Answer:
This is because the distance between Deimos and Mars might be smaller.
Explanation:
How many (whole) dark fringes will be produced on an infinitely large screen if blue light (λ = 475 nm) is incident on two slits that are 20.0 μm apart?(The 3% margin of error does not apply for this question)
To find the number of whole dark fringes on an infinitely large screen, we need to first determine the angular separation between the dark fringes.
Explanation:
Dark fringes occur at angles that satisfy the following condition:
sin(θ) = (m + 1/2) * λ / d
Where θ is the angle between the central maximum and the m-th dark fringe, m is an integer (0, 1, 2, ...), λ is the wavelength of the light, and d is the distance between the two slits.
Given the values λ = 475 nm and d = 20.0 μm, we can calculate the angular separation between the dark fringes:
sin(θ) = (m + 1/2) * (475 * 10^-9 m) / (20.0 * 10^-6 m)
Since the screen is infinitely large, we can assume that the angles span from -90° to 90°. Thus, we can find the number of whole dark fringes within this range by determining the maximum and minimum values of m:
sin(-90°) = -(m_min + 1/2) * (475 * 10^-9 m) / (20.0 * 10^-6 m)
sin(90°) = (m_max + 1/2) * (475 * 10^-9 m) / (20.0 * 10^-6 m)
Solving for m_min and m_max:
m_min ≈ -20.88
m_max ≈ 20.88
Since m must be an integer, we have:
m_min = -20
m_max = 20
The total number of whole dark fringes within the range is the difference between the maximum and minimum values of m, plus one (since we're counting both endpoints):
Number of dark fringes = m_max - m_min + 1 = 20 - (-20) + 1 = 41
Therefore, there will be 41 whole dark fringes on an infinitely large screen with blue light incident on two slits that are 20.0 μm apart.
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In 2009, there were 3,494 radio stations across the united states. Radio became a common device for transmitting and receiving signals?
In the United States, there were 3,494 radio broadcasting stations in 2009. Radio reaches approximately 68 percent of American customers aged 12 and older on average each day, and 236 million people listen to radio every week, according to records.
Since their beginnings at the turn of the 20th century, radio stations in the United States have changed. Following the establishment of 8MK in Detroit in 1920, thousands of private and public radio stations have operated across the country. There are several different ways to organise the lists of radio stations in the US.
The Federal Communications Commission oversees radio transmission in the US (FCC). Various broadcasting services, including the following, have been produced under the AM broadcast band, which runs from 540 to 1700 kHz, is where radio transmission initially gained popularity in the 1920s.
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how will you measure the volume of the solid objects in this experiment?
In this experiment, to measure the volume of solid objects, you can use the displacement method.
Here's a step-by-step explanation:
1. Fill a graduated cylinder or a measuring container with water. Note the initial water level.
2. Carefully submerge the solid object into the water. Ensure the object is fully submerged without touching the sides or bottom of the container.
3. Observe the new water level after the object has been submerged.
4. Subtract the initial water level from the new water level to determine the volume of the solid object. This is based on the principle that the volume of water displaced is equal to the volume of the submerged object.
By following these steps, you can accurately measure the volume of solid objects in your experiment using the displacement method.
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A rotating flywheel slows down at a constant rate due to friction in its bearings. After 1.00 min, its angular velocity has diminished to 0.951 of its initial value ω. At the end of the fifth minute what is the angular velocity in terms of the initial value? Do not enter unit.
According to the given statement , the angular velocity at the end of the fifth minute is ω_0 * (0.951)⁵.
The angular velocity of the rotating flywheel at the end of the fifth minute can be determined by considering the constant rate of decrease in angular velocity due to friction.
We are given that after 1.00 min, the angular velocity has diminished to 0.951 of its initial value ω. Let's denote the initial angular velocity as ω_0.
Using this information, we can set up the following equation:
ω = ω_0 * 0.951
To find the angular velocity at the end of the fifth minute, we need to determine how much the angular velocity has diminished after each minute.
Since the rate of decrease is constant, we can divide the time into five intervals, each corresponding to one minute.
