The balance of chemical equation : 2KClO₃ ⟶ 2KCl + 3O₂
Further explanationEqualization (balance) of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc. 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product 3. Select the coefficient of the substance with the most complex chemical formula equal to 1Reaction
\(\tt KClO_3\Rightarrow KCl+O_2\)
1. Coefficient
KClO₃ ⟶ aKCl + bO₂
2. Equation
K ⇒ left =1, right=a ⇒a=1
Cl⇒ left =1, right=a ⇒a=1
O ⇒ left = 3, right = 2b ⇒3=2b, b = 1.5
The equation turns into :
KClO₃ ⟶ KCl + 1.5O₂
multiplied by 2
2KClO₃ ⟶ 2KCl + 3O₂
A reaction vessel is filled with 4.04 g of hydrogen gas and 16.0 g of oxygen gas, and the mixture
explodes. Identify the limiting reactant and deduce the mass of water produced. Show all your
calculations to support your answer.
Balanced Equation: 2H2 + O2 = 2H2O
The limiting reactant is hydrogen. The mass of water produced is 18.02g.
What is limiting reactant?The limiting reactant in a chemical reaction determines the amount of product formed.
Balance equation is: 2H₂(g) + 1O₂(g) → 2H₂O(l)
Find the moles for each of the reactants, n = m/M
n(H₂) = 4.04g / 2.02 g/mol= 2.00mol
n(O2) = 16.00g / 32.00 g/mol = 0.05mol
Molar mass of water is (2 x 1.01) + (16) = 18.02 g/mol
The ratio is 1:2 ,i.e. one mole of O₂ will produce twice as many moles of water. Therefore, multiply the amount of moles for O₂ by two
n (O₂) = 0.05mol * 2 = 1mol
The mass of water produced,
m(H2O) = 1mol * 18.02g/mol = 18.02g
Thus, 18.02g is the mass of water produced.
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what is the purpose of the sodium bicarbonate in this experiment? extract excess water from the ether layer. extract the product. extract sulfuric acid from the ether layer.
The purpose of the sodium bicarbonate in this experiment is to extract excess water from the ether layer.
Sodium bicarbonate is a chemical compound with the formula NaHCO3. It is a white solid that is crystalline but is also usually available in a fine powder form.
In the experiment mentioned, the sodium bicarbonate is being used to extract the sulfuric acid from the ether layer.
Sulfuric acid is a strong acid that can be hazardous to work with, and it is also an impurity that could interfere with the purity of the desired product. To extract the sulfuric acid from the ether layer, sodium bicarbonate is added to the mixture. The sodium bicarbonate reacts with the sulfuric acid to produce carbon dioxide, water, and sodium sulfate.
The carbon dioxide gas is released, and the sodium sulfate dissolves in the aqueous layer, leaving the sulfuric acid behind in the ether layer. The ether layer is then separated from the aqueous layer, and the sulfuric acid can be discarded or treated appropriately.
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A 10.00 mL diluted chloride sample was titrated with 0.02749 M AgNO3, and 16.51 mL AgNO, was required to reach the endpoint. How would the following errors affect the calculated concentration of CI? a. The student read the molarity of AgNO, as 0.02479 M instead of 0.02749 M. The experimentally calculated moles of Ag would be too! calculated [CI] in the unknown would come out too b. The student was past the endpoint of the titration when the final buret reading was taken. v The experimentally determined moles of Ag would be too | calculated C1 concentration. so the calculated moles of CI would come out too so the calculated moles of CI would come out ✓ The as would the
The effect of errors on the calculated concentration of CI is significant.
A 10.00 mL diluted chloride sample was titrated with 0.02749 M AgNO3, and 16.51 mL AgNO, was required to reach the endpoint. The effect of errors on the calculated concentration of CI can be explained as follows:a. The student read the molarity of AgNO, as 0.02479 M instead of 0.02749 M. If the student read the molarity of AgNO, as 0.02479 M instead of 0.02749 M, then the experimentally calculated moles of Ag would be too high. Consequently, the calculated [CI] in the unknown would come out too low. b.
