [2 (x+6)] + [3 ((x+6)/4] = 84
x + 2x + 12 + 3/4 x + 18/4 = 84
3.75x + 16.5 = 84
3.75x = 67.5
x = 18
Number of free throws = x = 18
Number of two point field goals = x + 6 = 18 + 6 = 24
Number of three-point field goals = (x + 6) / 4 = 24/4 = 6
Hence the combination are 18 free throws, 24 two point field goals and 6 three-point field goals.
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The denominator of a fraction is greater than its numerator by 7. If
the numerator is increased by 1 and the denominator is increased by
4, the fraction becomes 1/3
. Find the original fraction.
Answer:
4/11
Step-by-step explanation:
Let :
x = numerator
x + 7 = denominator \(\frac{x}{x + 7}\)
\(\frac{x}{x+7} + \frac{1}{4} = \frac{1}{3}\)
\(\frac{x + 1}{x + 11} = \frac{1}{3}\)
cross multiply
3(x + 1) = x + 11
3x + 3 = x + 11
combine like terms
3x - x = 11 - 3
2x = 8
x = 4
x + 7 = 4 + 7 = 11
original fraction = 4/11
What is the exact length of EC?
A. 4√29/7 Feet
B.√164 Feet
C. 4√5 Feet
D. 2√41 Feet
Answer:
C. \(4\sqrt{5}\) feetStep-by-step explanation:
We have similar triangles:
ΔADC ~ ΔBECFind segment BC using similarity and ratios:
AD/ BE = AC / BC28 / 8 = (10 + BC)/ BC28BC = 8(10 + BC)28BC = 8BC + 8020BC = 80BC = 4Find EC using Pythagorean:
\(EC = \sqrt{BE^2+BC^2}=\sqrt{8^2+4^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}\)Correct choice is C
If f(x)=5x+12, what is f(2)
Answer:
To find f(2), we simply substitute 2 for x in the function f(x)=5x+12 and simplify:
f(2) = 5(2) + 12
= 10 + 12
= 22
Therefore, f(2) = 22.
Step-by-step explanation:
Can someone help me it's due tomorrow
Doing one problem would work for me
The common denominator for the fractions given will be:
1. The common denominator is 8.
2. The common denominator is 6.
3. The common denominator is 10.
4. The common denominator is 12.
How to illustrate the denominator?It should be noted that when a fraction is illustrated as a/b.
a = numerator
b = denominator.
1. We have 1/8 and 1/4. The common denominator is 8 since that's the lowest common multiple for the denominators.
2. We have 4/6 and 1/2. The common denominator is 6 since that's the lowest common multiple for the denominators.
3. We have 2/5 and 1/2. The common denominator is 10 since that's the lowest common multiple for the denominators.
4. We have 5/12 and 1/4. The common denominator is 12 since that's the lowest common multiple for the denominators.
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