Explain the difference between a distributed database and distributed processing sotwerad dis he a. Assume that your company has assigned you the responsibility of selecting the corporate DBMS. Develop a checklist for the technical and other aspects involved in the selection process.

We are required to determine the operating time per year in the given case. Here's how we can solve this problem:A plant engineer is evaluating the purchase of two possible motors.

Both motors are each rated at 125hp, but have different efficiencies and purchase costs. The less expensive motor has an initial purchase cost of $1000 and is 88% efficient. The more expensive motor has an initial purchase cost of $1500 and is 92% efficient.

The plant pays

$0.07/kW⋅h,

which reflects the cost if the total electricity costs are paid at the end of year 10. The annual effective interest rate over a 10-year period of life is 10%.The net present value (NPV) formula to compare two different options of investment (purchase of a motor in this case) is

NPV = C1 + C2/(1+i)² + C3/(1+i)³ + ….. - CI/(1+i)n

where,Ci = Cash inflow/outflow for year i (year 0 is usually the present year)

i = Discount rate

N = life of the investment

As both the options have the same net present value, we can assume that the net present value for both the options would be equal.

Calculating the net present value of Option 1 (Less expensive motor):Initial purchase cost

= $1000Operating cost (electricity)

= (125hp × 0.746 kW/hp) × (1/0.88 - 1) × 365 × 24 h/yr × $0.07/kWh =$6158.01

Net Present Value of Option

1 = -$1000 - $6158.01/(1+0.10)²

= -$4641.63

Calculating the net present value of Option 2 (More expensive motor):Initial purchase cost

= $1500O

perating cost (electricity)

= (125hp × 0.746 kW/hp) × (1/0.92 - 1) × 365 × 24 h/yr × $0.07/kWh

= $5337.69Net Present Value of Option 2

= -$1500 - $5337.69/(1+0.10)² = -$4665.

14Now we can use the following equation:Operating time per year

= (annual electricity cost)/(125hp × 0.746 kW/hp × (1/η - 1))where,η

= Efficiency of the motorUsing the above equation for both the options, we get:Operating time per year for Option 1

= $6158.01/(125hp × 0.746 kW/hp × (1/0.88 - 1))

= 614.36 h/yrOperating time per year for Option 2

= $5337.69/(125hp × 0.746 kW/hp × (1/0.92 - 1))

= 690.47 h/yr

Therefore, the most nearly operating time per year is (C) 690 h/yr.

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To answer the question: "T/F there is a limit of 35 changing cells in the edit scenario dialogue box"

True, there is a limit of 35 changing cells in the Edit Scenario dialogue box in Microsoft Excel.

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Answer:

1.c

2.c

3.c

Explanation:

James is a  pilot, whistle. He is wearing a flight suit. Paris is the palace where does he fly to. Hence, option C, C, and C are correct.

When flying an aircraft, such as a military aircraft, a glider, or a helicopter, one must wear a full-body suit called a flight suit. These outfits are typically meant to keep the user warm and are also functional (they have many of pockets) (including fire ). In most cases, it looks like a jumpsuit.

The G suit, sometimes known as a "anti-G suit," is a one-piece jumpsuit that shields a pilot from the pressure of G forces pressing down on him and causing discomfort or unconsciousness.

The traditional attire for pilots of military and commercial aircraft, helicopters, and even gliders is flight suits or flyers coveralls. In areas where there is a risk of fire, ground personnel—including aircrews—often wear flight suits as well.

Thus, option C, C, and C are correct.

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a. Based on the 43 years of record and the fact that the 1972 flood occurred once during this interval, it can be estimated that a flood of this magnitude would be expected to occur once every 43 years, on average.

b. Using the graph paper, plot a recurrence curve for the Rapid Creek flood data. Ignoring the 1972 flood, an eyeball, best fit, and a straight line should be plotted through the points. The 100-year flood discharge can be determined by looking at the point on the graph which is at the 100-year recurrence interval.

c. The recurrence interval of the 1972 flood, using the curve drawn, can be determined by looking at the point on the graph which is nearest to the 1972 flood discharge.

d. Given the range of values from a and c above, it can be stated that floods as large as the one which occurred in 1972 are rare events and occur infrequently.

