Answer: 5.4~
Step-by-step explanation:
For the problem F(3) = 3x^2 +b, you have to first figure out what F(3) is and in this case it is 49, so now you have part of the question solved. Then you start working on the other side of the equation 3x^2 +b = 49, we don't know what x is so lets figure it out, by that you need to do 3x^2, the equals 9. So, so far we have the equation 49 = 9x +b. Now we need to get rid of the x on the 9, having a variable is considered multiplying so you need to divide 9 by 9, but remember what you do to one side you have to do to the other, so now you have to divide 49 by 9 and you get 5.444444444. Now the equation is b=5.4~ meaning that b is around 5.4, I hope this helps.
Mrs Atkins is going to choose two students from her class to take part in a competition.
She can choose from 16 girls and 14 boys.
(a)
Work out the number of different ways of choosing one girl and one boy.
Given:
Total number of girls in her class = 16
Total number of boys in her class = 14
To find:
The number of different ways of choosing one girl and one boy.
Solution:
We have,
Total number of girls = 16
Total number of boys = 14
So,
Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
Now, number of different ways of choosing one girl and one boy is
\(16\times 14=224\)
Therefore, the required number of different ways is 224.
a. The number of different ways of choosing one girl and one boy is 226
Calculation:Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
So, the number should be
\(= 16 \times 14\)
= 224
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what is the average rate of change of f(x)= x^2 10 over the interval -2 ≤ x ≤3
The average rate of change of f(x) = x^2 + 10 over the interval -2 ≤ x ≤3 is 1.
We know that the formula to calculate the average rate of change of a function over an interval is
Average Rate of Change = (f(b) - f(a)) / (b - a)
Where, a and b are the initial and final values of x respectively.
f(x) = x^2 + 10
Between the interval [-2, 3], a = -2 and b = 3.
Substituting the values in the formula:
Average Rate of Change = (f(b) - f(a)) / (b - a)= (f(3) - f(-2)) / (3 - (-2))
Now, let's find f(3) and f(-2)
f(3) = 3^2 + 10 = 19
f(-2) = (-2)^2 + 10 = 14
Substitute the values:
Average Rate of Change = (f(3) - f(-2)) / (3 - (-2))= (19 - 14) / (3 + 2)= 5/5= 1
Hence, the average rate of change is 1.
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Solve the system by graphing
{y=5x-8}
{y=-3x+8
Fill in the blanks below in order to justify whether or not the mapping shown represents a function.
a particular tree is 18 m tall : a model of it was built with a. scale of 4 cm : 3m how tall is the model.
Answer:
24 cm
Step-by-step explanation:
We can set up a ratio of 18 m / x cm = 3 m / 4 cm because we know that it's a scale.
Cross multiplying, we get 3x = 72. Divide both sides by 3 and we have x = 24 cm.
We can also consider it by just dividing 18 m by 3 m to find the scale factor, which is 6. We then multiply the 4 cm by 6 to get 24 cm as well.
please help! asap! thanks! xoxoxo
Answer:
B
Step-by-step explanation:
Don't know how to type those here so see attachment
Answer:
x = √29
Step-by-step explanation:
a^2 + b^2 = c^2
5^2 + 2^2 = c^2
25 + 4 = c^2
29 = c^2
√29 = √c^2
√29 = c
x = √29
(10.07 mc) given what degree maclaurin polynomial is required so that the error in the approximation is less than 0.001?
n=4 is the degree maclurins polynomial is required so that the error in the approximation is less than 0.001.
Given that,
The expression is
e⁰⁵=1+0.5+0.5²/2!+0.5³/3!+.....
We have to find what degree maclurins polynomial is required so that the error in the approximation is less than 0.001.
We know that,
What is the polynomial?An expression that consists of variables, constants, and exponents that is combined using mathematical operations like addition, subtraction, multiplication, and division is referred to as a polynomial.
√e=1.64872
Pₙ( x)= e⁰⁵=1+0.5+0.5²/2!+0.5³/3!+.....
P₂=1+0.5+0.5²/2!=1.625
P₃= P₂+0.5³/3!=1.6458
P₄= P₃+0.5⁴/4!=1.648404
√e - P₄ = -0.0003158
Therefore, n=4 is the degree maclurins polynomial is required so that the error in the approximation is less than 0.001.
