We are given the following expression
\(-\frac{1}{3}-10+7+\frac{2}{3}+5\)We are asked which of the given option shows the best use of associative and commutative properties to simplify the above expression?
Let us first have a look at associative and commutative properties of addition.
Associative property of addition:
\(a+(b+c)=(a+b)+c\)Which states that when you add you can group numbers in any order.
Commutative property of addition:
\(a+b=b+a\)Which states that you can add in any order, the result would always be the same.
Option A is given by
\((-\frac{1}{3}+\frac{2}{3})+\lbrack5+7+(-10)\rbrack\)As you can see, the first part covers the commutative property and the second part covers the associative property.
We simply grouped the fractional parts together and also grouped the integers together.
Remember that you can group numbers in any order, the result would always be the same.
Therefore, option A seems to be the best use of associative and commutative properties to simplify the given expression.
find the area of a regular pentagon with radius 22
Which expression could be used to determine the area of the shaded figure?
use an appropriate local linear approximation to estimate the value of the given quantity.answer q3 only.
In this case, we know that
\(cos30=\frac{\sqrt[\placeholder{⬚}]{3}}{2}\)so we can use this value to estimate cosine of 32 degrees.
The local linear approximation is given by
\(y-y_1=m\lparen x-x_1)\)where, in our case,
\(\begin{gathered} x=32 \\ x_1=30 \\ y=cos32 \\ y_1=cos30=\frac{\sqrt{3}}{2} \end{gathered}\)and m is the derivative of the function
\(cos\theta\)evaluated at
\(\theta=30\text{ degrees}\)In this regard, the derivative of cosine of thetat is given by
\(\frac{d}{d\theta}cos\theta=-sin\theta\)then the slope m is given as
\(m=\frac{d}{d\theta}cos\theta_{\theta=30}=-s\imaginaryI n30=-\frac{1}{2}\)Then by substituting this value and the above ones on the local linear approximation, we have
\(y-y_1=m\operatorname{\lparen}x-x_1)\Rightarrow cos32-\frac{\sqrt[]{3}}{2}=-\frac{1}{2}\left(32-30\right)\)which gives
\(\begin{gathered} cos32-\frac{\sqrt{3}}{2}=-\frac{1}{2}\left(2\right) \\ cos32-\frac{\sqrt{3}}{2}=-1 \end{gathered}\)then by moving square root of 3 over 2 to the right hand side, we get
\(cos32=-1+\frac{\sqrt[\placeholder{⬚}]{3}}{2}\)
Solve the following system of equations.3x+5y=164x-9y=-10x =Y=
To simplify the calculations, you can set the following system of equations that is equivalent to the given system. Multiply the first equation by 4, and the second by 3:
\(\begin{gathered} 12x+20=64, \\ 12x-27y=-30. \end{gathered}\)Subtracting the second equation for the first one, you get:
\(\begin{gathered} 12x+20-12x+27y=64+30, \\ 47y=94, \\ y=\frac{94}{47}, \\ y=2. \end{gathered}\)Substituting y=2 in the first equation and solving for x, you get:
\(\begin{gathered} 3x+5(2)=16, \\ 3x+10=16, \\ 3x=16-10, \\ 3x=6, \\ x=\frac{6}{3}, \\ x=2. \end{gathered}\)Answer: \(x=2,y=2.\)-3x-5x+8=16
Please I don’t understand
-1
We can solve in this way,
-3x-5x+8=16
-8x=16-8
-8x=8
x= -8/8
x= -1
Therefore for this equation, x= -1.
En una ciudad de 5000 habitantes, la tasa diaria
de infección con un virus de la gripe varia directamente con el producto de
personas infectadas y el número de personas no infectadas. Cuando se han
infectado 1000 personas, la gripe se esparce a razón de 40 nuevos casos por día.
¿Para qué número de personas infectadas, la tasa diaria de infección es la
máxima?
