Despite the theoretically minimal dispersion forces, large molecular mass and chain tangles can have an impact on boiling point.
Motor oilRepeated -CH 2 molecules form lengthy, apolar chains that are distinctive to motor oil. The chemicals found in motor oils have only intermolecular interactions because of their nonpolar structure and lack of electronegativity difference; to be more exact, they are subject to particular London dispersion forces.
The boiling point shouldn't be high because the London dispersion forces aren't too powerful. However, because of the substantial molecular mass and higher electron number of these lengthy chains, the dispersion forces are significantly increased.
Additionally, when chains tangle, they take on new configurations that may reduce their surface area and increase the amount of energy needed to vaporize them.
Therefore, a high boiling point may be caused by two main factors: large molecular mass and chain tangling.
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How do catalysts generally affect chemical reactions? A They increase the temperature of the system. B They increase the surface area of the reactants. C They increase the activation energy by introducing enzymes. D They lower the activation energy by providing an alternate pathway.
Answer:
D
Explanation:
A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy without itself being consumed by the reaction.
Activation energy is the minimum amount of energy required for a chemical reaction to proceed in the forward direction.
A catalyst increases the reaction rate by providing an alternative pathway or mechanism for the reaction
Which of the following statements is true about the relationships between photon energy, wavelength, and frequency?
Group of answer choices
The photon frequency is proportional to energy and inversely proportional to wavelength.
The photon frequency is inversely proportional to energy and proportional to wavelength.
The photon frequency is proportional to energy and proportional to wavelength.
The photon frequency is inversely proportional to energy and inversely proportional to wavelength.
Answer: The Answer is A.
Explanation:
The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.
Hope this Helps!
The photon energy, wavelength, and frequency are the characteristic of the waves and particles. "The photon frequency is proportional to energy and inversely proportional to wavelength." Thus, option A is correct.
What is photon energy?Photon energy has been defined as the energy constituted by the photon of the atom. It is given by the product of Planck's constant and wave frequency. The frequency of the photons is in inverse relation to the wavelength. It is given as,
E = hυ = h c / λ
Here, E is energy, h is Planck's constant, c is the speed of light, υ id frequency, and λ is the wavelength.
On the other hand, the frequency is in direct relation to the energy. The higher the frequency of the photons higher will be its energy.
Therefore, option A. frequency is inversely proportional to the wavelength.
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if 150 g of gallium reacts with excess oxygen how many grams of gallium oxide will be produced?
Approximately 200.18 grams of gallium oxide will be produced when 150 grams of gallium reacts with excess oxygen.
To determine the mass of gallium oxide produced when 150 g of gallium reacts with excess oxygen, we need to understand the balanced chemical equation for the reaction between gallium and oxygen.
The balanced equation for the reaction is:
4 Ga + 3 O2 → 2 Ga2O3
From the balanced equation, we can see that 4 moles of gallium react with 3 moles of oxygen to produce 2 moles of gallium oxide (Ga2O3).
To calculate the mass of gallium oxide produced, we need to follow these steps:
Convert the mass of gallium (150 g) to moles.
The molar mass of gallium (Ga) is 69.72 g/mol. Therefore, the number of moles of gallium is:
Moles of gallium = Mass of gallium / Molar mass of gallium
= 150 g / 69.72 g/mol
≈ 2.15 moles
Determine the mole ratio between gallium and gallium oxide.
From the balanced equation, we know that 4 moles of gallium react to form 2 moles of gallium oxide. Therefore, the mole ratio is 4:2, which simplifies to 2:1.
Calculate the moles of gallium oxide produced.
Since the mole ratio is 2:1, the number of moles of gallium oxide produced is half the number of moles of gallium:
Moles of gallium oxide = 2.15 moles / 2
≈ 1.07 moles
Convert moles of gallium oxide to mass.
The molar mass of gallium oxide (Ga2O3) is 187.44 g/mol. Therefore, the mass of gallium oxide produced is:
Mass of gallium oxide = Moles of gallium oxide * Molar mass of gallium oxide
= 1.07 moles * 187.44 g/mol
≈ 200.18 g
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Ammonia NH3 chemically reacts with oxygen gas O2 to produce nitric oxide NO and water H2O.
