Element x decays radioactively with a half life of 15 minutes. if there are 960 grams of element x, how long, to the nearest tenth of a minute, would it take the element to decay to 295 grams?


y=a(.5)^(t/h)

Answer:

Step-by-step explanation:

I won't be answering the question but i will explain how to do it.

So....

.1 is 1/10 of 1.

.3 is 3/10 of 1.

MEANING .1 is smaller than 3.

1/2 is SMALLER than 3/4.

1/2 is equal to 2/4.

.85 is EQUAL to 85/100 rounded up to 9/10 making it larger than numbers such as .79 and 1/2.

PLZ MARK BRAINLIEST!!!

A Negative correlation coefficient means that as one variable increases, the other decreases (i.e., an inverse relationship).

Answer:

3.5555555555556

Step-by-step explanation:

you cannot find the Mean Absolute Deviation of one number. This answer is the data set 2, 9, and 0. 3.5555555555556 is the Mean Absolute Deviation of 2, 9, 0.

Answer:

58% left

Step-by-step explanation:

He drinks 5oz.

12-5 = 7oz (which is how much he has left)

7 / 12 = 0.58333 -> 58%

sin x = cos (90 - x) or cos x = sin (90 - x)

This identity holds when the two angles are complementary

i.e. they sum up to 90 degrees.

The value of x is 35°

There are three commonly used trigonometric identities.

Sin x = 1/ cosec x

Cos x = 1/ sec x

Tan x = 1/ cot x or sin x / cos x

Cot x = cos x / sin x

We have,

cos x° = sin (20° + x°), where 0 < x < 90

We know that,

sin x = cos (90 - x) or cos x = sin (90 - x)

This identity holds when the two angles are complementary

i.e. they sum up to 90 degrees.

x + 90 - x = 90

Now,

cos x = sin (20 + x)

x + 20 + x = 90

2x + 20 = 90

2x = 70

x = 35

Thus,

The value of x is 35°

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The probability that at least 25 of the 29 customers have looked at their credit score in the past six months is:

P(X ≥ 25) = sum(P(X = i)) i = 25 to 29

This is a question of probability and statistics, specifically in the area of binomial distributions. The probability of a single event can be calculated using the binomial probability formula:

P(X = k) = (n choose k) * p^k * (1-p)^(n-k)

X = the number of successful outcomes (in this case, the number of customers who have looked at their credit score in the past six months)

k = the number of successful outcomes we want to know the probability of (in this case, 25)

n = the total number of trials or customers (in this case, 29)

p = the probability of a successful outcome (in this case, 0.67 or 67%)

        P(X ≥ k) = sum(P(X = i)) i = k to n

        P(X ≥ 25) = sum(P(X = i)) i = 25 to 29

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Oooooooioooooooooooo

Answer:

b

Step-by-step explanation:

Answer:

x_6x=21_15_3x/. x+6x=21+15+3x

Step-by-step explanation:

To plot the function g(x) = cos(x) + x\(e^{-x\) in Octave, you can follow some steps.

Open Octave or GNU Octave in your preferred environment.

Define the function g(x) using an anonymous function syntax:

g = (x) cos(x) + x.*exp(-x);

Set the range of x values for the plot. In this case, we'll use x ranging from -2pi to 2pi:

x = linspace(-2*pi, 2*pi, 1000);

Plot the function using the defined range of x values:

plot(x, g(x));

Customize the plot by adding a title, labeling the axes, and displaying a grid:

title("Plot of g(x) = cos(x) + xe^{-x}");

xlabel("x");

ylabel("g(x)");

grid on;

Display the plot.

After executing these steps, you should see a plot of the function g(x) = cos(x) + x\(e^{-x\) with the specified window size, title, labeled axes, and grid.

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To determine the amount that 60% or more of all 1 bedroom apartments in Freeburg would rent for, we can use the concept of standard deviations.

Given that the average rent for a 1 bedroom apartment in Freeburg is $295 and the standard deviation is $25, we can determine the rent threshold for 60% or more of all apartments.

