edge lengths are given in units. Find the surface area of each prism in square units

Answer:Then since ∠BOD = 90°, we know that ∠BOC + ∠COD = 90°. In other words, ∠BOC and ∠COD are complementary. Thus, the answer is angle BOC

Step-by-step explanation:

Answer:

The person above is correct! The answer is C. <BOC

Step-by-step explanation:

Hope u have a great rest of your day/night! <3333

Answer:

(0,6), and (18,0)

Step-by-step explanation:

2x +6y = 36

6y = -2x +36

y =(-2/6) x+ 36/6

y=(-1/3)x +6

compare this equation to y=mx+b where b is the y-intercept so the

y-intercept is a point at (0, 6)

to find the x-intercept make the equation equal to 0

(-1/3)x+6=0 subtract 6 in both sides

(-1/3)x = -6 cross multiply

-x = 3*-6

x=18 so the

x-intercept is a point at (18,0)

The optimization problem has a maximum value of P when x = 13 and y = 6.5. The maximum value of P = 13 * 6.5 = 84.5.

To solve the optimization problem and maximize P = xy with the constraint x + 2y = 26, follow these steps:

1. Express one variable in terms of the other using the constraint: x = 26 - 2y

2. Substitute the expression for x into the objective function P: P = (26 - 2y)y

3. Differentiate P with respect to y to find the critical points: dP/dy = 26 - 4y

4. Set the derivative equal to zero and solve for y: 26 - 4y = 0 => y = 6.5

5. Plug the value of y back into the expression for x: x = 26 - 2(6.5) => x = 13

6. Check the second derivative to confirm it's a maximum: d²P/dy² = -4 (since it's a constant negative, this confirms it's a maximum)

Thus, the optimization problem has a maximum value of P when x = 13 and y = 6.5. The maximum value of P = 13 * 6.5 = 84.5.

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The argument states that since all paintings by Matisse are beautiful and the museum has a painting by Matisse, the museum must have a beautiful painting.

The argument presented is an example of a logical fallacy known as affirming the consequent. It follows the form of a logical fallacy known as the fallacy of the converse. The fallacy of the converse occurs when one assumes that if the consequent (in this case, having a painting by Matisse) is true, then the antecedent (in this case, the painting being beautiful) must also be true. However, this is not a valid logical inference.

While it is true that the argument assumes that all paintings by Matisse are beautiful, it does not necessarily follow that the museum's painting by Matisse is also beautiful. There may be exceptions to the generalization that all Matisse paintings are beautiful. Additionally, beauty is subjective, and what one person finds beautiful, another may not.

Therefore, based on the argument presented, we cannot conclude with certainty that the museum has a beautiful painting solely because it possesses a painting by Matisse. The argument relies on a logical fallacy and does not provide sufficient evidence to support the claim that the museum's painting is beautiful.

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The most likely mean for the sample distribution is option c. negatively skewed.

Based on the given information, we know that the mean (M) is less than both the median and the mode. This suggests that the distribution is skewed to the left (negatively skewed), with a long tail on the left side of the distribution.

The mean of a sample distribution is the average value of all the observations or measurements in the sample. It is calculated by adding up all the values in the sample and dividing the sum by the total number of observations in the sample.

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Therefore, the sample variance is approximately 65 using 95% confidence interval.

To find the sample variance, we need to use the formula for the confidence interval of the mean:

X ± tα/2 (s/√n)

Where:

X is the sample mean

tα/2 is the critical value for the t-distribution at the desired confidence level (with n-1 degrees of freedom)

s is the sample standard deviation

n is the sample size

From the given information, we know that the sample size n = 13, and the confidence interval is (3.5990, 19.0736) with a 95% confidence level. This means that the critical value for the t-distribution at α/2 = 0.025 and 11 degrees of freedom is approximately 2.201.

Using the formula for the confidence interval and the upper and lower bounds of the interval, we can solve for s:

19.0736 = X + 2.201(s/√13)

3.5990 = X - 2.201(s/√13)

Adding the two equations gives:

22.6726 = 2X

Therefore, X = 11.3363

Substituting this value of X into one of the original equations gives:

19.0736 = 11.3363 + 2.201(s/√13)

Solving for s, we get:

s ≈ 8.0587

Rounding to the nearest integer, the sample variance is:

s^2 ≈ 65

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Answer: To determine the total number of fixtures required for the job, we can set up a proportion using the information given.

