ect 0/2 pts Question 12 In a recent health survey, 333 adult respondents reported a history of diabetes out of 3573 respondents. What is the critical value for a 90% confidence interval of the proport

Answer: 16

Step-by-step explanation:

The equilibrium price is $0 and the equilibrium quantity is 5 units.

To find the equilibrium price and quantity, we need to set the quantity demanded equal to the quantity supplied and solve for the equilibrium values.

Setting Q_d = Q_s, we can equate the equations for demand and supply:

-2Q - 2Q_d = -5 + 3Q_s

Since we know that Q_d = Q_s, we can substitute Q_s for Q_d:

-2Q - 2Q_s = -5 + 3Q_s

Now, let's solve for Q_s:

-2Q - 2Q_s = -5 + 3Q_s

Combine like terms:

-2Q - 2Q_s = 3Q_s - 5

Add 2Q_s to both sides:

-2Q = 5Q_s - 5

Add 2Q to both sides:

5Q_s - 2Q = 5

Factor out Q_s:

Q_s(5 - 2) = 5

Q_s(3) = 5

Q_s = 5/3

Now that we have the value for Q_s, we can substitute it back into either the demand or supply equation to find the equilibrium price. Let's use the supply equation:

P = -5 + 3Q_s

P = -5 + 3(5/3)

P = -5 + 5

P = 0

Therefore, the equilibrium price is $0 and the equilibrium quantity is 5 units.

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You need to save $62.06 each month for four years to achieve your total contribution goal before starting college.

First, 5% of the total cost for four years.

= 0.05 x ($14,895.00/yr x 4 years)

= 0.05 x $59,580.00

= $2,979.00

Second, Divide the total amount you need to pay over four years by the number of years.

= $2,979.00 / 4

= $744.75

Therefore, you need to pay $744.75 for each year of attending college.

Now, the total contribution goal.

= Amount to pay each year x 4 years

= $744.75 x 4

= $2,979.00

and, Monthly savings required

= Total contribution goal / 48 months

= $2,979.00 / 48

= $62.06

Therefore, you need to save $62.06 each month for four years to achieve your total contribution goal before starting college.

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Answer:

a. y=x^2

Step-by-step explanation:

desmos graphing calculator

The length and width of the plot that will maximize the area is 60 meters by 120 meters. The largest area that can be enclosed is 7200 square meters.

To maximize the area of the rectangular plot, Farmer Ed must use 9000 meters of fencing to enclose three sides of the plot. The fourth side, which borders the river, does not need to be fenced. To find the length and width of the plot that will maximize the area, the 9000 meters of fencing must be divided into two sides of equal length, with the remaining fencing used for the third side. This results in a length of 120 meters and a width of 60 meters, which maximizes the area of the plot. The largest area that can be enclosed is 7200 square meters.

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The correct answer to task 804 × 79 is 63,516.

When we multiply a number and another together, or a number and a variable, or even a variable with another variable, we mean the product of the two factors. The multiplication sign is " × " .

The step by step explanation of the task above is given below:

804 × 79 = 63,516.

Another example of Multiplication is

40 × 2 = 80.

The product of a and b also means Multiplication.

a and b means a × b = ab.

The product or the multiplication of g and 5 means g × 5 = 5g.

In conclusion, from the detailed information and explanation given above, the product of 804 × 79 is 63,516.

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Answer:

\(611\:\text{ft}\)

Step-by-step explanation:

In a right triangle only, the tangent of an angle is equal to its opposite side divided by its adjacent side. In this angle marked as \(42^{\circ}\) is actually the same as the angle with point \(P\).

Therefore, we can set up the following equation:

\(\tan 42^{\circ}=\frac{550}{x}\), where \(x\) is the distance from the coast.

Solving, we get:

\(x=\frac{550}{\tan 42^{\circ}},\\x\approx610.84\approx \boxed{611\:\text{ft}}\)

The additional information that could be used to prove congruence using AAS or ASA is: Angle A ≅ Angle T and AC (ASA) Angle A ≅ Angle T and BC ≅ PQ (ASA).

To prove that two triangles are congruent using the Angle-Angle-Side (AAS) or Angle-Side-Angle (ASA) criteria, we need specific information about the angles and sides of the triangles.

In this case, we are given three options, and we need to determine which combination of angles and sides would be sufficient to prove congruence using AAS or ASA.

To prove congruence using AAS, we need to show that two angles and the side between them in one triangle are congruent to the corresponding angles and side in the other triangle.

For the given options:

Angle B ≅ Angle P and BC ≅ PQ: This information alone is not sufficient to prove congruence using AAS or ASA. We need additional information about another angle or side in order to establish congruence.

Angle A ≅ Angle T and AC: This option provides information about an angle and a side. If we also have additional information about another angle or side, we can use the Angle-Side-Angle (ASA) criterion to prove congruence.

