Find all values of X,where |x| = 11.​

When viewed through the magnifying glass, the termite appears to be approximately 1.58 mm in length.

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9514 1404 393

Answer:

  -16%/hour

Step-by-step explanation:

The slope formula is useful for that.

  m = (y2 -y1)/(x2 -x1)

  m = (52 -84)/(3 -1) = -32/2 = -16

The slope is -16% per hour.

the solutions to the equation have value of a=-4, b=1 and c=38.

In mathematics, factorization is the process of finding the factors of a given mathematical object, such as a number, polynomial, or matrix. Factors are objects that can be multiplied together to obtain the original object.

To solve the equation x² + 8x = 38 for x, we can use the following steps:

Move the constant term to the other side of the equation:

x² + 8x - 38 = 0

x=(-b±√b²-4ac)/2a

x=(-8±√64-4×1×(-38))/2×1

x=-4+√38

or x=-4-√38

On comparing with x= a+ b √c

x= a- b √c

value of a=-4

b=1

c=38

Therefore,  value of a=-4, b=1 and c=38.

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Answer:

7-7y=-3y+6

7-6=7y-3y

1=4y

4y÷4=1÷4

y=1/4

Answer:

y = 1.3

Step-by-step explanation:

Therefore, the expression (7-3i) + (x - 2i)² - (4i + 2x²) in the simplest a + bi form is: -2x² - 1 - (4x + 7i)

Linear Equation                   General Form                    Example

Slope intercept form             y = mx + b                            y + 2x = 3

Point–slope form                   y – y1 = m(x – x1 )              y – 3 = 6(x – 2)

General Form                            Ax + By + C = 0               2x + 3y – 6 = 0

Intercept form                        x/a + y/b = 1                 x/2 + y/3 = 1

As a Function f(x) instead of y      f(x) = x + C                         f(x) = x + 3

The Identity Function                      f(x) = x                     f(x) = 3x

Constant Functions                      f(x) = C                       f(x) = 6

Let's start by expanding the square term (x - 2i)² using the formula for (a + b)²:

(x - 2i)² = x² - 4xi + 4i²

Note that i² = -1, so we can simplify this expression to:

(x - 2i)² = x² - 4xi - 4

Substituting this expression and the given values into the original expression, we get:

(7 - 3i) + (x² - 4xi - 4) - (4i + 2x²)

Grouping the real and imaginary terms, we get:

(7 - 4 - 2x²) + (-3i - 4i - 4x) + (x²)

Simplifying the real part, we get:

-2x² - 1

Simplifying the imaginary part, we get:

-7i - 4x

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Answer:

\(\frac{40}{27}\)

Step-by-step explanation:

We need to evaluate the sum of the following finite geometric series.

We need to define r and \(a_{n}\)

\(r = 1/3\)

\(a_{n} =(\frac{1}{3} )^{n-1}\)

Follow the geometric sequence sum formula and substitute :

\(1*\frac{1-(\frac{1}{3})^4 }{1-\frac{1}{3} }\)

Simplify :

\(1 * \frac{3*\frac{80}{81} }{2}\)

Get rid of the 1 :

\(\frac{3*\frac{80}{81} }{2}\)

Multiply the numerators :

\(\frac{\frac{80}{27} }{2}\)

Move the denominator of the fraction in the numerator and move it to the denominator of the whole fraction :

\(\frac{80}{27*2}\)

Multiply the denominators :

\(\frac{80}{54}\)

Simplify  by dividing both the numerator and denominator by 2 :

\(\frac{40}{27}\)

The value of dy  is 0.25, when x=1 and dx =0.3.

How to solve differentiation?

\(y=e^{x/2}\)

Concept :

\(y=e^x\\\frac{dy}{dx} = e^x\)

Taking differentiation on both side, we get

\(\frac{dy}{dx} = \frac{1}{2}\ e^{x/2}\\\)

Put the values of x and dx, we get

\(dy = 0.5 \times 0.3 \times e^{0.5}\\dy = 0.25\)

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Answer:

The first equation is equal to 15 and the second one is equal to 16 . So the second equation is bigger.

In a case where a = 11 ft, b = 5 ft, and c = 7 ft, the surface area of the geometric shape formed by this net is B. 145 sq. ft.

The concept that will be used here is area of triangle, we will we need need to know the area of the first 2 triangles

The area of the triangle can be expressed as :

A =( 1/2 bh)

A = (1/2 ba)

Then substitute the values we have,

a = [1/2 (11 ft.) (5 ft)]

a =  27.5 sq ft.