The student was past the endpoint of the titration when the final buret reading was taken. If the student was past the endpoint of the titration when the final buret reading was taken, then the experimentally determined moles of Ag would be too low. This would cause the calculated C1 concentration to come out too high. Consequently, the calculated moles of CI would come out too high. Therefore, the effect of errors on the calculated concentration of CI is significant.
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What mass of sulfuric acid (H2SO4) is contained in 50.00 mL of a 5.85 M solution? grams
Answer:
28.69 grams
Explanation:
To find the mass, we first need to find the moles. Once we have the moles, it is easy to use the molar mass of H2SO4 to find its mass.
To find the moles, remember that molarity (M) is equal to the moles divided by the volume (L). The volume HAS TO be converted to liters!
M = moles / V
5.85 M = moles / 0.05 L
moles = 0.2925
Now we know that we have 0.2925 moles of sulfuric acid. The molar mass of sulfuric acid is 98.08 g/mol.
0.2925 moles * (98.08 g / mol) = 28.69 grams
Make sense? If you have any questions, don't hesitate to ask!
This type of chemist understands the structure of living systems and, in turn, their
functions and ways to control them.
A Biochemist is a type of chemist understands the structure of living systems and, in turn, their functions and ways to control them.
What is the chemistry of living systems called?The chemistry of living system is known as Biochemistry.
Biochemistry is a study of the chemical changes that occur in living organisms.
Scientists that study biochemistry are called Biochemists.
Biochemistry studies the structure and function of biological molecules such as carbohydrates, lipids, proteins, e.t.c., as well the chemical reaction they undergo.
Biochemistry also studies the energy changes that occur in living systems.
In conclusion, the chemistry of living systems is called Biochemistry.
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Throughout history, scientists have been known to copy ideas from their peers. Dmitry Mendeleev was no exception—he arranged all of the elements known at the time according to their atomic masses, just as Johann Döbereiner and John Newlands did before him. However, Mendeleev intentionally left blank spaces in his working version of the periodic table of elements.
Which statement best explains the importance of the blank spaces in Mendeleev’s version of the periodic table of elements?
The statement which best explains the importance of the blank spaces in Mendeleev’s version of the periodic table of elements is that they predicted the existence of elements that had not yet been discovered.
What is Periodic table?This is referred to as the tabular arrangement of elements into groups and periods based on their common properties and features. There are 18 groups and seven periods in which elements are grouped under.
Mendeleev intentionally left blank spaces in his working version of the periodic table of elements because he predicted the existence of elements that had not yet been discovered.
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The peptide bond is stronger than the ester bond. What structural feature of the peptide bond gives it additional bond strength
The peptide bond is indeed stronger than the ester bond, and its additional strength is due to its structural features.
The peptide bond is a covalent bond formed between the carboxyl group (-COOH) of one amino acid and the amino group (\(-NH_2\)) of another amino acid. This bond is formed by a condensation reaction, where a molecule of water is released.
The unique structural feature of the peptide bond is its partial double bond character, which arises due to the resonance between the lone pair of electrons on the nitrogen atom and the adjacent carbonyl carbon atom. This resonance creates a planar structure, with the peptide bond being nearly rigid and incapable of rotation.
The partial double bond character and the planar structure of the peptide bond result in the formation of strong dipole-dipole interactions and hydrogen bonds between adjacent peptide bonds, leading to the formation of a stable and rigid polypeptide backbone.
This makes the peptide bond stronger than the ester bond, which lacks the partial double bond character and the planar structure.
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if 600.0 ml of air is heated from 293 k to 333 k what volume will it occupy
Answer:
Explanation:
V1= 600.0 mL
T1= 293 K
V2 unknown
T2= 333K
Charles law V1*T2=V2*T1
where V1 and T1 are the initial volume and temperature. V2 and T2 are the final temperature and volume.
V2=(V1*T2)/T1 = ( 600.0*333)/293= 682 mL (with significant figures)(681.911 mL before signifcant figures.)
A chemist prepares a solution of magnesium fronde (Mg) dy weighing out 1.19 mg of magnesium Nuoride into a 350. ml. volumetric flask and nming the
5
Rask to the mark with water.