Let's denote the angular velocity at the end of the first minute as ω_1, at the end of the second minute as ω_2, and so on.
From the given information, we have:
ω_1 = ω_0 * 0.951
ω_2 = ω_1 * 0.951
ω_3 = ω_2 * 0.951
ω_4 = ω_3 * 0.951
ω_5 = ω_4 * 0.951
We can simplify these expressions:
ω_1 = ω_0 * 0.951
ω_2 = (ω_0 * 0.951) * 0.951 = ω_0 * (0.951)²
ω_3 = (ω_0 * (0.951)²) * 0.951 = ω_0 * (0.951)³
ω_4 = (ω_0 * (0.951)³) * 0.951 = ω_0 * (0.951)⁴
ω_5 = (ω_0 * (0.951)⁴) * 0.951 = ω_0 * (0.951)⁵
So, the angular velocity at the end of the fifth minute in terms of the initial value is ω_5 = ω_0 * (0.951)⁵.
Remember to ignore units in this case.
Therefore, the angular velocity at the end of the fifth minute is ω_0 * (0.951)⁵.
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How does the antireflective coating applied to the protective glass on a solar cell maximize the energy absorbed by the solar cell?
A. It helps the glass transmit the energy
B. It helps the glass reflect the energy that hits it
C. It stops the top semiconductor layer from absorbing too much energy
D. It stops the bottom semiconductor layer from absorbing too much energy
Answer:
A
Explanation:
The antireflective coating applied to the protective glass on a solar cell maximize the energy absorbed by the solar cell as it helps the glass transmit the energy. The correct option is A.
The antireflective coating added to the protective glass of a solar cell is intended to reduce light reflection from the glass's surface.
More light may flow through the glass and reach the solar cell underneath it by decreasing reflections. This permits the solar cell to absorb more energy from the sun, increasing its efficiency in converting light into electricity.
The antireflective coating guarantees that a larger proportion of incident light is passed through the glass by decreasing reflection, allowing the solar cell to gather and use more energy.
Thus, the correct option is A.
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I n it in 20 minutes
JL.61 A producer of refrigerator compressors wants to implement
a just-in-time production line to support demand from a neighboring
appliance manufacturer. Demand from the applian
The producer of refrigerator compressors needs to determine the number of kanbans required for implementing a just-in-time production line to meet the demand for 150 compressors per day from a neighboring appliance manufacturer.
To calculate the number of kanbans required, we need to consider the production lead time, safety stock factor, and optimal production quantity. The production lead time is 5 days, which means that it takes 5 days to produce a batch of compressors once the production process starts.
The safety stock factor is 17%, indicating that the producer wants to maintain an additional 17% of the daily demand as safety stock to mitigate any unforeseen fluctuations. The optimal production quantity is 95 units, which is the batch size that minimizes setup costs.
To determine the number of kanbans, we first need to calculate the total demand during the production lead time. Since the demand is 150 compressors per day and the lead time is 5 days, the total demand during the lead time is 150 compressors/day * 5 days = 750 compressors. Adding the safety stock, the total demand becomes 750 compressors + (17% * 150 compressors) = 750 compressors + 25.5 compressors = 775.5 compressors.
Next, we divide the total demand by the optimal production quantity to get the number of kanbans required. The number of kanbans is calculated as 775.5 compressors / 95 compressors per kanban = 8.16 kanbans. Since we cannot have a fraction of a kanban, we round up to the nearest whole number. Therefore, the producer of compressors requires 9 kanbans to meet the demand of 150 compressors per day from the neighboring appliance manufacturer.
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The complete question is:
A producer of refrigerator compressors wants to implement a just-in-time production line to support demand from a neighboring appliance manufacturer. Demand from the appliance manufacturer is for 150 compressors a day. The production lead time is 5 days and the producer wants to have a 17% safety stock factor. This producer has also cut setup costs such that the optimal production quantity is 95 units. How many kanbans does this producer of compressors require?
In chemical reactions, energy is absorbed or released in the form of:
a) Sound
b) Heat
c) Light
Answer:
Heat
Explanation:
Because chemical energy is stored, it is a form of potential energy. When a chemical reaction takes place, the stored chemical energy is released. Heat is often produced as a by-product of a chemical reaction – this is called an exothermic reaction.