To find the threshold, we need to calculate the Z-score corresponding to the desired percentile. The Z-score measures how many standard deviations a data point is from the mean. The Z-score formula is given by (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation.

To find the Z-score for the 60th percentile, we look up the corresponding value in the Z-table. The Z-table provides the area under the normal distribution curve up to a certain Z-score. In this case, we want to find the Z-score that corresponds to an area of 0.60.

Assuming a normal distribution, a Z-score of approximately 0.253 corresponds to the 60th percentile.

Using the formula (Z-score * standard deviation) + mean, we can calculate the rent threshold: (0.253 * $25) + $295 = $301.325.

Therefore, 60% or more of all 1 bedroom apartments in Freeburg would rent for approximately $301.325 or higher.

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Answer:

133.33, 200, 266.66

Step-by-step explanation:

GIven data

This is a ratio problem, and we will use the part to all method to get the solution

The given ratio is

= 2: 3: 4​

the total ratio

=2+3+4

=9

Hence the first part is

2/9= x/600

cross multiply

9x= 1200

x= 1200/9

x= 133.33

The second part

3/9=x/600

1/3=x/600

3x=600

x=200

The third part

4/9=x/600

4/9=x/600

9x=600*4

9x=2400

x=2400/9

x=266.66

Therefore the figures are

133.33, 200, 266.66

Answer:

D)24˚

Step-by-step explanation:

Since you know a full turn is 360˚ since we need to find "b"

we add 41˚ with 295˚

which is 336

then subtract 360 with 336

which is 24˚

So the answer is D) 24˚

Hope this helps!

Answer:

hi there user!

The correct answer should be option D!

Step-by-step explanation:

circle angle: 360 degrees

360 - (295 + 41) =

360 - 336 =

24

hope this helped qwq

The drum should have a radius of approximately 6.32 yards and a height of approximately 6.02 yards to minimize the cost of construction.

Let's denote the height of the drum by 'h' and the radius by 'r'. We must determine the drum's measurements to reduce material costs.

V=r2h is the formula for a cylinder's volume.  We know that the capacity of the drum is 861 cubic yards. Thus, 861 = πr²h.

To minimize the cost, we need to find the minimum cost of material used for the drum. The cost of the top and bottom is $19 per square yard, and the cost of the side is $6 per square yard. The top and bottom of the drum are circles with area πr² each, and the side of the drum is a rectangle with area 2πrh. Thus, the cost of material is given by C = 19πr² + 9πr² + 12πrh.

Using the equation for the volume of the drum, we can substitute for h and obtain the cost function in terms of r. We can then find the derivative of the cost function with respect to r and set it equal to zero to find the critical value of r that minimizes the cost. We get at r = 6.32 yards by solving for r.

Substituting r = 6.32 yards into the equation for the volume of the drum, we obtain h = 6.02 yards.

Thus, the drum with dimensions of radius 6.32 yards and height 6.02 yards can be constructed at minimum cost.

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The expected number of empty bins when tossing n balls into n bins, with each toss being independent and equally likely, can be determined using the concept of probability.

Let's define the probability that a specific bin remains empty after n tosses as P(empty). Since each ball has n choices, there are n^n possible ways to distribute the balls. To find the probability that a specific bin is empty, we can consider the situation where balls can be tossed into the remaining n-1 bins, resulting in (n-1)^n possible distributions. Therefore, P(empty) = ((n-1)^n) / (n^n).

Now, to calculate the expected number of empty bins, we can use the concept of linearity of expectation. The expected value of the sum of random variables is equal to the sum of the expected values of the individual random variables. In this case, the random variables represent the empty status of each bin (1 if empty, 0 if not).

The expected number of empty bins is the sum of the probabilities of each bin being empty, which is n * P(empty). So, the expected number of empty bins = n * (((n-1)^n) / (n^n)).

Using this formula, you can determine the expected number of empty bins when n balls are tossed into n bins independently and with equal likelihood.