What mass of nitric oxide is produced by the reaction of 10.g of ammonia?
Be sure your answer has the correct number of significant digits.
2 moles of ammonia and 2.5 moles of oxygen gas will produce 2 moles of nitric oxide and 3 moles of water.
The reaction between ammonia (NH3) and oxygen gas (O2) to produce nitric oxide (NO) and water (H2O) is shown below:4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)The balanced equation shows that 4 moles of ammonia react with 5 moles of oxygen gas to produce 4 moles of nitric oxide and 6 moles of water. To determine the amount of products formed when a certain amount of reactants is used, we need to use stoichiometry.Suppose we react 2 moles of ammonia with 2.5 moles of oxygen gas. From the balanced equation, we can see that the ratio of moles of ammonia to moles of oxygen gas is 4:5. Therefore, ammonia is the limiting reagent because only 2 moles of ammonia are available, which is not enough to react with 2.5 moles of oxygen gas.To determine the amount of products formed, we will use the mole ratio from the balanced equation:4 moles NH3 : 5 moles O2 : 4 moles NO : 6 moles H2O2 moles NH3 is equivalent to (5/4) × 2 moles O2 = 2.5 moles O2So, 2 moles NH3 + 2.5 moles O2 → 2 moles NO + 3 moles H2O.The number of significant digits in the answer will depend on the number of significant digits in the given amounts of reactants.
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ANSWER ASAP!!!! PLEASE
Answer:
single replacement
Explanation:
The H2 in the sulfuric acid is replaced by the solid zn to form the salt zinc sulfate, ejecting the hydrogen ions which become an h2 molecule. This is also a redox reaction as Zn is oxidized and the H+ ions are reduced.
arrange lif, hci, hf, and f2 in order of increasing normal boiling point
The order of increasing normal boiling point is:hf < hci < lif < f2. The normal boiling point of a substance is related to its intermolecular forces and molecular weight. Substances with stronger intermolecular forces and higher molecular weights generally have higher normal boiling points.
The given substances are:
Lif (lithium fluoride)
Hci (hydrogen chloride)
Hf (hafnium fluoride)
F2 (fluorine gas)
The molecular weights of these substances increase in the order F2 < Hci < Lif < Hf.
The intermolecular forces present in these substances are:
F2: weak van der Waals forces
Hci: dipole-dipole interactions
Lif: ionic interactions
Hf: stronger ionic interactions
The order of increasing normal boiling points is: F2 < Hci < Lif < Hf
So, fluorine gas (F2) has the lowest normal boiling point and hafnium fluoride (Hf) has the highest normal boiling point among the given substances.
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What is the reducing agent in the reaction below?
Cr2O72- +6S2O32- + 14H+ =2Cr3+ + 3S4O62- +7H2O
a)Cr2O72-
b)S2O32-
c)H+
d)Cr3+
e)S4O62-
f)H2O
g)none of these; this is not a redox reaction
I am having trouble deciding which one is losingelectrons/being oxidized.
The reducing agent in this reaction is S2O32- (thiosulfate ion) because it loses electrons and is oxidized to form S4O62- (tetrathionate ion). Option b.
The reducing agent is the species that undergoes oxidation (loses electrons) and causes the reduction (gain of electrons) of another species. In this reaction, the reducing agent is S2O32- since it is oxidized from a +2 oxidation state to a +6 oxidation state in the formation of S4O62-. Therefore, the answer is (b) S2O32-.
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you have 0.5 liters of a gold chloride solution you add 0.5 liters to the solution creating one liter of solution with a concentration of 0.26 M. what was the original concentration.
The original concentration of the gold chloride solution was 0.52 M.
To determine the original concentration of the gold chloride solution, we can use the concept of dilution. When two solutions of different concentrations are mixed together, the resulting concentration can be calculated using the formula:
C1V1 = C2V2
where C1 and V1 represent the initial concentration and volume, and C2 and V2 represent the final concentration and volume.