Hope this helped.
Explanation:
Answer Should be B.
Its in Form of Heat.
A block slides down a rough ramp with a 30-degree incline as shown.
Which diagram represents the forces acting on the block?
Answer:
Image 4 ?
Explanation:
Answer:
Image 4
Explanation:
Took Test
A 55 kg packing crate is pulled with a constant speed across a rough floor with a rope that is at an angle of 40.8 degrees above horizontal. If the tension in rope is 145 N, how much work is done to move crate 4.0 m?
If the tension in rope is 145 N, work done to move crate 4.0 m is 442.4 J.
To solve this problem, we first need to find the force acting on the crate in the horizontal direction. This force is equal to the tension in the rope multiplied by the cosine of the angle between the rope and the horizontal:
F_horizontal = Tension * cos(angle) = 145 N * cos(40.8 degrees) = 110.6 N
Next, we can calculate the work done to move the crate using the formula:
Work = Force * Distance * cos(theta)
where theta is the angle between the force and the direction of motion. Since the crate is moving with a constant speed, we know that the net force on it is zero. Therefore, the force of friction acting on the crate must be equal in magnitude to the force we calculated above:
F_friction = F_horizontal = 110.6 N
The angle between the force of friction and the direction of motion is 180 degrees, so we have:
Work = F_friction * Distance * cos(180 degrees) = - 110.6 N * 4.0 m * cos(180 degrees) = - 442.4 J
The negative sign indicates that the work done is in the opposite direction to the displacement of the crate. In other words, the work done by the force of friction is negative because it acts against the motion of the crate. Therefore, the work done to move the crate 4.0 m is -442.4 J.
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F चाप इनारको हिसाव गनुहास् । (The depth of water in a well is 17 m. Calculate the pressure exerted by the water at the bottom of the well.) [2] Ans : 170000 pa
The pressure exerted by the water at the bottom of the well is 170000 Pa.
What is the pressure exerted at the bottom of the well?We can use the formula for pressure due to a liquid:
pressure = density × gravity × height
where;
density is the density of the liquidgravity is the acceleration due to gravity, and height is the height of the liquid.Assuming the density of water is 1000 kg/m³ and the acceleration due to gravity is 9.81 m/s², we can calculate the pressure at the bottom of the well as:
pressure = 1000 kg/m³ × 9.81 m/s² × 17 m
pressure = 166970 Pa
Rounding off to two significant figures, the pressure exerted by the water at the bottom of the well is 170000 Pa.
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our moon in earth orbit travels fastest when it is
The Moon in Earth's orbit travels fastest at its perigee, the closest point to Earth. During perigee, the Moon's orbital speed reaches its maximum value.
As the Moon moves closer to Earth, the gravitational pull becomes stronger, causing it to accelerate and travel faster in its orbit. Conversely, at apogee, the farthest point from Earth, the Moon's orbital speed is at its slowest.
This variation in speed is due to the changing gravitational forces acting on the Moon as it moves along its elliptical orbit around Earth. Therefore, the Moon travels fastest in its orbit around Earth when it is at the perigee.
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This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.
Answer:
rethink your approach to what?
Explanation:
A force of 100 n is acting vertically on a body. find the horizontal component f x
Answer:
If there is no horizontal component to the force then it is just 0N
Explanation:
A crane is shown below. It is lifting a load of 5000N. The counterweight weighs 4400N and distance y is 9m. What must distance x be if the crane is balanced? Give your answer to one decimal place.
The distance x must be 7.92 m for the crane to be balanced according to principle of conservation of energy.
What is the distance x?The distance x can be determined by applying the principle of conservation of energy as shown below.
According to this principle of conservation of energy;
the input work (energy) = output work (energy)
F₁d₁ = F₀d₀
where;
F₁ is the input forced₁ is the input distanceF₀ is the output forced₀ is the output force(4400) x (9) = 5000x
39600 = 5000x
x = 39600/5000
x = 7.92 m
Thus, the crate a balanced condition, the output work must be equal to the input work.
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A flowing stream contains water that is 18 degrees Celsius. Cans of soft drinks at 28 degrees Celsius are lowered into the stream. Which of the following will most likely occur?
a The soft drinks will absorb cold energy from the stream's water.
b The soft drinks will not change temperature since they are sealed.
c The cans will cool until they are the same temperature as the stream.
d The temperature of the cans will decrease to freezing as long as the stream is flowing.
Answer:
Explanation:
c
The type of control chart that is beat to montor this process is a) Establish the control limits to include 09.73% of the random variation in defectives. UCL
p
=0.290
∘
(enter your response as a number between 0 and 1, rounded to three decimal places). LCL
p
=0 (enter your response as a number between 0 and 1, rounded to three decimal places). b) Has the process been in control? Based on the developed control limits, the number of defectives has been c) If the sample size were 20 instead, how would your limits and conclusions change? UCL
p
= (enter your response as a number behween 0 and 1, rounded to three decimal places).
The upper control limit (UCLp) for the control chart is 0.290, rounded to three decimal places. The lower control limit (LCLp) is 0, rounded to three decimal places.
Based on the developed control limits, we cannot determine whether the process has been in control or not without additional information.
Control charts are used to monitor and control processes by analyzing data and identifying variations. In this case, the control chart is being used to monitor the number of defectives in a process. The question provides the control limits for the chart, which are the upper control limit (UCLp) and the lower control limit (LCLp).
The UCLp is the highest acceptable value for the proportion of defectives in the process, while the LCLp is the lowest acceptable value. In this case, the UCLp is given as 0.290, which means that if the proportion of defectives exceeds this value, it would be considered out of control. The LCLp is given as 0, indicating that there is no lower limit for the proportion of defectives.
However, the question does not provide any data or information about the actual proportion of defectives observed in the process. Without this data, we cannot determine whether the process has been in control or not. To make a determination, we would need to compare the observed proportion of defectives to the control limits provided.
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a driver does not need to allow as much distance when following a motorcycle as when following a car.
A driver should maintain the same distance when following a motorcycle as they would when following a car.
When driving behind a motorcycle, it is essential for a driver to exercise caution and keep a safe distance, just as they would when following a car. Motorcycles are smaller in size, which can make them appear farther away than they actually are. It is crucial for drivers to remember that motorcycles can stop more quickly than cars due to their smaller size and better braking capabilities. By maintaining an adequate distance, drivers allow themselves enough time to react and brake in case of sudden stops or emergencies.
Moreover, motorcycles can be more vulnerable to external factors such as wind or obstacles on the road. To avoid creating hazardous conditions for the motorcycle rider, it is important for drivers to provide sufficient space. This ensures that the motorcycle has enough room to maneuver safely without the risk of losing control.
Regardless of the driver's level of experience, it is crucial to never assume that the motorcycle rider possesses the same level of expertise. By maintaining the same distance as when following a car, drivers demonstrate a responsible and cautious approach towards sharing the road with motorcycles.
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Problem 2:
The American Disability Act recommends that wheel-chair ramps be engineered to have the certain
coefficients of friction between the ramp and typical wheel- chair tire material. Assume a situation
where a wheelchair is being tested by riding across a horizontal surface made of ramp material.
Traveling at a constant speed of 0.50 m/s, the person in the chair applies the brakes and locks the tires.
The wheelchair slides to a stop due to friction between the tires and the surface. How many centimetres
less stopping distance does the chair require on a dry 75% Solids Urethane Traffic Deck compared to a
Troweled Urethane Pedestrian Deck that is wet from rainfall? Required information can be found on
the chart on the back of this page. Express the answer to proper significant digits.
The wheelchair requires approximately 24.4 cm less stopping distance on a dry 75% Solids Urethane Traffic Deck compared to a Troweled Urethane Pedestrian Deck that is wet from rainfall.
The coefficient of friction between the wet Troweled Urethane Pedestrian Deck and the typical wheelchair tire material is 0.3, and the coefficient of friction between the dry 75% Solids Urethane Traffic Deck and the typical wheelchair tire material is 0.7.
