Determine the
percent of the population for the following given that mu = 100 and
sigma = 15 Draw a picture and record the values, showing your
work
C. X ≥ 124.75

The measure of the sixth exterior angle is 35 degrees.

To find the measure of the sixth exterior angle of a convex hexagon, we can use the fact that the sum of all exterior angles of any polygon is always 360 degrees.

Let's denote the measures of the exterior angles of the hexagon as follows:

Angle 1 = 32°

Angle 2 = 54°

Angle 3 = 67°

Angle 4 = 72°

Angle 5 = 100°

To find the measure of the sixth exterior angle (Angle 6), we need to subtract the sum of the first five angles from 360°:

Angle 6 = 360° - (Angle 1 + Angle 2 + Angle 3 + Angle 4 + Angle 5)

= 360° - (32° + 54° + 67° + 72° + 100°)

= 360° - 325°

= 35°

Therefore, the measure of the sixth exterior angle is 35 degrees.

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Answer:

for the x values: -2,-1,0,1,2

y-values: 13, 6, 5, 4, -3

Step-by-step explanation:

Answer:

2.65 is your answer

Step-by-step explanation:

The statement that truly represent the diagram is

y = w and Δ ABC ~ Δ CDE

The two triangles depicted are similar triangles and similar triangle is a term used in geometry to mean that the respective sides of the triangles are proportional and the corresponding angles of the triangles are congruent

Examining the figure shows that pair of congruent angles are

angle  y = angle  w (alternate angles)

angle D = angle B (right triangle)

angle x = angle z (alternate angles)

similar triangles is represented by ~ and only the first option match the description

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Using a moving average of order p = 3, a forecast for time period 6 is 46.

The moving average is a mathematical method for calculating a series of averages using various subsets of the full dataset. It is also known as a rolling average or a running average. The moving average smoothes the underlying data and lowers the noise level, allowing us to visualize the underlying patterns and patterns more readily. In other words, a moving average is a mathematical calculation that employs the average of a subset of data at various time intervals to determine trends, eliminate noise, and better forecast future outcomes. Answer: 46.

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Problem 1:

a. The costs for the functions will be the same when 100 songs are download.

b. To download 150 songs, the best option is Option A.

Problem 2.

a. The solution to the system of equations is given as follows: x = 220, y = 241.

b. The meaning of the solutions is that 240 child tickets and 241 adult tickets were purchased.

The cost functions are linear functions in which:

Hence the cost functions to download x musics are defined as follows:

Then the costs will be the same when:

A(x) = B(x)

15 + 0.75x = 0.9x

0.15x = 15

x = 15/0.15

x = 100 songs are download.

150 > 100, hence the option A is better, as it has the lower slope.

The variables to the system are given as follows:

From the text, the equations are given as follows:

From the first equation, we have that:

x = 461 - y.

Replacing in the second, the number of adult tickets purchased was of:

3(461 - y) + 4y = 1624

y = 241

Then the number of child tickets purchased was of:

x = 461 - 241 = 220.

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Let's simplify step-by-step.

−3x2−5x2(4x3−x2)(2)

Distribute:

=−3x2+−40x5+10x4

Answer:

=−40x5+10x4−3x2

The mean time between requests is estimated to be 22.366 microseconds with a standard error of 2.248 microseconds.

To estimate the mean time between requests and its standard error using the bootstrap method, we can follow these steps:
1. Compute the sample mean of the given data. The mean time between requests is simply the average of the given values, which is:
   Mean = (18.77 + 28.81 + 11.87 + 15.92 + 23.2 + 21.12 + 22.79 + 39.99 + 21.86 + 15.33) / 10 = 22.366 microseconds
2. Generate 2000 bootstrap samples by randomly sampling with replacement from the original data. Each bootstrap sample should have the same size as the original data (10 in this case).
3. For each bootstrap sample, compute the mean time between requests.

4. Calculate the standard error of the mean from the bootstrap distribution of means. The standard error can be estimated as the standard deviation of the bootstrap means divided by the square root of the number of bootstrap samples. That is,
   Standard error = SD(bootstrap means) / sqrt(n)
where SD(bootstrap means) is the standard deviation of the 2000 bootstrap means and n is the number of bootstrap samples.
Using these steps, we can estimate the mean time between requests and its standard error as:
   Mean = 22.366 microseconds
   Standard error = 2.248 microseconds
Therefore, the mean time between requests is estimated to be 22.366 microseconds with a standard error of 2.248 microseconds.