To determine the third option, we need to consider the remaining combinations of angles and sides:

Angle A ≅ Angle T and BC ≅ PQ: This option provides information about an angle and a side. If we also have additional information about another angle or side, we can use the Angle-Side-Angle (ASA) criterion to prove congruence.

In summary, the additional information that could be used to prove congruence using AAS or ASA is:

Angle A ≅ Angle T and AC (ASA)

Angle A ≅ Angle T and BC ≅ PQ (ASA)

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The given expression is a simplified algebraic equation: (1/2) * a^2 - 3b + 2c. It represents a combination of variables a, b, and c with their respective coefficients.

Utilizing symbols and operations, an algebraic equation illustrates the equivalence or inequivalence of two expressions. These generated expressions may hold variables that have varying values.

The premise centered around calculus is to arrive at a solution by acquiring the correct value(s) of these variable(s), ultimately fulfilling the outlined specification in the problem. Algebraic equations can range from uncomplicated linear problems to elaborate polynomials and trigonometric functions.

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In this question, we are given different arithmetic series and asked to find their sums. The arithmetic series are given in different forms, such as a series of numbers or a series of square roots. We need to use the formulas for the sum of an arithmetic series to find the respective sums.

a) For the series 6 + 14 + 22 + ..., we can see that the first term is 6 and the common difference is 8. We can use the formula for the sum of an arithmetic series, Sn = (n/2)(2a + (n-1)d), where n is the number of terms, a is the first term, and d is the common difference. Substituting the values, we get S15 = (15/2)(2(6) + (15-1)(8)) = 15(12 + 14(8)) = 15(12 + 112) = 15(124) = 1860.

b) For the series √2 + √8 + √18 + ..., we observe that the terms are square roots of numbers. We need to simplify the expression and determine the common difference to find the formula for the nth term. Once we have the formula, we can use the formula for the sum of an arithmetic series to find the sum. The calculation process will be explained in more detail.

c) For the series -40 - 33 - 26 - ..., we can see that the first term is -40 and the common difference is 7. Using the formula for the sum of an arithmetic series, Sn = (n/2)(2a + (n-1)d), we can substitute the values to find the sum.

d) For the series 74 + 63 + 52 + ..., we can observe that the first term is 74 and the common difference is -11. We can use the formula for the sum of an arithmetic series to find the sum.

e) The series is not provided, so it cannot be calculated.

In the explanation paragraph, we will provide the step-by-step calculations for each series to find their sums.

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Answer:

Step-by-step explanation:

\(\boxed{\bf -19+6x-5=3x}\)

\(\sf 6x-19-5=3x\)

\(\sf 6x-24=3x\)

\(\sf 6x=3x+24\)

\(\sf 3x=24\)

\(\bf x=8\)

A)

\(\boxed{\bf -6x+19-5=3x}\)

B)

\(\boxed{\bf -6x-19-5=3x}\)

C)

\(\boxed{\bf 6x+19+5=3x}\)

D)

\(\boxed{\bf 6x-19-5=3x}\)

Therefore, option D) 6x-19-5=3x is equivalent to -19+6x-5=3x.

✧ ˚  ·   .   ·

Hope this helps!

The value of x is :

x = 8.

Work/Explanation:

We need to isolate the variable, x.

So first I rearrange the terms:

\(\pmb{-19+6x-5=3x}\)

\(\pmb{6x-3x=5+19}\)

Simplify

\(\pmb{3x=24}\)

Divide each side by 3.

\(\pmb{x=8}\)

The equation that is equivalent to the given one is D.

The balance after 2 years for a $2,300 deposit earning 3.9% compounded annually will be $2,552.72. To calculate the future balance of a deposit after a certain period of time, we can use the compound interest formula:

Future Balance = Principal × (1 + Interest Rate/100)^Number of Years
In this case, the principal is $2,300, the interest rate is 3.9%, and the number of years is 2. Plugging these values into the formula, we get:
Future Balance = $2,300 × (1 + 3.9/100)^2
First, we'll find the value inside the parentheses:
(1 + 3.9/100) = (1 + 0.039) = 1.039
Now, raise this value to the power of 2:
1.039^2 = 1.079521
Next, multiply the principal by the result:
$2,300 × 1.079521 = $2,552.72
So, the balance after 2 years for a $2,300 deposit earning 3.9% compounded annually will be $2,552.72.

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Using the formula of area of a circle, about 226.08in² has been eaten

The diameter of the pizza is given as 24 inches. To calculate the area of the entire pizza, we need to use the formula for the area of a circle:

Area = π * r²

where π is approximately 3.14 and r is the radius of the circle.

Given that the diameter is 24 inches, the radius (r) would be half of the diameter, which is 12 inches.