Then we can find the value of the area as :

A = [1/2 c*b]

If we substitue the values we,

a = [1/2 (5 ft) (7 ft)]

= 17.5 sq. ft

Then we can proceed to calculate the area of the rectangle which can be done using the formula:

A = (lw) where a = (11 ft.)(5 ft.) = 55 sq. ft

We can now find the summation of all the a's as :

[2(27.5) + 2(17.5 ) + 55 ]

= 145 sq. ft.

Therefore, option B is correct.

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missing options:

A. 167 sq. ft.

B. 145 sq. ft.

C. 117.5 sq. ft.

D. 147 sq. ft.

Answer:

Step-by-step explanation:

this triangle is regular one

Answer:

obtuse scalene triangle

This is a word problem and our approach is to make mathematical sense of it as much as possible.

represents 11 more than 9 times of 10. We'll equally use BODMAS.

ANSWER = 101

p = 5 - 5q/x - 6/x

q = - px/5 - 6/5 + x

The value of p is 2 and value of q = 0.

Using operations like addition, subtraction, multiplication, and division, a mathematical expression is defined as a group of numerical variables and functions.

The given expression is,

px+6=5(x-q)

Where x = 2

So put value of x in the given expression

⇒2p + 6 = 5(2 - q)

⇒2p + 6 = 10 - 5q

⇒ 2p + 5q = 4

Put q = 0 we get

p = 2

Therefore, p = 2  and q = 0

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Answer:

2+3+6

Step-by-step explanation:

answer- option D

2+3+6

Answer:

2 +3+6

Step-by-step explanation:

it would = 11 the others equals the same

The pair of numbers that yields the maximum product when their sum is 24 is (12, 12), and the maximum product is 144. The corresponding quadratic function is P(x) = -x^2 + 24x, and the parabola opens downwards.

To find a pair of numbers whose sum is 24 and whose product is as large as possible, we can use the concept of maximizing a quadratic function.

Let's denote the two numbers as x and y. We know that x + y = 24. We want to maximize the product xy.

To solve this problem, we can rewrite the equation x + y = 24 as y = 24 - x. Now we can express the product xy in terms of a single variable, x:

P(x) = x(24 - x)

This equation represents a quadratic function. To find the maximum value of the product, we need to determine the vertex of the parabola.

The quadratic function can be rewritten as P(x) = -x^2 + 24x. We recognize that the coefficient of x^2 is negative, which means the parabola opens downwards.

To find the vertex of the parabola, we can use the formula x = -b / (2a), where a = -1 and b = 24. Plugging in these values, we get x = -24 / (2 * -1) = 12.

Substituting the value of x into the equation y = 24 - x, we find y = 24 - 12 = 12.

So the pair of numbers that yields the maximum product is (12, 12). The maximum product is obtained by evaluating the quadratic function at the vertex: P(12) = 12(24 - 12) = 12(12) = 144.

Therefore, the maximum product is 144. This quadratic function has a maximum value because the parabola opens downwards.

To graph the function, you can plot several points and connect them to form a parabolic shape. Here is an uploaded image of the graph of the quadratic function: [Image: Parabola Graph]

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Hubble's constant in units of km/s/million LY is approximately 21.47.

what is  approximately ?

Approximately means close to or nearly, but not exactly. It is used to indicate that a value or number is an estimation or approximation, rather than an exact value. It is often used when a precise value is not necessary or when the exact value is unknown or difficult to determine.

In the given question,

To convert Hubble's constant from km/s/Mpc to km/s/million LY, we need to multiply it by a conversion factor that accounts for the difference in distance units. We can use the fact that 1 Mpc is equal to 3.26 million LY:

1 Mpc = 3.26 million LY

Therefore, to convert Hubble's constant from km/s/Mpc to km/s/million LY, we can use the following conversion factor:

1 Mpc / 3.26 million LY

Multiplying Hubble's constant by this conversion factor gives:

H = 70 km/s/Mpc x (1 Mpc / 3.26 million LY) = 21.47 km/s/million LY

Therefore, Hubble's constant in units of km/s/million LY is approximately 21.47.

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3.1.1 The basic property of operations used is the commutative property of multiplication.

3.1.2 The basic property of operations used is the additive inverse property.

3.1.3 The basic property of operations used is the associative property of addition.

3.1.1 The basic property of operations used in this calculation is the commutative property of multiplication. It states that the order of the factors in a multiplication problem can be rearranged without changing the product. In this case, the numbers 25 and 4 were swapped, resulting in the same product of 100.