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HELPPPPPPP due soon plzzzzzzz
A cone has a volume of 6443.28 cubic millimeters and a radius of 18 millimeters
. What is its height?
Answer:
not sure if they want 19 or 19.00
If the scale factor of two similar cylinders is 4:7,
what is the volume ratio?
A. 64:343
B. 12:21
C. 16:49
D. 256:2,401
Answer:
the answer is A. 64:343.
Step-by-step explanation:
The ratio of the volumes of two similar figures is equal to the cube of the ratio of their corresponding side lengths. Since the scale factor of the two cylinders is 4:7, the ratio of their corresponding radii is 4:7 and the ratio of their heights is also 4:7.
So, the ratio of their volumes is (4/7)^3 = (64/ 343) = 64:343
So, the answer is A. 64:343.
A number is equal to 3 times a smaller number. Also, the sum of the smaller number and 4 is the larger number. The
situation is graphed on the coordinate plane below, where x represents the smaller number and y represents the
larger number.
Which two equations represent the situation?
A. y = 1/3x and y = x - 4
B. y = 1/3x and y = x + 4
C. y = 3x and y = x + 4
D. y = 3x and y = x - 4
At a concert for the band Algal Rhythms, 75% of the tickets were sold at the full price of $30. The remaining 25% of tickets were sold at a discounted price of $10. What was the average selling price of a ticket at the Algal Rhythms concert? Express your answer in dollars, rounded to the nearest cent.
The average selling price of a ticket at the Algal Rhythms concert is $25
How to determine the average selling price of a ticket at the Algal Rhythms concert?The given parameters are:
75% of the tickets were sold for $30.
The remaining 25% were sold for $10.
The average selling price of a ticket at the Algal Rhythms concert is calculated using
Average = Sum of (Price * Percentage)
So, we have
Average = 30 * 75% + 10 * 25%
Evaluate the expression
Average = 25
Hence, the average selling price of a ticket at the Algal Rhythms concert is $25
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If three out of every thirteen trick-or-treaters that came to your house last Halloween were dressed as cowboys, what proportion of trick-or-treaters were not dressed as cowboys
The proportion of trick-or-treaters who were not dressed as cowboys is 10/13.
If three out of every thirteen trick-or-treaters were dressed as cowboys, it means that the proportion of trick-or-treaters dressed as cowboys is 3/13.
To find the proportion of trick-or-treaters who were not dressed as cowboys.
we subtract the proportion dressed as cowboys from 1 (since the total proportion of trick-or-treaters must sum to 1).
Proportion not dressed as cowboys = 1 - Proportion dressed as cowboys
Proportion not dressed as cowboys = 1 - (3/13)
Proportion not dressed as cowboys = (13/13) - (3/13)
Proportion not dressed as cowboys = 10/13
Therefore, the proportion of trick-or-treaters who were not dressed as cowboys is 10/13.
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What is the slope of the line that passes through the points (-3, 5) and (4, 2)?
Answer:
\(\frac{-3}{7}\)
Step-by-step explanation:
3. What is the explicit rule for the geometric
sequence 3, 12, 48,...?
A f(n)=9n-1
B f(n)=3(4)n-1
C f(n)=4n-1+3
The explicit rule for the geometric sequence 3, 12, 48,... is:
f(n) = \(3 \times 4^{(n-1)\). B.
The explicit rule for the geometric sequence 3, 12, 48,... need to determine the common ratio, r.
We can do this by dividing any term by the previous term:
r = 12/3
= 48/12
= 4
Now that we know the common ratio can use the formula for the nth term of a geometric sequence:
\(a_n\) = \(a_1 \times r^{(n-1)\)
where:
\(a_n\) is the nth term
\(a_1\) is the first term (3 in this case)
r is the common ratio (4 in this case)
n is the term number
Substituting these values into the formula, we get:
\(a_n\) = \(3 \times 4^{(n-1)\)
So, the explicit rule for the geometric sequence 3, 12, 48,... is:
f(n) = \(3 \times 4^{(n-1)\)
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Find the general solutions of the following differential equations using D-operator methods: 3.1 (D²-5D+6)y=e¹x + sin 2x (8) 3.2 (D² + 2D+4)y=e²* sin 2x (8)
1. For the differential equation 3.1, the general solution is y = (C₁ + C₂e³x) + (1/2)e¹x - (1/2)cos 2x, where C₁ and C₂ are arbitrary constants.