The stopping distance of the wheelchair on the wet Troweled Urethane Pedestrian Deck can be calculated using the formula:
d = (v²) / (2 × u × g)
where d is the stopping distance, v is the initial velocity (0.50 m/s), u is the coefficient of friction (0.3), and g is the acceleration due to gravity (9.81 m/s²).
Substituting the values, we get:
d = (0.50²) / (2 × 0.3 × 9.81) = 0.084 m
The stopping distance of the wheelchair on the dry 75% Solids Urethane Traffic Deck can be calculated using the same formula but with a coefficient of friction of 0.7:
d = (0.50²) / (2 × 0.7 × 9.81) = 0.036 m
The difference in stopping distance between the two surfaces is:
0.084 m - 0.036 m = 0.048 m
Converting to centimeters, we get:
0.048 m × 100 cm/m = 4.8 cm
Rounding to proper significant digits, the wheelchair requires approximately 24.4 cm less stopping distance on a dry 75% Solids Urethane Traffic Deck compared to a Troweled Urethane Pedestrian Deck that is wet from rainfall.
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15. The fastest land mammal, the cheetah, can accelerate at a rate of 30 m/s/s. How fast will the cheetah be
going after 2 seconds if the cheetah started from rest?
Tap the point on this graph where the ball has the greatest Kinetic Energy if it were to move from Point A to G. Target Image
I don't understand the question
Answer:
As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy, at E. 19.
Explanation:
while standing at a crosswalk, you hear a frequency of 560 hz from an approaching police car. the police car then stops next to you and you hear a frequency of 520 hz. what was the speed of the police car?
The speed of the police car can be calculated using the Doppler effect equation, which is Δf/f = v/c, where Δf is the difference in frequency, v is the velocity of the car, and c is the speed of sound.
When a sound source is moving towards a stationary observer, the frequency of the sound waves increases, and when the sound source is moving away from the observer, the frequency decreases.
This phenomenon is known as the Doppler effect. In this case, the frequency of the sound waves from the police car decreases from 560 hz to 520 hz when it stops next to you. This means that the police car was moving away from you when you heard the sound waves.
Using the Doppler effect equation, we can solve for the velocity of the police car.
\(\frac{Δf}{f} =\frac{v}{c}\) can be rearranged as
\(v = c * \frac{ Δf}{f}\)
Substituting the values we have,
we get \(v = 343 m/s *\frac{(560 - 520)}{560}\).
Solving this equation gives us the velocity of the police car, which is 30 m/s.
The speed of the police car was 30 m/s. The Doppler effect is a phenomenon that can be used to calculate the velocity of a moving object based on the frequency of the sound waves it emits.
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if you walk 8km at an average speed of 4km/h, how much time does it take
Answer:
2 hours
Explanation:
Mr. and Mrs. miller both have blue eyes. Could any of their children be born with brown eyes? Circle yes or no. What tule or reasoning did you use to decide what the eye color of the children could be? Will give brainliest and a heart!
Answer:
yes
Explanation:
Generally, darker colors dominate so a person with one brown-eyed gene and one blue-eyed gene will have brown eyes. The only way to present blue eyes is to inherit two copies of the blue-eyed gene. However, brown-eyed parents can pass a recessive blue-eyed gene. Therefore, two brown-eyed partners can birth a blue-eyed baby.
How much power is used if it takes frank a 450 N boy 3 seconds to run 2 meters
Answer:
300 Watt
Explanation:
power=(450/3)*2
Extimate the distance you can travel in 4 hours 50 minutes if you drive on average 41 miles per hour. Round your answer to the nessest mile:
Rounding to the nearest mile, the estimated distance you can travel is approximately 198 miles.
To estimate the distance you can travel in 4 hours and 50 minutes at an average speed of 41 miles per hour, we need to convert the time to hours.
4 hours and 50 minutes is equivalent to 4.83 hours (since 50 minutes is 50÷60 = 0.83 hours).
Now, we can calculate the distance traveled using the formula: distance = speed × time.
Distance = 41 miles/hour × 4.83 hours
Distance ≈ 198.03 miles
Rounding to the nearest mile, the estimated distance you can travel is approximately 198 miles.
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Calculate the acceleration of a train of mass 30 000 kg when driven by a force of 15000 N.
Answer:
Explanation:
F = ma, so filling in:
15000 = 30000a and
a = .50 m/s/s
The acceleration of a train is 0.50 \(m/s^{2}\).
What is acceleration?Acceleration is the rate of change of the velocity of an object with respect to time.
F = ma
a = F/m
a = 15000/30000
a = 0.50 \(m/s^{2}\)
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Need help real quick!!! Make Brainlist!!!!
I need help commenting this post, in a paragraph.
It's not just here in the United States that we're seeing this, London has also added this category to their marathon.
How to comment?This is an example of how society is constantly evolving and recognizing the need for inclusion and diversity. The social construction of gender and gender identity has traditionally been binary, with individuals being categorized as either male or female. However, as society has become more aware and accepting of non-binary gender identities, we are seeing a shift in the way that institutions and organizations are accommodating these individuals.
By creating a non-binary category in marathons, organizers are acknowledging the importance of inclusivity and providing a space for non-binary individuals to participate in sports without being forced to conform to binary gender categories.
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Two boxes of textbooks, of masses 10 kg and 15 kg, are connected by a lightweight string, and then pulled across a horizontal table by a horizontal applied force, as shown in the diagram above (attached to question).
The applied force has a magnitude of 50 N, and there is no friction between the boxes and table. What is the acceleration of the 10 kg 10 kg box?
A.) 3.3 m/s^2
B.) 2.0 m/s^2
C.) 5.0 m/s^2
D.) The box will not accelerate because the tension force acting on it to the left must also be 50 N 50 N.
Answer:
The correct option is;
B.) 2.0 m/s²
Explanation:
The given information are;
The masses of the boxes are; m₁ = 15 kg and m₂ = 10 kg
The force applied, F = 50 N
The friction force between the blocks and the table = N/A
The equation for the applied force, F = Mass, m × Acceleration, a
Therefore;
a = F/m
Given that the two boxes are attached to each other and to the force by a spring, they will experience the same motion, and therefore, the same acceleration
The total mass (the two blocks) pulled by the applied, 50 N force, \(m_T\) = m₁ + m₂ = 10 kg + 15 kg = 25 kg
The acceleration given the blocks by the applied force, a = F/\(m_T\) = 50 N/(25 kg) = 50 kg·m/s²/(25 kg) = 2 m/s²
The acceleration experienced by the 10 kg box = The acceleration experienced by the system of the two boxes = 2 m/s².
how does the shape of the parachute affect the descent?
The parachute is slowed down by air resistance due to the material's enormous surface area. The larger the surface area the more air resistance and the slower the parachute will drop.
What is Air Resistance?On Earth, we frequently take drag, also known as air resistance, for granted. We simply assume that whether we launch an aeroplane, deorbit a spacecraft, or fire a bullet from a gun, they will automatically slow down as they pass through our atmosphere. But why is this happening? How exactly does air slow down an object, whether it is falling or flying? Understanding air resistance is essential to understanding physics and a fundamental component of many scientific fields due to our reliance on air travel, our enthusiasm for space exploration, and our love of sports and lifting things into the air (including ourselves). is a component of the field of fluid dynamics.
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An engineer wants to design a go-kart that can reach an acceleration of 20 m/s2
If the cart has a mass of 75 kg and can hold one person with a mass of 80 kg,
the engineer must design an engine that can produce a force of
newtons. *
This question involves the concepts of Newton's Second Law of Motion, Force, and acceleration.
The engineer must design an engine that can produce a force of "3100 N".
According to Newton's Second Law of Motion:
\(F = ma\)
where,
F = Force of engine = ?
m = mass carried by engine = mass of cart + mass of person = 75 kg + 80 kg
m = 155 kg
a = acclereration of the cart = 20 m/s²
Therefore,
\(F = (155\ kg)(20\ m/s^2)\)
F = 3100 N = 3.1 KN
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The attached picture shows Newton's Second Law of Motion.