Determine the pH at the point in the titration of 40.0 mL of 0.200 M H₂NNH₂ with 0.100 M HNO₃ after 100.0 mL of the strong acid has been added. The value of Kb for H₂NNH₂ is 3.0 × 10⁻⁶.

Answers

Answer 1

Answer:

pH = 1.85

Explanation:

The reaction of H₂NNH₂ with HNO₃ is::

H₂NNH₂ + HNO₃ → H₂NNH₃⁺ + NO₃⁻

Moles of H₂NNH₂ and HNO₃ are:

H₂NNH₂: 0.0400L ₓ (0.200mol / L) = 8.00x10⁻³ moles of H₂NNH₂

HNO₃: 0.1000L ₓ (0.100mol / L) = 0.01 moles of HNO₃

As moles of HNO₃ > moles of H₂NNH₂, all H₂NNH₂ will react producing H₂NNH₃⁺, but you will have an excess of HNO₃ (Strong acid).

Moles of HNO₃ in excess are:

0.01 mol - 8.00x10⁻³ moles = 2.00x10⁻³ moles of HNO₃ = moles of H⁺

Total volume is 100.0mL + 40.0mL = 140.0mL = 0.1400L.

Thus, [H⁺] is:

[H⁺] = 2.00x10⁻³ moles / 0.1400L = 0.0143M

As pH = - log [H⁺]

pH = 1.85
Answer 2

The pH of the resulting solution is 1.85.

The reaction is 1:1 hence;

Number of moles of  H₂NNH₂ = 40/1000 L × 0.200 M = 0.008 moles

Number of moles of  HNO₃ = 100/1000 L × 0.100 M = 0.01 moles of HNO3

Number of moles of excess acid = 0.01 moles - 0.008  = 0.002 moles

Total volume of solution;

40.0 mL + 100.0 mL = 140 mL or 0.14 L

Molarity of excess acid = 0.002 moles/ 0.14 L = 0.014 M

Since;

pH = -log[H^+]

pH = -log[0.014 M]

pH = 1.85

The pH of the resulting solution is 1.85.

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Related Questions

A mixture of 1-heptyne, 2-heptyne, and 3-heptyne was hydrogenated in the presence of a palladium catalyst until hydrogen uptake ceased. How many seven-carbon hydrocarbons were produced

Answers

Answer:

four

Explanation:

Recall that the hydrogenation of 1-heptyne, 2-heptyne, and 3-heptyne  is an addition reaction. The hydrogen is added across the triple bond in the presence of palladium serving as the catalyst.

Note that 1-heptyne and 2-heptyne do not exist as geometric isomers hence they yield one corresponding hydrocarbon each. However, 3-heptyne exhibits geometric isomerism. As a result of this, 3-heptyne yields cis and trans products making a total of four seven-carbon hydrocarbons produced.

So, the number of seven carbon hydrocarbons produced is one.

1-heptyne, 2-heptyne, and 3-heptyne

Note that if there is excess hydrogen, then all triple bonds will be substituted by hydrogen  so  only  heptane is  formed, double bonds and tirple bonds disappear to

\(CH_3-(CH_2)_5-CH_3\)

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2LiClO+KHSO - Li2SO4 + Cl2 + KOOH
1. How many moles of KOOH is produced, if you started the reaction with 5 moles of
LiCIO?

2LiClO+KHSO - Li2SO4 + Cl2 + KOOH 1. How many moles of KOOH is produced, if you started the reaction

Answers

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO +  KHSO₄     →      Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

                 LiClO          :          KOOH

                    2              :              1

                   5               :             1/2×5 = 2.5

2.5 moles of KOOH are produced.

The rate constant for this first-order reaction is 0.0459 s¹ at 300 °C.
A → products
If the initial mass of A is 15.49 g, calculate the mass of A remaining after 0.731 min.

Answers

The concept half life is used here to determine the mass of 'A' remaining after 0.731 min. The rate constant of a reaction is defined as the rate of the reaction when the molar concentration of each of the reactants is unity. The mass of A remaining is 5.163 g.

What is half life?

The half life period of a reaction is defined as the time in which the concentration of a reactant is reduced to half of its initial concentration. The expression for half life period of a first order reaction is:

\(t _{1} /_{2} = 0.693 / k\)

k - rate constant

k = 0.693 / 0.0459 = 15.098 s

Divide by 60 to convert half life into minutes.

15.098 s = 0.251 minutes

The number of half lives that have past is:

0.731 min / 0.251 min = 2.912 ≈ 3

Initial mass / number of half lives = 15.49 / 3 = 5.163 g

Thus the mass of A remaining after 0.731 min is 5.163 g.

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Use the Internet to find the SDS for regular bleach (sodium hypochlorite, 4-6%).
Identify each of the following items on the SDS:

Answers

The SDS for regular bleach (sodium hypochlorite, 4-6%) for physical state is a thin liquid.

What is SDS?

SDSs provide students, researchers, workers, and emergency personnel with the proper procedures for handling a pure chemical, as well as information on what to do in an emergency situation involving the chemical.

The following items are:

A) Physical state

B) Routes of exposure and symptoms

C) Required protective equipment

D) First aid procedures

E) Fire-fighting measures

F) Chemical reactivity

G) Safe storage

H) Safe disposal

I) Environmental precautions and ecotoxicity

j) Spill cleanup procedures

A) Physical state : Thin liquid

B) Routes of exposure and symptoms :

Inhalation: Exposure to vapor or mist may irritate respiratory tract and cause coughing. Inhalation of  high concentrations may cause pulmonary edema.

Eye Contact:  Corrosive. May cause severe damage to eyes.

Skin Contact: May cause severe irritation to the skin. Prolonged contact may cause burns to the skin.

Ingestion: Ingestion may cause burns to the gastrointestinal tract and respiratory tract, nausea, vomiting,  and diarrhoea.

C) Required protective equipment :

Eye/Face Protection If splashes are likely to occur: Wear safety glasses with side shields (or goggles) or a face shield.

Skin and Body Protection Wear rubber or neoprene gloves and protective clothing such as a long-sleeved shirt.

Respiratory Protection If irritation is experienced, NIOSH/MSHA-approved respiratory protection should be worn.

Positive-pressure supplied air respirators may be required for high airborne contaminant concentrations. Respiratory protection must be provided in accordance with current local regulations.

Hygiene Measures Handle in accordance with good industrial hygiene and safety practice. Wash hands after direct contact. Do not wear product-contaminated clothing for prolonged periods. Remove  and wash contaminated clothing before re-use. Do not eat, drink, or smoke when using this  product

D) First aid procedures:

General Advice Call a poison control centre or doctor immediately for treatment advice. Show this safety data sheet to the doctor in attendance.

Eye Contact Hold eye open and rinse slowly and gently with water for 15 - 20 minutes. Remove contact lenses, if present, after the first 5 minutes, then continue rinsing the eye. Call a poison control centre or doctor for treatment advice.

Skin Contact Take off contaminated clothing. Rinse skin immediately with plenty of water for 15-20 minutes. Call a poison control centre or doctor for treatment advice.

Inhalation Move to fresh air. If breathing is affected, call a doctor.

Ingestion has the person sip a glassful of water if able to swallow. Do not induce vomiting unless told to do so by a poison control centre or doctor.

Do not give anything by mouth to an unconscious person. Call a poison control centre or doctor immediately for treatment advice.

Protection of First-aiders Avoid contact with skin, eyes, and clothing. Use personal protective equipment as required.

Wear personal protective clothing

E) Fire-fighting measures:

Suitable Extinguishing Media

Use extinguishing measures that are appropriate to local circumstances and the surrounding environment.

Unsuitable Extinguishing Media

CAUTION: Use of water spray when fighting fire may be inefficient.

Specific Hazards Arising from the Chemical

This product causes burns to the eyes, skin, and mucous membranes. Thermal decomposition can release sodium chlorate and irritating gases and vapours.

Explosion Data

Sensitivity to Mechanical Impact None.

Sensitivity to Static Discharge None.

Protective equipment and precautions for firefighters

As in any fire, wear self-contained breathing apparatus pressure-demand, MSHA/NIOSH (approved or equivalent) and full protective gear.

