Answer:
The maximum magnetic force is 2.637 x 10⁻¹² N
Explanation:
Given;
Power, P = 8.25 m W = 8.25 x 10⁻³ W
charge of the radiation, Q = 1.12 nC = 1.12 x 10⁻⁹ C
speed of the charge, v = 314 m/s
area of the conecntration, A = 1.23 mm² = 1.23 x 10⁻⁶ m²
The intensity of the radiation is calculated as;
\(I = \frac{P}{A} \\\\I = \frac{8.25 \times 10^{-3} \ W}{1.23 \ \times 10^{-6} \ m^2} \\\\I = 6,707.32 \ W/m^2\)
The maximum magnetic field is calculated using the following intensity formula;
\(I = \frac{cB_0^2}{2\mu_0} \\\\B_0 = \sqrt{\frac{2\mu_0 I}{c} } \\\\where;\\\\c \ is \ speed \ of \ light\\\\\mu_0 \ is \ permeability \ of \ free \ space\\\\B_0 \ is \ the \ maximum \ magnetic \ field\\\\B_0 = \sqrt{\frac{2 \times 4\pi \times 10^{-7} \times 6,707.32 }{3\times 10^8} } \\\\B_0 = 7.497 \times 10^{-6} \ T\)
The maximum magnetic force is calculated as;
F₀ = qvB₀
F₀ = (1.12 x 10⁻⁹) x (314) x (7.497 x 10⁻⁶)
F₀ = 2.637 x 10⁻¹² N
A long, straight conveyor belt at a sushi restaurant carries sushi past customers with a constant velocity. If the sushi roll you want is 4.30 m to the right of you 11.0 s after exiting the little door at the beginning of the conveyor belt, and it is still 2.10 m to the right of you 10.0 s later, how far is the little door to the right of you?
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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You are pulling a wagon with a mass10kg and it’s moving forward at a constant rate. Your friend gets into the wagon and it’s slows down. What can you do to get the wagon moving faster?
Explanation:
Without changing the constant speed, your friend can empty the contents of the wagon, or decrease the overall rate, or the terrain the wagon is traveling on, all of these would increase the wagon's speed. Also, you could try applying a heavier pulling force, like using a horse instead of yourself, or you and a horse to get going faster.
Hope this helps!
HELP GIVING BRAINLIEST TO PERSON WHO ANSWERS ALL QUESTIONS.
Use the words in the box to complete the sentences below.
reaction
malleable
gaseous
dense
drag
alloy
gravity
catalyst
electromagnetic
8. Give one specific example each of a physical change and a chemical change.
9. Oxidation is a
change that involves oxygen and other matter.
10. When aluminum is exposed to air and water, a thin layer of aluminum oxide forms on the surface.
Why is this oxidation helpful?
11. Choose a sport, and then describe how friction, gravity, and inertia affect the action.
12. List these forms of electromagnetic energy in order from longest to shortest wavelength:
microwaves, ultraviolet light, gamma rays, radio waves, sound, X-rays, visible light.
13.
14. Acid acts as a
15. Rust is a chemical
is an attractive force that exists between any two pieces of matter.
to increase the speed of oxidation.
16. Stainless steel is an iron, carbon, and chromium
that involves iron and oxygen.
that doesn't rust.
it is.
because their atoms have strong but flexible bonds.
pressure that balances the pressure created
17. Whether an object floats or sinks is determined by how
18. Metals are
19. Air inside our bodies exerts
by Earth's atmosphere.
20. Airplanes in flight have to overcome
created by gases in the atmosphere.
21. The shortest wavelengths of
energy are the most dangerous.
Give one specific example each of a physical change and a chemical change.
Physical change: Ice melting into water
Chemical change: Burning wood to ash
Oxidation is a chemical change that involves oxygen and other matter.
When aluminum is exposed to air and water, a thin layer of aluminum oxide forms on the surface. This oxidation is helpful because the oxide layer acts as a protective coating and prevents further corrosion of the aluminum.
Sport: Basketball
Friction: When players try to stop or change direction, the friction between their shoes and the court helps them do so.
Gravity: The force of gravity pulls the basketball downwards, and players have to jump to reach it.
Inertia: A player in motion tends to stay in motion, so when a player dribbles the ball and then suddenly stops, the ball may bounce off their hands because of their inertia.
List these forms of electromagnetic energy in order from longest to shortest wavelength:
Radio waves, microwaves, visible light, ultraviolet light, X-rays, gamma rays.
A catalyst is a substance that speeds up a chemical reaction without being consumed itself.
Acid acts as a corrosive substance and can dissolve certain materials.
Rust is a chemical change that involves iron and oxygen.
Stainless steel is an alloy of iron, carbon, and chromium that doesn't rust. It is helpful because it is resistant to corrosion and is commonly used in kitchen utensils and appliances.
