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Simplify the inequalities and match them with the graphs that represent them.
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3x > 15

2x > 12

x + 1 < 8

7x < 42

i need answers asp

Answer:

75 cars

Step-by-step explanation:

Convert the 8 hours into minutes, 480.

Divide by the 32 minutes, 15.

Multiply by the number of cars in 32 minutes, 5.

Answer is 75.

Answer:

75 cars.

Step-by-step explanation:

Let's use a ratio to solve:

minutes  :  cars

    32       :    5

   160      :   25

   320     :   50

   480     :   75

Since 480 minutes is 8 hours, and they get 75 cars washed in 480 minutes, then they have washed 75 cars in 8 hours.

As per the concept of quadratic equation, If the producers set the price of the video game at $75.69 per game, they can expect to supply 700 thousand units of the game based on the given demand equation.

To determine the price at which producers will supply 700 thousand video games, we need to set the demand equal to 700 thousand and solve for p.

So we have:

D(p) = 700

-0.253p² - 18.238p + 2246.356 = 700

-0.253p² - 18.238p + 1546.356 = 0

We can solve this quadratic equation using the quadratic formula:

p = (-b ± √(b² - 4ac)) / 2a

where a = -0.253, b = -18.238, and c = 1546.356

Plugging in the values, we get:

p = (-(-18.238) ± √((-18.238)² - 4(-0.253)(1546.356))) / 2(-0.253)

p = (18.238 ± √(18.238² + 1562.287)) / 0.506

p = (18.238 ± 39.626) / 0.506

p = 75.694 or -143.237

Since we are interested in the positive value, the price at which producers will supply 700 thousand video games is approximately $75.69 per game, rounded to the nearest cent.

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Complete Question:

The demand for a new video game is given to be D(p)=−0.253p² −18.238p+2246.356 thousand when the price is p dollars per game.

At what price will producers supply 700 thousand video games? round to the nearest cent (2 decimal places). $____________ per game

The extreme values of f(x, y) = xy occur at the points (2, 1) and (-2, -1) on the ellipse \(3x^{2} +2y^{2} =1\).

To find the extreme values of f(x, y) = xy on the ellipse \(3x^{2} +2y^{2} =1\), we can use the method of Lagrange multipliers.

Define the function g(x, y) = \(3x^{2} +2y^{2} -1\). We need to find points (x, y) where the gradient of f is proportional to the gradient of g:

∇f = λ∇g

The gradient of f is ∇f = (y, x), and the gradient of g is ∇g = (6x, 4y). Therefore, we have the following system of equations:

y = 6λx
x = 4λy

Substitute the second equation into the first:

y = 6λ(4λy)
y = \(24λ^{2y}\)

If y ≠ 0, then 1 = \(24λ^{2}\), and λ = ±1/2. Plugging this value into the second equation gives x = ±2. Thus, we have two potential extreme points: (2, 1) and (-2, -1).

Now consider the case when y = 0. The constraint equation becomes \(3x^{2} =1\), and x = ±1/√3. However, these points correspond to f(x, y) = 0, which is not an extreme value.

Therefore, the extreme values of f(x, y) = xy occur at the points (2, 1) and (-2, -1) on the ellipse \(3x^{2} +2y^{2} =1\).

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Answer:

The answer is D because when you plug in 0 for the x value, you get positive 2

A family of many generations but with only a few members of each generation is called a beanpole family pattern

A Beanpole family is a multi-generational family that is long and thin with few aunts, uncles and grandparents. This is a result of extended life expectancy and fewer children being born.

A generation refers to all of the people born and living at about the same time, regarded collectively.

Hence, A family of many generations but with only a few members of each generation is called a beanpole family pattern

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Answer:

1625

Step-by-step explanation:

\(35(5) + 1450 = 1625\)

35 x 5 = 175

175 + 1450 = 1625

Answer:

425 Miles

Explaination:

Please give the brainliest.

Sigma factors are necessary in the initiation phase of transcription. This phase requires a complex called RNA polymerase to locate the DNA's start site and begin the synthesis of a new RNA strand.

