Examine the sample orp output below. At what approximate added volume of titrant does the equivalence point occur? enter your answer numerically.

Answer:

HClO3 > HBrO3 > HIO3

Explanation:

let's have a quick look at the terminology used in question,

Acidic strength- It is the ability of any molecule to donate H+ ion

Oxyacids- Acids that contain atleast one hydroxy (-OH) group

in the given oxyacids of Halogens, Chlorine is more electronegative than bromine and iodine.

So it will bind the proton (H+ ion) to it more tightly than other halogens hence the Acidic strength of HClO3 is highest among the following.

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Answer:

220.9g of water are required

Explanation:

The molar enthalpy of vaporization is defined as the heat released when 1 mole of water changes from liquid to gas.

For water, 1 mole releases 40.79kJ. To release 500kJ are necessaries:

500kJ * (1mol / 40.79kJ) = 12.26 moles are necessaries

To convert moles to grams we must use the molar mass (H2O = 18.02g/mol):

12.26 moles * (18.02g / 1 mol) =

Answer:

So if you divide the kg of butter and the cake that will be your answer and then you should have a fraction so the fraction would be 0.25 over 2 because you simplified it. 0.25/2

Explanation:

Answer:

\(\huge\boxed{\sf KCl_{(aq)}+Na_{(aq)} \longrightarrow K_{(l)}+NaCl_{(aq)}}\)

Explanation:

Chemical formulas for every compound:

Potassium vapor => \(K_{(l)\)

Molten soldium chloride => \(NaCl_{(aq)}\)

Molten Potassium chloride => \(KCl_{(aq)}\)

Molten Sodium Metal => \(Na_{(aq)}\)

The reaction will be as follows:

\(KCl_{(aq)}+Na_{(aq)} \longrightarrow K_{(l)}+NaCl_{(aq)}\)

This reaction is usually called displacement reaction in which an element displaces another element of a compund.

\(\rule[225]{225}{2}\)

After considering the given the data we conclude that the  ionization energy generally increases from left to right across a period. Therefore, the element with the highest ionization energy in period 3 would be located on the right side of the periodic table.

We can also see from the search results that helium has the highest ionization energy of all the elements, while sodium has the lowest ionization energy in period 3. Therefore, we can conclude that the element with the highest ionization energy in period 3 is located to the right of sodium.
Based on the periodic table, we can see that the elements in period 3 are:
Sodium (Na)
Magnesium (Mg)
Aluminum (Al)
Silicon (Si)
Phosphorus (P)
Sulfur (S)
Chlorine (Cl)
Argon (Ar)
Therefore, the element with the highest ionization energy in period 3 is most likely Argon (Ar), which is located on the far right side of the period.
In summary, the element with the highest ionization energy in period 3 is most likely Argon (Ar).
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Answer:

Hey!

Multiply the % × amu

Answer:

Enthalpy is a property of a thermodynamic system, defined as the sum of the system's internal energy and the product of its pressure and volume, H = U + pV

Explanation:

From the calculation, there is still more than 75 percent on the earth now (option D).

The term half life is the time taken for half of the number of radioactive isotopes to remain.

Given that;

N/No = (1/2)^t/t1/2

N = amount at time t

No = amount at the beginning

t = time taken

t1/2 = half life

Hence;

N/No = (0.5)^4.6 * 10^9/50 * 10^9

N/No = 0.94

Hence, the percentage that is currently in the earth is about 94%.

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Answer:

Diversity?

Explanation:

Think thats bio

Answer: F

Explanation:

Answer:

30 neutrons

Explanation:

neutrons = atomic mass - atomic number

neutrons = 56 - 26 = 30

The number atoms of carbon are there in 1.00 mol of carbon is the 6.023 × 10²³ atoms.

Given that :

The number of the moles of the atoms = 1 mole

The value of the 1 mole of the substance is equals to the 6.023 × 10²³ atoms.

The Avogadro's number = 6.023 × 10²³

The Avogadro's number is equals to the number of the atoms in the 1 mole.

Therefore, the number of the atoms in 1 mole = 6.023 × 10²³  atoms.

Thus, the Number of the atoms of the carbon in the 1 mole of the carbon is 6.023 × 10²³  atoms.

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Answer:

The area is important for climate science research because they can look at the glaciers and see over the years what is happening with them, are they multiplying or are they decreasing and if so at what rate.

Answer:

Melting glaciers are causing sea levels to rise. It’s important to study natural conditions in the Northern Patagonian Ice Field because the landscape there is dynamic and the effects of climate change can easily be seen. The retreat of the Nef Glacier and the disappearance of icebergs on the lake are evidence of rising temperatures and climate change.

Explanation:

Answer:

Bean Plant

Explanation:

This is because a bean plant produces it's own food.

Answer:

The answer would be C. Flowing water is where you get energy from hydroelectric dams.

Molarity of the solution = 0.08 M

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\(\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}\)

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

0.5 lb=226,796 g

MW silver nitrat - AgNO₃ = 169,87 g/mol

mol AgNO₃ :

\(\tt mol=\dfrac{mass}{MW}=\dfrac{226.796}{169.87}=1.335\)

Molarity :

\(\tt M=\dfrac{1.335}{16.75}=0.08\)

Answer:

hi erza are u online. okkklll

Group 2 carbonates become more thermally stable as you descend the group because the size of the metal cation increases, leading to a decrease in the lattice energy and an increase in the polarizability of the carbonate ion.

As you descend Group 2 of the periodic table, the size of the metal cation increases. This increase in size leads to a decrease in the lattice energy of the carbonate, as the larger cation is less effective in attracting and holding onto the carbonate ion. At the same time, the carbonate ion becomes more polarizable, meaning that it is better able to distort its electron cloud in response to the electric field of the metal cation. This combination of factors leads to an increase in the stability of the carbonate as you move down the group. As a result, the carbonates of the heavier Group 2 elements, such as barium carbonate, are more thermally stable than those of the lighter elements, such as magnesium carbonate.

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The number of sigma and pi bonds in propene is a total of 8 and 1 respectively.

A step-by-step explanation is given below:
1. Propene has the chemical formula C3H6.
2. There are three carbon atoms and six hydrogen atoms.
3. Each carbon-hydrogen bond is a sigma bond, totaling 6 sigma bonds.
4. There is a single bond between the first two carbon atoms, which is a sigma bond, adding 1 sigma bond to the total.
5. The double bond between the second and third carbon atoms consists of one sigma bond and one pi bond.

So, It concludes that in propene, there are 8 sigma bonds and 1 pi bond.

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Answer:

box A

Explanation:

10 is bigger than 3 since 10 is bigger it has more force in it

Melting points of enantiomers will not compare to each other as they have same M.P. and Diastereoisomers are compared on the basis of melting point.

Stereoisomers are those isomers which are having the same molecular formula but different spatial arrangemet of atoms within the molecule.

Hence, only diastereoisomers are compared on the basis of melting point.

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Answer:

The phenomenon that works here is called Total internal reflection

Explanation:

When the angle of incidence is increased past the critical angle, the refracted angle will not exit the medium and all incident light will reflect back off a boundary back into the first medium.

This phenomenon is called Total Internal Reflection. Total Internal Reflection will only occur with a large angle of incidence that is greater than the critical angle.

Now, when we talk about the second medium  

using the Law of refraction

Sini/Sinr =refractive index of medium 2/ refractive index of medium1

when the light ray passes from denser medium to rarer medium TIR happens along with angle of incident should be greater than critical angle. In this case incident angle is 45 degrees

conclusion: medium 2 is rarer here than medium 1

Answer:

87.33 kPa (2 d.p.)

Explanation:

To solve this problem, use the combined gas law.

\(\boxed{\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}}\)

where:

As we want to find the final pressure, rearrange the formula to isolate P₂:

\(\sf P_2=\dfrac{P_1V_1T_2}{T_1V_2}\)

As the temperatures have been given in Celsius, we need to first convert the temperatures from Celsius to kelvin by adding 273.15:

\(\implies \sf T_1=48+273.15=321.15\;K\)

\(\implies \sf T_2=64+273.15=337.15\;K\)

The given values are:

Substitute the values into the formula and solve for P₂:

\(\implies \sf \sf P_2=\dfrac{108 \cdot 0.952 \cdot 337.15}{321.15 \cdot 1.236}\)

\(\implies \sf \sf P_2=\dfrac{34664.414}{396.9414}\)

\(\implies \sf P_2=87.3287946...\)

\(\implies \sf P_2=87.33\;kPa\;(2\;d.p.)\)

Therefore, the final pressure of the gas is 87.33 kPa (2 d.p.).

True , A catalyst is a substance that quickens a chemical reaction; therefore, in homogeneous catalysis, the catalyst and reactants are in the same phase. Most of the time, everything will exist as a gas or be contained within a single liquid phase.

The difference between heterogeneous and homogeneous catalysts is that the former are in the same phase as the latter are not.

A single phase is what is meant by the notion of a pure substance or homogenous mixture. There are two or more phases in a heterogeneous mixture. Water and oil do not mix uniformly when combined; instead, two distinct layers are created.

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Answer: approximately 18.75 mL of 3.0 M HNO₂ solution can be completely neutralized by 75 mL of 1.5 M Mg(OH)₂ solution.

Explanation:

To determine the volume of 3.0 M HNO₂ solution that can be neutralized by 75 mL of 1.5 M Mg(OH)₂ solution, we can set up an equation based on the stoichiometry of the balanced chemical equation.

The balanced chemical equation for the neutralization reaction between HNO₂ and Mg(OH)₂ is:

2 HNO₂ + Mg(OH)₂ → Mg(NO₂)₂ + 2 H₂O

From the equation, we can see that it takes two moles of HNO₂ to react with one mole of Mg(OH)₂.

First, let's calculate the number of moles of Mg(OH)₂ present in 75 mL of 1.5 M solution:

Number of moles of Mg(OH)₂ = Volume (in L) × Concentration (in mol/L)

= 75 mL × (1 L / 1000 mL) × 1.5 mol/L

= 0.1125 mol

Since the stoichiometry ratio is 2:1 (HNO₂:Mg(OH)₂), we can conclude that 0.1125 moles of Mg(OH)₂ can neutralize 0.1125/2 = 0.05625 moles of HNO₂.

Now, let's determine the volume of 3.0 M HNO₂ required to contain 0.05625 moles:

Volume (in L) = Number of moles / Concentration (in mol/L)

= 0.05625 mol / 3.0 mol/L

≈ 0.01875 L

Finally, we convert the volume from liters to milliliters:

Volume (in mL) = Volume (in L) × 1000

≈ 0.01875 L × 1000

≈ 18.75 mL

Answer:

Strong

Explanation:

You're holding it over a fire

so it's a strong force

Answer:

1.64 moles O₂

Explanation:

Part A:

Remember 1 mole of particles = 6.02 x 10²³ particles

So, the question becomes, how many  '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?

This implies a division of given number of particles by 6.02 x 10²³ particles/mole.

∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂

_______________

Part B needs an equation (usually a combustion of a hydrocarbon).

Answer:

Explanation:

1. Virus's are hard to detect because of their simple construction.

2. Some mutate very easily.

3. It is hard to isolate the virus and kill it without doing damage to the host.

The first-order rate constant for this deactivation is 0.052 min⁻¹ .Using  the equation for first-order kinetics:
\(ln(A_{}/A) = kt\) .Where A₀ is the initial concentration, A is the concentration at time t, k is the first-order rate constant, and t is time.

We can convert these percentages into decimal fractions by dividing them by 100.
Using the given data, we can calculate the values \(ln(A_{0}/A)\)of  for different time intervals:
\(ln(1.00/0.90) = 0.105\)
\(ln(1.50/0.968) = 0.422\)
\(ln(2.00/0.990) = 0.203\)
\(ln(2.50/0.997) = 0.00993\)
\(ln(3.00/0.999) = 0.00100\)
Now, we can plot ln(A₀/A) vs. time (t) and get a straight line with a slope equal to -k, the first-order rate constant. The slope of the line can be calculated using any two points on the line:
\(slope =(ln(A_{0}/A_{2}) - ln(A_{0}/A_{1}))/(t_{2} - t_{1})\)
Using the values for ln(A₀/A) and time from the given data, we get:
\(slope =(0.00100 - 0.105)/(3.00 - 1.00) = -0.052\)
Therefore, the first-order rate constant (k) for this deactivation is:
k = 0.052 min⁻¹ (rounded to three significant figures)

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Answer:

See explanation

Explanation:

Even though the options were not stated in the question, it is clear that the prediction required must reflect the stated fact that the sublimation temperature of CO2 is -78.5°C. This is the fact that was observed in the cause of the experiment. Hence any of the options that reflects this statement must be the correct option among the list of options available in the question.