The concentration of the diprotic acid H₂X is approximately 0.153488 mol/L.
To find the concentration of the diprotic acid H₂X, we can use the concept of stoichiometry and the balanced equation for the reaction between the acid and sodium hydroxide (NaOH).
The balanced equation for the reaction is:
H₂X + 2NaOH → Na₂X + 2H₂O
Based on the balanced equation, we can determine the mole ratio between H₂X and NaOH, which is 1:2. This means that 1 mole of H₂X reacts with 2 moles of NaOH.
First, let's calculate the number of moles of NaOH used in the titration:
moles of NaOH = volume of NaOH solution (L) × concentration of NaOH (mol/L)
moles of NaOH = 0.0212 L × 0.362 mol/L
moles of NaOH = 0.0076744 mol
Since the mole ratio between H₂X and NaOH is 1:2, the number of moles of H₂X can be determined as:
moles of H₂X = 1/2 × moles of NaOH
moles of H₂X = 1/2 × 0.0076744 mol
moles of H₂X = 0.0038372 mol
Next, we calculate the concentration of the diprotic acid H₂X:
concentration of H₂X (mol/L) = moles of H₂X / volume of H₂X solution (L)
concentration of H₂X = 0.0038372 mol / 0.0250 L
concentration of H₂X = 0.153488 mol/L
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Which two events will happen if more H2 and N2 are added to this reaction after it reaches equilibrium?
3H2 + N2 to 2NH3
If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)
1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).
2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.
It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).
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Recycling of aluminum beverage cans is an example of the fact that Group of answer choices decreasing entropy is a spontaneous process. increasing entropy is a spontaneous process. decreasing entropy is a nonspontaneous process. increasing entropy is a nonspontaneous process.
Answer:
The correct option is;
decreasing entropy is a nonspontaneous
Explanation:
Recycling of aluminium beverage cans involves the process of remelting scrapped beverage after the cans were first produced and used initially
1) The cans are cut into pieces so as to make them more compact and accessible for cleaning
2) The cans are then blocked and melted by heating and the impurities and hydrogen gas are removed
3) The composition of the molten aluminium alloy is altered by the addition of the alloy composition to get the right specification of the alloy
4) The molten alloy can then be sent for usage where it will be processed into solid aluminium objects without the requirement for much energy addition
By the second law of thermodynamics, processes 1, and 2 which involve the addition of energy from the surrounding to decrease the randomness of the scrapped beer cans such that the entropy of the surrounding decreases are not spontaneous processes, while process 4 where the molten aluminium will be cooled down to form solid aluminium does not require energy input but adds energy to the surrounding in the surrounding's entropy, is therefore a spontaneous process.
Therefore, decreasing the entropy of the universe by heating aluminium to melt it is a non spontaneous process
Identify the bases below that can be used to deprotonate a terminal alkyne.
a. NaNH
b. NaOCH
c. NaH
d. NaOH
The bases given that can be used to deprotonate a terminal alkyne include a. NaNH₂ and c. NaH.
How to find the bases that can deprotonate a terminal alkyne?Terminal alkynes are organic compounds that contain a carbon–carbon triple bond at the end of the carbon chain. They are relatively acidic and can be deprotonated by a strong base to form an acetylide ion.
Sodium amide is a very strong base ( pKa of its conjugate acid, NH3, is ~38 ), so it can deprotonate a terminal alkyne. Sodium hydride is a very strong base ( pKa of its conjugate acid, H2, is ~35 ), so it can deprotonate a terminal alkyne.
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When a substance is hard but liable to break or shatter easily, it is called...
a malleability
b brittle
c luster
d compound
Answer:
B. Brittle
Explanation:
It's a substance that is hard but liable to break or shatter easily.
Brittleness is the quality of objects and materials to break easily, that is, it is the ability of a material to fracture with little deformation.
What is brittleness?Brittleness is the mechanical property of a material as opposed to toughness, that is, it is the ease with which a material breaks without causing elastic deformation.
Characteristics of a brittle substanceIt is hard but tends to break on light impact.Brittle substances have greatly reduced elastic and plastic phases.Therefore, we can conclude that brittleness is the ability of some materials to shatter or break, undergoing little deformation.
