does anyone know what the questions are for module 3 algebra dba

The equation of a circle exists:

\($(x-h)^2 + (y-k)^2 = r^2\), where (h, k) be the center.

The center of the circle exists at (16, 30).

Let, the equation of a circle exists:

\($(x-h)^2 + (y-k)^2 = r^2\), where (h, k) be the center.

We rewrite the equation and set them equal :

\($(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0\)

\($x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0\)

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

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Therefore, The probability that the device will work is 0.634 or 63.4%.

This problem can be solved using the complement rule. The complement of the device working is all the parts failing. Therefore, the probability of the device not working is (1 - 0.216)^7 = 0.366. To find the probability of the device working, we subtract this from 1:
1 - 0.366 = 0.634.
To find the probability that the device will work, we'll use the complementary probability. This means we'll first find the probability that all parts fail and then subtract it from 1. Let's denote the probability of a part failing as q, which is equal to 1 - p.
Step 1: Calculate q.
q = 1 - p = 1 - 0.216 = 0.784
Step 2: Calculate the probability of all parts failing.
P(all parts fail) = q^7 = 0.784^7 ≈ 0.1278
Step 3: Calculate the probability that the device will work.
P(device works) = 1 - P(all parts fail) = 1 - 0.1278 ≈ 0.8722
In conclusion, the probability that the device will work is approximately 0.8722.

Therefore, The probability that the device will work is 0.634 or 63.4%.

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Answer:

These are dividend, divisor, quotient and remainder.

Step-by-step explanation:

Determine the first digit or set of digits your divisor will go into at least once.

Determine the maximum number of times your divisor will go into the said digit or digits.

Place the answer over the corresponding digit. For multiple digits, place it over the last digit.

Multiply the answer from above by your dividend.

Place the result under your dividend starting from the left most digit.

Subtract the result from your dividend. Only subtract the digits that line up. For instance, if you have a five digit dividend, but the result is only two digits, only subtract using the first two digits of your dividend.

Bring down the next digit of your dividend beside the result.

Repeat the process using the new set of digits. Each time, bring down the next digit of your dividend.

Answer:

CAUSE I FEEL THE BREK FEEL THE BREK FELLLLLLL THE BREKK

Step-by-step explanation:

9514 1404 393

Answer:

  y = 4

Step-by-step explanation:

The given points are on the horizontal line ...

  y = 4

This is the standard-form equation of that line.

Answer:

c

Step-by-step explanation:

The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

The critical value(s) and rejection region(s) for the type of z-test with a level of significance a = 0.03 and a right-tailed test are as follows :Step 1: Determine the critical value of  zThe critical value is calculated by using the normal distribution table and the level of significance. A right-tailed test will have a critical value of zα. For a level of significance of 0.03, we will look for the z-value that corresponds to 0.03 in the normal distribution table.Critical value for a = 0.03 is z = 1.88 (approx).Step 2: Determine the Rejection Region The rejection region for a right-tailed test is defined as any z-value that is greater than the critical value. That is, if the test statistic is greater than 1.88, we reject the null hypothesis at the 0.03 level of significance, and if it is less than or equal to 1.88, we fail to reject the null hypothesis.Therefore, the rejection region for a right-tailed test with a level of significance of 0.03 is as follows:Rejection Region: Z > 1.88  OR  Z ≤ -1.88Graph: The graph for the given values will be as follows:The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

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To reach a 99% confidence level, a lot of effort will be needed. A 1% chance of wrong acceptance is acceptable to the superior because confidence levels and this risk go hand in hand.

Your sample size and variability will determine how precise your statistics are.

Tighter confidence intervals with smaller error margins are produced by greater sample sizes or lower variability. Wider confidence intervals and greater error margins are produced by smaller sample sizes or increased variability.

The interval width depends on the degree of confidence. That interval won't be as narrow if you desire a higher degree of confidence. At 95% or higher confidence, a narrow interval is preferred.

