Evaluate 19x-(7+x)+8+x when x=2. Show Your Work​

Answer:

y = x + 3

Step-by-step explanation:

y = mx + b

m = slope = (difference in y)/(difference in x)

m = (9 - 5)/(6 - 2) = 4/4 = 1

y = x + b

5 = 2 + b

b = 3

y = x + 3

The function below is not provided in the question, therefore, I cannot provide a specific linearization method to fit the data to a linear regression model.

However, in general, the correct linearization method for a function to be fit to a data set using linear regression would depend on the functional form of the equation.

For example, if the function is exponential, taking the logarithm of the data may result in a linear relationship that can be fit using linear regression.

The specific linearization method to fit a function to a linear regression model would depend on the functional form of the equation. For an exponential function, taking the logarithm of the data may result in a linear relationship that can be fit using linear regression. However, since the function in question is not provided, I cannot provide a specific linearization method.

The correct linearization method for a function to be fit to a linear regression model depends on the functional form of the equation and cannot be determined without knowledge of the specific function.

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As the sample size grows, the distribution of the sampled means becomes normally distributed option (C) is correct.

With simple random sampling, each component of the population has an equal chance of being selected for the sample.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

Suppose a simple random sample of size n is obtained from a population whose distribution is skewed right.

As we know, the distribution of sample means will be normally distributed even if the individual samples do not, according to the Central Limit Theorem, if the mean values for increasing sample sizes are determined.

Thus, as the sample size grows, the distribution of the sampled means becomes normally distributed.

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The coordinate of the other endpoint a line segment with endpoint of (-24, 8) and midpoint of (-16, 12) is ( -8,16 ).

The midpoint formula is expressed as;

M = ( (x₁+x₂)/2, (y₁+y₂)/2

Given the data in the question;

Midpoint (-16, 12)

Endpoint 1 (-24,8)

End point 2

Plug the given values in to the midpoint formula and solve for x₂ and y₂.

M = ( (x₁+x₂)/2, (y₁+y₂)/2

(x,y) = ( (x₁+x₂)/2, (y₁+y₂)/2

First, solve for the x-coordinate

x = (x₁+x₂)/2

2x = x₁ + x₂

2(-16) = -24 +  x₂

-32 = -24 +  x₂

x₂ = -32 + 24

x₂ = -8

Next, solve for the y-coordinate

y = (y₁+y₂)/2

2y = y₁ + y₂

2(12) = 8 + y₂

24 = 8 + y₂

y₂ = 24 - 8

y₂ = 16

Therefore, the coordinate of second endpoint is ( -8,16 ).

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Answer:

1,3

Step-by-step explanation:

If a coordinate point is at (4, 2) and is translated down 3 units and right 1 unit, what is its new coordinate point?

4-3=1

2+1=3

(1,3)

Answer: (-1,5)

Step-by-step explanation:

Answer:

1

Anything to the 0th power is 1.

Answer:

1

Step-by-step explanation:

Answer:

Step-by-step explanation:

Measure of an inscribed angle intercepted by an arc is half of the measure of the arc.

From the picture attached,

m(∠A) = \(\frac{1}{2}m(\text{arc BD})\)

           = \(\frac{1}{2}[m(\text{BC})+m(\text{CD}]\)

           = \(\frac{1}{2}[55^{\circ}+145^{\circ}]\)

           = 100°

m(∠C) = \(\frac{1}{2}[(360^{\circ})-m(\text{arc BCD})]\)

           = \(\frac{1}{2}(360^{\circ}-200^{\circ})\)

           = 80°

m(∠B) + m(∠D) = 180° [ABCD is cyclic quadrilateral]

115° + m(∠D) = 180°

m(∠D) = 65°

m(arc AC) = 2[m(∠D)]

m(arc AB) + m(arc BC) = 2(65°) [Since, m(arc AC) = m(arc AB) + m(arc BC)]

m(arc AB) + 55° = 130°

m(arc AB) = 75°

m(arc ADC) = 2(m∠B)

m(arc AD) + m(arc DC) = 2(115°)

m(arc AD) + 145° = 230°

m(arc AD) = 85°

Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

To find the Taylor polynomials centered at x = 0 for the function f(x) = 16tan(x), we can use the Taylor series expansion for the tangent function and truncate it to the desired degree.

The Taylor series expansion for tangent function is:

tan(x) = x + (1/3)x^3 + (2/15)x^5 + (17/315)x^7 + ...

Using this expansion, we can find the Taylor polynomials of degree 2 and 3 centered at x = 0:

Degree 2 Taylor polynomial:

P2(x) = f(0) + f'(0)(x - 0) + (1/2!)f''(0)(x - 0)^2

= 16tan(0) + 16sec^2(0)(x - 0) + (1/2!)16sec^2(0)(x - 0)^2

= 0 + 16x + 8x^2

Degree 3 Taylor polynomial:

P3(x) = P2(x) + (1/3!)f'''(0)(x - 0)^3

= 0 + 16x + 8x^2 + (1/3!)(48sec^2(0)tan(0))(x - 0)^3

= 16x + 8x^2

Therefore, the Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

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The inequality represents the sentence below is that the p minus 1. 4 greater-than 9.

Inequality equation is the equation in which the two expressions are compared with greater than, less than or other inequality signs.

Given that the difference of a number and one and four tenths is more than nine and seventy-eight hundredths.

Before solving it, first let's discuss the tenth and hundredths,

Here, the sentence given that the difference of a number and one and four tenths is more than nine and seventy-eight hundredths.

One and four tenths can be written as,

\(1\dfrac{4}{10}\)

Nine and seventy-eight hundredths can be written as,

\(9\dfrac{78}{100}\)

Let suppose the number is p. This difference of this number and one four tenths is more than nine and seventy-eight hundredths. Thus,

\(p-1\dfrac{4}{10} > 9\dfrac{78}{100}\\p-\dfrac{14}{10} > \dfrac{978}{100}\\p-1.4 > 9.78\\\)

Hence, the inequality represents the sentence below is that the p minus 1. 4 greater-than 9.

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Answer:

x = 6

Step-by-step explanation:

we can multiply the entire equation by 3 to simplify the numbers

-2x + 27 = 4x - 9

27 = 6x - 9

36 = 6x

x = 6

Answer:

cappppppppppp

Step-by-step explanation:

jp wyd homie

The solutions to the equation −11x − 7 = \(-3x^2\), rounded to the nearest tenth, are x ≈ -1.1 and x ≈ 6.1.

An equation is a mathematical statement that shows that two expressions are equal. It is usually written as an expression on the left-hand side (LHS) and an expression on the right-hand side (RHS) separated by an equal sign (=).

The expressions on both sides of the equation can contain variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. The variables in an equation represent unknown values that can vary, while the constants are fixed values that do not change.

Equations are used to represent mathematical relationships or describe real-world situations. They can be used to solve problems, make predictions, and test hypotheses.

To solve an equation, one must find the value of the variable that makes the LHS equal to the RHS. This is done by performing mathematical operations on both sides of the equation to isolate the variable. The goal is to get the variable by itself on one side of the equation, with a specific value on the other side.

Equations can be simple or complex, linear or nonlinear, and can involve one or more variables. Examples of equations include:

2x + 5 = 13

y = \(3x^2\) - 2x + 7

4a + 2b - 3c = 10

Equations are used in many areas of mathematics and science, including physics, chemistry, and engineering, among others.

We are given the equation \(-11x - 7 = -3x^2\).

To solve for x, we can rearrange the equation into a quadratic form by bringing all terms to one side:

\(-3x^2 + 11x + 7\) = 0

We can solve this quadratic equation by using the quadratic formula:

x = (-b ± sqrt(\(b^2\) - 4ac)) / 2a

where a = -3, b = 11, and c = 7.

Substituting these values, we get:

x = (-11 ± sqrt(\(11^2\) - 4(-3)(7))) / 2(-3)

Simplifying inside the square root:

x = (-11 ± sqrt(121 + 84)) / (-6)

x = (-11 ± sqrt(205)) / (-6)

Using a calculator, we can approximate this to:

x ≈ -1.1 or x ≈ 6.1

Therefore, the solutions to the equation \(-11x - 7 = -3x^2\), rounded to the nearest tenth, are x ≈ -1.1 and x ≈ 6.1.

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If sequence of transformations that maps △ABC to △A^' B^' C^'.The sequence of transformation is 90 degrees counterclockwise rotation, followed by a vertical translation to the right by 2 unit. The ordered pair-rule for each are  (x,y) tends to (-x,-y)

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure.

Image is the original shape of the object and final shape ond position of the object is the preimage.

In the given figure,

original image is △ABC and  △A^' B^' C^' is the preimage.

Transformation includes changing the position of a shape.

The steps followed for transformation include rotating the image to 90 degrees counterclockwise rotation, later by a vertical translation to the right by 2 unit.

The ordered pair-rule for each are  (x,y) tends to (-x,-y)

Hence △ABC is the original image and  △A^' B^' C^' is the preimage and The ordered pair-rule for each are  (x,y) tends to (-x,-y)

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Answer:

∠A = 120° (180°-60°)

∠W = 60° (b/c ∠W=∠X)

∠Y = 100° (b/c 180°-80°)

∠X = 60° (180°-120°)

∠Z = 120° (180-60°)

Step-by-step explanation:

im unsure about A and W

Answer:

Answer:

fx/gx=10

Step-by-step explanation:

fx= (36x5)-(44x4)-(28x3)

fx=80

gx= 4x2

gx=8

To work out fx/gx:

fx/gx=80/8

fx/gx=10

Answer:

Step-by-step explanation:

in which way do you want it factorized?

Answer:

a) 22:25 is the earliest time

b)15 min

Step-by-step explanation:

Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....

10:10(standard) = 22:10 (military)

22:10 -> 15min-> 22:25

Answer:

a) 22:25 is the earliest time

b)15 min

Because

Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....

Answer:

13/12

Step-by-step explanation:

make into inproper fraction then cross multiply then reduce to lowest terms. hope this helps

Answer:

Length of each stump is 2.167 feet

Step-by-step explanation:

8 2/3 divided by 4 is 2.166667

2.166667 simplified is 2.167

The series solution up to and including x⁴ is given by y(x) = 1 + 6x + (1/2)x² + (5/6)x³ + (1/4)x⁴ + ...

1.(a) A sequence is said to converge if its terms approach a specific value as the index of the terms increases without bound. In other words, as you go further along in the sequence, the terms get arbitrarily close to a particular limit value.

A sequence is said to diverge if its terms do not approach a specific value or if they move away from any possible limit as the index increases without bound. In other words, there is no single value that the terms of the sequence tend to as you go further along.

(b) Is there a sequence 01, 02, a3... with lan) <0.0001 for all n = 1,2,3,... that diverges No, there is no such sequence. If a sequence has a limit, then for any positive epsilon (ε), there exists a positive integer N such that for all n > N, |an - L| < ε, where L is the limit. In this case, if the limit exists, all terms beyond a certain index will be arbitrarily close to the limit, and it would violate the condition lan) < 0.0001 for all n = 1,2,3,... Therefore, if the condition holds, the sequence must converge.

(c) Is there a sequence 1000 01, 02, 03... with an < for all n = 1,2,3,... n 45 135 405 that diverges No, there is no such sequence. The sequence you provided starts with 1000, and each subsequent term increments by 1. Since the terms are increasing, the sequence does not approach any limit and therefore diverges.

2. (a)The nth term in the sequence an, assuming the sequence starts at a₀ we can observe that each term is obtained by multiplying the previous term by 4. So the expression for the nth term in the sequence can be given as

Aₙ = a₀ × 4ⁿ⁻¹

Given that a₀ = 15, the expression for the nth term in the sequence is:

aₙ = 15 × 4ⁿ⁻¹

(b) Does the series obtained by adding the terms of the sequence, Σan, converge or diverge

The series obtained by adding the terms of the sequence converges or diverges, we need to calculate the sum of the terms. Let's denote the sum of the series as S.

S = a₀ + a₁ + a₂ + ... + aₙ

Substituting the expression for an derived in part (a), we have:

S = 15 + 15 × 4⁰ + 15 × 4¹ + 15 × 4² + ... + 15 × 4ⁿ⁻¹

Using the formula for the sum of a geometric series, we can simplify this expression:

S = 15 × (1 + 4⁰ + 4¹ + 4² + ... + 4ⁿ⁻¹)

The sum of a geometric series with a common ratio greater than 1 is given by:

S = a × (1 - rⁿ) / (1 - r)

In this case, a = 15 and r = 4. Letting n approach infinity, we have:

S = 15 × (1 - 4ⁿ) / (1 - 4)

As n approaches infinity, the term 4ⁿ grows larger and larger. Since the common ratio (4) is greater than 1, the term 4ⁿ approaches infinity. Therefore, the sum of the series also approaches infinity.

Hence, the series obtained by adding the terms of the sequence diverges.

3) A series solution up to and including x⁴ for the initial value problem (IVP) y" - xy' + y² = 1 with the initial conditions y(0) = 1 and y'(0) = 6, we can use the power series method.

Let's assume that the solution y(x) can be expressed as a power series:

y(x) = a₀ + a₁x + a₂x² + a₃x³ + a₄x⁴ + ...

Differentiating y(x) with respect to x, we get:

y'(x) = a₁ + 2a₂x + 3a₃x² + 4a₄x³ + ...

Similarly, differentiating y'(x) with respect to x, we obtain:

y''(x) = 2a₂ + 6a₃x + 12a₄x² + ...

Now, let's substitute these expressions into the given differential equation:

y''(x) - xy'(x) + y(x)² = 1

(2a₂ + 6a₃x + 12a₄x² + ...) - x(a₁ + 2a₂x + 3a₃x² + 4a₄x³ + ...) + (a₀ + a₁x + a₂x² + a₃x³ + a₄x⁴ + ...)² = 1

Expanding and collecting the terms with the same power of x, we get:

(2a₂ - a₀) + (6a₃ - a₁ - 2a₂) x + (12a₄ - 2a₁ + 3a₃) x² + ...

To satisfy the equation, each coefficient of x must be equal to zero. Setting the coefficients to zero, we have:

2a₂ - a₀ = 0 (Coefficient of x⁰)

6a₃ - a₁ - 2a₂ = 0 (Coefficient of x¹)

12a₄ - 2a₁ + 3a₃ = 0 (Coefficient of x²)

Using the initial conditions y(0) = 1 and y'(0) = 6, we have:

a₀ = 1 (Initial condition)

a₁ = 6 (Initial condition)

Solving the equations above, we find

a₂ = a₀/2 = 1/2

a₃ = (a₁ + 2a₂)/6 = (6 + 2/2)/6 = 5/6

a₄ = (2a₁ - 3a₃)/12 = (2(6) - 3(5/6))/12 = 1/4

Therefore, the series solution up to and including x⁴ is given by:

y(x) = 1 + 6x + (1/2)x² + (5/6)x³ + (1/4)x⁴ + ...

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To design a can shaped like a right circular cylinder that minimizes the amount of material used, we can utilize the concept of optimization.

dA/dr =

-864/r² + 4πr = 0

However, you can solve the equation numerically or by using optimization methods.

Let's assume the radius of the cylinder is "r" and the height is "h."

The volume of a right circular cylinder is given by the formula V = π\(r^{2h}\).

In this case, the volume is given as 432π cm³. So, we have:

π\(r^{2h}\) = 432π

We want to minimize the surface area, which is the amount of material used to construct the can.

The surface area of a right circular cylinder is given by the formula A = 2πrh + 2πr².

Now, we need to express the surface area "A" in terms of a single variable to apply optimization techniques.

We can use the volume equation to solve for "h":

h = 432/(πr²)

Substituting this value of "h" in the surface area equation, we get:

A = 2πr(432/(πr²)) + 2πr²

= 864/r + 2πr²

Now, we have the surface area "A" as a function of the variable "r."

To find the minimum amount of material, we need to find the value of "r" that minimizes the surface area.

To do this, we can take the derivative of "A" with respect to "r" and set it equal to zero:

dA/dr =

-864/r² + 4πr = 0

Solving this equation will give us the value of "r" that minimizes the surface area.

Once we find "r," we can substitute it back into the equation for "h" to get the corresponding height.

Unfortunately, due to the complexity of the calculations involved, it's not possible to provide an exact numerical solution without further computations.

However, you can solve the equation numerically or by using optimization methods to find the values of "r" and "h" that minimize the amount of material used in the can.

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By using normal distribution, it is obtained that weight of a randomly selected chicken egg is 28.39 grams

What is normal distribution?

Normal distribution is a continuous type probability distribution whose probability density function is

\(\frac{1}{\sigma \sqrt{2\pi}}e^{-\frac{z^2}{2}\)

where,  z = \(\frac{x - \mu}{\sigma}\)

\(\mu\) is the mean and \(\sigma\) is the standard deviation

In case of normal distribution

Formula for z = \(\frac{x - \mu}{\sigma}\)

\(\mu\) is the mean and \(\sigma\) is the standard deviation

Let the weight of the egg be x grams

Here, z = -1.41, \(\mu\) = 58 and \(\sigma\) = 21

\(-1.41 = \frac{x - 58}{21}\\\)

x = -1.41 \(\times\) 21 + 58

x = 28.39 grams

Weight of a randomly selected chicken egg is 28.39 grams

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The rewritten expression using a common factor is:

4x + 16 = 4*(x + 16)

Here we want to rewrite the expression:

4x + 16

Ussing a common factor, so let's factorize the terms.

The first one is simple:

4x = 4*x

The second one is also simple, we can write:

16 = 4*4

Then the common factor is 4, and we can rewrite the expression as:

4x + 16 = 4*(x + 16)

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Answer:

Step-by-step explanation:

1.7 - 2.7 - 1.34 + 4.9 - 1.48

First we can group the positive and negative numbers

1.7 + 4.9 - 2.7 - 1.34 - 1.48

add the positive numbers then add the negative numbers

1.7 + 4.9 becomes 6.6

-2.7 - 1.34 - 1.48 becomes - 5.52

Now add both the answers

6.6 + (- 5.52) = 1.08

Hope this helps

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After six​ months, the​ subjects' symptoms are studied and compared. Answer parts​ are given below.

An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.

Given:

A pharmaceutical company wants to test the effectiveness of a new allergy drug.

The company identifies 250 females​ 30–35 years old who suffer from severe allergies.

The subjects are randomly assigned into two groups.

One group is given the new allergy drug and the other is given a placebo that looks exactly like the new allergy drug.

After six​ months, the​ subjects' symptoms are studied and compared.

Here, 30-35 year-old girls are used to test the new allergy medication's effects.

(a)

Females between the ages of 30 and 35 who are the test subjects are the experimental units.

The new allergy medication, whose results are being studied, is the remedy.

It's best to choose C.

(b)

A bias may develop if a researcher or patient knows whether subjects received a medication or a placebo.

In this case, choice B is preferable.

(c)

If neither the researcher nor the subject knew whether they were receiving a medicine or a placebo, the study would be considered double-blind.

In this case, choice A is preferable.

Therefore, all the correct choices are given above.

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The complete question is given in the image.

To decide which measurement has a reverse relationship with the number of wins, we ought to seek for a relationship coefficient with negative esteem. A negative correlation coefficient shows that as one variable increments, the other variable tends to diminish.

Without seeing the real relationship framework, we cannot point out the precise statistic that has a reverse relationship with the number of wins. In any case, ready to search for the relationship coefficient that features negative esteem.