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[H+] = [OH-] represents what type of solution?
Answer:
An acid is a solution with more H+ ions than OH- ions. An acid is any compound that yields hydrogen ions (H+) or hydronium ions (H3O+) when dissolved in water. Hydronium ions – are the combination of H+ ions and H2O molecules.
Explanation:
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When measuring the volume of a liquid, why is it best to use a measuring container that is narrow?
Answer:
n the sciences, the “tools” for measuring the volumes of liquids are generally made from glass, plastic or occasionally metal, although professionals referred to all of them as “glassware.” Scientists, and chemists in particular, have a variety of glassware at their disposal for measuring volumes. The particular piece of glassware chosen in any situation will depend primarily upon two factors: the required volume and the accuracy required for the measurement.
Explanation:
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Two rabbit species, X and Y, live in an Arctic environment that is also populated by wolves. Species x turns white in the winter and
brown in the spring. Species y stays brown all year. The population of species X has slowly been increasing over the population of
species Y. What is most likely causing this population change?
Answer:
yy
Explanation:
convert 10erg into joule
Answer:
0.000001 joule
Explanation:
brainlest?
the amount of space an object occupies is called its
Which method would NOT encourage more product, HI, to form from the reaction below?
51.8 kJ + H₂(g) + 1₂(g) ⇒ 2HI(g)
A. heat the reaction
B. add H, gas
C. add HI gas
D. add I, gas
We must first comprehend the balanced equation for the reaction between phosphoric acid and magnesium in order to determine how many moles of hydrogen may be produced from a starting point of.435 moles of phosphoric acid and surplus magnesium.
This reaction's balanced equation is 2H3PO4 + 3Mg 3Mg2+ + 2HPO4-2 + 3H2. This equation tells us that three moles of hydrogen are created for every two moles of phosphoric acid. We may thus estimate that.653 moles of hydrogen will be created if we start with.435 moles of phosphoric acid.
.653 moles of hydrogen are obtained by multiplying.435 moles of phosphoric acid by 3/2, which is the calculation used to determine this. Therefore, if we begin with.435 moles of phosphoric acid and too much.
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Animals in an experiment are to be kept under a strict diet. Each animal should receive 25 grams of protein and 5grams of fat. The laboratory technician is able to purchase two food mixes: Mx A has 10% protein and 6% fat; mix B has 50% protein and 5% fat. How many grams of each mix should be used to obtain the right diet for one animal? One animar's diet should consist of grams of MaA.
250 grams of Mix A (MxA) should be used to obtain the right diet for one animal.
To determine the number of grams of Mix A (MxA) needed to obtain the right diet for one animal, let's assume that x represents the number of grams of MxA used.
The protein content in MxA is 10%, which means 0.10x grams of protein will be obtained from MxA.
The fat content in MxA is 6%, which means 0.06x grams of fat will be obtained from MxA.
Since the desired diet for one animal should consist of 25 grams of protein and 5 grams of fat, we can set up the following equation based on the protein content:
0.10x = 25
Solving for x:
x = 25 / 0.10
x = 250 grams.
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Net redox reaction in acetyl CoA formation and the citric acid cycle
In the sequential reactions of acetyl CoA formation and the citric acid cycle, pyruvate (the output from glycolysis) is completely oxidized, and the electrons produced from this oxidation are passed on to two types of electron acceptors.
Drag the labels on the left to show the net redox reaction in acetyl CoA formation and the citric acid cycle. Note that two types of electron carriers are involved.
a) CO2
(b) NADH
(c) FAD
(d)FADH2
The net redox reactions and labels involving the two types of electron carriers in acetyl CoA formation and the citric acid cycle are:
Acetyl CoA Formation: (b) NADH and (a) CO2
Citric Acid Cycle: (b) NADH, (d) FADH2, and (a) CO2
The metabolic process of acetyl CoA formation and the citric acid cycle is a key pathway for energy production in cells.
Pyruvate, the end product of glycolysis, is completely oxidized during this process, and the electrons produced from this oxidation are passed on to two types of electron acceptors: NAD+ and FAD. NAD+ is reduced to NADH, while FAD is reduced to FADH2.