According to the information, the maximum infection rate is: k * 2500 * (5000 - 2500) = 6250k = 40
How to calculate for what number of infected people, the daily infection rate is the maximum?To address this problem, we can use the law of the infection rate, which states that the infection rate is directly proportional to the product of the number of people infected and the number of people not infected. Therefore, we can write:
infection rate = k * (infected people) * (uninfected people)where "k" is a constant of proportionality. Since we want to find the number of people infected that produces the maximum infection rate, we can consider the infection rate as a function of the variable "x" representing the number of people infected. Therefore, we can write:
infection rate = k * x * (5000 - x)To find the value of "x" that maximizes the infection rate, we can derive this function and set the derivative equal to zero:
d(infection rate)/dx = k * (5000 - 2x) = 0This implies that 5000 - 2x = 0, and therefore:
x = 2500Therefore, the number of infected people that produces the maximum daily rate of infection is 2,500.
However, we must verify that this result is consistent with the information given in the problem. We know that when there are 1,000 people infected, the flu spreads at the rate of 40 new cases per day. Therefore, if we add 1,500 more infected people (for a total of 2,500), the infection rate would be:
infection rate = k * 2500 * (5000 - 2500) = 6250kIf the infection rate is 40 new cases per day, we have:
40 = 6250kwhich implies that:
k = 0.0064Therefore, the maximum infection rate is:
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plsss explain nd i’ll give brainliest answer
Answer: 118
Step-by-step explanation:
Angle ABC and Angle BCD add up to 180 degrees, because Line AB and line CD are parallel. Because of this, Angle BCD can be moved up the the angle above 3n-47. Because the two angles fall on to a straight line, we can say that (3n-47)+(n+7)=180. Solving, n=55, so angle ABC equals 118 degrees.
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At a zoo in a butterfly enclosure, 5 drops of nectar is sufficient for 2 butterflies. How many butterflies could be fed with 59 drops of nectar?
Answer:
111 can i get brailyist for replying so fast.
Answer:
23
Step-by-step explanation:
\( \frac{2}{5} \times \frac{x}{59} \)
the number of drops of nectar goes on the bottom, and the number of butterflies goes on the top
then you cross multiply to get 5x= 118
solve for × and you get 23.6
for this situation, 0.6 of a butterfly doesn't make sense, so we need to round down.
we round down because it's okay if there's extra nectar, but there can't be less than enough.
you can be 23 butterflies with 59 drops of nectar
A ferris wheel is 12 meters in diameter and makes one revolution every 8 minutes. Suppose you board the ferris wheel at ground level when time is t=0. For how many minutes of one revolution will your seat be above 9 meters?
The time taken for one revolution of our seat to be above 9 meters is 12 minutes.
What is the linear speed of the Ferris wheel?
The linear speed of the Ferris wheel is the tangential speed of the wheel describing the rate of change of linear displacement with time.
v = ωr
where;
ω is the angular speed = 1 rev/8minr is the radius of the circular path = 12 m / 2 = 6 mω = 1 rev/8min
v = (1 rev/ 8 min) x 6m
v = (6/8) rev.m/min
The time of motion of one revolution at height of 9 m.
d = 9 rev.m
t = d/v
t = (9) / (6/8)
t = (9 x 8) / 6
t = 12 minutes
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Solve the problem using a system of equations: The difference of the squares of two numbers is 15. The difference of twice the square of the first number and the square of the second number is 30. Find the numbers.
(__,__),(__,__)
The numbers which hold true for the situation modelled in the task content are; (-√15, 0) and (+√15, 0).
Which numbers hold true for the situation?The system of equations which model the situation is;
x²- y² = 15
2x² - y² = 30.
Hence, by subtracting equation 1 from 2; we have;
x² = 15
x = ±√15.
and hence by substitution; the value of y is;
(√15)² + y = 15
y = 0.
Hence, the required values of the numbers are;
(-√15, 0) and (+√15, 0).
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On a certain hot summer's day, 195 people used the public swimming pool. The daily prices are $1.75 for children and $2.25 for adults. The receipts for admission totaled $383.75. How many children and how many adults swam at the public pool that day?
