Does Anyone Need Answer To Question

How many electrons are in an atom of elemental sodium?

✘ A) equal to the number of neutrons

✔ ∅ B) equal to the number of protons

✘ C) equal to the number of protons and neutrons

Answer:

uhhhhh not sure i cant see it

Explanation:

Answer:

They are still the same particals just. packed together diffrently depending on what stae of matter it's in.

Explanation:

Answer:

The first thing we have to do is change and state all the units so that we can use our ideal gas law equation (\(PV = nRT\)).

650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.

\(650 \ mmHg \ * \ \frac{101kPa}{760 mmHg} = 86 \ kPa\)

P = 86kPa

T = 15°C + 273K = 288K

R (Gas constant) = 8.31 kj/mol  

Molar mass of Ammonia (\(NH_{3}\)) = (1 x 3) + (14) = 17g/mol

n (moles) = \(\frac{mass}{molar \ mass}\) \(= \frac{56.8}{17} =\) 3.34 mol

V = ?

Rearrange the equation to solve for Volume:

\(V = \frac{nRT}{P}\)

Substitute the values inside:

V = \(\frac{(3.34)(8.31)(288)}{(86)} = 93 L (rounded)\)

Therefore 93 L of volume is occupied by the ammonia gas.

Answer:

number of protons in a nucleus

Explanation:

number of protons in a nucleus.  The number of protons in the nucleus is, by definition, the atomic number.

Answer:

hope it helps...

Explanation:

The energy of an electron depends on its location with respect to the nucleus of an atom. The higher the energy of an electron in an atom, the farther is its most probable location from the nucleus.

Therefore, 111.6 g of lead(IV) phosphate are produced when 150.0 g of ammonium phosphate and 250 g of lead(IV) nitrate are available.

The balanced chemical equation for the reaction is:

(NH4)3PO4 + 3Pb(NO3)4 → Pb3(PO4)4 + 12NH4NO3

First, we need to calculate the limiting reagent to determine which reactant will be consumed completely and therefore will limit the amount of product formed.

The moles of ammonium phosphate available is:

n(NH4)3PO4 = m/M = 150.0 g / 149.09 g/mol = 1.005 mol

The moles of lead(IV) nitrate available is:

nPb(NO3)4 = m/M = 250 g / 783.32 g/mol = 0.319 mol

To determine the limiting reagent, we compare the mole ratio of ammonium phosphate to lead(IV) nitrate in the balanced equation. For every one mole of ammonium phosphate, three moles of lead(IV) nitrate are required. Therefore, the amount of lead(IV) nitrate required to react with 1.005 mol of ammonium phosphate is:

nPb(NO3)4 required = 1.005 mol / 3 mol Pb(NO3)4/mol NH4)3PO4 = 0.335 mol

Since we only have 0.319 mol of lead(IV) nitrate available, it is the limiting reagent.

The amount of lead(IV) phosphate produced can be calculated using the mole ratio from the balanced equation:

nPb3(PO4)4 = 0.319 mol Pb(NO3)4 × (1 mol Pb3(PO4)4/3 mol Pb(NO3)4) × (1032.72 g Pb3(PO4)4/mol) = 111.6 g

Therefore, 111.6 g of lead(IV) phosphate are produced when 150.0 g of ammonium phosphate and 250 g of lead(IV) nitrate are available.

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From the reaction Mg(OH)₂  is more effective.

What is antacid ?

Acids can be neutralized by antacids, which are very simply built salts and salt-like molecules. This neutralization processes result in processes including hydrolysis and precipitations of insoluble compounds, as well as a number of products (other salts, water, and possibly carbon dioxide).

What is hydrochloric acid ?

In its reaction with an organic base, hydrochloric acid (HCl, also known as muriatic acid) transforms into a salt known as hydrochloride. Hydrochloric acid has a variety of commercial uses.