3.1.2 The basic property of operations used in this calculation is the additive inverse property. It states that for any number, there exists an additive inverse such that when the number and its additive inverse are added together, the result is zero. In this case, adding 412 and its additive inverse (-412) results in zero.

3.1.3 The basic property of operations used in this calculation is the associative property of addition. It states that the grouping of numbers being added does not affect the sum. In this case, the numbers 25, 37, 20, 5, 30, and 7 were regrouped to facilitate easier mental addition. By grouping 25 and 37, and then grouping 20, 5, 30, and 7, the final sum of 62 is obtained, which is the same as adding all the numbers together in the original order.

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75=14y+5

or, -14y=5-75

or, -14y = -70

or, y = -70/-14 = 5

The answer is 5.

Answer: Slove for the y in 75

= (14y + 5)

Then subsitute the y = 5 into 75 = (14y + 5)

75 = 75

Since 75 = 75 is redudat information , this seems to be a dependent system.

Infinitely Many solutions.

Answer:

\(\text{27}\)

Step-by-step explanation:

Given that :

\(\text{Dimension of poster board} = 1 \ \text{yd} \ \text{by} \ 1 \ \text{yd}\)

\(\text{Dimension of each poster board} = \dfrac{1}{3} \ \text{yd} \ \text{by} \ \dfrac{1}{9} \ \text{yd}\)

Number of poster signs that can be cut :

\(\text{Area of poster sign} = \dfrac{1}{3} \times \dfrac{1}{9} = \dfrac{1}{27} \ \text{yard}^2\)

\(\text{Area of poster board} = 1 \ \text{yard}^2\)

Number of poster signs that can be cut :

\(\dfrac{\text{Area of poster board}}{\text{Area of poster sign}}\)

\(1 \ \text{yard}^2\div (\dfrac{1}{27} ) \ \text{yard}^2\)

\(1 \div \dfrac{1}{27}\)

\(1 \times \dfrac{27}{1}\)

\(\bold{= 27 \ poster \ signs}\)

Answer:

\(7x^2-2x-2\)

Step-by-step explanation:

\(-3x^2+9+10x^2-11-2x\)

Combine like terms:

\(10x^2-3x^2-2x+9-11\)

Simplify:

\(7x^2-2x-2\)

Hope this helps!

Answer: 7x^2 - 2x - 2

Step-by-step explanation:

in this expression, all you have to do is combine like terms. those are -3x^2 and 10x^2, 9 and -11.

-3x^2 + 9 + 10x^2 - 11 - 2x     rearrange to make easier

-3x^2 + 10x^2 - 2x + 9 - 11     combine like-terms

7x^2 - 2x - 2

The domain value that corresponds to a range value of 4 is,

⇒ x = 1/2

Given that;

Function is,

y = 4x + 2

Since, the equation equal to the range value:

4 = 4x + 2

Then, we can solve for "x":

4 - 2 = 4x

2 = 4x

x = 1/2

Now that we have the value of "x", we can find the corresponding value of "y" by substituting it into the given equation:

y = 4x + 2

y = 4(1/2) + 2

y = 4 + 2

y = 6

Therefore, the domain value that corresponds to a range value of 4 is,

⇒  x = 1/2

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The vertices of the reflected square.

Let's calculate them:

A' = (-0.914, 3.914)

B' = (-2.828, 5.828)

C' = (-0.086, 7.086)

D' = (1.828, 5.172)

The vertices of the image of the square ABCD after reflecting it about the line through (0, 0) and (-2, 2), we can use the following steps:

Find the equation of the reflection line:

The reflection line passes through (0, 0) and (-2, 2).

We can calculate the slope (m) of the line using the formula (y2 - y1) / (x2 - x1):

m = (2 - 0) / (-2 - 0) = 2 / -2 = -1.

Using the point-slope form of a line (y - y1) = m(x - x1), we can use either of the given points to write the equation of the line:

y - 0 = -1(x - 0)

y = -x.

Find the midpoint of each side of the square:

The midpoints of the sides of a square are also the midpoints of its diagonals.

The midpoint of AB is ((4+6)/2, (3+4)/2) = (5, 3.5).

The midpoint of BC is ((6+5)/2, (4+6)/2) = (5.5, 5).

The midpoint of CD is ((5+3)/2, (6+5)/2) = (4, 5.5).

The midpoint of DA is ((3+4)/2, (5+3)/2) = (3.5, 4).

Reflect the midpoints about the line:

To reflect a point (x, y) about the line y = -x, we can find the perpendicular distance (d) from the point to the line and use it to determine the reflected point.