Let's assume the total number of fixtures required for the job is represented by "x."

According to the problem, 33% of the fixtures required were delivered. This can be written as 33% of x, or 0.33x.

We also know that 66 fixtures were delivered.

So we can set up the following proportion:

0.33x / x = 66 / 1

To solve this proportion, we can cross-multiply:

0.33x = 66

Next, we can divide both sides of the equation by 0.33 to isolate x:

x = 66 / 0.33

Performing the division:

x = 200

Therefore, 200 fixtures are required to complete this job.

The limit of the sequence (1) {2}, (2) {(-1)^n}, and (3) {n sin(n)}, converges to DNE (does not exist) or the sequence diverges. The limit of the sequence (4) {sin(nπ)} is undefined, as it oscillates between -1 and 1.

In the case of sequence (1) {2}, the limit is a constant value, and the sequence converges to that value. However, in the case of sequence (2) {(-1)^n}, the sequence oscillates between -1 and 1, and there is no single value that it approaches as n tends to infinity. Therefore, the limit does not exist, and the sequence diverges.

Sequence (3) {n sin(n)} also does not have a limit as n tends to infinity. The term n sin(n) oscillates between positive and negative values without approaching a specific value. Hence, the limit of this sequence is DNE, and it diverges.

In the case of sequence (4) {sin(nπ)}, the term sin(nπ) oscillates between -1 and 1 as n varies. Since there is no convergence to a specific value, the limit of this sequence is undefined.

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The simplified form of the given expression is 4/√6. Therefore, option D is the correct answer.

A surd is an expression that includes a square root, cube root or other root symbol. Surds are used to write irrational numbers precisely – because the decimals of irrational numbers do not terminate or recur, they cannot be written exactly in decimal form.

The given expression is 6√2/√3 - 8/3√(3/2).

Here, 6√2/√3 - 8√3/3√2

= 6√2/√3 - 8/√3√2

= 6√2/√3 - 8/√6

= 12/√6- 8/√6

= 4/√6

Therefore, option D is the correct answer.

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A quantitative variable x is a "Random Variable" if the value that x takes on in a given experiment or observation is a chance or random outcome.

A random variable is one with an unknown value or a function which assigns qualities to each of the outcomes of an experiment.

Some key features regarding the Random Variable are-

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The closed formula of h(t) and f(t) for

h(0)=f(0)=100b => h(t) = 100(2t+1), f(t) = 100(2t-1) ,

h(0)=200, f(0)=100 => h(t) = 200(2t+1), f(t) = 100(2t-1)

h(0)=600, f(0)=500 =>h(t) = 300 + 200(2t+\((-1)^{t}\)), f(t) = 200 - 100\((-1)^{t}\)

The recursive equations for the given two interacting population of hares and foxes are

h(t+1)=4h(t)-2f(t)

f(h+1)=h(t)+f(t)

for the given initial population in parts from a to c we need to create a close formula for h(t) and f(t)

h(t) = 100(2t+1)

f(t) = 100(2t-1)

h(t) = 200(2t+1)

f(t) = 100(2t-1)

h(t) = 300 + 200(2t+\((-1)^{t}\))

f(t) = 200 - 100\((-1)^{t}\)

The closed formula of h(t) and f(t) for

h(0)=f(0)=100b => h(t) = 100(2t+1), f(t) = 100(2t-1) ,

h(0)=200, f(0)=100 => h(t) = 200(2t+1), f(t) = 100(2t-1)

h(0)=600, f(0)=500 =>h(t) = 300 + 200(2t+\((-1)^{t}\)), f(t) = 200 - 100\((-1)^{t}\)

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So, the cards should be placed in the following way:-5 on the left side of the equation2 on the right side of the equation4 on the left side of the equation1 on the right side of the equationThus, the equation would be: -5 + 2(4) = 6 - 3(5/4)The above equation has the same value of x as the given equation.

The given expression is: -x + 5 + 2x - 4 = 6 - 3x. Rearranging the equation, we get: 2x - x + 3x = 6 - 5 + 4. Simplifying further, we have: 4x = 5. Dividing both sides by 4, we find: x = 5/4.

To maximize the value of x, we need to use the largest possible numbers. So, the cards should be placed in the following way:

-5 on the left side of the equation

2 on the right side of the equation

4 on the left side of the equation

1 on the right side of the equation

Thus, the equation would be: -5 + 2(4) = 6 - 3(5/4).