Calculate the concentration in g/l. of the chemist's magnesium fuoride solution. Round your answer to 3 significant digits.
0
Х
?
33
-Involves electrons
-Happens outside atomic
nucleus
-Releases relatively small
amounts of energy
-Involves neutrons
-Happens inside atomic
nucleus
-Releases relative large
amounts of energy
How should the student label each circle in this diagram?
reaction A: chemical; reaction B: nuclear
reaction A: nuclear: reaction B: chemical
reaction A: strong nuclear; reaction B: weak nuclear
reaction A: weak nuclear; reaction B: strong nuclear
Reaction A is chemical, while Reaction B is nuclear, is the proper response. Electrons are involved in chemical processes that take place outside of the atomic nucleus and release modest quantities of energy.
On the other hand, nuclear processes, which take place inside the atomic nucleus and include neutrons, release comparatively high levels of energy. The terms "weak nuclear" and "strong nuclear," which describe the forces that hold protons and neutrons together in the nucleus, are inapplicable in this situation.
These forces are not present in chemical and nuclear reactions, which are fundamentally distinct processes. Nuclear reactions entail the conversion of one element into another, whereas chemical reactions require the building and breaking of chemical bonds.
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2.F is a solution containing O.122mol/dm3 of HCl.G contains 7.0g of Y0H per dm3.Assuming at the end of titration exercise,28.00cm3 of the acid neutralized 25.00cm3 of the base.Calculate the, i.Concentration of G in mol/dm3 ii.Molar mass of YOH iii.Percentage by mass of Y in YOH The equation for the reaction HCl + YOH YCl + H20
i) The concentration of G in mol/dm3 is also 0.003416 mol/dm³.
ii) Molar mass of YOH is 204.49 g/mol
iii) The concentration of G is 0.003416 mol/dm³, the molar mass of YOH is 204.49 g/mol, and the percentage by mass of Y in YOH is 91.63%.
To solve this problem, we'll use the given information and the equation for the reaction: HCl + YOH → YCl + H2O
i. Concentration of G in mol/dm³:
From the given information, we know that 28.00 cm³ of the acid (F) neutralizes 25.00 cm³ of the base (G). This means the stoichiometric ratio between HCl and YOH is 1:1. Therefore, the number of moles of HCl neutralized by 28.00 cm³ of F is:
n(HCl) = concentration of F × volume of F in dm³
= 0.122 mol/dm³ × 28.00 cm³ / 1000 cm3/dm³
= 0.003416 mol
Since the stoichiometric ratio is 1:1, the concentration of G in mol/dm³ is also 0.003416 mol/dm3.
ii. Molar mass of YOH:
To calculate the molar mass of YOH, we need to know the mass of YOH used in the reaction. From the given information, we know that 7.0 g of YOH is present in 1 dm3 of G. Therefore, the molar mass of YOH can be calculated as:
Molar mass of YOH = Mass of YOH / Number of moles of YOH
= 7.0 g / 0.003416 mol
= 204.49 g/mol (rounded to two decimal places)
iii. Percentage by mass of Y in YOH:
The molar mass of Y in YOH can be calculated by subtracting the molar mass of OH from the molar mass of YOH:
Molar mass of Y = Molar mass of YOH - Molar mass of OH
= 204.49 g/mol - 17.01 g/mol
= 187.48 g/mol
The percentage by mass of Y in YOH can be calculated as:
Percentage by mass of Y = (Molar mass of Y / Molar mass of YOH) × 100%
= (187.48 g/mol / 204.49 g/mol) × 100%
= 91.63% (rounded to two decimal places)
Therefore, the concentration of G is 0.003416 mol/dm3, the molar mass of YOH is 204.49 g/mol, and the percentage by mass of Y in YOH is 91.63%.
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Which statements describe the electron sea model? Check all that apply.
The statements that describe the electron sea model are;
Electrons all have approximately the same energy.
Electrons move freely among atoms (delocalized).
What is the electron sea model?We know that there are several models that can be used for the determination of the movement of the electrons in the atom. In the electron sea model, we are saying that the electrons are quite free to move freely from one atom to the another and they are not attached to any particular atom.