A 99% CI is going to be wider than a 95% CI from the same sample. Given that the wider interval would have a higher possibility of having the genuine population value, this makes sense.

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Answer:

22.25

Step-by-step explanation:

Answer:

−38 227/512

Step-by-step explanation:

The equation of the tangent plane to z=x**2−y**2 at the point (x,y)=(2,1) is z = 4x - 2y - 5 and to z=3x-2y at (x,y)=(4,3) is z = 3x - 2y + 6.

The partial derivatives of z with respect to x and y must first be found in order to determine the equation of the tangent plane to the surface z=x**2-y**2 at the point (x,y)=(2,1):

Z/Y = -2Y, and Z/X = 2X.

After that, we can use the expression for a plane's point-normal form, which is given by:

z - z0 Equals n · (x - x0, y - y0) (x - x0, y - y0)

where n is the plane's normal vector and (x0, y0, z0) is a location on the plane. We know the normal vector is given by because we want the tangent plane: n = <∂z/∂x, ∂z/∂y, -1>

The normal vector is therefore n = 4, -2, -1> at the location (2,1). Also known is the equation z0 = f(2,1) = 22 - 12 = 3. Consequently, the expression of the tangent plane's solution is:

z - 3 = <4, -2, -1> · (x - 2, y - 1) (x - 2, y - 1)

z - 3 = 4(x - 2) (x - 2) - 2(y - 1) (y - 1) - (x - 2) (x - 2)

z = 4x - 2y - 5

(b) We must first determine the partial derivatives of z with respect to x and y in order to obtain the equation of the tangent plane to the surface z=3x-2y at (x,y)=(4,3):

∂z/∂x = 3 ∂z/∂y = -2

Then, we can use the point-normal form of the equation of a plane, which is denoted by the formula: z - z0 = n (x - x0, y - y0), where (x0, y0, z0) is a point on the plane and n is the normal vector to the plane. Due to our desire for the tangent plane, we are aware that the normal vector is given by: n = z/x, z/y, -1.

The normal vector is therefore n = 3, -2, -1> at the location (4,3). Additionally, we are aware of the fact that z0 = f(4,3) = 3(4) - 2(3) = 6 for the given number (4). In light of this, the tangent plane equation is

z - 6 = <3, -2, -1> · (x - 4, y - 3)

z - 6 = 3(x - 4) - 2(y - 3) - (x - 4)

z = 3x - 2y + 6

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Answer: 9

Step-by-step explanation:

9x9=81

Answer:

not a 100% hopefully it right. 20.25m

Step-by-step explanation:

81÷4=20.25

The 99% prediction that number of defects per countertop is (-19.68, 9.13), under the given condition that new employee have had 13 hours of training.

Let us assume a linear regression model where the number of defects per countertop is projected based on the number of hours of training an employee has received. The 99% prediction interval for the number of defects per countertop can be evaluated applying the formula
y' ± t(α/2,n-2) × s[y"]
here
y' = predicted value of y,
t(α/2,n-2) = t-critical value for a given level of confidence (in this case 99%)
(n-2) =degrees of freedom ,
s[y"] = standard error of the estimate.

Utilizing the given data, we can evaluate y'

y' = 6.717822 - 1.004950 × 13
= -5.276

Therefore, the standard error of the estimate  is given as 1.229787.
Applying a t-distribution table with n-2 degrees of freedom (n=1), we can get that t(α/2,n-2) = 12.706. Then, the  evaluated 99% prediction interval for the number of defects per countertop is
-5.276 ± 12.706 × 1.229787
= (-19.68, 9.13)

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Answer:

A. vertex B

B. Side BC and BD

C. Angle EBD

Step-by-step explanation:

An angle is an undefined term in plane geometry.

Vertex of \(\angle 4\)

The vertex of an angle is the point where the rays that form the angle meet.

From the diagram, rays BE and BA meet at point B to form \(\angle 4\).