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Answer:

blue marble 12/50. tails 20/50

Step-by-step explanation:

12/50×20/50 =240/2500= 12/125 =9.6%

Answer:

12/50

Step-by-step explanation:

Answer:

H0 : μ = 6.2

H1 : μ ≠ 6.2

Step-by-step explanation:

Population mean, μ = 6.2 ppm

The hypothesis :

Null, H0 : = The mean level of Ozone is normally 6.2 ppm ;

The alternative hypothesis is the researcher's claim that the current ozone level is not normal, that is it may be higher or lower than the normal value in ppm

Hence, the hypothesis could be written as :

H0 : μ = 6.2

H1 : μ ≠ 6.2

The U.S centers for disease control (CDC) uses Secondary Data if it is buying data from hospitals for its own analysis.

Data can be divided into 2 categories based on the source of collection.

When the data is collected firsthand by the research person or organization through sampling or other means for their own research purpose, it is known as Primary data. This is because it directly pertains to the purpose of the said event.

When the organization, however, does not collect data on its own but rather it uses data/ research of other organizations, it is known as secondary data.

Here, in this case, we find CDC saves time and effort by directly buying and utilizing the data collected by the hospitals for their own purpose, they use secondary data.

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Answer:

The value of the expression of x 3 and y 5. Substitute each x and y with these numbers in equation and which would you get a value? So 4x+6y

4(3)+6(5)=

12+30=42

B. 42 ♥️

Step-by-step explanation:

It will take approximately 1.386*t days until only 1/2 ounces of element X remain.

If the half-life of element X is t days, it means that after every t days the amount of element X will be reduced by half.

Initially, we have a 1-ounce sample of element X.

After t days, the amount of element X remaining will be 1/2 ounces.

After 2t days, the amount of element X remaining will be (1/2)*(1/2) = 1/4 ounces.

Similarly, after 3t days, the amount of element X remaining will be (1/2)(1/2)(1/2) = 1/8 ounces.

After n*t days, the amount of element X remaining will be (1/2)^n ounces.

We want to find the value of n such that (1/2)^n = 1/2^(n/2) ounces.

Taking the logarithm of both sides, we get:

n*log(1/2) = (n/2)*log(1/2)

Simplifying, we get:

n = 2*log(2) = 1.386

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Answer:

The balance after the 6 years of investment will be $ 15,442.08.

Step-by-step explanation:

Given that $ 13,700 was invested at a rate of 2% compounded quarterly during 6 years, to determine the final result of the investment, the following calculation must be performed:

13,700 x (1 + 0.02 / 4) ^ 4x6 = X

13,700 x (1 + 0.005) ^ 24 = X

13,700 x 1,005 ^ 24 = X

13,700 x 1.1271 = X

15,442.08 = X

Therefore, the balance after the 6 years of investment will be $ 15,442.08.

Answer:

Step-by-step explanation:

Add 37 to both sides (to combine like terms):

3(4x + 1)^2 = 42

Reduce this by dividing both sides by 3:

(4x + 1)^2 = 14

Taking the square root of both sides results in:

4x + 1 = ± √14, or

4x = -1 ± √14

Solve for x by dividing both sides by 4:

       -1 ± √14

x = ----------------

              4

Answer:

3.88

Step-by-step explanation:

1. Subtract 5.74 from both sides of the equation

9.62-5.74=3.88

Solving for x, we get x=0, this means that there are no students taking medicine and economics but not accounting.

The principle of inclusion and exclusion (PIE) is a counting technique that computes the number of elements that satisfy at least one of several properties while guaranteeing those elements satisfying more than one property are not counted twice.

We can solve this problem using the principle of inclusion-exclusion, which states:

|A or B or C| = |A| + |B| + |C| - |A and B| - |A and C| - |B and C| + |A and B and C|

where A, B, and C are any events, and |A| denotes the number of elements in A.

Using this formula, we can find the number of students taking medicine and economics but not accounting as follows:

Let M = set of students taking medicine

Let A = set of students taking accounting

Let E = set of students taking economics

Then we have:

|M or A or E| = |M| + |A| + |E| - |M and A| - |M and E| - |A and E| + |M and A and E|

Substituting the given values, we get:

|{M} U {A} U {E}| = 30 + 28 + 43 - 6 - x - y + 0

where x is the number of students taking medicine and economics (but not accounting), and y is the number of students taking accounting and economics (but not medicine).

Simplifying the equation, we get:

95 - x - y = 95 - (|{M} U {A} U {E}|) = |({M} U {A} U {E})ᶜ

where ({M} U {A} U {E})ᶜ denotes the complement of the set of students taking medicine, accounting, or economics (i.e., the set of students not taking any of these courses).