NaHCO₃ (aq)+ HCl (aq)⇒ NaCl (aq) + H₂O (1)+ CO₂ (g)

N= m/M = 1.00g/ 84.01g/mol= 1.19*10^-2 mol NaHCO₃

1.19*10^-2mol NaHCO₃* 1 mol HCl / 1 mol NaHCO₃ 1.19*10^-2 mol HCl

Mg (OH)₂ (S) +2HCl (Aq)  ⇒ 2H₂O (1)+MgCl₂(Aq)

N=m/M = 1.008/58.33g/mol = 1.71*10^-2 mol Mg(OH)₂

1.71*10^-2mol Mg(OH)₂ *2 mol HCl / 1 mol Mg(OH)₂= 3.42*10^-2 mol HCl

Mg(OH)₂  is more effective.

Therefore, from the reaction Mg(OH)₂  is more effective.

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The answer is Homo sapiens. Homo sapiens is a genus of animals that are omnivorous. To be omnivorous means to be able to eat a plant-based AND animal-based diet. Ther are other kinds of omnivores, however, since the key term must start with H, this makes the above the right answer.

Bears, birds, dogs, raccoons, foxes, some insects, and even humans are examples of omnivores. Predators are creatures that hunt other animals, whereas prey are animals that are hunted.

As adults, frogs and toads are carnivores, devouring insects and occasionally small animals. They are herbivores as tadpoles, consuming algae and decomposing materials.

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The relative contribution of CO2 attributed to global warming is 60 % in the environment.

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Answer:

Maybe try to memorize it by the valence electrons. You can do this!!

The grams of aluminum oxide produced by multiplying the moles of aluminum oxide by its molar mass. The molar mass of aluminum oxide (Al2O3) is 101.96 g/mol. grams of aluminum oxide = moles of aluminum oxide * molar mass of aluminum oxide

To find the grams of aluminum oxide produced, we first need to calculate the moles of aluminum reacted.

Given that the molar mass of aluminum is 26.98 g/mol, we can calculate the moles of aluminum:

moles of aluminum = mass of aluminum / molar mass of aluminum
moles of aluminum = 46.0 g / 26.98 g/mol

Next, we can use the balanced chemical equation to determine the ratio between aluminum and aluminum oxide. According to the equation, 4 moles of aluminum produce 2 moles of aluminum oxide.

So, the moles of aluminum oxide produced can be calculated using the mole ratio:

moles of aluminum oxide = moles of aluminum * (2 moles of aluminum oxide / 4 moles of aluminum)

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Answer:

0.251 L

Explanation:

convert grams of solute to moles of solute using molar mass

13.3 g LiCl / 42.39 g LiCl gives 0.314 moles of LiCl

Molarity = moles / liter

rework this to solve for liters, which is

moles/molarity = liter

0.314 mol/1.25M = 0.251

Oxygen always has an oxidation number of -2 when bonded in a compound. Here -2 represents that oxygen atom has gained two electrons.

The Oxidation Number can be defined as the number that is allocated to elements in a chemical combination. The oxidation number is basically the count of electrons that atoms in a molecule can share, lose or gain while forming chemical bonds with other atoms of a different element.

A positive oxidation number shows loss of electrons, and a negative oxidation number shows gain of electrons.

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Answer:

kilograms

Explanation:

hope this helps, pls mark brainliest :D

Answer:kilogram

Explanation:

I got the smarts

Answer:

it is Gas

Explanation:

that is the correct answer

i hope i helped

Answer:

I think its 2

Answer:

20

Explanation:

Because 240÷12=20 m÷v=d

The object's density is given with the help of the mass of the object and with the volume. The density of the object weighing 240 gm with a volume of 12 mL is 20 g/mL.

The density of an object is the volume of the solution displaced by the mass of the object. It is given by the ratio of the mass to the volume of the object and the solution displaced.

Density is an important measurement formula that is used in fluid dynamics to determine buoyancy.

The density of the object is given as,

Density (D) = Mass ÷ Volume

Given,

Mass = 240 gm

Volume = 12mL

Substituting values in the above formula the density will be calculated as:

Density (D) = 240 gm ÷ 12 mL

D = 20 gm/mL

Therefore, the density of the 240 gm object will be 20 gm/mL.

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Answer:

0.6145M

Explanation:

Based on the chemical equation, 2 moles of MnO₄⁻ reacts with 5 moles of H₂C₂O₄.

To solve this problem, we need to find moles of MnO₄⁻, with the chemical equation the moles of H₂C₂O₄ and, the concentration of this solution.

Moles MnO₄⁻:

24.98mL = 0.02498L * (0.1968mol / L) = 4.916x10⁻³ moles MnO₄⁻

Moles H₂C₂O₄:

4.916x10⁻³ moles MnO₄⁻* (5 moles H₂C₂O₄ / 2 moles MnO₄⁻) =

0.01229 moles H₂C₂O₄

Molarity H₂C₂O₄:

0.01229 moles H₂C₂O₄ / 0.0200L =

The systematic name for the compound Ba(NO3)2 is barium nitrate. Barium nitrate is an inorganic salt with the chemical formula Ba (NO3)2. It is a colorless, odorless, and crystalline solid that is highly soluble in water. The compound is formed by combining one atom of barium and two ions of nitrate.

The name “barium” comes from the Greek word “barys,” which means “heavy,” and is a reference to its high density. The term “nitrate” refers to the polyatomic ion NO3-, which is composed of one nitrogen atom and three oxygen atoms. Barium nitrate is commonly used in pyrotechnics, as it is a powerful oxidizing agent that produces a bright green flame when ignited.

The systematic naming of inorganic compounds is based on the rules set out by the International Union of Pure and Applied Chemistry (IUPAC). The name of an ionic compound is composed of the cation name followed by the anion name. In the case of barium nitrate, “barium” is the name of the cation, while “nitrate” is the name of the anion.

Therefore, the systematic name for the compound Ba(NO3)2 is barium nitrate.

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The contour interval is 20 m

The elevation at Y, of the point Y is 300 m

The elevation at B is 320 m

The elevation at C is 360 m

The vertical separation or difference in elevation between contour lines is referred to as a contour interval.

Every fifth contour line is a set of bold or thicker lines known as an index contour. The height of the terrain will also rise if the numbers linked with particular contour lines are rising.

There are three types of contour lines: intermediate, index, and supplementary.

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Answer:

12 moles of propane.

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 127 °C

Number of mole (n) =?

Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 127 °C

T(K) = 127 + 273

T(K) = 400 K

Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 400 K

Gas constant (R) = 8.314 L.KPa/Kmol

Number of mole (n) =?

PV = nRT

184.8 × 216 = n × 8.314 × 400

39916.8 = n × 3325.6

Divide both side by 3325.6

n = 39916.8 / 3325.6

n = 12 moles

Thus, 12 moles of propane is present in the cylinder

Answer: Maybe, It could be a good and bad idea.

Explanation:

This is beacuse Metal does not absorb and can block sunlight.

M2 refers to the money supply measure known as M2 money stock.

The FOMC's decisions and actions can impact M2 through its control over interest rates, open market operations, and the influence on economic conditions and confidence. Changes in monetary policy by the FOMC aim to manage the money supply and promote price stability, economic growth, and employment.

M2 is a broad measure of the money supply that includes cash, checking and savings deposits, money market funds, and other time deposits.

The Federal Open Market Committee (FOMC) is a committee within the U.S. Federal Reserve System that is responsible for making decisions regarding monetary policy, including setting interest rates and implementing measures to manage the money supply.

The actions taken by the FOMC can have an impact on M2 and the broader money supply in the economy. Here's how:

1. Open Market Operations: The FOMC conducts open market operations by buying or selling government securities in the open market. When the FOMC buys government securities, it injects money into the banking system, increasing bank reserves and potentially leading to an expansion of M2.

2. Interest Rate Policy: The FOMC sets the target federal funds rate, which is the interest rate at which depository institutions lend and borrow funds from each other overnight. By adjusting the federal funds rate, the FOMC influences borrowing costs for banks and, in turn, affects their lending practices. Changes in interest rates can impact the demand for loans and affect the growth of M2.