The above equation has the same value of x as the given equation, which is 5/4.

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Answer:

2/3

Step-by-step explanation:

Glenn needs to cut pieces of ribbon that are each 1 meter long to make ribbon key chains. If he has 6 pieces of ribbon that are each 1 dekameter long, how many 1−meter pieces of ribbon can he cut?

1 decametre = 10 metres

Hence,

10 meters = 6 pieces of ribbon

1 meter = x pieces

Cross Multiply

10x = 6

x = 6/10

x = 2/3 (1 meter pieces of ribbon)

Answer:

f(0)=5(0)-20

f(0)= -20

y- intercept is (0,-20)

Answer:

f = 5 + -20x-1

Step-by-step explanation:

Simplifying

f(x) = 5x + -20

Multiply f * x

fx = 5x + -20

Reorder the terms:

fx = -20 + 5x

Solving

fx = -20 + 5x

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.

f = -20x-1 + 5

Simplifying

f = -20x-1 + 5

Reorder the terms:

f = 5 + -20x-1

Rounding to the nearest whole number, she will have run a total distance of 13 kilometers after 16 days.

To find out how far she will have run in total after 16 days, we can use the formula for calculating compound interest:

A = P(1 + r/100)^n

Where:

A = Total distance run after n days

P = Initial distance (4.8 kilometers)

r = Rate of increase per day (6.9%)

n = Number of days (16)

Plugging in the given values, we can calculate the total distance:

A = 4.8(1 + 6.9/100)^16

Using a calculator or performing the calculations step by step, we get:

A ≈ 4.8(1.069)^16 ≈ 4.8(2.092473)^16 ≈ 4.8(2.628)

A ≈ 12.6144

Rounding to the nearest whole number, she will have run a total distance of 13 kilometers after 16 days.

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To represent the hourly wage of an employee at the antique store, we can use the following equation:
y = 15 + 0.75x
where y represents the worker's hourly wage, and x represents the number of years the employee has worked at the store. In this equation, 15 is the initial hourly wage, and 0.75 is the annual raise.

The equation that shows how a worker's hourly wage, y, depends on the number of years he or she has worked at the store can be written as:

y = 15 + 0.75x

where x represents the number of years the employee has worked at the antique store.

This equation takes into account the starting wage of $15 per hour and the $0.75 raise that the employee receives each year they work at the store.

So, for example, if an employee has worked at the store for 5 years, their hourly wage would be:

y = 15 + 0.75(5) = 18.75

where y represents the worker's hourly wage, and x represents the number of years the employee has worked at the store.

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In stroke play, when Player A concedes a short putt to Player B on the 7th hole and Player B picks up their ball and tees off on the 8th hole before holing out on the 7th hole, the ruling is that Player B incurs a penalty for not completing the hole.

In stroke play, if player A concedes a short putt to player B on the 7th hole, it means that player B can pick up their ball without completing the hole.

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Answer:

Question 2 :  
\(\boxed{-35}\)

Question 3:
\(\boxed{7}\)

Question 4:
\(\boxed{-5}\)

Question 5:
\(\boxed{-5}\)

Step-by-step explanation:

The easiest points to take on the line are those where x =0, y = 35 (0,35) and x = 7, y =0 (7,0)

Question 2.
We can see that between these two points, the y value decreases linearly from 35 to 0. So the rise between (0, 35) and (7,0) = \(0 -35 = -35\)

Question 3

\(\textrm{Between (0, 35) and (7,0) the x value increases from 0 to 7 so the run is 7}\)

Question 4

\(\dfrac{rise}{run}= \dfrac{-35}{7}= -5}\)

Question 5

Slope is the same as rise over run

We can also write this as
\(\dfrac{0-35}{7-0} = \dfrac{-35}{7} = -5\)

Though not asked for, the equation of the line is
\(y = -5x + 35\)

The value of KP at this temperature is 3.53×10⁻⁵. At equilibrium it is found that p(NO) = 0.008870 atm, p(NO2)

= 0.003340 atm, and p(N2O)

= 0.008170 atm.

Given: 3 NO(g) 1 NO2(g) + 1 N2O(g);

p(NO) = 0.008870 atm, p(NO2) = 0.003340 atm, and p(N2O) = 0.008170 atm.

We are to find the value of KP at this temperature.

