Don't know where to start.... please help!

Don't Know Where To Start.... Please Help!

Answers

Answer 1
Start by finding the volume of the rectangular prizm. That would be 17•13•8=1768. Next find the volume of the trapezoidal prizm. The trapezoid would be 1/2(6+17)•14=161cm squared but you need to find the volume. So do 161•13=2093

2093+1768=3861

Answer = 3861cm cubed

Related Questions

Hi Guys

Please answer this question. I will choose Brainliest.

Worth 10 points and it is a Maths question.

Cheers,
Jake

Hi GuysPlease answer this question. I will choose Brainliest.Worth 10 points and it is a Maths question.Cheers,Jake

Answers

Answer: x² + 3x - 10

Step-by-step explanation:

(x + 5)(x - 2)

Distribute:

x² - 2x + 5x - 10

Combine like terms:

x² + 3x - 10

Hope this helps!

Use the four functions shown.

1. f (x) = e Superscript (4 minus x). 2. f (X) StartAbsoluteValue 4 minus x EndAbsoluteValue. 3. f (x) = RootIndex 3 StartRoot 4 minus x EndRoot. 4. f (x) = (4 minus x) Superscript two-thirds.

Which function is differentiable for all values of x over the interval (–5, 5)?

I
II
III
IV

Answers

Answer:

Function I

Step-by-step explanation:

Differentiate each function.

Function I

\(f(x)=e^{4-x}\)

\(\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}\)

\(f'(x)=-e^{4-x}\)

The domain of f'(x) is all real numbers:  (-∞, ∞)

Therefore f(x) is differentiable for all values of x over the interval (-5, 5).

Function II

\(f(x)=|4-x|\)

\(\boxed{\begin{minipage}{6.5 cm}\underline{Differentiating an absolute value function}\\\\$|f(x)|'=\dfrac{f(x)}{|f(x)|}f'(x)$\\\end{minipage}}\)

\(f'(x)=-\dfrac{4-x}{|4-x|}\)

The domain of f'(x) is all real numbers except x = 4:  (-∞, 4) ∪ (4, ∞)

Therefore, f(x) is not differentiable for all values of x over the interval (-5, 5).

Function III

\(\begin{aligned}f(x)&=\sqrt[3]{4-x}\\&=(4-x)^{\frac{1}{3}}\end{aligned}\)

\(\boxed{\begin{minipage}{7 cm}\underline{Differentiating $[f(x)]^n$}\\\\If $y=[f(x)]^n$, then $\dfrac{\text{d}y}{\text{d}x}=n[f(x)]^{n-1} f'(x)$\\\end{minipage}}\)

Therefore:

\(\begin{aligned}f'(x)&=\dfrac{1}{3}(4-x)^{\frac{1}{3}-1} \cdot -1\\&=-\dfrac{1}{3}(4-x)^{-\frac{2}{3}}\\&=-\dfrac{1}{3(4-x)^{\frac{2}{3}}}\end{aligned}\)

The domain of f'(x) is all real numbers except x = 4:  (-∞, 4) ∪ (4, ∞)

Therefore, f(x) is not differentiable for all values of x over the interval (-5, 5).

Function 4

\(f(x)=(4-x)^{\frac{2}{3}}\)

\(\boxed{\begin{minipage}{7 cm}\underline{Differentiating $[f(x)]^n$}\\\\If $y=[f(x)]^n$, then $\dfrac{\text{d}y}{\text{d}x}=n[f(x)]^{n-1} f'(x)$\\\end{minipage}}\)

Therefore:

\(\begin{aligned}f'(x)&=\dfrac{2}{3}(4-x)^{\frac{2}{3}-1} \cdot -1\\&=-\dfrac{2}{3}(4-x)^{-\frac{1}{3}}\\&=-\dfrac{2}{3(4-x)^{\frac{1}{3}}}\end{aligned}\)

The domain of f'(x) is all real numbers except x = 4:  (-∞, 4) ∪ (4, ∞)

Therefore, f(x) is not differentiable for all values of x over the interval (-5, 5).

If you know the answer please put the answer and the explanation thank you.

If you know the answer please put the answer and the explanation thank you.

Answers

In the class, Lucy's score is 6.