We have to know that the electrons are known to occur in specific energy levels. The electrons must only be found in the energy level that corresponds to that particular electrons. This also means that the electrons that are in the electron sea must all be of the same energy.
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Missing parts;
Which statements describe the electron sea model? Check all that apply. Electrons all have approximately the same energy. Electrons move among orbitals of different energies. Electrons move freely among atoms (delocalized).
A 6-kg bowling ball sits on top of a building that is 120 meters tall.
Circle one: KE / GPE / both
Show your work for finding the values of each type of energy the object has:
help fast please
KE: The kinetic energy (KE) of the bowling ball is 0 J since it is not moving.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy an object possesses due to its motion. Kinetic energy can be found in many forms, such as the energy of a moving car, a roller coaster car, a spinning bicycle wheel, or sound waves traveling through the air. Kinetic energy is the energy of motion and can be transferred from one object to another.
GPE: The gravitational potential energy (GPE) of the bowling ball can be found by using the formula GPE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the building. In this case, m = 6 kg, g = 9.8 m/s2, and h = 120 m. Thus, GPE = 6 x 9.8 x 120 = 7,128 J.
KE: The kinetic energy (KE) of the bowling ball is 0 J since it is not moving.
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A ma of 6. 4 tonne of ulfur i burned to produce ulfur dioxide ga. Calculate the maximum volume, in dm3, of ulfur dioxide ga that can be produced at rtp
[molar volume of ulfur dioxide ga at rtp=24dm3]
[1 tonne= 10^6g]
give your anwer in tandard form
The maximum volume of gas is 1.2*10^7 dm3 that is calculated using mass of SO3 i.e., 6.4 tonnes.
The molar volume, symbol Vm is the volume occupied by one mole of a substance (chemical element or chemical compound) at a given temperature and pressure. It is equal to the molar mass (M) divided by the mass density (ρ). The given mass of sulfur trioxide is 6.4 tonnes.
In order to calculate the volume of sulfur dioxide, we need to calculate the moles of the gas first using the mass and number of molecules.
The moles of SO3 gas is 6.4 *10^6/64 which is 1*10^6 moles.
The maximum volume of gas is 1*10^6/2*24 = 1.2*10^7 dm3.
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How can light help us understand atoms?
Answer: We can calculate the energy levels of an atom
Explanation:
Spectral lines tell us how many different energy levels an atom has, and how far apart those energy levels are spaced.This is possible because spectral lines are the result of an excess (emission lines) or deficiency (absorption lines) of observed photons emitted from certain types of matter. The lines are caused by electrons moving between energy levels within individual atoms. Since each element emits it's own unique spectrum, this means that different types of atoms must have a distinct number of electrons in very particular energy levels.
find the molality of the solution if 35.0 g of propyl alcohol (ch3ch2 ch2oh) are dissolved in 200 g of water. 1.55 m 2.92 m 2.37 m 0.965 m
The molality of the solution is approximately 1.55 m. Therefore, the correct answer is A) 1.55 m.
To find the molality (m) of the solution, we need to determine the number of moles of the solute (propyl alcohol) and the mass of the solvent (water).
Given:
Mass of propyl alcohol (solute) = 35.0 g
Mass of water (solvent) = 200 g
Step 1: Convert the mass of propyl alcohol to moles.
First, we need to calculate the molar mass of propyl alcohol (C3H7OH):
C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol
Molar mass of propyl alcohol = (3 * 12.01 g/mol) + (8 * 1.008 g/mol) + 16.00 g/mol = 60.12 g/mol
Now, we can calculate the number of moles of propyl alcohol:
Number of moles of propyl alcohol = Mass of propyl alcohol / Molar mass of propyl alcohol
= 35.0 g / 60.12 g/mol
Step 2: Calculate the molality.
Molality (m) is defined as the number of moles of solute per kilogram of solvent.
Mass of water (in kg) = Mass of water (g) / 1000
Now we can calculate the molality:
Molality (m) = Number of moles of propyl alcohol / Mass of water (in kg)
= (35.0 g / 60.12 g/mol) / (200 g / 1000)
Simplifying the expression, we get:
Molality (m) = (35.0 g * 1000) / (60.12 g/mol * 200 g)
= 1.55 m (rounded to two decimal places)
Option A
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A single atom of an element has 21 neutrons, 20 electrons, and 20 protons, which elementis it?
