Explain the difference between partitioning a directed line segment MN in a 2:7 ratio
versus a 7:2 ratio. Include a specific example as part of your explanation.

Answers

Answer 1

The difference between partitioning a directed line segment MN in a 2:7 ratio versus a 7:2ratio because of following

To understand this let us take the line segment MN which is of a length is divided into 9 equal parts. Here, we are dividing it into nine parts because the proportions 2 and 7 make a sum of 9.

When we divide the line segment MN in the ratio 2:7, the first two parts out of the nine from the left side are separated from the rest 7. This means that the first proportion from the left hand side of the line is smaller than the other.

Now, when we divide the line segment MN in the ratio7:2, the first seven parts out of the nine from the left side are separated from the rest two. This means that the first proportion from the left hand side of the line is larger than the other.

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Related Questions

6. how is twice a number decrease by three is negative seven written as a question A. 2+×_3=7 B. 2×_3=7 C. ×2-3=7 D. (×-3)2=-7​

Answers

Answer:

Step-by-step explanation:

6. how is twice a number decrease by three is negative seven written as a question A. 2+×_3=7 B. 2×_3=7 C. ×2-3=7 D. (×-3)2=-7​

Solve for x. Pls and thank you

Solve for x. Pls and thank you

Answers

Answer:

x=4

Step-by-step explanation:

72 + 51 + 13x + 5 = 180

128 + 13x = 180

13x = 52

x = 4

Answer:

x = 4

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180

72 + 51 + 13x + 5 = 180 add like terms

128 + 13x = 180 subtract 128 from both sides

13x = 52 divide both sides by 13

x = 4

find the next numbers 5, 1, 7, 0, 9, -1, 11...

Answers

Answer:

7,13,6

Step-by-step explanation:

you must take the number minus 4 then add 6 minus 7 then add 9, minus 10 then add 12.

On a certain hot summers day, 402 people used the public swimming pool. The daily prices are 1.50$ for children and 2.00$ for adults. The receipts for admission totaled 648.50$. How many children and how many adults swam at the public pool that day?

Answers

As a result of answering the given question, we may state that As a expressions result, the pool was used by 311 children.

what is expression ?

An expression in mathematics is a combination of numbers, variables, and mathematical operations (such as addition, subtraction, multiplication, division, exponentiation, and so on) that expresses a quantity or a value. Expressions might be simple, such as "3 + 4", or complex, such as "(3x2 - 2) / (x + 1)". They can also include functions like "sin(x)" or "log(y)". Expressions can be evaluated by substituting values for the variables and performing the mathematical operations in the order specified. For example, if x = 2, the formula "3x + 5" evaluates to 3(2) + 5 = 11. Expressions are frequently used in mathematics to express real-world situations, create equations, and simplify complex mathematical problems.

To indicate the number of children and adults who used the pool, we'll use two variables. Let:

Let x denote the number of children and y the number of adults.

We can deduce from the problem:

x + y = 402 (the total number of individuals who used the pool) (the total number of people who used the pool)

1.5x + 2y = 648.5 (the total revenue from entrance) (the total revenue from admission)

We can solve for x and y using these two equations.

\(x + y = 402\sx = 402 - y\\1.5x + 2y = 648.5 1.5(402 - y) + 2y = 648.5 603 - 1.5y + 2y = 648.5\)

The pool was visited by 91 adults. The first equation can be used to calculate the number of children:

\(x + y = 402\sx + 91 = 402\sx = 311\)

As a result, the pool was used by 311 children.

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Container X contained 1200g of sand.Container Y contained 7.2kg of sand.After an equal amount if sand was removed from each container,Container Y had 7 times as much sand as container X.how much sand was removed from each container?​

Answers

I NEED HELP DOES ANYONE HAVE THIS QUESTION

Linear Equations & Linear Systems:Question 5
What is the solution to the following system of equations?

