Different satellites orbit the earth with a vast range of altitudes, from just a couple hundred km, all the way to tens of thousands of km above the surface. The international space station (ISS) is in a low earth orbit, just 400km above the surface (you can see it with the naked eye at sunset and sunrise as a bright, moving dot). At this altitude, the acceleration due to gravity has a value of 8.69m/s Assuming that the radius of the earth is 6400km).
1. What is the speed of the ISS? Express your answer to three significant figures and include the appropriate units.
2. What is the orbital period (T) of the ISS in minutes?

Answers

Answer 1

Answer:

a)  v = 7.69 10³ m / s,  b)    T = 92.6 min

Explanation:

a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity

          a = v² / r

          v = \(\sqrt{a r}\)

the distance to the ISS is

           r = R_earth + d

           r = 6400 10³ + 400 10³

           r = 6800 10³ m

we calculate

           v = \(\sqrt{8.69 \ 6800 \ 10^3}\)Ra (8.69 6800 103)

           v = \(\sqrt{59.09 \ 10^6}\)

           v = 7.687 10³ m / s

           

the result with the correct significant figures

            v = 7.69 10³ m / s

b) The speed of the ISS is constant, so we can use the uniform motion relationships

            v = d / t

if distance is the orbit distance

            d = 2π r

time is called period

            v = 2π r / T

            T = 2π r / v

let's calculate

            T = 2π 6800 10³ /7,687 10³

            T = 5.558 10³ s

let's reduce the period to minutes

            T = 5.558 10³ s (1 min / 60s)

            T = 9.26 10¹ min

            T = 92.6 min


Related Questions

Star A has a magnitude of 1.0 and is 60 times brighter than B. What is magnitude of B?

Answers

Answer:

The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:

Brightness ratio = 2.512^(magnitude difference)

60 = 2.512^(magnitude of A - magnitude of B)

Taking the logarithm base 2.512 of both sides:

log base 2.512(60) = magnitude of A - magnitude of B

Solving for the magnitude of B:

magnitude of B = magnitude of A - log base 2.512(60)

magnitude of B = 1.0 - log base 2.512(60)

Calculating the value:

magnitude of B ≈ 1.0 - 2.799

magnitude of B ≈ -1.799

Therefore, the magnitude of Star B is approximately -1.799.

Explanation:

Final answer:

Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.

Explanation:

To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.

Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.

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The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?

The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?

Answers

I think c but I’m not sure so don’t use mine

If you dropped a ball on the surface of Katar, what rate would it accelerate toward the ground

Answers

Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or point travelling straight forward. Due to the constant change in direction, motion on a circle accelerates even while the speed is constant.

The rate at which an object's velocity changes in relation to time is known as acceleration. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

The formula a = v/t denotes acceleration (a), which is the product of the change in velocity (v) and the change in time (t). Using metres per second squared (m/s²), you can gauge how quickly velocity varies.

Acceleration due to gravity on earth = 9.8 m/s²

Therefore, the rate at which the ball will fall on the Katar is 9.8m/s²

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity since it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.

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1. Which distance is the greatest?
O 7000 meters
O 99.99 meters
O 4.5 x 10³ meters
O 9.0 x 10² meters

Answers

Answer:

7000 meters

Explanation:

obviously 99.99 is less than 7000

10 cubed is 10 × 10 × 10, 1000, × 4.5 is 4500, which is less than 7000

10 squared is 100, which × 9 is only 900, which is also less than 7000

have a good day

One molecule of dinitrogen tetroxide contains...

A.
four nitrogen atoms and four oxygen atoms.

B.
two nitrogen atoms and four oxygen atoms.

C.
four nitrogen atoms and two oxygen atoms.

D.
two nitrogen atoms and two oxygen atoms.

Answers

Answer:

C

Explanation:

C is correct

Ok!

151617

If a dog has a mass of 2.5 kg, what is its weight and what is the normal force that it feels.
I

Answers

Answer:

Weight = normal force = 24.5 N

Explanation:

Given that,

Mass of a dog, m = 2.5 kg

We need to find its weight and the normal force that it feels.

The weight of an object is given by :

W = mg

Where g is the acceleration due to gravity

\(W=2.5\times 9.8\\\\=24.5\ N\)

The normal force is balanced by the weight of an object. So,

Weight = normal force = 24.5 N

The small size of cells _____.

allows for efficient transport of materials

causes food to be broken down slowly

slows down the removal of wastes

allows for fewer cell organelles

Answers

Answer:

allows for efficient transport of materials

Explanation:

Living cells relatively have a small size, so small that a microscope is needed to see their structure. However, this small size is for their benefitting as it increases their surface area to volume ratio (SA:V).