The perpendicular distance d from the line y = -x to a point (x, y) is given by the formula:

d = (y + x) / √(2).

The coordinates of the reflected points can be found using the formula for reflection across a line:

x' = x - 2d / √(2)

y' = y - 2d / √(2).

Calculate the reflected vertices:

The coordinates of the reflected vertices are as follows:

A' = (4 - 2(3.5 + 5) / √(2), 3 - 2(3.5 - 5) / √(2))

B' = (6 - 2(5 + 5) / √(2), 4 - 2(5 - 5) / √(2))

C' = (5 - 2(5.5 + 5) / √(2), 6 - 2(5.5 - 5) / √(2))

D' = (3 - 2(4 + 5) / √(2), 5 - 2(4 - 5) / √(2))

Now we can plot the original square ABCD and its image A'B'C'D' on the same graph to visualize the reflection.

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x⁴ - 8x² + 17 is the function that represents the fog(x).

To find fog(x), we first need to find g(f(x)), which means we need to substitute the expression for f(x) into the expression for g(x):

g(f(x)) = g(x² - 4)

Now, we can substitute the expression for g(x) into the above expression:

g(f(x)) = (x² - 4)² + 1

Expanding the squared term, we get:

g(f(x)) = x⁴ - 8x² + 17

Therefore, fog(x) = g(f(x)) = x⁴ - 8x² + 17.

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Complete question:

f(x) = x² - 4 and g(x)= x^2 + 1  find fog(x).

Answer: 7% at 6 years would best fit their payment option. They would then be paying $238.69 monthly and which is under $250, I hope this helps!

The general equation of a circle with the center at the point (a,b) and radius r is:

Since the coordinates of the center of this problem's circle are negative, they will be adding to the x and y variables. And the radius is sqrt(10) so when it's squared it gives 10. The equation is:

The correct answer is option C

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The sample size is \(n =944\)

b

The sample size is \(n_b = 1068\)

Step-by-step explanation:

From  the question we are told that

   The proportion is mathematically represented as  \(\r p = 0.33\)

    The marginal error is  \(e = 0.03\)

     The confidence level is  95 %  = 0.95

The z-value of the confidence level is

         \(z_c = 1.96\)

This value is obtained from the z table

     The sample size is mathematically evaluated as

            \(n = [\frac{z_c}{e} ]^2 * \r p(1- \r p)\)

substituting values

             \(n = [\frac{1.96}{0.03} ]^2 * 0.33 (1- 0.33)\)

             \(n =944\)

If no estimate is available the let assume  \(\r p = 0.50\)

     So  

              \(n_b = [\frac{z_c}{e} ]^2 * \r p(1- \r p)\)

substituting values

              \(n_b = [\frac{1.96}{0.03} ]^2 * 0.50 (1- 0.50)\)    

               \(n_b = 1068\)

Answer:

25

Step-by-step explanation:

You plug in the g(x) function into the f(x) function as the x, after this you replace the x with -1 and solve for you answer, so it should look like

f(g(x))=(2x+7)^2

f(g(-1)=(2*-1+7)^2=25

Answer:

\I got not answer cause im da BUDDHA

But gimme brainliest squekky plssss

Answer:

1. Area of the path = 1800 m²

2. The cost of cementing the path = Rs. 360000

Step-by-step explanation:

Dimension of the garden = 90 m by 80 m.

Width of path = 5 m

1. Area of the path = Area of the path with garden - Area of the garden

Area of the garden = length x breadth

                                = 90 x 80

                                = 7200

Area of the garden is 7200 m².

Area of the garden with path = length x breadth

But, length = 90 + 10 = 100 m

      breadth = 80 + 10 = 90 m

Area of the garden with path = 100 x 90

                                                 = 9000

Area of the garden with path = 9000  m²

Area of the path = 9000 - 7200

                           = 1800 m²

2. The cost of cementing the path = Rs.200 x 1800

                                            = Rs. 360000

Answer: Thus, the present age of Queens University College is 45 years, and the present age of GAGE University College is 15 years.

Step-by-step explanation: Let Q be the present age of Queens University College and G be the present age of GAGE University College.

Since the present age of Queens University College is three times that of GAGE University College, we can write the equation Q = 3G.

After 5 years, the difference of their ages will be 30 years, so we can write the equation Q + 5 = G + 30.

Substituting the first equation into the second equation, we get 3G + 5 = G + 30.

Solving for G, we find that G = 15.

Substituting this value into the equation Q = 3G, we find that Q = 3 * 15 = 45.

Thus, the present age of Queens University College is 45 years, and the present age of GAGE University College is 15 years.