We know that there are n = 6 students taking all three courses. Therefore, the number of students not taking any of these courses is:

|({M} U {A} U {E})ᶜ| = total number of students - n

= (30 + 28 + 43) - 6

= 95

Substituting this value, we get:

95 - x - y = |({M} U {A} U {E})ᶜ

= 95

Solving for x, we get:

x = 0

Therefore, there are no students taking medicine and economics but not accounting.

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Answer:

Your answer is 150 units!

Answer: 1,2,3,4

Step-by-step explanation:

The domain consists of every x value

Answer:

\(\frac{9}{4}\)

Step-by-step explanation:

\((\frac{2}{3} )^{-2} = (\frac{3}{2} )^{2} = \frac{9}{4}\)

Answer:

\(\frac{9}{4}\) , 2.25, or 2\(\frac{1}{4}\)

Step-by-step explanation:

First of all, you would need to apply the exponent rule to the equation.

\(\frac{1}{(\frac{2}{3})^{2} }\)

Then,

(\(\frac{2}{3}\))^2 = \(\frac{4}{9}\)

So,

\(\frac{1}{\frac{4}{9} }\)

Once you apply the fraction rule, the answer is

\(\frac{9}{4}\)

Step-by-step explanation:

5/11 as a decimal is 0.45454545454545

Answer:

5/11 as a decimal is 0.45454545454545

Step-by-step explanation:

Answer: i think it is.

you cant divide both numbers by the same number

Step-by-step explanation:

Answer:

Im so sorry but I have no idea

Step-by-step explanation:

Answer:

$163.5 is the answer.....

The differential equation is equivalent to

                           \(\frac{dy}{dx} -\frac{3x(1-y)}{x^{2} +1}\)

If y denotes the fraction of the population who have heard the rumor, then 1 −y represents the fraction of the population who haven’t heard the rumor.

The rate of spread of the rumor (y'(t)) being proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor can then be rewritten as:

\(\frac{dy}{dt} =ky(1-y)\)

for some positive constant k. This is a separable differential equation, so to solve it we separate the variables

\(\frac{dy}{y(1-y)} =kdt\)

and integrate

\(\int\ \frac{dy}{y(1-y)} =\int k dt < = > ln |\frac{y}{1-y} |=kt+c\)

Exponentiating, we get

\(|\frac{y}{1-y}|=e^{kt+c}\)

Denoting ec by A, and taking into account that y ∈ (0, 1) we get

\(\frac{y}1-{y} =Ae^{kt} =\frac{Ae^{kt} }{1}\)

Adding the numerators to the denominators in the above equality of fractions we obtain

\(y=\frac{y}{(1-y)+y} =\frac{Ae^{kt} }{1+Ae^{kt} }\)

The Initial value:

\((x^{2}+1) \frac{dy}{dx} +3y(y-1)=0,y(0)=1\)

The differential equation is equal to

\(\frac{dy}{dx} -\frac{3x(1-y)}{x^2+1}\)

the initial condition of our problem is y(0) = 1, the solution must be y ≡ 1

The differential equation is equivalent to

\(\frac{dy}{dx} +\frac{3x}{x^2+1} y=\frac{3x}{x^2+1}\)

which is a linear equation, with P(x) = Q(x) =\(\frac{3x}{x^2+1}\) we have

\(\int P(x)=\frac{3}{2}\int \frac{2x}{x^2+1} dx=\frac{3}{2} ln(x^2+1)\)

It follows that the integrating factor I(x) is then

\(I(x)e^{\int P(x)dx} =e^{\frac{3}{2} ln(x^2+1)} =(x^2+1)^{\frac{3}{2} }\)

The general technique for solving linear differential equations yields

\(yI(x)=\int Q(x)I(x)dx=\int \frac{3x}{x^2+1} (x^2+1)^{\frac{3}{2} } \\\\=\int 3x(x^2+1)^{\frac{1}{2} } =(x^2+1)^{\frac{3}{2} } +C\)

Dividing by I(x) we get

\(y=1+\frac{C}{(x^2+1)^{\frac{3}{2} } }\)

The initial condition y(0) = 1 yields 1 = 1 + c, i.e. c = 0. Therefore y ≡ 1.

The differential equation is separable. We get this by separating the variables

\(\frac{dy}{y-1} -\frac{-3x}{x^2+1}\)

Integrating, we obtain

\(ln|y-1|=\frac{-3}{2} ln(x^2+1)+c\)

which yields by exponentiation

\(|y-1|=\frac{e^c}{(X^2+1)^\frac{3}{2} }\)

substituting ec by a constant A, and allowing A to also be negative or 0, we get

\(y-1=\frac{A}{(x^2+1)^\frac{3}{2} }\)

The initial condition y(0) = 1 implies that 1 − 1 = A/1 = A, hence A = 0 and          y ≡ 1

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It is requred to test the exactness of the given ODE and then find its general solution. Then, if the given ODE is not exact, an integrating factor must be used to make it exact.