Somebody pls help me

Linear Equations & Linear Systems:Question 5What is the solution to the following system of equations?Somebody

Answers

(2, -3) is the solution

Suppose ln x-ln y=y-4 , where y is a differentiable function of x and y=4 when x=4 . What is the value of dy/dx when x=4 ?

Answers

Answer:

When x=4, ln x-ln y=y-4, so ln 4-ln 4=4-4, which is true. Therefore, when x=4, y=4, and dy/dx=0.

Step-by-step explanation:

So, when x = 4, the value of the differentiable function dy/dx is 0.

What is differentiable function?

A differentiable function of one real variable is one that has a derivative at each point in its domain. In other words, a differentiable function's graph has a non-vertical tangent line at each interior point in its domain.

Here,

Given the equation ln x - ln y = y - 4, we can rearrange it to get ln(x/y) = y - 4. Taking the derivative of both sides with respect to x using the chain rule:

d/dx (ln(x/y)) = d/dx (y - 4)

(1/x) (dx/dx) - (1/y) (dy/dx) = dy/dx

dy/dx = (1/y) (dx/dx) + (1/x) (dy/dx) = (1/y) + (1/x) (dy/dx)

Rearranging and solving for dy/dx:

(x/y) (dy/dx) = (1/y) - (1/x)

dy/dx = (x/y^2) (1/x - 1/y) = (x/y^2) (1/x - 1/y)

We can substitute x = 4 and y = 4 into the expression to find the value of dy/dx when x = 4:

dy/dx = (4/16) (1/4 - 1/4) = 0

So, the value of differentiable function dy/dx when x = 4 is 0.

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PLEASE HELP< I WILL GIVE YOU BRAINIEST

What are the real and imaginary parts of the complex number?
−6−i

Answers

Real part: -6
Imaginary part: -i

xample 2
Find the median, lower quartile, and upper quartile of the numbers.
2 4 32 9 12 22 18 20 16 24 28 11
1 - Arrange the numbers in order from least to greatest.
249 11 12 16 18 20 22 24 28 32
16 18
2-median (second quartile) =
2.
34
= 17
2.
2 4 9 11 12 16 18 20 22 24 28 32
second our
Plz help nerd's

Answers

Answer:

Median: 17

Q1: 10

Q3: 23

Step-by-step explanation:

2, 4, 9, 11, 12, 16,   18, 20, 22, 24, 28, 32

Median is middle number/average of the 2 middle numbers. 16 + 18 = 34/2 = 17

First/lower quartile/Q1 = middle of lower half of ordered data set

= 9 + 11 = 20/2 = 10

Third/upper quartile/Q3 = middle of upper half of ordered data set

= 22 + 24 = 46/2 = 23

Sorry if this is too late. Posting it will probably save someone else, though.

use the theorem given below to find the curvature. r(t) = 9t i 4 sin(t) j 4 cos(t) k theorem: the curvature of the curve given by the vector function r is (t) = |r ′(t) ⨯ r″(t)| |r ′(t)|3 .

Answers

To find the curvature of the curve represented by the vector function \(r(t) = 9t \mathbf{i} + 4 \sin(t) \mathbf{j} + 4 \cos(t) \mathbf{k}\), we can use the given theorem:

The curvature (\(k(t)\)) of a curve defined by the vector function \(r(t)\) is given by the formula \(k(t) = \left|\frac{{\mathbf{r}'(t) \times \mathbf{r}''(t)}}{{\left|\mathbf{r}'(t)\right|^3}}\right|\).

First, we need to find the first and second derivatives of \(r(t)\):

\(\mathbf{r}'(t) = 9 \mathbf{i} + 4 \cos(t) \mathbf{j} - 4 \sin(t) \mathbf{k}\)

\(\mathbf{r}''(t) = -4 \sin(t) \mathbf{j} - 4 \cos(t) \mathbf{k}\)

Next, we substitute these derivatives into the formula for curvature:

\(k(t) = \left|\frac{{(9 \mathbf{i} + 4 \cos(t) \mathbf{j} - 4 \sin(t) \mathbf{k}) \times (-4 \sin(t) \mathbf{j} - 4 \cos(t) \mathbf{k})}}{{\left|(9 \mathbf{i} + 4 \cos(t) \mathbf{j} - 4 \sin(t) \mathbf{k})\right|^3}}\right|\)

Simplifying this expression involves calculating the cross product, magnitude, and simplification of terms. However, without further information about the range of \(t\) or specific values, it is challenging to provide a specific numerical answer.