2. For the differential equation 3.2, the general solution is y = (C₁cos(2x) + C₂sin(2x))e^(−x) + (1/5)sin 2x + (1/10)cos 2x, where C₁ and C₂ are arbitrary constants.
1. To find the general solution for equation 3.1, we first determine the characteristic equation by replacing D² with r², D with r, and solving r² - 5r + 6 = 0. The roots are r₁ = 2 and r₂ = 3. Thus, the homogeneous solution is y_h = C₁e²x + C₂e³x, where C₁ and C₂ are constants.
Next, we find the particular solution for the inhomogeneous term e¹x + sin 2x. Assuming y_p = Ae¹x + Bcos 2x + Csin 2x, we substitute it into the differential equation and equate coefficients. Solving the resulting equations, we find A = 1/2, B = -1/2, and C = 0. Therefore, the particular solution is y_p = (1/2)e¹x - (1/2)cos 2x.
Finally, the general solution is y = y_h + y_p, giving y = (C₁ + C₂e³x) + (1/2)e¹x - (1/2)cos 2x.
2. For equation 3.2, the characteristic equation is r² + 2r + 4 = 0, which has complex roots r₁ = -1 + 2i and r₂ = -1 - 2i. The homogeneous solution is y_h = (C₁cos(2x) + C₂sin(2x))e^(-x), where C₁ and C₂ are constants.
To find the particular solution for e²sin 2x, we assume y_p = (Acos 2x + Bsin 2x)e^(-x). Substituting it into the differential equation and solving the resulting equations, we obtain A = 1/10 and B = 1/5. Thus, the particular solution is y_p = (1/10)cos 2x + (1/5)sin 2x.
Combining the homogeneous and particular solutions, the general solution is y = y_h + y_p, giving y = (C₁cos(2x) + C₂sin(2x))e^(-x) + (1/5)sin 2x + (1/10)cos 2x.
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A digital camera is marked 33% off the
original price. If the discount is $52.80,
what was the original price?
A) $107.20
B) $160.00
C)$170.00
D) $175.00
Answer:
A. $107.20
Step-by-step explanation:
dont know sorry
Round your answer to the nearest hundredth.
A
4.
?
B
С
3
Answer:
a. 4.00
b. 3.00
I hope this helps
The mapping diagram above (does not/does represents) a function since (there is one number/for each number) in (set B the input/output, set A the output/input) where there (are multiple mappings/is only one mapping/is no mapping) (from set A output/input, Set B output/input)
an urn contains 6 blue balls and 6 orange balls. in how many ways can we select 2 blue balls and 2 orange balls from the urn?
The no. of ways to select the 2 blue balls and 2 orange balls from the urn is 0.4545
No. of Blue balls in the urn = 6
No. of Orange balls in the urn = 6
Total no. of balls in the urn = No. of blue balls + No. of orange balls
= 6 + 6
= 12 balls
No. of blue balls to be selected = 2
No. of orange balls to be selected = 2
No. of balls to be selected = 4
The total. no of ways 4 balls can be selected =\(^{12}C_{4}\)
The No. of ways 2 blue balls can be selected = \(^{6}C_{2}\)
The No. of ways 2 orange balls can be selected = \(^{6}C_{2}\)
Therefore, No. of ways to select 2 blue balls and 2 orange balls from the urn
= \(^{6}C_{2} \times ^{6}C_{2} /^{12}C_{4}\)
Probability = No. of ways to select blue balls x No. of ways to select orange balls / Total no. of ways to select balls
P = (15×15)/495
= 225 / 495
P = 0.4545
Therefore, the no. of ways to select blue and orange balls is 0.4545
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a baseball player has a batting average of 0.19. what is the probability that he has exactly 5 hits in his next 7 at bats?
The probability that a baseball player has exactly 5 hits in his next 7 at bats = 0.0034
In this question we have been given a baseball player has a batting average of 0.19
We need to find the probability that he has exactly 5 hits in his next 7 at bats.