RNA polymerase recognizes promoters, which are DNA sequences adjacent to the transcription start sites that define the start site for RNA synthesis. Sigma factors are subunits of RNA polymerase that help it recognize promoters.Sigma factors regulate the initiation of RNA synthesis by RNA polymerase.

The sigma factor is a DNA-binding protein that recognizes specific promoter sequences and recruits RNA polymerase to the DNA molecule at the appropriate location. When the sigma factor binds to a promoter, RNA polymerase becomes anchored and initiates transcription. There are several sigma factors, each of which recognizes a different promoter sequence.

They are required for transcription of different sets of genes in response to environmental cues or other cellular stimuli.It is worth noting that the promoter sequence that sigma factors bind to can vary in terms of its similarity to the consensus sequence recognized by the sigma factor.

Sigma factors can also recognize alternative promoter sequences that bind to the RNA polymerase core enzyme with lower affinity than the consensus sequence. In general, a promoter with a perfect match to the consensus sequence is more effective than one with a non-perfect match in initiating transcription.

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The surface area of the triangular prism be 108 ft²

The volume of the triangular prism be 48 ft³.

Given, a triangular prism (base is a right triangle).

Triangle legs are 3 ft and 4 ft, hypotenuse is 5 ft, height of prism is 8 ft.

Now, the surface area of the triangular prism is,

Surface Area = 2×Area of the base triangle + Side rectangle 1 +Side rectangle 2 + Side rectangle 3

Surface Area = 2×(1/2×3×4) + 5×8 + 3×8 + 4×8

Surface Area = 12 + 40 + 24 + 32

Surface Area = 108 ft²

Now, Volume of the triangular prism be,

Volume = Area of the base triangle × height

Volume = 1/2×3×4×8

Volume = 48 ft³

Hence, the surface area of the triangular prism be 108 ft²

and the volume of the triangular prism be 48 ft³.

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If the average temperature at the South Pole is -49.62°C and the average temperature at the North Pole is -34.68°C, then the average temperature at the north pole is higher at the south pole by 14.94°C.

To find out how much higher the average temperature is at the North Pole compared to the South Pole, follow these steps:

Therefore, the average temperature at the North Pole is 14.94°C higher than at the South Pole.

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A constant function is a function that returns the same output every time it is called, regardless of the input. In this case, we want to create a constant function that returns an infinite list of all the natural numbers starting at 0.

Here's an example of how you could implement the nats function in Haskell:

makefile

Copy code

nats :: [Integer]

nats = [0..]

The [0..] syntax creates an infinite list that starts with 0 and continues indefinitely. Every time the nats function is called, it returns this same infinite list, so it's considered a constant function.

Another way to write the nats function is to use the iterate function, which generates a list by repeatedly applying a function to an initial value.

makefile

Copy code

nats :: [Integer]

nats = iterate (+1) 0

In this case, iterate (+1) 0 generates a list by repeatedly adding 1 to 0. The first element of the list is 0, the second element is 0 + 1 = 1, the third element is 1 + 1 = 2, and so on. This generates an infinite list of all the natural numbers starting at 0, which is exactly what we want.

In either case, you can take any number of elements from the nats list by using the take function. For example, take 5 nats would return the first 5 elements of the nats list, which would be [0, 1, 2, 3, 4].

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This code will print the value of the variable 'x', which is '1'. The 'printline()' function is used to display the value of a variable on the output screen.

Looking into the code we can see that:
1. The variable 'y' is declared and initialized with a value of '1'.
2. The variable 'x' is declared and initialized with a value of '1' as well.
3. The 'printline()' function is called and the variable 'x' is passed as an argument.
4. The 'printline()' function prints the value of 'x' on the output screen.

Since the value of 'x' is '1', the code will print '1' as the output.

In summary, the code will print the value of the variable 'x', which is '1'.

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Question

Which algebraic expression has like terms?

\(9n^3 - 2n + 3 - 4n^2\)

\(7n^3 + 3n - 3 - 6n^2\)

\(7n^3 + 4n - 3n^3 - 5n^2\)

\(6n^3 - 4n^4 + 6n - 5n^2\)

Answer:

A. \(9n^3 - 2n + 3 - 4n^2\)

B. \(7n^3 + 3n - 3 - 6n^2\)

Step-by-step explanation:

Given:

The above expressions

Required:

Expressions with like terms

Algebraic expressions are said to have like terms if and only if the have the equivalent exponents;

Like terms are dependent on the exponents and are independent on the sign of each terms.

Listing out the exponents of each options;

A. \(9n^3 - 2n + 3 - 4n^2\)

The exponents of n are 3 1 0 2

Rearrange: 0 1 2 3

B. \(7n^3 + 3n - 3 - 6n^2\)

The exponents of n are 3 1 0 2

Rearrange: 0 1 2 3

C. \(7n^3 + 4n - 3n^3 - 5n^2\)

The exponents of n are 3 1 3 2

Rearrange: 1 2 3 3

D. \(6n^3 - 4n^4 + 6n - 5n^2\)

The exponents of n are 3 4 1 2

Rearrange: 1 2 3 4

From the list of exponents above, only A and B are equal;

Hence, the following expressions have the like terms

A. \(9n^3 - 2n + 3 - 4n^2\) and B. \(7n^3 + 3n - 3 - 6n^2\)

Answer:

-2.

Step-by-step explanation:

4 x -2 = -8.

Answer:

1.8 meters

Step-by-step explanation:

It was easy for me

Let's prove the following equality [rv(q^(rp))]=r^(pv¬q) using a series of logical equivalences.

Step 1: \([rv(q^{(rp)})]=r^{(pv¬q)\) (given)

Step 2: \([r v (q ^{ (rp))}] = [r v (q ^{ p}) ^{ (q {^ ¬q}) v (r ^ {p}) ^{ (r ^{ ¬q})} ]\) (distributive law)

Step 3: \([r v (q ^ {p}) ^ {(q ^ {¬q) }v (r{ ^ p}) ^{ (r{ ^ ¬q}})] }= [r v (q ^{ p}) ^ {(F) v (r ^ {p}) ^ {(F)}}}]\)(negation law)

Step 4: \([r v (q ^{ p}) ^{ (F) }v (r ^{ p}) ^ {(F)}] = r v (q ^{ p}) ^{ (r ^ {p})}\) (identity law)

Step 5:\(r v (q ^{ p}) ^{ (r ^{ p{}) = r ^ {(q ^{ p v (r ^{ p})}}})\) (DeMorgan's law)

Step 6:\(r ^ {(q ^ {p }v (r ^{ p})) = r ^{ (p v q)}\) (commutative law)

Step 7: Therefore, \([rv(q^{(rp)})]=r^{(pv¬q)\)is proved.

Answer: By using a series of logical equivalences, \([rv(q^{(rp)})]=r^{(pv¬q)\)is proved.

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The given equation is proved using a series of logical equivalences as follows:

\([rv (q^ {(rp)})] = r^ {(pv¬q)} = ¬[(r V q) ^{ r}] ^ {¬(p V q)} = (r ^{ p})^{¬q\)

Given equation is:

[rv (q^ (rp))] = r^ (pv ¬q)

Let's prove this equation using a series of logical equivalences.

Step 1: Apply Commutative Law.

We know that\(P ^ Q\)≡ \(Q ^ P\) and P V Q ≡ Q V P.

\([rv (q^ {(rp)})] = [(rp) ^ {q}]Vr (1\)\)

So, the equation becomes \([(rp) ^ {q}] V r = r ^ {(pV ¬q)\)

Step 2: Apply Distributive Law.

We know that \(P ^ {(Q V R)\) ≡ \((P ^ Q)\)V\((P ^ R)\) and

P V \((Q ^ R)\)≡\((P V Q) ^ {(P V R)\).\([(rp) ^ q]\)V r = (\(r ^ p\)) V \((r ^ ¬q})\) (2)

Step 3: Apply De Morgan's Law.

We know that ¬\((P ^ Q)\) ≡ ¬P V ¬Q and

¬(P V Q) ≡ \(¬P ^ {¬Q\).(¬r V ¬p\() ^ ¬q\) V r = (\(r ^ p\)) V \((r ^ ¬q})\) (3)

Step 4: Apply Distributive Law on both sides.

\((¬r ^ {¬q} V r) V (¬p ^ {¬q} V r) = (r ^ {p}) V (r ^ {¬q}) (4)\)

Step 5: Apply De Morgan's Law on both sides.

¬(r V \(q ^ r\)) V (\(¬p ^ ¬q\\\) V r) = (\(r ^ p\)) V (\(r ^ ¬q\)) (5)

Step 6: Apply Distributive Law on the left-hand side and get the right-hand side in conjunction.

¬[\((r V q) ^ r\)] V (\(¬p ^ ¬q\)V r) = (\(r ^ p\)) ^ (\(r ^ ¬q\)) (6)

Step 7: Apply Commutative Law. (r V q\() ^ r\) ≡\(r ^ {(r V q)\) by Commutative Law.

\([¬r ^ {¬q V r}] V (¬p ^ {¬q V r}) = (r ^ p) ^ (r ^ ¬q})\) (7)

Step 8: Apply Distributive Law on the right-hand side.

\([¬r ^ {¬q V r}] V (¬p ^ {¬q V r}) = r ^{ (p ^ {¬q})\)(8)

Step 9: Apply De Morgan's Law on both sides. \(¬[(r V q) ^ {r}] ^ {¬(p V q)} = r ^ {(p ^ {¬q})\) (9)

Step 10: Apply Commutative Law.\(r ^ {(p ^ {¬q})} ≡ (r ^ {p}) ^{ ¬q\) by Commutative Law.

\(¬[(r V q) ^ {r}] ^ {¬(p V q)} = (r ^ {p}) ^ ¬q\)(10)

Thus, the given equation is proved using a series of logical equivalences as follows.

\([rv (q^ {(rp)})] = r^ {(pv¬q)} = ¬[(r V q) ^{ r}] ^ {¬(p V q)} = (r ^{ p})^{¬q\)

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Answer:

79.5

Step-by-step explanation:

35 correct = 35x2.5=87.5

32 wrong = 32x-0.25=-8

no. of pts = 87.5+(-8) = 79.5

The οrdered pair that is a sοlutiοn οf the equatiοn is (-5, 0).

A value οr grοup οf values that satisfy an equatiοn οr an inequality are referred tο as sοlutiοns in mathematics. Fοr instance, if we have the equatiοn 2x + 3 = 7, the answer is x = 2 since we get the cοrrect answer when we replace x with 2: 2(2) + 3 = 7.

Similar tο the last example, if we had an inequality like x + 4 > 10 then the sοlutiοn is x > 6, meaning any value οf x greater than 6 wοuld make the inequality true.

Tο find which οrdered pair is a sοlutiοn οf the equatiοn -5x - 3y = 25, we need tο substitute values οf x and y intο the equatiοn and see if it hοlds true.

Let's try the ordered pairs one by one:

a) (-5, 0)

Substituting x = -5 and y = 0 in the equation, we get:

-5(-5) - 3(0) = 25

25 = 25

This equation is true, so (-5, 0) is a solution of the equation.

b) (0, -8)

Substituting x = 0 and y = -8 in the equation, we get:

-5(0) - 3(-8) = 25

24 = 25

This equation is not true, so (0, -8) is not a solution of the equation.

Therefore, the ordered pair that is a solution of the equation is (-5, 0).

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Complete question:

Which ordered pair is a solution of this equation?

-5x - 3y = 25

a) (-5, 0)

b) (0, -8)

Answer:

n = 109/ 5 if the expression is 5n - 5.3 = 56

The Natural area will be 100 feet wide.

Algebra is a branch of mathematics that deals with equations and variables.

To start, there are some specific requirements for the dimensions of the nature area. The length should be twice the width, which means that if we use "w" to represent the width, the length would be "2w". Additionally, a retaining wall that is "h" feet high will be installed around the perimeter of the space.

The total length of the retaining wall needed is given, which means we can use this information to solve for "w". To do this, we need to use a bit of algebra.

First, let's write out the equation for the total length of the retaining wall:

2(2w) + 2w = 600

6w = 600

Dividing both sides by 6, we get:

w = 100

Therefore, the width of the nature area will be 100 feet.

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Answer:

The maximum size of car payment he can afford is;

Explanation:

Given that Oliver makes $54,000 per year.

His monthly income will be;

Also, it was stated that;

debt payments (other than mortgages) should be less than 8% of a consumer's monthly gross income.

8% of Oliver's monthly income will be;

So, Oliver cannot pay more than $360 of debt per month.

Removing the $100 student-loan payment every month.

We have;

Therefore, the maximum size of car payment he can afford is;

Answer:

B and D

Step-by-step explanation:

a is right because there are numbers that exist that are larger than five and smaller than 9

c is right because again, there are numbers that exist that are larger than -3 and smaller than 7.

b cannot be right because there are no numbers that can be larger than 9 that are also smaller than 5

d also cannot be right because there are no numbers that are less than -5 that are also more than -3.

Answer:

b and d

Step-by-step explanation:

those two can never be trusted

Answer:

4 and 5

Step-by-step explanation:

I can explain the general process for hypothesis testing using the chi-square (x2) test. The chi-square test is used to determine if there is a significant association between two categorical variables.

To determine the hypotheses, x2 statistic, and p-value, we need more specific information about the problem, including the variables A and B and their observed frequencies or proportions.

1. Hypotheses:

  - Null Hypothesis (H0): There is no association between the variables A and B.

  - Alternative Hypothesis (HA): There is an association between the variables A and B.

2. Calculate the x2 statistic:

  - The x2 statistic measures the difference between the observed and expected frequencies in each category. The formula for calculating the x2 statistic depends on the specific data and research question.

3. Calculate the p-value:

  - The p-value represents the probability of observing a result as extreme as the one obtained, assuming the null hypothesis is true. The calculation of the p-value also depends on the specific data and research question.

4. Determine significance at alpha 0.01:

  - If the p-value is less than the significance level (alpha), typically 0.01 or 0.05, we reject the null hypothesis and conclude that there is evidence of an association between the variables.

Therefore, remember, the process described here is general, and the specific steps and calculations will depend on the data and research question provided.

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Answer:

9

Step-by-step explanation:

The mean is equal to the sum of all numbers divided by the amount of numbers there are. If we represent the mean as m, sum as s, and number of numbers as n, we can write our equation as

m = s/n

Therefore, as we know the mean (7) and number of numbers (4), we can plug those in to find the sum.

7 = s / 4

Multiply both sides by 4

28 = s

We then have our sum. Because we know 3 numbers, and there are 4 total, there is one number left to figure out. Our current sum is 5+7+7 = 19, and we need a sum of 28. The difference between the sums, equivalent to the fourth number, is 28-19=9.

The growth rate of the bacterial colony after 3 hours is 32%, the population of a slowly growing bacterial colony after t hours is given by the function p(t) = 100 + 24t + 2t²

The growth rate of the colony is the rate of change of the population, which is given by the derivative of the function. The derivative of p(t) is p'(t) = 24 + 4t

The growth rate after 3 hours is p'(3) = 24 + 4 * 3 = 32. This means that the population of the colony is increasing by 32% after 3 hours.

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Answer:

4c+5

Step-by-step explanation:

add the c values which is 4. then add all other values which is 5

I believe its

4c+5

If I'm wrong srry

Donna's unit rate (which is equivalent to her speed, in this case) is:

U = 1/12 laps per minute.

The unit rate is defined as the quotient between two quantities (in this case will be distance over time).

We know that Donna runs 1/4 of a lap in 3 minutes, then the unit rate (it would be the distance that she runs in one minute) is given by the quotient:

U = (1/4 laps)/(3 minutes)

U = 1/(4*3) laps per minute

U = 1/12 laps per minute

This means that Donna does 1/12 of a lap in each minute that she runs.

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Answer:

78kg

Step-by-step explanation:

76×5= 380kg

380-72-74-75-81= 78kg