find the average value have of the function h on the given interval. h(u) = (18 − 9u)−1, [−1, 1]

The number of phones sold is 26 and the number of accessories sold is 30.

An equation is said to be linear if the maximum power of the variable is usually 1.  A linear equation with one variable has the standard form Ax + B = 0. In this case, x is the variable and A is the coefficient of x, and B is a constant.

In mathematical problems, 'x' stands for unknown value or quantity. Here we use the Linear equation concept to solve the problem.

Given that

Cameron earns an $11 commission for every phone he sells and a $2. 50 commission for every accessory he sells.

On a given day Cameron made a total of $361 in commission from selling a total of 56 phones and accessories sold. ​

Let x and y be the number of phones and accessories

Given that

Cameron made a total of $361 in commission

=> 11x + 2.5y = 361  ----- (1)

Total number of phones and accessories sold

=> x + y = 56

Multiply by 11

=> 11x + 11y = 616 ----- (2)

Do (2) - (1)

=> 11x + 11y - ( 11x + 2.5y) = 616 - 361

=> 11x + 11y - 11x - 2.5y = 255

=> 8.5y = 255

=> y = 255/8.5

=> y = 30  

Substitute y = 30 in x + y = 56  

=> x + 30 = 56

=> x = 26

Therefore,

The number of phones sold is 26 and the number of accessories sold is 30.

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Answer:

$19.50

Step-by-step explanation:

Turn the %15 into a decimal

130 x 0.15 = 19.50

They left $19.50 as their tip.

Answer:  Oldi gives the best value of money.

Step-by-step explanation:

Lidal's deal : 9 rolls for £3.51

Oldi's deal : 4 rolls for  £1.52

Cost per roll = \(\dfrac{\text{total cost}}{\text{Number of rolls}}\)

So,

For Lidal, Cost per roll = \(\pounds\dfrac{3.51}{9}=\pounds0.39\)

For Oldi', Cost per roll = \(\pounds\dfrac{1.52}{4}=\pounds0.38\)

Clearly,  \(\pounds 0.39> \pounds 0.38\)

Hence, Oldi gives the best value of money.

The domain of f/g(x) is given by B. {x ∈ ℝ | x ≠ -2, -3, 3}The correct option is B. {x ∈ ℝ | x ≠ -2, -3, 3}, which represents the real numbers excluding -2, -3, and 3.

To find the domain of f/g(x), we need to consider the values of x for which the denominator g(x) is non-zero. Division by zero is undefined in mathematics, so we exclude any values of x that make the denominator zero.

The denominator g(x) = x^3 + 2x^2 - 9x - 18 can be factored as follows:

g(x) = (x - 3)(x + 2)(x + 3)

To determine the values of x that make the denominator zero, we set each factor equal to zero and solve for x:

x - 3 = 0 => x = 3

x + 2 = 0 => x = -2

x + 3 = 0 => x = -3

Therefore, the values x = -2, x = -3, and x = 3 make the denominator zero.

To find the domain of f/g(x), we exclude these values from the domain of f(x). Hence, the domain of f/g(x) is given by:

{x ∈ ℝ | x ≠ -2, -3, 3}

Therefore, the correct option is B. {x ∈ ℝ | x ≠ -2, -3, 3}, which represents the real numbers excluding -2, -3, and 3.

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Answer:

a.

\(f(t) = 21000( {.918}^{t} )\)

b.

\(f(4) = 21000( {.918}^{4}) = 14913.86\)

Answer:

a=30°; b=40°;c=40°; d=40°; e=110°: f=110°; g=30°; h=140°; i=70°; j=70°

True. In a pairwise scatter plot matrix, each scatterplot represents the relationship between two variables.

Since the scatterplot between variable X and variable Y is the same as the scatterplot between variable Y and variable X, the matrix is perfectly symmetric.

The scatterplot at the lower-left corner is indeed identical to the one at the upper-right corner. This symmetry is a result of the fact that the relationship between X and Y is the same as the relationship between Y and X.