We know that the equilibrium constant Kc and the equilibrium constant KP are related as follows:

KP = Kc (RT)Δn=Kc (0.0821×498)Δn where Δn is the difference in the number of moles of gaseous products and gaseous reactants.

We can determine Δn by the stoichiometry of the balanced chemical equation.3 NO(g) 1 NO2(g) + 1 N2O(g)

Number of moles of gaseous products = 1 + 1 = 2

Number of moles of gaseous reactants = 3Δn

= 2 - 3

= -1KP

= Kc (0.0821×498)ΔnKP

= Kc (0.0821×498)-1KP

= Kc/32.86

Now, we need to find the value of Kc. We can find Kc using the equilibrium partial pressures as follows:

Kc = p(NO2)p(N2O)/p(NO)3Kc

= (0.003340)(0.008170)/(0.008870)3Kc

= 1.16×10⁻³KP = Kc/32.86KP

= 1.16×10⁻³/32.86KP

= 3.53×10⁻⁵.

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At equilibrium it is found that p(NO) = 0.008870 atm, p(NO2)= 0.003340 atm, and p(N2O) = 0.008170 atm. The value of KP at this temperature is 3.53×10⁻⁵.

Given: 3 NO(g) 1 NO2(g) + 1 N2O(g);

p(NO) = 0.008870 atm, p(NO2) = 0.003340 atm, and p(N2O) = 0.008170 atm.

We are to find the value of KP at this temperature.

We know that the equilibrium constant Kc and the equilibrium constant KP are related as follows:

KP = Kc (RT)Δn=Kc (0.0821×498)Δn where Δn is the difference in the number of moles of gaseous products and gaseous reactants.

We can determine Δn by the stoichiometry of the balanced chemical equation.3 NO(g) 1 NO2(g) + 1 N2O(g)

Number of moles of gaseous products = 1 + 1 = 2

Number of moles of gaseous reactants = 3Δn

= 2 - 3

= -1KP

= Kc (0.0821×498)ΔnKP

= Kc (0.0821×498)-1KP

= Kc/32.86

Now, we need to find the value of Kc. We can find Kc using the equilibrium partial pressures as follows:

Kc = p(NO2)p(N2O)/p(NO)3Kc

= (0.003340)(0.008170)/(0.008870)3Kc

= 1.16×10⁻³KP = Kc/32.86KP

= 1.16×10⁻³/32.86KP

= 3.53×10⁻⁵.

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The frequency table will list the number of travelers who liked each city. In this case, 124 travelers liked Indianapolis best, 416 liked St. Louis, 1225 liked Chicago, and the remaining number preferred Milwaukee.

The frequency table will present the preferences of the frequent business travelers while the relative frequency table will express these frequencies as a proportion of the total number of travelers. It will list the four cities (Indianapolis, St. Louis, Chicago, and Milwaukee) and their corresponding frequencies, which represent the number of travelers who preferred each city. According to information provided, 124 travelers liked Indianapolis, 416 liked St. Louis, 1225 liked Chicago, and the remaining number preferred Milwaukee.

The relative frequency table will express the frequencies as proportions relative to the total number of travelers. To calculate the relative frequency, the frequency of each city will be divided by the total number of travelers, which is 2200 in this case.

The resulting proportions will be rounded to three decimal places. The relative frequencies will indicate the proportion of travelers who preferred each city relative to the total number of respondents.

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Answer:

Paco, Tim, Jenny, Maria

Step-by-step explanation:

The equation of parabola in intercept form will be \(y=-\frac{4}{27}(x-10)(x+2)\)

Given,

x -intercepts are 10 and -2 which passes through (1,4)

Equation of parabola in intercept form can be written as,

\(y=a(x-p)(x-q)\)

Where, p and q are the x-intercepts

\(y=a(x-10)(x-(-2))\\\\y=a(x-10)(x+2).....i\)

Substituting the point (1,4) in equation \(i\) to find 'a'

\(4=a(1-10)(1+2)\\\\4=a(-9)(3)\\\\4=-27a\\\\a=-\frac{4}{27}\)

Substituting 'a' in eq. i

\(y=-\frac{4}{27}(x-10)(x+2)\)

Thus, the equation of parabola in intercept form will be \(y=-\frac{4}{27}(x-10)(x+2)\).

