Describe some drawbacks to using heating mantles...

Answers

Answer 1

Heating mantles are commonly used in chemical laboratories for heating solutions in round-bottom flasks. Although they are useful in many ways, they also have some drawbacks.

One of the main disadvantages of heating mantles is that they can be a safety hazard if they are not used properly. Heating mantles can easily overheat and cause the flask to crack or even explode, which can cause injury to the operator and damage to the equipment. Another drawback of using heating mantles is that they are not suitable for heating all types of solutions. For example, heating mantles are not recommended for heating volatile or flammable solutions as they can cause fires or explosions. Additionally, heating mantles can be expensive to purchase and maintain. They require regular cleaning and calibration to ensure that they are working correctly, and this can be time-consuming and costly. Finally, heating mantles can be energy-intensive and consume a lot of electricity, which can add up to high utility bills. In summary, while heating mantles are useful for heating solutions, they have some drawbacks that should be taken into account when using them in the laboratory.

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Related Questions

0.50 moles of gas take up 10.5 L
of space under constant pressure
and temperature conditions.
What volume is required to hold
2.0 moles of the gas?

Answers

Answer:

Explanation:as V is proportional to n(mole),you can easily calculate using V1/n1=V2/

The volume required to hold 2 moles of the gas is 42 L

Explanation:

(2.0 x 10.5)/0.50

= 21/0.50

= 42 L

Balance this equation: CS^2 + O^2 ---> CO^2 + SO^2

Answers

Balanced equation = CS₂ + O₂ = 2CO₂ + SO₂ . The reaction's mass and charge are in balance on both sides.

What is a reaction to balance?

An equation for a chemical reaction that has the same total charge and number of atoms for both the reactants and the products is called a balanced equation. To put it another way, the reaction's mass and charge are in balance on both sides.

A balanced chemical equation is one in which the mass of the reactants and the mass of the products are both equal to the number of atoms of each element on both sides of the equation.

Why do we balance equations?

To comply with the law of conservation of mass, which states that "Total mass of all the products of the reaction in a chemical reaction is equal to the total mass of all the reactants," the chemical equation must be balanced.

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Which is the best definition of
force?
A. a push or pull
B. a change in motion
C. a motion that does not change

Answers

Answer:

A

Explanation:

........................

Answer:

push or pull i think..okay?

he circles below represent a phase change occurring at constant temperature: h5ani Is the value of each of the following positive (+), negative (−), zero (0), or impossible to determine from the given information? (a) qsys (b) ΔEsys (c) ΔEuniv + − 0 inconclusive + − 0 inconclusive + − 0 inconclusive

Answers

(a) qsys: impossible to determine

(b) ΔEsys: 0

(c) ΔEuniv: inconclusive

What is the determination of the changes in qsys, ΔEsys, and ΔEuniv during the phase change?

In the given information, the circles represent a phase change occurring at constant temperature. However, the information provided does not allow us to determine the value of qsys, which represents the heat transfer to or from the system. Without additional data, we cannot ascertain whether heat is being added or removed from the system.

Regarding ΔEsys, which represents the change in internal energy of the system, it is determined to be zero. This indicates that there is no change in the system's internal energy during the phase change occurring at constant temperature.

Lastly, the value of ΔEuniv, which represents the change in the total energy of the system and its surroundings, is inconclusive based on the given information. Without further details, it is not possible to determine whether the phase change results in a change in the total energy of the system and its surroundings.

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Order the items below from largest to smallest size.

ITEM BANK

1 atom of oxygen
1 mole of oxygen
1 molecule of oxygen
3.01 X 1023 atoms of oxygen
4 grams of oxygen


1_
2_
3_
4_
5_​

Answers

Answer:

1- gram of oxygen, 2- 3.01x1023 atoms of oxygen, 3- 1 molecule of oxygen, 4- 1mole of oxygen, 5- 1atom of oxygen.

who is given credit for discovering the periodic table of elements? when and where did he live?

Answers

The credit for discovering the periodic table of elements goes to the Russian chemist Dmitri Mendeleev. He was born in Tobolsk, Siberia in 1834 and lived until 1907.

Mendeleev is recognized as the father of the modern periodic table because of his work in organizing and categorizing the elements based on their chemical properties.

In 1869, Mendeleev published his periodic table, which arranged the known elements in order of increasing atomic weight and grouped them by their chemical properties. He left gaps in the table for elements that had not yet been discovered, predicting their properties based on the patterns he observed in the known elements.

Mendeleev's work revolutionized chemistry and led to a better understanding of the relationships between the elements. His periodic table formed the basis for future discoveries in chemistry and is still used today in modern science.

In conclusion, Dmitri Mendeleev is credited with discovering the periodic table of elements and his contributions to the field of chemistry have had a lasting impact on science.

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What is the molecular mass of glucose C6H12O6 molecule ?

Answers

180 u is the molecular mass of glucose C6H12O6 molecule

What is molecular mass ?

Molar mass is the mass of one mole of a substance, defined as its atomic or molecular mass in grams.  It is defined as the number of units (atoms, molecules, ions, etc.) in a substance that contains the same number of units as 12 grams of pure carbon-12. The molar mass of a substance is important because it provides a conversion factor between the  mass of a substance and the number of moles of a substance, allowing chemical reactions and composition of compounds to be more easily calculated. Molar mass can be calculated by summing the atomic masses of all atoms in a molecule of a substance. For example, the molar mass of water (H2O) is 18.015 g/mol. This means that 1 mole of water weighs 18.015 grams .

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Why are some isotopes radioactive and some are not?

Answers

Answer: there are atoms that either have too many or too few neutrons or protons in their nuclei. This results in an imbalance between the jedi forces holding them together, which leads to an excess of internal energy. Such atoms are said to be unstable or radioactive.

Explanation:

Arrange the elements in each of the following groups
in increasing order of the most positive electron affinity: (a) Li, Na, K; (b) F, Cl, Br, I; (c) O, Si, P, Ca, Ba

Answers

The elements arranged in increasing order of the most positive electron affinity for each group are:

(a) Li, Na, K

(b) I, Br, Cl, F

(c) Ba, Ca, Si, P, O

(a) Li, Na, K: In this group, the electron affinity increases as we move from left to right in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Li, Na, and K.

(b) F, Cl, Br, I: In this group, the electron affinity generally increases as we move from left to right and from bottom to top in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are I, Br, Cl, and F.

(c) O, Si, P, Ca, Ba: In this group, the electron affinity generally increases as we move from left to right and from top to bottom in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Ba, Ca, Si, P, and O.

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Tellurium-123 is a radioactive isotope occurring in natural tellurium. The decay constant is 1.7 × 10^−21/s . What is the half-life in years?

Answers

the half-life of Tellurium-123 is approximately 1.296 × 10^13 years.

The decay constant (λ) of an isotope is related to its half-life (t½) through the equation:

λ = ln(2) / t½

where ln represents the natural logarithm.

To find the half-life of Tellurium-123, we can rearrange the equation as follows:

t½ = ln(2) / λ

Given that the decay constant (λ) of Tellurium-123 is 1.7 × 10^−21/s, we can substitute this value into the equation:

t½ = ln(2) / (1.7 × 10^−21/s)

Calculating this using a calculator, we find:

t½ ≈ 4.085 × 10^20 s

To convert this into years, we divide by the number of seconds in a year. Assuming there are 365.25 days in a year (accounting for leap years), and 24 hours, 60 minutes, and 60 seconds in a day:

t½ (years) ≈ (4.085 × 10^20 s) / (365.25 days/year * 24 hours/day * 60 minutes/hour * 60 seconds/minute)

Evaluating this expression, we find:

t½ (years) ≈ 1.296 × 10^13 years

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help me please thank you

help me please thank you

Answers

Answer:

I dont know what that is I just need points lol sorry

Answer:

1. metaphase

2. prophase

3. telophase

4. interphase

5. interphase

6. interphase

7. anaphase

8. interphase

(4,5,6,8 I'm not sure)

if a chemist wishes to prepare a buffer that will be effective at a ph of 5.00 at 25°c, the best choice would be an acid component with a ka equal to

Answers

If a chemist wishes to prepare a buffer that will be effective at a ph of 5.00 at 25°c, the best choice would be an acid component with a ka equal to 9.10 x 10⁻⁶.

Define  buffer solutions

A buffer is a substance that can withstand a pH change when acidic or basic substances are added. Small additions of acid or base can be neutralised by it, keeping the pH of the solution largely constant. For procedures and/or reactions that call for particular and stable pH ranges, this is significant.

A buffer must contain an acid component with a pKa near to the required pH for it to function at a pH of 5.00. We can compute pKa using the equation pKa = -log(Ka) to determine the optimal option. The ideal choice of Ka corresponds to the pKa that is closest to 5.00.

pKa = -log(9.10 x 10⁻⁴) = 3.04

pKa = -log(9.10 x 10⁻⁶) = 5.04

pKa = -log(9.10 x 10⁻⁸) = 7.04

The best choice is with a Ka equal to 9.10 x 10⁻⁶.

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Topic Mole
2 NaCl + 1 Zn(NO3)2 --> 1 ZnCl2 + 2 NaNO3
How many grams of ZnCl₂ will be produced if
you have 500 grams of Zn(NO3)2

Answers

If you have 500 grams of Zn(NO₃)₂, approximately 359.90 grams of ZnCl₂ will be produced.

To determine the number of grams of ZnCl₂ produced when 500 grams of Zn(NO₃)₂ is used, we need to calculate the molar masses and use stoichiometry.

The molar mass of Zn(NO₃)₂ can be calculated by summing the atomic masses of each element:

Zn: 65.38 g/mol

N: 14.01 g/mol

O: 16.00 g/mol (x 6 because there are 6 oxygen atoms)

Total molar mass of Zn(NO₃)₂ = 65.38 + (14.01 x 2) + (16.00 x 6) = 189.38 g/mol

Next, we use the balanced equation to determine the stoichiometric ratio between Zn(NO₃)₂ and ZnCl₂. From the equation, we can see that the ratio is 1:1.

Therefore, the number of moles of ZnCl₂ produced will be the same as the number of moles of Zn(NO₃)₂ used.

To calculate the number of moles of Zn(NO₃)₂, we divide the mass by the molar mass:

Number of moles of Zn(NO₃)₂ = 500 g / 189.38 g/mol ≈ 2.642 mol

Since the ratio between Zn(NO₃)₂ and ZnCl₂ is 1:1, the number of moles of ZnCl₂ produced will also be 2.642 mol.

Finally, we calculate the mass of ZnCl₂ by multiplying the number of moles by its molar mass:

Mass of ZnCl₂ = 2.642 mol x 136.29 g/mol (molar mass of ZnCl₂) ≈ 359.90 g

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Two biologists, two chemists, and two physicists go out to dinner and sit at a round table with 6 equally spaced chairs. In how many ways can they sit so that no two scientists of the same type (for example, two biologists) are seated next to each other? (Two seatings that are merely rotations of each other are not considered distinguishably different.)
Why is my approach wrong?
I first seat the biologist to one of the seats, he has one choice. I then seat the other biologist, he has 3 choices. Next, I seat one of the chemists, who has 4 choices. The next chemist then has to choices. Finally, we have the physicists who have no choice but to be in the two remaining seats.
1*3*4*2 = 24.
Why is the answer 32? Please explain, thanks

Answers

By taking into account the different seating possibilities for the biologists, chemists, and physicists, you will find that the total number of valid seating arrangements is indeed 32.

Your approach is incorrect because it does not consider all possible arrangements that satisfy the given conditions. Let's analyze your approach step by step.

You correctly start by seating one biologist, which can be done in 1 way. However, when you proceed to seat the second biologist, you assume that there are 3 choices. This is where the error occurs.

Consider the following possibilities:

If the first biologist is seated at Chair 1, the second biologist cannot be seated at Chair 2 or Chair 6, as they would be sitting next to each other. Therefore, the second biologist can only be seated at Chair 4.

If the first biologist is seated at Chair 2, the second biologist can only be seated at Chair 5.

If the first biologist is seated at Chair 3, the second biologist can only be seated at Chair 6 or Chair 1.

If the first biologist is seated at Chair 4, the second biologist can only be seated at Chair 1.

If the first biologist is seated at Chair 5, the second biologist can only be seated at Chair 2.

If the first biologist is seated at Chair 6, the second biologist can only be seated at Chair 3.

So, there are actually 6 different arrangements for seating the two biologists.

Now, if we continue with your approach, seating the chemists and physicists, we need to consider the additional possibilities that arise due to the constraints of the biologist's seating arrangements.

Therefore, the correct approach would involve considering all possible arrangements that satisfy the given conditions. By taking into account the different seating possibilities for the biologists, chemists, and physicists, you will find that the total number of valid seating arrangements is indeed 32.

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a balloon has a volume of 10.2 l at 2.3 atm of pressure and 500c. what is the temperature of the same balloon at 3.3 atm and 20.4 l?

Answers

a balloon has a volume of 10.2 l at 2.3 atm of pressure and 500c. the temperature of the same balloon at 3.3 atm and 20.4 l is  77 °c;

calculation as follows: V1/T1 =V2/T2, 2.3/298 = 2.7/T2, T2 = 77 °c. The mean vertical component of a gas's moving molecules is then evaluated by it's own pressure. The pressure acts right angles to the facade (normal); the tangential (shear) element of the force is proportional to the viscosity of the gas. The standard pressure measurement unit is the pascal (Pa). Because a pascal is a very tiny quantity of pressure, the kilopascal represents the most useful unit for each and every day gas pressures (kPa). 1000 pascals corresponds one kilopascal. The atmosphere is another frequently utilised unit of pressure (atm). Temperature and pressure are basic sets of circumstances for experimental measurements that allow comparisons between different sets of data to be made.

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In this reaction, how many grams of O2 are required to completely react with 110 grams of Al

Answers

Answer:

98 g

Explanation:

Start with the balanced equation. Then, make a little chart under the equation showing the information you have and need.

        3O₂(g) + 4Al(s)  →  2Al₂O₃(s)

m        ?           110 g

M      ___       ____

n       ___ <=  ____

"m" is for mass. "M" is for molar mass (some teachers use "MM"). "n" is for the number of moles.

To find the mass of oxygen:

Calculate the molar mass of oxygen (\(M_{O_{2}\))Calculate molar mass of aluminum (\(M_{Al}\))Use \(M_{Al}\) to find the moles of aluminum (\(n_{Al}\))With \(n_{Al}\), use the mole ratio to find the moles of oxygen (\(n_{O_{2}}\))Use \(n_{O_{2}}\) and \(M_{O_{2}}\) to find the mass of oxygen (\(m_{O_{2}}\))

To find molar mass, use the atomic mass on your periodic table. For each atom of an element, add on its atomic mass.

Molar mass of aluminum (one Al atom):

\(M_{Al} = 26.982 g/mol\)

Molar mass of oxygen (two O atoms):

\(M_{O_{2}} = 16.000g/mol+16.000g/mol\)

\(= 32.000g/mol\)

Update the chart:

               3O₂(g)       +          4Al(s)          →     2Al₂O₃(s)

m                ?                        110 g

M      32.000 g/mol       26.982 g/mol

n                ___         <=      ____

Find the moles of aluminum

\(n_{Al} = \frac{110g}{1} *\frac{1mol}{26.982g}\)    Multiply mass by molar mass to find moles.

\(n_{Al} = \frac{110}{1} *\frac{1mol}{26.982}\)       The units "g" cancel out.

\(n_{Al} = 4.0(7)mol\)        Keep one extra significant figure. (110 has 2 sig. figs.)

               3O₂(g)       +          4Al(s)          →     2Al₂O₃(s)

m                ?                        110 g

M      32.000 g/mol       26.982 g/mol

n                ___         <=   4.0(7) mol

Find the moles of oxygen using the mole ratio, which comes from the coefficients in the balanced equation.

The mole ratio of oxygen to aluminum is 3 to 4.

\(n_{O_{2}} = \frac{4.0(7)mol_{Al}}{1}*\frac{3mol_{O2}}{4mol_{Al}}\)     Multiply moles of aluminum by the mole ratio.

\(n_{O_{2}} = \frac{4.0(7)}{1}*\frac{3mol_{O2}}{4}\)             "molAl" units cancel out.

\(n_{O_{2}} = 3.0(52)mol_{O2}\)              Keep two sig. figs. when the first is a "5"

               3O₂(g)       +          4Al(s)          →     2Al₂O₃(s)

m                ?                        110 g

M      32.000 g/mol       26.982 g/mol

n          3.0(52) mol   <=    4.0(7) mol

Find the mass of oxygen

\(m_{O_{2}} = \frac{3.0(52)mol}{1}*\frac{32.000g}{1mol}\)        Multiply moles by molar mass.

\(m_{O_{2}} = \frac{3.0(52)}{1}*\frac{32.000g}{1}\)             The "mol" unit cancels out.

\(m_{O_{2}} = 97.(6)g\)                         Keep one sig. fig. to round. "6" rounds up.

\(m_{O_{2}} = 98g\)                               <= Final answer

∴ 98 grams of oxygen are required to completely react with 110 grams of aluminum.

density of volume of water and solid if its 62.7 ml

Answers

Answer:  Assuming the question wants to know the mass of the same volumes of ice and water:  57.5 g for ice and 62.7 g for water/

Explanation:  The density of ice and water are 0.917 g/cm^3 and 1.99 g/cm^3, respectively.  1cm^3 = 1ml

(62.7 ml)*(0.917 g/cm^3) = 57.5 g for ice

(62.7 ml)*(1.99 g/cm^3) = 62.7 g for water

how to tell if something is more soluble in solubility curve

Answers

Answer:

To find the least soluble substance at a given temperature we follow the temperature line up and the first substance curve we hit is the least soluble. For most soluble it is the same procedure except the last substance curve hit is the most soluble.

To determine if a substance is more soluble or less soluble based on a solubility curve, you need to compare the solubility values at different temperatures. Here's how you can interpret a solubility curve:

1. Higher Points on the Curve: If a point on the curve is higher, it indicates that the substance is more soluble at that temperature. In other words, at higher temperatures, the substance can dissolve in a greater amount.

2. Lower Points on the Curve: If a point on the curve is lower, it means that the substance is less soluble at that temperature. In this case, at lower temperatures, the substance can dissolve in a smaller amount.

3. Comparing Points: By comparing the solubility values at different temperatures, you can determine which temperature has a higher solubility and which has a lower solubility. The steeper the slope of the curve, the faster the increase or decrease in solubility with temperature.

Solubility curves provide a graphical representation of the relationship between temperature and solubility. They allow you to determine the solubility characteristics of a substance and how it changes with temperature.

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How do I find the pH of two different solutions if they have the same number of moles?

Answers

Answer:

You can use a PH tester do identify the PH of each solution.  Depending on what solutions ur testing, u shouldn't mix them as for there could be either a minor or bad chemical reaction

Explanation:

Consider the following half-reaction balanced for an acidic solution: 2H2O + SeO2 → SeO42- + 4H+ + 2e-. What is the balanced half-reaction for a basic solution?

Answers

Answer

\(SeO_2+4OH^-\rightarrow SeO^{2-}_4+2H_2O+2e^-\)

Explanation

The given balanced half-reaction for an acidic solution:

\(2H_2O+SeO_2\rightarrow SeO^{2-}_4+4H^++2e^-\)

What to find:

Tha balanced half-reaction for a basic solution.

Step-by-step-solution:

To balance the half-reaction for a basic solution;

1. Add OH⁻ ions to BOTH SIDES to neutralize any H⁺

\(2H_2O+SeO_2+4OH^-\rightarrow SeO^{2-}_4+4H^++4OH^-+2e^-\)

2. Combine H+ and OH- to make H2O.

\(2H_2O+SeO_2+4OH^-\rightarrow SeO^{2-}_4+4H_2O+2e^-\)

3. Simplify by canceling out excess H2O

\(SeO_2+4OH^-\rightarrow SeO^{2-}_4+2H_2O+2e^-\)

4. Balance the charges by adding e-

\(SeO_2+4OH^-\rightarrow SeO^{2-}_4+2H_2O+2e^-\)

watch the unit 4 part 1 lecture video and answer the following question: which of the following best describes what fire is? question 1 options: a. a mechanical reaction b. a chemical reaction c. a fission reaction d. a fusion reaction

Answers

After watching the Unit 4 Part 1 lecture video, it can be concluded that a chemical reaction best describes what fire is. The correct option is B. a chemical reaction.

Fire is a chemical reaction. It needs three components to keep going, fuel, oxygen, and heat. When the fire burns, it releases gases and by-products, including smoke, ash, and carbon dioxide. Heat and light are also produced by the reaction, and these are the components we recognize as fire.

Flames are visible because they're hot enough to excite the atoms and molecules in the air, causing them to emit light, which is visible to the human eye. Fire has been used as a tool by humans for millions of years. It was used as a light source, for warmth, cooking, and protection from predators. Hence, the correct option is B.

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[Poiseuille's Law] [S] Poiseuille's Law states that the resistance of blood flow in an artery (with units of mmHg) can be modeled as
R(L,r) = kL/r^4 where L is the length of the artery (in cm) and r is the radius of the artery (in mm), and k is a constant which depends mainly on the viscosity of the blood (among other factors).
(a) Calculate R_L (L, r) and R_r (L, r) and interpret their meaning, including units and an interpretation of the sign of the derivative.
(b) Calculate R_rr (L, r) and R_rL (L, r) and interpret their meaning, including units and an interpre- tation of the sign of the derivative.

Answers

(A) R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery.

(a) To calculate R_L (L, r), we differentiate the equation with respect to L while keeping r constant:

\(R_L(L, r) = d/dL (kL/r^4) = k/r^4\)

R_L represents the rate of change of resistance with respect to the length of the artery, L. The units of R_L are mmHg/cm. A positive value for R_L indicates that an increase in the length of the artery will result in an increase in resistance, meaning it becomes harder for blood to flow through the longer artery.

To calculate R_r (L, r), we differentiate the equation with respect to r while keeping L constant:

\(R_r(L, r) = d/dr (kL/r^4) = -4kL/r^5\)

R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) To calculate R_rr (L, r), we differentiate R_r (L, r) with respect to r while keeping L constant:

\(R_rr(L, r) = d/dr (-4kL/r^5) = 20kL/r^6\)

R_rr represents the rate of change of R_r with respect to r. The units of R_rr are mmHg/mm^2. A positive value for R_rr indicates that as the radius of the artery increases, the rate of decrease in resistance increases. In other words, the wider the artery becomes, the easier it is for blood to flow through.

To calculate R_rL (L, r), we differentiate R_r (L, r) with respect to L while keeping r constant:

\(R_rL(L, r) = d/dL (-4kL/r^5) = 0\)

R_rL represents the rate of change of R_r with respect to L. The units of R_rL are mmHg/(cm·mm). The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery. This implies that changes in the length of the artery do not affect the rate of change of resistance with respect to the radius.

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A rate constant obeys the Arrhenius equation, the factor A 2.2 x 1013 s and the activation energy being 150. kJ mol. What is the value of the rate constant at 227°C, in a. 6.7x10^-22 s^-1 b. 2.1x10^13 s^-1 c. 1.5x10^11 s^-1 d. 4.7x10^-3 s^-1

Answers

the value of the rate constant at 227°C,is option c) 1.5 x 10^11 s^-1..

The Arrhenius equation is given by k = Ae^(-Ea/RT), where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the universal gas constant, and T is the temperature in Kelvin.

Given that A = 2.2 x 10^13 s^-1, Ea = 150 kJ mol^-1, and the temperature T = 227°C + 273.15 = 500.15 K, we can calculate the value of the rate constant as

follows:k = Ae^(-Ea/RT) = (2.2 x 10^13 s^-1)e^(-150000 J mol^-1 / (8.314 J K^-1 mol^-1)(500.15 K)) = 1.5 x 10^11 s^-1Therefore, the answer is option c) 1.5 x 10^11 s^-1.

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A gas has a volume of 150 cm3. Convert this volume into mL

Answers

Answer:

The answer is

150 mL

Explanation:

To convert the volume from cm³ to mL we use the conversion

1 cm³ = 1 mL

So from the question

if 1 cm³ = 1 mL

Then 150 cm³ = 150 mL

Hope this helps you

how many electrons can the fourth energy level can accommodate? a.2 b.8 c.16 d.32​

Answers

Answer:

8

Explanation:

Line a is parallel to line b with a transversal of line c. Find m∠4 if m∠8 = 65.

Answers

115, if it is same side exterior/interior. it will be 65 if it's corresponding or alternative interior/exterior

a 1) How would you make 1 liter of a 10% NaCl solution from a solid stock? Provide details of what kind of containers you would use.

Answers

To make 1 liter of a 10% NaCl solution from a solid stock, you will require the following materials and containers.MaterialsSolid NaClDistilled water1-Liter volumetric flask250-mL volumetric flask 2-beakersProcedureTo prepare 1 liter of a 10% NaCl solution, the following procedure should be followed:Measure out 100g of NaCl using a balance.

Measure the weight of an empty 250-mL volumetric flask.Add the NaCl to a 250-mL beaker and add a small amount of distilled water to it to dissolve the NaCl.Carefully pour the dissolved NaCl solution into the 250-mL volumetric flask. Add distilled water to the mark on the flask to make up the volume. Stopper the flask and invert it several times to mix the solution.Measure the weight of the 1-Liter volumetric flask.Add the 250-mL volumetric flask solution to a 1-Liter volumetric flask.Add distilled water to the mark on the flask to make up the volume.

Stopper the flask and invert it several times to mix the solution.The final volume of the solution will be 1 liter of a 10% NaCl solution.PrecautionsEnsure the NaCl has completely dissolved before adding more water to avoid making a less concentrated solution.Measure the weight of the volumetric flask before and after adding the solution to calculate the volume of solution that was added.Use distilled water to prepare the solution.

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what is the molar mass of a substance that has a mass of 40 grams and a molar amount of 0.8 moles

Answers

Answer:

The molar mass is 0.02 g/mol

Explanation:

The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

\(M=\frac{n}{m}\)

We are given

\(m=40\) g

\(n=0.8\) mol

Substituting our values into the equation gives us

\(M=\frac{0.8}{40}\)

\(M=0.02\) g/mol

Highlight the claim.
A common type of asexual reproduction found in nature is called Mitosis. Mitosis requires less energy than sexual reproduction does. Mitosis can
occur in seconds and does not require a mate to reproduce. Sexual reproduction requires two compatible parents. It also requires time to produce
the egg and sperm cells and then for fertilization to occur. Energy is required to find a compatible mate, produce sex cells, and for fertilization
Therefore Mitosis requires less energy than sexual reproduction does.

Answers

Answer:

The claim is: Therefore Mitosis requires less energy than sexual reproduction does.

Explanation:

what is the main purpose of a salt bridge? group of answer choices to maintain solution volume to allow higher concentration solution to migrate to lower concentration solution. to maintain charge balance because the electrons are moving from one-half cell to the other to allow exchange of metal cations only

Answers

Because the electrons are switching between one side of the cell and the other, to maintain charge balance.

The correct option is C.

Which salt is used in salt bridge?

The salt bridge is frequently an upside-down glass U-shaped tube filled with table salt in empirical settings. In order to create an electrochemical cell, its two legs dip into two different electrolyte vessels (the half-cells).

What use does a salt bridge function?

The salt bridge's job is to maintain the solutions' electrical neutrality while allowing unrestricted ion passage across cells. The absence of the salt bridge will result in a buildup of both positive and negative charges surrounding the electrodes, which will stop the reaction.

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The complete question is -

What is the main purpose of a salt bridge?

A-To maintain solution volume to allow higher concentration solution

B-To migrate to lower concentration solution.

C-To maintain charge balance because the electrons are moving from one-half cell to the other.

D-To allow exchange of metal cations only

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