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The basis for the vector space of polynomials of degree at most 4 and constant term equal to zero is {x, x², x³, x⁴}.

Let us represent each polynomial in the following format:P(x) = a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀

The degree of the polynomial is 4.

So, the highest power of x that appears in the polynomial is x⁴.

And it has to have a constant term equal to zero.

Therefore, a₀=0.

Let us define the coefficients of P(x) as a vector: a = [a₄ a₃ a₂ a₁ a₀]T.

ere, T represents the transpose of a.

Then, the vector space of polynomials of degree at most 4 and constant term equal to zero is the subspace of the vector space of all polynomials. This subspace is denoted by P₄. And its basis is {x, x², x³, x⁴}.

It is clear that {x, x², x³, x⁴} is linearly independent. This is because there is no non-zero linear combination of x, x², x³, and x⁴ that gives the zero polynomial with a constant term equal to zero.

To show that {x, x², x³, x⁴} spans P₄, we need to show that any polynomial of degree at most 4 and constant term equal to zero can be written as a linear combination of x, x², x³, and x⁴.

Let P(x) be an arbitrary polynomial of degree at most 4 with a constant term equal to zero.

So, P(x) = a₄x⁴ + a₃x³ + a₂x² + a₁x.

Now we have to express P(x) as a linear combination of x, x², x³, and x⁴.P(x) = a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀ * 0= a₄x⁴ + a₃x³ + a₂x² + a₁x + 0x

Therefore, P(x) is a linear combination of x, x², x³, and x⁴.

Thus, {x, x², x³, x⁴} is the basis for the vector space of polynomials of degree at most 4 and constant term equal to zero.

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Dodie's triangular plot with 160 rose plants will have 12 rows.

To solve it,

Assigning a variable to the number of rows we want to find. Assume that this variable is "n".

Since there are 5 more plants in each row than in the previous row,

We can use an arithmetic sequence to represent the number of plants in each row.

Specifically, the first row will have 1 plant, and the second row will have

1 + 5 = 6 plants, the third row will have 1 + 5 + 5 = 11 plants, and so on.

The formula for an arithmetic sequence is,

an = a1 + (n-1)d

Where an is the nth term of the sequence,

a1 is the first term,

And d is a common difference.

Using this formula, we can write an expression for the total number of plants in all n rows,

160 = n/2 (2 + (n-1)5)

Simplifying this equation, we get,

160 = 2.5n² + 2.5n - 5

Now we can solve for n using the quadratic formula,

n = (-2.5 ± √(2.5²+ 4(2.5)(165)))/(2(2.5))

After simplifying this equation, we get two solutions,

n = -13.2 and n = 12.2.

Since we can't have a negative number of rows, we'll take the positive solution, n = 12.2.

Now, since we can't have a fraction of a row, we'll round down to the nearest integer.

Therefore, Dodie's plot will have 12 rows.

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The solution to the inequality is: x >= 55 or x <= -32.

what is inequality?

An inequality is a mathematical statement that compares two values or expressions and indicates that they are not equal. In other words, an inequality shows the relationship between two values or expressions that are not the same.

To solve the inequality, we need to isolate x on one side of the inequality symbol in each of the two inequalities.

For the first inequality:

3 - 2/5 * x <= -19

Subtracting 3 from both sides, we get:

-2/5 * x <= -22

Dividing both sides by -2/5 (which is the same as multiplying both sides by -5/2), we get:

x >= 55

For the second inequality:

-3/4 * x >= 24

Dividing both sides by -3/4 (which is the same as multiplying both sides by -4/3), we get:

x <= -32

Therefore, the solution to the inequality is:

x >= 55 or x <= -32.

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45 percent of the 8th graders estimated they spend less than an hour a day on social media. The solution has been obtained by using concept of frequency.

What is frequency?

The frequency of a specific value in a set of data is how frequently it appears. Typically, we would keep track of data frequency in a frequency table.

We are given that 17 8th graders spent more than an hour a day on social media and 14 8th graders spent less than an hour a day on social media.

The total 8th graders who spent time on social media is 14 + 17 = 31

The percentage of the 8th graders estimated they spend less than an hour a day on social media is

= 14*100/31

= 45.16%

= 45%

Hence, 45 percent of the 8th graders estimated they spend less than an hour a day on social media.

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The name for a data value that is far above or below the rest is called an outlier.

An outlier is an observation that deviates significantly from other observations in a dataset. It is an extreme value that lies outside the typical range of values and may have a disproportionate impact on statistical analyses and calculations. Outliers can occur due to various reasons, including measurement errors, data entry mistakes, or genuine rare events. Identifying and handling outliers appropriately is important in data analysis to ensure accurate and reliable results.

When dealing with outliers, it is important to assess whether they are the result of errors or genuine extreme values. Statistical techniques, such as box plots, scatter plots, or z-scores, can be used to detect outliers. Once identified, the appropriate action depends on the nature and cause of the outliers. In some cases, outliers may need to be corrected or removed from the dataset, while in other cases, they may provide valuable insights or require further investigation.

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a) 35 x 13 + 3.14 x \(\frac{13}{2}\)²

= 455 + 3.14 x 42.25

= 455 + 132.665

= 587.665 m²

∴ The area is  587.665 m².

a.gcd(56, 42) = 14, and a linear combination of 56 and 42 is 14 = 56 × 2 - 42 × 1.

b.gcd(81, 60) = 3, and a linear combination of 81 and 60 is 3 = 21 × 5 - 60 × 1.

c. gcd(153, 117) = 9, and a linear combination of 153 and 117 is 9 = 117 × (-3) + 153 × 4.

d. gcd(259, 77) = 7, and a linear combination of 259 and 77 is 7 = 259 × 5 - 77 × 16.

e.gcd(72, 42) = 6, and a linear combination of 72 and 42 is 6 = 72 × (-2) + 42 × 7.

Given are the following pairs of numbers: (a) 56 and 42 (b) 81 and 60 (C) 153 and 117 (d) 259 and 77 (e) 72 and 42

a) 56 and 42:

To find gcd of 56 and 42, we use the Euclidean algorithm:

\($$\begin{aligned} 56 &= 42 \times 1 + 14 \\ 42 &= 14 \times 3 + 0 \end{aligned}$$\)

So gcd(56, 42) = 14

To find a linear combination of 56 and 42, we use the extended Euclidean algorithm:

\($$\begin{aligned} 56 &= 42 \times 1 + 14 \\ 42 &= 14 \times 3 + 0 \\ 14 &= 56 - 42 \times 1 \\ &= 56 - (56 - 42) \times 1 \\ &= 56 \times 2 - 42 \times 1 \end{aligned}$$\)

Therefore, gcd(56, 42) = 14, and a linear combination of 56 and 42 is 14 = 56 × 2 - 42 × 1.

b) 81 and 60:

To find gcd of 81 and 60, we use the Euclidean algorithm:

\($$\begin{aligned} 81 &= 60 \times 1 + 21 \\ 60 &= 21 \times 2 + 18 \\ 21 &= 18 \times 1 + 3 \\ 18 &= 3 \times 6 + 0 \end{aligned}$$\)

So gcd(81, 60) = 3

To find a linear combination of 81 and 60, we use the extended Euclidean algorithm:

\($$\begin{aligned} 81 &= 60 \times 1 + 21 \\ 60 &= 21 \times 2 + 18 \\ 21 &= 18 \times 1 + 3 \\ 18 &= 3 \times 6 + 0 \\ 3 &= 21 - 18 \times 1 \\ &= 21 - (60 - 21 \times 2) \times 1 \\ &= 21 \times 5 - 60 \times 1 \end{aligned}$$\)

Therefore, gcd(81, 60) = 3, and a linear combination of 81 and 60 is 3 = 21 × 5 - 60 × 1.

C) 153 and 117: To find gcd of 153 and 117, we use the Euclidean algorithm:

\($$\begin{aligned} 153 &= 117 \times 1 + 36 \\ 117 &= 36 \times 3 + 9 \\ 36 &= 9 \times 4 + 0 \end{aligned}$$\)

So gcd(153, 117) = 9

To find a linear combination of 153 and 117, we use the extended Euclidean algorithm:

\($$\begin{aligned} 153 &= 117 \times 1 + 36 \\ 117 &= 36 \times 3 + 9 \\ 36 &= 9 \times 4 + 0 \\ 9 &= 117 - 36 \times 3 \\ &= 117 - (153 - 117 \times 1) \times 3 \\ &= 117 \times (-3) + 153 \times 4 \end{aligned}$$\)

Therefore, gcd(153, 117) = 9, and a linear combination of 153 and 117 is 9 = 117 × (-3) + 153 × 4.

d) 259 and 77:

To find gcd of 259 and 77, we use the Euclidean algorithm:

\($$\begin{aligned} 259 &= 77 \times 3 + 28 \\ 77 &= 28 \times 2 + 21 \\ 28 &= 21 \times 1 + 7 \\ 21 &= 7 \times 3 + 0 \end{aligned}$$\)

So gcd(259, 77) = 7

To find a linear combination of 259 and 77, we use the extended Euclidean algorithm:

\($$\begin{aligned} 259 &= 77 \times 3 + 28 \\ 77 &= 28 \times 2 + 21 \\ 28 &= 21 \times 1 + 7 \\ 21 &= 7 \times 3 + 0 \\ 7 &= 28 - 21 \times 1 \\ &= 28 - (77 - 28 \times 2) \times 1 \\ &= 28 \times 5 - 77 \times 1 \\ &= (259 - 77 \times 3) \times 5 - 77 \times 1 \\ &= 259 \times 5 - 77 \times 16 \end{aligned}$$\)

Therefore, gcd(259, 77) = 7, and a linear combination of 259 and 77 is 7 = 259 × 5 - 77 × 16.

e) 72 and 42: To find gcd of 72 and 42, we use the Euclidean algorithm:

\($$\begin{aligned} 72 &= 42 \times 1 + 30 \\ 42 &= 30 \times 1 + 12 \\ 30 &= 12 \times 2 + 6 \\ 12 &= 6 \times 2 + 0 \end{aligned}$$\)

So gcd(72, 42) = 6To find a linear combination of 72 and 42, we use the extended Euclidean algorithm:

\($$\begin{aligned} 72 &= 42 \times 1 + 30 \\ 42 &= 30 \times 1 + 12 \\ 30 &= 12 \times 2 + 6 \\ 12 &= 6 \times 2 + 0 \\ 6 &= 30 - 12 \times 2 \\ &= 30 - (42 - 30 \times 1) \times 2 \\ &= 42 \times (-2) + 30 \times 3 \\ &= (72 - 42 \times 1) \times (-2) + 42 \times 3 \\ &= 72 \times (-2) + 42 \times 7 \end{aligned}$$\)

Therefore, gcd(72, 42) = 6, and a linear combination of 72 and 42 is 6 = 72 × (-2) + 42 × 7.

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Answer:

you need to take a better picture nobody can see that i not trying be be rude

Step-by-step explanation:

Answer:

upload clear picture, it is very easy

Step-by-step explanation:

Your answer is False

The probability of winning $1000 a day for life is approximately 5.245 x 10^-11 and the probability of winning $1000 a week for life is approximately 1.07 x 10^-8. The probability of winning the jackpot ($1000 a day for life) is 1/(60^5 * 4), while the probability of winning $1000 a week for life is 1/(60^5).

