Draw two cyclic constitutional isomers of cis-1-chloro-2-methylcyclobutane with the same size ring.

Answers

Answer 1

Cyclic constitutional isomers refer to isomers that differ in the arrangement of atoms in a cyclic molecule. In cis-1-chloro-2-methylcyclobutane, the chlorine atom and the methyl group are attached to the same carbon atom of the cyclobutane ring. The two cyclic constitutional isomers can be obtained by interchanging the positions of the chlorine and the methyl group.


Both isomers have the same ring size of 4 carbons. However, the positions of the chlorine atom and the methyl group in the ring differ between the two isomers. The name of each isomer reflects the location of the substituents on the ring.

In isomer A, the methyl group is attached to the first carbon atom of the ring and the chlorine atom is attached to the second carbon atom. In isomer B, the positions of the two substituents are reversed. Therefore, these two isomers are constitutional isomers, meaning that they have the same molecular formula but different connectivity of atoms.

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Related Questions

.Pb2+
Write electron configurations for the following ions.
Part A:
Ru3+
Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.
Part B
As3−
Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.
Part C
Y3+
Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.
Part D
Pd2+
Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2

Answers

Part A: Ru3+ The electron configuration for Ru is [Kr]5s^24d^6. To form Ru3+, three electrons are removed. Therefore, the electron configuration for Ru3+ is [Kr]4d^5.

Part B: As3-

The electron configuration for As is [Ar]4s^23d^104p^3. To form As3-, three electrons are gained. Therefore, the electron configuration for As3- is [Ar]4s^23d^104p^6.

Part C: Y3+

The electron configuration for Y is [Kr]5s^24d^15p^1. To form Y3+, three electrons are removed. Therefore, the electron configuration for Y3+ is [Kr]4d^0.

Part D: Pd2+

The electron configuration for Pd is [Kr]5s^04d^10. To form Pd2+, two electrons are removed. Therefore, the electron configuration for Pd2+ is [Kr]4d^8.

Part A: Ru3+

The electron configuration for Ru is [Kr]5s^24d^6. To form Ru3+, three electrons are removed. This means that the 5s orbital is emptied and one electron is removed from the 4d orbital. Therefore, the electron configuration for Ru3+ is [Kr]4d^5. This configuration indicates that there are 5 electrons in the 4d orbital.

Part B: As3-

The electron configuration for As is [Ar]4s^23d^104p^3. To form As3-, three electrons are gained, filling up the 4p orbital. Therefore, the electron configuration for As3- is [Ar]4s^23d^104p^6. This configuration indicates that there are 6 electrons in the 4p orbital.

Part C: Y3+

The electron configuration for Y is [Kr]5s^24d^15p^1. To form Y3+, three electrons are removed. This means that the 5s and 4d orbitals are emptied. Therefore, the electron configuration for Y3+ is [Kr]4d^0. This configuration indicates that there are no electrons in the 4d orbital.

Part D: Pd2+

The electron configuration for Pd is [Kr]5s^04d^10. To form Pd2+, two electrons are removed, leaving the 5s and 4d orbitals empty. Therefore, the electron configuration for Pd2+ is [Kr]4d^8. This configuration indicates that there are 8 electrons in the 4d orbital.

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this is a easy question.what does inertia mean?

Answers

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

1. A) Calculate DO of water at 25 0 C, P 0 = 1.01x10 5 Pa; given: water vapor pressure (25 0 C) is 3.2x10 3 Pa and Henry constant of oxygen in water is 1.3x10 -8 mol/l.Pa b) How's DO content changed as increase or decrease water temperature? Explain.

Answers

Answer:

cfvgbhnjmk,

Explanation:

define isotope
hello​

Answers

Answer:

Isotope is one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behaviour but with different atomic masses and physical properties.

Hello Sis!!!!!!

Answer:

Isotopes are atoms of the same element that have the same atomic number but different in mass number.

What is the total number of electrons being shared in the single bonds between Hydrogen and Oxygen atoms in the compound of H2O?

Answers

The total number of electrons being shared in the single bonds between hydrogen and oxygen atoms in H₂O is 2 pairs or 4 electrons.

In the compound H₂O, which represents a molecule of water, there are two single bonds between the hydrogen (H) and oxygen (O) atoms. Each single bond consists of a pair of electrons being shared between the bonded atoms.

Since there are two single bonds in H₂O, there are a total of two pairs of electrons being shared. Therefore, the total number of electrons being shared in the single bonds between hydrogen and oxygen atoms in H₂O is 2 pairs or 4 electrons.

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The London (dispersion) forces are weakest for which of the following gases under the same conditions of temperature and pressure: F2, CH4, CF4, CH2F

Answers

The strength of London dispersion forces is proportional to the polarizability of the molecule, which in turn depends on its size and shape. Larger and more complex molecules tend to have greater polarizability and therefore stronger London dispersion forces.

Out of the given gases, F₂ is the smallest and least complex molecule, and therefore it has the weakest London dispersion forces. The other three gases - CH₄, CF₄, and CH₂F - are all larger and more complex, and thus have stronger London dispersion forces than F₂.

Therefore, F₂ has the weakest London dispersion forces under the same conditions of temperature and pressure compared to CH₄, CF₄, and CH₂F.

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Almost all of Earth's atmosphere is created through the process of photosynthesis.

True
False

Answers

Answer:

ture

Explanation:

trees, plants is what keeps us alive

HELP PLEASE THIS IS CONFUSING

HELP PLEASE THIS IS CONFUSING

Answers

Number of moles = 8.3 x 10⁻¹³

Further explanation

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³  particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's =  6.02.10²³

5 x 10¹¹ atoms of Silver :

\(\tt mol=\dfrac{5\times 10^{11}}{6.02\times 10^{23}}=8.3\times 10^{-13}\)

What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of
light in a vacuum is 3.00 x 108 m/s, and Planck's constant is 6.626 x 10-34
Jos.)
A. 688 nm
B. 1450 nm
C. 764 nm
D. 1310 nm

Answers

Let's see

\(\\ \rm\rightarrowtail E=hv\)

\(\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}\)

lambda is wavelengthh is Planck constantc is velocity of sound in airE in energy

\(\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}\)

\(\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}\)

\(\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m\)

\(\\ \rm\rightarrowtail \lambda=68.8\mu m\)

The wavelength of light with 2.89 x 10⁻¹⁹ J of energy is approximately 1450 nanometers.

Option (B) is correct.

The wavelength of light can be calculated using the formula:

λ = h / (E * c)

Where λ represents wavelength, h is Planck's constant (6.626 x 10⁻³⁴ Js), E is the energy (2.89 x 10⁻¹⁹ J), and c is the speed of light in a vacuum (3.00 x 10⁸ m/s).

Now, substitute the given values into the equation:

λ = 6.626 x 10⁻³⁴ Js / (2.89 x 10⁻¹⁹ J * 3.00 x 10⁸ m/s)

Calculate the denominator first: 2.89 x 10⁻¹⁹ J * 3.00 x 10⁸ m/s ≈ 8.67 x 10⁻¹¹ Js

Now, calculate the wavelength: λ ≈ 6.626 x 10⁻³⁴ Js / 8.67 x 10⁻¹¹ Js ≈ 7.65 x 10⁻²⁴ m

Convert the result from meters to nanometers (1 m = 10⁹ nm): 7.65 x 10⁻²⁴ m ≈ 7.65 x 10 ⁽⁻²⁴⁺⁹⁾ nm ≈ 7.65 x 10⁻¹⁵ nm ≈ 1450 nm.

Therefore, the wavelength of light with 2.89 x 10⁻¹⁹ J of energy is approximately 1450 nanometers, and the correct answer is B.

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¿Cómo pueden los padres pasar a sus
hijos rasgos como el color de ojos?

Answers

Answer:

Los padres transmiten rasgos o características, como el color de ojos y el tipo de sangre, a sus hijos a través de sus genes. Algunas condiciones de salud y enfermedades también pueden transmitirse genéticamente. A veces, en

An inflated balloon is left outside overnight. initially it has a volume of 1.84 L when the temperature is 293.4 K and the pressure. what temperature will the balloon have a volume of 1540mL. If the pressure falls to 14.41 psi?

Answers

Answer:

ffff

Explanation:

How are the four kinds of DNA nucleotides different from each other?