How to work out Lucy's score?

In statistics, the median is the middle value in a sorted, ascending or descending list of numbers. Thus, it represents the midpoint of the data.

The median is often compared with other descriptive statistics such as the mean (average), mode, and standard deviation.

Since Lucy is one of the 29 students in the class and her score was the same as the median score for her class.

Thus, the median score will be 15th score (i.e. the midpoint of 29). Using the frequency in of each score from the figure, let's keep adding the frequency until we reach 15 and we will then check the corresponding score at the 15th position:

2 + 2 + 4 + 7 = 15

Thus, the the corresponding score at the 15th position is 6.

Therefore, the median score is 6 and consequently Lucy's score is 6.

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Ayudaaaaaa
Porfi
Gracias

AyudaaaaaaPorfi Gracias

Answers

The expression representing the perimeter of the polygon is given as follows:

7mn³/3 + 4m² + 3mn².

What is the perimeter of a polygon?

The perimeter of a polygon is given by the sum of all the lengths of the outer edges of the figure, that is, we must find the length of all the edges of the polygon, and then add these lengths to obtain the perimeter.

Hence the perimeter for the polygon in this problem is given as follows:

mn³(1/3 + 2) + m²(1 + 3) + mn²(1 + 2) = 7mn³/3 + 4m² + 3mn².

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Simplify. 3/4−4x+1/2x−1/2+1/2x Enter your answer in the box. Do not use decimals in your answer

Answers

Answer:

-3x+1/4

Step-by-step explanation:

hope this helps!

Answer:

-3x+1/4

Step-by-step explanation:

i got it right on k12

A quadratic equation, y = ax^2 - 6x + 10, has exactly one real root. Calculate the value of a.

Answers

Answer:

a = 0.9

Step-by-step explanation:

For the quadratic equation \(\boxed{ax^2 + bx + c = 0}\) to have exactly one real root, the value of its discriminant, \(\boxed{b^2 - 4ac}\), must be zero.

For the given equation:

\(y = ax^2 - 6x + 10\),

• a = a

• b = -6

• c = 10.

Substituting these values into the formula for discriminant, we get:

\((-6)^2 - 4(a)(10) = 0\)

⇒ \(36 - 40a = 0\)

⇒ \(36 = 40a\)

⇒ \(a = \frac{36}{40}\)

⇒ \(a = \bf 0.9\)

Therefore the value of a is 0.9 when the given quadratic has exactly one root.

A 4-ft-high and 7-ft-wide rectangular plate is submerged vertically in water so that the top is 1 ft below the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3).

Answers

Total depth of the bottom of the plate is 4 + 1 = 5

Force = limit(5,1) 62.5 *7* x * dx

= 437.5. Lim(5,1) x*dx

= 437.5(x^2/2)^5 , 1

= 437.5 x (5^2/2 - 1/2)

= 437.5 x 12

= 5,250 pounds

The hydrostatic force against one side of the plate will be 5250 pounds.

What is hydrostatic force?

The force exerted by the water of surface is known as hydrostatic force.

A 4-ft-high and 7-ft-wide rectangular plate is submerged vertically in water so that the top is 1 ft below the surface.

\(\rm Force = \int^5_1 62.5 *7* x * dx\\\\\\ Force = 437.5 \left [ \dfrac{x^2}{2} \right]^5_1\\\\\\Force = 218.75 \left [ x^2 \right]^5_1\\\\\)

Solve the equation further, we have

Force = 218.75 x (5² – 1²)

Force = 218.75 x 24

Force = 5,250 pounds

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Mano you new wom a) Divide 70,756 by 19. b) Subtract 940 from your answer to part a).​

Answers

The solution of the expression is,

a) 3,724

b) 2,784

We have to given that,

a) Divide 70,756 by 19.

b) Subtract 940 from your answer to part a).​

Now, We can simplify as,

a) Divide 70,756 by 19.

⇒ 70,756 ÷ 19

⇒ 3,724

And, Subtract 940 from your answer to part a).​ that is, 3724

⇒ 3724 - 940

⇒ 2,784

Therefore, The solution of the expression is,

a) 3,724

b) 2,784

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angle of is a right angle. the sides of are the diameters of semicircles as shown. the area of the semicircle on equals , and the arc of the semicircle on has length . what is the radius of the semicircle on ?

Answers

The radius of the semicircle having an arc of length equal to 8.5 \(\pi\) in a right-angle triangle ABC is equal to 7.5 cm.

Given:

Angle ABC of triangle ABC is a right angle. The sides of ABC are the diameters of semicircles.

The area of the semicircle on AB equals 8\(\pi\).

Area of a semicircle = \(\pi r^2/2\)

Therefore:

\(\pi r^2/2\) =  8\(\pi\)

\(r^2 = 16\)

\(r = 4\)

Next, the arc of the semicircle on AC has a length of 8.5\(\pi\).

Length of the arc of a semicircle = \(\pi r\)

\(\pi r\) = 8.5\(\pi\)

\(r = 8.5\)

Using Pythagoras theorem

\(8.5^{2} = 4^{2} + x^{2}\)

\(x^{2} = 8.5^2 - 4^2\\\)

\(x^{2} = 56.25\)

\(x = \sqrt{56.25}\)

\(x = 7.5\)

The radius of the semicircle of BC = 7.5 Units.

Refer to this complete question for this:

Angle ABC of triangle ABC is a Right angle. The sides of ABC are the diameters of semicircles as shown. The area of the semicircle on AB equals 8pi and the arc of the semicircle on AC has a length of 8.5pi. What is the radius of the semicircle of BC?

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angle of is a right angle. the sides of are the diameters of semicircles as shown. the area of the semicircle

find the sum of 10 and the difference between 8 and 3



can you plz answer this I am beginner my exam going to start can u all plz help to answer this​

Answers

Answer:

15

Step-by-step explanation:

10+(8-3)=15

................

help please I'm confused and don't know how to figure it out ​

help please I'm confused and don't know how to figure it out

Answers

Answer:

Vertical angles are congruent so x=145°

Answer:

x= 145° ( Corresponding angles)

please help if your good at geometry:(

please help if your good at geometry:(

Answers

Answer:

Y = theta = 32.68

Step-by-step explanation:

Formula

y^2 = x^2 + z^2  - 2*x*z * cos(theta)

Givens

y = 55

theta = ?

z = 50

x = 90

Solution

55^2 = 90^2 + 50^2 - 2*90*50 cos(theta)

3025 = 8100 + 2500 - 9000 cos(theta)      Combine the right

3025 = 10600 - 9000 Cos(theta)                Subtract 10600

3025 - 10600 = -9000 Cos(theta)

-7575 = - 9000 Cos(theta)                            Divide by - 9000

-7575/-9000 = cos(theta)

0.8417 = cos(theta)

cos-1(0.8417) = theta

theta = 32.68

Let A, B, and C be three events in a random experiment
with sample space S. Write expressions for each of the following sets in terms of the set operations "union," "intersection",
"complement," and "difference":
• (a) only A occurs: A − B − C
• (b) A and B occur but C does not occur: (A ∪ B) − C
• (c) exactly one of the events occurs: (A − B − C) ∪ (B − A −C) ∪ (C − A − B)
• (d) at least one of the events occurs: A ∪ B ∪ C
• (e) at most one of the events occurs: S − (A ∩ B) − (A ∩ C) −(A ∩ B)
• (f) exactly two of the events occur: (A ∩ B − C) ∪ (A ∩ C −B) ∪ (B ∩ C − A)
• (g) at least two of the events occur: (A∩B)∪(A∩C)∪(B∩C)
• (h) at most two of the events occur: S − (A ∩ B ∩ C)
• (i) all three events occur: A ∩ B ∩ C
• (j) none of the events occur: S − A − B − C

Answers

(a) only A occurs: A − B − C

(b) A and B occur but C does not occur: (A ∪ B) − C

(c) exactly one of the events occurs: (A − B − C) ∪ (B − A −C) ∪ (C − A − B)

(d) at least one of the events occurs: A ∪ B ∪ C

(e) at most one of the events occurs: S − (A ∩ B) − (A ∩ C) − (B ∩ C)

(f) exactly two of the events occur: (A ∩ B − C) ∪ (A ∩ C − B) ∪ (B ∩ C − A)

(g) at least two of the events occur: (A∩B)∪(A∩C)∪(B∩C)

(h) at most two of the events occur: S − (A ∩ B ∩ C)

(i) all three events occur: A ∩ B ∩ C

(j) none of the events occur: S − A − B − C

(a) If only event A occurs, then the event A is said to be the difference of the universal set (S) and the events B and C (S − B − C).

(b) If events A and B occur but event C does not occur, then the union of events A and B (A ∪ B) is the difference of the universal set (S) and the event C (S − C).

(c) If exactly one of the events occurs, then it can be represented as the union of the differences of the universal set (S) and the other two events for each of the three events (A − B − C) ∪ (B − A −C) ∪ (C − A − B).

(d) If at least one of the events occurs, then it can be represented as the union of all three events (A ∪ B ∪ C).

(e) If at most one of the events occurs, then it can be represented as the difference of the universal set (S) and the intersection of any two events (S − (A ∩ B) − (A ∩ C) − (B ∩ C)).

(f) If exactly two of the events occur, then it can be represented as the union of the intersections of two events and the difference of the third event (A ∩ B − C) ∪ (A ∩ C − B) ∪ (B ∩ C − A).

(g) If at least two of the events occur, then it can be represented as the union of the intersections of any two events (A∩B)∪(A∩C)∪(B∩C).

(h) If at most two of the events occur, then it can be represented as the difference of the universal set (S) and the intersection of all three events (S − (A ∩ B ∩ C)).

(i) If all three events occur, then it can be represented as the intersection of all three events (A ∩ B ∩ C).

(j) If none of the events occur, then it can be represented as the difference of the universal set (S) and all three events (S − A − B − C).

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This is just a question I had.
If Denny (random name) left to another country and he left the Tuesday of this week (June 20) and he left for a month, what day would he be back on? I though July 18 but I’m not sure. Pls help?

Answers

Answer:

Step-by-step explanation:

Well, since the length of a month can vary in the number of days, this answer can also vary.

For example, February is only 28 days long, while December is 31 days long.

That being said, the average length of all 12 months is 30.436875 days, so if Denny left to another country on June 20th, he would most likely be back   July 19th of July 20th.

I hope this helps!

Find the slope of the line that passes through (10, 8) and (1, 9)?

Answers

Answer:

The answer is

\( - \frac{1}{9} \)

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

\(m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\ \)

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(10, 8) and (1, 9)

The slope is

\(m = \frac{9 - 8}{1 - 10} = \frac{1}{ - 9} \\ = - \frac{1}{9} \)

We have the final answer as

\( - \frac{1}{9} \\ \)

Hope this helps you

We can use the given points to solve.

Slope formula: y2-y1/x2-x1

9-8/1-10

1/-9

-1/9

Best of Luck!

Jose needs 302 programs for the school play on Thursday. How many boxes of programs will he need, given that each box contains 44 programs?

Answers

i tried to solve it and i got this
Jose needs 302 programs for the school play on Thursday. How many boxes of programs will he need, given

A rectangle with a length of 5cm and width of 2cm is cut diagonally. What is the area of one of the triangles formed?

PLEASE LEAVE STEPS!

Answers

Answer:

5cm^2

Step-by-step explanation:

l=5 w=2

Area= 5×2

=10cm^2

Area of triangle= 10/2

=5cm^2

We have 2 squares. One square is shaded 2/12 and the other shaded square in the diagram is 2/15 shaded. How much of the total diagram is shaded?

A.0.148
B.0.148 repeated
C. 0.3
D.0.3 repeated

Answers

Answer: The answer to your question is C. Brainliest?

Step-by-step explanation:

For the first square, we can multiply both the numerator and denominator by 5 to get an equivalent fraction with a denominator of 60:

2/12 = (2 x 5) / (12 x 5) = 10/60

For the second square, we can multiply both the numerator and denominator by 4 to get an equivalent fraction with a denominator of 60:

2/15 = (2 x 4) / (15 x 4) = 8/60

Now, we can add the two fractions:

10/60 + 8/60 = 18/60

Simplifying this fraction by dividing both numerator and denominator by 6, we get:

18/60 = 3/10

Therefore, the total shaded area in the diagram is 3/10 or 0.3 in decimal form.

The answer is C. 0.3.

How many meters are in 214 cm

Answers

There are 100 cm in a m so there is 2.14 meters in 214 cm

John can change four tires on a car
in a half hour. How many tires can
he change in 6 hours? How many
cars is that? How long does it take
John to change one tire?

Answers

Answer:
In 6 hours John can change 48 car tires
That is 12 cars
It takes 7 minutes and 39 seconds to change a car tire

Explanation:
4x12=48
48/4=12
30/4=7.5
Take the 4 tires he changed and multiply it by two.

In one hour he can change 8 tires

8 tires times 6 hours is 48

He changes 48 tires in 6 hours.

Divide 48 by 4 because there are at least 4 tires on a car

That gives you 12

So he changed the tires of 12 cars in 6 hours.

To find the time of one tire you would take 30 min and divide it by 4. Because it takes 30 minutes to change 4

That gives you 7.5

So 7 minutes and 30 seconds to change one tire


How many can he change in 6 hours?
4x2=8 8x6=48 tires

How many cars is that?
48 divided by 4=12

How long for one tire?

30 divided by 4= 7.5 minutes

These points are linear.
Find the slope.
x0 |1 |2|3|4|5
y|0|2|4|6|8|10
slope = [?]

Answers

Answer:

Step-by-step explanation:

x₁ = 0   ; y₁=0  &

x₂ = 1    ; y₂=2

Slope =\(\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

         \(=\dfrac{2-0}{1-0}\\\\\\=\dfrac{2}{1}\\\\\\= 2\)

Slope = 2

-15>-11+w solve inequality for W

Answers

Answer:

Starting with:

-15 > -11 + w

Add 11 to both sides:

-15 + 11 > w

Simplifying:

-4 > w

Therefore, the solution for the inequality -15 > -11 + w, when solved for w, is:

w < -4

In one part of a rainforest 3/5 of the frogs are poisonous. what fraction of the frogs are not poisonous?

Answers

Then 1 - 3/5 = 2/5. This means that 2/5 of the frogs in that particular part of the rainforest are not poisonous. This fraction can also be expressed as 40/100 or 0.4 in decimal form.

In the given scenario, we know that 3/5 of the frogs in a particular part of the rainforest are poisonous. This means that the remaining fraction of the frogs are not poisonous.

To find this fraction, we need to subtract 3/5 from 1 (since the sum of the fractions of poisonous and non-poisonous frogs is equal to 1).

It's important to note that just because a frog is not poisonous, it doesn't mean it's safe to touch or handle them. It's always best to admire these beautiful creatures from a safe distance and leave them alone in their natural habitat.

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x-intercept of 3 and y-intercept of 8
How do you write a lunar equation given this information and how do you write the equation in slope form

Answers

Answer:

y = -8/3x + 8

Step-by-step explanation:

Step 1:  Identify which values we have and need to find in the slope-intercept form:

The general equation of the slope-intercept form of a line is given by:

y = mx + b, where

(x, y) is any point,m is the slope,and b is the y-intercept.

Since we're told that the y-intercept is 8, this is our b value in the slope-intercept form.

Step 2:  Find m, the slope of the line:

Since the x-intercept is 3, the entire coordinates of the x-intercept are (3, 0)

Thus, we can find m, the slope of the line by plugging in (3, 0) for (x, y) and 8 for b:

0 = m(3) + 8

0 = 3m + 8

-8 = 3m

-8/3 = m

Thus, the slope is -8/3.

Therefore, the the equation of the line in slope-intercept form whose x-intercept is 3 and whose y-intercept is 8 is y = -8/3x + 8.

Optional Step 3:  Check the validity of the answer:

We know that the entire coordinates of the x-intercept are (3, 0) and the entire coordinates of the y-intercept are (0, 8).

Thus, we can check that we've found the correct equation in slope-intercept form by plugging in (3, 0) and (0, 8) for (x, y), -8/3 for m, and 8 for b and seeing if we get the same answer on both sides of the equation when simplifying:

Plugging in (3, 0) for (x, y) along with -8/3 for m and 8 for b:

0 = -8/3(3) + 8

0 = -24/3 + 8

0 = -8 = 8

0 = 0

Plugging in (0, 8) for (x, y) along with -8/3 for m and 8 for b;

8 = -8/3(0) + 8

8 = 0 + 8

8 = 8

Thus, the equation we've found is correct as it contains the points (3, 0) and (0, 8), which are the x and y intercepts.

For safety reasons, the angle a ladder makes with the ground should be no greater than 67°. Find the length to the nearest foot of the shortest ladder that will safely reach a roof that is 23 feet high.

Answers

Using trigonometric function the length to the nearest foot of the shortest ladder that will safely reach a roof that is 23 feet high is calculated as 25 feet.

What are trigonometric functions?

Simply put, trigonometric functions—also called circular functions—are the functions of a triangle's angle. This means that these trigonometric functions provide the relationship between the angles and sides of a triangle. Sine, cosine, tangent, cotangent, secant, and cosecant are the fundamental trigonometric functions.

Given the angle a ladder makes with the ground should be no greater than 67°.

So the angle θ ≤ 67°.

Let us assume the angle to be equal to 67°

The height of the roof from the ground is 23 feet.

The ladder and wall form the right triangle where the ladder works as hypotenuse and the wall as perpendicular.

With the sine function, find the length of the ladder -

sin θ = perpendicular/hypotenuse

Let the length of ladder be x.

sin 67° = 23/x

x = 23/sin 67°

x = 23/0.920

x = 25 feet

Therefore, the length of the ladder is 25 feet.

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packaging idaho produce company ships potatoes to its distributors in bags whose weights are normally distributed witb. nean weight of 50 pounds and a standard deviation of .5 pounds. if a bag of potatoes is selected at random from a shipment, what is the probability that it weighs more than 51 pounds

Answers

The probability that it weighs more than 51 pounds exactly 53 pounds.

Given that, mean weight of 50 pounds and a standard deviation of 0.5 pounds.

We need to find the probability that it weighs more than 51 pounds,

P(X = 53) = 0

z = (51 - 50) / 0.5 = 2.00

P(X > 51) = P(z > 2.00) = 0.0228

z1 = (49 - 50) / 0.5 = -2.00

z2 = (51 - 50) / 0.5 = 2.00

P(49 < X < 51) = P(-2.00 < z < 2.00) = P(z < 2.00) - P(z < -2.00) = 0.9772 - 0.0228 = 0.9544

Hence, the probability that it weighs more than 51 pounds exactly 53 pounds.

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I need help plzzzzzz tysm​

I need help plzzzzzz tysm

Answers

If the question is asking to multiply by the variables, it would be 3(-2)+5(-1) which is equal to -6 - 5.

Help !! Will mark brainlest !!
A flowering plant stands 6.5 inches tall when its placed under a growing light. Its growth is 0.25 inches per day. Which of the following equations represents this situation?
A- y=0.25x+6.5
B- y=6.5x+0.25
C- y= -0.25x+6.5
D- y= - 6.5x+0.25

Answers

Answer: the answer would be a-y=0.25x+6.5

Which inequality represents the situation described below?
The distance, d, is less than 200 miles.
A. d ≥ 200
B. d > 200
C. d ≤ 200
D. d < 200

Answers

Hello!

The distance, d, is less than 200 miles.

B. d > 200

What is the answer to this combination lock

What is the answer to this combination lock

Answers

Answer: 375

Step-by-step explanation:

Ruling out each number:

6: In the first two rows, the 6's placement did not change but the clue did, meaning that it is talking about a different number. Otherwise, it would say it's in the right place twice or in the wrong place twice.

3 & 5: Since we know 6 is already ruled out, both 5 & 3 would have to be correct.

2 & 4 & 8: Is proven wrong in the 4th clue.

7: 7 would have to be in the middle since the second clue says it's in the wrong place. If it was 1, it would say it's in the right space.

1: Is proven wrong after 7 is proven true.

Figuring out placement:

5: For the first clue, it says that it's in the correct place meaning that 5 is the last digit.

3: For both of the times 3 appears, it is in the wrong spot, revealing that it's the first digit.

7: In the second clue, it could either be 1 or 7. However, since 3 took the first spot and 5 took the last spot, 7 would have to be in the middle since the clue says it's in the wrong place. If it was 1, it would say it's in the right space.

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