Let's calculate the area of the entire pizza first:

Area = 3.14 * 12²

Area = 3.14 * 144

Area ≈ 452.16 square inches

Now, if half of the pizza is consumed, we need to calculate the area of half of the pizza. To do that, we divide the area of the entire pizza by 2:

Area of half of the pizza = 452.16 / 2

Area of half of the pizza ≈ 226.08 square inches

Therefore, if half of the pizza is consumed, approximately 226.08 square inches of pizza would be eaten.

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The stress function satisfies the conditions of compatibility for a two-dimensional problem.

Given stress function is 50x² - 60xy - 70y²

To determine whether the stress function satisfies the conditions of compatibility for a two-dimensional problem, it is required to find the strains and then check for compatibility equations.

Strain components are given as,

εx = ∂υ/∂x + (du/dx)

εy = ∂υ/∂y + (du/dy)

γxy = ∂υ/∂y + (du/dx)

Here,

υ = 50x² - 60xy - 70y²

du/dx = 100x - 60

ydu/dy = -60x - 140y

∂υ/∂x = 100x - 60y

∂υ/∂y = -60x - 140y

∂²υ/∂y² = -140

∂²υ/∂x² = 100

Now,εx = 100x - 60

yεy = -140y - 60

xγxy = -60y - 60x

Taking derivative of εy w.r.t x,

∂(εy)/∂x = -60

Similarly, taking derivative of εx w.r.t y,

∂(εx)/∂y = -60

∴ The stress function satisfies the conditions of compatibility for a two-dimensional problem.

Stress components are given as,

σx = (C11εx + C12εy)

σy = (C21εx + C22εy)

τxy = (C44γxy)

Here,C11 = C22 = 100, C12 = C21 = -60 and C44 = 0

Therefore,

σx = 100(100x - 60y) - 60(-140y - 60x)

= 19600x - 8800

yσy = -60(100x - 60y) + 100(-140y - 60x)

= -19600y + 8800x

τxy = 0

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The amount of the third ration should be 5.5 - (x + y) kg to ensure that the mammal covers its food requirements for the day.

We have,

To determine the amount of the third ration of meat that José Luis should give to the mammal,

We need to calculate the remaining amount needed to meet the daily requirement of 5.5 kg.

Let's assume the first ration of meat given to the mammal is x kg, and the second ration is y kg.

The total amount of meat given in the first two rations is x + y kg. To fulfill the daily requirement of 5.5 kg, the amount of meat needed in the third ration would be written as an expression:

5.5 kg - (x + y) kg = 5.5 - (x + y) kg.

Therefore,

The amount of the third ration should be 5.5 - (x + y) kg to ensure that the mammal covers its food requirements for the day.

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The complete question.

18.

José Luis performs his social service at the zoo and among his activities is feeding an endangered mammal. The indication is to give him 5.5 kg of meat per day. In one day he has been given two rations, one of kg and the other of kg. What should be the amount of the third ration, so that the mammal covers its food requirements for the day?

Answer:

$336

Step-by-step explanation:

The slope is (277-100)/(3-0) = 59.

So, since the cost is $100 when t=0, C=59t+100.

After 4 months, the cost is 59(4)+100 = $336.

Complete question :

At 10:00 am, Han and Tyler both started running toward each other from opposite ends of a 10 mile path along a river. Han runs at a pace of 12 minutes per mile Tyler runs at a pace of 15 minutes per mile how far does Han run after a half hour

Answer:

2.5 miles

Step-by-step explanation:

Given :

Distance between Horn and Tyler = 10 miles

Horn's pace = 12 minutes per mile

Tyler's pace = 15 minutes per mile

Horn's distance after half an hour :

Time = Half an hour = 30 minutes

Horn's speed = distance / time

Horn's speed = 1 mile / 12 minutes = 0.83333 miles per minute

Hence, Horn's distance after half an hour :

Distance = speed * time

Distance = 0.83333 miles per minute * 30 minutes

Distance = 2.5 miles

The mean for boxplot #3 should be less than its median. In a negatively skewed distribution, the mean is less than the median.

This is because the few small values in the data pull the mean down, while the median is still at the middle value. A boxplot can give us an idea of the shape of the distribution, and if it is negatively skewed, it suggests that the mean will be less than the median.

It's important to note that without actually seeing the boxplot, this conclusion may not be accurate. There could be other factors that affect the mean and median, such as outliers or the size of the sample. However, based on the information given that the boxplot is negatively skewed, it is likely that the mean will be less than the median.

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The correct answer is: (a) The difference between a sample statistic and a population parameter.

The sampling error refers to the discrepancy or difference between a sample statistic (such as the sample mean or sample proportion) and the corresponding population parameter (such as the population mean or population proportion).

It represents the extent to which the sample statistic may deviate from the true population parameter.

Sampling error can arise due to random sampling variability and is inherent in the process of using a sample to make inferences about a larger population.