Hence, the name of the vertex is B

Sides of \(\angle 1\)

The sides of an angle are the rays or sides that form the angle

\(\angle 1\) is formed by rays BC and BD

Hence, the sides are BC and BD

Another name for \(\angle 5\)

An angle can be named by combining the sides and the vertex.

The sides of \(\angle 5\) are DB and BE, while the vertex is B

This means that rays DB and BE meet at point B

Hence, another name is \(\angle DBE\)

Classify the angles

Angles are classified based on the measure

\(\angle FBC\) is a right angle, because \(\angle FBC = 90^o\)

\(\angle EBF\) is an obtuse angle because \(\angle EBF\) is greater than \(90^o\) but less than \(180^o\)

\(\angle ABC\) is a straight angle, because \(\angle ABC= 180^o\)

Angle bisector

The line or ray that divides an angle into equal halves is an angle bisector.

Ray BE is an angle bisector, because it divides \(\angle DBA\) into two equal halves.

Find \(\angle EBC\)

We have:

\(\angle EBD = 36\)

\(\angle DBC = 108\)

\(\angle EBC\) is calculated using:

\(\angle EBC = \angle EBD +\angle DBC\)

\(\angle EBC = 108+36\)

\(\angle EBC = 144\)

Find \(\angle ABE\)

We have:

\(\angle EBF = 117\)

\(\angle DBC = 108\)

\(\angle ABE\) is calculated using:

\(\angle EBF = \angle ABE +\angle EBD + \angle ABF\)

Where

\(\angle ABF = 90\)

\(\angle ABE = \angle EBD\)

So, we have:

\(117 = \angle ABE +\angle ABE + \angle 90\)

\(117 = 2\angle ABE + 90\)

Collect like terms

\(2\angle ABE =117 - 90\)

\(2\angle ABE =27\)

Divide both sides by 2

\(\angle ABE =13.5\)

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Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Motorcycle driver travels 15kph faster than a bicycle rider

Motorcycle covers 60km in 2 hours less than the time it takes bicycle rider to travel the same distance ;

Let bicycle rider's speed = r kph

Motorcycle driver's speed = (15 + r) kph

TIME it takes bicycle rider to cover a distance of 60km = t hours

TIME it takes motorcycle driver to cover a distance of 60km = (t - 2) hours

The given information says that the number of calls coming to the customer care center of a mobile company per minute is a Poisson random variable with a mean of 5, So the probability that no call comes in a certain minute is 1

                 A Poisson distribution is a probability distribution that shows the probability of a certain number of events occurring within a specific time or space, provided that these events occur at an average rate that is constant throughout the space or time.

             Given a Poisson random variable with mean λ, the probability of observing x occurrences of an event in a certain time interval is given by:

                          P(X = x) = (e^(-λ) * λ^x) / x!,

             where e is Euler's number (approximately equal to 2.71828).

We are required to find the probability that no call comes in a certain minute, i.e., P(X = 0).

Substituting the given values into the Poisson distribution formula:

                     P(X = 0) = (e^(-5) * 5^0) / 0!

                                   = (1 * 1) / 1

                                   = 1

    Therefore, the probability that no call comes in a certain minute is 1.

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To express the given system of differential equation as an almost linear system, we need to find the partial derivatives of the given functions with respect to x and y.

∂f/∂x = -ex
∂f/∂y = 2
∂g/∂x = -1
∂g/∂y = -4cosy

Now, substituting these values in the general form of an almost linear system,

x′(t) = ax + by + r(x,y)
y′(t) = cx + dy + s(x,y)

we get,

x′(t) = -ex + 2y
y′(t) = -x - 4cosy

So,

a = -e, b = 2, c = -1, d = 0

At the critical point (0,0), the Jacobian matrix is

J(0,0) = ⎡⎣⎢⎢⎢-1 2⎤⎦⎥⎥⎥

The eigenvalues of this matrix can be found by solving the characteristic equation,

det(J - λI) = 0

where I is the identity matrix of the same size as J.

det ⎡⎣⎢⎢⎢-1-λ 2⎤⎦⎥⎥⎥ = (-1-λ)(-λ) - 2(2) = λ^2 + λ - 4

Using the quadratic formula, we get the eigenvalues as

λ1 = (-1 + sqrt(17))/2 ≈ 0.56
λ2 = (-1 - sqrt(17))/2 ≈ -2.56

Since the eigenvalues have opposite signs, the critical point is a saddle.

