during a ballistics test a bullet is fired into a thick gel to bring it to a stop. a 5.5-g bullet traveling at 325 m>s is brought to a stop in the gel by an average force of 550 n. what amount of time is needed for the bullet to come to rest?

Answers

Answer 1

The time needed for the bullet to come to rest, given that it was travelling at 325 m/s is 3.25×10⁻³ s

How do I determine the time needed for the bullet to stop?

We'll begin by obtaining the deceleration of the bullet. This is shown below:

Mass (m) = 5.5 g = 5.5 / 1000 = 0.0055 KgForce (F) = -550 NDeceleration (a) =? 5.71×10¹⁴

F = ma

-550 = 0.0055 × a

Divide both sides by 0.0055

a = -550 / 0.0055

a = -100000 m/s²

Finally, we shatll determine the time needed for the bullet to come to rest. Detail below:

Initial velocity (u) = 325 m/sDeceleration (a) = -100000 m/s² Final velocity (v) = 0 m/sTime (t) =?

a = (v - u) / t

-100000 = (0 - 325) / t

-100000 = -325 / t

Cross multiply

-100000 × t = -3

Divide both sides by -100000

t = -325 / -100000

t = 3.25×10⁻³ s

Thus, we can say that the time needed is 3.25×10⁻³ s

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Related Questions

Part a which fibers generate the smallest value for conduction velocity? Which fibers generate the smallest value for conduction velocity? c fibers d fibers b fibers a fibers

Answers

The fibers that generate the smallest value for conduction velocity are the C fibers.

C fibers are unmyelinated nerve fibers with a small diameter. Due to their lack of myelin sheath, which acts as an insulator, the conduction velocity of C fibers is relatively slow compared to other types of nerve fibers. These fibers are responsible for transmitting sensory information related to pain, temperature, and itch.

On the other hand, A fibers, specifically A-delta and A-beta fibers, are myelinated nerve fibers with larger diameters. The myelin sheath allows for faster conduction of nerve impulses, resulting in higher conduction velocities compared to C fibers. A-delta fibers are involved in the transmission of sharp, fast pain signals, while A-beta fibers are responsible for conveying touch and pressure sensations.

In summary, C fibers generate the smallest value for conduction velocity due to their small diameter and lack of myelin sheath, while A fibers, particularly A-delta and A-beta fibers, have larger diameters and myelination, resulting in faster conduction velocities.

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need help please and thank you​

need help please and thank you

Answers

Answer:

0.13m/s

Explanation:

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Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.

Answers

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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Why don't we see objects in the universe colliding or moving towards each other due to gravitational force?​

Answers

Answer:

the objects in the universe are evenly placed. This means that a celestial object's gravity may not be able to attract another object. Another reason may be that the stars in solar systems act as points of equilibrium for the planets in the system. Take for example the sun. It maintains the position of the planets in the system and likewise the earth maintains the position of the moon. You can picture it as evenly placed atoms in matter and the subsequent electrons held by the nucleus

Answer:

BECAUSE OF THE DISTANCEBETWEEN EACH OBJECT DECREASES THE CHANCE IN SEEING OBJECTS COLIDE. HOPE THIS HELPS ...

Which competition is the “ most important soccer competition in the world “ ?

a - National championship

b - World Cup

c - olympics

Answers

It would be B. The World Cup

Hope this helps

Have a great day/night

Describe the greenhouse
effect? (IR)

Answers

The greenhouse effect is the way in which heat is trapped close to Earth's surface by “greenhouse gases.” These heat-trapping gases can be thought of as a blanket wrapped around Earth, keeping the planet toastier than it would be without them. The greenhouse effect is a process that occurs when energy from a planet's host star goes through its atmosphere and warms the planet's surface, but the atmosphere prevents the heat from returning directly to space, resulting in a warmer planet.

Answer:

the greenhouse effect is the warming of the earth's surface and atmosphere which is caused by the presence of water vapour, carbon dioxide and certain other gasses

an lc circuit has an inductance of 20 mh and a capacitance of 5.0 pf. at time t = 0 the charge on the capacitor is 3.0 pc and the current is 7.0 ma. the total energy is:

Answers

An lc circuit has an inductance of 20 mh and a capacitance of 5.0 pf. at time t = 0 the charge on the capacitor is 3.0 pc and the current is 7.0 ma. the total energy is:  0.049 J.

To determine the total energy in the LC circuit, we need to consider the energy stored in both the inductor and the capacitor. The energy stored in an inductor is given by the formula: \(E_{inductor}\) = (1/2) * L * \(I^2\) where L is the inductance and I is the current. Substituting the given values, we have:

\(E_{inductor}\) = (1/2) * (20 mH) * \((7.0 mA)^2\)= 0.049 J (joules)

The energy stored in a capacitor is given by the formula: E_capacitor = (1/2) * C * , where C is the capacitance and V is the voltage across the capacitor. To find the voltage across the capacitor, we can use the equation: Q = C * V, where Q is the charge on the capacitor.

Substituting the given values, we have:

3.0 pC = (5.0 pF) * V

V = 0.6 V (volts)

Now, we can calculate the energy stored in the capacitor:

E_capacitor = (1/2) * (5.0 pF) * \((0.6 V)^2\) = 0.09 pJ (picojoules)

Finally, the total energy in the LC circuit is the sum of the energy stored in the inductor and the capacitor:

Total energy = \(E_{inductor}\) + E_capacitor = 0.049 J + 0.09 pJ

Since the units are different, we need to convert pJ to joules:

1 pJ = \(10^{ -12}P\) J

Therefore, the total energy in the LC circuit is approximately 0.049 J +  0.049 J. J, which can be simplified to 0.049 J.

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A rock falls off a cliff and hits the ground after three seconds. The rock's velocity is 29. 4 m/s when it hits the ground. What is its acceleration of the rock in the downward direction? 0. 31 ms2 3 ms2 9. 8 ms2 88. 2 ms2.

Answers

The acceleration of the rock in the downward direction is 9.8 m/s².

The time (t) taken by the rock to fall off the cliff = 3 s

We can use the kinematic equation of motion: v = u + at

Here, u = 0 (initial velocity of rock before falling off the cliff)

We can rearrange the equation to solve for acceleration: a = (v - u)/t = v/t

Substituting the given values, we get:

a = v/t= 29.4 m/s ÷ 3 s

≈ 9.8 m/s²

Therefore, the acceleration of the rock in the downward direction is 9.8 m/s².

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find the impulse of a 20.0 KG object accelerates to8.1 M/S from 2.3 M/S

Answers

Answer:

116 N•s

Explanation:

change in momentum = mvf-mvi

= m(Vf - Vi)

= 20( 8.1-2.3)

change in momentum= 116 kg•m/s

: .impulse is 116 N•s

Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg • m2. The father exerts a force on themerry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s2.(a) How long (in s) does it take the father to give the merry-go-round an angular velocity of 2.29 rad/s? (Assume the merry-go-round is initially atrest.)S(b) How many revolutions must he go through to generate this velocity?revolutions(C) If he exerts a slowing force of 270 N at a radius of 1.25 m, how long (in s) would it take him to stop them?s

Answers

a)

Since we have a constant angular acceleration we have that:

\(\alpha=\frac{\omega-\omega_0}{t}\)

Plugging the values we know we have that:

\(\begin{gathered} 4.44=\frac{2.29-0}{t} \\ t=\frac{2.29}{4.44} \\ t=0.516 \end{gathered}\)

Therefore it will take 0.516 (rounded to three decimals) seconds to achive this angular velocity.

b)

To find how many revolutions he needs we first calculate the change in angular position using the formula:

\(\begin{gathered} \omega^2-\omega^2_0=2\alpha(\theta-\theta_0) \\ (\theta-\theta_0)=\frac{\omega^2-\omega^2_0}{2\alpha} \\ (\theta-\theta_0)=\frac{2.29^2-0^2}{2(4.44)} \\ (\theta-\theta_0)=0.590551801 \end{gathered}\)

Now we divide this change in angular position by 2pi (the angle equivalent to a revolution) to get the revolutions:

\(\frac{0.590551801}{2\pi}=0.094\)

Therefore it takes 0.094 (round to three decimals) revolutions to get to this angular velocity.

c)

The torque is the force by the radius, then we have:

\(\tau=(270)(1.25)=337.5\)

But the torque is also equal to the moment of inertia multiplied by the angular acceleration:

\(\tau=I\alpha\)

Then we have:

\(\begin{gathered} 337.5=84.4\alpha \\ \alpha=\frac{337.5}{84.4} \\ \alpha=3.998815166 \end{gathered}\)

Now we use the formula for angular acceleration to get the time:

\(\begin{gathered} -3.998815166=\frac{0-2.29}{t} \\ t=\frac{-2.29}{-3.998815166} \\ t=0.573 \end{gathered}\)

Therefore it takes 0.573 seconds to stop the merry go round.

An amusement park ride travels up and down.
The vertical position of the
ride in meters over
time is shown below.

what is the displacement of the ride between 0 s and 16 s ?

what is the distance traveled between 0 s and 16 s ?


PLEASE HELPP!!!!

An amusement park ride travels up and down.The vertical position of the ride in meters overtime is shown

Answers

Answer:

Kindly check explanation

Explanation:

The total displacement between 0 seconds and 16second will be :

Final position (Xf) after 16 seconds = 0 m

Initial position(Xi) at 0 seconds = 12 m

(Xf - Xi) = 12m

The total distance traveled between 0 seconds and 16 seconds will be :

Vertical Distance traveled = 12 meters

The arrows in the diagram show the direction of the magnetic fields of the atoms that make up an object. Which sentence best describes the object? A. The object is made of nonmagnetic material. B. The material of the object can attract a magnet. C. The object is weakly magnetic. OD. The material of the object can be magnetized.​

The arrows in the diagram show the direction of the magnetic fields of the atoms that make up an object.

Answers

Option D, the sentence that best describes the object is the material of the object can be magnetized.​

Atoms of magnetic material

The direction of the magnetic fields of the atoms that make up an object is always aligned towards the north pole or south of the material.

Objects that are made of unmagnetised  materials such iron, cobalt and nickel are attracted to either pole of a magnet, but not repelled.

The diagram given shows unmagnetised material, and hence the material of the object can be magnetized.​

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A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?

Answers

Answer:

0.109  m/s

Explanation:

The calculation of the volume flow rate of the water is shown below:-

Av = Velocity (\(\pi\))(Radius)^2

= 0.87(\(\pi\))(0.2)^2

= 0.135258 m^3 / sec

= 0.109371429 m/s

or

= 0.109

So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come

A 0.57 kg rubber ball has a speed of 2.2 m/sat point A and kinetic energy 8.0 J at pointB. Finda) the ball’s kinetic energy at A.Answer in units of J.015 (part 2 of 3) 10.0 pointsb) the ball’s speed at B.Answer in units of m/s.016 (part 3 of 3) 10.0 pointsc) the total work done on the ball as it movesfrom A to B.Answer in units of J.

Answers

Given that the mass of the ball is m = 0.57 kg.

The speed of the ball is

\(v_A=2.2\text{ m/s}\)

A) The kinetic energy at point A will be

\(\begin{gathered} K\mathrm{}E._A\text{ =}\frac{1}{2}m(v_A)^2 \\ =\frac{1}{2}\times0.57\times(2.2)^2 \\ =1.38\text{ J} \end{gathered}\)

B) Given that the kinetic energy,

\(K\mathrm{}E._B=\text{ 8 J}\)

The ball's speed at point B will be

\(\begin{gathered} K\mathrm{}E._B=\frac{1}{2}m(v_B)^2 \\ v_B=\sqrt[]{\frac{2K.E._B}{m}} \\ =\sqrt[]{\frac{2\times8}{0.57}} \\ =5.298\text{ m/s} \end{gathered}\)

C) The total work done on the ball to move from point A to B is

\(\begin{gathered} W=K\mathrm{}E._B-K.E._A \\ =8-1.38\text{ } \\ =6.62\text{ J} \end{gathered}\)

Find the potential function and the gravitational field intensity function inside and outside of a thin ring with Radius R, in terms of r (the distance from the center of the ring to the field point.) Note: inside R >r, outside r>R. the function will be different.

Answers

The potential function and the gravitational field intensity function inside and outside of a thin ring with radius R, in terms of r (the distance from the center of the ring to the field point), are as follows:

Inside the ring (r < R): The potential function is given by V = -GM/r, and the gravitational field intensity function is E = GM/r², where G is the gravitational constant and M is the mass of the ring.

Outside the ring (r > R): The potential function is V = -GM/r + GM/R, and the gravitational field intensity function is E = GM/r², where G is the gravitational constant, M is the mass of the ring, and R is the radius of the ring.

Inside the ring (r < R), the potential function is given by V = -GM/r. This represents the gravitational potential due to the mass of the ring at a point inside the ring. The negative sign indicates that the potential decreases as the distance from the center of the ring decreases. The gravitational field intensity function is E = GM/r², representing the strength of the gravitational field at a point inside the ring. The field intensity decreases as the distance from the center of the ring increases, following an inverse square relationship.

Outside the ring (r > R), the potential function is V = -GM/r + GM/R. In addition to the potential due to the mass of the ring, there is an additional potential term GM/R, which arises from considering the ring as a point mass located at its center. The gravitational field intensity function remains the same as E = GM/r², indicating that outside the ring, the gravitational field follows an inverse square relationship with the distance from the center of the ring.

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a hunter went with a group of 4 people in the forest to hunt an antelope. the first person saw the antelope, the second one ran after it, the third one shot it and the fourth one carried it. As a student of S. 1 ,use the knowledge in measurements in Physics to help the hunter to equally share the meat. ​

Answers

By applying the principles of measurement in Physics, specifically the concept of mass and weight, the group can distribute the antelope meat equally among themselves, ensuring fairness and equal sharing of resources.  

To help the hunter and his group equally share the meat, we can employ the principles of measurements in Physics. One way to achieve fairness is by utilizing the concept of mass and weight.

Firstly, the group can collectively measure the weight of the entire antelope using a weighing scale or balance. This will give them the total mass of the meat. Let's assume it weighs 100 kilograms.

Next, the group needs to divide the meat equally among themselves. Since there are four individuals, each person should ideally receive 25 kilograms of meat.

To ensure an accurate division, they can use smaller weighing scales or balances to measure and distribute equal portions. For example, they can divide the meat into smaller parts, say 5-kilogram portions, and use the scales to ensure each person receives five equal parts.

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A direct current of 3.0 A flows through a circuit consisting of a battery and a 6.0 A resistor. Calculate the potential difference across the resistor. a​

Answers

Question :-

A Direct Current of 3.0 A flows through a Circuit consisting of a Battery and a 6.0 Ohm's Resistor. Calculate the Potential Difference across the Resistor .

Answer :-

Potential Difference is 18 Volt's .

Explanation :-

As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .

As we know ,

V = I R

Where ,

V denotes to Potential DifferenceI denotes to CurrentR denotes to Resistance

Therefore , by Substituting the given values in the above Formula :-

\( \sf {\dag \: \: \: Potential \: Difference \: = \: Current \: \times \: Resistance} \)

\( \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: \times \: 6.0} \)

\( \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: \times \: 6} \)

\( \bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }} \)

Hence :-

Potential Difference = 18 Volt's .

\( \underline {\rule {210pt}{4pt}} \)

Additional Information :-

\( \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)

\(\Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } \)

\(\Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)

\( \underline {\rule {210pt}{4pt}} \)

Note :-

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A runner ran 40 km at 10 km/hr. What amount of time did it take the runner to go this distance?

Answers

Answer:

4 hrs

Explanation:

40/10 = 4 hrs

a 30 cm volume of water was placed in a cylinder and a stone dropped in,the water rose
to 35 is it true the rock is 5 cm

Answers

The stone may have a diameter of  \(5 cm\)  , but it also may be smaller and denser, or larger and less dense. It is impossible to correctly estimate the size of the stone without more details.

What is the Archimedes' principle?

When an object is dropped into a liquid, it moves the same volume of liquid with it. The Archimedes principle is this.

In this instance, the addition of the stone caused the water in the cylinder to rise from \(30\) cm to \(35\) cm in volume. The volume of the stone is therefore equal to the \(5\) cm \(3\) volume difference between the two measurements.

However, this information alone cannot be used to estimate the stone's size in terms of its actual measurements.

Therefore, The stone may have a diameter of \(5 cm\) , but it also may be smaller and denser, or larger and less dense. It is impossible to correctly estimate the size of the stone without more details.

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Nitrogen-13 has a half-life of 10 minutes. How much of a 200 mg sample would remain after 30 minutes?.

Answers

25 milligrams of the initial 200 mg sample would remain after 30 minutes.

Nitrogen 13 has a half life of 10 minutes.

Having half life of 10 minutes mean that whatever be the initial concentration of the nitrogen 13 element, it will decrease down to half concentration after the 10 minutes.

So, if the initial concentration of the sample is 200 milligrams then after 10 minutes the concentration of the sample will be 100 mg and again after the 10 minutes the concentration will again decrease to half an the concentration of the sample will become 50 milligrams now again after further 10 minutes the concentration of the sample will reduce to only 25 milligrams.

So, where we can conclude that the amount of Nitrogen 13 that will be remaining after 30 minutes will be 25 milligrams

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Which waves can
travel though space

Answers

Answer: Radio waves

Explanation:

Radio waves can travel through space. So, if you're wearing a space suit that contains a radio unit and one of your buddies sends you a radio message that there's pizza in the space station, you'd be able to hear it. That's because radio waves aren't mechanical -- they're electromagnetic. Electromagnetic waves can transmit energy through a vacuum.

I have a project of how a steam engine works
pls tell me what i should research on or give ideas

Answers

In the metal junction box, insert the dowel rod and skewer so that the skewer is pointing up within the copper pipe.

How is the steam engine operated?

A steam engine is a heat engine that uses steam as its working fluid to carry out mechanical work. The steam engine moves a piston back and forth inside a cylinder using the force created by the pressure of the steam. A connecting rod and crank can convert this pushing force into a rotational force for work.

How are steam engines employed in modern times?

Technological devices have changed how people live. Nowadays, steam is used to propel ships and turn massive turbines that produce electricity for billions of people worldwide.

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radio telescopes of modest size can't make out as much detail (have a lower resolution) than visible light telescopes. how do astronomers overcome this limitation?

Answers

Astronomers can overcome the limitation of the lower resolution of radio telescopes by using a technique called interferometry.

Interferometry is a process that electrically connects several radio telescopes that are scattered apart. Astronomers can imitate a larger telescope with higher resolution by merging the signals from these telescopes.

With a single, modest-sized radio telescope, they are unable to obtain the finer details and crisper images that they are able to with this method. In order for interferometry to function, each telescope's signals must be precisely timed, aligned, and combined.

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2. When braking and turning, you use ___?
a. All four wheels of traction
b. Only the outside edge of your tires
c. Split traction
d. Additional traction

Answers

Answer:

split traction

Explanation:

A tank is is half full of oil that has a density of 900 kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 m/s2 for g. Assume r

Answers

The water weighs 900kg / (\(m^{2}\))

Force required to raise this layer is,

\(F_{t}\) = 900g(\(V_{t}\))

= 900(9.8) π(225 -\(y_{1}\) ^ 2) Δy

Each particle in the layer must travel a distance of approximately (15 + 5) -  \(y_{1}\)= 20 - \(y_{1}\)

The work \(w_{1}\) done to raise this layer to the top is approximately the product of the force \(F_{1}\) and the distance 20 - y

\(W_{1}\) ≈ \(F_{1}\)(20 - \(y_{1}\) )

≈ 900(9.8) π (225 - \(y_{1}\)^2)(20 - \(y_{1}\)) Δy

then solve,

and we get,

volume = π(225 - \(y_{1}\)^2)Δy

What is density ?

The substance's mass per unit of volume is known as its density (volumetric mass density or specific mass). Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho). The density of a pure substance is equal to its mass concentration in numbers. Density varies widely among materials and may be important in relation to packaging, purity, and buoyancy. The densest known elements under conditions of normal temperature and pressure are osmium and iridium. It is occasionally substituted by the dimensionless quantity "relative density" or "specific gravity," which is the ratio of the density of the material to that of a standard material, typically water, to make density comparisons across different systems of units easier.

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please help!!
There are more electrons in the orbitals of an atom that there are protons in the nucleus of the atom true or false

Answers

Answer:

An element is a pure substance that contains only one type of atom. TRUE. 2. ... FALSE, they are all carbon atoms. 7. The smallest unit of matter is an atom. TRUE. 8. When an ... TRUE. 10. Most of the mass of an atom is found in the electron layers. FALSE. 11. The nucleus of an atom contains protons and neutrons. TRUE ...

Explanation:

give four example each for newton's first,second,and thirdlaw of motion​

Answers

1st: [An airplane midflight] will maintain its direction unless maneuvered by a pilot
Kicking a ball. Driving a car, any stationary object.
2nd: [Pushing a box] the more force you put into moving the box the faster the box will move.
Ball rolling down a hill, riding a bike, batting a ball
3rd: [Jumping] your feet push against the ground
Moving car, running into a wall, paddling

How does the observed pitch of the buzzer change as it moves towards the observer?.

Answers

The observed frequency increases and ear hears a higher pitch.

The Doppler Effect is the change in wave frequency caused by the relative motion of a wave source and its observer. Christian Johann Doppler discovered it and described it as the process of increasing or decreasing starlight based on the relative movement of the star.

The Doppler effect, also known as the Doppler shift, is a phenomenon that occurs when the source of waves moves in relation to an observer. A common physical demonstration of the Doppler Effect is an ambulance crossing you with its siren blaring. The Doppler effect is important in astronomy because it allows us to calculate the velocity of light-emitting objects in space, such as stars or galaxies.

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could not find angular material core theme. most material components may not work as expected

Answers

When you see the error message "could not find angular material core theme. most material components may not work as expected," it means that the Angular Material theme is missing, and the application is having difficulty displaying Material components.

How to resolve the issue?

Here are some steps to resolve this issue:

1. You should first ensure that Angular Material has been installed in your application. You may use the following command to install Angular Material:ng add ("at" symbol)angular/material

2. Then, import the necessary styles in the styles.scss file to include the Angular Material theme.

Once you've completed these steps, restart your server and see if the error has been resolved. The Material Design components should now display correctly.

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Help: The diagram below illustrates a light ray bouncing off a surface. Fill in the boxes with the correct terms.

Help: The diagram below illustrates a light ray bouncing off a surface. Fill in the boxes with the correct

Answers

The correct terms that fills the box are;

(i) The incident ray

(ii) The normal

(iii) The reflected ray

(iv) The angle of incident

(v) The reflected angle

What is the terms of the ray diagram?

The terms of the ray diagram is illustrated as follows;

(i) This arrow indicates the incident ray, which is known as the incoming ray.

(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.

(iii) This arrow indicates the reflected ray; the out going arrow.

(iv) This the angle of incident or incident angle.

(v) This is the reflected angle or angle of reflection.

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