Whether an object floats or sinks is determined by how dense it is. If an object is less dense than the liquid it is placed in, it will float. If it is more dense, it will sink.
Metals are malleable because their atoms have strong but flexible bonds. This allows them to be shaped without breaking.
Air inside our bodies exerts pressure that balances the pressure created by Earth's atmosphere.
Airplanes in flight have to overcome drag created by gases in the atmosphere. They also have to overcome the force of gravity to stay in the air.
The shortest wavelengths of electromagnetic energy, such as gamma rays, are the most dangerous because they have a lot of energy and can penetrate matter easily.
ChatGPT
what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees
Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:
You have the initial velocity (v): 35 m/s
You have the launch angle (θ): 45 degrees
We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.
To calculate vx (horizontal component):
vx = v * cosθ
vx = 35 * cos(45) = 24.7 m/s
To calculate vy (vertical component):
vy = v * sinθ
vy = 35 * sin(45) = 24.7 m/s
We can calculate the horizontal distance (d) traveled using:
d = vx * t (where t is time)
Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:
t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)
t = 24.7 / 9.8 = 2.52 seconds
Now we can calculate the full horizontal distance traveled:
d = vx * t
d = 24.7 * 2.52
= 62.3 meters
So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.
Let me know if you have any other questions!
Answer:
To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.
The horizontal component of the motion remains constant throughout the trajectory and is given by:
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.
The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:
Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)
Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.
The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.
Using these calculations, we can find the horizontal distance traveled by the object.
Let's calculate step by step:
Step 1: Calculate the time of flight
Vertical displacement = 0 (at the highest point)
0 = (35 * sin(45))^2 / (2 * 9.8)
0 = (24.75^2) / 19.6
0 = 616.0125 / 19.6
0 = 31.43
Step 2: Calculate the time of flight
Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2
0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2
0 = 24.75 * time - 4.9 * time^2
4.9 * time^2 - 24.75 * time = 0
time * (4.9 * time - 24.75) = 0
time = 0 (initial point) or 24.75 / 4.9
time = 5.05 seconds
Step 3: Calculate the horizontal distance
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
Horizontal distance = 35 * 5.05 * cos(45)
Horizontal distance = 35 * 5.05 * (sqrt(2)/2)
Horizontal distance = 88.96 meters
Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.HELP PLEASE
*on picture*
Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.
Answer:
Refer to the step-by-step Explanation.
Step-by-step Explanation:
Simplify the equation with given substitutions,
Given Equation:
\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)
Given Substitutions:
\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)
Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)
Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the left-hand side of the equation:
\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
Simplifying the third term.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)
"R²'s" cancel, we are left with:
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)
We have like terms, combine them.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)
Each term has an "m" in common, factor it out.
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)
Now we have the following equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the right-hand side of the equation:
\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)
\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)
Now we have the equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
\(\hrulefill\)
Now solving the equation for the variable "v":
\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
Dividing each side by "m," this will cancel the "m" variable on each side.
\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)
Subtract the term "gh" from either side of the equation.
\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)
Multiply each side of the equation by "10/7."
\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)
Now squaring both sides.
\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)
Thus, the simplified equation above matches the simplified equation that was given.
A 4kg ball moving 8m/s to the right collides with a 2kg ball at rest. After the
collision, the 4kg ball moves with a new velocity of 4.8m/s to the right. Assuming
that the collision is elastic, how fast is the 2kg ball moving?
We can see that the new velocity of the 2 Kg ball is 6.4 m/s.
What is the momentum?Momentum is a measure of an object's motion. It is defined as the product of an object's mass and velocity. In physics, momentum is a vector quantity, meaning it has both magnitude and direction.
The law of conservation of momentum states that in an isolated system, the total momentum of the system remains constant if no external forces are acting upon it.
Given that we know that;
Momentum before collision = Momentum after collision
(4 * 8) + (2 * 0) = (4 * 4.8) + (2 * v)
Let v be the new velocity
32 = 19.2 + 2v
v = 32 - 19.2/2
v = 6.4 m/s
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A person is standing on a spring bathroomscale on the floor of an elevator which ismoving up and slowing down at the rate of2.16 m/s2.The acceleration of gravity is 9.8 m/s2.If the person’s mass is 88.1 kg, what doesthe scale read?Answer in units of n.
Explanation
Step 1
Diagram
For the accelerations, here we assume the upward be positive and downward be negative,so
\(\begin{gathered} \text{Net acceleration = }g-(-a) \\ \text{Net acceleration =}9.8-(-2.16)=10.96 \end{gathered}\)note that a is negative because the elevator is slowing down
now, the reading of the scale is
\(\begin{gathered} F=ma \\ \text{replace} \\ F=88.1\text{ Kg}\cdot10.96(\frac{m}{s^2}) \\ F=965.576\text{ N} \end{gathered}\)therefore, the answer is
96
Airflow lifts a 3.6 kg bird 50 m up. How much work was done by the flow?