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Septima P. Clark, Modjeska Simkins, and Matthew J. Perry played significant leadership roles in the fight for African American rights in South Carolina.

Septima P. Clark was an influential educator who pioneered citizenship and literacy schools for African Americans. Modjeska Simkins was a civil rights activist and community organizer who fought against racial discrimination and advocated for voting rights.

Matthew J. Perry was a prominent civil rights attorney who challenged segregation laws and fought for equal justice under the law.Septima P. Clark made significant contributions to the civil rights movement in South Carolina through her work as an educator.

She established citizenship and literacy schools that provided African Americans with the necessary tools to engage in civic participation and exercise their voting rights. Clark's schools were instrumental in empowering African Americans and promoting social and political change.

Modjeska Simkins was a prominent civil rights activist and community organizer in South Carolina. She fought against racial discrimination and segregation, working tirelessly to secure voting rights for African Americans.

Simkins was involved in various organizations and campaigns aimed at challenging discriminatory laws and practices, and she played a crucial role in mobilizing African American communities to advocate for their rights.

Matthew J. Perry was a renowned civil rights attorney in South Carolina. He was a key figure in challenging segregation laws and fighting for equal justice under the law.

Perry played a significant role in numerous landmark cases, including Briggs v. Elliott, which ultimately contributed to the landmark Brown v. Board of Education Supreme Court ruling that declared segregation in public schools unconstitutional. Perry's legal efforts were crucial in dismantling systemic racism and advancing civil rights in South Carolina.

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The product of matrices A and B is matrix C

a)  \(C = (3 )\)

b)  \(C = \begin{pmatrix}-30\end{pmatrix}\)

c)  \(C = \begin{pmatrix}14&20\end{pmatrix}\)

d)  \(C =\begin{pmatrix}20&5\end{pmatrix}\)

What is multiplication of matrices?

The product of two matrices A and B is defined if the number of columns of A is equal to the number of rows of B. The first matrix must have the same number of columns as the second matrix has rows. The number of rows of the resulting matrix equals the number of rows of the first matrix, and the number of columns of the resulting matrix equals the number of columns of the second matrix

Given data ,

a)

Let the 2 matrices be A and B

The value of matrix A is

\(A = \begin{pmatrix}4&5\end{pmatrix}\)

The value of matrix B is

\(B = \begin{pmatrix}2\\ \:-1\end{pmatrix}\)

The product of matrix A and B is C

The value of matrix C is

\(C = \begin{pmatrix}4&5\end{pmatrix}\begin{pmatrix}2\\ -1\end{pmatrix}\)

On simplifying the matrix C , we get

\(C = \begin{pmatrix}4\cdot \:2+5\left(-1\right)\end{pmatrix}\)

\(C = (3 )\)

Therefore , the value of matrix C is \(C = (3 )\)

b)

Let the 2 matrices be A and B

The value of matrix A is

\(A = \begin{pmatrix}2&6\end{pmatrix}\)

The value of matrix B is

\(B = \begin{pmatrix}-3\\ \:-4\end{pmatrix}\)

The product of matrix A and B is C

The value of matrix C is

\(C = \begin{pmatrix}2&6\end{pmatrix}\begin{pmatrix}-3\\ -4\end{pmatrix}\)

On simplifying the matrix C , we get

\(C = \begin{pmatrix}2\left(-3\right)+6\left(-4\right)\end{pmatrix}\)

\(C = \begin{pmatrix}-30\end{pmatrix}\)

Therefore , the value of matrix C is  \(C = \begin{pmatrix}-30\end{pmatrix}\)

c)

Let the 2 matrices be A and B

The value of matrix A is

\(A = \begin{pmatrix}1&2\end{pmatrix}\)

The value of matrix B is

\(B = \begin{pmatrix}4&6\\ 5&7\end{pmatrix}\)

The product of matrix A and B is C

The value of matrix C is

\(C =\begin{pmatrix}1&2\end{pmatrix}\begin{pmatrix}4&6\\ 5&7\end{pmatrix}\)

On simplifying the matrix C , we get

\(C = \begin{pmatrix}1\cdot \:4+2\cdot \:5&1\cdot \:6+2\cdot \:7\end{pmatrix}\)

\(C = \begin{pmatrix}14&20\end{pmatrix}\)

Therefore , the value of matrix C is  \(C = \begin{pmatrix}14&20\end{pmatrix}\)

d)

Let the 2 matrices be A and B

The value of matrix A is

\(A = \begin{pmatrix}0&5\end{pmatrix}\)

The value of matrix B is

\(B = \begin{pmatrix}3&6\\ 4&1\end{pmatrix}\)

The product of matrix A and B is C

The value of matrix C is

\(C =\begin{pmatrix}0&5\end{pmatrix}\begin{pmatrix}3&6\\ 4&1\end{pmatrix}\)

On simplifying the matrix C , we get

\(C = \begin{pmatrix}0\cdot \:3+5\cdot \:4&0\cdot \:6+5\cdot \:1\end{pmatrix}\)

\(C =\begin{pmatrix}20&5\end{pmatrix}\)

Therefore , the value of matrix C is  \(C =\begin{pmatrix}20&5\end{pmatrix}\)

Hence ,

The product of matrices A and B is matrix C

a)  \(C = (3 )\)

b)  \(C = \begin{pmatrix}-30\end{pmatrix}\)

c)  \(C = \begin{pmatrix}14&20\end{pmatrix}\)

d)  \(C =\begin{pmatrix}20&5\end{pmatrix}\)

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Answer:

x=4

Step-by-step explanation:

This line has an undefined slope since it goes straight up

The line falls on the x coordinate 4

The total cost for buying 10 packs of paper and 30 notebooks is $87.50.

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Given that, Mr. Imani wants to purchase paper and notebooks for his classroom. at dollar discount he can buy packs of paper, p, for $1.25 each and notebooks, n, for $2.50 each. this is modelled by 1.25p + 2.50n. evaluate for p = 10 and n=30

Putting p = 10 and n = 30, we get,

1.25*10+2.50*30 = 87.50

Hence, The total cost for buying 10 packs of paper and 30 notebooks is $87.50.

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Answer:

b is the answer

Step-by-step explanation:

9514 1404 393

Answer:

  17. True

  18. False

Step-by-step explanation:

A dilation will be an enlargement when the magnitude of the scale factor is greater than 1.

__

17. The magnitude of the scale factor is 1 2/3, a value greater than 1. The dilation is an enlargement (True).

__

18. The magnitude of the scale factor is 1/2, a value less than 1. The dilation is not an enlargement. The statement is False.

Step-by-step explanation:

the measure of angle h is 92°.to determine to meaning of the unknown.angle ,be sure to use the total some of a 180°. if two angles are given.add them together.and then subtract from 180°.if two angles are the same and unknown, subtract the known angle from 180° and then divide by 2.

4. f(x,y) is homogeneous of degree 2.

5. a) f(x,y) is homothetic with h(x,y) = xy and g(x) = x-1

4. Show that f(x,y)=\(x^2\)y is homogeneous, and find its degree of homogeneity:

A function is said to be homogeneous of degree k, if it satisfies the condition:

f(tx,ty) = \(t^k\)f(x,y)

We have f(x,y) = \(x^2\)y. Let’s check if it satisfies the above condition:

f(tx,ty) = \((tx)^2(ty) = t^3x^2y = t^2(x^2y\)) = \(t^2\)f(x,y)

Hence f(x,y) is homogeneous of degree 2.

