Evaluate (x +y)0 for x= -3 and y=5.
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01

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Answer:

Faster

Explanation:

Answer:

The correct answer is D) 63% of the maximum current.

Explanation:

The time constant (represented by the symbol τ) for an RC or RL circuit is defined as the time it takes for the current (or voltage) to reach approximately 63% of its maximum value. This is based on the exponential charging or discharging behavior of capacitors and inductors in these circuits.

Therefore, in the given series circuit with a resistor and an inductor, the time constant represents the time required for the current to reach 63% of the maximum current.

63% of the maximum current is the answer of this question.

In a series circuit consisting of a resistor and an inductor connected to a battery, the time constant (denoted by the symbol τ) represents the time required for the current to reach a certain percentage of its maximum value.

The time constant (τ) is given by the equation:

τ = L / R

where L is the inductance of the inductor in henries (H) and R is the resistance of the resistor in ohms (Ω).

The time constant represents the time it takes for the current to reach approximately 63% (1 - 1/e ≈ 0.63) of its maximum value in an RL circuit.

Therefore, the correct answer is:

D) 63% of the maximum current.

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Answer:

1. 4

2.0.625HZ

3.500

4. 428274940000000 or 4.2*10^14

5. 2

Explanation:

omnicalculator.com/physics/wavelength

Answer:

Explanation:

Pneumatic and hydraulic systems have many similarities. Both pneumatics and hydraulics are applications of fluid power. They each use a pump as an actuator, are controlled by valves, and use fluids to transmit mechanical energy.

Answer.:

Explanation:

The image is either virtual or real and the height of the image is 10cm.

To find the image type and its height, we need to know about the magnification of convex lens.

          Height of image/height of object or image distance(V) / object distance(U)

So, image height = magnification × object height

                            = 2×5 = 10 cm

Thus, we can conclude that the image is virtual if it's formed on the left of the lens and is real if it's formed on the right of the lens. The height of the image is 10 cm.

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Answer:

B.MINERALS HAVE CRSTAL

Charge q1=1.00 nC is at x1 = 0 and charge q2 = 3.00 nC is at x2 = 2.00 m. At a point 1.00 m away from charge q1, the electric field will be equal to zero.

This can be determined by calculating the electric field at this point, which is given by:E = (1/4πεo) x (q1/x2 - q2/x2), where εo is the electric permittivity of free space and x is the distance from charge q1.
At x = 1.00 m, E = 0.

An electric field is defined as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, which is either attracting or repelling them. It is also refers as the physical field for a system of charged particles.

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Answer:

B

Explanation:

The radiation has the lowest frequency is a.fm radio waves.

Radiation is energy that comes from a source and travels through space and can penetrate different materials. Light, radio, and microwaves are types of radiation  called non-ionizing. The  radiation discussed in this article is called ionizing radiation because it can create charged particles (ions) in matter.

ionizing radiation is produced by unstable atoms. Unstable atoms differ from stable atoms because unstable atoms have excess energy or mass or both. Radiation can also be produced by high-voltage equipment (eg X-ray equipment).

Atoms with unstable nuclei are said to be radioactive. To achieve stability, these atoms give up or emit excess energy or mass. These emissions are called radiation.

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Answer:

Questions occur until only one true or yes answer.

Explanation:

A decision tree is a visual representation of a decision-making process that involves a series of questions or decisions that lead to a final outcome or decision. Each question or decision in the tree has two or more possible answers, and each answer leads to a different branch or path in the tree. The questions are designed to be answered with either a true or yes answer, which eventually leads to the final decision or outcome. Therefore, the correct option is 4.

Energy is defined in science as the ability to move matter or change matter in some other way.

Minimum angle: θ ≈ 23.2 degrees | Rock's speed: v ≈ 2.65 m/s

To determine the minimum angle the string can make with the horizontal, we can analyze the forces acting on the rock when it is whirled in a horizontal circle.

Minimum angle:

The tension in the string provides the centripetal force required to keep the rock moving in a circle. The maximum tension the string can withstand before breaking is given as 150 N. At the minimum angle, the tension in the string will be equal to the breaking strength.

The centripetal force is given by the equation: \(F = m * (v^2 / r),\)where F is the force, m is the mass, v is the velocity, and r is the radius of the circle.

At the minimum angle, the tension (F) in the string is equal to the breaking strength, which is 150 N. The mass (m) of the rock is given as 970 g (0.97 kg), and the radius (r) is 1.8 in (0.04572 m). We can solve for the velocity (v).

\(150 N = 0.97 kg * (v^2 / 0.04572 m)v^2 = (150 N * 0.04572 m) / 0.97 kgv^2 = 7.0456 m^2/s^2v = √(7.0456) m/sv ≈ 2.65 m/s\)

Now, we can use trigonometry to find the minimum angle. The tension (150 N) is the vertical component of the tension force, and the horizontal component can be calculated using the angle θ:

Tension (horizontal component) = Tension (vertical component) / tan(θ)

Tension (horizontal component) = 150 N / tan(θ)

Since the tension in the horizontal direction is equal to the centripetal force, we can substitute the centripetal force equation:

\(m * (v^2 / r) = 150 N / tan(θ)\)

Now we can solve for the minimum angle (θ):

\(tan(θ) = (m * v^2) / (r * 150 N)θ = arctan((m * v^2) / (r * 150 N))\)

Substituting the given values, we can calculate the minimum angle.

Rock's speed at the minimum angle:

At the minimum angle, the rock's speed can be calculated using the previously derived velocity value (v).

The rock's speed at the minimum angle is approximately 2.65 m/s.

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Answer:

how much?

Explanation:

A diffraction grating with 750 slits per mm is illuminated by light, resulting in a first-order diffraction angle of 34.0°.

To solve this problem, we can use the formula for the angle of diffraction given by the equation: sin(θ) = mλ/d, where θ is the angle of diffraction, m is the order of the diffraction (in this case, first-order), λ is the wavelength of light, and d is the spacing between the slits on the diffraction grating.

In this case, we are given the first-order diffraction angle (θ = 34.0°) and the spacing between the slits (d = 1/750 mm = \(1.33\) ×\(10^{-3}\) mm. We need to find the wavelength of the light (λ).

Rearranging the formula, we have: λ = d * sin(θ) / m.

Plugging in the values, we get: λ =\((1.33\)  ×\(10x^{(-3)} mm\) ) *\(\frac{sin(34.4)}{1}\)

Calculating this expression, we find the wavelength of the light to be approximately \(3.46\) ×\(10^{-5}\) mm or 34.6 nm.

Therefore, the wavelength of the light illuminating the diffraction grating is approximately 34.6 nm.

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The cleanliness of the buret following pre-treatment was pristine. The density of water at 29∘C is 0.99595.

To find the volume of water in the buret, weigh the buret and record the mass (measured in grams). Fill the buret with water up to a specific volume, and record the mass (in grams) and volume (in mL) again. Subtract the mass of the empty buret from the mass of the buret filled with water to get the mass of the water. Show your work.Using the formula, Density = Mass / Volume, calculate the density of water.

Calculate the volume of the second transfer by taking the volume of the first transfer and subtracting the volume delivered during the first titration. Finally, to calculate the average absolute error, take the absolute value of the difference between the theoretical amount of titrant required to reach the endpoint and the actual amount of titrant delivered to reach the endpoint.Post Experiment Questions: The student grade buret delivered approximately 5 mL samples with an average absolute error of 0.02 mL, showing good accuracy or precision compared to the tolerance of expected for these burets.

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Answer:

an insurance contract;   transfer risk

Explanation:

From the information given,

diameter of ornament = 8

radius = diameter/2 = 8/2

radius of curvature, r = 4

Recall,

focal length, f = radius of curvature/2 = 4/2

f = 2

Recall,

magnification = image d

Answer:

Part A) The maximum energy stored in the capacitor, Emax is 4.19 x 10^-4 J.

Part B) The number of times per second that it contains this energy is 2.18 x 10^6 s^-1.

Explanation:

Part A:

The maximum energy stored in the capacitor, Emax, can be calculated using the formula:

Emax = 0.5*C*(Vmax)^2

where C is the capacitance, Vmax is the maximum voltage across the capacitor, and the factor of 0.5 comes from the fact that the energy stored in a capacitor is proportional to the square of the voltage.

To find Vmax, we can use the fact that the maximum current in the inductor occurs when the voltage across the capacitor is zero, and vice versa. At the instant when the current is maximum, all the energy stored in the circuit is in the form of magnetic energy in the inductor. Therefore, the maximum voltage across the capacitor occurs when the current is zero.

At this point, the total energy stored in the circuit is given by:

E = 0.5*L*(Imax)^2

where L is the inductance, Imax is the maximum current, and the factor of 0.5 comes from the fact that the energy stored in an inductor is proportional to the square of the current.

Setting this equal to the maximum energy stored in the capacitor, we get:

0.5*L*(Imax)^2 = 0.5*C*(Vmax)^2

Solving for Vmax, we get:

Vmax = Imax/(sqrt(L*C))

Substituting the given values, we get:

Vmax = (1.10 A)/(sqrt(0.420 H * 0.280 nF)) = 187.9 V

Therefore, the maximum energy stored in the capacitor is:

Emax = 0.5*C*(Vmax)^2 = 0.5*(0.280 nF)*(187.9 V)^2 = 4.19 x 10^-4 J

Part B:

The frequency of oscillation of an L-C circuit is given by:

f = 1/(2*pi*sqrt(L*C))

Substituting the given values, we get:

f = 1/(2*pi*sqrt(0.420 H * 0.280 nF)) = 2.18 x 10^6 Hz

The time period of oscillation is:

T = 1/f = 4.59 x 10^-7 s

The capacitor will contain the amount of energy found in part A once per cycle of oscillation, so the number of times per second that it contains this energy is:

1/T = 2.18 x 10^6 s^-1

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When trying to form standing waves in an air column by using a tuning fork, resonance is achieved when the frequency of the wave produced by the tuning fork matches the natural frequency of the air column.

When this happens, standing waves are produced and the amplitude of vibration of the air column is maximum. At this point, the length of the air column is equal to half the wavelength of the wave produced by the tuning fork, there are different ways to identify that you hit a resonance at a certain length when using a tuning fork to form standing waves in an air column. One common method is to listen for a loud sound at the open end of the air column. At resonance, the air column is at its maximum amplitude of vibration and produces a sound that is much louder than at other frequencies. Another way is to observe the flame of a burning candle. When resonance occurs, the flame flickers violently due to the rapid changes in air pressure inside the tube.

A third way to identify resonance is by measuring the length of the air column when resonance occurs, this can be done using a ruler or a measuring tape. The length of the air column when resonance occurs can be used to calculate the wavelength of the sound produced by the tuning fork. This can then be used to calculate the speed of sound in air, using the formula speed = frequency x wavelength. Overall, resonance is an important concept in acoustics and plays a critical role in the formation of standing waves in air columns.

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Answer:

745.4K ~ 472.3 C

Explanation:

This is an Ideal Gas Law problem where we have to manipulate the equation a bit. Let's start with the basic:

PV = nRT will be used for both the initial and final, so we will rearrange this problem to state:

(V(initial))/(T(Initial)) = nR/P

Since we know that the pressure, number of moles of He, and ideal gas constant (R) remain the same from start to finish so we can write the problem as such:

(V(initial))/(T(Initial)) = nR/P = (V(final))/(T(final))

                             or

(V(initial))/(T(Initial)) = (V(final))/(T(final))

Now lets define some of these values:

T(initial) = 25degree (assuming degrees Celsius) ~ 298.15K

V(initial) = 2.0L

V(final) = 5.0L

T(final) = ?

Since we are solving for T(final) let's rearrange the problem once more to be solving for T(final):

T(final) = (V(final)T(Initial))/V(initial)

Now plug in your values:

T(final) = (5.0L*298.15K)/(2.0L) ~ 745.4K ~ 472.3degrees Celsius

Answer:

yes nucleus is found in plant and animal cells.

Hope this helps :)

Answer:

Explanation:

Greetings!!!

weight= 1.0kg

Extension (x)= 0.25m

spring constant (k)= 50.0N/m

Acceleration= ?

\(firstly.recall \: the \: hooks \: law\)

\(substitute \: known \: varabiles \: into \: the \: equation\)

\(solve \: for \: force\)

\(secondly \: reall \: the \: newtons \: second \: law\)

\(substitute \: known \: variables \: into \: the \: equation \: \)

\(solve \: for \: acceleration \: \)

Hope it helps!!!

Answer:

A. 0.5m/s².

B. –0.5m/s².

C. –0.5m/s².

D. 100m.

Explanation:

A. Determination of the acceleration in the first 20s.

Initial velocity (u) = 0

Final Velocity (v) = 10m/s

Time (t) = 20secs.

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (10 – 0)/20 = 10/20

a = 0.5m/s²

Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²

B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:

Initial velocity (u) = 10m/s

Final Velocity (v) = 5m/s

Time (t) = 30 – 20 = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (5 – 10)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the 20 and 30secs is

–0.5m/s².

C. Determination of the acceleration in the last 10s.

Initial velocity (u) = 5m/s

Final Velocity (v) = 0

Time (t) = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (0 – 5)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the last 10secs is

–0.5m/s².

D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.

Velocity (v) = 5m/s

Time (t) = 50 – 30 = 20secs

Displacement (d) =?

Velocity = Displacement /Time

v = d/t

5 = d/20

Cross multiply

d = 5 x 20

d = 100m

Therefore, the distance travelled by the cyclist at constant speed is 100m

Answer:

True

Explanation:

Velocity is a vector quantity, which means that it carries both magnitude and direction. Hence when direction of a particle changes, although magnitude (speed) may remain same, it's velocity changes due to direction change. For ex. A particle is m... A particle is moving along x axis with speed 1m/s, it's velocity will be represented as 1i (i represents unit vector along x)

But if it now starts moving along y axis, it's velocity is 1j (j represents unit vector along y axis). Hence velocity changes with direction.

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