Answer:
3x-x+2=4
Step-by-step explanation:
Children = x
Adults = y
x + y = 754...1
1.50x + 2.25y = 1422...2
Multiply (1) by 2.25
2.25x + 2.25y = 1696.50...3
1.50x + 2.25y = 1422...2
Subtract (2) from (3)
0.75x = 274.50
x = 366
Substitute x = 366 in (1)
x + y = 754
366 + y = 754
y = 388
366 children and 388 adults swam at the pool.
The quadrilateral, ABCD, is inscribed in a circle. Using the diagram below, which of the following angles would be supplementary?
Answer:
It’s the second one
Step-by-step explanation:
The angles that would be supplementary will be ∠A & ∠C and ∠B & ∠D. Then the correct option is D.
What is a cyclic quadrilateral?If the quadrilateral is inscribed in a circle then the quadrilateral is known as a cyclic quadrilateral. And the sum of opposite angles of the quadrilateral is 180 degrees.
Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.
We know that the sum of opposite angles of the quadrilateral is 180 degrees. Then the equation is given as,
∠A + ∠C = 180°
∠B + ∠D = 180°
The angles that would be supplementary will be ∠A & ∠C and ∠B & ∠D. Then the correct option is D.
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HELP QUICK EASY Pi WORK PLEASE HELP QUICK
Answer:
3.998 km?
not exactly sure but good luck
Step-by-step explanation:
Can someone help me with this problem? I need to find x and y
Answer:
x = √17
y = 10.1
Step-by-step explanation:
x² + 8² = 9²
x² = 81 - 64 = 17
x = √17
sin∅ = √17/9
∅ = 27.27°
9/y = cos(27.27)
y = 9/cos(27.27) = 10.13
y = 10.1
[11 - {4 - 11} ] times (5-4)
Answer:
18
Step-by-step explanation:
[11-(-7)] * (1)
[11+7] * (1)
18*1
18
A man deposits $ 14,850 into a bank, which pays 4% interest that is compounded
semiannually. What will he have in his account at the end of three years?
Given:
Principal = $14850
Rate of interest = 4% compounded semiannually.
Time = 3 years
To find:
The amount after 3 years.
Solution:
Formula for amount is:
\(A=P\left(1+\dfrac{r}{n}\right)^{nt}\)
Where, P is principal, r is the rate of interest in decimal, n is the number of times interest compounded and t is the number of years.
The interest is compounded semiannually, so n=2.
Putting \(P=14850, r=4, n=2, t=3\) in the above formula, we get
\(A=14850\left(1+\dfrac{0.04}{2}\right)^{2(3)}\)
\(A=14850\left(1+0.02\right)^{6}\)
\(A=14850\left(1.02\right)^{6}\)
On further simplification, we get
\(A=14850(1.12616242)\)
\(A=16723.511937\)
\(A\approx 16723.51\)
Therefore, the amount in the account after three years is $16723.51.
Find ordered pairs y=-7x+8
The ordered pairs for the equation y = -7x + 8 are (0, 8), (1, 1), and (-1, 15).
What are the ordered pairs for the equation y?To find ordered pairs for the equation y = -7x + 8, we can substitute different values of x and solve for y.
Let's choose three values of x:
When x = 0, y = -7(0) + 8 = 8. So one ordered pair is (0, 8).
When x = 1, y = -7(1) + 8 = 1. So another ordered pair is (1, 1).
When x = -1, y = -7(-1) + 8 = 15. So another ordered pair is (-1, 15).
Therefore, the ordered pairs are (0, 8), (1, 1), and (-1, 15).
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Your statement balance is $433.97. You have an outstanding check for $46.78 and an
outstanding deposit for $235.00. What is your adjusted balance?
A) S245.75
B) $387.19
C) $622.19
D) $668.97
if there are three sleds for every five children which equation shows the correct relationship between the number of sleds
Answer:
multiplication
Step-by-step explanation:
it should be 5×3
Determine the equation of the line below using the given slope and point.
Slope = m = 4 , Point (-3,-11)
\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{-11})\hspace{10em} \stackrel{slope}{m} ~=~ 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-11)}=\stackrel{m}{ 4}(x-\stackrel{x_1}{(-3)}) \implies y +11 = 4 ( x +3) \\\\\\ y+11=4x+12\implies {\Large \begin{array}{llll} y=4x+1 \end{array}}\)
The equation is:
⇨ y + 11 = 4(x + 3)Work/explanation:
Recall that the point slope formula is \(\rm{y-y_1=m(x-x_1)}\),
where m is the slope and (x₁, y₁) is a point on the line.