A large surface area to volume ratio (SA:V) enables easy movement of molecules to and fro the cell membrane via the process of DIFFUSION. Therefore, having a small size allows for efficient transport of materials needed in the cell.

Where does the body get each of these
molecules?
• glucose molecules
• amino acid molecules
• oxygen molecules

Answers

Answer:

Glucose - from the food we eat, then the food is broken down into another type of sugar called glucose.

Amino Acid - animal proteins such as meat, eggs and poultry. When you eat protein, it is broken down into amino acids.

Oxygen - we get oxygen by breathing in fresh air.

Answer:

glucose - food

amino acid - animal proteins (meat, eggs, poultry)

oxygen- hemoglobin

If a car is pushed with a force of 18N for 8m, how much work has been done?

Answers

According to the question, the work done by a car is calculated as 144Nm.

What is force?

Force may be defined as a process of pushing or pulling on an object that significantly produces acceleration in the body on which it acts. It is an external agent capable of changing a body's state of rest or motion. It has a magnitude and a direction.

According to the question,

The force applied on a car = 18 N

The displacement made by a car = 8m.

Now, the work done is calculated with the help of the given formula:

Work done = Force × Displacement.

                           = 18 N × 8m = 144Nm.

Therefore, the work done by a car is calculated as 144Nm.

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Find Density of a cylinder with diameter of 5.0 cm and height of 12.0cm and mass of 600.0g

Answers

Answer: 2.55 g/cm^3

Explanation:

density is defined as:

Density = mass/volume

Now, the mass of the cylinder is 600g

and the volume of a cylinder is:

V = pi*r^2*h

where r is the radius (half of the diameter), here r = (5/2)cm and h is the height, here 12 cm

So the volume is:

V = 3.14*(2.5cm)^2*12cm = 235.5cm^3

then the density is:

D = 600g/235.5cm^3 = 2.55 g/cm^3

In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following statements are true? Select all that apply.

There is no change in the kinetic energy of the book.

The potential energy of the book-Earth system decreases.

The potential energy of the book-Earth system increases.

The potential energy of the book increases.

In Figure 10.13, the author illustrates a book being raised at constant speed. Which of the following

Answers

Answer:

There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Explanation:

This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.

The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.

If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

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At which point on the image to the right would the ball have the greatest velocity if it moved from A to G.

please help me out.

A


B


C


D


E


F


G

At which point on the image to the right would the ball have the greatest velocity if it moved from A

Answers

Answer:

Total energy = Kinetic Energy + Potential Energy = Constant

Since the potential energy is lowest at point D the kinetic energy will be greatest at point D and the velocity will be the greatest.

f(x) = 3x^2+5x-14
Find f(-9)

Answers

Answer:

f(-9) = 184

Explanation:

f(x)=3x²+5x-14

f(-9)= 3(-9)² +5(-9)-14 Order of Operations : Exponents

     =  3(81)+5(-9)-14

     = 243+5(-9)-14

     =  243-45-14

     = 198-14

f(-9)= 184

Hope this helps :)

Answer:

184

Explanation:

Two parallel, vertical, plane mirrors, 38.8 cm apart, face each other. A light source at point P is 30.1 cm from the mirror on the left and 8.7 cm from the mirror on the right.
(a) How many images of point P are formed by the mirrors?
(b) Find the distance from the mirror on the right to the two nearest images behind the mirror.
first nearest image=
second nearest image=
(c) Find the number of reflections of light rays for each of these images.
first nearest image=
second nearest image=

Answers

Answer:

Explanation shown below.

Explanation:

1.The number of images formed by 2 parallel mirrors is an infinite number of images.

2. The characteristics of a plane mirror is such that the object distance equals the image distance.

Hence the object distance is 8.7cm from the right; the image formed would be 8.7cm behind the mirror.

Now a second image is going to be formed by the left mirror which is going to have an image distance of 30.1cm behind the mirror.

Now this image would be reflected on the right side to form a new image which is going to be seen as 38.8 +30.1 = 68.9cm behind the right Mirror .

Hence the shortest distances are 8.7cm and 68.9cm

3. The number of reflections is infinite for both cases.

A 5 kg body rests on a horizontal plane where it is missing frictional force. A force of 10N is applied at the angle of 37 ° over the plan, for a time of 5 s. How far does the body move during this time?