In the Florida Lottery Cash4Life game, a player must select five numbers from 1 to 60 and then one Cash Ball number from 1 to 4. The jackpot prize is $1000 a day for life if all five numbers and the Cash Ball match the winning numbers drawn on Monday nights. If just all five numbers match the winning numbers, the player will win $1000 a week for life.
To determine the probability of winning $1000 a day for life, we can use the formula for the probability of independent events: P(A and B) = P(A) x P(B)

(a) To win the jackpot of $1000 a day for life, the player needs to match all five numbers and the Cash Ball. There are 60 options for each of the five numbers and 4 options for the Cash Ball. The total number of possible outcomes is 60^5 (60 choices for each of the five numbers) times 4 (for the Cash Ball). So the probability of winning the jackpot is 1/(60^5 * 4). (b) To win $1000 a week for life, the player needs to match only the five numbers, without considering the Cash Ball. The total number of possible outcomes for this scenario is 60^5. Therefore, the probability of winning $1000 a week for life is 1/(60^5).

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The resulting fraction is 35/12..Converting the fraction back to a mixed number, we find that 35/12 is equal to 2 and 11/12.Comparing this result to 2 and k/12, we can see that k = 11.5 and 2/3 minus 2 and 3/4 equals 2 and 11/12, where k = 11.

To prove that 5 and 2/3 minus 2 and 3/4 is equal to 2 and k/12, we'll perform the necessary operations to determine the value of k.

First, let's convert the mixed numbers into improper fractions:5 and 2/3 can be written as (3*5 + 2)/3 = 17/3.

2 and 3/4 can be written as (4*2 + 3)/4 = 11/4.

Now, subtracting these fractions: (17/3) - (11/4).

To find the common denominator, we multiply the denominators: 3 * 4 = 12.Rewriting the fractions with the common denominator, we have: (68/12) - (33/12).Subtracting the numerators, we get: 68 - 33 = 35.

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The missing part of the equation is \(-7.0\times10^4 s^2kg⋅m^2 / 1000000.\)

To fill in the missing part of the equation, let's analyze the given information and the desired conversion. The equation is:

\((-7.0\times 10^4 s^2g⋅m^2)\cdot \pi = ? s^2kg\cdot m^2\)

In this equation, we have a quantity expressed in\(s^2g\cdot m^2\) units on the left-hand side. To convert it to \(s^2kg\cdot m^2\) units, we need to multiply it by a conversion factor.

To perform the conversion, we can use the fact that 1 kg is equal to 1000 g. Therefore, the conversion factor we need is:

1 kg / 1000 g

To ensure that the units cancel out correctly, we need to square this conversion factor because we have \(s^2g\cdot m^2\) on the left-hand side. So the missing part of the equation is:

\((-7.0\times 10^4 s^2g\cdot m^2)\cdot \pi = (-7.0\times 10^4 s^2g\cdot m^2)\cdot (1 kg / 1000 g)^2\)

Simplifying this expression, we get:

\((-7.0\times10^4 s^2g\cdot m^2)\cdot \pi = -7.0 \times10^4 s^2kg\cdot m^2 / 1000000\)

Therefore, the missing part of the equation is \(-7.0 \times 10^4 s^2kg\cdot m^2 / 1000000.\)

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Answer:

73urur

Step-by-step explanation:

ndndndnfnnfnfjgjfjf

Answer:

-0.5

Step-by-step explanation:

x=-23÷46

x=-0.5

that's the answer :)

you should try to keep it under 5 minutes.

since there will be easier ones and harder ones, its ok to take up to 10 minutes on a test as long a you try to get the easy ones done first. if you can skip questions then go back to them later, do the hardest ones first thengo back and do the easier ones afterwards.

Try to take your time when you need to. if you get stuck, think about what it says. Try to think of it another way. You also want to get as much done as you can, this is because if you miss 5-10 questions, the grade could be seriously decreased, as you might have gotten a few other questions wrong.

Make sure to do a "QC" as I call it; or a "Quick Check." If it looks good and it's reasonable then you are fine to move on. it it doesnt look right, retrace your steps. Then rewrite it if you got something else on your next try for the QC.

I hope you do good!

May luck be with you!

Answer:

TWO PAIR OF VERTICAL ANGLES ARE

D,C

A,R