Answer:
Calcium
Explanation:
The number of protons is the atomic number of the element. Number 20 on the periodic table is Calcium.
how many grams of nan3 are needed to produce enough n2 gas to fill an air bag with a volume of 20.0 l upon complete decomposition?
Answer:
35.37 grams - of NaN3 are needed to produce enough N2 gas to fill an airbag with a volume of 20.0 L upon complete decomposition.
Determining the concentration of NaN3 needed:
To determine how many grams of NaN3 are needed to produce enough N2 gas to fill a 20.0 L airbag upon complete decomposition, follow these steps:
1. Convert the volume of N2 gas (20.0 L) to moles using the Ideal Gas Law formula: PV = nRT.
Rearrange the formula to solve for n (moles): n = PV/RT.
- P (pressure) = 1 atm (assuming standard atmospheric pressure)
- V (volume) = 20.0 L
- R (gas constant) = 0.0821 L atm/mol K
- T (temperature) = 298 K (assuming room temperature)
2. Plug in the values and solve for n:
n = (1 atm × 20.0 L) / (0.0821 L atm/mol K × 298 K) = 0.816 moles of N2 gas
3. Use the stoichiometry of the reaction to determine the moles of NaN3 required:
NaN3 (s) -> Na (s) + 3/2 N2 (g)
Since 3 moles of N2 gas are produced from 2 moles of NaN3, we can set up a proportion to find the moles of NaN3:
(3 moles N2) / (2 moles NaN3) = (0.816 moles N2) / x moles NaN3
4. Solve for x (moles of NaN3):
x = (2 moles NaN3 × 0.816 moles N2) / 3 moles N2 = 0.544 moles NaN3
5. Convert moles of NaN3 to grams using its molar mass (65.01 g/mol):
(0.544 moles NaN3) × (65.01 g/mol) = 35.37 g NaN3
So, 35.37 grams of NaN3 are needed to produce enough N2 gas to fill a 20.0 L airbag upon complete decomposition.
We need 35.68 grams of NaN3 to produce enough N2 gas to fill an airbag with a volume of 20.0 L upon complete decomposition.
Explanation:
The balanced equation for the decomposition of NaN3 is 2NaN3(s) → 2Na(s) + 3N2(g).
2 moles of NaN3 produce 3 moles of N2.
Given, Volume of the airbag is 20.0 L.
The gas law is as follows: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature, given that P, R, and T are constant.
Let's assume standard temperature and pressure: P = 1 atm, and T = 273.15 K.
Using the ideal gas law to determine the number of moles of N2 gas that we need to fill the airbag completely.
It implies that V = nRT/P
Solving for the number of moles: n = PV/RT
n = (1 atm)(20.0 L)/(0.0821 L atm/(mol K))(273.15 K)
n = 0.824 mol of N2 gas
The number of moles of NaN3 we need to produce 0.824 mol of N2 gas can be determined using the mole ratio in the balanced chemical equation.
2 moles of NaN3 produces 3 moles of N2.
So, 0.824 mol of N2 requires (2/3) x 0.824 mol of NaN3
n(NaN3) = (2/3) x 0.824 mol of NaN3n(NaN3) = 0.549 moles of NaN3.
Now, we can determine the mass of NaN3 required to produce 0.549 moles of NaN3 using its molar mass.
Mass = moles × molar mass.
Mass of NaN3 = 0.549 × 65 = 35.68 g.
Therefore, we need 35.68 grams of NaN3 to produce enough N2 gas to fill an airbag with a volume of 20.0 L upon complete decomposition.
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calculate the free energy change for this reaction at 25 °c. is the reaction spontaneous? (assume that all reactants and products are in their standard
Free energy change, denoted by ΔG, is a measure of the amount of work that a thermodynamic system can perform. It is calculated as the difference between the change in enthalpy (ΔH) and the product of the temperature (T) and the change in entropy (ΔS). ΔG° is negative, the reaction is spontaneous.
