explain why the temperature of the boiling water was used as the initial temperature of the metal? vocab terms that must be included :(specific heat).

By adding missing bonds, charges, nonbonding electrons, and curved arrows, the mechanism for the given reaction is depicted in the attached image.

Mechanism of Organic Reaction An organic reaction mechanism is typically represented by the overall reaction type (which can be substitution, addition, elimination, oxidation, reduction, or rearrangement), the presence of any reactive intermediates, the nature of the initiating reagent, the presence of any catalysis facilitated by a catalyst, and, finally, its stereochemistry.

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The percentage decrease in the amount of dissolved oxygen is 10%

Percent yield is the percent ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%. If the actual and theoretical yield ​are the same, the percent yield is 100%

In chemistry, yield is a measure of the quantity of moles of a product formed in relation to the reactant consumed, obtained in a chemical reaction, usually expressed as a percentage.

From the graph,

The amount of dissolved oxygen at  15°C is 10 mg/L

The amount of dissolved oxygen at  20°C is 9 mg/L

The decrease in the amount of dissolved oxygen is 1mg/L

The percentage decrease = (1/10) × 100 = 10%

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Answer:

warm clothing hiking sticks safter gear. food water. the basics

(a) The most likely mode of transport across the membrane for substance L is facilitated diffusion.

Transport is the movement of people, animals and goods from one location to another. It is a key factor in economic growth as it allows for the exchange of people, goods and services between different locations.

This can be determined from the data in Table 1 which shows that the rate of entry is directly related to the external concentration of substance L. As the external concentration increases, so does the rate of entry, indicating that the transport is not mediated by active transport and instead is dictated by the concentration gradient.
(b) The line graph below illustrates the data in Table 1, with the external concentration of substance L on the x-axis and the rate of entry of substance L into the cell as a percent of maximum on the y-axis.
(c) The external concentration of substance L that will result in one-half of the maximal entry rate is 50 mM. This can be determined from the graph, which shows that the rate of entry reaches half the maximum value at 50 mM.
(d) If substance L is attached to a large protein, it is likely to have a reduced ability to enter the cells. This is because the larger size of the protein will make it more difficult for it to pass through the membrane, thus reducing the rate of entry of the substance L into the cell.

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Students who use correct scientific reasoning are Student 1 namely: If the reaction is not allowed to finish, the sodium bicarbonate will not decompose completely, making the final mass higher than the theory.Te corrct amswer is B.

If the sodium bicarbonate is not properly broken down, water and carbon monoxide will not be produced, which can be eliminated to lessen the product's mass. The product will therefore weigh heavier or have a bigger ultimate mass than predicted because of an incomplete reaction.

Given the aforementioned justifications, it is obvious that Student 2 is mistaken in this instance. This is not a scientific explanation in the instance of Student 3 and is merely a wild guess that isn't true in all circumstances.

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When a nitrile is treated with an excess of LiAlH4 followed by water, the obtained product is a primary amine.

1. Nitrile (RC≡N) reacts with excess LiAlH4 (lithium aluminum hydride), which is a strong reducing agent.
2. The LiAlH4 reduces the nitrile to an imine (RCH=NH) intermediate.
3. The imine intermediate is further reduced by the excess LiAlH4 to form an aldimine (RCH2-NH2).
4. Finally, water (H2O) is added to the reaction to hydrolyze any remaining LiAlH4, and the primary amine (RCH2-NH2) is obtained as the final product.

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There are approximately 0.05239 grams of KF in 45.0 mL of 0.200 M KF. 58.3 mL of 3.00 M HCl needs to be added to a 500 mL volumetric flask and then filled with water to the mark to prepare a 0.350 M HCl solution.

To calculate the number of grams of KF in 45.0 mL of 0.200 M KF, we need to use the formula:

grams = (volume in liters) x (molarity) x (molar mass)

Converting the given volume to liters we get,

45.0 mL = 45.0/1000 = 0.045 L

grams = 0.045 L x 0.200 mol/L x (molar mass of KF)

molar mass of K = 39.10 g/mol

molar mass of F = 18.99 g/mol

molar mass of KF = 39.10 g/mol + 18.99 g/mol = 58.09 g/mol

grams = 0.045 L x 0.200 mol/L x 58.09 g/mol

grams = 0.05239 g

Therefore, there are approximately 0.05239 grams of KF in 45.0 mL of 0.200 M KF.

The equation we can use is:

(M₁)(V₁) = (M₂)(V₂)

M₁ = 3.00 M (concentration of the concentrated HCl)

V1 = unknown (volume of the concentrated HCl needed)

M₂ = 0.350 M (desired concentration of the diluted HCl)

V₂ = 500 mL = 0.500 L (desired total volume of the diluted HCl solution)

Substituting the values into the equation, we get:

(3.00 M)(V1) = (0.350 M)(0.500 L)

V₁ = (0.350 M)(0.500 L) / 3.00 M

V₁ = 0.0583 L = 58.3 mL

Therefore, approximately 58.3 mL of 3.00 M HCl needs to be added to a 500 mL volumetric flask and then filled with water to the mark to prepare a 0.350 M HCl solution.

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Answer:

0.7943448326634696 moles.

The “33 percent more for free” deal is better than the “33 percent off” deal. This is because the “33 percent more for free” deal gives you 13.3 ounces of coffee for $10, while the “33 percent off” deal gives you only 6.7 ounces of coffee for $6.67

For the “33 percent more for free” deal:

10 dollars for 10 ounces of coffee

13.3 ounces of coffee for 10 dollars (33% more)

Price per ounce = 10/13.3 = $0.75 per ounce

For the “33 percent off” deal:

10 dollars for 10 ounces of coffee

6.7 ounces of coffee for $6.67 (33% off)

Price per ounce = 6.67/6.7 = $0.99 per ounce

So, the “33 percent more for free” deal is better than the “33 percent off” deal because you get more coffee for your money.

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Answer:

Events that happen over and over form a pattern

The molar volume of Ne gas will be 21.44 L.

We know that, according to Ideal Gas law:

PV = nRT

Where,

P = pressure, V = volume, n = no. of moles of gas, R = gas constant,

T = temperature

On the other hand,

D = PMb/RT ...1

Where, D = density, Mb = molar mass

PV = nRT can also be written as V = n(RT/P) ....2

From equation 1, we can find RT/P which is equal to Mb/D

So, RT/P = Mb/D

Now put this value in equation 2

Therefore, V = n(Mb/D) ......3

V = Vm = molar volume

n = 1 mole

molar mass, Mb of Ne is 20.180gm

density, d is given 0.941g/l

Now on putting all the values in equation 3, we get:

Vm = n(Mb/D)

Vm = 1(20.180/0.941)

Vm = 21.44 L

Therefore, molar volume of Ne gas will be 21.44 L.

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Plants can be defined as multicellular organisms that has the ability to manufacture or produce their own food.

The multicellular organisms are those organisms that are made up of various cells which work together to maintain the functionality of the living organism.

The plant can be described as a multicellular organism as it contains cells such as:

The plants are also has the ability to manufacture their own food due to the presence of the green pigment called the chloroplast.

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Suppose 5.0 mol of antimony (III) fluoride is added to 10.0 mol of carbon tetrachloride, and from the 100% reaction there are the equivalents of 0 moles of SbF₃, 5.0 moles of SbCl₃, 0 moles of CCl₄, and 15.0 moles of CClF₂.

A balanced reaction is one where the reactants and products are present in equal amounts, and if the 100% reaction takes place, then the reactant sides have 1 mol of SbF₃ and 3 mol of CCl₄ that make the product of 1 mol of SbCl₃ and 3 mol of CClF₂. After the 100% reaction, all the reactants get converted into the product. The complete reaction is the below.

SbF₃ + 3CCl₄ → SbCl₃ + 3CClF₂

Hence, suppose  5.0 mol of antimony (III) fluoride is added to 10.0 mol of carbon tetrachloride, and from the 100% reaction there are the equivalents of 0 moles of SbF₃, 5.0 moles of SbCl₃, 0 moles of CCl₄, and 15.0 moles of CClF₂.

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Answer:

P2 = 2.25 atm

Explanation:

Given:

V1 = 1.5 L. V2 = 2.0 L

P1 = 3.0 atm. P2 = ?

Use Boyle's law and solve for P2:

P1V1 = P2V2

or

P2 = (V1/V2)P1

= (1.5 L/2.0L)(3.0 atm)

= 2.25 atm

Answer:

monsoon causes wet and dry seasons throughout much of the tropics

A lewis structure for the acetate ion is included the carbon hydrogen and the oxygen atom . the one oxygen atom is doubly bonded with the carbon atom and one is single  bonded with negative charge.

The acetate ion included the carbon hydrogen and the oxygen atom . the lewis structure of acetate ion is one O atom double-bonded to the carbon. the double-bonded O atom has two lone pairs. the other O atom has three lone pairs and  -1 negative charge.

The valence electron of the C atom  = 8

The valence electron of the H atom = 3

The valence electron of the O atom = 12

The total number of the valence electrons of the CH₃CO⁻ is = 24

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Answer:

Explanation:

Go to a craft store and buy so me material that are biodegradable

Answer:gold iron and uranium

Explanation:

Answer:

iron, density: 7.8 g/cm³

aluminum, density: 2.7 g/cm³

silver, density: 10.5 g/cm³

lead, density: 11.3 g/cm³

Explanation:

other ones wrong

What should be done to reduce the risk when working with concentrated acids and bases are;

1) Ensure that the concentrated acids and bases are stored separately in safety cabinets.

2) If you don't have separate safety cabinets and the must be stored in same cabinet, then you must ensure that they are stored in separate compartments.

3) Lastly, the separate compartments or cabinets must have their separate spill containment compounds.

          When working with strong acids and bases during neutralization reactions, usually the production of gases can make the solution which is corrosive to splash and get to people around there.

         Due to how strong the acids and base are, these splashes from the neutralized solution could have potentially damaging effects on humans when it contacts them by either casing skin burns or even blindness.  

Now, to reduce the risk of the adverse effects stated above, what could be done is;

1) Ensure that the concentrated acids and bases are stored separately in safety cabinets.

2) If you don't have separate safety cabinets and the must be stored in same cabinet, then you must ensure that they are stored in separate compartments.

3) Lastly, the separate compartments or cabinets must have their separate spill containment compounds.

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If the battery was removed, the energy produced by the battery would not be able to continue its path along the circuit.

I used the simulation to model the changes by adjusting the Temperature slider at the bottom. As I increased the temperature, the equilibrium shifted towards the products side.

The temperature is a measure of how hot or cold something is. It is measured using a thermometer and can be expressed in Celsius, Fahrenheit, or Kelvin. Temperature can be affected by many factors, including air pressure, humidity, wind, and the time of day.

I also observed the pie graph to see how the system changed. As the temperature increased, the number of molecules for both nitrogen and hydrogen decreased, while the number of molecules for ammonia increased. I also used the pause button on the simulation to observe the number of particles at any point of time. This allowed me to see how the reaction was progressing and how the equilibrium shifted as the temperature increased.

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Answer:

i think 50C

Explanation:

It only makes since cause if its 4.43 and u want the volume to be 3.13 it has to me 50C

Use Charles law

\(\\ \rm\rightarrowtail V_1T_2=V_2T_1\)

\(\\ \rm\rightarrowtail 4.43T_2=(70)(3.13)\)

\(\\ \rm\rightarrowtail 4.43T_2=219.1\)

\(\\ \rm\rightarrowtail T_2=49.4°C\)

The 15 kg block require more work to raise by 4 meter compare to  20 kg blocks .

The free body diagram is attached below,

We know that,  Weight \(W=m*g\)

where m is mass of object and g is gravitational acceleration.

Value of  \(g=9.8m/s^{2}\)

So that, weight is depend on mass of object.

And , \(workdone=force*distance\)

Work done require to raise 15kg block by 4 m is,

                 \(W=15*4*g=60g\)

Work done require to raise 20kg block by 2 m is,

               \(W=20*2*g=40g\)

Hence, The 15 kg block require more work to raise by 4 meter compare to  20 kg blocks .

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Answer:

The density of helgas sample is 17.8 g/cm³.

Explanation:

Given that,

Mass of sample of Rowena = 5 gram

Density = 8.9 g/cm³

Mass of sample of helga = 10 gram

We need to calculate the volume of sample

Using formula of volume

\(V=\dfrac{m}{\rho}\)

Where, m = mass

\(\rho\) = density

Put the value into the formula

\(V=\dfrac{5}{8.9}\)

\(V=0.56\ cm^3\)

We need to calculate the density of helgas sample

Using formula of density

\(\rho=\dfrac{m}{V}\)

Where, m = mass

V = volume

Put the value into the formula

\(\rho=\dfrac{10}{0.56}\)

\(\rho=17.8\ g/cm^3\)

Hence, The density of helgas sample is 17.8 g/cm³.

The magnification of a camera lens is determined by the ratio of the focal length of the lens to the distance between the lens and the film. In this case, the focal length of the lens is given as 22 mm and the farthest it can be placed from the film is 33 mm.

To calculate the magnification, we need to divide the focal length by the distance between the lens and the film.

Magnification = focal length / distance

In this case, the closest distance between the lens and the film is 33 mm. So, the magnification can be calculated as:

Magnification = 22 mm / 33 mm

Simplifying this expression, we get:

Magnification = 0.6667

Therefore, the magnification of the closest object with this camera lens is 0.6667.

This means that the image of the closest object will appear about two-thirds the size of the actual object on the film.

In other words, if you were to take a close-up photograph of an object using this camera lens, the resulting image on the film would be about two-thirds the size of the actual object.

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Answer:

maybe it's a

Explanation:

because metal can not bend

Answer:

it is C

Explanation:

metals are good conductor of heat

El valor de la presión osmótica que corresponde a una solución que contiene 2 moles de soluto en un litro de solución a una temperatura de 17°C es 47.56 atmósferas.

La presión osmótica se puede calcular usando la siguiente ecuación:

\( \pi = \frac{nRT}{V} \)   (1)

En donde:

n: es el número de moles = 2 moles

R: es la constante de los gases = 0.082 L*atm/(K*mol)

T: es la temperatura = 17 °C = 290 K

V: es el volumen = 1 L

Introduciendo lo valores anteriores en la ecuación (1), tenemos:

\( \pi = \frac{nRT}{V} = \frac{2 moles*0.082 L*atm/(K*mol)*290 K}{1 L} = 47.56 atm \)

Por lo tanto, la presión osmótica es 47.56 atmósferas.

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Espero que te sea de utilidad!

Answer:

NaOH

Explanation:

NaOH is among the water soluble bases

Answer:

See below, please.

Explanation:

With water

2Na+2H2O=2NaOH+H2 (gas)

With dilute acids

for example, HCl

2Na+2HCl=2NaCl+H2 (gas)