3. Impact on Confidence and Spending: The FOMC's actions and communications can influence consumer and business confidence. When the FOMC signals a more accommodative monetary policy stance, it can encourage borrowing and spending, potentially leading to an increase in the growth of M2.

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The structure for 5-chloro-2-propyl-1-heptanol can be drawn by drawing a 7 carbon chain with (OH) functional group on C1, adding propyl group on C2 and  Cl on C5                                  

5-Chloro-2-propyl-1-heptanol is an organic compound that belongs to the class of alcohols.

The IUPAC name of the compound is 5-chloro-2-propylheptan-1-ol, which denotes the position of the hydroxyl group on the carbon chain. The prefix "heptan-" refers to the seven-carbon chain, and the suffix "-ol" denotes the presence of an alcohol functional group (-OH).

5-Chloro-2-propyl-1-heptanol is a colorless to pale yellow liquid with a strong odor. It is a primary alcohol. It is a versatile chemical intermediate that can be used to prepare a variety of other compounds, including pharmaceuticals, agrochemicals, and flavors. It is also used as a solvent and a reagent in organic synthesis

Thus, the structure for 5-chloro-2-propyl-1-heptanol can be drawn by drawing a 7 carbon chain with (OH) functional group on C1, adding propyl group on C2 and  Cl on C5  

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Red Litmus paper turns blue

Answer:

\( Ca(OH) _2 \)

Explanation:

In lime water \( \red{\bold {RED}} \) litmus paper turns \( \blue {\bold {BLUE}} \) because lime water is alkaline.

\(formula \: for \: lime \: water : Ca(OH) _2 \\ \)

The correct answer is: c. 5.7 mg. It's important to note that when performing calculations involving proportions, it's crucial to use consistent units.

To determine the amount of dye needed when using only 65 mL of water, we can set up a proportion based on the given information.

Amount of dye = 22 mg

Amount of water = 250 mL

New amount of water = 65 mL

Unknown amount of dye = ?

We can set up the proportion as follows:

(22 mg) / (250 mL) = (x mg) / (65 mL)

To solve for x (the unknown amount of dye), we can cross-multiply and solve for x:

22 mg * 65 mL = 250 mL * x mg

1430 mg·mL = 250x mg·mL

To isolate x, we divide both sides of the equation by 250 mL:

(1430 mg·mL) / (250 mL) = (250x mg·mL) / (250 mL)

5.72 mg = x

Therefore, when using only 65 mL of water, we will need 5.72 mg of dye.

In this case, both the amount of dye and the amount of water were given in milligrams (mg) and milliliters (mL), respectively. By setting up the proportion correctly and performing the calculation, we determined the required amount of dye for the given volume of water.

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The molarity of the base used in the experiment, which was determined based on the recovered NaCl and the volumes of hydrochloric acid and sodium hydroxide, was approximately 1.15 M.

To determine the molarity of the base used in the experiment, we need to use the stoichiometry of the balanced chemical equation and the given data.

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:

HCl + NaOH → NaCl + H2O

First, we need to find the number of moles of NaCl produced. We can do this by using the given mass of NaCl (2.22 g) and its molar mass (58.44 g/mol):

moles of NaCl = mass of NaCl / molar mass of NaCl

moles of NaCl = 2.22 g / 58.44 g/mol

moles of NaCl = 0.038 moles

Next, we can use the stoichiometry of the balanced equation to determine the number of moles of NaOH that reacted. Since the mole ratio between NaCl and NaOH is 1:1, the number of moles of NaOH is also 0.038 moles.

Now, we can calculate the molarity of the base (sodium hydroxide) using the given volume of sodium hydroxide solution (0.033 L):

Molarity of NaOH = moles of NaOH / volume of NaOH solution

Molarity of NaOH = 0.038 moles / 0.033 L

Molarity of NaOH ≈ 1.15 M

Therefore, the molarity of the base used in the experiment is approximately 1.15 M.

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