F) Chemical reactivity

Reactivity :

Reacts with other household chemicals such as toilet bowl cleaners, rust removers, acids, or products containing ammonia to produce  hazardous irritating gases, such as chlorine and other chlorinated compounds

G) Safe storage

Store away from children. Reclose the cap tightly after each use. Store this product upright in a cool, dry area, away from direct sunlight and heat to avoid deterioration. Do not contaminate food or feed by storage of this product.  

H) Safe disposal

Dispose of in accordance with all applicable federal, state, and local regulations. Do not contaminate food or feed by disposal of this product.

I) Environmental precautions and ecotoxicity

Environmental Precautions This product is toxic to fish, aquatic invertebrates, oysters, and shrimp. Do not allow products to enter storm drains, lakes, or streams.

Ecotoxicity

This product is toxic to fish, aquatic invertebrates, oysters, and shrimp. Do not allow product to enter storm drains, lakes, or streams.

j) Spill cleanup procedures

Methods for Cleaning Up Absorb and Containment. Wash residual down to the sanitary sewer.

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A molecule contains 52.20 g of manganese (Mn) and 3.80 g of carbon(C).

What is its empirical formula?

Answers

Answer:

              Mn₃C

Explanation:

Calculate Moles of Mn

Mole = Mass/M.Mass

Mole = 52.20 g / 54.93 g/mol

Mole = 0.95 mol

Calculate Moles of C

Mole = Mass/M.Mass

Mole = 3.80 g / 12.01 g/mol

Mole = 0.316 mol

Now,

= 0.95 / 0.316 = 3.00

This means for every one atom of C there are three atoms of Mn.

Result:

          Mn₃C

Apex Leaming-Pre-Lab
4. The graph shows a plot of the amount of a radioactive material remaining in
a sample versus time. According to the graph, what is the half-life of carbon-
14? Explain how you used the graph to determine this information.

Apex Leaming-Pre-Lab4. The graph shows a plot of the amount of a radioactive material remaining ina sample

Answers

The half-life of the carbon-14 obtained from the graphical representation of radioactive material remaining in a sample versus time is 5730 years.

How do i determine the half-life of carbon-14?

The half-life a radioactive material is the time taken for half the material to decay or disintegrate.

For example, if the initial mass of a material is 10 g and the material becomes 5 g after 2 days. Then, we can say that the half-life of the material is 2 days.

With the above information in mind, we can obtain the half-life of the carbon-14 as illustrated below:

From the graph, we obtain:

Initial amount of carbon-14 = 1Half the initial amount = 1/2

Now, we shall obtain the time for 1/2 in the graph.

The time for 1/2 in the graph is 5730 years.

Thus, we can conclude that the half-life of the carbon-14 is 5730 years.

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Please help me with this, I will mark you most brainliest. Thank you so much

Please help me with this, I will mark you most brainliest. Thank you so much

Answers

Answer:

20KJ

Explanation:

What is nitrogen G how will be formed G

What is nitrogen G how will be formed G

Answers

Nitrogen G is a colorless, tasteless gas that is the most plentiful element in Earth's atmosphere and is a constituent of all living matter of nitrogen.

what is nitrogen g explain?

Nitrogen is an essential gaseous element with an atomic number of 7 and an atomic weight of 14.0067. Nitrogen gas has two particles of Nitrogen therefore, the molecular formula of this gas is N2. It is a non-metallic element that settled Group 15

nitrogen. [ nī′trə-jən ] N. A nonmetallic element that constructs up about 78 percent of the atmosphere by capacity, Nitrogen is a nonmetal and the lightest member of group 15 of the periodic table

So we can conclude that Nitrogen is the chemical element with the symbol N and atomic number 7.

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12. 5.6g of solid copper was heated with 476.2 J at room temperature (25°C). Given that
copper has a C of 0.38 J/g°C, what would its final temperature be?

Answers

Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

Question 4 (1 point) The volume of 16.0 grams of SO2 gas at STP is closest to

Molar mass: 64.07 g/mol

33.6 L
11.2 L
5.6 L
44.8 L​

Answers

Answer:

5.6L

Explanation:

64.07g=22.4dm^3

16.0g. =?

(16.0×22.4)÷64.07

=5.5939

approximately 5.6L

What is the molarity of an HCl solution if 25.0 mL of this solution required 17.80 mL of 0.108 M NaOH to reach the end point in a titration?