The curvature of a curve represents the rate at which the curve deviates from being a straight line at any given point. It describes how sharply the curve bends or curves at that point. In this case, the vector function \(r(t)\) describes a three-dimensional curve in space. By calculating the curvature using the given theorem, we can determine how the curve bends or curves at different values of \(t\).

The curvature can provide insights into the geometry and behavior of the curve. For example, if the curvature is large, it indicates a sharp bend or curve, while a small curvature suggests a relatively straight or gently curving segment. By analyzing the curvature at various points along the curve, we can identify regions of significant curvature, such as points of inflection or areas with high curvature. This information is valuable in fields such as physics, engineering, computer graphics, and geometry, where understanding the shape and behavior of curves is essential.

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The curvature of the curve given by the vector function r(t) = 9t i + 4sin(t) j + 4cos(t) k is (4/97) * sqrt(1296sin^2(t) + 256cos^4(t)).

To find the curvature of the curve given by the vector function r(t) = 9t i + 4sin(t) j + 4cos(t) k using the provided theorem, we need to compute the first and second derivatives of r(t) and then apply the formula for curvature.

First, let's find the first derivative, r'(t), of the vector function r(t):

r'(t) = (d/dt)(9t i + 4sin(t) j + 4cos(t) k)

      = 9 i + 4cos(t) j - 4sin(t) k

Next, let's find the second derivative, r''(t), by differentiating r'(t):

r''(t) = (d/dt)(9 i + 4cos(t) j - 4sin(t) k)

       = -4sin(t) j - 4cos(t) k

Now, we can calculate the cross product of r'(t) and r''(t):

r'(t) ⨯ r''(t) = (9 i + 4cos(t) j - 4sin(t) k) ⨯ (-4sin(t) j - 4cos(t) k)

Using the properties of the cross product, we can expand this expression:

r'(t) ⨯ r''(t) = (9 * (-4sin(t))) i ⨯ j

                + (9 * (-4sin(t))) i ⨯ k

                + (4cos(t) * (-4cos(t))) j ⨯ k

Simplifying further:

r'(t) ⨯ r''(t) = -36sin(t) i

                - 36sin(t) k

                - 16cos^2(t) j

Now, let's calculate the magnitude of r'(t) ⨯ r''(t):

|r'(t) ⨯ r''(t)| = sqrt((-36sin(t))^2 + (-36sin(t))^2 + (-16cos^2(t))^2)

                = sqrt(1296sin^2(t) + 256cos^4(t))

Next, we need to compute the magnitude of r'(t):

|r'(t)| = sqrt((9)^2 + (4cos(t))^2 + (-4sin(t))^2)

        = sqrt(81 + 16cos^2(t) + 16sin^2(t))

        = sqrt(81 + 16)

|r'(t)| = sqrt(97)

Finally, we can plug these values into the formula for curvature:

k(t) = |r'(t) ⨯ r''(t)| / |r'(t)|^3

    = sqrt(1296sin^2(t) + 256cos^4(t)) / (sqrt(97))^3

Simplifying further:

k(t) = (4/97) * sqrt(1296sin^2(t) + 256cos^4(t))

Therefore, the curvature of the curve given by the vector function r(t) = 9t i + 4sin(t) j + 4cos(t) k is (4/97) * sqrt(1296sin^2(t) + 256cos^4(t)).

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In the diagram, O is circumscribed about quadrilateral ABCD. What is m<B?​

In the diagram, O is circumscribed about quadrilateral ABCD. What is m&lt;B?

Answers

Answer:

B; 94 degrees

Step-by-step explanation:

From the diagram, what we have is a cyclic quadrilateral

For a cyclic quadrilateral, opposite angles are supplementary

That means;

They add up to give 180 degrees

Mathematically;

angle D + angle B = 180

angle B = 180 - angle D

angle B = 180-86

angle B = 94 degrees

Stacy's Weekly salary is $1516.52 what is her annual salary?

Answers

Answer:

Does she get paid once every week?

Step-by-step explanation:

Approx. $78,859.04 somewhere around there

3] Question 5 Consider the vector field F(x, y, z) = y cos (xy) i + x cos (xy)j – sin zk. (i) Calculate the curl of the vector field F. State whether F is conservative. (ii) Let C be the curve joining the origin (0,1,-1) to the point with coordinates (1, 2V2,2) defined by the following parametric curve r(t) = n* i + t}j + tcos atk, 15t52. Calculate the scalar line integral of the vector field. F. dr. F.dr.

Answers

Given vector field, F(x, y, z) = y cos (xy) i + x cos (xy) j – sin z k To calculate the curl of F, we need to take the curl of each component and subtract as follows,∇ × F = ( ∂Q/∂y - ∂P/∂z ) i + ( ∂P/∂z - ∂R/∂x ) j + ( ∂R/∂x - ∂Q/∂y ) k...where P = y cos(xy), Q = x cos(xy), R = -sin(z)

Now we calculate the partial derivatives as follows,

∂P/∂z = 0, ∂Q/∂y = cos(xy) - xy sin(xy), ∂R/∂x = 0...

and,

∂P/∂y = cos(xy) - xy sin(xy), ∂Q/∂z = 0, ∂R/∂y = 0

Therefore,

∇ × F = (cos(xy) - xy sin(xy)) i - sin(z)j

The curl of F is given by:

(cos(xy) - xy sin(xy)) i - sin(z)j.

To state whether F is conservative, we need to determine if it is a conservative field or not. This means that the curl of F should be zero for it to be conservative. The curl of F is not equal to zero. Hence, the vector field F is not conservative. Let C be the curve joining the origin (0,1,-1) to the point with coordinates (1, 2V2,2) defined by the following parametric curve:

r(t) = n* i + t}j + tcos atk, 15t52.

The curve C is defined as follows,r(t) = ni + tj + tk cos(at), 0 ≤ t ≤ 1Given vector field, F(x, y, z) = y cos(xy) i + x cos(xy)j – sin zk Using the curve parameterization, we get the line integral as follows,∫CF.dr = ∫10 F(r(t)).r'(t)dt...where r'(t) is the derivative of r(t) with respect to t

= ∫10 [(t cos(at))(cos(n t)) i + (n cos(nt))(cos(nt)) j + (-sin(tk cos(at)))(a sin(at)) k] . [i + j + a tk sin(at)] dt

= ∫10 [(t cos(at))(cos(n t)) + (n cos(nt))(cos(nt)) + (-a t sin(at) cos(tk))(a sin(at))] dt

= ∫10 [(t cos(at))(cos(n t)) + (n cos(nt))(cos(nt)) - a^2 (t/2) (sin(2at))] dt

= [sin(at) sin(nt) - (a/2) t^2 cos(2at)]0^1

= sin(a) sin(n) - (a/2) cos(2a)

The vector field F(x, y, z) = y cos(xy) i + x cos(xy)j – sin zk is given. Firstly, we need to calculate the curl of F. This involves taking the curl of each component of F and subtracting. After calculating the partial derivatives of each component, we get the curl of F as (cos(xy) - xy sin(xy)) i - sin(z)j. Next, we need to determine whether F is conservative. A conservative field has a curl equal to zero. As the curl of F is not equal to zero, it is not a conservative field. In the second part of the problem, we have to calculate the scalar line integral of the vector field F. dr along the curve C joining the origin to the point with coordinates (1, 2V2, 2). We use the curve parameterization to calculate the line integral. After simplifying the expression, we get the answer as sin(a) sin(n) - (a/2) cos(2a).

The curl of the given vector field F(x, y, z) = y cos(xy) i + x cos(xy)j – sin zk is (cos(xy) - xy sin(xy)) i - sin(z)j. F is not conservative as its curl is not zero. The scalar line integral of the vector field F along the curve C joining the origin to the point with coordinates (1, 2V2,2) is sin(a) sin(n) - (a/2) cos(2a).

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cindy makes $9 an hour working at a local plant nursery. she does this for 10 weeks of her summer vacation. she works about 20 hours each week. which is the most reasonable estimate of what cindy will earn during the summer?

Answers

Cindy will make a total amount of $1,800 for 10 weeks

How to calculate the amount of money that Cindy will make for the 10 weeks of her summer vacation?

Cindy makes $9 an hour working at a local plant nursery

She does this for 10 weeks

She works for about 20 hours each week

Therefore the total amount of money Cindy made in 10 weeks can be calculated as follows

= 9(20) × 10

= 180 × 10

= 1800

Hence Cindy will make a total amount of $1800 in 10 weeks

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val runs 1 1/2 miles each day. She has run for 4 days. How far has she run altogether​

Answers

6 miles. 4 times 1 and a half equals 6

Answer:

6 miles

Step-by-step explanation:

1 1/2 miles x 4 days= 6 miles over 4 days

\(4^3\sqrt{-88}\)


Help I don't know where the negative goes.

Answers

if you meant simplification

\(4^3\sqrt{-88}\implies 64\sqrt{-88}\implies 64\sqrt{(-1)(2^2)(2)(11)}\implies 64(2)\sqrt{(-1)(2)(11)} \\\\\\ 128\sqrt{(2)(11)}\cdot \sqrt{-1}\implies 128\sqrt{22}~i\)

A survey showed that 4/5 of moviegoers think tickets are too expensive.
What percent of those surveyed think tickets are too expensive?

Answers

Answer:

80%

Step-by-step explanation:

5 times 20 = 100 so with that each 5th is 20% so 4 times 20 is 80

2. How many bits are needed to represent decimal values ranging from 0 to 12,500?

Answers

To represent decimal values ranging from 0 to 12,500, we need 14 bits.

To determine the number of bits needed to represent decimal values ranging from 0 to 12,500, we need to find the smallest number of bits that can represent the largest value in this range, which is 12,500.

The binary representation of a decimal number requires log base 2 of the decimal number of bits. In this case, we can calculate log base 2 of 12,500 to find the minimum number of bits needed.

log2(12,500) ≈ 13.60

Since we can't have a fraction of a bit, we round up to the nearest whole number. Therefore, we need at least 14 bits to represent values ranging from 0 to 12,500.

Using 14 bits, we can represent decimal values from 0 to (2^14 - 1), which is 0 to 16,383. This range covers the values 0 to 12,500, fulfilling the requirement.

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Help! I have 20 minutes

Help! I have 20 minutes

Answers

Answer:

a = 80

b = 40

c = 58

d = 19

e = 34

f = 36

Pls mark brainliest. Thanks!

Answer:

a = 80

b=40

c=58

d=19

e=34

f=36

Step-by-step explanation:



A simple random sample with n = 56 provided a sample mean of 22.5 and a sample standard deviation of 4.4. (Round your answers to one decimal place.)

a) Develop a 90% confidence interval for the population mean.

b) Develop a 95% confidence interval for the population mean.

c) Develop a 99% confidence interval for the population mean.

Answers

a) The 90% confidence interval for the population mean is approximately (21.52, 23.48).

b) The 95% confidence interval for the population mean is approximately (21.322, 23.678).

c) The 99% confidence interval for the population mean is approximately (20.926, 24.074).

To develop confidence intervals for the population mean, we can use the formula:

Confidence Interval = sample mean ± (critical value * standard error)

where the standard error is equal to the sample standard deviation divided by the square root of the sample size.

a) For a 90% confidence interval, we need to find the critical value corresponding to a confidence level of 90%. The critical value can be obtained from the t-distribution table with (n-1) degrees of freedom. Since the sample size is 56, the degrees of freedom is 56-1 = 55.

From the t-distribution table, the critical value for a 90% confidence interval with 55 degrees of freedom is approximately 1.671.

The standard error can be calculated as:

Standard Error = sample standard deviation / sqrt(sample size)

Standard Error = 4.4 / sqrt(56)

Standard Error ≈ 0.5882

Now we can calculate the confidence interval:

Confidence Interval = 22.5 ± (1.671 * 0.5882)

Confidence Interval = 22.5 ± 0.9816

Confidence Interval ≈ (21.52, 23.48)

b) For a 95% confidence interval, the critical value for 55 degrees of freedom is approximately 2.004 (obtained from the t-distribution table).

Standard Error = 4.4 / sqrt(56) ≈ 0.5882

Confidence Interval = 22.5 ± (2.004 * 0.5882)

Confidence Interval = 22.5 ± 1.178

Confidence Interval ≈ (21.322, 23.678)

c) For a 99% confidence interval, the critical value for 55 degrees of freedom is approximately 2.678 (obtained from the t-distribution table).

Standard Error = 4.4 / sqrt(56) ≈ 0.5882

Confidence Interval = 22.5 ± (2.678 * 0.5882)

Confidence Interval = 22.5 ± 1.574

Confidence Interval ≈ (20.926, 24.074)

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Mark had 3/2 cans of paint and used 1/2 cans for his room. What fraction of the paint did he use

Help I’m slowww

Answers

Answer:

1/3 fraction of whole paint is used by mark

Step-by-step explanation:

Mark used  1/2 out of 3/2 cans.

\(\frac{1}{2}\) ÷ \(\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}\)

can someone help.. i’ll chose brainliest if best

can someone help.. ill chose brainliest if best

Answers

Answer:week 3 and week 1

Step-by-step explanation:

Answer:

chicken

Step-by-step explanation:

what is the average lexile score for an 8th grader?

Answers

1400/up to 75th percentile

The points (3,-2) and (2, 1) are both solutions to which inequality?

Answers

(3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

How to determine the inequality?

The complete question is added as an attachment

The points are given as:

(3, -2) and (2, 1)

Next, we test the points on each inequality in the list of options.

So, we have:

Option 1

y > 1/2x + 2

Substitute (3, -2) and (2, 1) for x and y

-2 > 1/2 * 3 + 2 ⇒ -2 > 3.5 -- false

2 > 1/2 * 1 + 2 ⇒ 2 > 2.5 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y > 1/2x + 2

Option 2

y <= 3/2x - 1

Substitute (3, -2) and (2, 1) for x and y

-2 <= 3/2 * 3 - 1 ⇒ -2 <= 3.5 -- true

1 <= 3/2 * 2 - 1 ⇒ 1 < 2 -- true

Hence, (3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

Option 3

y >= 4x - 2

Substitute (3, -2) and (2, 1) for x and y

-2 >= 4 * 3 - 2 ⇒ -2 >= 10 -- false

2 <= 4 * 2 - 2 ⇒ 2 <= 6 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y >= 4x - 2

Option 4

y < -2x + 1

Substitute (3, -2) and (2, 1) for x and y

-2 < -2 * 3 + 1 ⇒ -2 < -5 -- false

2 < -2 * 2 + 1 ⇒ 2 < -3 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y < -2x + 1

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The points (3,-2) and (2, 1) are both solutions to which inequality?

and r(x) = 3x² If P(x)=x²-3x²-1/2 x + 10, Q(x) = ²x² - 1x ²-1/2 X- subtract R(x) from the sum of P(x) and Q(x). 6x + 1 then find p(x) + q(x) - r(x). 3 5 and R(x) - 34 X + the 4X​

Answers

Answer:Z

cos x dx = sin x + C

Z

sec2 x dx = tan x + C

Z

sec x tan x dx = sec x + C

Z

1

1 + x2

dx = arctan x + C

Z

1

1 − x2

dx = arcsin x + C

8.1 Substitution

Needless to say, most problems we encounter will not be so simple. Here’s a slightly more

complicated example: find

Z

2x cos(x

2

) dx.

This is not a “simple” derivative, but a little thought reveals that it must have come from

an application of the chain rule. Multiplied on the “outside” is 2x, which is the derivative

of the “inside” function x

2

. Checking:

d

dx sin(x

2

) = cos(x

2

)

d

dxx

2 = 2x cos(x

2

),

so Z

2x cos(x

2

) dx = sin(x

2

) + C.

Even when the chain rule has “produced” a certain derivative, it is not always easy to

see. Consider this problem:

Z

x

3

p

1 − x

2 dx.

There are two factors in this expression, x

3

and p

1 − x

2, but it is not apparent that the

chain rule is involved. Some clever rearrangement reveals that it is:

Z

x

3

p

1 − x

2 dx =

Z

(−2x)

1

2

(1 − (1 − x

2

))p

1 − x

2 dx.

This looks messy, but we do now have something that looks like the result of the chain

rule: the function 1 − x

2 has been substituted into −(1/2)(1 − x)

x, and the derivative

Step-by-step explanation:Z

cos x dx = sin x + C

Z

sec2 x dx = tan x + C

Z

sec x tan x dx = sec x + C

Z

1

1 + x2

dx = arctan x + C

Z

1

1 − x2

dx = arcsin x + C

8.1 Substitution

Needless to say, most problems we encounter will not be so simple. Here’s a slightly more

complicated example: find

Z

2x cos(x

2

) dx.

This is not a “simple” derivative, but a little thought reveals that it must have come from

an application of the chain rule. Multiplied on the “outside” is 2x, which is the derivative

of the “inside” function x

2

. Checking:

d

dx sin(x

2

) = cos(x

2

)

d

dxx

2 = 2x cos(x

2

),

so Z

2x cos(x

2

) dx = sin(x

2

) + C.

Even when the chain rule has “produced” a certain derivative, it is not always easy to

see. Consider this problem:

Z

x

3

p

1 − x

2 dx.

There are two factors in this expression, x

3

and p

1 − x

2, but it is not apparent that the

chain rule is involved. Some clever rearrangement reveals that it is:

Z

x

3

p

1 − x

2 dx =

Z

(−2x)

1

2

(1 − (1 − x

2

))p

1 − x

2 dx.

This looks messy, but we do now have something that looks like the result of the chain

rule: the function 1 − x

2 has been substituted into −(1/2)(1 − x)

x, and the derivative

Suppose you estimate the consumption function of Y; = α₁ + α₂X₁ +e; and the savings function of Z; =ᵝ₁ + ᵝ₂Xi+u₁, where Y denotes for consumption, Z denotes for savings, X denotes for income, a's and ß's are parameters and e and u are the random error terms. Furthermore, X = Y+Z, that is, income is equal to consumption plus savings, and variables are all in numerical terms.
(i) What is the relationship, if any, between the OLS estimators of 2 and 2? Show your calculations. [4]
(ii) Will the residual (error) sum of squares be the same for the two models of Y₁ = α₁ + a₂X₁ +e; and Z₁ =ᵝ₁ + ᵝ₂X;+u;? Explain your answer. [4]
(iii) Can you compare the R² terms of the two models? Explain your answer. [3]

Answers

(i) The relationship between the OLS estimators of α₂ and ᵝ₂ can be determined by considering the relationship between the consumption function and the savings function. Since X = Y + Z, we can substitute this into the consumption function equation to obtain Y = α₁ + α₂(Y + Z) + e. Simplifying the equation, we get Y = (α₁/(1 - α₂)) + (α₂/(1 - α₂))Z + (e/(1 - α₂)). Comparing this equation with the savings function Z₁ = ᵝ₁ + ᵝ₂X + u₁, we can see that the OLS estimator of ᵝ₂ is related to the OLS estimator of α₂ as follows: ᵝ₂ = α₂/(1 - α₂).

(ii) The residual sum of squares (RSS) will not be the same for the two models of Y₁ = α₁ + α₂X₁ + e and Z₁ = ᵝ₁ + ᵝ₂X₁ + u₁. This is because the error terms e and u₁ are different for the two models. The RSS is calculated as the sum of squared differences between the observed values and the predicted values. Since the error terms e and u₁ are different, the predicted values and the residuals will also be different, resulting in different RSS values for the two models.

(iii) The R² terms of the two models cannot be directly compared. R² is a measure of the proportion of the total variation in the dependent variable that is explained by the independent variables. Since the consumption function and the savings function have different dependent variables (Y and Z, respectively), the R² values calculated for each model represent the goodness of fit for their respective dependent variables. Therefore, the R² terms of the two models cannot be compared directly.

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Quality is important when making cleaning products. The quality control department wants to test throughout each production day, select every 100th product produces. What type of sample is this an example of

Answers

This is an example of systematic sampling, where every nth item is selected for testing throughout the production day.

In this case, every 100th product produced is selected for quality control testing. Systematic sampling is a statistical technique used in survey methodology that involves choosing components from an ordered sampling frame. An equiprobability approach is the most typical type of systematic sampling.

This method treats the list's evolution in a cyclical manner, returning to the top after it has been completed. The sampling process begins by randomly choosing one element from the list, after which every subsequent element in the frame is chosen, where k is the sampling interval (sometimes referred to as the skip).

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Find the volume of the solid.10 cm10 cm10 cmThe volume of the solid is(Simplify your answer.)

Answers

we have that

The figure show a cube

the volume of the cube is equal to

V=b^3

where b is the length side

we have

b=10 cm

substitute

V=10^3

V=1.000 cm3

Land Area
City
Chicago
(in square miles)
227.635
468.670
Population
(in 2011)
2,707,120
Los Angeles
3,819,702
To the nearest tenth, by how many people per square mile is the population density of Chicago greater than the population density of
Los Angeles?

Answers

Population density=Total population/Total area

#Chicago

Population density

2707120/227.63511892.4

#Los angeles

Population density

3819702/468.6708150.1

Difference

11892.4-8150.13742.3

The population density of Chicago is 3741.9 greater than Los Angele's population density.

What are arithmetic Operations?

The four fundamental operations of arithmetic are addition, subtraction, multiplication, and division of two or even more items.

Included in them is the study of integers, especially the order of operations, which is important for all other areas of mathematics,  notably algebra, data management, and geometry.

As per the given information in the question,

The population density is the ratio of the total population to the total area.

Total population of Chicago = 2,707,120

The land area of Chicago = 227.635

Then, the population density of Chicago will be:

= 2,707,120/227.635

= 11892.37

Total population of Los Angeles =  3,819,702

The land area of Los Angeles = 468.670

Then, the population density of Los Angeles will be:

= 3,819,702/468.670

= 8150.08

Then, the difference between Chicago and Los Angeles will be:

= 11892.37 - 8150.08

= 3741.9

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The table below represents the closing prices of stock TUV for the first five
days it was open. Using your calculator, what is the equation of exponential
regression that fits these data?
Day
1
2
3
4
5
Value
3.75
9.375
23.438
58.594
146.484
O A. y= 1.75 2.35*
OB. y= 2.5 3.5*
OC. y= 1.25.2.75*
OD. y= 1.5-2.5*

Answers

The equation of exponential regression that fits the data is given as follows:

y = 1.5(2.5)^x.

How to define an exponential function?

An exponential function has the definition presented as follows:

y = ab^x.

In which the parameters are given as follows:

a is the value of y when x = 0.b is the rate of change.

To obtain the equation of exponential regression, we must insert the points of the data-set into a calculator.

The points are given as follows:

(1, 3.75), (4, 9.375), (3, 23.438), (4, 58.594), (5, 146.484).

Inserting these points into a calculator, the equation is given as follows:

y = 1.5(2.5)^x.

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