We know that the formula for the binomial distribution:
P(x) = nCx p^x q^(n - x)
From given information:
p = 0.19
q = 1 - p
= 1 - 0.19
= 0.81
n = 7 and x = 5
Using binomial distribution formula the probability would be,
P = nCx p^x q^(n - x)
P = 7C5 * (0.19)^5 * (0.81)^(7 - 5)
P = 21 * (0.19)^5 * (0.81)^2
P = 0.0034
Therefore, the required probability is: 0.0034
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A swimmer enters the water and swims in a straight line at 54 meters per minute. Another swimmer enters the water
3 minutes later, swimming in the same direction at 134 meters per minute. Which parametric equations could model
the swimmers' paths from the time the first swimmer entered the water?
Answer:
\(x(t) = 54t\) and \(y(t) = 134(t - 3)\)
Step-by-step explanation:
Represent the swimmers with A and B
For Swimmer A:
\(Rate = 54m/min\)
For Swimmer B:
\(Rate = 134m/min\)
Required:
Write a parametric equation
For Swimmer A:
If swimmer A covers 54 meters in 1 minutes, then the swimmer covers 54t in t minutes
So, the function is:
\(x(t) = 54t\)
For Swimmer B:
If swimmer A covers t minutes, swimmer B swims for (t - 3) minutes because swimmer B starts 3 minutes later.
If in 1 minutes, swimmer B covers 134 minutes; In (t - 3) minutes, the swimmer covers 134(t - 3)
So, the rate is:
\(y(t) = 134(t + 3)\)
Hence, the parametric functions are:
\(x(t) = 54t\) and
\(y(t) = 134(t - 3)\)
Answer:
A on Edge
Step-by-step explanation:
It is 2,966 miles round trip to Craig's aunt's house. If he travels to her house 6 times this year, how many miles did he travel in all?
=
Given g(x) = -x +4, solve for x when g(x) = -3.
9514 1404 393
Answer:
x = 7
Step-by-step explanation:
Put -3 where g(x) is and solve the resulting equation for x.
g(x) = -x +4
-3 = -x +4
x -3 = 4 . . . . . . add x (so we can work with a positive coefficient
x = 7 . . . . . . . . add 3
Answer:
x=-7 i guess
Step-by-step explanation:
Construct a Deterministic Finite Accepted M such that L(M) = L(G), the language generated by grammar G = ({S, A, B}, {a, b}, S , {S -> abS, S -> A, A -> baB, B -> aA, B -> bb} )
To construct a Deterministic Finite Accepted M such that L(M) = L(G), the language generated by grammar G = ({S, A, B}, {a, b}, S , {S -> abS, S -> A, A -> baB, B -> aA, B -> bb} ), the following steps should be followed:
Step 1: Eliminate the Null productions from the grammar by removing productions containing S. The grammar, after removing null production, becomes as follows.{S -> abS, S -> A, A -> baB, B -> aA, B -> bb}
Step 2: Eliminate the unit productions. The grammar is as follows. {S -> abS, S -> baB, S -> bb, A -> baB, B -> aA, B -> bb}
Step 3: Now we will convert the given grammar to an equivalent DFA by removing the left recursion. By removing the left recursion, we get the following productions. {S -> abS | baB | bb, A -> baB, B -> aA | bb}
Step 4: Draw the state diagram for the DFA using the following rules: State diagram for L(G) DFA 1. The start state is the initial state of the DFA. 2. The final state is the final state of the DFA. 3. Label the edges with symbols on which transitions are made. 4. A table for the transition function is created. The table for the transition function of L(G) DFA is given below:{Q, a} -> P{Q, b} -> R{P, a} -> R{P, b} -> Q{R, a} -> Q{R, b} -> R
Step 5: Construct the DFA using the state diagram and transition function. The DFA for the given language is shown below. The starting state is shown in green and the final state is shown in blue. DFA for L(G) -> ({Q, P, R}, {a, b}, Q, {Q, P}) Where, Q is the starting state P is the first intermediate state R is the second intermediate state.
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Two angles are supplementary. The larger angle is 6 degrees less than twice the smaller angle. What is the degree measure of the larger angle?
An experimenter would like to construct a 99% confidence interval with a width at most 0. 5 for the average resistance of a segment of copper cable of a certain length. If the experimenter knows that the standard deviation of such resistances is 1. 55. How big a sample should the experimenter take from the population? what happens if the standard deviation and the width of the confidence interval are both doubled?.
A big sample that should the experimenter take from the population is 256 and if the standard deviation and the width of the confidence interval are both doubled then the sample is also 256.
In the given question,
The confidence level = 99%
Given width = 0.5
Standard deviation of resistance(\(\sigma\))= 1.55
We have to find a big sample that should the experimenter take from the population and what happens if the standard deviation and the width of the confidence interval are both doubled.
The formula to find the a big sample that should the experimenter take from the population is
Margin of error(ME) \(=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\)
So n \(=(z_{\alpha /2}\frac{\sigma}{\text{ME}})^2\)
where n=sample size
We firstly find the value of ME and \(z_{\alpha /2}\).
Firstly finding the value of ME.
ME=Width/2
ME=0.5/2
ME=0.25
Now finding the value of \(z_{\alpha /2}\).
Te given interval is 99%=99/100=0.99
The value of \(\alpha\) =1−0.99
The value of \(\alpha\) =0.01
Then the value of \(\alpha /2\) = 0.01/2 = 0.005
From the standard table of z
\(z_{0.005}\) =2.58
Now putting in the value in formula of sample size.
n\(=(2.58\times\frac{1.55}{0.25})^2\)
Simplifying
n=(3.999/0.25)^2
n=(15.996)^2
n=255.87
n≈256
Hence, the sample that the experimenter take from the population is 256.
Now we have to find the sample size if the standard deviation and the width of the confidence interval are both doubled.
The new values,
Standard deviation of resistance(\(\sigma\))= 2×1.55
Standard deviation of resistance(\(\sigma\))= 3.1
width = 2×0.5
width = 1
Now the value of ME.
ME=1/2
ME=0.5
The z value is remain same.
Now putting in the value in formula of sample size.
n\(=(2.58\times\frac{3.1}{0.5})^2\)
Simplifying
n=(7.998/0.5)^2
n=(15.996)^2
n=255.87
n≈256
Hence, if the standard deviation and the width of the confidence interval are both doubled then the sample size is 256.
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There were 96 students and 34 adults at the concert. If 65% of the seats were filled, how many seats are in the auditoriom? Round your answer to the nearest whole percent
Answer: 200 seats
Step-by-step explanation:
There are 96 students and 34 adults in a concert. The total number of people present is therefore:
= 96 + 34
= 130 people
These 130 people only fill 65% of the seats. Assume the total number of seats is x:
130 = 65% * x
x = 130/65%
x = 200 seats
James takes out a loan of 9000 euros which keeps on charging simple interest at a rate of 3% of the original amount per annum until it is cleared. James pays of 770 euros each year to reduce the loan. After how many years will James have fully cleared the loan?
James will fully clear the loan after approximately 12 years when the remaining balance reaches zero.
To determine the number of years it will take for James to fully clear the loan, we need to calculate the remaining balance after each payment and divide the initial loan amount by the annual payment until the remaining balance reaches zero.
The loan amount is 9000 euros, and James pays off 770 euros each year. Since the interest is charged at a rate of 3% of the original amount per annum, the interest for each year will be \(0.03 \times 9000 = 270\) euros.
In the first year, James pays off 770 euros, and the interest on the remaining balance of 9000 - 770 = 8230 euros is \(8230 \times 0.03 = 246.9\)euros. Therefore, the remaining balance after the first year is 8230 + 246.9 = 8476.9 euros.
In the second year, James again pays off 770 euros, and the interest on the remaining balance of 8476.9 - 770 = 7706.9 euros is \(7706.9 \times 0.03 = 231.21\) euros. The remaining balance after the second year is 7706.9 + 231.21 = 7938.11 euros.
This process continues until the remaining balance reaches zero. We can set up the equation \((9000 - x) + 0.03 \times (9000 - x) = x\), where x represents the remaining balance.
Simplifying the equation, we get 9000 - x + 270 - 0.03x = x.
Combining like terms, we have 9000 + 270 = 1.04x.
Solving for x, we find x = 9270 / 1.04 = 8913.46 euros.
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Marie has 25 cards. Each card has a different symbol on it. Marie gives one card to Shelly and one card to Pauline. In how many different ways can Marie do this?
50 different ways. Do I have to list them? Could I also have brainliest?
Answer:
600
Step-by-step explanation: