Evaluate each value expression for the given value of x : 22-x/5 , x=20

HURY!!!!!!!!!!!

Answer:

A is correct answer

Step-by-step explanation:

like me

Answer:

A

Step-by-step explanation:

a) The statement in part (a) is correct. When in the explicit form of a differential equation, the lowest derivative is isolated on one side of the equation.

b) To solve the initial value problem. Thus, z′−3x2z=3 and by multiplying both sides of the equation by

\(e^∫−3xdx=e^-3x\), we get:

e^-3xz′−3e^-3xx2z

\(=3e^-3x+C\) Know let's multiply both sides by\(x^3\) and get:

\(z′x3−3x2z=3x^3e^-3x+C\) Keeping in mind that

\(z=y3−1\), we have:

\(y3=x+12e3x+Cx3+d\)

where C and d are constants of integration.

c) Here's the solution to the first-order ODE: 

Differentiating both sides with respect to t yields:

\(d/dt[tlnt] = dt/dt, d/dt[t] + td/dt[ln(t)]\)

\(= e^t, 1/t*dr/dt + r/t\)

= e^t. \(= e^t.\)

\(dtd​(mv)=0\) and the drag on the sandwich exactly equals its weight.

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Answer:

17.106 Teaspoons of fertilizer

Step-by-step explanation:

Joni has a circular garden with a diameter of 16.5. If she uses 2 teaspoons of fertilizer for every 25 square feet of garden how many teaspoons of fertilizer will Joni need for her entire garden?

Step 1

We calculate the area of the garden.

The garden is circular in shape.

Area of a circle = πr²

r = radius = Diameter/2

Diameter = 16.5 ft

r = 16.5/2

r = 8.25 ft

Area of the circle = π × 8.25²

Area of the circle (Garden) = 213.82464998 ft²

Approximately = 212.825ft²

Step 2

If she uses 2 teaspoons of fertilizer for every 25 square feet of garden how many teaspoons of fertilizer will Joni need for her entire garden?

25 ft² = 2 teaspoons of fertilizer

212.825ft² = x

Cross Multiply

25 ft² × x = 212.825ft² × 2

x = 213.825× 2/25 ft²

x = 17.106 Teaspoons of fertilizer

Answer:

6.25%

Step-by-step explanation:

percentage of red = ( no. of red markers / total no. of markers) *100

                              = 28 *100 / 448

                               = 6.25%

Donna Mosier should use an Individuals control chart to set control limits for the data entry process.

An Individuals control chart is a type of process control chart used to monitor the process when the sample size is one. In this case, Mosier is examining 100 records entered by each of the 20 clerks, making the sample size one.

To set control limits that include 99.73% of the random variation in the data entry process, Mosier can use the following steps:

By using an Individuals control chart, Mosier can set control limits to monitor the data entry process and detect any issues before they become major problems.

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Answer:

3,900,000,000

Step-by-step explanation:

The current global population is 7,800,000,000.

Half of this is 3,900,000,000.

Hicksian demand functions are:x1** = 2P₁x₂ ; x₂** = P₂²

Utility function: u(x1+x2) = .5ln(x1) + .25ln(x₂) .The Marshallian demand functions are: x1* = - and x₂* = P₂.

The indirect utility function is found by substituting Marshallian demand functions into the utility function and solving for v(P₁, P₂, Y).u(x1*,x2*) = v(P₁,P₂,Y) ⇒ u(-, P₂) = v(P₁,P₂,Y) ⇒ .5ln(-) + .25ln(P₂) = v(P₁,P₂,Y) ⇒ v(P₁,P₂,Y) = - ∞ (as ln(-) is not defined)

Thus the indirect utility function is undefined.

Minimum expenditure function can be derived from the Marshallian demand function and prices of goods:

Exp = P₁x1* + P₂x2* = P₁(-) + P₂P₂ = -P₁ + P₂²

Minimum expenditure function is thus:

Exp = P₁(-) + P₂²

Hicksian demand functions can be derived from the utility function and prices of goods:

H1(x1, P1, P2, U) = x1*H2(x2, P1, P2, U) = x2*

Hicksian demand functions are:

x1** = 2P₁x₂

x₂** = P₂²

If there are no restrictions on the amount of money the consumer can spend, the Hicksian demand functions for x1 and x2 coincide with Marshallian demand functions.

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Answer: A. 5

Step-by-step explanation:

Answer:

A)  5 cm.

Step-by-step explanation:

Volume = length * width * height

150 = length * 5 * 6

Length = 150 / (5*6)

= 150/30

= 5.

Taking a difference, we can see that the trip to city C is 482.6 mi longer.

Here we know that the distance from city a to city b is 256.8 miles, and the distance from city a to city c is 739.4 miles

To find how much farther is the trip to city c than the trip to city b, we just need to take the difference between the two distances above.

That means that we need to take the distance to city c and subtract the distance to city b.

We will get:

739.4 mi -  256.8 mi = 482.6 mi

The trip to city C is 482.6 mi more than the trip to city B.

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To calculate the total maximum horizontal stress (Shmax) in a subsurface system with reverse faulting, we can use the formula:

Shmax = P / A

where P is the pressure at the given depth and A is the stress ratio. Given: Depth = 2,000 ft, A = 0.8, Friction angle (φ) = 30°

First, we need to calculate the vertical stress (σv) at the given depth using the equation:

σv = ρ g  h

where ρ is the unit weight of the overlying rock, g is the acceleration due to gravity, and h is the depth.

Next, we can calculate the effective stress (σ') using the equation:

σ' = σv - Pp

where Pp is the pore pressure.

Assuming the pore pressure is negligible, σ' is approximately equal to σv.

Finally, we can calculate Shmax using the formula:

Shmax = σ' * (1 + sin φ) / (1 - sin φ)

Substituting the given values into the equations, we can calculate Shmax. However, the unit weight of the rock and the value of g are required to complete the calculation.

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Answer:

last year = 530570

this year = 424456

decreased plants = 530570-424456 = 106114

decreased percent = 106114÷530570×100%

= 20%

therefore 20% is the decrease precent in the number of potted plants ordered anually

The probability of rolling a sum of 10 is \(\frac{1}{18}\)

as we know that total number of outcomes for a dice is equal to six raised to the power times the dice is rolled

that is,  total number of outcomes = \(6^{2} = 36\)

also, the sum can be equal to 10 in only two cases, (6,4) and (5,5)

according to the formula

Probability = \(\frac{favorable events}{ total number of outcome} = \frac{2}{36} = \frac{1}{18}\)

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Question:

You roll a fair six-sided die and record the result X. You roll the die again and record the result Y. What is the probability of rolling a sum of 10?

The centroid of a triangle is the point where the three medians of the triangle intersect. In this case, the triangle has vertices at (0, 0), (5, 0), and (0, 7).

First, let's calculate the average x-coordinate:
¯x = (0 + 5 + 0) / 3 = 5/3 ≈ 1.67

Next, let's calculate the average y-coordinate:
¯y = (0 + 0 + 7) / 3 = 7/3 ≈ 2.33, the centroid of the triangle with vertices at (0, 0), (5, 0), and (0, 7) is approximately (1.67, 2.33).
In summary, the centroid of the triangle with verticesvertices at (0, 0), (5, 0), and (0, 7) is located at approximately (1.67, 2.33). This point represents the average position of the three vertices and is the intersection point of the medians of the triangle.

The centroid coordinates are found by taking the average of the x-coordinates and the average of the y-coordinates of the three vertices. In this case, we add up the x-coordinates (0 + 5 + 0 = 5) and divide by 3 to get an average of 5/3, which is approximately 1.67. Similarly, we add up the y-coordinates (0 + 0 + 7 = 7) and divide by 3 to get an average of 7/3, which is approximately 2.33. These values represent the x-coordinate (¯x) and the y-coordinate (¯y) of the centroid, respectively. Therefore, the centroid of the triangle is located at approximately (1.67, 2.33).

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Answer:

5

Step-by-step explanation:

Answer:

Step-by-step explanation:

25*8=200 soooooooooo 200=22x divide 22 on both sides and you get x=100/11

Answer:

25×8=200

200÷22x

x=9,09

therefore x=9,1

The p-value for a z-test statistic of -1.98 can be determined by finding the area under the standard normal distribution curve to the left of -1.98.

In hypothesis testing, the p-value represents the probability of obtaining a test statistic as extreme as, or more extreme than, the observed test statistic under the null hypothesis.

Given that the z-test statistic is -1.98, we want to find the probability associated with this value. To do so, we look up the corresponding area under the standard normal distribution curve.

Using statistical software or a standard normal distribution table, we can find that the area to the left of -1.98 is approximately 0.0244 (or 2.44% when expressed as a percentage).

However, since the z-test statistic is negative, we are interested in the left tail of the distribution. To find the p-value, we consider the area in the left tail, which is 0.0244.

Therefore, the p-value for this test is approximately 0.0244. This means that if the null hypothesis is true, there is approximately a 2.44% chance of observing a test statistic as extreme as -1.98 or more extreme.

It is worth noting that the p-value should be compared to the predetermined significance level (α) to make a decision about rejecting or failing to reject the null hypothesis. If the p-value is less than or equal to α, typically set at 0.05, the null hypothesis is rejected in favor of the alternative hypothesis. If the p-value is greater than α, the null hypothesis is not rejected.

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To model the area burned as a function of time, we can use the formula for the area of a circle, which is A = πr^2. In this case, the radius of the circle is given by r(t) = 2t + 1, where t represents time in minutes.

To find the area burned at any given time, we substitute the expression for r(t) into the formula for the area:

A(t) = π(2t + 1)^2

Now, let's simplify this equation step by step:

1. Expand the square:
A(t) = π(4t^2 + 4t + 1)

2. Distribute π to each term inside the parentheses:
A(t) = 4πt^2 + 4πt + π

So, the function modeling the area burned as a function of time is A(t) = 4πt^2 + 4πt + π.


We are given the radius of the circle of burning forest as r(t) = 2t + 1, where t is the time in minutes. To find the area burned, we need to use the formula for the area of a circle, which is A = πr^2. By substituting the expression for r(t) into the formula, we get A(t) = π(2t + 1)^2. Simplifying further, we expand the square and distribute π to each term inside the parentheses, resulting in A(t) = 4πt^2 + 4πt + π.


The function A(t) = 4πt^2 + 4πt + π models the area burned as a function of time, where t represents the time in minutes.

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answer : linear

source: trust me people

Answer:

157482

Step-by-step explanation:

234 × 673 = 157482

Answer:

157,482

Step-by-step explanation:

Use a calculator.

The measure of the angles are: K, L, C, N, O G = -3/4, 65, 8 40.4, 89 and 44 respectively

To determine K

9x + 2 = 23 + 5x -1

9x -5x = -1 +2

4x = -3Making x the subject we have

x= -3/4

To find the value of L

Let angle L be x

x + 65 = 130

x=130-65

That is x = 65

To find the m<C

4x + 7 = 3x + 15

Collecting like terms

4x - 3x = 15-7

Making x the subject of the relation we have

x=8

To find the m<N

7x + 6x - 1 = 90

13x = 89

x=89/13

x= 6.9

Substitute x = 6.9 in 6x -1

6(6.9) -1

m<L = 40.4

To find the m<O

5x - 11 = 4x +9

5x-4x = 9 +11

x=20

By substitution in 4x +9 we have

4(20) +9

80+9

m<S = 89

To find the value of the angle G

6x - 4 = 5x +4

6x - 5x = 4+4

x = 8

Therefore the m<G is

5x +4

5(8) +4

40+4 = 44 digress

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The width of the fountain will be 3 feet and the fraction of the area of the courtyard will be occupied by the fountain is 3/44

Is the measure of the space occupied by a body bounded by an environment called perimeter, the same is expressed in units of squared side. Example: ft^2, m^2

The formula and procedure to solve this geometry exercise is:

A(rectangle) = length * width

Information about the problem:

A(stone) = 246 ft^2

A(fountain) = ?

Width = ?

Calculating the area of the fountain we get:

Area of fountain = area of the rectangle - 246

Area of fountain = (12 x 22) - 246

Area of fountain = 264 - 246

Area of fountain = 18 ft^2

Calculating the width of the fountain we have:

A(rectangle) = length * width

18 = W x 6

W = 18/6

W = 3 feet

Calculating the fraction of the area of the courtyard will be occupied by the fountain we get:

Fraction = Area of fountain / area of the rectangle

Fraction = 18 ft^2 /264 ft^2

Fraction = 18/264

Simplifying we have:

Fraction = 3/44

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Answer:

don't know if this works but I'll try

Step-by-step explanation:

Y=60x+55

y is how many days and the 55 is there because that is how much mariah already has made?

Answer:

x = -5

Y = -22/3

Step-by-step explanation:

Y= 2/3x - 4                     Y = -x + 1

We put -x + 1 in for y to solve for x

-x + 1 = 2/3x - 4

-5/3x + 1 = -4

-5/3x = -5

x = -5

Now put -5 in for x and solve for y

Y= 2/3(-5) - 4

Y = -10/3 - 4

Y = -22/3

So, there are only one solution x = -5 and y = -22/3

Answer:

\(t = 1.71825\)

Step-by-step explanation:

Given

\(h(t) = -16t^2 + 24t + 6\)

Required

When will the coin hit the ground

When the coin hits the ground, \(h(t) = 0\)

The expression \(h(t) = -16t^2 + 24t + 6\) becomes

\(0 = -16t^2 + 24t + 6\)

Multiply through by -1

\(16t^2 - 24t - 6 = 0\)

Solve using quadratic formula

\(t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}\)

Where

\(a = 16\)

\(b = -24\)

\(c = -6\)

\(t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}\)

\(t = \frac{-(-24)\±\sqrt{(-24)^2 - 4 *16 * -6}}{2 * 16}\)

\(t = \frac{24\±\sqrt{576 +384}}{32}\)

\(t = \frac{24\±\sqrt{960}}{32}\)

\(t = \frac{24\±30.984}{32}\)

Split

\(t = \frac{24+30.984}{32}\) or \(t = \frac{24-30.984}{32}\)

\(t = \frac{54.984}{32}\) or \(t = \frac{-6.984}{32}\)

\(t = 1.71825\) or \(t = -0.21825\)

But time can't be negative;

So:

Time to hit the ground is 1.71825 seconds

34.32 milligrams of radioactive substance will remain after 54 hours .

For example, time affects a planet's position. The concept was first introduced with infinitesimal calculus towards the end of the 17th century, and differentiable functions were considered up until the 19th century (that is, they had a high degree of regularity). When the concept of a function was defined in terms of set theory near the end of the 19th century, the areas in which it could be used were greatly broadened.

Remember the formula for an exponential function is represented by

\(f(x) = ab^{x}\)

where a is the initial value and bb is the growth rate.

If the base, b > 1, then it shows exponential growth. If it is 0< b < 1, then it shows exponential decay.

Using the formula for exponential function, we substitute the necessary details from the problem to get the rate first:

initial milligrams of that radioactive substances = 100

final amount of that radioactive substances = 50

number of hours = 35

decay rate can be found by =

\(50 = 100b^{35}\\ \\\frac{50}{100} = b^{35}\\ \\ b = 0.5^{\frac{1}{35} }\)

now that we use 54/35 to  represent the time needed to find how much of the substance is left:

\(f(x) = 100(0.5)^{\frac{54}{35} }\)

= 100(0.3432050906)

= 34.32

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According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7

Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.

Given,

n = 66

We know that,

According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

\(k=1+log_{2} n\)

Here, n is equal to 66 and by substituting the value to the equation we get:

\(k=1+log_{2} (66)\)

k = 7.0444

k ≈ 7

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Answer:

a you cant add if they are not the same denominator

Answer:

\(Answer: A\)

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