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Answer:

see below

Step-by-step explanation:

y=mx+b: slope and intercept

ax+by/c: standard

(x-x1)*m=y-y1: point slope

The remaining work can be completed by c in 4 days

Calculating work:

We consider the total work as 1 unit

If a person can complete a work in a number of days

Then the efficiency of the person per day = 1/number of days  

And the total Work done = Number of Days × Efficiency

From the given problem,

a can do a work in 5 days

The work can be done by 'a' in 1 day (efficiency of a) = 1/5

b can do work in 10 days  

The work can be done by 'b' in 1 day = 1/10

c can do work in 15 days  

The work can be done by 'c' in 1 day = 1/15    

The work can be done by a, b, and c = 1/5 + 1/10 + 1/15

=  [ (6+3+2)/30 ] =  11/30  

a, b and c started working together and worked for 2 days

The total work done in 2 days = 2 × [ total work done by a, b, c in 1 day ]

= 2(11/30) = 11/15

a, b and c worked for 2 days and completed 11/15 of work

after that, a, and b left, and the remaining work is done by c

Let c complete the remaining work in x days

The work can be done by 'c' in x days = x [ efficiency of c ] =x/15    

As we know the total work = 1 unit

⇒ 11/15 + x/15 = 1

⇒ (11 + x) /15 = 1

⇒ 11 + x = 15

⇒ x = 15 - 11 = 4

c can complete the remaining work in 4 days

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True. It's because the capacitance between two plates depends on the electric field between them, which is naturally geometry-dependent; if you have charges in different places, you get a different electric field.

A capacitor's capacitance is affected by the area of the plates, the distance between the plates, and the dielectric's ability to support electrostatic forces.
The capacitance of a parallel plate capacitor (depending on its geometry) is given by the formula C=Ad C = A d, where C is the capacitance value, A is the area of each plate, d is the distance between the plates, and is the permittivity of the material between the parallel capacitor's plates.
The curvature of the plates indicates whether the plates are spherical or cylindrical. As a result, the only factor that has no effect on the capacitance of the capacitor is the type of material used to make the plates.

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The graph of the function is attached below:

The asymptote of the function is:

(-3 log(-x-4)/log2)-8  →∞ as x→ -4

Exactly one element of Y is assigned to each element of X in a mathematical function from a set X to a set Y. The sets X and Y are referred to together as the function's codomain and domain, respectively.

Al-Biruni and Sharaf al-Din al-Tusi were two Persian mathematicians who are credited with developing the earliest known approach to the concept of function. The basic conception of functions was the relationship between fluctuating quantities and other variables. An illustration of this is how time affects a planet's position. The idea was developed historically with the infinitesimal calculus towards the end of the 17th century, and until the 19th century, the functions that were taken into consideration were differentiable.

Given function is,

f(x)= -3 log₂ (-x-4) - 8

The graph of the function is attached below:

The asymptote of the function is:

(-3 log(-x-4)/log2)-8  →∞ as x→ -4

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Answer:

<4 = 67 degrees

Step-by-step explanation:

angle 1 + angle 4 makes 180 degrees so since angle 1 is 113 degrres

180-113=67

Hope it helps:)

Therefore, it can be seen that the CIA profit/loss is $111,878.

Borrow $4 million in USD at the 4-month interest rate of 2.9%.

Convert the USD to CAD at the spot rate of 1.278 CAD/USD.

Invest the CAD in a 4-month Canadian deposit account at the 4.7% interest rate.

Sell the CAD forward at the 4-month forward rate of 1.2902 CAD/USD.

After 4 months, repay the USD loan and settle the forward contract.

The profit/loss from the CIA strategy is calculated as follows:

Profit/loss = (Interest earned on CAD deposit - Interest paid on USD loan) - (Forward rate - Spot rate)

In this case, the profit/loss is calculated as follows:

Profit/loss = (0.047 * 4,000,000 - 0.029 * 4,000,000) - (1.2902 - 1.278)

= $112,000 - $0.12

= $111,878

Therefore, the CIA profit/loss is $111,878.

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2) To this, the input is the value on the horizontal axis of the graph, the output is the value on the vertical axis of the graph. By connecting the two values and seeing where they meet up is how I got the answers.

a) input = -6     output = 1

b) input = 5      output = -3

c) input = 0       output = -1

Hope that helps!

The energy of each photon in the beam is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Substituting the values, we get E = (6.626 x 10^-34 J s)(2.998 x 10^8 m/s)/(500 x 10^-9 m) = 3.98 x 10^-19 J.

The intensity of the beam is the rate at which energy is passing through a unit area perpendicular to the direction of propagation of the beam, given by I = P/A, where P is the power and A is the area. The power of the beam is the product of the energy of each photon and the number of photons passing through a unit area per unit time, given by P = nEAv, where n is the concentration of photons, A is the area, v is the speed of the beam, and E is the energy of each photon.