These electron carriers play a critical role in the production of ATP, which is the primary energy currency of cells. The NADH and FADH2 produced during these reactions are then used in the electron transport chain to generate a proton gradient, which drives the synthesis of ATP.
Acetyl CoA Formation:
Pyruvate + CoA + NAD+ -> Acetyl-CoA + CO2 + NADH
Citric Acid Cycle:
Acetyl-CoA + 3NAD+ + FAD + GDP + Pi -> 2CO2 + 3NADH + FADH2 + GTP + CoA
So the labels would be:
Acetyl CoA Formation: (b) NADH and (a) CO2
Citric Acid Cycle: (b) NADH, (d) FADH2, and (a) CO2
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Why did the percentage of oxygen increase in the early atmosphere?
The increase in the percentage of oxygen in the early atmosphere was a result of the evolution of photosynthetic organisms, and it played a crucial role in the development of life on Earth.
What is Atmosphere?
The atmosphere is the layer of gases that surrounds a planet and is held in place by the planet's gravity. On Earth, the atmosphere is composed of a mixture of gases that include nitrogen (78%), oxygen (21%), argon (0.9%), and carbon dioxide (0.04%), as well as trace amounts of other gases. The atmosphere plays a vital role in supporting life on Earth, providing the air that we breathe and protecting us from harmful radiation from the sun.
The early atmosphere of the Earth was mostly composed of nitrogen, carbon dioxide, water vapor, and small amounts of methane, ammonia, and other gases. The percentage of oxygen in the early atmosphere was very low, estimated to be less than 0.1%.
The increase in the percentage of oxygen in the Earth's atmosphere is believed to be due to the emergence and evolution of photosynthetic organisms, such as cyanobacteria and algae. These organisms are capable of using sunlight to convert carbon dioxide and water into organic matter and oxygen through the process of photosynthesis. This process began around 3.5 billion years ago and over time, oxygen began to accumulate in the atmosphere, as it was released as a waste product of photosynthesis.
As oxygen levels increased, it became possible for more complex organisms to evolve, including those that use oxygen for respiration. The accumulation of oxygen also had a significant impact on the Earth's climate and environment, leading to the development of the ozone layer and the reduction of carbon dioxide levels in the atmosphere.
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which of the following best summarizes the composition of hydrocarbon molecules in this outcrop of tar sand? choose one: a. small, simple hydrocarbon molecules b. moderate-length chain hydrocarbon molecules c. large, complex chain hydrocarbon molecules
The Correct answer is A) small, simple hydrocarbon molecules the following best summarizes the composition of hydrocarbon molecules in this outcrop of tar sand.
Crude oil, natural gas, and coal all contain hydrocarbons, which are organic molecules made of hydrogen and carbon. Humans have modified them to be utilized as an energy source, such as in the production of gasoline and jet fuel.
The simplest organic molecules, hydrocarbons are composed exclusively of hydrogen and carbon atoms.
Fuel is the most significant application of hydrocarbons. Among the most widely used hydrocarbon fuels include gasoline, natural gas, fuel oil, diesel, jet fuel, coal, kerosene, and propane. Plastics and synthetic fabrics like polyester are made using hydrocarbons as well.
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D5W refers to one of the solution used as an intravenous fluid. It is a 5% by mass solution of dextrose, C 6 H 12 O 6 in water. The density of D5W is 1.08 g/ml. The molarity of the solution isa. 0,3 Mb. 0,6 Mc. 0,28 Md. 0,26 M
D5W refers to one of the solutions used as an intravenous fluid. It is a 5% by mass solution of dextrose, C6H12O6 in water. The density of D5W is 1.08 g/ml. The molarity of the solution is 0.3 M. Thus, option a is correct.
The formula for molarity is as follows:
Molarity (M) = Moles of Solute ÷ Volume of Solution (in liters).
As a result, let's start by calculating the moles of solute:
Mass (M) = Density (D) x Volume (V)
= 1.08 g/ml x 1000 ml Mass (M) = 1080 g
Since the percentage of dextrose in D5W is 5% by mass, the mass of dextrose in 1000 ml of D5W can be calculated as follows:
Mass of Dextrose = (5/100) x 1080 g Mass of Dextrose = 54 g
Moles of Dextrose = Mass of Dextrose ÷ Molar mass of dextrose
Moles of Dextrose = 54 g ÷ 180 g/mol = 0.3 mol
Molarity (M) = Moles of Solute ÷ Volume of Solution (in liters) = 0.3 mol ÷ 1 L = 0.3 M
Therefore, the molarity of the solution is 0.3 M. Thus, option a is correct.