To calculate the free energy change for a reaction at a certain temperature, we use the equation ΔG = ΔH - TΔS, where ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.
Since we are assuming that all reactants and products are in their standard states, we can use the standard enthalpy of formation (ΔH°f) and standard entropy (ΔS°) values from tables.
Let's take an example reaction: A + B → C
Assuming the standard states for A, B, and C, and using the given values from tables, we can calculate the free energy change at 25°C as:
ΔG° = ΣnΔG°f(products) - ΣnΔG°f(reactants)
ΔG° = ΔG°f(C) - ΔG°f(A) - ΔG°f(B)
Let's say the values we get are:
ΔG°f(A) = 50 kJ/mol
ΔG°f(B) = 80 kJ/mol
ΔG°f(C) = 100 kJ/mol
Substituting these values into the equation, we get:
ΔG° = 100 - (50 + 80)
ΔG° = -30 kJ/mol
Since ΔG° is negative, the reaction is spontaneous. This means that the products (C) are more stable than the reactants (A and B) and the reaction will occur without any external intervention.
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To calculate the free energy change for a reaction, we use the equation ∆G = ∆H - T∆S, where ∆H is the change in enthalpy, T is the temperature in Kelvin, and ∆S is the change in entropy.
Assuming we have all reactants and products in their standard states, we can look up their standard enthalpies of formation (∆H°f) and standard entropies (∆S°) from a table.
Let's say we have the reaction A + B → C + D and the following values:
∆H°f(A) = -100 kJ/mol
∆H°f(B) = -50 kJ/mol
∆H°f(C) = 200 kJ/mol
∆H°f(D) = 0 kJ/mol
∆S°(A) = 50 J/mol*K
∆S°(B) = 100 J/mol*K
∆S°(C) = 150 J/mol*K
∆S°(D) = 75 J/mol*K
We can calculate the change in enthalpy (∆H) by subtracting the sum of the enthalpies of the reactants from the sum of the enthalpies of the products:
∆H = (∆H°f(C) + ∆H°f(D)) - (∆H°f(A) + ∆H°f(B))
∆H = (200 + 0) - (-100 - 50)
∆H = 350 kJ/mol
We can also calculate the change in entropy (∆S) by subtracting the sum of the entropies of the reactants from the sum of the entropies of the products:
∆S = (∆S°(C) + ∆S°(D)) - (∆S°(A) + ∆S°(B))
∆S = (150 + 75) - (50 + 100)
∆S = 75 J/mol*K
Now we can use the equation ∆G = ∆H - T∆S to calculate the free energy change (∆G) at 25 °C (298 K):
∆G = ∆H - T∆S
∆G = 350000 - 298 * 75
∆G = 129050 J/mol or 129.05 kJ/mol
If ∆G is negative, the reaction is spontaneous (i.e. it will occur without external input of energy). In this case, ∆G is negative, so the reaction is spontaneous.
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1. X is a crystalline salt.On exposure to air ,there is a loss in mass of x (a)suggest a phenomenon exhibited by x. (b)mention 2 salts that x could be. 2 a)Define salt hydrolysis b)mention 2 examples of salts that produce alkaline solutions when dissolve in water.
Answer:
1. a) Crystalline hydrated salt lose their mass or moisture on exposure to the air and change into amorphous salt, the phenomenon is called efflorescence.
b) Two salts that x could be are gypsum (Caso4.H2O) and copper (II) sulfate (CuSO4.H2O).
Gypsum (Caso4.H2O) form anhydrite(CaSO4), when exposed to air and copper (II) sulfate (CuSO4.H2O) form a white layer of anhydrous copper (II) Sulfate when expose to sir.
2. a) Salt hydrolysis is defined as the ions from salts react with water and form either basic or an acidic solution.
b) Two examples of salts that produce alkaline solutions when dissolving in water are sodium bicarbonate (NaHCO3) and Calcium Carbonate (CaCO3).
why doesn't calcium react with water in your body
explain pls
Answer:
Bones aren't made of calcium metal. Bones are a collegun structure filled in with mostly calcium carbonate and some calcium phosphate
Answer:
Bones aren't made of calcium metal. Bones are a collegun structure filled in with mostly calcium carbonate and some calcium phosphate
Explanation:
I hope this helps
Can anyone help me please
Answer:
Nucleic acids
Explanation:
all organic foods (fruit, meat, etc) contain it to some degree. because all organic foods have dna in them.
What initiates release of neurotransmitters into the synapse? O Depolarization opens Ca2* channels, allowing Ca2+ to move vesicles to the synaptic membrane. O Hyperpolarization opens K* channels, allowing K* to move vesicles to the synaptic membrane. O Depolarization opens Na* channels, allowing Na* to move vesicles to the synaptic membrane. O Depolarization opens K* channels, which opens fusion pores in the postsynaptic membrane. O Hyperpolization opens Ca2+ channels, which opens fusion pores in the postsynaptic membrane. 2 pts
The release of neurotransmitters into the synapse is initiated by depolarization, which opens Ca2+ channels, allowing Ca2+ to move vesicles to the synaptic membrane.
This is the correct answer.When an action potential (AP) arrives at the axon terminal, it results in the opening of voltage-gated Ca2+ channels. The influx of Ca2+ into the nerve terminal causes the exocytosis of neurotransmitter-containing vesicles into the synaptic cleft. Calcium influx is thought to trigger neurotransmitter release via a mechanism that involves Ca2+ binding to the vesicle-associated protein synaptotagmin 1 (Syt1), which promotes the interaction of vesicles with the presynaptic membrane.The entry of Ca2+ through voltage-gated calcium channels is critical for neurotransmitter release, and its absence leads to severe neurological disorders such as ataxia and epilepsy. Calcium ion (Ca2+) is one of the most crucial signaling molecules in cells and is essential for many physiological functions, including neurotransmitter release. Calcium ions activate synaptic vesicle fusion and neurotransmitter release by binding to specific proteins in the active zone of the nerve terminal.
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hat are the major products obtained upon treatment of ethyl methyl ether with excess HBr? Multiple Choice
1) Bromomethane and ethanol
2)Bromoethane and methanol
3)Bromoethane and bromomethane
4)Ethanol and methanat
Option 2) Bromoethane and methanol is correct
The major products obtained upon treatment of ethyl methyl ether with excess HBr are Bromoethane and methanol.
What is ethyl methyl ether?
Ethyl methyl ether is a colorless gas that is used as a solvent. The IUPAC name for this compound is methoxyethane. It is a member of the ether family of compounds. When ethyl methyl ether reacts with excess HBr, it undergoes a substitution reaction and forms Bromoethane and methanol. The mechanism for this reaction is given below: Methoxyethane reacts with hydrogen bromide to produce methanol and ethyl bromide (bromoethane). Here are the products that are formed in this reaction: Bromoethane (C2H5Br) and Methanol (CH3OH)
The chemical equation for this reaction can be written as: CH3OCH2CH3 + HBr → CH3OH + CH3CH2Br \(\boxed{Option\ 2)}\)
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what is the fluid used to make paper?
Answer:
MSDSs list Liquid Paper as containing titanium dioxide, solvent naphtha, mineral spirits, resins, dispersant, and fragrances. Liquid Paper came under scrutiny in the 1980s, due to concerns over recreational sniffing of the product. The organic solvent 1,1,1-trichloroethane was used as a thinner in the product.
Explanation:
You have a sample of a polymer based material that you are asked to characterize. Explain, briefly, how you would determine 1) if the polymer is in fact a thermoset, 2) how much filler is in it and 3) what the filler is, 4) what antioxidants and UV absorbents are present and in what quantity, 5) if there is dye or pigment coloring the material and whether or not it is the filler, and 6) how you would identify what thermoset it is. If you propose using an instrument or technique you need to specify what you will be measuring and how it will provide the required information.
A polymer-based material can be characterized using various techniques and instruments.
Here's how to determine whether the polymer is a thermoset, the amount of filler present in it, what the filler is, and the quantity of antioxidants and UV absorbents present:
1. To determine if the polymer is a thermoset, heat it. Thermosets don't melt, but thermoplastics do.
2. To determine the amount of filler in the polymer, weigh a sample of the polymer and then burn it. The residue will be the filler. Subtract the residue's mass from the polymer's initial weight to determine the filler's weight.