Substituting the values, we get P = (1.7 x 10^13 m^-3)(3.98 x 10^-19 J/photon)(1 m^2/s)(2.998 x 10^8 m/s) = 1.02 W. The area of the beam is not given, so we cannot calculate the intensity directly. However, if we assume a circular beam with a radius of 1 cm (area = πr^2 = π(0.01 m)^2 = 3.14 x 10^-4 m^2), we can calculate the intensity as I = P/A = 1.02 W/3.14 x 10^-4 m^2 = 3.24 x 10^3 W/m^2, which is closest to option E) 3.2 x 10^2 W/m^2 (after rounding to the nearest tenth).

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Answer:

21/2 or 10.5

Step-by-step explanation:

5x - 3y

5(5/2) - 3(2/3)

25/2 - 2

25/2 - 4/2

21/2

The poll will show an error of 600 votes. The total number of votes including the error will be 15600 or 14400.

Statement B is correct.

A percentage can be defined as a number that is expressed in fractions of 100. The percentage is denoted by the sign "%".

Given that the total number of actual voters is 15,000 for Candidate A. A poll has a percent error of 4%.

The error can be calculated as given below.

\(E = 15000 \times \dfrac {4}{100}\)

\(E = 600\)

The poll has an error of 600 votes.

The total number of votes A including errors are given as,

\(A = 15000 + E\\A = 15000 + 600\\A = 15600\)

Or

\(A = 15000 -E\\A = 15000-600\\A = 14400\)

Hence we can conclude that the total number of votes including the error shown by the poll is 15600 or 14400. Statement B is correct.

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Answer:

acute equilateral

Step-by-step explanation:

acute is less than 90 angles, and all sides are equal.

Answer:

It looks to me like an Acute Equilateral.

Step-by-step explanation:

The maximum of y(t) in meters is 838 meters. Rounded-off to three significant figures, the maximum of y(t) is 838 m. Therefore, the answer is "838 meters (your numerical answer must be written here)."

We can use the formula of the vertical coordinate y(t) of the projectile when air resistance is proportional to the velocity of the projectile. y(t) = (p / k) (v_0 + (mg / k)) - (mg / k) t - (1 / 2)(k / m) t^2, where v_0 is the initial velocity, m is the mass of the projectile, k is a constant depending on the geometry of the projectile, p is the empirical coefficient, and g is the acceleration due to gravity.

Using the given data, we have y(3) = 419 meters and y(6) = 679 meters.

Substituting the values of time and vertical coordinate into the formula, we have two equations:y(3) = (p / k) (v_0 + (mg / k)) - (mg / k) (3) - (1 / 2)(k / m) (3)^2 = 419 ... (1)y(6) = (p / k) (v_0 + (mg / k)) - (mg / k) (6) - (1 / 2)(k / m) (6)^2 = 679 ... (2)

We can solve this system of equations by using the substitution method. First, we can solve equation (1) for v_0:v_0 = [(y(3) + (mg / k) (3) + (1 / 2)(k / m) (3)^2) k / p] - (mg / k) ... (3)

Substituting equation (3) into equation (2), we have:y(6) = (p / k) [(y(3) + (mg / k) (3) + (1 / 2)(k / m) (3)^2) k / p] - (mg / k) + (mg / k) (3) + (1 / 2)(k / m) (6)^2 ... (4)

Simplifying equation (4), we get:y(6) = (y(3) + (mg / k) (3) + (1 / 2)(k / m) (3)^2) (6 / 3)^2 ... (5)

Simplifying, we get:p / k = 0.0358696

Substituting this value into equation (3), we have:v_0 = 83.8331 m/s

Substituting v_0 and p / k into equation (6), we get:k = 3.69431 kg/ms, p = 0.132552

We can find the maximum of y(t) by finding the derivative of y(t) with respect to t and setting it to zero:y'(t) = (p / k) (v_0 + (mg / k)) - (mg / k) - (k / m) t = 0

Solving for t, we get:t = (p / mg) (v_0 + (mg / k)) ... (8)

Substituting v_0, p / k, m, g, and k into equation (8), we have:t = 7.23335 s

Substituting t into equation (1) or (2), we have:y_max = 838.308 m

Rounded-off to three significant figures, the maximum of y(t) is 838 m.

Therefore, the answer is "838 meters (your numerical answer must be written here)."