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Answer:

5a - 1

Step-by-step explanation:

add common terms

2a - 5 + 3a + 4

2a + 3a and -5 + 4

5a - 1

:)

Answer:

5a - 1

Step-by-step explanation:

Simple additon math skillz

Step-by-step explanation:

the answer will be zero 0

The answers, rounded to the appropriate number of significant figures, are as follows:

(a) 1.088 ×\(10^2\)

(b) 2.132

(c) 1.3331 ×\(10^1\) and

(d) 1.05.

Let's calculate the answers to the given operations using the appropriate number of significant figures.

(a) 8.370×1.3×10

To perform this multiplication, we multiply the decimal numbers and add the exponents of 10:

8.370 × 1.3 × 10 = 10.881 × 10 = 1.0881 × \(10^2\)

Since the original numbers have four significant figures, we round the final answer to four significant figures:

1.088 × \(10^2\)

(b) 4.265/2.0

For division, we divide the decimal numbers:

4.265 ÷ 2.0 = 2.1325

Since both numbers have four significant figures, the answer should be rounded to four significant figures:

2.132

(c) (1.2588×\(10^3\))×(1.06×\(10^-^2\))

To multiply these numbers, we multiply the decimal numbers and add the exponents:

(1.2588 × \(10^3\)) × (1.06 × \(10^-^2\)) = 1.333128 × \(10^1\)

Since the original numbers have five significant figures, we round the final answer to five significant figures:

1.3331 × \(10^1\)

(d) \((1.11)^(^1^/^2^)\)

To calculate the square root, we raise the number to the power of 1/2:

\((1.11)^(^1^/^2^)\)= 1.0524

Since the original number has three significant figures, the answer should be rounded to three significant figures:

1.05

It's important to note that the significant figures in a result are determined by the original data and the operations performed. The final answers provided above reflect the appropriate number of significant figures based on the given information and the rules for significant figures.

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There are 119 inches in 3.0226 meters, rounded to the nearest inch. To get this answer, the conversion factor of 2.54 cm per inch is used to convert meters to inches.

First, we need to convert 3.0226 meters to centimeters for converting we can multiplying it by 100

3.0226 meters = 302.26 centimeters

Next, we can convert centimeters to inches, for this we need to divide it by 2.54

302.26 centimeters / 2.54 centimeters per inch ≈ 119 inches

Rounding to the nearest inch, we get

119 inches ≈ 119 inches

Therefore, there are approximately 119 inches in 3.0226 meters.

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The total quantity produced when p = 5 is 26 in the long run.

In the short run, each firm will produce where its marginal cost equals the market price, which we'll denote as p.

So, for Type A firms, the short-run supply curve is:

q4(p) = (p-2)/2

And for Type B firms, the short-run supply curve is:

qB(p) = (p-2)/6

The short-run market supply is simply the sum of the quantities supplied by each type of firm at a given price level. So, if there are 10 Type A firms and 6 Type B firms, the short-run market supply at a price level of p is:

Qs(p) = 10q4(p) + 6qB(p)

= 10(p-2)/2 + 6(p-2)/6

= 8p - 20

The total quantity produced when p=5, we can substitute p=5 into the market supply equation we just derived:

Qs(5) = 8(5) - 20

= 20

So, the total quantity produced when p=5 is 20.

The long run, firms can enter or exit the market, and as a result, the number of firms in each market may change.

In this case, we'll assume that the number of Type A and Type B firms can adjust freely in the long run, and that each firm earns zero economic profit in the long run.

If there are zero economic profits, each firm's total revenue (TR) must equal its total cost (TC), which means that price must equal average total cost (ATC).

For Type A firms, ATC4(q) = TC4(q)/q = 1/q + 2 + q, so:

5 = 1/q + 2 + q

Rearranging and solving for q, we get:

q4 = 2

So each Type A firm will produce 2 units of output in the long run.

For Type B firms, ATCB(q) = TCB(q)/q = 6/q + 2 + 3q, so:

5 = 6/q + 2 + 3q

Rearranging and solving for q, we get:

qB = 1

So each Type B firm will produce 1 unit of output in the long run.

If there are 10 Type A firms and 6 Type B firms, the total quantity produced in the long run when p=5 is:

Qlr = 10q4 + 6qB

= 10(2) + 6(1)

= 26

So, the total quantity produced when p = 5 is 26 in the long run.

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Answer:

The answer is -11, -14

Step-by-step explanation:

I did this last year