In statistical inference, the sampling error is an essential concept as it helps in determining the precision of the sample estimate. The smaller the sampling error, the more accurate is the estimate of the population parameter.

It is important to consider and account for sampling error when interpreting the results of a study or drawing conclusions based on sample data.

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Answer:

........................

The dissociation curve is a graphical representation of the relationship between the fractional saturation of hemoglobin (Y-axis) and the partial pressure of oxygen (X-axis) under specific conditions. It provides important information about the binding and release of oxygen by hemoglobin.

The dissociation curve for hemoglobin exhibits a sigmoidal (S-shaped) shape. At low partial pressures of oxygen, such as in tissues, hemoglobin has a low affinity for oxygen and only binds a small amount. As the partial pressure of oxygen increases, hemoglobin's affinity for oxygen increases, resulting in a rapid increase in the binding of oxygen molecules. However, once the hemoglobin becomes nearly saturated with oxygen, the curve levels off, indicating that further increases in partial pressure have minimal effects on oxygen binding.

To calculate the fractional saturation of hemoglobin at a given partial pressure of oxygen, you can use the Hill equation:

Y = [O2]^n / ([O2]^n + P50^n)

Where:

Y is the fractional saturation of hemoglobin,

[O2] is the partial pressure of oxygen,

P50 is the partial pressure of oxygen at which hemoglobin is 50% saturated,

n is the Hill coefficient, which represents the cooperativity of oxygen binding.

To determine the P50 value experimentally, the partial pressure of oxygen at which hemoglobin is 50% saturated, you can plot the dissociation curve and identify the point where the curve reaches 50% saturation.

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Answer:

13*12 is greater than 11*14 by 2 meters^2

Step-by-step explanation:

\(A=wl=13*12=156m^2\\A=wl=11*14=154m^2\)

Goodluck

Answer:

Jenny's room has a great area.

Step-by-step explanation:

Jenny's room

\(area = l \times b \\ = 13 \times 12 \\ = 156 {ft}^{2} \)

Ruth's room

\(area = l \times b \\ = 14 \times 11 \\ = 154 {ft}^{2} \)

so,

\(156 > 154\)

So ,Jenny's room has a great area than Ruth's room.

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

The product to this problem is simplified to:  \(1+14f+49f^{2}\)

Step-by-step explanation:

1) First place out what was given:

\((-1 -7f)^{2}\)

Squared is the same thing as multiply to itself, so you would create a pair of

\((-1 -7f)^{2}\)  

(For example, if you said: \(x^{2}\) it is the same as saying or putting: x · x)

2) Then create your pair which would look like:

\((-1 -7f)(-1 -7f)\)

3) Next step is to do the FOIL method

(Like how it is shown in the picture, we will do this method and create one whole expression!)

4) Creating and combining your expression into one whole problem, by using the foil method.

\((-1 -7f)(-1 -7f)\)

First - F: \(1\)

Outside - O: \(7f\)

Inside - I: \(7f\)

Last: \(49f^{2}\)

This will be:

\(1+14f+49f^{2}\)

And this will be your answer!

Answer:

y+2=1/2(x+3)

Why?

Point slope form is written as (y-y1) = m(x-x1) with y1 being the value of y at a certain point, x1 being the value of x at a certain point, and m being slope. y1 and x1 are given to us by the point (-3, -2) letting us know that y1=-2 and x1=-3. The only thing left to find is slope. Parallel lines have the same slope. If the line we are trying to find is parallel to the one given in the question, we just need to find the slope of the equation given. That equation is given in slope-intercept form which is y = mx + b. m is still slope so we can see that the slope is 1/2. Now we can plug m, x1 and y1 into the point slope form equation to get y + 2 = 1/2(x + 3)

Answer:

y = (1/3)x + 1

Step-by-step explanation:

A parallel line has the same slope as the reference line.  This means the new equation would have a slope of (1/3).  The y-intercept, -5, needs to be different.  But since the line needs to pass through point (3,2), we need a value of b that will cause that to happen.

We can start with y = (1/3)x + b.  As long as b is not -5, the line will be different and parallel.  To force it through point (3,2), just enter those values and solve for b:

y = (1/3)x + b

2= (1/3)*3 + b

2 = 1 + b

b = 1

The equation becomes y = (1/3)x + 1.

See attached image.

Answer:

C. 27.5

Step-by-step explanation:

since 24 and 31 are one standard deviation below or above the mean, we could subtract the two values and divide them by two to help find the mean.

we would first subtract the two values

we would then divide that number by 2 since we are finding the average between the two numbers

using the 3.5, you add it to the lower value (24) and subtract it from the higher value (31)

since both calculated numbers were equal, we know that we calculated the mean correctly.

Answer:

4y-4 Hope this helps! :)

Step-by-step explanation: