The solution to this system is `x = [1, 1/4, 1/16]`, which is a nonzero vector in the -4-eigenspace.
One possible solution is the following matrix:
```
A = [[-4, 0, 0],
[1, -4, 0],
[0, 1, -4]]
```
We can verify that the eigenvalue -4 has algebraic multiplicity 3 by computing the characteristic polynomial:
```
det(A - lambda*I) = (-4 - lambda) * (-4 - lambda) * (-4 - lambda)
```
where `I` is the 3x3 identity matrix. Therefore, the eigenvalue -4 has geometric multiplicity 1, since the -4-eigenspace is a line.
To find the eigenvector associated with this eigenvalue, we solve the equation `(A - (-4)*I)x = 0`, or equivalently, `Ax = (-4)x`. This gives us the following system of equations:
```
-4x1 = 0
x1 - 4x2 = 0
x2 - 4x3 = 0
```
The solution to this system is `x = [1, 1/4, 1/16]`, which is a nonzero vector in the -4-eigenspace.
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Please help.
True or false
Answer:
True
Step-by-step explanation:
That is the distance formula.
Answer:
FALSE
Step-by-step explanation:
Distance Formula: \(\sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2}\)
Find the equation of the line shown.
Answer:
I think that it is y= -2x +9
Step-by-step explanation:
I am sure about the slope but the y-intercept (9) might be wrong.
FILL IN THE BLANK. a method that is invoked when an object is created is known as a _________ method.
The method that is invoked when an object is created is known as a constructor method.
Constructor in C++ is a special method that is invoked automatically at the time of object creation. It is used to initialize the data members of new objects generally.
The constructor in C++ has the same name as the class or structure. Constructor is invoked at the time of object creation. It constructs the values i.e. provides data for the object which is why it is known as constructors.
Constructor does not have a return value, hence they do not have a return type.
The prototype of Constructors is as follows:
<class-name> (list-of-parameters);
Constructors can be defined inside or outside the class declaration:-
The syntax for defining the constructor within the class:
<class-name> (list-of-parameters) { // constructor definition }
The syntax for defining the constructor outside the class:
<class-name>: :<class-name> (list-of-parameters){ // constructor definition}
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une entreprise a dépensé en tout 14 400e en 2001 pour l'entretien de ses voitures a. recopier et compléter le tableau ci-dessous. b. calculer la dépense moyenne pour l'entretien d'une voiture. c. les dépense d'entretien ont été représentées dans le diagramme circulaire ci-contre, mais la légende a été effacée. rétablir cette légende.
a company spent a total of 14,400th in 2001 for the maintenance of its cars a. copy and complete the table below. b. calculate the average expense for car maintenance. vs. maintenance costs have been shown in the circular diagram opposite, but the legend has been deleted. restore this legend.Answer:
Step-by-step explanation:
a company spent a total of 14,400th in 2001 for the maintenance of its cars a. copy and complete the table below. b. calculate the average expense for car maintenance. vs. maintenance costs have been shown in the circular diagram opposite, but the legend has been deleted. restore this legend.
A- 57 7/9 ft. 3
B- 11 2/3 ft 3
48 2/9 ft 3
28 2/3 ft 3
Answer:
A. 57 7/9
Step-by-step explanation:
First you multiply 13/3 (the length) by 10/3 (the width). You get 130/9. You then multiply 130/9 (the base) by 12/3 which equals 1560/27.
1560/27 can be simplified to 57.7777778, which in turn converts to 57 7/9.
57 7/9 is the final answer.
If a and b are positive numbers and each of the equations x 2
+ax+2b=0 and x 2
+2bx+a=0 has real roots, then find the smallest possible value of (a+b).
The smallest possible value of (a+b) is 2, and this value is attained when a = 1 and b = 1.
Let r and s be the roots of the equation x^2 + ax + 2b = 0, and let p and q be the roots of the equation x^2 + 2bx + a = 0. Since both equations have real roots, their discriminants are nonnegative:
a^2 - 8b ≥ 0
4b^2 - 4a ≥ 0
Simplifying the second inequality, we get:
b^2 - a ≥ 0
b^2 ≥ a
We want to minimize (a+b). Adding the two given equations, we get:
(x^2 + ax + 2b) + (x^2 + 2bx + a) = 0
2x^2 + (a+2b+2b)x + (a+2b) = 0
This equation has real roots if and only if its discriminant is nonnegative:
(a+2b+2b)^2 - 8(2x^2)(a+2b) ≥ 0
(a+4b)^2 - 16b(a+2b) ≥ 0
a^2 + 8ab + 12b^2 ≥ 0
This inequality is always true for positive a and b, so we can safely assume that a and b are positive. Therefore, we can divide both sides by 4b^2 to get:
(a/b)^2 + 8(a/b) + 12 ≥ 0
Letting t = a/b, we can rewrite this as a quadratic inequality:
t^2 + 8t + 12 ≥ 0
This inequality is true for all values of t, so there are no restrictions on the ratio a/b. Therefore, we can minimize (a+b) by choosing a and b to be as small as possible subject to the constraint that b^2 ≥ a. Since a and b are both positive, we can take a = 1 and b = 1 to achieve this minimum. This gives:
(a+b) = 1+1 = 2
Therefore, the smallest possible value of (a+b) is 2, and this value is attained when a = 1 and b = 1.
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Simplify negative nine over six divided by three over negative two
Answer:
1/4
Step-by-step explanation:
I used a calculator
Eric builds a small pyramid for a school project. His pyramid has a height of twelve inches and a square base that measures ten inches on each side. Eric wants to find the smallest cube-shaped box to put his pyramid in so that he can safely bring it to school right side up. What is the volume of this box, in inches cubed
To find the volume of the smallest cube-shaped box that can contain the pyramid, we need to first determine the length of the smallest edge of the box. Since the base of the pyramid is a square, the smallest edge of the box will be the diagonal of the square base of the pyramid.
Using the Pythagorean theorem, we find that the diagonal is:√(10² + 10²) = √200 = 10√2 inches Thus, the length of each edge of the smallest cube-shaped box that can contain the pyramid will be 10√2 inches. The volume of a cube is given by the formula
V = s³, where s is the length of one of its edges. Therefore, the volume of the box will be:(10√2)³ = 1000√8 cubic inches To simplify this expression, we can use the fact that √8 = √(4 · 2) = 2√2. Thus, the volume of the box is:1000√8 = 1000 · 2√2 = 2000√2 cubic inches Therefore, the volume of the smallest cube-shaped box that can contain Eric's pyramid is 2000√2 cubic inches, or approximately 2827.43 cubic inches to two decimal places.
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Please help I don't understand!
Answer:
3.8
Step-by-step explanation:
1. Use sine rule
d/sin(D) = f/sin(F) (d=EF, f=DE=3)
2. cross multiply
d=f(sin(D)/sin(F)) = 3(sin(75)/sin(50))=3.783
Answer:
(b) 3.8
Step-by-step explanation:
Often, simple relations will help you solve geometry problems. Here, you only need to know that larger angles are opposite longer sides.
__
The angle opposite side EF is angle D, which is 75°. That angle is larger than angle F, which is opposite the side marked as having length 3.
This means EF > 3.
There is only one answer choice greater than 3. Choice B is 3.8.
EF ≈ 3.8
______
The only "work" is remembering that larger angles are opposite longer sides.
Let g(x) = 2x and h(x) = x2 + 4.
Evaluate (hg)(-5).
104
250
146
-246
To evaluate (hg)(-5), we need to first find the value of hg and then substitute -5 in place of x.
hg means we need to first apply the function g to h(x). So,
hg(x) = g(h(x)) = g(x^2 + 4) = 2(x^2 + 4) = 2x^2 + 8
Now, substitute -5 for x:
hg(-5) = 2(-5)^2 + 8 = 50 + 8 = 58
Therefore, the answer is not listed as an option. The correct answer is 58.
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the sum of three consecutive integers is three times the second integer. show that this is true for the three consecutive integers 7,8 and 9
Step-by-step explanation:
7+8+9=24
second integer is 8 so 8*3=24
Do not include anything other than numbers in your responses. For example, do not include comma or dollar sign in your numbers. As a rule of thumb, keep 2 decimal places for larger numbers and 3 decimal places for smaller numbers less than 1. An accounts department is concerned about the number of internal purchase forms that its users completed incorrectly. As a result they are monitoring the proportion of purchase forms that were not completed correctly. This was chosen, rather than measuring the actual number of defects, because any number of defects on a form required about the same effort to revise. The following table shows number of forms completed incorrectly "out of 200 forms" that is processed each day. Construct a control chart for the data that monitors the proportion of incorrect forms. Is the process in control? Day 1 2 Number of Incorrect Forms 13 13 3 15 4 13 19 5 6 13 15 7 8 16 9 13 10 13 Sum 143 IMPORTANT: In this problem, keep 3 decimal places in your calculations. Which of the following charts is appropriate? (P Chart/C Chart) Based on your choice on the last question, calculate "one" of the followings, P (for P chart), or C (for C chart): If you chose P Chart, how much is standard deviation of p (sigma_p)? (Write 0 if you are not doing P chart) Upper Control Limit: Lower Control Limit: Is the proportion of incorrect forms in control? (Yes/No)
We can determine if the process is in control by checking if any of the data points fall outside the control limits.
To construct a control chart for monitoring the proportion of incorrect forms, we will use the P chart because we are interested in monitoring the proportion of defects relative to the total number of forms processed.
To calculate the standard deviation of p (sigma_p) for the P chart, we can use the formula:
sigma_p = sqrt((p * (1 - p)) / n)
where:
p = average proportion of defective forms
n = number of forms processed
First, let's calculate the average proportion of defective forms (p):
p = Sum of incorrect forms / (200 * Number of days)
p = 143 / (200 * 10)
p ≈ 0.0715
Next, let's calculate sigma_p using the formula mentioned above:
sigma_p = sqrt((0.0715 * (1 - 0.0715)) / (200 * 10))
sigma_p ≈ 0.0093
For the P chart, the Upper Control Limit (UCL) is given by:
UCL = p + 3 * sigma_p
UCL ≈ 0.0715 + 3 * 0.0093
UCL ≈ 0.0994
The Lower Control Limit (LCL) for the P chart is typically set to zero since the proportion cannot be negative:
LCL = 0
Now, we can determine if the process is in control by checking if any of the data points fall outside the control limits.
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Evaluate the function
f(x)=−4x^2+6x−4
Find f(5)
Hey there!
1. How to find f(5)?
To find f(5) - simply substitute x = 5 in the function. f(5) means the value of f(x) at x = 5.2. Substitution and Evaluate
\( \large{f(5) = - 4( {5})^{2} + 6(5) - 4}\)
Remember to follow the PEMDAS/BODMAS rules! Exponent comes before multiplication.
\( \large{f(5) = - 4(25) + 30 - 4} \\ \large{f(5) = - 100 + 30 - 4} \\ \large{f(5) = - 74}\)
3. Final Answer
f(5) = -74If you have any questions regarding the question or my answer, feel free to ask!
10. In a 2 hour Mathematics paper, there are
20 questions to be answered by Yao. After
1 hour he had answered 5 questions.
b) What fraction of the time had gone?
Answer:
1/2
Step-by-step explanation:
1 hour=60 minutes
2 hours=120 minutes
60/120=1/2
hope you got it
If you have any problem just ask me
If you think this is the best answer please mark me as brainliest
After 1 hour, Yao had completed 25% (1/4) of the 2-hour Mathematics paper.
In order to understand the fraction of time Yao had spent on the Mathematics paper after 1 hour, let's break down the problem. Yao was given a 2-hour Mathematics paper to complete, and he answered 5 questions in the first hour.
Now, let's calculate the fraction of time that had passed. To do this, we can set up a ratio of the time Yao had spent to the total time available. The time Yao spent is 1 hour, and the total time available is 2 hours. So the fraction of time that had gone can be represented as:
= Time spent / Total time
= 1 hour / 2 hours
= 1/2
Therefore, after 1 hour, Yao had completed half of the allotted time. However, we are asked to express this fraction in terms of questions answered. Yao had answered 5 questions out of a total of 20 questions.
To express the fraction of time in terms of questions answered, we can set up another ratio. The questions Yao answered is 5, and the total number of questions is 20. So the fraction of time that had gone can be represented as:
= Questions answered / Total questions
= 5 questions / 20 questions
= 1/4
Hence, after 1 hour, Yao had completed 1/4 of the total questions in the Mathematics paper. This means he still had 3/4 (or 75%) of the questions to complete in the remaining hour.
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HELPPP ITS ABT ESTIMATION ILL MARK U BRAINLIST
Answer: the answer is A
reason: 224294 * 43 / 100 = around 96320
please help w part b! right picture this time
Answer:
View the image below
Step-by-step explanation:
what is the ratio of the area of a square inscribed in a semicircle with radius $r$ to the area of a square inscribed in a circle with radius $r$? express your answer as a common fraction.
The ratio of the area of a square inscribed in a semicircle to the area of a square inscribed in a circle is 2/5.
What is a semicircle?
A semicircle in mathematics is a one-dimensional locus of points that makes up one-half of a circle. A semicircle's entire arc always measures 180 degrees. There is only one symmetry line in it.
For instance, if the radius is known, we can use the formula, which states that the area of a semicircle is equal to half that of a circle. As a circle's area is r2, Therefore, a semicircle's area is equal to 1/2(r2), where r is its radius. 3.14, or 22/7, is the value of.
Solution Explained:
Let's assume and take
The dimensions of the little square ABCD = 2 x 2 =4
of the little triangle's hypotenuse Radius of the semi-circle for BCG
H=sqrt(5) = The semicircle's radius
IHJK = 2sqrt is the diagonal of the huge square (5)
One side of the large square is IHJK when sin(45) x 2sqrt(5) = sqrt(10).
Therefore, the area of ABCD/area of IHJK is equal to 4/sqrt(10)2 = 2/5.
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An 8-inch by 10-inch map is drawn to a scale of 1 inch = 50 miles. If the same map is to be enlarged so that now 2 inches = 25 miles, how many 8-inch by 10-inch pieces of blank paper will be taped together in order for all of this map to fit?
a 1/2 b 2 c 4 d 8 e 16
To fit the enlarged map, which has dimensions of 16 inches by 20 inches, using 2 inches = 25 miles as the scale, 4 pieces of blank paper, each measuring 8 inches by 10 inches, would need to be taped together. Option C.
To determine how many 8-inch by 10-inch pieces of blank paper are needed to fit the enlarged map, we need to compare the size of the original map to the size of the enlarged map.
The original map is 8 inches by 10 inches. According to the given scale of 1 inch = 50 miles, the dimensions of the original map in miles are 8 inches * 50 miles/inch = 400 miles by 10 inches * 50 miles/inch = 500 miles.
The enlarged map has a scale of 2 inches = 25 miles. We need to calculate the dimensions of the enlarged map in inches. Let's represent the dimensions of the enlarged map as L inches by W inches.
From the given scale, we can set up the proportion: 1 inch / 50 miles = 2 inches / 25 miles.
Cross-multiplying, we get: 1 inch * 25 miles = 2 inches * 50 miles.
Simplifying, we find: 25 miles = 100 miles.
This implies that L inches = 2 inches * 8 = 16 inches, and W inches = 2 inches * 10 = 20 inches.
Now we can determine how many 8-inch by 10-inch pieces of blank paper are needed to fit the enlarged map. Since each piece of paper has dimensions 8 inches by 10 inches, we divide the dimensions of the enlarged map by the dimensions of each piece of paper.
The number of pieces of paper needed = (L inches / 8 inches) * (W inches / 10 inches) = (16 inches / 8 inches) * (20 inches / 10 inches) = 2 * 2 = 4.
Therefore, the answer is 4 pieces of blank paper. Option C is correct.
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the number $345{,}600$ can be expressed as $6^a5^b4^c$ for integers $a$, $b$ and $c.$ what is the value of the product $abc?$
The value of the product \($abc = 1 * 3 * 1 = 3$\).
To express the number \($345{,}600$\) as a product of powers of prime numbers, we first need to find the prime factorization of the given number.
\($345{,}600 = 2^3 * 3 * 5^3 * 23$\)
Now we need to rewrite the given expression \($6^a5^b4^c$\) in terms of prime numbers:
\($6^a5^b4^c = (2 * 3)^a * 5^b * (2^2)^c = 2^{a+2c} * 3^a * 5^b$\)
By comparing the exponents of the prime factorization of \($345{,}600$\) with the rewritten expression, we can determine the values of \($a$\), \($b$\), and \($c$\):
\(a+2c=3$, \\$a=1$, \\and $b=3$\)
Solving for \($c$\), we get:
\($c = (3 - a) / 2 = (3 - 1) / 2 = 1$\)
Now we have \(a=1$, $b=3$, and $c=1$\). The product \($abc = 1 * 3 * 1 = 3$\).
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PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP
Answer:
13a) E is (a,3b)
13b) I is (4a,0)
Step-by-step explanation:
Answer:
The answers that I got from solvng it:
13a) E is (a,3b)
13b) I is (4a,0)
Sorry, if it isnt right...
A photographer buys some merchandise with a list price of $5,000. If the supplier offers trade discount rates of 20/10/5, find the trade discount (in $). (Find the single equivalent discount first.)
The trade discount when the supplier offers trade discount rates of 20/10/5 is $1580.
How to calculate the value?Subtract the trade discount from 100% and change to decimals. This will be:
= 100% - 20% = 0.8
= 100% - 10% = 0.9
= 100% - 5% = 0.95
The net price factor will be:
= (0.8 × 0.9 × 0.95)
= 0.684
The single equivalent discount will be:
= 1 - Net price factor
= 1 - 0.684
= 0.316
The trade discount will be:
= Price × Discount
= $5000 × 0.316
= $1580
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Tess wants to make throw pillows for her couch. She has 6 yards of fabric. Each pillow uses 2/3 of a yard of fabric. How many pillows can she make?
Answer:
4
Step-by-step explanation:
\( \frac{2}{3} \times 6 = 4\)
I think she can make 4 throw pillows if she should use 6 yards of fabric
i hope this helped
Harry is paying for a meal with groups of friends. They received great service, so he is giving a $20% tip. The meal came to $225.10 before sales tax. How much will he leave as a tip?
Answer:
$45.02
Step-by-step explanation:
The tip here is being figured on the bill before tax. It is the product of the bill amount and the tip rate:
$225.10 × 20% = $45.02
Harry will leave $45.02 as a tip.
Can someone help please
Answer:
YES
Step-by-step explanation:
write the full set of vectors x ∈ r3 for which 1 0 0 , 0 1 0 , x is a basis for r3
The set of vectors x ∈ R3 for which 1 0 0, 0 1 0, x is a basis for R3 is given by all vectors x that are linearly independent from 1 0 0 and 0 1 0, and have at least one non-zero component.
To find the set of vectors x ∈ R3 for which 1 0 0 , 0 1 0 , x is a basis for R3, we need to find the vector x that completes the basis for R3.Since the basis for R3 consists of three linearly independent vectors, the vector x must also be linearly independent from the first two vectors, 1 0 0 and 0 1 0. This means that x cannot be a linear combination of the first two vectors, and must have at least one non-zero component.
Let x = [x1, x2, x3] be the vector that completes the basis for R3. Then, we can write any vector v ∈ R3 as a linear combination of the basis vectors as:
v = a1 [1 0 0] + a2 [0 1 0] + a3 [x1 x2 x3]
where a1, a2, and a3 are scalars.
Since the basis vectors are linearly independent, this equation has a unique solution for any vector v ∈ R3. Therefore, the set of vectors x ∈ R3 for which 1 0 0 , 0 1 0 , x is a basis for R3 is given by all vectors x that are linearly independent from 1 0 0 and 0 1 0.
One way to express this set of vectors is as follows:
x = [x1, x2, x3] ∈ R3 such that x1 ≠ 0 or x2 ≠ 0 or x3 ≠ 0.
In other words, the vector x can have any value in R3, as long as it has at least one non-zero component.
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on a coordinate plane, a curved line with an upward arc, labeled g of x, crosses the x-axis at (negative 2, 0), and the y-axis at (0, 4). a straight horizontal line, labeled f of x, crosses the y-axis at (0, 4). which represents where f(x)
Therefore, the straight horizontal line labeled f(x) represents where f(x) is equal to 4.
Based on the given information, the function f(x) is represented by the straight horizontal line that crosses the y-axis at (0, 4). The point (0, 4) on the y-axis indicates that when x is 0, the value of f(x) is 4. Since the line is horizontal, it maintains a constant value of 4 for all values of x.
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7.
Which kind of function best models the data in the table? Graph the data and write an equation to model the data.
A. exponential; y = 3x – 1
B. linear; y = x – 1
C. quadratic; y = x2 – 1
D. linear; y = –x – 1
Answer:
D. linear; y = –x – 1
Step-by-step explanation:
Linear; y=-x - 1
The slope is negative since it’s decreasing. So it’s not the first equation. It’s not a quadratic equation because there is no forming U shape for this data. It’s not a exponential function because the slope is not 3 and a exponential function is in the form y=a(b)^x
...............................................................................................................................................
Answer:
The correct answer is D) linear; y = –x – 1
Step-by-step explanation:
To find this, use any values in the table and it will produce a true statement. This is how we check to see if a model is correct. See the two examples below for proof.
(4, 5)
y = -x - 1
-5 = -4 - 1
- 5 = -5 (TRUE)
(0, -1)
y = -x - 1
-1 = 0 - 1
-1 = -1 (TRUE)
PLS HELP PLS ITS TIMES ILL GIVEBRAINLIEST IF CORRECT HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!
Answer:
The answer must be C
Step-by-step explanation:
I can explain if you want to, just let me know!
What is the sale price of a plastic watch originally priced at $4.80 if the sale is 50%
Answer:
$2.40
Step-by-step explanation:
There is a 50% discount, so you do 50% of 4.80 which is 2.40
Then subtract 2.40 from 4.80
and you get 2.40
\(.50*4.80=2.40\)
\(4.80-2.40=2.40\)
I hope that wasn't confusing.
Hope this helps! (✿◠‿◠)
The required price of a plastic watch in the sale is $2.40.
Given that,
to determine the sale price of a plastic watch originally priced at $4.80 if the sale is 50%.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,
The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.
Here,
A plastic watch was originally priced at $4.80.
After 50% the price is = 50% * 4.80
= 4.80 * 50 / 100
= 4.80 * 1/2
= $ 2.40
Thus, the required price of a plastic watch in the sale is $2.40.
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Your sample consists of 49 subjects, with a mean of 33.8 and the (population) standard deviation is known and equals 3.22. Calculate the test statistic BY HAND:
The test statistic is approximately -2.03.
To calculate the test statistic, we can use the one-sample t-test formula:
t = (x - μ) / (s / √n)
Where:
x is the sample mean,
μ is the hypothesized population mean,
s is the sample standard deviation,
n is the sample size.
In this case, we have:
x = 44.3 (sample mean)
μ = 44.6 (hypothesized population mean)
s = 1.01 (sample standard deviation)
n = 46 (sample size)
Plugging in the values, we can calculate the test statistic:
t = (44.3 - 44.6) / (1.01 / √46)
= -0.3 / (1.01 / √46)
= -0.3 / (1.01 / 6.782)
≈ -0.3 / 0.148
Rounding to 2 decimal places, the test statistic is approximately -2.03.
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Complete question =
Testing:
H0:μ=44.6
H1:μ<44.6
Your sample consists of 46 subjects, with a mean of 44.3 and standard deviation of 1.01.
Calculate the test statistic, rounded to 2 decimal places.