Answers

Answer:

The sugar in DNA is deoxyribose. ... Nucleotides in DNA contain four different nitrogenous bases: Thymine, Cytosine, Adenine, or Guanine. There are two groups of bases: Pyrimidines: Cytosine and Thymine each have a single six-member ring.

Adenine, Cytosine, Thymine, and Guanine are the four nucleotides that make up DNA. The four nucleotides have different base structures, but they are all composed of a nitrogenous base, a deoxyribose sugar, and a phosphate group.

What are nucleotides ?

Nucleotides are organic compounds made up of a phosphate and a nucleoside. They function as monomeric units of the deoxyribonucleic acid and ribonucleic acid polymers, which are both crucial macromolecules for all kinds of life on Earth.

Adenine, Cytosine, Thymine, and Guanine are the four nucleotides that make up DNA. The four nucleotides have different base structures, but they are all composed of a nitrogenous base, a deoxyribose sugar, and a phosphate group.

The quantity of phosphate residues that a nucleotide has determined its name. Adenosine triphosphate, for instance, is the name of a nucleotide that consists of an adenine base and three phosphate residues (ATP). Adenosine diphosphate would be the nucleotide if it has two phosphates (ADP).

Thus, Adenine, Cytosine, Thymine, and Guanine are the four nucleotides that make up DNA.

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a solution of toluene (c₇h₈) in 301 g of cyclohexane (c₆h₁₂) has a boiling point of 90.30 °c. what quantity in moles of toluene are in the solution? (for cyclohexane kb

Answers

There are 0.96 moles of toluene are in the solution of toluene (C₇H₈) in 301 g of cyclohexane (C₆H₁₂) having a boiling point of 90.30°C.

Given data -

Boiling point of cyclohexane = 90.30°C

Mass of cyclohexane = 301 g

Kb of cyclohexane = 2.92°C/m

Tb of cyclohexane = 80.90°C

Using the equation,

           m = ∆Tb

                   Kb

where,

m is molality of the solution,

Tb is the change in boiling point of cyclohexane -

          90.30 ° C - 80.90 °C = 9.40 °C

Kb is the boiling point elevation constant of cyclohexane, 2.92 °C/m

          Molality (m) =  9.40 = 3.22 mol/kg

                                   2.92

Number of moles of toluene = molality x mass of cyclohexane (in kg)

                                                = 3.22 x 301  

                                                               1000

Number of moles of toluene = 0.96 mol

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help me i waisted 60 points but bots keep answering someone else answer
it says its answered but its a bot i swear

help me i waisted 60 points but bots keep answering someone else answerit says its answered but its a

Answers

Answer:

mid-ocean ridge.

Explanation:

Metals have special bonds, between atoms. The valence electrons are mobile and are shared by all metal atoms present.
Metals exhibit ______ due to the mobility of valence electrons.

a)brittleness
b)high conductivity
c)low melting point
d)high solubility in water

Answers

Answer:

High conductivity

Explanation:

Metals exhibit high conductivity due to the mobility of valence electrons.

16
How do you solve this

16How do you solve this

Answers

46.07 g/mol hope that helps :) brainliest would be nice

Why does science need both applied and pure research?

Answers

Answer:

universal in nature while applied research is limited in nature.

Explanation:

Question 5 (8 marks) Differentiate the following set of terms in relation to evaluation of the measurement tools. Provide relevant examples. ANSWER: Validity, Reliability, and Practicality

Answers

In the evaluation of the measurement tools, the following terms must be differentiated: validity, reliability, and practicality.

Validity refers to how accurately a tool measures what it is supposed to measure. A measurement tool is considered to be valid if it measures what it is supposed to measure. Validity can be classified into three types: content, criterion, and construct. Content validity refers to whether the measurement tool captures all aspects of the phenomenon being measured. Criterion validity refers to whether the measurement tool correlates with a known standard of measurement. Construct validity refers to whether the measurement tool measures the theoretical concept it claims to measure. Reliability refers to the consistency of a measurement tool's results. A measurement tool is reliable if it consistently measures what it is supposed to measure. Reliability can be classified into three types: test-retest, inter-rater, and internal consistency.

Test-retest reliability refers to whether the measurement tool produces consistent results when given to the same individuals at different times. Inter-rater reliability refers to whether the measurement tool produces consistent results when given to different raters. Internal consistency refers to whether the measurement tool produces consistent results across different parts of the same test. Practicality refers to how easy a measurement tool is to administer and score. A measurement tool is considered practical if it is easy to administer and score. For example, a 100-item questionnaire may be impractical to use in a clinical setting where time is limited. In conclusion, validity, reliability, and practicality are important factors to consider when evaluating measurement tools.

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Twenty students were surveyed to find out how
many hours of TV they watch during a school
week. The results are shown to the right Answer
the following questions and round your answers to
the nearest half hour
The range of the data is
hours
DONE

Twenty students were surveyed to find out howmany hours of TV they watch during a schoolweek. The results

Answers

Answer:

this is good question I am thankful to you

Answer:

The range of the data is 11 hours

Explanation:

edge 2022, trust

Write the configuration of a magnesium atom? Will the atom lose or gain electrons? Explain using the idea of stability and energy.

Answers

Answer:

\(1s^{2} 2s^{2} 2p^{6} 3s^{2}\)

Magnesium will lose 2 electrons.

Explanation:

Looking at a periodic table, magnesium is in the third period and the second group. It would help to look up where atomic orbitals are on the periodic table, but basically, s orbitals are filled in the first two groups. Since magnesium is in the second group, it will just have filled a 3s orbital with two electrons.

Elements in groups 1A, 2A, and 3A especially like to lose electrons to gain stability. Elements want to have a filled valence (outer) orbital with 8 electrons (except for hydrogen and helium) like noble gases. As such, they will lose or gain electrons in the easiest way possible to get a filled valence orbital. Magnesium wants to have the electron configuration of the nearest noble gas, in this case neon, so it will lose 2 electrons to achieve this stability. It takes much less energy to lose 2 electrons than gain 6 to fill its valence orbital, so magnesium will go for the former.

The electronic configuration of magnesium is 2,8,2. In this example the atom will lose two electrons forming a positive ion(metal)to become stable

What is the name of this ionic compound (Fr2SO4)

Answers

Answer:

3.5: Ionic Compounds- Formulas and Names

Last updatedAug 25, 2020

3.4: An Atomic-Level Perspective of Elements and Compounds

 

3.6: Molecular Compounds- Formulas and Names

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6.9: Binary Ionic Compounds and Their Properties

6.18: Ionic Compounds Containing Polyatomic Ions

Learning Objectives

Derive names for common types of inorganic compounds using a systematic approach

Nomenclature, a collection of rules for naming things, is important in science and in many other situations. This module describes an approach that is used to name simple ionic and molecular compounds, such as NaCl, CaCO3, and N2O4. The simplest of these are binary compounds, those containing only two elements, but we will also consider how to name ionic compounds containing polyatomic ions, and one specific, very important class of compounds known as acids (subsequent chapters in this text will focus on these compounds in great detail). We will limit our attention here to inorganic compounds, compounds that are composed principally of elements other than carbon, and will follow the nomenclature guidelines proposed by IUPAC. The rules for organic compounds, in which carbon is the principle element, will be treated in a later chapter on organic chemistry.

Ionic Compounds

To name an inorganic compound, we need to consider the answers to several questions. First, is the compound ionic or molecular? If the compound is ionic, does the metal form ions of only one type (fixed charge) or more than one type (variable charge)? Are the ions monatomic or polyatomic? If the compound is molecular, does it contain hydrogen? If so, does it also contain oxygen? From the answers we derive, we place the compound in an appropriate category and then name it accordingly.

Compounds Containing Only Monatomic Ions

The name of a binary compound containing monatomic ions consists of the name of the cation (the name of the metal) followed by the name of the anion (the name of the nonmetallic element with its ending replaced by the suffix –ide). Some examples are given in Table  3.5.2 .

Table  3.5.1 : Names of Some Ionic Compounds

NaCl, sodium chloride Na2O, sodium oxide

KBr, potassium bromide CdS, cadmium sulfide

CaI2, calcium iodide Mg3N2, magnesium nitride

CsF, cesium fluoride Ca3P2, calcium phosphide

LiCl, lithium chloride Al4C3, aluminum carbide

Compounds Containing Polyatomic Ions

Compounds containing polyatomic ions are named similarly to those containing only monatomic ions, except there is no need to change to an –ide ending, since the suffix is already present in the name of the anion. Examples are shown in Table  3.5.2 .

Table  3.5.2 : Names of Some Polyatomic Ionic Compounds

KC2H3O2, potassium acetate (NH4)Cl, ammonium chloride

NaHCO3, sodium bicarbonate CaSO4, calcium sulfate

Al2(CO3)3, aluminum carbonate Mg3(PO4)2, magnesium phosphate

Ionic Compounds in Your Cabinets

Ionic Compound Use

NaCl, sodium chloride ordinary table salt

KI, potassium iodide added to “iodized” salt for thyroid health

NaF, sodium fluoride ingredient in toothpaste

NaHCO3, sodium bicarbonate baking soda; used in cooking (and as antacid)

Na2CO3, sodium carbonate washing soda; used in cleaning agents

NaOCl, sodium hypochlorite active ingredient in household bleach

CaCO3 calcium carbonate ingredient in antacids

Mg(OH)2, magnesium hydroxide ingredient in antacids

Al(OH)3, aluminum hydroxide ingredient in antacids

NaOH, sodium hydroxide lye; used as drain cleaner

K3PO4, potassium phosphate food additive (many purposes)

MgSO4, magnesium sulfate added to purified water

Na2HPO4, sodium hydrogen phosphate anti-caking agent; used in powdered products

Na2SO3, sodium sulfite preservative

Table  3.5.3 : Names of Some Transition Metal Ionic Compounds

Transition Metal Ionic Compound Name

FeCl3 iron(III) chloride

Hg2O mercury(I) oxide

HgO mercury(II) oxide

Cu3(PO4)2 copper(II) phosphate

Naming Ionic Compounds

Name the following ionic compounds, which contain a metal that can have more than one ionic charge:

Fe2S3

CuSe

GaN

CrCl3

Ti2(SO4)3

Solution

The anions in these compounds have a fixed negative charge (S2−, Se2− , N3−, Cl−, and  SO2−4 ), and the compounds must be neutral. Because the total number of positive charges in each compound must equal the total number of negative charges, the positive ions must be Fe3+, Cu2+, Ga3+, Cr4+, and Ti3+. These charges are used in the names of the metal ions:

iron(III) sulfide

copper(II) selenide

gallium(III) nitride

chromium(III) chloride

titanium(III) sulfate

Exercise  3.5.1  

Write the formulas of the following ionic compounds:

(a) chromium(III) phosphide

(b) mercury(II) sulfide

(c) manganese(II) phosphate

(d) copper(I) oxide

(e) chromium(VI) fluoride

Answer

(a) CrP; (b) HgS; (c) Mn3(PO4)2; (d) Cu2O; (e) CrF6

Explanation:

The given compound is francium sulfate.

Explanation:

While naming ionic compounds :

First, write the name of cation Then after that name of the anion.

Given

The molecule formula of a compound\(Fr_2SO_4\):

To find:

The name of the given compound formula

Solution:

Cation in formula = \(Fr^+\) = Francium cation

Anion in the formula= \(SO_4^{-2}\) = Sulfate anion

So, the name of the given compound is francium sulfate.

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With the above balanced equation, make at least four mole ratios (one is done for you):
6 KOH
2 K3PO4

Answers

The four mole ratios are: 6 KOH / 2 K₃PO₄, 2 KOH / 1 Co₃(PO₄)₂,

1 K₃PO₄ / 1 Co₃(PO₄)₂, 1 Co(OH)₂ / 2 KOH.

What do you understand by mole ratio?

Mole ratio refers to the ratio between the number of moles of two substances in a chemical reaction.

The given chemical equation is:

2 KOH + Co₃(PO₄)₂ → K₃PO₄ + Co(OH)₂

And the first mole ratio given is:

6 KOH / 2 K₃PO₄

To find the other mole ratios, we need to first balance the chemical equation. It is already balanced, so we can proceed to find the other mole ratios:

(2) 2 KOH / 1 Co₃(PO₄)₂

This ratio indicates that two moles of potassium hydroxide react with one mole of cobalt(II) phosphate.

(3) 1 K₃PO₄ / 1 Co₃(PO₄)₂

This ratio indicates that one mole of potassium phosphate is produced for every mole of cobalt(II) phosphate that reacts.

(4) 1 Co(OH)₂ / 2 KOH

This ratio indicates that one mole of cobalt(II) hydroxide is produced for every two moles of potassium hydroxide that react.

Therefore, the four mole ratios are:

(1) 6 KOH / 2 K₃PO₄

(2) 2 KOH / 1 Co₃(PO₄)₂

(3) 1 K₃PO4 / 1 Co₃(PO₄)₂

(4) 1 Co(OH)₂ / 2 KOH

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Correct question is:

KOH + Co₃(PO₄)₂ →

With the above balanced equation, make atleast four mole ratios ( one is done for you ):

\(\frac{6KOH}{2K3PO4}\)    -      -        -

A student was given a 2.850-g sample of a mixture of potassium nitrate and potassium bromide and was asked to find the percentage of each compound in the mixture. She dissolved the sample and added a solution that contained an excess of silver nitrate, AgNO3. The silver ion precipitated all of the bromide ion in the mixture as AgBr. It was filtered, dried, and weighed. Its mass was 1.740 g. What was the percentage of each compound in the mixture

Answers

Answer:

See explanation

Explanation:

The reaction occurs as follows;

KBr(aq) + AgNO3(aq) ----> AgBr(s) + KNO3(aq)

Number of moles of AgBr formed = mass /molar mass =1.740 g/187.77 g/mol = 0.0093 moles

From the reaction equation;

1 mole of KBr yields 1 mole of AgBr

Hence the number of moles of KBr reacted = 0.0093 moles

Mass of KBr present = 0.0093 moles × 119g/mol = 1.11 g

Mass of KNO3 = 2.850 g - 1.11 g = 1.74 g

Percentage of KBr = 1.11 g/2.850 g × 100 = 38.9%

Percentage of KNO3 = 1.74 g/2.850 g × 100 = 61.1%

A scientist has a 4.0 M solution of HCI and his new experiment requires 200.0 mL of 2.0 M HCI. How much HCI will he need?

400 mL

100 mL

420 mL

Answers

The HCL needed by the scientist for an experiment that requires 200.0 mL of 2.0 M HCI is 100mL.

The information in the question is:

Concentration of hydrochloric acid (HCI) = 4.0 M

Volume of hydrochloric acid (HCI) required for the experiment = 200.0 mL

Concentration of hydrochloric acid (HCI) required for the experiment = 2.0 M

We can use the formula of Molarity to find out the amount of hydrochloric acid (HCI) required:

M₁V₁ = M₂V₂

Where, M₁ = Molarity of the solution

V₁ = Volume of the solution

M₂ = Molarity of the required solution

V₂ = Volume of the required solution

We have, M₁ = 4.0 MV₁ = ?M₂ = 2.0 MV₂ = 200.0 mL

Putting the values in the formula:

M₁V₁ = M₂V₂⇒ V₁ = M₂V₂/M₁⇒ V₁ = (2.0 mol/L × 200.0 mL) / 4.0 mol/L⇒ V₁ = 100.0 mL

Therefore, the scientist will need 100 mL of hydrochloric acid (HCI) for the experiment. Hence, the correct option is B. 100 mL.

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use of chemical substance in our daily life their advantages and disadvantages​

Answers

Answer:

Explanation:

By observing chemical reactions, we are able to understand and explain how the natural world works. Chemical reactions turn food into fuel for your body, make fireworks explode, cause food to change when it is cooked, make soap remove grime, and much more.

Selective serotonin reuptake inhibitors and tricyclic antidepressants (tcas) both function by which mechanism?

Answers

Selective serotonin reuptake inhibitors (SSRIs) and TCAs both increase the levels of neurotransmitters in the brain to improve mood and alleviate symptoms of depression, but they differ in their selectivity and side effect profiles.

Selective serotonin reuptake inhibitors (SSRIs) and tricyclic antidepressants (TCAs) both function by affecting the levels of certain neurotransmitters in the brain to alleviate symptoms of depression.

SSRIs, such as fluoxetine and sertraline, work by selectively inhibiting the reuptake of serotonin, a neurotransmitter involved in mood regulation. By blocking the reuptake process, SSRIs increase the concentration of serotonin in the synaptic cleft, enhancing its transmission and improving mood.

On the other hand, TCAs, like amitriptyline and imipramine, inhibit the reuptake of not only serotonin but also other neurotransmitters like norepinephrine. By blocking the reuptake of these neurotransmitters, TCAs increase their availability in the synaptic cleft, which can help regulate mood and alleviate depressive symptoms.

While both SSRIs and TCAs have similar mechanisms of action in terms of inhibiting the reuptake of neurotransmitters, they differ in their selectivity and side effect profiles. SSRIs are generally preferred due to their relatively fewer side effects and better tolerability.

In summary, SSRIs and TCAs both increase the levels of neurotransmitters in the brain to improve mood and alleviate symptoms of depression, but they differ in their selectivity and side effect profiles.

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What volume of o2 is produced when 28.5 g of hydrogen peroxide decomposes to form water and oxygen at 150 degrees c and 2.0 atm?

Answers

Taking into account the reaction stoichiometry, the volume of O₂ is 7.28406 L when 28.5 g of hydrogen peroxide decomposes to form water and oxygen at 150 degrees c and 2.0 atm.

Reaction stoichiometry

The balanced reaction is:

2 H₂O₂  → 2 H₂O + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂O₂: 2 molesH₂O: 2 molesO₂: 1 mole

The molar mass of the compounds is:

H₂O₂: 34 g/moleH₂O: 18 g/moleO₂: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂O₂: 2 mole× 34 g/mole= 68 gramsH₂O: 2 moles× 18 g/mole= 36 gramsO₂: 1 mole× 32 g/mole= 32 grams

Mass of O₂ formed

The following rule of three can be applied: if by reaction stoichiometry 68 grams of H₂O₂ form 1 mole of O₂, 28.5 grams of H₂O₂ form how many moles of O₂?

moles of O₂= (28.5 grams of H₂O₂×1 mole of O₂)÷68 grams of H₂O₂

moles of O₂= 0.42 grams

Then, 0.42 moles of O₂ are formed.

Definition of ideal gas law

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

Where:

P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas.

Volume of O₂

In this case, you know:

P= 2 atmV = ?n= 0.42 molesR= 0.082 (atmL)÷(molK)T= 150 C= 423 K

Replacing in the definition of the ideal gas law:

2 atm×V = 0.42 moles×0.082 (atmL)÷(molK)× 423 K

Solving:

V = (0.42 moles×0.082 (atmL)÷(molK)× 423 K)÷ 2 atm

V= 7.28406 L

Finally, the volume of O₂ is 7.28406 L.

Learn more about the reaction stoichiometry:

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Name the following compound:
CH3-CH2-CH2-CH2-CH3
CH3 CH3

Answers

Answer:

Pentane

Explanation:

since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it \(C_{5} H_{12}\)

Difference between modern periodic table and medeelves periodic table​

Answers

Answer:

The main difference between Mendeleev and Modern Periodic Table is that Mendeleev’s periodic table orders the elements based on their atomic mass whereas Modern periodic table orders the elements based on their atomic number.

Explanation:

Which of the following best represents Boyle's Law?A) The pressure of a gas exerted on the walls of its container is directly proportional to the volume of the gas when the temperature of the gas remains constant.B) The volume of a gas inside a container is inversely proportional to the temperature of the gas when the pressure of the gas remains constant.C) The volume of a gas inside a container is directly proportional to the temperature of the gas when the pressure of the gas remains constant.D) The pressure of a gas exerted on the walls of its container is directly proportional to the temperature of the gas when the volume of the gas remains constant.E) The pressure of a gas exerted on the walls of its container is inversely proportional to the temperature of the gas when the volume of the gas remains constant.F)The pressure of a gas exerted on the walls of its container is inversely proportional to the volume of the gas when the temperature of the gas remains constant.

Answers

Answer

F) The pressure of a gas exerted on the walls of its container is inversely proportional to the volume of the gas when the temperature of the gas remains constant.

Explanation

Boyle's law states that the volume of a given mass of gas varies inversely with the pressure when the temperature is kept constant. An inverse relationship is described in this way. As one variable increases in value, the other variable decreases. He discovered that doubling the pressure of an enclosed sample of gas, while keeping its temperature constant, caused the volume of the gas to be reduced by half.

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