Explain contribution of Mendleev for arrangement of elements in his periodic table

When a student accidentally adds 2.0g of Mg metal instead of Zn to react with 5.0g of \(CuSO_4\), the copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate reacted to form Cu. Therefore, option C is the correct answer

\(CuSO_4 + Mg \rightarrow Cu + MgSO_4\)

Copper (II) sulfate reacts with magnesium to form copper and magnesium sulfate, and the reaction is exothermic. As a result, the temperature of the solution increases.

When magnesium is added to a copper (II) sulfate solution, the magnesium displaces copper from copper (II) sulfate, forming magnesium sulfate and copper.

The addition of magnesium instead of zinc means that the copper (II) sulfate solution would react with magnesium rather than zinc. Magnesium has a lower reactivity than zinc, which means that it will displace copper from copper (II) sulfate instead of zinc.

However, not all the copper (II) sulfate will be reacted to form copper, since only a portion of the copper (II) sulfate is consumed by the reaction with magnesium.

Therefore correct option is c " the copper (II) sulfate solution would react with the Mg, because Cu is less active than Mg. However, not all the copper (II) sulfate was reacted to form Cu."

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Answer:

 The correct answer is option A, that is, HCl.  

An acid refers to an ion or molecule possessing the tendency of donating a hydrogen ion or a proton, or alternatively, exhibiting a tendency of producing a covalent bond with a pair of electrons. The aqueous Arrhenius acids exhibit characteristic features that offer a practical illustration of an acid.  

The acids can turn blue litmus paper red, can form aqueous solutions with a sour taste, and reacts with bases and some kind of metals to produce salts. One of the general aqueous acids is HCl (hydrochloric acid) that is found in the stomach and stimulates digestive enzymes.  

Explanation:

The correct answer is 0.25 mole of O2 as the number of particles in 0.25 mole of O₂ is equal to the number of particles in 0.249 moles of N₂.

Given, Number of nitrogen gas (N2) particles = 1.5 × 10²³ particles

To find: Same number of particles as a sample containing = ?

To find the same number of particles as in 1.5 × 10²³ particles of nitrogen gas, we need to convert the given number of particles into moles using Avogadro's number (6.022 × 10²³ particles/mol).

So,Number of moles of N₂ = number of particles of N₂ / Avogadro's number= 1.5 × 10²³ / 6.022 × 10²³ = 0.249 moles approximately

Now, let's calculate the number of particles present in each given option.

a) 2.0 moles of He

Number of particles of He = 2.0 moles × Avogadro's number

= 2.0 × 6.022 × 10²³

= 12.044 × 10²³

b) 0.25 mole of O2

Number of particles of O₂ = 0.25 moles × Avogadro's number

= 0.25 × 6.022 × 10²³

= 1.506 × 10²³

c) 1.0 mole of H2

Number of particles of H₂ = 1.0 moles × Avogadro's number= 1.0 × 6.022 × 10²³

= 6.022 × 10²³

d) 0.50 mole of NeNumber of particles of Ne = 0.50 moles × Avogadro's number= 0.50 × 6.022 × 10²³

= 3.011 × 10²³

Hence, the correct answer is 0.25 mole of O2 as the number of particles in 0.25 mole of O₂ is equal to the number of particles in 0.249 moles of N₂.

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Answer:

A and D

Explanation:

unsaturated hydrocarbons have double or triple bonds

A substance that changes in a chemical reaction and is represented by the reaction arrow on the left side of a chemical equation.

A substance formed in a chemical equation. and written on the right side of the reaction arrow in a chemical equation is referred to as a product. According to the law of conservation of matter, matter cannot be created or destroyed. The number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products in chemical equations. The atoms and molecules that interact in a chemical reaction are referred to as reactants. The atoms and molecules produced by a chemical reaction are referred to as products.

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Phương trình NaOH sai nha

As a defense attorney representing a company charged with exceeding the EPA limits on calcium perchlorate discharges, you would want to ask the chemist specific questions to challenge the validity of the test results and potentially have the charges dismissed. Here are three possible questions:

1. What were the quality control measures taken during the EDTA titration process to ensure accuracy and precision of the results?
This question aims to determine if proper procedures were followed during the analysis. The chemist should have taken appropriate measures such as calibration of equipment, replicates, and use of standards to ensure accurate results. Any shortcomings in quality control could cast doubt on the reliability of the test results. 2. Was there any possibility of sample contamination or interference during the collection, transportation, storage, or analysis of the water samples? This question seeks to understand if any external factors may have influenced the test results. The chemist should explain how they ensured that the samples were not contaminated or affected by other substances. Any indication of possible contamination or interference could weaken the case against your client. 3. Can you explain how the EPA determined the specific limit of 20 ppm for calcium perchlorate in groundwater, and provide scientific evidence supporting this limit? By asking this question, you are challenging the basis for the EPA's established limit. The chemist should be able to explain the rationale behind setting the limit at 20 ppm, including any relevant studies or scientific data. If the chemist cannot provide a satisfactory explanation, it may cast doubt on the validity of the limit itself and weaken the case against your client.

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Answer:

The answer is "13.25 cm"

Explanation:

When the lengths of being in an entity were also documented by either a cm-length ruler in 2 decimal positions. These measurements showed the decimal point, 13.25 cm possess 2 decimal roles, and 0 decimal places that is equal to 130 or 132 cm.  It is the right choice is therefore 13.25 cm, because it takes two decimals and this is more accurate.

Answer:1.5 cm

Explanation:edge2020

Answer

moles = 5.81 mol

Explanation

Given:

Volume = 144 L

AT SATP

1 mole = 24.4651 L

Solution:

1 mole = 24.4651 L

x mole = 144 L

x = 144/24.4651

x = 5.8 mol

The end of a very long 5-mm-diameter rod is held at 124°C. The surface of the rod is exposed to ambient air at 30°C, with a convective heat transfer coefficient of 100 W/m2K. Determine the temperature at a radial distance of 2.5 mm from the rod's center. The thermal conductivity of the rod is 15 W/mK.b) What is the temperature gradient in the rod at this location?c).

What is the heat flux at this location?The temperature at a radial distance of 2.5 mm from the rod's center is 79.58°C.The solution for this problem can be found by following the steps below:Solution:a) The temperature of the rod, T, can be calculated using the formula for one-dimensional conduction:q/A = -k (d T/d r)whereq is the heat flux,A is the cross-sectional area of the rod,r is the radial distance from the center of the rod,k is the thermal conductivity of the rod,and T is the temperature of the rod.

Taking the boundary condition into account,T(r=0) = 124°CandT(r=2.5 mm) = 30°C, the solution to the differential equation is:T = T0 + (T1 - T0) (r/R)2whereT0 = 30°CT1 = 124°CR = 2.5 mm/2 = 1.25 mmso,T = 30 + (124 - 30) (r/1.25)2 = 30 + 78 (r/1.25)2at r = 2.5 mm,T = 79.58°Cb) The temperature gradient, d T/d r, is given by the derivative of the above equation:d T/d r = 124 (r/1.25)2 / 1.25where d T/d r = 98.72°C/mat r = 2.5 mmc) The heat flux, q/A, is given by the Fourier's law of heat conduction:q/A = -k (d T/d r)whereq/A = -15 (98.72/1000) = -1.48 W/m2at r = 2.5 mmTherefore, the temperature at a radial distance of 2.5 mm from the rod's center is 79.58°C, the temperature gradient in the rod at this location is 98.72°C/m, and the heat flux at this location is -1.48 W/m2.

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A first-order reaction refers to a reaction in which the rate of the reaction is directly proportional to the concentration of a single reactant raised to the first power and is expressed as it would take approximately 46.4 minutes for the 80% completion of this first-order reaction to occur. 46.4 minutes.

Rate = k[A]

In this equation, k is the reaction rate constant, and [A] represents the concentration of reactant A.

The half-life of a reaction of the first order completes in 10 minutes. We need to find out how much time will be needed for the 80% completion of this reaction.

To solve for the time needed for 80% completion of a reaction of the first order, we need to use the formula:

Time for 80% completion = 2.303/k x log ([A]₀/[A]t)

where k is the reaction rate constant, [A]₀ is the initial concentration of the reactant and [A]t is the concentration of the reactant after the given time t, and 2.303 is a conversion factor.

Let [A]₀ = 1 and [A]t = 0.2 (since 80% completion means 20% of the original concentration remains)

We know that, t1/2 = 10 min;

therefore, k = 0.693/t1/2

= 0.693/10

= 0.0693 (as 0.693 = ln2)Now,

Time for 80% completion

= 2.303/k x log ([A]₀/[A]t)

= 2.303/0.0693 x log(1/0.2)

= 46.4 minutes

Therefore, it would take approximately 46.4 minutes for the 80% completion of this first-order reaction to occur. 46.4 minutes.

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The Omnipotent view of management refers to the belief that managers are directly responsible for an organization's success or failure. According to this view, managers have the power and control to make decisions that will significantly impact the organization's performance.

In terms of the organizational environment, ABC CO needs to focus on several aspects. Firstly, it should prioritize building strong relationships with customers by understanding their needs and delivering value through its products or services. Secondly, maintaining good relationships with suppliers is crucial to ensure a reliable supply chain and access to necessary resources. Thirdly, keeping a close eye on competitors is essential to stay competitive and identify opportunities for differentiation. Lastly, monitoring and adapting to economic, legal, and socio-cultural factors is vital to ensure compliance with regulations and aligning the organization with societal trends and expectations.

In conclusion, the Omnipotent view of management emphasizes the influence of managers in shaping organizational outcomes, while the Symbolic view recognizes the significance of external factors. For the current state of ABC CO, a balanced approach that considers both internal and external factors would be beneficial. The culture should promote collaboration, innovation, and adaptability, while the organization should focus on building strong relationships with customers, suppliers, and competitors while adapting to the economic, legal, and socio-cultural environment.

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Answer:

I think it is A

Explanation:

A.They study how to make plants produce certain chemicals

The question is incomplete, the complete question is:

Standardization of a Borax solution (Na2B4O7). A student titrates a 20.00 mL sample of an aqueous borax solution with 1.044 M H2SO4. It takes 2.63 mL of acid to reach the equivalence point. Knowing it takes 1 H2SO4 to neutralize 2 Na2B4O7, what was the concentration of this Borax solution?

Answer: The concentration of borax solution is 0.069 M.

Explanation:

To calculate the concentration of borax solution, the formula used is:

\(n_1C_1V_1=n_2C_2V_2\) ....(1)

where,

\(n_1, C_1\text{ and }V_1\) are the n-factor, concentration and volume of sulfuric acid

\(n_2,C_2\text{ and }V_2\) are the n-factor, concentration and volume of borax solution.

We are given:

\(n_1=1\\C_1=1.044M\\V_1=2.63mL\\n_2=2\\C_2=?M\\V_2=20mL\)

Putting values in equation 1, we get:

\(1\times 1.044\times 2.63=2\times C_2\times 20\\\\C_2=\frac{1\times 1.044\times 2.63}{2\times 20}\\\\C_2=0.069M\)

Hence, the concentration of borax solution is 0.069 M.

The species would be an anuran (an amphibian)

We need to answer this in English.

Here we want to find "A species that mates on the surface and then deposits its eggs in the water to be surrounded by sperm"

This would be known as a species of amphibian called an anuran, specifically a frog or toad.

Frogs and toads belong to the order Anura and have a characteristic reproductive cycle that involves external fertilization. During reproduction, the male releases his sperm into the water, and the female deposits her eggs in the water as well. The eggs are externally fertilized by sperm that swim around them. This process is known as external or external fertilization.

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Answer

4Al + 3O2 ------> 2Al₂O₃

4 moles of Al₂O₃ will be produced

Explanation

Given:

Moles of A = 8 moles

The given unbalanced equation is: __Al + __O2 --> __Al2O3

Solution:

The balanced equation for the reaction is:

4Al + 3O2 ------> 2Al₂O₃

From the balanced equation, 4 moles of Al produced 2 moles Al₂O₃

Therefore, 8 moles of Al will produce

4 moles of Al₂O₃ will be produced.

High-energy matter consisting of positively and negatively charged particles is Plasma.

Plasma is high - energy matter consist of positively particles and negatively charged particles. This is the most common state of matter that is plasma state. Matter consisting negatively charged particles and positively charged particles and overall charge is neutral . Particles have high energy that when collide, electrons knocked loose from atom and forming positive ion and negative ion. particles are moving very fast in plasma state. Examples of plasma are stars, neon tubes , lightening bolts, fluorescent lights, fire.

Thus,   High-energy matter consisting of positively and negatively charged particles is Plasma.

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High-quality scientific research is characterized by several key criteria. Three examples of such criteria include: rigorous experimental design and methodology, reliable data analysis and interpretation, and clear and transparent reporting of results.

These criteria ensure that research is conducted in a systematic and reliable manner, leading to trustworthy and valid findings.

Rigorous Experimental Design and Methodology: High-quality scientific research requires a well-designed experimental approach. This involves careful planning, proper control groups, randomization, and replication. A rigorous methodology ensures that experiments are conducted under controlled conditions, minimizing bias and confounding variables, and allowing for accurate and reliable data collection.

Reliable Data Analysis and Interpretation: After data collection, high-quality research involves thorough and appropriate analysis of the data. This includes using appropriate statistical methods to evaluate the significance of the results and drawing valid conclusions. Proper data analysis helps researchers identify patterns, trends, and relationships, supporting or refuting their hypotheses in an objective and reliable manner.

Clear and Transparent Reporting of Results: High-quality research demands transparent reporting of the methods, procedures, and findings. This includes providing detailed descriptions of the experimental setup, data collection processes, and statistical analyses used. Clear reporting allows other researchers to replicate the study and verify its results. Additionally, complete reporting ensures that readers can understand the research methodology and draw their own conclusions based on the evidence presented.

By adhering to these criteria, high-quality scientific research maintains integrity, credibility, and reproducibility. It fosters trust among the scientific community and facilitates the advancement of knowledge by building upon reliable foundations.

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To express lnA1, lnA2, and lnA3 in terms of lnA0, εA,1, εA,2, and εA,3, we can use the given equations: From the equation At = A + gt + At, we can rewrite it as At - gt = A + At. Taking the natural logarithm (ln) of both sides, we have ln(At - gt) = ln(A + At).

Similarly, from the equation At = rhoAA~t−1 + ϵA,t,−1, we can rewrite it as At - rhoAA~t−1 = ϵA,t,−1. Taking the natural logarithm (ln) of both sides, we have ln(At - rhoAA~t−1) = ln(ϵA,t,−1). Now, let's express lnA1, lnA2, and lnA3 in terms of ln A0, εA,1, εA,2, and εA,3. Expressing lnA1:  

- From equation 1, we have ln(A1 - g1t) = ln(A0 + A1).

Rearranging the equation, we get ln(A1 - g1t) - ln(A1) = ln(A0).
- From equation 2, we have ln(A1 - rhoAA~1−1) = ln(εA,1).

Rearranging the equation, we get ln(A1 - rhoAA~1−1) - ln(A1) = ln(εA,1).

Therefore, lnA1 = ln(A0) + ln(εA,1).

Calculating the expected values of lnA1, lnA2, and lnA3: - Taking the expected value (E) of equation 1, we have E[ln(A1 - g1t)] = E[ln(A0 + A1)]. Since g1t is constant, we can write it as E[ln(A1)] - g1t = ln(A0 + E[A1]).

Rearranging the equation, we get E[ln(A1)] = ln(A0 + E[A1]) + g1t.

- Taking the expected value (E) of equation 2, we have E[ln(A1 - rhoAA~1−1)] = E[ln(εA,1)].  Since rhoAA~1−1 is constant, we can write it as E[ln(A1)] - rhoAE[A~1−1] = ln(εA,1).

Rearranging the equation, we get E[ln(A1)] = ln(εA,1) + rhoAE[A~1−1].

Therefore, the expected value of lnA1 is given by E[lnA1] = ln(A0 + E[A1]) + g1t = ln(εA,1) + rhoAE[A~1−1]. Similarly, we can calculate the expected values of lnA2 and lnA3 using the corresponding equations and constants.
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Answer:

file link http/www.openfree

In this case, the primary structure forms hydrogen bonds to fold itself.

The answer is primary structure.

Answer:

[OH⁻] = 8.91x10⁻¹²M

Explanation:

In aqueous solutions, the [OH] and [H⁺] are associated in the equation of hydrolisis of water:

1x10⁻¹⁴ = [OH⁻] [H⁺]

With pH, we can solve for [H⁺] and obtain, the [OH⁻] using this equation:

pH = -log [H⁺]

[H⁺]= 10^-pH

[H⁺] = 1.122x10⁻³M

1x10⁻¹⁴ = [OH⁻] [1.122x10⁻³M]

Electrical energy is changed into mechanical energy which takes place when the cook uses the blender. So, the correct option is B.

Electrical energy is defined as the energy related to the forces on electrically-charged particles and the motion of those particles whose energy is supplied by a combination of current and electric potential that is delivered by a circuit.

Electrical energy is present all around us in many different forms, where some of the best examples of electrical energy are using car battery electrical energy in electrical systems, wall outlet to transfer electrical energy to charge our phones, and our muscles that uses electrical energy to contract and relax. Electrical energy is changed into mechanical energy which takes place when the cook uses the blender.

Therefore, the correct option is B.

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Answer:

Ankara is the capital of Turkey! Hope this helped you out! :)

Explanation:

The capital of Turkey is Ankara

hopefully this helped :3

Answer:

0.0286M

Explanation:

Using the formula as follows:

CaVa = CbVb

Where;

Ca = concentration of HCl acid (M)

Cb = concentration of NaOH base (M)

Va = volume of HCl acid (mL)

Vb = volume of NaOH base (mL)

According to the information provided in this question;

Ca = 0.10 M

Cb = ?

Va = 10mL

Vb = 35mL

Using CaVa = CbVb

Cb = CaVa/Vb

Cb = (0.10 × 10) ÷ 35

Cb = 1 ÷ 35

Cb = 0.0286M

The benefit of genetically engineering corn to produce its own Bt toxin is that it can protect the plant from insects without the need for additional insecticide application, reducing the environmental impact and cost of farming.

Genetic engineers use a bacterium called Bacillus thuringiensis (Bt) to transfer the Bt toxin gene into the corn plant, typically through a process called Agrobacterium-mediated transformation or gene gun bombardment.

Bt toxin is a protein produced by the bacterium Bacillus thuringiensis that is toxic to many insect pests. By engineering corn to produce its own Bt toxin, the plant becomes resistant to certain insects, reducing the need for farmers to apply insecticides, which can have negative environmental impacts and add cost to farming.

To insert the Bt toxin gene into the corn plant, genetic engineers typically use a bacterium called Agrobacterium tumefaciens, which naturally transfers DNA between itself and plants. The Bt toxin gene is inserted into the bacterium, which then infects the corn plant and transfers the gene into the plant's DNA.

Alternatively, genetic engineers can use a gene gun to bombard the corn plant with microscopic gold or tungsten particles coated with the Bt toxin gene. The gene is then incorporated into the plant's DNA through a process called homologous recombination. Both methods have been used successfully to create Bt corn.

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The 4-methyl pentane-2-ol (\(C_6H_{14}O\)) is an alcohol compound with a methyl group attached to the fourth carbon atom and a hydroxyl group attached to the second carbon atom in a five-carbon chain.

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