If airflow lifts a 3.6 kg bird 50 m up, then the work done by the airflow is 1764 joules.
Given,
Mass of the bird = 3.6 kg,displacement covered by the bird due to airflow d) = 50 m,Work done against the friction (W) =?
We know that :
Work done against the friction (W) = force × displacement
W = F × d
W = m × g x d [ Force = mass × acceleration due to gravity ]
W = 3.6 × 9.8 × 50 [ g = 10 m/s2 ]
W = 1764 joules
Hence, the work done by the airflow is 1764 joules.
A force is an influence that has the power to alter an object's motion. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest.
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Light of wavelength 3500Å is incident on two metals A and B whose work functions are 3.2 eV and 1.9 eV respectively. Which metal will emit photoelectrons?
(a) A
(b) B
(c) Both A and B
(d) Neither A nor B
Answer:
(c) Both A and B
Explanation:
Given;
wavelength of the incident light, λ = 3500 Å = 3500 x 10⁻¹⁰ m
The energy of the incident light is given by;
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
f is frequency = c / λ
\(E = \frac{hc}{\lambda} \\\\E = \frac{(6.626*10^{-34})(3*10^8)}{3500*10^{-10}}\\\\E = 5.68 *10^{-19} \ J\\\\E = 5.68 \ eV\)
Work function is the minimum amount of energy required to liberate electrons from a metal surface.
The work function of metal A is 3.2 eV and
Th e work function of metal B is 1.9 eV
Both work functions are less than the incident energy of the light calculated as 5.68eV.
Thus, both metals will emit photoelectrons.
(c) Both A and B
A bullet is shot from a rifle with a speed of 600 m/s. If a target is 2000 meters away, how long will it take
to hit the target?
The time taken for the bullet moving with a speed of 600 m/s to hit a target 200 meters away is 3.33 s.
What is time?
Time is the measured or measurable period during which an action, process, or condition exists or continues.
To calculate the time it takes the bullet to hit the target, we use the formula below.
Formula:
v = d/t.......... Equation 1Where:
v = Velocityd = distancet = timeMake t the subject of the equation
t = d/v............ Equation 2From the question,
Given:
d = 2000 metersv = 600 m/sSubstitute these values into into equation 2
t = 2000/600t = 3.33 secondsHence, the time it will take to hut the target is 3.33 seconds.
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A 40.0 kg block of lead is heated from -25°C to 200°C.
How much heat is absorbed by the lead block?
A. 2,354,000 J
B. 1,170,000 J
C. 56,891 J
D. 10,650 J
Answer:
B. 1,170,000 J
Explanation:
Given;
mass of lead block, m = 40 kg
initial temperature, t₁ = -25 ⁰C
final temperature, t₂ = 200 ⁰C
The heat absorbed the lead block is calculated as;
H = mcΔt
where;
c is the specific heat capacity of lead = 130 J/kg⁰C
H = 40 x 130 x (200 - (-25))
H = 40 x 130 x (200 + 25)
H = 40 x 130 x 225
H = 1,170,000 J
Therefore, the heat absorbed the lead block is 1,170,000 J
what is a mirror's radius of curvature if cars 17.0 m away appear 0.37 their normal size? follow the sign conventions.
Therefore, if cars 17.0 m away appear 0.37 their normal size, the mirror's radius of curvature is -6.29.
What is radius of curvature?In differential geometry, the radius of curvature, R, is the reciprocal of the curvature. Its radius is the same as the radius of the circular path that, at that specific moment, most closely matches the curve. The diameter of the a circle that, individually and collectively, fits a normal section the best seems to be the radius of curvature of surfaces. The curvature's length and radius is denoted by R, and its derivative by K, where R=1/K.
The diameter of a hollow sphere in which the spherical mirror was housed determines its radius of curvature. The radius of curvature is the distance between the pole and center of a spherical mirror.
How do you use radius formula?Radius = Diameter/ 2 applies when the diameter is known. Radius = Circumference/2 can be calculated after the circumference is known. The radius is calculated using the formula Radius = ⎷(Area of the circle/π) when the area is known.
Briefing:For the mirror, we can solve two equations:
1/f=1/d_0 -1/d_i
M= -d_i/d_0
Index I stands for a picture, while index 0 stands for the object.
Magnification in this instance is 0.37:
0.37= -d_i/d_0
-0.37d0 = di d0 =17.0m
di= -0.37 × 17.0
di = 6.29m
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PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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Rank the following media in terms of the speed of sound through each
medium, from fastest to slowest?
Answer:
11.5
Explanation:
What is SeaWorld?
What is this
What is that
SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.
SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.
SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.
Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.
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forms of energy are those a system possess as a whole with respect to some outside reference frame, such as kinetic and potential energies.
Total energy is preserved as potential energy is converted to kinetic energy.In contrast to kinetic energy, which an item possesses as a result of its motion, potential energy is the energy that an object possesses as a result of its height, position, or arrangement.
An object's mechanical energy is equal to the product of its potential energy and kinetic energy.
When we compress a spring, the energy from our hand is stored there as the spring's potential energy, which is what holds the spring in that certain position. Its whole potential energy is there at that point. The spring has a tendency to extend outside and bounce outwards as soon as we release it. It implies that it gains kinetic energy. As a result, we may infer that potential energy is changing into kinetic energy.
Additionally, the spring will receive the identical quantity of kinetic energy that is being lost as potential energy, maintaining a constant total mechanical energy. It implies that the spring's whole energy has been saved.
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money is rare? or is it bad
Answer:
money is not rare. you can find it everywhere. what exactly is the question? whether it is bad or not is an opinion.
Explanation:
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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A car travels west 60 kilometers in 2.5 hours. Its average velocity for the trip is ____ km/h.
pls help
Answer:
24km/h
Explanation:
V = D/T
= 60/2.5
= 24
An engine rated at 5.0 3 104 watts exerts a constant force of 2.5 3 103 newtons on a vehicle. Determine the average speed of the vehicle.
Given data:
* The power of the engine is,
\(P=5\times10^4\text{ watts}\)* The force exerted by the engine is,
\(F=2.5\times10^3\text{ N}\)Solution:
The power of the engine in terms of force and average speed is,
\(P=Fv\)where v is the average speed,
Substituting the known values,
\(\begin{gathered} 5\times10^4=2.5\times10^3\times v \\ v=\frac{5\times10^4}{2.5\times10^3} \\ v=2\times10^{4-3} \\ v=20\text{ m/s} \end{gathered}\)Thus, the average speed of the vehicle is 20 meters per second.
12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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Mario drives his Kart at an average speed of 42 miles per hour for 1.7 minutes. How far does he drive? Include units in your answer
We will have the following:
First, we transform the velocity unit of time, that is:
\(42\frac{mi}{h}\ast\frac{1h}{60min}=0.7\frac{mi}{min}\)Then, we will have that:
\(x=\frac{0.7mi\ast1.7min}{1min}\Rightarrow x=1.19mi\)So, it moved 1.19 miles.
Charges may be transferred by:
A) induction
B) insulation
C) reduction
D) conduction
Answer:
D) conduction
Explanation:
In the same liquid, the pressures are equal at all points that are
A. the same distance below the liquid surface.
B. along the vertical walls of the container.
C. not touching any immersed objects.
D. not in the sunlight.
The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.
This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point in the sunlight is equal to the pressure at any other point not in the sunlight.
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Triple expansion steam engines were used extensively to power ocean liners like the Titanic. They worked via high steam pressure that was gradually decreased as it travelled from one cylinder to another due to the principles of Charles’ law. The first cylinder was the smallest and the last had the largest volume. If it enters the first cylinder (100 Liters) at 18.9 atm and exits the last at 1.7 atm, what is its final Volume?
Given
\(\begin{gathered} P_1=18.9\text{ atm} \\ V_1=100\text{ L} \\ P_2=1.7\text{ atm} \end{gathered}\)The ideal gas equation is given as,
\(PV=nRT\)Here, n is the number of moles, R is the universal gas constant and T is the temperature (constant).
Therefore,
\(PV=\text{const}\)Hence,
\(P_1V_1=P_2V_2\)Therefore, the final volume V_2 is given as,
\(V_2=\frac{P_1V_1}{P_2}\)Substituting all known values,
\(\begin{gathered} V_2=\frac{18.9\text{ atm}\times100\text{ L}}{1.7\text{ atm}} \\ =1111.76\text{ L} \end{gathered}\)Therefore, the final volume is 1111.76 L.
A human population profile shows the
Answer:
it shows the gorwth
Explanation:
the orientation of an mrna codon relative to a trna anticodon is best described as: a. antiparallel. b. parallel. c. perpendicular. d. non-complementary.
The orientation of an mRNA codon corresponding to a tRNA anticodon is best described as A: antiparallel.
An anticodon is a three-base sequence, paired with a particular amino acid, that a tRNA molecule brings to the associated codon of the mRNA during translation. The anticodon sequence is said to be complementary to the mRNA, using base pairs in the anti-parallel direction. The tRNA anticodon 3-UAC-5 will make pair with the mRNA codon.
Thus, the orientation of an mRNA codon relative to a tRNA anticodon is said to be antiparallel.
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A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
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Next
cm³. A cubic box with a volume of [
m on each side.
The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.
Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.
Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.
So the filled cubic box has a side length of approximately 0.141 m.