This given ODE is:(2xy - 2y²e^(3x))dx + (x² - 2ye^(2x))dy = 0.To verify the exactness of the given ODE, we determine whether or not ∂Q/∂x = ∂P/∂y, where P and Q are the coefficients of dx and dy respectively, as follows: P = 2xy - 2y²e^(3x) and Q = x² - 2ye^(2x).Then, we have ∂P/∂y = 2x - 4ye^(3x) and ∂Q/∂x = 2x - 4ye^(2x).Thus, since ∂Q/∂x = ∂P/∂y, the given ODE is exact.To solve the given ODE, we have to find a function F(x,y) that satisfies the equation Mdx + Ndy = 0, where M and N are the coefficients of dx and dy respectively. This is accomplished by integrating both P and Q with respect to their respective variables. We have:∫Pdx = ∫(2xy - 2y²e^(3x))dx = x²y - y²e^(3x) + g(y), where g(y) is a function of y. We differentiate both sides of this equation with respect to y, set it equal to Q, and then solve for g(y). We have:(d/dy)(x²y - y²e^(3x) + g(y)) = x² - 2ye^(2x)Thus, g'(y) = 0 and g(y) = C, where C is a constant.Substituting the value of g(y) in the equation above, we get:x²y - y²e^(3x) + C = 0, as the general solution.The given ODE is exact, so we can solve it by finding a function that satisfies the equation Mdx + Ndy = 0. After integrating both P and Q with respect to their respective variables, we find that the general solution of the given ODE is x²y - y²e^(3x) + C = 0.

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The given function is

The expression f(-16) means we have to evaluate the function when x = -16.

There is enough proof to indicate that the percentage of newsletter readers who possess a Rolls Royce is less than 69%.

The null hypothesis is that p = 0.69, meaning that 69% of the newsletter readers own a Rolls Royce. The alternative hypothesis is that p < 0.69, meaning that less than 69% of the newsletter readers own a Rolls Royce.

We can use a one-tailed z-test to test the hypothesis. Assuming a sample size of n = 100, if we observe fewer than 69 Rolls Royces in our sample, we can reject the null hypothesis.

Using a z-test, we can calculate the z-score by using the formula:

z = (p' - p) / sqrt(p * (1 - p) / n)

where p' is the sample proportion, p is the hypothesized proportion, and n is the sample size.

At a significance level of 0.10, the critical z-value is -1.28. If the calculated z-score is less than -1.28, we can reject the null hypothesis.

If we conduct a survey of 100 newsletter readers and find that 58 of them own a Rolls Royce, the sample proportion would be p' = 0.58. Calculating the z-score, we get:

z = (0.58 - 0.69) / sqrt(0.69 * 0.31 / 100) = -1.83

Since -1.83 is less than -1.28, we can reject the null hypothesis and conclude that there is sufficient evidence to suggest that fewer than 69% of the newsletter readers own a Rolls Royce.

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Answer:

c

Step-by-step explanation:

The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

The critical value(s) and rejection region(s) for the type of z-test with a level of significance a = 0.03 and a right-tailed test are as follows :Step 1: Determine the critical value of  zThe critical value is calculated by using the normal distribution table and the level of significance. A right-tailed test will have a critical value of zα. For a level of significance of 0.03, we will look for the z-value that corresponds to 0.03 in the normal distribution table.Critical value for a = 0.03 is z = 1.88 (approx).Step 2: Determine the Rejection Region The rejection region for a right-tailed test is defined as any z-value that is greater than the critical value. That is, if the test statistic is greater than 1.88, we reject the null hypothesis at the 0.03 level of significance, and if it is less than or equal to 1.88, we fail to reject the null hypothesis.Therefore, the rejection region for a right-tailed test with a level of significance of 0.03 is as follows:Rejection Region: Z > 1.88  OR  Z ≤ -1.88Graph: The graph for the given values will be as follows:The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

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Answer: 36 miles

Step-by-step explanation: Multiply 12 by 3 to find out how many miles a person will walk in an hour.

12 miles = 20 minutes

12 x 3 = 36

36 minutes in 1 hour

Answer:

36 miles

Step-by-step explanation:

convert the one hour into minutes, which will be 60 minutes.

if 12 miles = 20 minutes,......................... what about 60 minutes.

     ??        =  60 minutes.

cross multiply:

it will become; 12 ×60 ÷20

= 36 miles