Answers

Answer:

the formula of acceleration

Which of the following would you expect to be a strong electrolyte in solution?

Answers

The following would expect to be a strong electrolyte in solution (b) KCI is correct option.

When dissolved in water, a strong electrolyte produces a large concentration of ions in solution by totally dissociating into ions.  The following compounds are typically strong electrolytes in solution according to this definition:

Al(OH)₃ (aluminum hydroxide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.KCl (potassium chloride) is a strong electrolyte. It completely dissociates into potassium ions (K⁺) and chloride ions (Cl⁻) in solution, resulting in a high concentration of ions and a high electrical conductivity.PbI₂ (lead(II) iodide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.

These substances readily dissociate into ions in water and exhibit high electrical conductivity, making them strong electrolytes in solution.

Therefore, the correct option is (b).

The complete question is,

Which of the following would be a strong electrolyte in solution?

a) Al(OH)₃ b) KCI c) Pbl₂

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Procedure for Calculations:1. Calculate vox and voyvox = v0 cos 0Voy = v0 sin 0

Procedure for Calculations:1. Calculate vox and voyvox = v0 cos 0Voy = v0 sin 0

Answers

In order to calculate vox and voy, let's use the velocity vo = 15 m/s and the angle theta = 60°.

Then, using the formulas, we have:

\(\begin{gathered} V_{ox}=V_o\cdot\cos\theta\\ \\ V_{ox}=15\cdot\cos60°\\ \\ V_{ox}=15\cdot\frac{1}{2}\\ \\ V_{ox}=7.5\text{ m/s} \end{gathered}\)\(\begin{gathered} V_{oy}=V_o\cdot\sin\theta\\ \\ V_{oy}=15\cdot\sin60°\\ \\ V_{oy}=15\cdot\frac{\sqrt{3}}{2}\\ \\ V_{oy}=13\text{ m/s} \end{gathered}\)

What is sound waves

Answers

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Characteristics of sound waves

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Describe what happens to the KE of the simple pendulum as it swings back and forth.

Answers

Answer:

Explanation: do y like me yes or no

As the pendulum swings back and forth, the balance between the two types of energy changes constantly. At some points in its swing, the pendulum has more kinetic energy. At other points, it has more potential energy. Of course, no working system is ideal. pendulum is an object hung from a fixed point that swings back and forth under the action of gravity. ... When the swing is raised and released, it will move freely back and forth due to the force of gravity on it. As a pendulum swings, its potential energy converts to kinetic and back to potential. Recall the concept of conservation of energy—that energy may change its form, but have no net change to the amount of energy.
Answer. Answer: When you let go of the raised bob, its potential energy is converted to kinetic energy as it swings down with increasing speed, and then back to potential energy as it swings up on the other side with decreasing speed. The massive object is affectionately referred to as the pendulum bob. When the bob is displaced from equilibrium and then released, it begins its back and forth vibration about its fixed equilibrium position. The motion is regular and repeating, an example of periodic motion.

Mary weighs 525 N and she walks down a flight of stairs to a level 6.5 m below her starting point. What is the change in Mary’s potential energy? Answer in units of J.

Answers

The change in Mary’s potential energy is - 3412.5 Joule.

What is gravitational potential energy?

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

Given that:

Weight of Marry: W = 525 N.

She walks down a flight of stairs to a level 6.5 m.

Hence, decrease in potential energy of her = Wh

= 525 N × 6.5 m

= 3412.5 Joule.

Hence, the  decrease in potential energy of her is 3412.5 Joule.

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What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg.m/s of
momentum?

Answers

Answer:

The product of the mass and the volume is known as momentum.

According to the law of momentum, it is stated that the two or more bodies remain in a constant state unless an external force is applied in an isolated room.

Momentum depends on the following:-

Mass

Velocity

Momentum = MASS \ X \ VOLUMEMomentum=MASS X VOLUME

\begin{gathered}momentum = 3000kgm/s\\\\mass = 2000kg\\\\velocity =\frac{momentum}{mass}\\\\v= \frac{3000}{2000} \\\\v= 1.5m/s\end{gathered}

momentum=3000kgm/s

mass=2000kg

velocity=

mass

momentum

v=

2000

3000

v=1.5m/s

i’ll mark you brainlist :)

ill mark you brainlist :)

Answers

Ndnxhxnxjzmsmamsmzmnx
i’m famous. follow me at faithwilliamss

Mikey got shocked when he touches a wire. How was the energy transferred to Mikey's fingers?
a. Convection b. Conduction c. Radiation d. Radioaction

Answers

Answer:

Conduction

Explanation:

Conduction is when heat or electricity is transmitted throughout a substance.

The energy transfer taking place through our body is called conduction. Our body is conductive and which make the electrical shock.

What is conduction?

There are three different modes of energy transfer namely, conduction, convection and radiation. Conduction is the energy transfer mode on solids and convection is taking place in gases and liquids.

Radiation is the energy transfer mode through vacuum. In conduction the energy transfers easily through the chain of  closely packed molecules. Whereas in convection, the molecule which obtained an energy travels across the space and transfers to other molecules.

Our body transfers energy inside through conduction process. Skin is very conductive and the electrons from the wire can be passed through our body that's why we gets electrically shocked.

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Which is the correct representation of the right-hand rule for a current flowing to the right?

Answers

Answer:

The third image

Explanation:

The one with the thumb pointing to the right

Answer:

3, correct on Edge 2020

Which is the correct representation of the right-hand rule for a current flowing to the right?

A mass hung from a spring vibrates 15 times in 12 seconds. Calculate the frequency the period of the vibration

Answers

Answer. Answer: answer is 1.25 seconds. 15 ÷ 12 = 1.25 sec.

how do you calculate voltage drop

Answers

Answer:

Multiply current in amperes by the length of the circuit in feet to get ampere-feet. Circuit length is the distance from the point of origin to the load end of the circuit.

Divide by 100.

Multiply by proper voltage drop value in tables. The result is voltage drop.

Explanation:

What is A rounded to the nearest tenth?
A
HHHHHHHHHHH
14
14.2 14.4
14.6
14.8
15
14.1 14.3 14.5 14.7 14.9
What is A rounded to the nearest one?

Answers

Answer: B

Explanition:

proof(how this formula comes )
vector
u.v=|u||v|cosβ

Answers

The formula you mentioned is known as the dot product formula or the scalar product formula. It is used to find the angle between two vectors u and v.

Let's start by defining the vectors u and v. Suppose we have two vectors u and v in a two-dimensional space.

u = (u1, u2)

v = (v1, v2)

The dot product of these vectors is defined as:

u . v = |u| |v| cos(β)

where |u| and |v| are the magnitudes of the vectors u and v respectively, and β is the angle between the vectors u and v.

Now, let's derive this formula. The dot product of two vectors u and v is given by:

u . v = (u1 × v1) + (u2 × v2)

The magnitude of a vector is given by:

|u| = sqrt(u1² + u2²)

|v| = sqrt(v1² + v2²)

We can use the dot product and magnitude equations to obtain:

cos(β) = (u . v) / (|u| × |v|)

Multiplying both sides by |u| × |v| gives us:

|u| × |v| × cos(β) = u . v

Therefore, we have derived the dot product formula:

u . v = |u| × |v| × cos(β)

This formula can be used to find the angle between two vectors u and v in any two-dimensional or three-dimensional space.

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The complete question is-

Write the proof of the formula

u.v=|u||v|cosβ

For which scientific method do you use experimental and control groups?
A. Forming a hypothesis
B. Analyzing data
C. Drawing conclusions
D. Conducting an experiment

Answers

Answer:

Analyzing data B.

Explanation:

Answer:

D

Explanation:

A box, initially at rest, has 36.7 N of force exerted on it for 2.81 s. If the box has a mass of 7.41 kg, what was its velocity at this time?

Answers

Answer:

13.91 m/s

Explanation:

First we need to find the acceleration:

Acceleration = Force/mass

Acceleration = 36.7N/7.41 kg

Acceleration = 4.95 m/s² (rounded to two decimal places)

Then we find the velocity:

Velocity = Acceleration * Time

Velocity = 4.95 m/s² * 2.81 s

Velocity = 13.91 m/s (rounded to two decimal places)

Hi there!

We can begin by calculating the acceleration of the box using Newton's Second Law:

\(\large\boxed{\Sigma F = ma}\)

∑F = Net force (N)

m = mass (kg)

a = acceleration (m/s²)

Rearrange to solve for acceleration:

\(\frac{\Sigma F}{m} = a\\\\\frac{36.7}{7.41} = 4.95 m/s^2\)

Now, we can use the kinematic equation:

\(v_f = v_0 + at\)

vf = Final velocity (? m/s)

v0 = initial velocity (0 m/s, from rest)

a = acceleration (m/s²)

t = time (s)

Plug in the values:

\(v_f = 0 + 4.95(2.81)\\\\v_f = \boxed{13.91 m/s}\)

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