5. Which of the following functions f(x,y) are homothetic? Explain.

(a) f(x,y)=\((xy)^2\)+1

(b) f(x,y)=\(x^2+y^3\)

Let us first understand the meaning of homothetic transformation.

A homothetic transformation is a non-rigid transformation of the Euclidean plane that preserves the direction of the straight lines but not their length. It stretches or shrinks the plane by a constant factor called the dilation.

Let’s now find out whether the given functions are homothetic or not.

(a) f(x,y)=\((xy)^2\)+1

In order to check if f(x,y) is homothetic or not, we need to check if the function satisfies the following condition:

f(x,y) = g(h(x,y))

where g is a strictly monotonic function and h is a homogeneous function with degree 1

We have

f(x,y) = \((xy)^2\)+1

Let’s assume g(x) = x - 1, then g(x+1) = x

Similarly, let’s assume h(x,y) = (xy), then h(tx,ty) = \(t^2\)h(x,y)

Now, we have

g(h(x,y)) = h(x,y) - 1 = (xy) - 1

Thus f(x,y) is homothetic with h(x,y) = xy and g(x) = x-1

(b) f(x,y)=\(x^2+y^3\)

We can’t write this function in the form f(x,y) = g(h(x,y)) where h(x,y) is a homogeneous function with degree 1. Hence this function is not homothetic.

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Answer:

it would be 60

Step-by-step explanation:

the angle b would be 40 since the one next to it is 140 and then 80 and 60 make 120 and then 180 - 120 is 60 for your answer

Answer:

see explanation

Step-by-step explanation:

(a)

calculate the lengths using the distance formula

d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\)

with (x₁, y₁ ) = J (- 3, - 7 ) and (x₂, y₂ ) = K (3, - 8 )

JK = \(\sqrt{(3-(-3))^2+(-8-(-7))^2}\)

    = \(\sqrt{(3+3)^2+(-8+7)^2}\)

    = \(\sqrt{6^2+(-1)^2}\)

    = \(\sqrt{36+1}\)

    = \(\sqrt{37}\)

repeat with (x₁, y₁ ) = M (8, 3 ) and (x₂, y₂ ) = N (7, - 3 )

MN = \(\sqrt{(7-8)^2+(-3-3)^2}\)

      = \(\sqrt{(-1)^2+(-6)^2}\)

     = \(\sqrt{1+36}\)

     = \(\sqrt{37}\)

repeat with (x₁, y₁ ) = P (- 8, 1 ) and (x₂, y₂ ) = Q (- 2, 2 )

PQ = \(\sqrt{-2-(-8))^2+(2-1)^2}\)

      = \(\sqrt{(-2+8)^2+1^2}\)

      = \(\sqrt{6^2+1}\)

      = \(\sqrt{36+1}\)

      = \(\sqrt{37}\)

(b)

JK ≅ MN ← true

JK ≅ PQ ← true

MN ≅ PQ ← true

The equation of the function is y = sec(2(x + π/6)) + 2

From the graph, we have the following parameters:

A secant function is represented as:

y = A sec(b(x + c)) + d

Where:

A = 0.5 * (max - min) = 0.5 * (3 - 1) = 1

b = Period = 2

c = Phase shift = π/6

d = 0.5 * (max + min) = 0.5 * (3 + 1) = 2

So, we have:

y = 1 * sec(2(x + π/6)) + 2

Evaluate

y = sec(2(x + π/6)) + 2

Hence, the equation of the function is y = sec(2(x + π/6)) + 2

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Answer

The answer is B on Edgenuit

Step-by-step explanation:

Desmos

Answer: See explanation

Step-by-step explanation:

The information given in the question can be turned into an equation as:

2u + y = 30 ........ i

5u + y = 42 ........ ii

Subtract i from ii

3u = 12

u = 12/3 = 4

A pair of socks cost $4

Since 2u + y = 30

2(4) + y = 30

8 + y = 30

y = 30 - 8 = 22

A pair of slippers cost $22

Answer:

C I think because it might be right

Step-by-step explanation: