during their developmental process, b and t lymphocytes undergo a selective process that specializes them for reacting only to one specific

To get the mass for these molecules, we will need to do three steps:

1 - convert from number of molecules to number of moles.

2 - calculate the molar mass for H₂O.

3 - use it to convert from number of moles to mass.

To convert from number of molecules to number of moles, we need to divide the number of molecules by the Avogadro's number:

Now, to calculate the molar mass of H₂O, we need the molar masses of H and O, which we can get on a periodic table:

Using it, we can convert the number of moles to mass:

Now, the proper way of approximating this value is to maintain the same number of significant figures as the number of molecules, because we used multiplications and divisions. It has two significant figure, so we need to approximate accourdingly:

So, there is 128.680... grams or, approximately, 130 grams of water.

Question

Answer

Explanation

Radio Frequency Is one of the electromagnetic frequency waves that lie in the range stretching from below 3 kilohertz to around 300 gigahertz and which includes the frequencies used for communication signals (such as for radio and television broadcasting and cellular telephone and satellite transmissions)

I hope this helps

The isotopes' number and the sum of the protons and neutrons are the same because the latter is equal to the mass number of an element.

Mass number of an element is the total number of protons and neutrons in an atomic nucleus.

According to this question, a table is presented where the isotope number of different elements equate the sum of the protons and neutrons in the atom of that element.

This is because the sum of the neutrons and protons in an atom is equal to the mass number of an element. This means that the isotope number is the mass number of each isotope.

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Answer:

7. isotonic

8. hypertonic

9. hypotonic

10. isotonic

11. hypotonic

12. hypertonic

Answer:

4 mol MgO

Explanation:

convert the limiting reactant to product by using dimensional analysis in order to see how many moles total can be created of the product

4 mol Mg x \(\frac{2 mol MgO}{2 mol Mg}\) = 4 mol MgO

Answer:

Two ions that produced similar colors in the flame test were Ca+2 and Sr+2. 3.

Explanation:

The colors are produced when an electron jumps to a higher level and then jump back down.

Ba2+ and Cu2+ and Sr2+ and Li+ were the pair with the similar color. Sr and Li displayed red colors, while Ba and Cu had mild greenish yellowish hues.

Why do some ions in the flame test generate colors that are similar?

The precise sizes of the potential energy jumps differ from metal to metal. As a result, the flame color of each metal will differ due to its unique spectral line pattern. The movement of the electrons in the metal ions contained in the compounds results in the hues of the flame.

The energy released by each electron when it returns to its initial condition determines the hue of the light that is produced.

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Answer:

Filtration

Explanation:

Answer:

Under the earth's surface, rocks melt, metamorphize, and crystalize.

Explanation:

Metamorphic and Igneous rocks are basically dependant on the heat/pressure of the environment under the surface :) Melting, metamorphosing and crystallization all occur under earth's surface.

The specific processes in the rock cycle that occur beneath the Earth surface are :

Under the Earth surface the specific rock cycle processes that leads to the formation of the different types of rocks includes;  Melting, metamorphization and rock crystallization.

Metamorphic rocks are formed from other rocks ( sedimentary and igneous rocks)  due to the change in temperature and this process is metamorphization. while igneous rocks are formed from molten rocks caused by the melting process. Sedimentary rocks are formed by the deposition of sediments from weathering of existing rocks this is the  crystallization process.

Hence the specific process in the rock cycle that occur beneath the Earth's surface are : Melting, metamorphosing and crystallization.

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Answer:

Atomic number of a chemical element is the number of protons found in the nucleus of every atom of that element.

The mass number, also called atomic mass number or nucleon number, is the total number of protons and neutrons in an atomic nucleus.

The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom.

Answer:

750000

Explanation:

multiply the mass value by 1e+6

Answer:

750000 mg is ur answer My G

Explanation:

No Explanation Needed Ig

Technetium-99m is a radioisotope that is widely used in nuclear medicine for various imaging studies. It is usually produced through a process called generator system from the decay of its parent isotope, Molybdenum-99 (Mo-99).

How technetium-99m is generated:Technetium-99m is generated by a process called a generator system from the decay of its parent isotope, Molybdenum-99 (Mo-99). This generator system is essentially a column packed with a gel-like substance, which is usually made of alumina, silica, or another material. The column contains Mo-99, which is produced in a nuclear reactor, and its daughter isotope Technetium-99m (Tc-99m).The Mo-99 decays into Tc-99m by beta decay, emitting a beta particle and a neutrino.

As a result, Tc-99m is separated from Mo-99 by using a saline solution or another eluant to flush the column. The Tc-99m-containing eluant is then used for imaging studies.There are several advantages to using Tc-99m for imaging studies. It has a short half-life of only six hours, which means that it does not stay in the body for a long time and is eliminated quickly. This makes it safer for patients than isotopes with longer half-lives. Additionally, Tc-99m emits gamma rays, which can be detected by imaging equipment such as gamma cameras. This allows for high-quality imaging studies that can help diagnose a wide range of medical conditions.

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Answer:

B

Explanation:

Answer:

\(a = \frac{24.79078- 1.7161b}{1.310 - b}\)

\(b = 1.310 - \frac{22.5427}{a - 1.7161}\)

Explanation:

Given

\(P = 1\ atm\)

\(V = 1.310\ L\)

\(T =160\ K\)

Required

Solve for a and b

Van Der Waals equation is:

\(P = \frac{RT}{V - b} - \frac{a}{V^2}\)

Substitute values for P, V and T, we have:

\(1 = \frac{R*160}{1.310 - b} - \frac{a}{1.310^2}\)

R is a constant and the value is:

\(R = 0.0821\)

So, the equation becomes:

\(1 = \frac{0.0821*160}{1.310 - b} - \frac{a}{1.310^2}\)

Simplify the expression

\(1 = \frac{13.136}{1.310 - b} - \frac{a}{1.7161}\) ----- (a)

Solving for (a):

\(1 + \frac{13.136}{1.310 - b} = \frac{a}{1.7161}\)

Multiply both sides by 1.7161

\(a = [1 + \frac{13.136}{1.310 - b}] * 1.7161\)

Take LCM

\(a = [\frac{1.310 - b+13.136}{1.310 - b}] * 1.7161\)

Evaluate like terms

\(a = [\frac{14.446- b}{1.310 - b}] * 1.7161\)

Open bracket

\(a = [\frac{24.79078- 1.7161b}{1.310 - b}\)

Solving for (b), we have:

\(1 + \frac{13.136}{1.310 - b} = \frac{a}{1.7161}\)

Subtract 1 from both sides

\(\frac{13.136}{1.310 - b} = \frac{a}{1.7161}-1\)

Take LCM

\(\frac{13.136}{1.310 - b} = \frac{a-1.7161}{1.7161}\)

Inverse both sides

\(\frac{1.310 - b}{13.136} = \frac{1.7161}{a - 1.7161}\)

Multiply both sides by 13.136

\(1.310 - b = 13.136 * \frac{1.7161}{a - 1.7161}\)

\(1.310 - b = \frac{22.5427}{a - 1.7161}\)

Collect like terms

\(b = 1.310 - \frac{22.5427}{a - 1.7161}\)

The pressure of \(N_{2}\) will rise under the given conditions. And, Yes, it is possible to reverse this tendency by adding \(H_{2}\). The minimum pressure of H2 required to reverse the tendency is 0.01 atm.

The reaction involved is: \(N_{2}\)(g) + 3\(H_{2}\)(g) ⇌ 2\(NH_{3}\)(g)  Hence, when \(H_{2}\) is added to the above system, the \(N_{2}\) and  \(H_{2}\)  will react to produce \(NH_{3}\). This reaction will reduce the amount of \(N_{2}\) present in the system, causing the pressure of \(N_{2}\) to decrease. Therefore, by adding \(H_{2}\)  , we can change the tendency of \(N_{2}\) pressure from rise to fall.To calculate the minimum pressure of  \(H_{2}\)  required to reverse the tendency, we have to use the equilibrium constant, Kp. The expression for Kp for the above reaction is: Kp =( \(NH_{3}\)) / p(\(N_{2}\)) p3( \(H_{2}\) )

At equilibrium, Kp = 1.7 × 104 at 1126 °C.Now, we will solve for the minimum pressure of \(H_{2}\)   needed to reverse the tendency. Let's assume that the pressure of \(N_{2}\) has increased by x atm. Therefore, the new pressure of \(N_{2}\) will be (0.0406 + x) atm. At equilibrium, we have:

p2(\(NH_{3}\) ) / p(\(N_{2}\)) p3( \(H_{2}\) ) = 1.7 × 104

On substituting the given values and simplifying, we get:

p2(\(NH_{3}\)) / p(N2) = 6.39 × 10-5

Now, p2(\(NH_{3}\)) = 5.97 atm, and p(\(N_{2}\)) = (0.0406 + x) atm.

On substituting these values, we get:5.97 / (0.0406 + x) = 6.39 × 10-5

Solving for x, we get:x = 0.00579 atm ≈ 0.01 atm (rounded to 2 significant digits)Therefore, the minimum pressure of \(H_{2}\)   required to reverse the tendency is 0.01 atm.

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The statement "hydrogen bonds can form between hydrogen and any non-metal" is FALSE.

Hydrogen bonds are the type of chemical bonds formed between a partially positively charged hydrogen atom of one molecule and a partially negatively charged electronegative atom (oxygen, nitrogen, or fluorine) of a different molecule.

The bond is between the hydrogen atom and the electronegative atom rather than between the two atoms involved. Because of the fact that only three atoms - oxygen, nitrogen, and fluorine - are the only ones electronegative enough to form hydrogen bonds with hydrogen, the statement above is false because hydrogen bonds only form between hydrogen and nitrogen, oxygen, or fluorine.

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Ammonia as proof that nitrate was converted to ammonia in the cultivation of nitrate broth Because amino acids are produced during protein synthesis, amino acid metabolism will always exist.

Nitrifying microorganisms in the soil change ammonia into nitrates. Nitrates are taken up by plants from the soil and used to assemble proteins. Animals may consume the plant, and its biomass may be used to produce animal protein.

The process of nitrate (NO3) being used as an electron acceptor for respiration microbes results in dissimilatory nitrate reduction to ammonium (DNRA), also known as nitrate/nitrite ammonification.

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Answer:

A.

Explanation:

❤️

Answer: it’s A. The paper towel should be wet, and the seeds should be placed in a dark place.

Explanation: I hope this helps!

Answer:

Natural Cycles

Explanation:

Most sulfur oxides are produced by burning: coal

Air pollution particles may be removed by _____. rain snow wind natural cycles

The three primary sources of air pollution are _____. factories cars electric power plants

The two basic types of air pollutants are _____. gases particulates

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The maximum number of grams of NH3 that can be produced by the reaction of 2.00 g of N2 with 3.00 g of H2 is 4.00 g.

This is because of the stoichiometric proportions of the reaction: 2 moles of N2 and 3 moles of H2 will produce 2 moles of NH3. According to the ideal gas law, 2.00 g of N2 and 3.00 g of H2 will produce 4.00 g of NH3.

The stoichiometry of the reaction can be calculated using the mole ratio of the reactants. Two moles of N2 are needed for every three moles of H2 in order to produce two moles of NH3.

This means that the ratio of N2 to H2 in the reaction is 2:3. To convert the grams of each reactant into moles, the molecular weight of each reactant is used.

N2 has a molecular weight of 28.02 g/mol and H2 has a molecular weight of 2.02 g/mol.

Once the mole ratios and molecular weights have been determined, the moles of each reactant can be calculated. 2.00 g of N2 is equal to 0.0714 mol, and 3.00 g of H2 is equal to 1.48 mol.

Using the mole ratios, the number of moles of NH3 that can be produced can be calculated. In this case, the maximum number of moles of NH3 is 0.0714 mol, since this is the limiting reactant.

The number of grams of NH3 produced can then be calculated using the molecular weight of NH3, which is 17.04 g/mol. 0.0714 mol of NH3 is equal to 1.22 g of NH3.

In conclusion, the maximum number of grams of NH3 that can be produced by the reaction of 2.00 g of N2 with 3.00 g of H2 is 4.00 g. This is due to the stoichiometric proportions of the reaction and the ideal gas law.

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Answer:

44.8 L

Explanation:

1 mole of a gas at s.t.p. occupies a volume of 22.4 L.

Molar mass of Neon is 20.1 g/mol

Number of moles of neon present in 40.2 g = Mass/molar mass

Number of moles = 40.2 / 20.1 = 2 moles.

Therefore, 2 moles of neon gas will occupy 2 * 22.4 L = 44.8 L

44.8 L

Molar mass of Neon is 20.1 g/mol

Number of moles of neon present in 40.2 g =\(Mass/molar mass\)

\(Number of moles = 40.2 / 20.1 \\= 2 moles.\)

At STP:-

Gases have a volume of 22.4L/mol.

Therefore, 2 moles of neon gas will occupy the volume is as follows:-

\(2 mol\times22.4 L/mol = 44.8 L\)

So, the volume is 44.8 L.

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Answer:

4g of hydrogen

Explanation:

4g of hydrogen (molar mass 2) corresponds to 2 moles of molecules or 4N number of atoms where N is the Avogadro's number (6.023×10

23)

Answer:

The balanced equation for the combustion of propane is:

C3H8 + 5O2 --> 3CO2 + 4H2O

So for every propane molecule, we need 5 oxygen molecules.

To calculate the number of oxygen molecules required to burn 2.56 x 10^22 propane molecules, we need to multiply the number of propane molecules by the ratio of oxygen molecules to propane molecules.

Ratio of O2 to C3H8 = 5:1

Number of O2 molecules required = (5/1) x 2.56 x 10^22 = 1.28 x 10^23

Now we can convert the number of oxygen molecules to grams using the molar mass of oxygen.

1 mole of O2 = 32 g

1.28 x 10^23 molecules of O2 = (1.28 x 10^23 / 6.022 x 10^23) moles of O2

Mass of O2 = (1.28 x 10^23 / 6.022 x 10^23) x 32 g

Mass of O2 = 6.82 grams

So, 6.82 grams of O2 are required to burn 2.56 x 10^22 propane molecules.

Answer:

C. 170 g.

Explanation:

multiply given moles by the molar mass of ammonia.

Answer:

water is liquid state of matter

Answer:

the answer is d

Explanation:

i just did it

The characteristic property of ionic compounds is B. They form hard, brittle crystals.

Ionic bond is a chemical bond formed as the result of transfer of electrons from one atom to another.

Ionic bonds are held by strong electrostatic force. Properties of ionic bonds are:

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The missing products of the neutralization reactions are;

1) KBr

2) NH3

3) HNO3

A neutralization reaction is a reaction that occurs between an acid and a base to yield salt and water only.

The missing products of the neutralization reactions are;

1) KBr

2) NH3

3) HNO3

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Answer:

KBr

2 NH4OH

2 HNO3

Explanation:

Answer:

V₂ = 5.97 L

Explanation:

Given data:

Initial temperature = 9°C (9+273 = 282 K)

Initial volume of gas  = 6.17 L

Final volume of gas = ?

Final temperature = standard = 273 K

Solution:

Formula:

The Charles Law will be apply to solve the given problem.

According to this law, 'the volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure'

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 6.17 L ×  273K /  282  k

V₂ = 1684.41 L.K / 282 K

V₂ = 5.97 L