3. To determine what filler is present, observe the residue after burning.
4. UV absorbents can be detected using UV-Vis Spectroscopy, while antioxidants can be determined using FTIR Spectroscopy.
5. To determine if the material has dye or pigment coloring, use colorimetry to measure its color, then compare it to the reference color of the polymer. If the color is different, it has dye or pigment coloring.
6. The polymer's thermoset can be identified using Differential Scanning Calorimetry (DSC) to examine the melting temperature, which is unique to each thermoset.
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What geographic obstacle causes water to condense in an air mass as the air mass moves? Explain your answer.
A. Forests
B.oceans
C.prairies
D.mountains
Answer:
Mountains
Explanation:
Mountains are colder than the lower elevations. When humid air enters a cooler region, the saturated air begins to cool and this reduces the ability of the air to maintain the evaporated water is the gas state. Molecules of water have reduced enerfy at the cooler temperatures. They will slow down and coalesce with other water molecules to form small droplets of water. The atmoshere cannot hold these heaevier droplets and they begin to fall (i.e., rain).
One migh ask why does the air temperature drop at higher altitudes? Heat rises, so why shouldn't it be warmer on top a mountain, compared to the valley. The reason is that the atmosphere becomes less dense the further from Earth's center on gets. This less dense air has a lower water saturation point, so it rains.
answer truthfully:))
Answer:
Formula: \(Velocity \: V = f \lambda \\ Solution: = 5 \times 0.8 \\ = 4 \: {ms}^{ - 1} \)
Answer:
The first guy is correct. That's what I got too
:quilibrium:
1. Define equilibrium when the equation
Use the equation below to answer the following equilibrium questions:
H₂O (g) + CO (g) =H₂(g) + CO₂(g) + 42 KJ
2. In the reaction above, what could happen that causes the equilibrium to shift to the right?
3. In the reaction above, what could happen to cause the equilibrium to shift to the left?
4. If pressure was increased, what direction would equilibrium shift?
5. If heat was added, what direction would equilibrium shift. What would happen to the concen
6.
If CO was added, what direction would equilibrium shift. What would happen to the concent
chiometry:
the following equation to answer the questions that follow:
Equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. It is represented by a double arrow (⇌) in chemical equations. In the given equation: H₂O (g) + CO (g) ⇌ H₂(g) + CO₂(g) + 42 KJ
To shift the equilibrium to the right, one or more of the following could occur:
Increasing the concentration of H₂ or CO₂
Decreasing the concentration of H₂O or CO
Increasing the pressure
Removing some of the products (H₂ and CO₂)
Decreasing the temperature
To shift the equilibrium to the left, one or more of the following could occur:
Decreasing the concentration of H₂ or CO₂
Decreasing the pressure
Increasing the temperature
If pressure is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the right side of the equation (H₂ and CO₂), the equilibrium will shift to the right. If heat is added, the equilibrium will shift in the endothermic direction to absorb the additional heat. In this case, the forward reaction is endothermic (42 KJ on the right side), so the equilibrium will shift to the right to consume the added heat.
If CO is added, the equilibrium will shift to the right to consume the additional CO.The concentration of H₂O and CO₂ will increase, while the concentrations of H₂ and CO will decrease until a new equilibrium is reached.
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all organisms of the same species have the same traits true or false? explain
Answer: It would be true
Explanation: Individuals of the same species have the same inherited traits but different acquired traits, such as what they have learned and skills they have developed. Only these different acquired traits can cause differences in each individual's chances of survival and reproduction.
The organisms have a variation in their genes. Those orgasms that share the same common ancestors have similarities in their genetic code, same anatomy, and the same emanate features.
As the life on earth took place some 4.5 billion years ago and since which the many organisms that evolved may possess the same genetic makeup that lead them to their evolution. There still exists interspecific variation and some have differences due to the mode of adaptation. Hence the statement is false.Learn more about the organisms of the same species that have the same traits
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