Plug in the data:
\(\rm{y-(-11)=4(x-(-3)}\)
Simplify.
\(\rm{y+11=4(x+3)}\)
Hence, the point slope equation is y + 11 = 4(x + 3).Simplified to slope intercept:
\(\rm{y+11=4x+12}\)
\(\rm{y=4x+1}\) <- this is the simplified slope intercept equation
Giving max points and brain thing
Determine whether the relations are functions.
YES
NO
{(1, 1), (2, 2), (3, 3), (4,4)}
{(1,2), (3, 4), (5, 6), (1, 3}
{(1, 6), (9, 3), (6, 1), (3, 9)}
{(7,5), (-3, 7), (-7, 5), (-3,5)}
Answer:
yes {(1, 1), (2, 2), (3, 3), (4,4)}
{no (1, 6), (9, 3), (6, 1), (3, 9)}
yes {(1,2), (3, 4), (5, 6), (1, 3}
no {(7,5), (-3, 7), (-7, 5), (-3,5)}b
I think it's correct
Step-by-step explanation:
choose all the values that are greater than 12/16. you must select all that apply 12.1612.16%¾1¾0.875%
choose all the values that are greater than 12/16. you must select all that apply
12.16
12.16%
¾
1¾
0.8
75%
we have that
12/16=6/8=3/4=0.75=75%
so
Verify each option
12.16
12.16 >0.75
therefore
12.16 is greater than 12/16
3/4
3/4=12/16
therefore
3/4 is not greater than 12/16
1 3/4
1 3/4 > 0.75
therefore
1 3/4 is greater than 12/16
0.8
0.8 >0.75
therefore
0.8 is greater than 12/16
75%
75%=75%
therefore
75% is not greater than 12/16
express the following into standard form
\( \frac{1}{3500000000} \)
Answer:
350000
P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6P(-2,2), Q(4,2), R(2, -6), S(-4,-6
PQRS is a parallelogram. Angle QSP = 47°. Angle QSR = 24°, PST is a straight line.
Answer:
The value of x = 109°
angle PQS = 24°
Step-by-step explanation:
24° + 47° + x = 180° { angles on straight line }
=> 71 ° + x = 180°
=> x = 180° - 71°
=> x = 109°
Now,
Angle PQS = 24°
angle PQS = angle QSR { alternative angle }
Step-by-step explanation:
a)(i) x=109°
(ii)It's given that PST is straight line then PST=180°,and
PST=QSP+QSR+x
180° =47°+24°+x
180°=71°+x
180°-71°=x
109°=x
b)(i)PQS=71°
(ii)we know opposite angles are equal in parallelogram
so PSR=PQR=71°
2^(2t)-12(2^(t))+32=0
Answer:
t = 2 and t = 3.
Step-by-step explanation:
To solve the equation 2^(2t) - 12(2^t) + 32 = 0, we can use a substitution to simplify the equation. Let's set u = 2^t:Substituting u = 2^t, the equation becomes:u^2 - 12u + 32 = 0Now we have a quadratic equation in terms of u. We can solve it by factoring or using the quadratic formula. Let's try factoring:(u - 4)(u - 8) = 0Setting each factor equal to zero, we have:u - 4 = 0 or u - 8 = 0Solving for u:u = 4 or u = 8Now, substitute back u = 2^t:For u = 4:
2^t = 4Taking the logarithm base 2 of both sides:
t = log2(4)
t = 2For u = 8:
2^t = 8Taking the logarithm base 2 of both sides:
t = log2(8)
t = 3
Schedule K-1 (Form 8865) (irs.gov) use this form provided to Natalie Maloney
Schedule K-1 (Form 8865) is used to report the partner's share of income, deductions, credits, and other items for the tax year of a foreign partnership.
Some guidelines for completing the form:Identification information: Fill out the partnership's name, employer identification number (EIN), and address.
Partner's identifying information: Fill out the partner's name, identifying number (usually their taxpayer identification number or TIN), address, and their percentage of ownership in the partnership.
Income items: Report the partner's share of ordinary income, net rental income, gain or loss from the sale of property, and other income items on lines 1-7. Make sure to also include any foreign source income or deductions.
Deductions: Report the partner's share of partnership deductions, such as business expenses, depreciation, and depletion, on lines 8-15.
Credits: Report the partner's share of any foreign taxes paid or other credits on lines 16-21.
Other items: Report any other items that are required to be reported on Schedule K-1, such as guaranteed payments, charitable contributions, and Section 743(b) adjustments, on lines 22-27.
At-risk limitation: If the partnership is engaged in an activity subject to the at-risk rules, report the partner's share of the at-risk limitation on line 28.
Passive activity limitation: If the partnership is engaged in a passive activity, report the partner's share of the passive activity limitation on line 29.
P.S Your question is incomplete, so I gave a general overview of the tax form for better understanding.
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What is the effect on the graph of f(x) = x2 when it is transformed to h(x) = 2 x2 + 15?
Answer:
B
Step-by-step explanation:
The effect on the graph of f(x)=x² when it is transformed to h(x)=2x²+15 is the graph of f(x) is vertically streched by 2 and moved up by 15 unit.
How does the transformation of a function happen?The transformation of a function may involve any change.
Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs) etc.
If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:
Horizontal shift (also called phase shift):
Left shift by c units, y=f(x+c) (same output, but c units earlier)
Right shift by c units, y=f(x-c)(same output, but c units late)
Vertical shift
Up by d units: y = f(x) + d
Down by d units: y = f(x) - d
Stretching:
Vertical stretch by a factor k: y = k × f(x)
Horizontal stretch by a factor k: y = f(x/k)
Given two functions, f(x) and h(x). Also, the function f(x) = x² is transformed to form h(x) = 2x² + 15. Therefore, we can write the transformation as,
f(x) vertically streched by a factor of2 first, Therefore,
g(x) = 2f(x)
= 2x²
Now, the function g(x) is moved up by 15 units, therefore,
h(x) = g(x) + 15
= 2x² + 15
Hence, the effect on the graph of f(x)=x² when it is transformed to h(x)=2x²+15 is the graph of f(x) is vertically streched by 2 and moved up by 15 unit.
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What is the remainder when the following polynomial division is performed? Place the answer in the proper location of the gird. Do not include parentheses in your answer.
The remainder of the polynomial division \(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)}\) is 2y²
How to determine the remainder of the polynomial divisionFrom the question, we have the following parameters that can be used in our computation:
\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)}\)
When the numerator is expanded, we have
\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)} = \frac{(y - 1)(y^3 + 1) + 2y^2}{y^3 + 1}\)
Split the expanded expression
\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)} = \frac{(y - 1)(y^3 + 1)}{y^3 + 1} + \frac{2y^2}{y^3 + 1}\)
Evaluate
\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)} = y - 1 + \frac{2y^2}{y^3 + 1}\)
From the above, we have
Quotient = y - 1
Remainder = 2y²
Hence, the remainder of the polynomial division is 2y²
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Select the correct answer from each drop-down menu.
The total area of the three triangles is
square units.
The area of the figure is
square units.
The total area of the three triangles is square units is 36 and the area of the figure is square units is 60.
What is the triangle?The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.
From the figure, the area of triangles can be calculated using the:
Area = (1/2)height×base length
Area of three triangle = 1/2(4×6) + 1/2(6×4) + 1/2(4×6)
Area of three triangle = 1/2(24×3) = 36 square units
Area of the figure = area of three triangle + area of the rectangle
= 36 + 6×4
= 60 square units
Thus, the total area of the three triangles is square units is 36 and the area of the figure is square units is 60.
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5
10
Joe borrowed $7,000 from the bank at a rate of 7% simple interest per year. How much interest did he pay
in 3 years?
In 3 years, Joe pays $
in interest.
Answer:
f h f
Step-by-step explanation:
jikdmj n