For illustration, in the event that we have a relationship network like this:

markdown

| W | Period | WHIP | SO/9 | BB/9 |

----------------------------------------------

W | 1 | -0.7 | -0.6 | 0.5 | -0.3 |

----------------------------------------------

Period | -0.7| 1 | 0.9 | -0.8 | 0.5 |

----------------------------------------------

WHIP | -0.6| 0.9 | 1 | -0.7 | 0.4 |

----------------------------------------------

SO/9 | 0.5| -0.8 | -0.7 | 1 | -0.4 |

----------------------------------------------

BB/9 | -0.3| 0.5 | 0.4 | -0.4 | 1 |

----------------------------------------------

We are able to see that the relationship coefficient between the number of wins (W) and the earned run normal (Time) is -0.7, which indicates a strong negative relationship. This implies that as the Time increments (showing poorer pitching execution), the number of wins tends to diminish. Subsequently, Time has a reverse relationship with the number of wins.

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Answer: 0.335

Step-by-step explanation:

exponents come first in the order of operation; 10^2=100

now 33.5/100=0.335

Answer:

\({ \rm{ \sqrt{ \frac{1 + \cos(x) }{1 - \cos(x) } } }} \\ \\ \)

- Rationalize the denominator of the above expression;

\({ \rm{ = \sqrt{ \frac{(1 + \cos(x)).(1 + \cos(x)) }{(1 - \cos(x)).(1 + \cos(x)) } } }} \\ \\ = { \rm \sqrt{ \frac{( {1}^{2} + 2 \cos(x) + \cos ^{2}(x)) }{( {1}^{2} - { \cos }^{2}(x)) } } } \\ \\ = { \rm\sqrt{ \frac{(1 + 2 \cos(x) + { \cos }^{2} (x)) }{(1 - { \cos }^{2}(x)) } } }\)

- From the above expression, 1 - cos²x = sin²x

\( = { \rm{ \sqrt{ \frac{1 + 2 \cos(x) + { \cos }^{2}(x) }{ { \sin }^{2}(x) } } }} \\ \)

\( = { \rm{ \sqrt{ \frac{ {(1 + \cos(x)) }^{2} }{ { \sin}^{2}x } } }} \\ \\ = { \rm{ \frac{ \sqrt{(1 + \cos(x)) {}^{2} } }{ \sqrt{ { \sin}^{2} x} } }} \\ \\ = { \rm{ \frac{1 + \cos(x) }{ \sin(x) } }} \\ \\ = { \rm{ \frac{1}{ \sin(x) } + \frac{ \cos(x) }{ \sin(x) } }} \\ \\ = { \boxed{ \rm{ \: \csc(x) + \cot(x) \: }}}\)

The function f(t) is defined as e raised to the power 5t plus 4t plus the natural logarithm of the quantity t squared plus 3 times the constant c, raised to the power of 7, plus t times e raised to the power of -1 plus 5 times e raised to the power of 6.

Given a function:

f(t)=e5t+4t+7ln(t2+3c)+te-1+5e6

where c is a constant.

The solution to the question is shown below.

Step 1: We have given a function:

f(t)=e5t+4t+7ln(t2+3c)+te-1+5e6

We have to find the number of words we have to write to express this function in words.

Step 2: Solution

f(t) = et5+4t + ln(t²+3c)⁷ +te-1+5e⁶

Where,

et5+4t = exponential function

ln(t²+3c)⁷ = natural logarithmic function

te-1 = linear function

e⁶ = exponential function

Therefore, f(t) can be expressed in words as:

The function f(t) is defined as e raised to the power 5t plus 4t plus the natural logarithm of the quantity t squared plus 3 times the constant c, raised to the power of 7, plus t times e raised to the power of -1 plus 5 times e raised to the power of 6.

Step 3: Conclusion

Hence, the function f(t) can be expressed in words with:The function f(t) is defined as e raised to the power 5t plus 4t plus the natural logarithm of the quantity t squared plus 3 times the constant c, raised to the power of 7, plus t times e raised to the power of -1 plus 5 times e raised to the power of 6.

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