Given that the final volume is 1 liter and the final concentration is 0.26 M, and the volumes of the original and added solutions are both 0.5 liters, we can substitute these values into the formula:
C1 * 0.5 L = 0.26 M * 1 L
Simplifying the equation:
C1 = (0.26 M * 1 L) / 0.5 L
C1 = 0.52 M
The calculation is based on the assumption that the dilution process is an ideal dilution, where there is no change in the total amount of gold chloride present in the solution during the mixing process. Additionally, it assumes that there are no chemical reactions or interactions between the two solutions.
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Tranition metal can often have multiple charge, which caue everal poibilitie for their chemical formula. A tudent conduct a combution experiment to determine the empirical formula of an unknown compound containing lead and oxygen. Ue their data collected in the table to calculate the empirical formula. What i the whole number ubcript of the oxide ion in the calculated formula?
The empirical formula of a compound is a crucial piece of information that helps to identify the chemical composition of a substance. It represents the simplest whole-number ratio of elements present in a compound.
Determining the empirical formula of a compound can be done through various laboratory experiments, such as combustion reactions, which measure the mass of each element in a sample. In a combustion experiment, a sample of the unknown compound is burned in the presence of excess oxygen, and the masses of each element (lead and oxygen) are measured and recorded in a table.
These masses are then used to calculate the moles of each element, and the ratio of moles is determined by dividing the moles of each element by the smallest moles of any element. The empirical formula is represented by the smallest whole number subscripts that result from this ratio.
Finally, the empirical formula of the unknown compound is determined, and the subscript of the oxide ion in the calculated formula can be determined. It is the whole number subscript assigned to the oxygen atom in the empirical formula.
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Question 3 (1 point)
Which set of forces will result in a change of motion?
100 N north and 100 N south
40 N north, 20 N north, and 60 N south
50 N west and 45 N east
30 N south, 20 N north, and 10 N north
Answer:
100 N north and 100 N south
When magnesium metal (Mg) reacts with hydrochloric acid (HCI), magnesium chloride (MgCl2) and hydrogen gas (H2) are produced according to the following chemical equation.
2 HCI (aq) + Mg (s) → MgCl2 (aq) + H2 (8)
If 1.44 moles of HCI is consumed in the chemical reaction above, how many grams of HCI are consumed? Molar mass of HCI is 36.46 g/mol.
For your answer, only type in the numerical value with three significant figures. Do NOT include the unit or the chemical (numbers only).
Mass of HCI consumed in the reaction 52.6 g.
Given information: Molar mass of HCI = 36.46 g/mol
No of moles of HCI consumed in the reaction = 1.44 moles
We can use the formula for the relationship between moles and mass to calculate the mass of HCI consumed in the reaction.
Mass = No of moles × Molar mass
Thus,Mass of HCI consumed in the reaction = 1.44 mol × 36.46 g/mol= 52.6064 g ≈ 52.6 g
Hence, 52.6 is the required answer in grams consumed of HCI
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What is 0.55 hectometers expressed in decimeters?
a.
550 dm
b.
5.5 dm
c.
55 dm
d.
0.00055 dm
Answer:
a. 550 dm
Explanation:
CAPSTONE PROJECT: A high-level description of the company, including any background needed to open a bar/restaurant. Address the ability to complete the project, including an indication that you have permission (if needed) and access to relevant information to work on the project. 500 words
To complete a capstone project on opening a bar/restaurant, you need a high-level description of the company and any necessary background information.
1. Research: Begin by gathering information about the bar/restaurant industry, market trends, and customer preferences. This will provide a foundation for your project.
2. Company Description: Write a concise description of the company, including its vision, mission, and values. Highlight the unique aspects that will set your bar/restaurant apart from competitors.
3. Background Information: Provide relevant background information, such as the location, target market, and potential customer demographics. This will help determine the feasibility and potential success of your venture.
4. Permissions and Access: Ensure that you have all necessary permissions, licenses, and permits required to open a bar/restaurant. Research local regulations and obtain any required documentation.
5. Resources: Identify and access relevant information and resources needed to work on the project. This may include industry reports, financial data, and marketing strategies.
6. Conclusion in Three Lines: In conclusion, the capstone project on opening a bar/restaurant requires a high-level company description and background information. It is essential to obtain the necessary permissions and access relevant resources to complete the project successfully.
To summarize, you need to research, provide a company description and background information, obtain permissions, and access relevant resources to complete the capstone project on opening a bar/restaurant.
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A 1. 80 m libr solution in acetonitrile, ch3cn, has a density of 0. 826 g/ml. What is the mole fraction of libr? (form. Wts. : libr = 86. 85, ch3cn = 41. 05).
The mole fraction of LiBr is 0.8946
Calculations for LiBr's mole fraction are as follows:We are aware that the mole fraction or molar fraction is defined as the amount of a constituent (expressed in moles), ni, divided by the total amount of all the elements in the mixture (also indicated in moles, ntotal).
mole fraction = n/n overall
first we should calculate hw many gram the solution from the density
assume the volume is 1 L
so.
density = mass solution/ volume solvent
0.826 g/ml = mass/ 100mL
mass= 82.6 g
so the mole of the solution is
mole = mass/ mass molar
mole solution = 82.6 g / 41.05g/ mole = 2.012 mole
Then we can find the mole of LiBr from the concentration
molar= moles x volume
1.8 M = moles x 1 L
moles LiBr = 1.8 moles
thus,
mole fraction = n/ n total
mole fraction = 1.8/ 2.012 = 0.8946
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For the gas phase decomposition of dinitrogen pentoxide at 335 K 2 N₂05 4 NO2 + 02 the average rate of disappearance of N205 over the time period from t = 0 s to t = 104 s is found to be 5.95×10-4
The calculated change in concentration is approximately 6.188×10^-5 M over the given time period.
To calculate the rate of disappearance in a first order decomposition of N₂O₅ over the given time period, we can use the formula:
Rate = Δ[N₂O₅] / Δt
Given:
Rate = 5.95×10^-4 M/s (disappearance of N₂O₅)
Δt = 104 s
We need to determine the change in concentration of N₂O₅ (Δ[N₂O₅]) over the given time period.
Rate = Δ[N₂O₅] / Δt
Δ[N₂O₅] = Rate × Δt
Δ[N₂O₅] = (5.95×10^-4 M/s) × (104 s)
Now, we can calculate the change in concentration of N₂O₅:
Δ[N₂O₅] = 6.188×10^-5 M
Therefore, over the time period from t = 0 s to t = 104 s, the change in concentration of N₂O₅ is approximately 6.188×10^-5 M.
Please note that we have only calculated the change in concentration of N₂O₅, not the initial or final concentrations.
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ASAP PLEASE I NEED TO BALANCE THEM PLZ HELP IM FAILING THANKS ILL GIVE BRAINLIEST
Answer:
4H₂O(l) → 4H₂(g) + 2O₂(g)
Balancing equations
1. 3Fe(s) + 4H₂O(g) → Fe₃0₄(s) + 4H₂(g)
2. 2AlBr₃(aq) + 3Cl₂(g) → 2AlCl₃(aq) + 3Br₂(l)
3. 2HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)
4. 2Al(s) + 3Pb(NO₃)₂ → 2Al(NO₃)₃(aq) + 3Pb(s)
5. 3NaOH(aq) + Fe(NO₃)₃ → Fe(OH)₃(s) + 3NaNO₃(aq)
Explanation:
From the question given, I have been able to balance the chemical equations correctly.
In balancing chemical equations, the chemical equation must have equal number of atoms for each element that are both in the reactant side and in the product side.
For the above to be achieved, the number of atoms in each element will have to be multiplied and added.
A look at the balanced chemical equation above, you will discover that each element has the same number of atoms both in the reactant side and in the product side.
Each chemical in the lab must have a Safety Data Sheet (SDS) that describes its properties and potential hazards including: dtneinreigs
Each chemical in the lab must have a Safety Data Sheet that describes its properties and potential hazards including protective measures and safety precautions for handling, storing, and transporting the chemical.