Answers

Answer:

\(\boxed {\boxed {\sf 0.0769 \ M}}\)

Explanation:

We are asked to find the molarity of an acid given the details of a titration experiment. The formula for titration is as follows:

\(M_AV_A= M_B V_B\)

In this formula, M is the molarity of the acid or base and V is the volume of the acid or base. The molarity of the hydrochloric acid (HCl) is unknown and the volume is 25.0 milliliters.

\(M_A * 25.0 \ mL = M_BV_B\)

The molarity of the sodium hydroxide (NaOH) is 0.108 molar and the volume is 17.80 milliliters.

\(M_A * 25.0 \ mL = 0.108 \ M * 17.80 \ mL\)

We are solving for the molarity of the acid and we must isolate the variable \(M_A\). It is being multiplied by 25.0 milliliters. The inverse operation of multiplication is division, so we divide both sides of the equation by 25.0 mL.

\(\frac {M_A * 25.0 \ mL }{25.0 \ mL}= \frac{0.108 \ M * 17.80 \ mL }{25.0 \ mL}\)

\(M_A= \frac{0.108 \ M * 17.80 \ mL }{25.0 \ mL}\)

The units of milliliters cancel.

\(M_A= \frac{0.108 \ M * 17.80 }{25.0 }\)

\(M_A= \frac{1.9224}{25.0 } \ M\)

\(M_A= 0.076896 \ M\)

The original measurements have 3 and 4 significant figures. We must round our answer to the least number of sig figs, which is 3. For the number we calculated, that is the ten-thousandth place. The 9 to the right of this place tells us to round the 8 up to a 9.

\(M_A \approx 0.0769 \ M\)

The molarity of the hydrochloric acid is 0.0769 Molar.

Stephan’s mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing. Which characteristic does the growth of the new plant depict?

Answers

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Convert 167 mL/h to units of liters per day. Show the unit analysis by dragging the conversion factors into the unit-factor slots.

Convert 167 mL/h to units of liters per day. Show the unit analysis by dragging the conversion factors

Answers

On converting 167 mL/h , we get 4.008 L/d

Converting 167 mL/h to units of liters per day

1L=1000mL

1d=24hrs

So  167 mL/1h x1L/1000mLx24h/1d=4008L/1000d

=4.008 L/d

Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.Unit conversion is a multi-step procedure that includes rounding, selecting the appropriate number of significant digits, and multiplying or dividing by a numerical factor.The conversion from one unit to another in order to ensure accuracy and prevent measurement misunderstanding.

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A gas is heated from 246 K to 289 K while its volume is increased from 22.0 L to 30.5 L by moving a large piston within a cylinder. If the original pressure was 0.98 atm, what would be the final pressure?

Answers

The answer is 0.998 atm.

To determine the final pressure of the gas, we can use the combined gas law equation:

P1 * V1 / T1 = P2 * V2 / T2

where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (what we want to find)
V2 = final volume
T2 = final temperature

Given:
P1 = 0.98 atm
V1 = 22.0 L
T1 = 246 K
V2 = 30.5 L
T2 = 289 K

Plugging in the values into the equation, we have:

0.98 atm * 22.0 L / 246 K = P2 * 30.5 L / 289 K

Now we can solve for P2:

P2 = (0.98 atm * 22.0 L * 289 K) / (246 K * 30.5 L)
P2 = 0.98 * 22.0 * 289 / (246 * 30.5)
P2 ≈ 0.998 atm

Therefore, the final pressure of the gas would be approximately 0.998 atm.

The 4-4-9 system is used to estimate the number of _______ in food. Question 9 options: A) kilojoules B) calories C) joules D) nutritional Calories

Answers

Answer: B) calories

Explanation:

The 4-4-9 system is used to estimate the number of calories in food. Under this system, it is assumed that one gram of Protein, one gram of Carbohydrates and one gram of Fats each contribute 4, 4 and 9 calories respectively to the caloric total.

This means that to find out the number of calories in food, multiply the total grams of proteins by 4, the total grams of carbohydrates by 4 and the total grams of Fats by 9 and then add up the results to find out the caloric contribution of Protein, Carbohydrates and Fats.  

Answer:

It's not C calories i put that and missed it

Explanation:

How do you think carbon is recycled between organisms and their environment?​

Answers

Answer: Through the process of photosynthesis, carbon dioxide is pulled from the air to produce food made from carbon for plant growth. Carbon moves from plants to animals. Through food chains, the carbon that is in plants moves to the animals that eat them.

Answer:

Carbon is constantly recycled in the environment. The four main elements that make up the process are photosynthesis, respiration, decomposition and combustion. When plants and animals die, decomposes break down the compounds in the dead matter and release carbon dioxide through respiration.

Help help help ASFAP

Help help help ASFAP

Answers

Answer:

A directory of relatives' phone numbers

Hope this helps

Explanation:

HELP PLEASE
A 6.50-g sample of copper metal at 25.0 °C is heated by the addition of 145 J of energy. The final temperature of the copper is ________ °C. The specific heat capacity of copper is 0.38 J/g-K.
58.7
33.7
83.7
25.0
33.5

Answers

A 6.50-g sample of copper metal at 25.0 °C is heated by the addition of 145 J of energy. The final temperature of the copper is 83.7 °C. The specific heat capacity of copper is 0.38 J/g-K.

The correct answer choice is "83.7"

To solve this problem, we can use the equation:

q = mcΔT

where q is the amount of energy absorbed by the copper, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the change in temperature of the copper.

Rearranging this equation to solve for ΔT, we get:

ΔT = q / (mc)

Substituting the given values, we get:

ΔT = 145 J / (6.50 g x 0.38 J/g-K)

ΔT = 58.7 K

Therefore, the final temperature of the copper is:

25.0 °C + 58.7 °C = 83.7 °C

So the correct option is 83.7.

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What happens to the amount of solution when we add food colour to it?

Answers

Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

when six h2o molecules interact with six co2 molecules, the result is six c6h12o6 molecules and six o2 molecules. in this reaction the products are.

Answers

When six h2o molecules interact with six co2 molecules, the result is six c6h12o6 molecules and six o2 molecules.

What is a chemical reaction?

A chemical reaction is a process that transforms one set of chemical substances into another. It is characterized by changes in the chemical composition of a substance and the release or consumption of energy. During a chemical reaction, bonds between atoms are broken and new bonds are formed to produce different substances. These new substances have different properties than the original substances and may have different chemical and physical properties.

Chemical reactions can occur in a variety of ways, such as the mixing of two or more substances, the exposure of a substance to heat, light, or radiation, and the introduction of a catalyst to speed up the reaction. The chemical reactions that occur are governed by the laws of thermodynamics and the reaction rate is determined by the activation energy required to break the bonds of the reactant molecules.

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1. Write a balanced equation for each of the following reactions. Be sure to include the state of matter for each reactant and product.
b) Solid calcium cyanide and liquid water react to generate calcium hydroxide and hydrogen cyanide, both in solution.

Answers

The balanced equation for the reaction between solid calcium cyanide and liquid water to generate calcium hydroxide and hydrogen cyanide would be \(Ca(CN)_2 (s) + 2H_2O(l)-- > Ca(OH)_2 (aq) + 2HCN (aq)\)

Balancing chemical equations

The reaction between solid calcium cyanide and liquid water to generate calcium hydroxide and hydrogen cyanide would be written as follows:

The chemical formula of solid calcium cyanide = \(Ca (CN)_2 (s)\)

The chemical formula of liquid water = \(H_2O (l)\)

The chemical formula of calcium hydroxide in solution = \(Ca(OH)_2 (aq)\)

The chemical formula of hydrogen cyanide in solution = \(HCN (aq)\)

Bringing all the species together, the equation for the reaction would be:

\(Ca(CN)_2 (s) + H_2O(l)-- > Ca(OH)_2 (aq) + HCN (aq)\)

But the above equation is not balanced. The number of hydrogen and cyanide atoms is not balanced. Balanced chemical equations always have an equal number of every atom in the reactants and in the products.

Thus, the balanced equation of the reaction would be;

\(Ca(CN)_2 (s) + 2H_2O(l)-- > Ca(OH)_2 (aq) + 2HCN (aq)\)

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What is bonding all about in chemistry?

Answers

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds.

Answer:

It is like about a attraction between atoms, molecules, and more.

if u have 100 ml of water in a foam cup or 100 ml of water in a can which variable gets manipulated

Answers

The variable that gets manipulated is Aluminium.

Hot water has more energy than cold water so the sugar dissolves faster in hot water than in cold water. When water is heated, the molecules gain energy and move faster. Because they move faster, they come into contact with the sugar more often dissolving it faster. I can do it. Changing the amount of water will affect the plant growth rate values.

Therefore, we know that the amount of water is the independent variable and the plant growth rate is the dependent variable. The energy from the hydrothermal molecules makes the solid more soluble. In hot water, molecules move more so there are more collisions between water molecules and solids.

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A sample of gas occupies 7.80 liters at 425°C? What will be the volume of the gas at 35°C if the pressure does not change?

Answers

Answer:

How do amoeba respire.

how do plants respire.

What plant structure keeps these droplets from entering the plant?

A. cuticle
B. stem
C. root
D. thorn

Please help!

Answers

Answer:

A

Explanation:

Two specialized cells called 'guard cells' make up each stoma (stoma is singular for stomata). Plants have many stomata up to 400 per mm2 on their leaf surfaces and they are usually on the lower surface to minimize water loss.

Why should objective tests be done in the chemical industry instead of subjective tests?

Answers

Objective testing must be given precedence over subjective tests within the chemical industry due to its ability to yield more reliable and accurate results.

What is objective and subjective tests?

In the chemical industry where precision is paramount, objective testing should be utilized as opposed to subjective assessments for more reliable outcomes.

Objective testing provides a standardised evaluation without bias which measures an individual's acumen accurately. This form of assessment employs question types such as multiple-choice queries with clear and concise responses that leave no room for ambiguity.

Conversely,' subjective test rely heavily on the judgements of others when gauging performance levels including open-ended questioning techniques which require creativity.

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98.96g/mol of CH2O what will be the chemical formula

Answers

The molar mass of CH2O is given as 98.96 g/mol. To determine the chemical formula, we need to find the simplest ratio of the elements present.

Let's break down the molar mass of CH2O:

- Carbon (C) has a molar mass of approximately 12.01 g/mol.
- Hydrogen (H) has a molar mass of approximately 1.01 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.

Now, let's calculate the molar mass of CH2O:
(1 x molar mass of C) + (2 x molar mass of H) + (1 x molar mass of O)
= (1 x 12.01 g/mol) + (2 x 1.01 g/mol) + (1 x 16.00 g/mol)
= 12.01 g/mol + 2.02 g/mol + 16.00 g/mol
= 30.03 g/mol

The molar mass of CH2O is approximately 30.03 g/mol, which is different from the given molar mass of 98.96 g/mol.

It seems that there might be an error or misunderstanding in the given molar mass value. The correct chemical formula for a compound with a molar mass of 98.96 g/mol cannot be determined based on the information provided.

The speed of light constant (c) is:
3.00 x 108(m/s)
9.8m/s²
6.626 x 10-34(J)
101.325kPa

Answers

The speed of light constant ( c ) is 3.00 × 108 ( m / s ). Therefore, option A is correct.

What is speed ?

Speed is what it means. the speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

"As a force, that is the speed of light in a vacuum. If you wonder why c, the Latin term celeritas, which means speed, is the solution."

This establishes the exact value of the speed of light in a vacuum at 299,792,458 m/s. This gives a very succinct response to the question, It does not, however, settle the issue. The SI is based on a lot of real-world factors.

Thus, option A is correct.

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A chemistry student wants to learn how pressure and volume affect one another. They gather a sample of helium from a ballon and measure the initial pressure at 4.5 atm and bounce at 12.1 liters. The students then increases the pressure to 15.2 atm

What’s P1
What’s P2
What’s V2

Answers

P1- 4.5 atm
P2- 15.2 atm
V2- 12.1 liters

combustion always result in to formation of water. what other type of reactions may result into formation of water? examples of these reactions​

Answers

As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.

Acid-Base Neutralization Reactions:

A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.

H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.

Example: Formation of Sodium Chloride (Common Salt):

HCl + NaOH → NaCl + H₂O

Hydrogen and Oxygen Reaction:

Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.

Example: 2 H₂ + O₂ → 2 H₂O

Learn more about reactions:

https://brainly.com/question/25769000

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