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If a hypothetical future Earth has increased the amount of radiation emitted to 604 W/m, calculate the hypothetical global surface temperature in degrees Kelvin and then in Celsius
Answer:
Explanation:
For amount of radiation from a hot body there is Stefan's Boltzman's law which is given below .
E = e σ T⁴
E is amount emitted , e is emissivity , σ is stefan's constant = 5.67 X 10⁻⁸ W / m² . for earth e =.85 approx
E = .85 x 5.67 X 10⁻⁸ x T⁴
604 = .85 x 5.67 X 10⁻⁸ x T⁴
604 = 4.82 x 10⁻⁸ T⁴
T⁴ = 125.31 x 10⁸
T = 3.3457 x 10²
= 334.57K
Temperature in Celsius = 334.57 - 273
= 61.57 Celsius .
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Someone administers a toxin that disrupts ribosomal RNA (rRNA) synthesis in the cell above. Which labeled structure would be most negatively impacted by this toxin?
Choose 1 answer:
(Choice A) None of these labeled structures would be negatively impacted.
(Choice B) Structure B
(Choice C) Structure C
(Choice D) Structure D
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Answer:
D. Endoplasmic reticulum
Explanation:
Because Rough endoplasmic reticulum contains Ribosomes.
Which of the following CANNOT be determined by looking at the spectra of a star? *
A:temperature
B:composition (the elements that make up the star)
C:movement toward or away from Earth
D:distance from Earth
Answer:
A:temperature
Explanation:
The temperature cannot be determined by looking at the spectra of the star due to lack of the equipment for its measurement. On the other-hand, the remaining statements like the distance from earth, movement towards or away from earth can be determined.
Calculate the number of moles of 2.00g of K2SO4
help asap!!
The higher the concentration of a sample of dilute sulfuric acid, the greater the volume of sodium hydroxide needed to neutralise the acid. A student tested 2 samples P and Q. Describe how the student could use titration to find out which sample P or Q is more concentrated
This problem is providing information about the titration of sulfuric acid with sodium hydroxide in order to neutralize the acid. It is required to describe how to find out the difference concentration on P and Q via titration.
In such a case, we should firstly write out the chemical reaction that takes place when sulfuric acid is neutralized by sodium hydroxide to form sodium sulfate and water:
\(2NaOH(aq)+ H_2SO_4\rightarrow Na_2SO_4 (aq)+2H_2O(l)\)
The aforesaid means that at the equivalence point, the following equation will be valid for the moles of the acid and the base:
\(2n_{acid}=n_{base}\)
Which can be written in terms of volume and concentration for the both of them:
\(2M_{acid}V_{acid}= M _{base} V_{base}\)
Thus, we can solve for the molarity of the acid to obtain:
\(M_{acid}= \frac{M _{base} V_{base}}{2V_{acid}}\)
This equation can be used to calculate the molarity of both samples of acid, if you know their volume, the concentration of the base and its volume, which are measurements and values you can obtain from your experiments.
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What is the sum of all the coefficients in this reaction when properly balanced?
Lead (II) nitrate + hydrogen sulfide yields lead (II) sulfide + nitric acid (HNO3)
Answer:
5
Explanation:
The properly balanced chemical equation for this is:
Pb(NO₃)₂ + H₂S → PbS + 2HNO₃
The coefficients in order are 1, 1, 1, and 2.
Therefore, 1+1+1+2=5
The sum of the coefficients added up is 5.
an atom in its ground state absorbs a single photon of light and then relaxes back to the ground state by emitting an infrared photon (1,200 nm) followed by an orange photon (600 nm). what is the wavelength of the photon that was absorbed initially
Wavelength of the photon of light and then relaxes back to the ground state by emitting an infrared photon (1,200 nm) followed by an orange photon (600 nm) that was absorbed initially is 400nm
Wavelength of the photon that was absorbed initially can be calculated as follows:
Photon's energy is inversely related to its wavelength.
E ∝ 1/λA
Given that the energy of the absorbed photon () equals the total energy of the photons released (E₁ +E₂).
Eₐ=E₁ +E₂
the relationship between E and λ,
1 = 1 + 1
λₐ λ₁ λ₂
1 = 1 + 1
λₐ 600x 10⁻⁹ 1200x 10⁻⁹
λₐ = 400nm
Therefore, the wavelength of the absorbed photon is 400 nm.
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Why should we work to protect estuaries? Select all that apply.
PLSSSS
Answer:
1, 3, and 4
Explanation:
I'm guessing, but those make the most sense
Answer:
3 and 4
Explanation:
Arrange the fatty acids in order of increasing melting point. Lowest melting point a-linoleic acid (18:3) oleic acid (18:1) stearic acid (18:0) palmitoleic acid (16:1) palmitic acid (16:0) Highest melting point
The order of the fatty acids in increasing melting point can be given as:
Lowest melting point- a-linoleic acid (18:3), Palmitoleic acid (16:1), Oleic acid (18:1), Palmitic acid (16:0), Stearic acid (18:0), and Highest melting point- Arachidonic acid (20:4).
What are fatty acids?
A fatty acid can be described as a molecule that consists of a long chain of carbon atoms attached to a carboxyl group (-COOH) at the end. The melting point of a fatty acid is dependent on the length of the carbon chain as well as the degree of unsaturation. The longer the carbon chain, the greater the melting point. The degree of unsaturation in a fatty acid is also a determining factor in its melting point because double bonds introduce kinks in the chain, preventing the formation of tightly packed crystalline structures.
Arrange the fatty acids in order of increasing melting point.
Lowest melting point: a-linoleic acid (18:3), Palmitoleic acid (16:1), Oleic acid (18:1), Palmitic acid (16:0), Stearic acid (18:0)Highest melting point: Arachidonic acid (20:4).
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3. How many atoms are found in 5.20 g of magnesium (Mg)?
Explanation:
In order to go from mass of magnesium to atoms of magnesium, we have to do two things:
Convert mass of Mg to moles of Mg using the molar mass of Mg as a conversion factor
Convert moles of Mg to atoms of Mg using Avogadro's number (6.02×1023) as a conversion factor
Step 1:
Before we start, I should note that the molar mass of Mg is 24.31gmol. We can go from mass to moles using dimensional analysis. The key to dimensional analysis is understanding that the units that you don't need any more cancel out, leaving the units that are desired:
48.60g
×1mol24.31g
=2.00mol
Step 2:
We'll use this relationship:
www.sprinklernewz.uswww.sprinklernewz.us
Using the moles of Mg that we just obtained, we can use Avogrado's number to perform dimensional analysis in order to cancel out units of mol to end up with atoms of Mg:
2.00mol
×6.02×1023atoms1mol
=1.204×1024atoms
Thus, 48.60g of Mg is equivalent to 1.204×1024atoms
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what is the ratio for 3 : 20 = 6 : _____
Answer:
3 : 20 = 6 : 40
Explanation:
3 is multiplied by 2 so the 20 is also multiplied by 2 giving you the answer above.
When elements chemically combine with each other, what do they form?
Answer:
Compounds
Explanation:
A compound is a substance formed when two or more elements are chemically joined. (For example Water, salt, and sugar are compounds.) When the elements are joined, the atoms lose their individual properties and have different properties from the elements they are composed of.
Replace this sample text with the prompt or directions for this item.
The atomic number of an element is the number of
The atomic mass is the number of
The electrons in the outermost shell are known as the
protons protons and neutrons
valence electrons
Answer:
1. Protons
2. Protons and Neutrons
3. Valence electrons
Explanation:
+1
Given the overall cell reaction: Zn(s) + Agt! → Zn*2 + Ag(s)
Which of the following will occur as the cell operates?
(1) The amount of Ag(s) will decrease (3) The amount of Agt will increase
2) The amount of Zn(s) will increase (4) The amount of Zn^2 will increase
A high viscosity liquid will
Answer: high viscosity fluids move sluggishly and resist deformation.
Explanation: some examples of high viscosity liquids is Honey, syrup, motor oil, and other liquids that do not flow freely