Explain how the carbon and oxygen atoms from co2 molecules in the air become part of the cellulose molecules in plant cell walls.

Answer:

 a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

Answer: you should use the platform desmos to help you if you put in all the information it will give you the graph then you can just copy it on to your graph.

Explanation:

Answer:

Mass of lead = 89.7 g

Explanation:

Given data:

Volume of lead = 7.91 cm³

Density of lead = 11.34 g/cm³

Mass of lead =  ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

Now we will put the values in formula.

11.34 g/cm³ = m/7.91 cm³

m = 11.34 g/cm³ × 7.91 cm³

m = 89.7 g

The pressure in the vessel at 400 K with half the mass of CH3OH is 0.40 atm.

This problem can be solved using the ideal gas law, which states that the pressure (P), volume (V), and temperature (T) of a gas are related by:

PV = nRT

where n is the number of moles of gas, and R is the ideal gas constant.

Assuming the volume and amount of gas remain constant in the vessel, we can set the two instances of the ideal gas law equal to each other to solve for the final pressure:

P1V = n1RT1

P2V = n2RT2

where the subscript 1 refers to the original conditions, and subscript 2 refers to the new conditions with half the mass of CH3OH.

We can rearrange the equations to solve for the final pressure:

P2 = P1(n2T2)/(n1T1)

Since the amount of CH3OH has been halved, n2/n1 = 0.5. We can substitute the given values into the equation:

P2 = (0.30 atm)(0.5)(400 K)/(1)(300 K)

P2 = 0.40 atm

Therefore, the pressure in the vessel at 400 K with half the mass of CH3OH is 0.40 atm.

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Explanation:

The reaction between magnesium ribbon and dilute hydrochloric acid is a classic example of a single replacement reaction, which can be represented by the following chemical equation:

Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)

In this reaction, magnesium (Mg) reacts with hydrochloric acid (HCl) to form magnesium chloride (MgCl2) and hydrogen gas (H2).

The rate of this reaction can be altered by changing the concentration of the hydrochloric acid. This is because the rate of a chemical reaction depends on the concentration of the reactants. Specifically, the rate of the reaction is proportional to the concentration of the reactants raised to some power, which is determined by the reaction's rate law.

In this reaction, the rate law can be expressed as:

Rate = k [Mg] [HCl]^x

Where k is the rate constant and x is the order of the reaction with respect to hydrochloric acid. The order of the reaction with respect to magnesium is one, since the concentration of magnesium does not change during the reaction.

When the concentration of hydrochloric acid is increased, the rate of the reaction increases because there are more hydrochloric acid molecules available to collide with magnesium atoms and react. This means that the value of x is greater than zero and the reaction is dependent on the concentration of hydrochloric acid.

Conversely, when the concentration of hydrochloric acid is decreased, the rate of the reaction decreases because there are fewer hydrochloric acid molecules available to react with magnesium. This means that the value of x is less than one and the reaction is not entirely dependent on the concentration of hydrochloric acid.

Answer:

oxygen ?

Explanation:

not sure but I think so

Aerobic cellular respiration requires an adequate supply of oxygen. In the presence of oxygen, the cell completely oxidised the glucose molecule to form ATP.

In cellular respiration, the cell takes glucose and breaks it down to form energy. Cellular respiration is of two types: aerobic respiration and anaerobic respiration.

In aerobic respiration, the cell requires oxygen. Due to the presence of oxygen, the complete oxidation of glucose takes place. Glucose is converted into pyruvic acid and then enters the Krebs cycle and the electron transport chain to make ATP.

In the aerobic cellular respiration process, the maximum amount of ATP is derived. In anaerobic respiration, the cell performs respiration without the presence of oxygen. An example is glycolysis.

In this glycolysis process, the complete oxidation of glucose does not take place. In the absence of oxygen from pyruvate, lactic acid and ethanol are produced. This is called fermentation.

Hence, for aerobic cellular respiration, oxygen is required.

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Answer: a) Table Salt

good luck

We need to add 0.316 moles of KNO3 to 100g of water to form a saturated solution at 10°C.

To determine how many moles of KNO3 would have to be added to 100g of water to form a saturated solution at 10°C, we need to know the solubility of KNO3 at this temperature.

According to the solubility data, the solubility of KNO3 at 10°C is approximately 32 grams per 100 grams of water.

So, to make a saturated solution at 10°C, we need to add 32 grams of KNO3 to 100 grams of water.

Now, we can calculate the number of moles of KNO3 needed using its molar mass :

Molar mass of KNO3 = 101.1 g/mol

Number of moles of KNO3 = mass of KNO3 / molar mass of KNO3

Number of moles of KNO3 = 32 g / 101.1 g/mol

Number of moles of KNO3 = 0.316 moles

Therefore, we need to add 0.316 moles of KNO3 to 100g of water to form a saturated solution at 10°C.

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Answer:

Glycolysis

Explanation :

Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism.Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.

Answer:

Glycolysis is the first step in the breakdown of glucose to extract energy for cell metabolism. Many living organisms carry out glycolysis as part of their metabolism. Glycolysis takes place in the cytoplasm of most prokaryotic and all eukaryotic cells.

Oxygen is involved in the initial breakdown of glucose to pyruvic acid. Cellular respiration accomplishes two major processes: (1) it breaks glucose down into smaller molecules, and (2) it harvests the chemical energy released and stores it in ATP molecules.

Please give brainliest

Answer is D

Explanation:

Answer:

B. Neutral

Explanation:

When there is a ionic bond,  one element steals or takes away an electron from the other element.

An example is NaCl

In this compound, Chlorine atom steals an extra electron from Sodium to fill its outer shell. So, this is a Ionic bond. Since, the Sodium compound gives away an atom, it is positively charged. Since, Chlorine steals an atom, it is negatively charged. Opposite charges attract, so they become a compound.

When positive and negative mix, it becomes neutral.

The concentration of the Ca(OH)₂ stock solution is 0.00511 M.

The pH of an aqueous solution of Ca(OH)₂ can be calculated using the following equation,

pH = 14 - log([Ca(OH)₂])

where [Ca(OH)₂] is the concentration of Ca(OH)₂ in moles per liter (M).

Since the solution has a pH of 14.235, we can plug this value into the equation and solve for [Ca(OH)₂]:

14.235 = 14 - log([Ca(OH)₂])

log([Ca(OH)₂]) = 14 - 14.235 = -0.235

[Ca(OH)₂] = 10^(-0.235) = 0.00513 M

The Ca(OH)₂ stock solution was diluted to a final volume of 500.00 ml by adding 91.138 ml of the stock solution to a volumetric flask and filling up to the mark with water. Therefore, the number of moles of Ca(OH)₂ in the stock solution can be calculated as:

moles of Ca(OH)₂ = concentration × volume = [Ca(OH)₂] × (91.138/1000) = 0.000467 moles

The stock solution was diluted to a final volume of 500.00 ml, so the final concentration of the Ca(OH)₂ solution is:

final concentration = moles / volume = 0.000467 moles / 0.500 L = 0.000934 M

Therefore, the concentration of the Ca(OH)₂ stock solution is:

concentration = final concentration × (final volume / initial volume) = 0.000934 M × (500.00 ml / 91.138 ml) = 0.00511 M

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Yes, the resulting solution would be a buffer solution. This is because it contains both a weak acid (CH3COOH) and its conjugate base (CH3COO-) as well as a strong base (NaOH) and its conjugate acid (Na+).

In this case, the solution contains a weak acid, acetic acid (CH3COOH), and its conjugate base, acetate ion (CH3COO-), as well as a strong base, sodium hydroxide (NaOH), and its conjugate acid, sodium ion (Na+).

The weak acid, CH3COOH, can donate a proton (H+) to act as a pH buffer by neutralizing any added base. The conjugate base, CH3COO-, can accept a proton (H+) to act as a pH buffer by neutralizing any added acid. This helps maintain the pH of the solution relatively stable.

Similarly, the strong base, NaOH, can accept a proton (H+) to act as a pH buffer by neutralizing any added acid, while the conjugate acid, Na+, can donate a proton (H+) to act as a pH buffer by neutralizing any added base. The presence of both the weak acid and its conjugate base, as well as the strong base and its conjugate acid, creates a buffer system that can effectively resist changes in pH when small amounts of acid or base are added to the solution.

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Answer:

It's explained below.

Explanation:

An everyday situation is when we raise an object.

Now, when we raise an object, energy is transferred to the Earth object system and thus the gravitational field energy of the system will increase.

Now, this energy is usually released when the object falls. The mechanism of this release is known as gravitational force.

In the same manner, two magnetic and electrically charged objects that are interacting at a distance will exert forces on each other and this can lead to transfer of energy between the interacting objects.

ANSWER

The mass of Na2SO4 is 874g

EXPLANATION

Given that;

The number of moles of HCl is 12.3 mol

Follow the steps below to find the mass of sodium sulfate produced

Step 1; Write a balanced equation for the reaction

In the reaction above, 2 moles of NaCl react with 1 mole of H2SO4 to give 2 moles of HCl and 1 mole of Na2SO4

Let the number of moles of Na2SO4 be x

The number of moles of Na2SO4 is 6.15 moles

Step 3; Find the mass of Na2SO4 using the below formula

Recall, that the molar mass of Na2SO4 is 142.04 g/mol

Therefore, the mass of Na2SO4 is 874g

As an atom's size shrinks, its electronegativity rises. This is due to the fact that electronegativity and atomic size are inversely related. Because of this, the atomic size decreases as electronegativity rises.

The contact between the nucleus and the surrounding electrons is reduced as the atomic radius rises, which results in a decline in electronegativity.

When comparing HNO3 and HNO2, HNO3 is a stronger acid because it has more electronegative atoms (in this case, more oxygen atoms).
When comparing HCIO and HCIO2, HCIO2 is a stronger acid because it has more electronegative atoms (in this case, more oxygen atoms).
When comparing HCIO and HBrO, HCIO is a stronger acid because it has fewer electronegative atoms (in this case, fewer oxygen atoms).
When comparing CCI3COOH and CBr2COOH, CCI3COOH is a stronger acid because it has more electronegative atoms (in this case, more chlorine atoms).

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C. Liters liquid x 1000ml/1L x g/ml x mol/g xΔH fusion is equation in which the ΔH fusion used to calculate the energy released when a volume of liquid freezes.

We are using the symbol to represent the heat of fusion. We describe to a solid material melting when it converts into a liquid. To permit the solid-state particles to dissociate from one another during the melting process, there must be an increase in energy. Fusion heat is the basis of this energy.

Enthalpy indicates the amount of heat transferred during a chemical reaction at constant pressure, whereas heat is a form of energy. This is the symbolises between enthalpy and heat. Furthermore, heat is not an intrinsic property of a system, whereas enthalpy is a result of the state.

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The central atom in SO₂ is sp2 hybridized. In SO₂, the central atom is sulfur (S).

To determine the hybridization of the central atom, we need to examine the electron configuration and the number of electron domains around the central atom.

Sulfur has the electron configuration 1s² 2s² 2p⁶ 3s² 3p⁴. The valence shell of sulfur consists of three electron domains: two sigma bonds with oxygen atoms and one lone pair of electrons.

To accommodate the three electron domains, sulfur undergoes hybridization. The electron domains are mixed to form new hybrid orbitals that are directed towards the corners of a trigonal planar geometry.

Since there are three electron domains involved in the hybridization, the sulfur atom is sp2 hybridized. The three hybrid orbitals are formed by combining one s orbital and two p orbitals.

Overall, the sp2 hybridization of sulfur in SO₂ allows for the formation of three sigma bonds and results in a trigonal planar molecular geometry.

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Ernest Rutherford, a New Zealand physicist, conducted the gold foil experiment and discovered that the atom has a positively charged nucleus.

In 1911, he conducted an experiment in which he fired alpha particles at a thin sheet of gold foil. The majority of the particles went straight through the gold foil, but a small percentage of the particles bounced back. He discovered that the bouncing back was caused by a small, positively charged nucleus at the center of the atom. Rutherford's experiment was crucial to our understanding of the structure of the atom. Prior to his experiment, the prevailing model of the atom was that it was a solid, indivisible sphere.

However, Rutherford's experiment showed that the atom was mostly empty space, with a positively charged nucleus at its center. This discovery paved the way for future research into atomic structure and helped to lay the foundation for the development of nuclear physics.

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The pH after the addition of 29.5 mL of NaOH to a 0.242 M solution of formic acid is 3.52.  

The pH after the addition of 29.5 mL of NaOH to a 0.242 M solution of formic acid, we can use the following equation:

pH = -log[H+]

here [H+] is the concentration of hydronium ions (H3O+).

The concentration of hydronium ions can be calculated using the equation:

[H+] = [HCHO] x [NaOH] / [HCHO] + [NaOH]

here [HCHO] is the concentration of formic acid, [NaOH] is the concentration of NaOH, and [H+] is the concentration of hydronium ions.

Using the given concentrations and the equation for [H+], we can calculate the pH as follows:

pH = -log[H+]

= -log[HCHO] x [NaOH] / [HCHO] + [NaOH]

= -1.76 x 0.242 / 0.242 + 1.76 x 0.242

= -1.76 + 1.76

= 3.52

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Answer: P2O5 is the empirical formula.

Explanation: When given percentages you can assume that many grams of each atom are in the compound. Then you divide grams by the molar mass of each element, giving you moles. Once you have moles, divide by the smaller molar amount, which should give you 1 mol of Phosphorus and 2.5 mol of Oxygen. Then multiply by 2 in order for both moles to be a whole number. This gets you 2 and 5.

The number of moles in 5.12 × 10³ Fluorine(F) atoms is 8.45 × 10 ‐ ²³ moles.

The moles is defined as the measurement of the amount of any substance. Its is the measure of the amount of elementary particles in a substance. One mole is numerically equal to 6.023 × 10²³  which is called Avogadro's number.

From Periodic Table, we can find that Molecular Weight of Fluorine(F) is 19. We know the Molar Weight of any element is numerically equal to its Molecular Weight i.e. numerically, Molecular Weight = Molar Weight of any matter.

The number of moles in 5.12 × 10³ Fluorine(F) atoms will be calculated as: (5.12 × 10³) / (6.023 × 10²³) = 8.45 × 10 ‐ ²³ moles

So, there are approximately 8.45 x 10^-23 moles  in 5.12 × 10³ atoms of Fluorine.

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Answer:

solvent

Explanation:

Answer:

Physicians do not have to treat every ill patient. However they must uphold their ethics (eg. do no harm, confidentiatlity, etc.).

Explanation:

Primary source:

Hippocratic Oath (translation since it's originally in Greek)

I swear by Apollo the physician, and Asclepius, and Hygieia and Panacea and all the gods and goddesses as my witnesses, that, according to my ability and judgement, I will keep this Oath and this contract:

To hold him who taught me this art equally dear to me as my parents, to be a partner in life with him, and to fulfill his needs when required; to look upon his offspring as equals to my own siblings, and to teach them this art, if they shall wish to learn it, without fee or contract; and that by the set rules, lectures, and every other mode of instruction, I will impart a knowledge of the art to my own sons, and those of my teachers, and to students bound by this contract and having sworn this Oath to the law of medicine, but to no others.

I will use those dietary regimens which will benefit my patients according to my greatest ability and judgement, and I will do no harm or injustice to them.

I will not give a lethal drug to anyone if I am asked, nor will I advise such a plan; and similarly I will not give a woman a pessary to cause an abortion.

In purity and according to divine law will I carry out my life and my art.

I will not use the knife, even upon those suffering from stones, but I will leave this to those who are trained in this craft.

Into whatever homes I go, I will enter them for the benefit of the sick, avoiding any voluntary act of impropriety or corruption, including the seduction of women or men, whether they are free men or slaves.

Whatever I see or hear in the lives of my patients, whether in connection with my professional practice or not, which ought not to be spoken of outside, I will keep secret, as considering all such things to be private.

So long as I maintain this Oath faithfully and without corruption, may it be granted to me to partake of life fully and the practice of my art, gaining the respect of all men for all time. However, should I transgress this Oath and violate it, may the opposite be my fate.

Answer:

A, C, and E. I hope you have a good day.

Explanation:

Answer:

1, 3, and 5

Explanation:

The percentage of chloride in the unknown sample is approximately 15.93%.

To calculate the percentage of chloride in the unknown sample, you can use the mass of silver chloride obtained to determine the number of moles of chloride in the original sample, and then convert that to a percentage.

First, calculate the number of moles of silver chloride by dividing the mass by its molar mass:

0.7332 g / 143.32 g/mol = 0.00513 mol AgCl

Next, calculate the number of moles of chloride in the original sample by assuming a 1:1 ratio of chloride ions to silver ions in the reaction:

0.00513 mol AgCl * 1 Cl- / 1 Ag+ = 0.00513 mol Cl-

Finally, divide the number of moles of chloride by the mass of the original sample and multiply by 100 to convert to a percentage:

(0.00513 mol Cl- / 0.3221 g) * 100 = 15.93%

So, the percentage of chloride in the unknown sample is approximately 15.93%.

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The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Answer:

Physical changes.

Explanation:

Any physical changes can be related to boiling. Freezing water, tearing paper, anything physical that changes and objects apperance is a physical change.

The 6¹⁴ text(c) activity of an ancient artifact is found to be 0.170 bq per gram of carbon. 49,305 is its age of ancient artifact.

To find the age of the artifact, we can use the formula for exponential decay:
N(t) = N₀ e(-λt)
Where N0 is the initial amount of 6¹⁴ text(c), N(t) is the current amount, λ is the decay constant (which is related to the half-life), and t is the time elapsed.
We know that the half-life of 6¹⁴ text(c) is 5730 years. This means that after 5730 years, half of the initial amount of 6¹⁴ text(c) will have decayed. So, we can find λ as follows:
λ = ln(2) / t1/2
λ = ln(2) / 5730
λ = 0.000120968
Now, we can use the activity of the artifact to find the current amount of 6¹⁴ text(c):
A = λN
N = A / λ
N = 0.170 / 0.000120968
N = 1403.94
So, the artifact currently has 1403.94 grams of 6¹⁴ text(c). We can use this value and the known initial amount of 6¹⁴ text(c) (which would have been present in the organism when it died) to find the age of the artifact:
N(t) = N₀ e(-λt)
1403.94 = N₀e(-0.000120968t)
We can solve for t:
ln(1403.94/N0) = -0.000120968t
t = -ln(1403.94/N0) / 0.000120968
We don't know the exact initial amount of 6¹⁴ text(c) in the organism, but we can assume it was the same as the current amount in the atmosphere (which is about 1.2 × 10¹² grams). So:
t = -ln(1403.94/1.2e12) / 0.000120968
t = 49,305 years
Therefore, the artifact is approximately 49,305 years old.

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Matching the solutions with the appropriate letters, we have:

0.147 m CuSO4 - C

0.205 m Ni(NO₃)₂ - B

8.75 × 10⁻² m Cr(CH₃COO)₃ - D

0.380 m ethylene glycol - A

Based on the information provided, we need to match the given aqueous solutions with the appropriate letter from the column on the right. The options are:

A. Highest boiling point

B. Second highest boiling point

C. Third highest boiling point

D. Lowest boiling point

Let's analyze each solution and determine their boiling points:

0.147 m CuSO₄ (copper sulfate) - This is an ionic compound and will dissociate into Cu²⁺ and SO₄²⁻ ions in water. As an electrolyte, it will exhibit colligative properties, including an increase in boiling point. Therefore, this solution would have the third highest boiling point. So the match is C.

0.205 m Ni(NO₃)₂ (nickel nitrate) - Similar to the previous solution, this is also an ionic compound and will dissociate into Ni²⁺ and NO³⁻ ions in water. It will exhibit colligative properties, resulting in a higher boiling point. This solution would have the second highest boiling point. So the match is B.

8.75 × 10⁻² m Cr(CH₃COO)₃ (chromium(III) acetate) - This is also an ionic compound and will dissociate into Cr³⁺ and CH₃COO⁻ ions in water. Like the previous solutions, it will exhibit colligative properties, leading to an increase in boiling point. This solution would have the lowest boiling point. So the match is D.

0.380 m ethylene glycol - Ethylene glycol is a nonelectrolyte, and it does not dissociate into ions in water. Therefore, it does not exhibit colligative properties to the same extent as ionic compounds. However, it still has a significant effect on the boiling point due to its high boiling point itself. Ethylene glycol has the highest boiling point among the given options. So the match is A.

Matching the solutions with the appropriate letters, we have:

0.147 m CuSO₄ - C

0.205 m Ni(NO₃)₂ - B

8.75 × 10⁻² m Cr(CH₃COO)₃ - D

0.380 m ethylene glycol - A

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