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Answer:

B. restricting the dislocation motion

Explanation:

Solid solution strengthening is a type of alloying that is carried out by the addition of the atoms of the element used for the alloying to the crystallized lattice structure of the base metal, which the metal that would be strengthened. The purpose of this act is to increase the strength of metals. It actually works by impeding or restricting the motion in the crystal lattice structure of metals thus making them more difficult to deform.

The solute atoms used for strengthening could be interstitial or substitutional. The interstitial solute atoms work by moving in between the space in the atoms of the base metal while the substitutional solute atoms make a replacement with the solvent atoms in the base metal.

Answer:

They help an organization realize the maximum benefit from its investment in equipment, personnel, and business processes. They use and analyze systems, interpret data, and customize systems to better meet the organization's needs.

Explanation:

brainliest plz

Answer:

ục tiêu của pháp y máy tính là kiểm tra phương tiện kỹ thuật số theo cách thức pháp y với mục đích xác định, bảo tồn, phục hồi, phân tích và trình bày các sự kiện và ý kiến ​​về thông tin kỹ thuật số

Explanation:

Answer:

glue

Explanation:

Here's a class diagram that represents the entities and their relationships for the video store scenario described:

+---------------------+        +---------------+       +-----------------+

|      Movie          |        |    Member     |       |    Rental       |

+---------------------+        +---------------+       +-----------------+

|  movie_id : int     |        |   member_id : |       | rental_id : int |

|  title : string     |        |   int        |<-------| movie : Movie    |

|  format : string    |        |   name : str |        | member : Member |

|  category : string  |        |   phone : str|        | rental_date : dt|

+---------------------+        |   type : str |        | is_returned : bool |

                               +---------------+        +-----------------+

                               |  credit_card: |                

                               +---------------+                

                               | rent_movies() |                

                               +---------------+                

                                         ^                      

                                         |                      

                               +---------------+                

                               | GoldenMember  |                

                               +---------------+                

                               | rent_limit:   |                

                               +---------------+                

                               | return_movies()|                

                               +---------------+                

                                         ^                      

                                         |                      

                               +---------------+                

                               | BronzeMember |                

                               +---------------+                

                               | rent_limit:   |                

                               +---------------+                

                               | return_movie()|                

                               +---------------+                

The Movie class has attributes movie_id, title, format and category. Each Member has a member_id, name, phone, and type. The Rental class is the association class that connects Movie and Member through the movie and member attributes, respectively, and adds rental_id, rental_date, and is_returned attributes.

There are two sub-classes of Member: GoldenMember and BronzeMember. The GoldenMember has an additional credit_card attribute and a rent_limit method that allows them to rent multiple movies at once. The BronzeMember has a rent_limit method that allows them to rent only one movie at a time. Both sub-classes have a return_movie or return_movies method, respectively, to allow them to return the rented movies.

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Unfortunately, I cannot see the figure you referred to in your question. However, I can provide you with the general steps to solve the problem.

To determine the dimensions of the riser so that it will take 0.5 min longer to freeze than the casting itself, you can use Chvorinov's rule, which relates the solidification time of casting to its volume and surface area.

The formula for Chvorinov's rule is:

t = K(V/A)^n

where:

t = solidification time (min)

K = mold constant (min/in^2)

V = volume of casting (in^3)

A = surface area of casting (in^2)

n = a constant that depends on the shape of the casting

To apply Chvorinov's rule to the riser, you need to determine the volume and surface area of the casting and the riser. Then, you can set up two equations using Chvorinov's rule, one for the casting and one for the riser, and solve for the diameter and height of the riser.

Here are the general steps to solve the problem:

Determine the volume and surface area of the casting. You can do this by breaking down the casting into simple shapes (e.g., cylinder, cone, sphere) and calculating their volumes and surface areas.

Determine the volume and surface area of the riser. Since the diameter-to-length ratio is 1.0, the riser is a cylinder. The volume of a cylinder is V = πr^2h, and the surface area is A = 2πrh + 2πr^2, where r is the radius of the cylinder and h is the height.

Plug the values for the volume and surface area of the casting and the riser into Chvorinov's rule to set up two equations:

t_casting = K(V_casting/A_casting)^n

t_riser = K(V_riser/A_riser)^n + 0.5

Substitute the formulas for the volumes and surface areas into the equations and simplify.

Solve the two equations for the radius and height of the riser.

I hope this helps you to solve the problem. If you have any further questions or need additional assistance, please let me know.

Answer:

Technician A

Explanation:

Technician A is correct. Technician B is wrong, as different drive vehicles (FWD, RWD, AWD, 4WD) each require a certain rotation for optimal tire wear.

Answer:

Automation generally means “a process performed without human assistance”, while autonomy implies “satisfactory performance under significant uncertainties in the environment and the ability to compensate for system failures without external intervention [emphasis mine].”

Explanation:

When estimating the test pattern for geometric distortion, all lines should seem straight.

Geometric distortion, when seen in a suitably scaled common picture display plane, describes the incorrect positioning of scatters with regard to their true position in the output image.

Terrain, camera tilts, film deformation, camera lens, atmospheric bending, and other camera flaws are the six main causes of aerial image distortion. The two main sources of air that tilt the camera are thought to produce the most error: the terrain and the camera itself.

The difference between the coordinate data from the actual image acquisition (sensor) and the ideal image coordinate data is known as geometrical distortion. Geometric correction entails gathering ground control points on the image and adjusting for geometric distortion brought on by some variance.

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Tech B is correct because his statement accurately reflects the diverse nature of atoms regarding their electron transfer capabilities.

Tech B is correct in stating that not all atoms can easily give up or accept electrons. The ability of an atom to gain or lose electrons depends on its atomic structure and the distribution of its electrons in the outermost energy level, known as the valence shell.

Atoms strive to achieve a stable electron configuration typically by obtaining a full valence shell with eight electrons (the octet rule), which is more stable. The elements with fewer than four or more than four valence electrons are typically more reactive as they either tend to gain or lose electrons to achieve a stable configuration.

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Answer:

Explanation:

Given that:

f = 250 Hz

\(\delta\)= 2%

\(f_n\)= 600 Hz

\(\zeta\) = 0.5 to 1.5  increment by 0.05

\(F = A sin (Xt)\)

For 250 Hz = 250 cycle/sec

\(X = 2 \pi t 250\)

\(X = 500 \pi t\)

\(X = Asin (500 \pi t)\)

\(\omega = 250 \\ \\ \omega_n = 600\)

M = 0.98 , 1.02

\(M_{(w)}} = \sqrt{[1-(\frac{w}{w_n})^2 + ( 2\zeta \frac{w}{w_n})^2}\)

\(\frac{1}{M} = [1-(\frac{w}{w_n})^2]+(2 \zeta \frac{w}{w_n})^2\)

\(\zeta = \frac{w_n}{2w}\sqrt{\frac{1}{M^2}-(1-(\frac{w}{w_n})^2)^2}\)

\(\zeta = \frac{600}{2(250)}\sqrt{\frac{1}{0.98^2}-(1-(\frac{250}{600})^2)^2}\)

\(\zeta = 0.7183\)

At 0.7183 value of damping ratio the error value was 2% at 0.98 value of M

\(\frac{1}{M} = [1-(\frac{w}{w_n})^2]+(2 \zeta \frac{w}{w_n})^2\)

\(\zeta = \frac{w_n}{2w}\sqrt{\frac{1}{M^2}-(1-(\frac{w}{w_n})^2)^2}\)

\(\zeta = \frac{600}{2(250)}\sqrt{\frac{1}{1.02^2}-(1-(\frac{250}{600})^2)^2}\)

\(\zeta = 0.6330\)

At  0.6330 value of damping ratio the error value was 2% at 1.02 value of M.

Hence, the damping ratio \(\zeta\) of the transducer must be placed between 0.6330 to 0.7183

The Standard Penetration Test (SPT) is is the one best field test for estimating the relative density of an uncemented sand deposit and the undrained shear strength of a deposit of saturated clay at the same site

An often utilized field test for determining the approximate density of an uncompacted sand deposit is the Standard Penetration Test (SPT). The process entails inserting a typical sample-collecting tool into the ground with a customary force and gauging the amount of force needed to reach a regular depth with the tool.

The vane shear test is a widely used field test for approximating the undrained shear strength of a saturated clay deposit. This process entails the placement of a blade into the ground and consistently turning it while observing the force necessary to turn the blade.

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GIS

The full for GIS is : Geographic Information System.

The GIS is a system of mapping that is used to create, analyze, manage and map all the types of data.

It is a method capturing, checking as well as displaying all the data that is related to the position of the surface of earth.

Remote Sensing

Remote sensing is defined as a process where the various physical characteristics of an area are constantly monitored and detected by a process of measuring the reflection of the emitted radiations at ta distance.

The snow covered areas of the Kabul basin can be monitored and analyzed by using the process of GIS and remote sensing.

They provide a continuous source of information and data about snow covered peaks, the amount of snow to the authorities.

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The steps that can be followed to create a Work Breakdown Structure (WBS) for the given scope.

1. Identify the main deliverables:

- Three bedrooms

- Two and a half bathrooms

- Pool

- Two patios, including one enclosed patio

2. Break down each deliverable into smaller, manageable tasks:

- Bedrooms:

- Design and plan

- Foundation and framing

- Electrical and plumbing

- Drywall and insulation

- Painting and finishing touches

- Bathrooms:

- Design and plan

- Foundation and framing

- Electrical and plumbing

- Drywall and insulation

- Installation of fixtures and accessories

- Pool:

- Design and plan

- Excavation and installation of pool shell

- Installation of filtration system

- Electrical and plumbing

- Filling with water and testing

- Patios:

- Design and plan

- Foundation and framing

- Electrical and plumbing

- Installation of flooring and finishing touches

- Enclosing one of the patios:

- Design and plan

- Framing and installation of walls and windows

- Electrical and plumbing

- Installation of flooring and finishing touches

3. Identify dependencies and relationships between tasks:

- The design and planning of each deliverable will need to be completed before any construction work can begin.

- Electrical and plumbing work will need to be completed before drywall and insulation work can begin.

- Flooring and finishing touches should be completed after the installation of fixtures and accessories.

4. Create a hierarchical structure with the main deliverables at the top level, and the smaller tasks beneath them.

5. Assign timeframes and resources to each task, and estimate the overall project duration.

Note: This is just an example of how to create a WBS for the given scope. The actual WBS may vary depending on the specific requirements of the project and the preferences of the project team.

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The power absorbed by the electric heater is;

P = 660 Watts

We are given;

Current; I = 6 A

Voltage; V = 110 V

Now, we want to find the power that is absorbed by the electric heater.

The formula for electric power is;

P = IV

Where;

I is current

I is current V is voltage

Thus:

P = 6 × 110

P = 660 Watts

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Answer:

I don't think so but you could  remember  little bit and  you could pass.

Explanation:

To solve this problem, we can use Newton's second law of motion:We can also use the equation for kinetic friction:

ΣF = ma

where ΣF is the net force acting on the system, m is the total mass of the system, and a is the acceleration of the system. We can also use the equation for kinetic friction:

f = μN

where f is the force of kinetic friction, μ is the coefficient of kinetic friction,and N is the normal force.

First, we need to find the acceleration of the system:

ΣF = ma

F_net = F_A - f

where F_A is the force exerted by crate A on the system, and f is the force of kinetic friction. Since the system is starting from rest, its initial velocity is 0.

F_A = m_total*a

m_total = m_A + m_B

f = μ*N

N = m_total*g

where g is the acceleration due to gravity.

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According to the Tresca criterion, the point with the lowest factor of safety against failure is the one with the highest difference between the maximum and minimum principal stresses.

To determine the point with the lowest factor of safety against failure according to the Tresca criterion, we need to find the maximum shear stress at each point. The Tresca criterion states that failure occurs when the maximum shear stress exceeds a certain value, which is often taken as the yield strength of the material divided by a factor of safety.

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Answer: jay is traveling at 4 miles per hour :)

Explanation:

To calculate the final grade, create a spreadsheet in Excel, enter assignment names and points, assign weights to exams, and use formulas to calculate grades. Adjusting the exam weight will automatically update the final grades.

To calculate the final grade for a student that allows you to change the weight given to exams, follow these steps:

To change the weight given to exams, change the value in cell C1. The values in column C will be recalculated automatically. The final grades in column G will also be updated.

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Answer:

TRUE

Explanation: I think

protecting the ecosystem saves the species is true because a lot of species lives in the ecosystem and is there habitat / i think

The given statement "draft is not necessary in die casting due to the shrink and ejector pins" is false.

Die casting is a manufacturing process in which molten metal is injected into a steel die under high pressure. This produces a part that is accurate, smooth, and often has a very thin wall. Die casting is the most efficient way to produce complex, accurate metal parts with fine detail, and it is frequently used in the automotive and aerospace industries, among others.

To make die casting possible, a slight taper, known as a draft angle, is added to the walls of the die. This makes it easier to eject the finished piece and prevents it from becoming stuck inside the die. The need for a draft angle in die casting. Die casting requires the use of a draft angle on all vertical faces.

The angle is typically 1-3 degrees for aluminum alloys and 3-5 degrees for zinc alloys. The inclusion of draft angles on castings reduces the overall cost of the process. Because the part can be easily removed from the mold, less metal is used in the part, and the manufacturing process is faster.

Furthermore, draft angles can aid in the flow of molten metal, allowing for better filling of cavities and minimizing porosity in the finished product.

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As it can not exist in the database unless another type of entity also exist in the database Entity A is a 'Strong Entity'. The answer is B.

A recursive relationship is a relationship between an entity and 'Itself'. The answer is D.

1-  In a database, a strong entity is an entity that can exist independently without being associated with any other entity. In this case, Entity A cannot exist in the database unless another type of entity (a strong entity) also exists. Therefore, Entity A is a strong entity. The correct answer is option B.

2- A recursive relationship is a relationship where an entity is related to itself. It occurs when an entity has a relationship with other instances of the same entity type. For example, in a hierarchical organization structure, an employee can have a relationship with other employees who are their subordinates. Therefore, the recursive relationship is between an entity and itself. The correct answer is option D.

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Based on the code given , the Step 1  is done by enforcing maximum() and min() in ARM7 assembly while Step 2  is done by enforcing the main while circle in ARM7 assembly.

To apply the maximum() and min() functions in ARM7 assembly, we can use some instructions to optimize the law and code speed. There is one possible way to do it based on the image attached.

Therefore, To apply the main while loop, we need to check if the left over of the division between result and d isn't zero, and if so, add c to affect. We can use the SWI 0x6 instruction to gain the balance of the division.

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See text below

We will translate the following C function, which calculates the Lowest Common Multiple (1cm) between two positive numbers, into ARM7 assembly:

unsigned int lcm(unsigned int a, unsigned int b)

{

(unsigned int c, d, result; // cannot be translated)

c = max(a, b); // i.e. c-a if a >= b, otherwise c=b d = min(a, b); // same, but vice-versa

result = c;

while ((result % d) != 0) {

}

result = result + c;

}

(return(result);

// cannot be translated)

In doing so, you are asked to optimize the assembly code for execution speed. i.e., a) fewest number of cycles, taking into account pipeline emptying/refilling on branch instructions for example, and b) fewest number of instructions.

Disregard the first/last lines of the lcm() function, which cannot be translated into assembly. This exercise is broken into these two steps:

1. First, implement the two successive lines min() and max() in ARM7 assembly:

c = max(a, b); // i.e. c-a if a>=b, otherwise c=b

d = min(a, b); // same, but vice-versa

[Hint 1]: Remember that the function's arguments, a and b, will be found in registers r0 and rl respectively. Every other register is free for you to use in your code. Remember to use conditional instructions whenever possible, to optimize code density and execution speed.

2. Implement the main while loop in ARM7 assembly.

[Hint 2]: The remainder of a division (i.e., the “modulo” operation %) can be obtained by relying on the BIOS, using the ARM7 instruction: SWI 0x6 (which cannot be conditional) after placing the input in the appropriate, predefined registers (see lecture notes), which cannot be selected/changed, and reading the output from the appropriate register.

Remember to comment each line of your program to explain what your code does.



Describe the changes to the memory and the registers, after the execution of each of the following five load/store instructions in the (five-lined) program below (i.e.. these five instructions are run as a sequence from the initial memory state shown below).

We assume big endian formatting.

Initial Memory State 0x420014 DE OC 63 20 0x420010 FF AE 10 00 0x42000c 13 46

FA 08

0x420008 0x420004 0x420000

24 AB

A0

22

00 00 CO

FF

00 1C OE 3B

Initial Registers

State

r0=0x00000000, r1=0x00000000, r2=0x00420008, 13=0x00000007,

r4=0x00000001

# Start of the program

LDR

r0, [r2, #-4]

LDRB

r1, [r2, r3]

STR

r1, [2], r4 LSL #2

SWP

STMDA

r4, r0, [r2]

# End of the program

r2!, (r4, r3, r0}