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Answer:

a=35°, b=55°, c=110°

Step-by-step explanation:

reason for a and b is that when 2 lines intersect, the opposite angles are equal.

well for c angles on a straight line add upto 180.

Answer:

P1= -2/3

P2= -10/3

Step-by-step explanation:

take the sq rt of both sides and use both + and - roots

3P+6=4

3P+6=-4

subtract 6 from both sides for each one

3P=-2

P=-2/3

3P=-10

P= -10/3

Answer:

since traingleABC~ADE

AB/BD=BC/DE

9/15=3/X

9X=15×3

X=15×3/9=5

The value of x is 5 units.

We need to solve for x, from the given figure.

Two triangles are similar if their corresponding angles are congruent and corresponding sides are proportional.

Now, in ΔABC and ΔADE

∠B=∠D=90°

∠EAD=∠CAB (common angles)

So, from AA similarity ABC~ADE

Then, AB/AD=BC/DE

9/15=3/x

9X=15×3

X=15×3/9=5 units

Therefore, the value of x is 5 units.

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Answer:

Step-by-step explanation:

A rectangular carpet measures 8 m by 6 m​Part of the carpet is covered by a square rug of length 2 m

Each game played is independently won by team A with probability p, then team A will surely win the first game.

Given that one team leads 3 to 0, this would mean that in 3 trials, team A won all three games.

The probability of winning 3 out of 3 for team A is

P(A) = P3

The probability of winning 3 out of 3 for team B is

P(B) = (1-P)3

It is given that one of these two scenarios is the case, then the probability it is team A is:

P3/ (P3 + (1-P)3)

The probability that team A would win 0 of the next 4 games is

(1-P)4,

this means the probability that team A wins the series if they are up 3 to 0 is

1 - ( 1 - P ) 4

Similarly, if team A is to win every game, it is surely that they will win the first game.

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Answer: y=-2

Step-by-step explanation:

Based on the location of the line and the focus of the parabola, the equation of the line will be y = -2.

The line is a horizontal line which means that the primary focus will be on the y axis.

The focus of the parabola is at F(6, 4) and the line is to be 6 units below this focus which means that the line on the y axis will be at:

= 4 - 6

= -2

This leaves the formula of the line as y = -2.

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20 m longer it is to walk from A to B along the diagonal of the walk than to walk along the edges of the park.

Given:

Assume ABCD is a rectangular park of right triangles ABC of length = 40m, width = 30m, ∠C = 90

In the right-angled triangle ABC,

By Pythagoras' theorem,

AB² = AC² + BC²

AB² = 30² + 40²

AB² = 900 + 1600

AB² = 2500

AB² = \(\sqrt{2500}\)

AB = 50m

The distance from A to B along the diagonal of the park = 50m

The distance from A through to C = 30m.

The distance from A through C to B = 30 + 40 = 70m.

Therefore, 20 m longer it is to walk from the diagonal of the park to walk along the edges of the park.

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Answer:

Growth

Step-by-step explanation:

Answer:

k=12

Step-by-step explanation:

k=29-17

29-17=12

Answer:

here man let me is 1 im sure the answer is =((1))

Step-by-step explanation:

6^(-3 * 10^(-10 * 27 * 25 / 5^(-8 * 3^(4 * 2^-3))))

a)  A steer weighing 1000 pounds would be approximately 1.4805 standard deviations below the mean.

b) A steer weighing 1250 pounds would be more unusual in this context.

To calculate the number of standard deviations from the mean, we can use the formula:

z = (x - μ) / σ

where:

- z is the number of standard deviations

- x is the given weight

- μ is the mean weight

- σ is the standard deviation

a) For a steer weighing 1000 pounds:

z = (1000 - 1114) / 77 ≈ -1.4805

Therefore, a steer weighing 1000 pounds would be approximately 1.4805 standard deviations below the mean.

b) To determine which weight is more unusual, we need to compare the z-scores for both weights.

For a steer weighing 1000 pounds:

z₁ = (1000 - 1114) / 77 ≈ -1.4805

For a steer weighing 1250 pounds:

z₂ = (1250 - 1114) / 77 ≈ 1.7662

The magnitude of the z-score indicates how far a value is from the mean. In this case, the steer weighing 1250 pounds has a larger positive z-score, indicating it is further from the mean compared to the steer weighing 1000 pounds.

Therefore, a steer weighing 1250 pounds would be more unusual in this context.

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