What is Safety Data Sheet?A Safety Data Sheet formerly known as a Material Safety Data Sheet is a detailed information - based report issued by a hazardous chemical's importer or manufacturer. It characterizes the device's physical and chemical properties.
The manufacturer or distributor is responsible for reviewing existing knowledge to correctly classify the toxic substance and determining the appropriate hazard and precautionary statements that must be included on the label and SDS.
Thus, this should also includes their properties and possible threats, together with safety precautions and protective measures for handling, storing, and transporting the chemical.
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calculate the amount of heat released from combustion of 2 g of wood. the heat capacity of the bomb calorimeter is 9.96 kj/°c .
If the heat capacity of the bomb calorimeter is 9.96 kj/°c, then the amount of heat released from combustion of 2 g of wood is 39.84 kJ.
To determine the amount of heat released from combustion of 2 g of wood, you need to use the formula
Q = C × ΔT Where:Q is the heat released or absorbed in joules (J)C is the heat capacity of the bomb calorimeter (given as 9.96 kJ/°C)ΔT is the change in temperature in degrees Celsius (°C)We can assume that all the heat released from the combustion of the wood is absorbed by the calorimeter, so we can use the heat capacity of the calorimeter to calculate the heat released. Since the calorimeter absorbs the heat, the value of Q will be negative (i.e. the heat is released).
Given: Mass of wood = 2 g Heat capacity of the bomb calorimeter = 9.96 kJ/°C First, we need to calculate the change in temperature. This can be done by measuring the temperature of the calorimeter before and after combustion. Let's assume that the temperature increases by 4.0 °C.ΔT = 4.0 °C Now, we can calculate the heat released: Q = C × ΔTQ = (9.96 kJ/°C) × (4.0 °C)Q = 39.84 kJ
Therefore, the amount of heat released from combustion of 2 g of wood is 39.84 kJ.
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6.58 grams of sulfur trioxide and 16.4 grams of water react to form H2SO4. identify the limiting reagent and the excess. how many grams of the excess is left over .
what mass of sulfuric acid is produced?
1. The limiting reagent is sulfur trioxide, SO₃ and the excess reagent is water, H₂O
2. The mass of the excess reagent leftover is 14.92 g
3. The mass of sulfuric acid, H₂SO₄ is produced is 8.06 g
1. How do i determine the limiting and the excess reagent?The limiting and excess reagent can be obtained as follow:
SO₃ + H₂O -> H₂SO₄
Molar mass of SO₃ = 80 g/molMass of SO₃ from the balanced equation = 1 × 80 = 80 g Molar mass of H₂O = 18 g/molMass of H₂O from the balanced equation = 1 × 18 = 18 gFrom the balanced equation above,
80 g of SO₃ reacted with 18 g of H₂O
Therefore,
6.58 g of SO₃ will react with = (6.58 × 18) / 80 = 1.48 g of H₂O
From the above calculation, we can see that only 1.48 g of H₂O out of 16.4 g is needed to react completely with 6.58 g SO₃.
Thus, the limiting reagent is SO₃ and the excess reagent is H₂O
2. How do i determine the mass of the excess reagent leftover?The mass of the excess reagent leftover can be obtained as follow:
Mass of excess reagent, H₂O given = 16.4 gMass of excess reagent, H₂O that reacted = 1.48 gMass of excess reagent, H₂O leftover =?Mass of excess reagent, H₂O leftover = Mass given - mass reacted
Mass of excess reagent, H₂O leftover = 16.4 - 1.48
Mass of excess reagent, H₂O leftover = 14.92 g
3. How do i determine the mass of H₂SO₄ produced?The mass of H₂SO₄ produced can be obtained as illustrated below:
SO₃ + H₂O -> H₂SO₄
Molar mass of SO₃ = 80 g/molMass of SO₃ from the balanced equation = 1 × 80 = 80 g Molar mass of H₂SO₄ = 98 g/molMass of H₂SO₄ from the balanced equation = 1 × 98 = 98 gFrom the balanced equation above,
80 g of SO₃ reacted to produce 98 g of H₂SO₄
Therefore,
6.58 g of SO₃ will react to produce = (6.58 × 98) / 80 = 8.06 g of H₂SO₄
Thus, the mass of H₂SO₄ produced is 8.06 g
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Which of the following pairs of elements is most likely to form an ionic bond?
A.
nitrogen and oxygen
B.
lithium and chlorine
C.
phosphorus and chlorine
D.
selenium and bromine
which of these statements is true concerning the following reaction?
na(g) → na⁺(g) e⁻.
a. This is an ionization process.
b. The energy required in the process is the definition of the electron affinity
c. Na(g) is gaining an electron
d. This reaction is exothermic
The correct answer is option A: This is an ionization process.
The statement which best describes the following chemical reaction is this is an ionization process.
The complete chemical reaction is given below.
In this reaction, the ionization of sodium is taking place.
Na(g) → Na⁺(g) e⁻
Ionization refers to a process or chemical reaction during which cations or anions are formed by the loss or gain of electrons.
If an atom loses an electron then it forms a cation i.e. positively charges atom and when it gains electrons then anions are formed i.e. negatively charged atoms.
In the above mention case, the parent sodium atom loses one electron and forms a cation. The overall process is called the ionization process.
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when naming cycloalkynes, the triple bond does not require a locant because it is assumed to be between c1 and c2. draw the structure of (r)-3-methylcyclononyne.
The comes to naming cycloalkanes, the triple bond is always assumed to be between carbon atoms 1 and 2 in the ring. This means that the triple bond does not require a locant in the name.
The structure of (R)-3-methylcyclononyne, we first need to identify the parent ring. In this case, it is a nine-carbon ring, which is a nonane. Then, we add the triple bond between carbon atoms 1 and 2 in the ring. This means that we need to add a methyl group to the third carbon atom in the ring. Finally, we need to assign the stereochemistry of the molecule. Since the name specifies that it is (R)-3-methylcyclononyne, we know that the methyl group is located on the right-hand side of the ring when the triple bond is oriented vertically. Putting all of this together, we get the following structure for (R)-3-methylcyclononyne: ```
H
|
H -- C -- C -- C ≡ C
| |
H -- C -- C -- C -- C
| |
H -- C -- C -- C -- C
|
CH3
`` In summary, when naming cycloalkanes, the triple bond does not require a locant because it is assumed to be between carbon atoms 1 and 2 in the ring. To draw the structure of (R)-3-methylcyclononyne, we first identify the parent ring, add the triple bond, add the methyl group, and assign the stereochemistry.
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what are the various hypotheses that are proposed to explain why chilis are so popular as a food additive
There are several food additive hypotheses that have been proposed to explain why chilis are popular as a food additive: Cultural hypothesis and Evolutionary hypothesis etc.
Cultural hypothesis: This hypothesis suggests that chilis are popular in cultures where hot and spicy food is valued. In these cultures, chilis may be used to add flavor and heat to dishes, and they may be considered a sign of cultural identity.
Evolutionary hypothesis: This hypothesis proposes that humans have evolved to enjoy spicy food because it provides certain health benefits. For example, capsaicin, the compound that makes chilis spicy, has been shown to have anti-inflammatory and pain-relieving properties.
Social hypothesis: This hypothesis suggests that people enjoy spicy food because of the social aspects of eating. For example, eating spicy food may be a way of bonding with others over a shared experience.
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Which parts of atoms can interact (react) to form chemical bonds? valence electrons protons the nucleus of each atom the orbitals
The valence electrons are the components of atoms that can interact or react to form chemical bonds.
These are the electrons located in the outermost energy level or shell of an atom.
They participate in chemical bonding and decide an element's reactivity and chemical characteristics.
Each atom's nucleus and protons are not directly involved in the formation of chemical bonds. On the other side, orbitals are areas of an atom where electrons are most likely to be present, but they don't interact or react with one another to create chemical bonds.
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Identify the gas law that applies to the following scenario: an inflated balloon is placed in the freezer for 60 minutes. when the balloon is removed, it is
smaller in size
avogadro's law
gay-lussac's law
charles law
o boyle's law
Boyle's Rule, A balloon serves as an illustration of Boyle's rule in action. The balloon is inflated with air, and as the air pressure presses on the rubber, the balloon expands.
In a balloon that has been placed in a freezer, which of the following gas laws is in effect?Charles's law can be observed in action in a gas thermometer, which uses a gas's volume change to show a change in temperature. It can also be observed more practically by freezing a balloon containing gas and seeing the balloon's volume decrease.
What happens to a balloon's volume when it is placed in a freezer?Because the average kinetic energy of the gas molecules in a balloon drops as the temperature rises, the frozen balloon shrank. Due to this, the molecules move more slowly and encounter the interior walls of objects less frequently and with weaker force.
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0 / 5 points
Order the following chemicals from lowest to highest melting point.
Water
Paraffin wax
Hydrogen sulfide
Ethanol
Carbon dioxide
Answer:
Ethanol - -173.5°FHydrogen sulfide - -121.9°FCarbon dioxide - -69.9 °FWater - 32°FParaffin wax - 115 to 154 °FExplanation:
Ethanol is a chemical, grain alcohol is a volatile and flammable, colorless, and odorless substance. The versatile solvent has many acidic compositions. Paraffin wax is an soft and colorless solid that is made from petroleum coal and oil. It is an excellent material for storing heat.Which of these travels the fastest through a medium?
a atom
b photon
c sound
d electron
How many milliliters of 0.164 M AgNO3 solution are needed to react completely with 76.5 mL of 0.391 M CaCl₂ solution? The net ionic equation for the reaction is Ag (aq) + Cl(aq) → AgCl(s) V(AgNO3) =____mL
Answer:
From the balanced net ionic equation, we can see that 1 mole of AgNO3 reacts with 1 mole of CaCl2 to produce 1 mole of AgCl. Therefore, we can use the stoichiometry of the reaction to calculate the amount of AgNO3 needed to react completely with the given amount of CaCl2.
First, we need to calculate the number of moles of CaCl2 in 76.5 mL of 0.391 M solution:
moles of CaCl2 = concentration x volume
moles of CaCl2 = 0.391 M x 0.0765 L
moles of CaCl2 = 0.0299 mol
Since 1 mole of AgNO3 reacts with 1 mole of CaCl2, we need 0.0299 mol of AgNO3 to react completely with the CaCl2. To calculate the volume of 0.164 M AgNO3 solution containing this amount of AgNO3, we can use the formula:
moles = concentration x volume
Rearranging the formula, we get:
volume = moles / concentration
Substituting the values, we get:
volume = 0.0299 mol / 0.164 M
volume = 0.1823 L
Converting to milliliters:
V(AgNO3) = 182.3 mL
Therefore, 182.3 mL of 0.164 M AgNO3 solution are needed to react completely with 76.5 mL of 0.391 M CaCl2 solution.
The ideal gas constant, R has several different values that could be used. Which quantity causes these differences?
O pressure
O temperature
O volume
O moles
Answer:
The answer is A
Explanation:
which action(s) will increase the equilibrium concentration of an inert gas (such as n2) in water? 1. decreasing the temperature of the water 2. increasing the volume of water 3. decreasing the pressure of the gas above the liquid
The following action will increase the equilibrium concentration of an inert gas (such as n2) in water: decreasing the pressure of the gas above the liquid. On the other hand, increasing the volume of water and decreasing the temperature of the water would not affect the equilibrium concentration of the inert gas in the water. Therefore, option 1 and 2 are incorrect.
When an inert gas such as nitrogen gas (N2) is added to water, it is not soluble in the water. As a result, equilibrium is established between the gaseous nitrogen and the nitrogen dissolved in the water.The concentration of an inert gas in water will increase if the pressure of the gas above the liquid is reduced. Because the gas will move toward the area of low pressure, more gas molecules will be able to dissolve into the water when the pressure above the water decreases.On the other hand, increasing the volume of water and decreasing the temperature of the water would not affect the equilibrium concentration of the inert gas in the water. Therefore, option 1 and 2 are incorrect.
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