Describe a method of Municipal treatment of water with neat diagram?​

1) List the known and unknown quantities.

Sample: unknown.

Concentration: 1.0*10^(-4).

pH: 10.00.

Characteristic: unknown.

2) pH scale.

Weak acid: 4 - 6

Weak base: 8 - 10

Strong acid: 1 - 3

Strong base: 11 - 14

According to the more specific pH scale above, 10.00 corresponds to a weak base.

Option B.

Answer:

A banana, like most other lifeforms, is about 70% water, and all the potassium it contains already exists in the form of K+ ions dissolved in water. Which is why bananas do not explode in water, or spontaneously combust.

Using the cell size and scale Interactive, the correct order of size, left to right, from smallest to largest is tRNA > influenza virus > E. coli bacterium Hepatitis virus > hemoglobin > phospholipid. The correct option is a.

t-RNA is transfer RNA. It helps in transferring information from RNA to DNA or DNA to RNA.

t-RNA is present in viruses, so it will be smaller than the virus because they are present inside the virus. Phospholipids are chains of lipids. They are macromolecules.

Therefore, the correct option is a. tRNA > influenza virus > E. coli bacterium Hepatitis virus > hemoglobin > phospholipid.

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Answer:

Subbituminous coal can form at temperatures as low as 35 to 80 °C (95 to 176 °F) while anthracite requires a temperature of at least 180 to 245 °C (356 to 473 °F).

Sub-types: Cannel coal

Child material class: Lignite

Explanation:

1. To solve for the grams of H2 needed, we need to use the given ΔH value to calculate the amount of moles of N2 that reacted. From the balanced chemical equation, we know that for every 3 moles of H2 that reacts, 1 mole of N2 reacts. Therefore, we can use the mole ratio to convert the moles of N2 to moles of H2 and then use the molar mass of H2 to convert to grams.

First, we need to calculate the moles of N2 that reacted to produce 150.9kJ of heat:
ΔH = -92.40 kJ/mol N2
150.9 kJ = (1 mol N2 / -92.40 kJ) x (-150.9 kJ)
mol N2 = 1.63 mol

Using the mole ratio from the balanced chemical equation:

1 mol N2 : 3 mol H2

We can calculate the moles of H2 needed:3 mol H2 = 1 mol N2

3 mol H2 = 1.63 mol N2
mol H2 = 0.543 mol

Finally, we can convert moles of H2 to grams:

mol H2 = 0.543 mol
molar mass of H2 = 2.02 g/mol
grams of H2 = (0.543 mol) x (2.02 g/mol)
grams of H2 = 1.10 g

Therefore, 1.10 grams of H2 are needed to involve 150.9kJ of heat.

2. To solve for the moles of NH3 produced, we can use the same mole ratio from the balanced chemical equation:

1 mol N2 : 2 mol NH3

From the moles of N2 that reacted calculated in part 1, we can calculate the moles of NH3 produced:
1 mol N2 = 2 mol NH3
1 mol N2 = 1.63 mol N2
mol NH3 = (2 mol NH3 / 1 mol N2) x (1.63 mol N2)
mol NH3 = 3.26 mol

Therefore, 3.26 moles of NH3 were produced in the process.

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Answer:

c

Explanation:

use %composition given to calculate emperical 4mular

The empirical formula of the compound having 57.5% Na, 40.0% O, and 2.5% H is NaOH (Option C)

Divide by their molar mass

Na = 57.5 / 23 = 2.5

O = 40 / 16 = 2.5

H = 2.5 / 1 = 2.6

Divide by the smallest

Na = 2.5 / 2.5 = 1

O = 2.5 / 2.5 = 1

H = 2.5 / 2.5 = 1

Thus, the empirical formula of the compound is NaOH

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Answer: 6.23

Explanation:

1) solve for pH  

pH=-log (H3O+) = - log 1.7 X 10^-8 =7.77

2) now do 14-pH  = 14 -7.77=6.23

Answer:

Blood fractionation is the process of fractionating whole blood, or separating it into its component parts. This is typically done by centrifuging the blood. The resulting components are: a clear solution of blood plasma in the upper phase (which can be separated into its own fractions, see Blood plasma fractionation),

Answer: Centrifugal force is used to separate the components of blood – red blood cells, platelets and plasma – from each other. ... The red blood cells precipitate to the bottom of the bag, with the platelets above them, then the white blood cells and the plasma at the very top. Also because Each part of the blood has a different function. Separating the blood into parts lets patients get only the specific part or parts of the blood that they need. So a whole blood donation can be used for several patients.

Hope this helps have a awesome day/nigh❤️✨t

Explanation:

Answer:

it was pillars

Explanation:

i guessed and it was right LOL

Answer:

O pillars

Explanation:

Right on EDGE 2021

Answer:

ΔT  = 98.84 °C

Explanation:

Given data:

Heat absorbed = 255 J

Mass of gold = 20.0 g

Specific heat capacity of gold = 0.129 J/g.°C

Temperature change = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values,

255 J = 20.0 g × 0.129 J/g.°C × ΔT

255 J  = 2.58 J / °C × ΔT

ΔT  = 255 J  / 2.58 J / °C

ΔT  = 98.84 °C

Answer:

One atom of that element like helium neon and other Noble gases

Explanation:

Answer:

Explanation:

The number of protons in the nucleus of an atom determines an element's atomic number. In other words, each element has a unique number that identifies how many protons are in one atom of that element. An example is all hydrogen atoms, and only hydrogen atoms, contain one proton and have an atomic number of 1.

The equation for the synthesis of ammonia is:

N₂ + 3 H₂ ---> 2 NH₃

We have to find the number of moles of H₂ needed to produce 6 mol of NH₃. To do that we will use the equation that we were given.

We can read the equation of the reaction as a recipe. When 1 mol of N₂ reacts with 3 moles of H₂, 2 moles of NH₃ are produced. So the relationship between H₂ and NH₃ is that 3 moles of H₂ are needed to produce 2 moles of NH₃. We wiill use that relationship to solve the problem.

6 moles of NH₃ * 3 moles of H₂/(2 moles of NH₃) = 9 moles of H₂

Answer: D) 9 moles of H₂ are needed.

Answer:

Hence, there are approximately $1.686\times {{10}^{22}}$ molecules in 2.3 grams of $N{{H}_{4}}S{{O}_{2}}$.

Explanation:

1. K (Potassium)

2. Te (Tellurium)

3. F (Flourine)

4. group 11, period 4

5. group 18, period 4

6. group 12, period 6

7. Cl

8. Pb

9. W

10. Sb

11. Na

12. period 6, group 11

13. period 5, group 11

14. period 2, group 16

15. Groups 13–16 of the periodic table contain one or more metalloids

16. Hydrogen

17. Helium

18. Calcium

19. Cobalt

20. Carbon

1. K (Potassium)metal is found in the group 1 and period 4.

2. Te (Tellurium) metalloid is found in the group 16 and period 5.

3. F (Flourine)nonmetal is found in the group 17 and period 2.

4. Group 11, period 4 group will you find copper.

5. Group 18, period 4 group will you find krypton.

6. Group 12, period 6 group will you find mercury.

7. Cl is the symbol for chlorine.

8. Pb the symbol for lead.

9. W the symbol for tungsten.

10. Sb is the symbol for antimony.

11. Na is the symbol for sodium.

12. Period 6, group 11 period will you find gold.

13. Period 5, group 11 period will you find silver.

14. Period 2, group 16  of the periodic table contain one or more metalloids.

15. Groups 13–16 groups will you find metalloids.

16. Hydrogen element has the symbol H.

17. Helium element has the symbol He.

18. Calcium element has the symbol Ca.

19. Cobalt element has the symbol Co.

20. Carbon element has the symbol C.

In chemistry mixture is a combination of two or more different chemical elements which are not chemically bond. A mixture is the physical combination of two or more elements in which their individual identities are retained and it also mixed by solutions, suspension and colloids.

In chemistry compound is combination of two or more different elements which are chemically bond. So compound is held by chemical bond. A compound can't be separate by physical separation and after the mixture you can't identified that it is compound or not.

Therefore, 1. K (Potassium)metal is found in the group 1 and period 4.

2. Te (Tellurium) metalloid is found in the group 16 and period 5.

3. F (Flourine)nonmetal is found in the group 17 and period 2.

4. Group 11, period 4 group will you find copper.

5. Group 18, period 4 group will you find krypton.

6. Group 12, period 6 group will you find mercury.

7. Cl is the symbol for chlorine.

8. Pb the symbol for lead.

9. W the symbol for tungsten.

10. Sb is the symbol for antimony.

11. Na is the symbol for sodium.

12. Period 6, group 11 period will you find gold.

13. Period 5, group 11 period will you find silver.

14. Period 2, group 16  of the periodic table contain one or more metalloids.

15. Groups 13–16 groups will you find metalloids.

16. Hydrogen element has the symbol H.

17. Helium element has the symbol He.

18. Calcium element has the symbol Ca.

19. Cobalt element has the symbol Co.

20. Carbon element has the symbol C.

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The correct answer is C: 0.86, 2.68, 110. The Global Warming Potential (GWP) is a measure of how much a given mass of a greenhouse gas contributes to global warming, relative to the same mass of carbon dioxide (CO₂).

The GWP takes into account the radiative forcing of each greenhouse gas and its atmospheric lifetime.

For a time horizon of 20 years, the GWP values are:

Methane: 86

Nitrous oxide: 268

CFC-12: 11,000

These values indicate that, over a 20-year period, methane is 86 times more potent as a greenhouse gas than CO₂, nitrous oxide is 268 times more potent, and CFC-12 is 11,000 times more potent.

To convert the GWP values to CO₂ equivalents, we multiply each value by the GWP of CO₂ (which is defined as 1). Therefore, the CO₂ equivalents for methane, nitrous oxide, and CFC-12 are:

Methane: 0.86 CO₂ equivalents

Nitrous oxide: 2.68 CO₂ equivalents

CFC-12: 110 CO₂ equivalents

Therefore, the correct answer is C: 0.86, 2.68, 110, as it lists the CO₂ equivalents in order for methane, nitrous oxide, and CFC-12, respectively.

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Answer:

2 nitrogen molecules are present

1 oxygen molecule is present

1 n2o molecules are present

A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option  C, E

The two correct answers that are made from renewable resources are:

C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.

E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.

The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:

A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.

B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.

D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.

Option C and E.

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About two electrons can have that quantum number.

Mg has the highest IE2 while Al has the highest IE3

The order of increasing atomic radius is; Cl> Te^2- >Te > S

Quantum numbers are a set of four parameters that are used to describe the state of an electron in an atom. They describe the energy, orbital shape, orientation, and spin of an electron in an atom. The four quantum numbers are:

Principal quantum number (n): This quantum number describes the energy level of an electron in an atom. It can take on any positive integer value, with higher values indicating higher energy levels. The principal quantum number determines the size of the electron's orbital.

Azimuthal quantum number (l): This quantum number describes the shape of the electron's orbital. It can take on values from 0 to (n-1).

Magnetic quantum number (m): This quantum number describes the orientation of the electron's orbital in space. It can take on values from -l to +l.

Spin quantum number (s): This quantum number describes the intrinsic angular momentum, or "spin," of the electron. It can have a value of +1/2 or -1/2, indicating the direction of the electron's spin.

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Answer:

15.4 g

Explanation:

The reaction that takes place is:

First we convert 5 grams of C₅H₁₀ into moles, using its molar mass:

Then we convert C₅H₁₀ moles into CO₂ moles, using the stoichiometric coefficients of the reaction:

Finally we convert 0.35 moles of CO₂ into grams:

Answer: 7.07 grams

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}\)    

\(\text{Moles of} zinc=\frac{21g}{65g/mol}=0.32moles\)

\(\text{Moles of} CuCl_2=\frac{7g}{134g/mol}=0.052moles\)

\(Zn+CuCl_2\rightarrow Cu+ZnCl_2\)

According to stoichiometry :

1 mole of \(CuCl_2\) require 1 mole of \(Zn\)

Thus 0.052 moles of \(CuCl_2\) will require=\(\frac{1}{1}\times 0.052=0.052moles\)  of \(Zn\)

Thus \(CuCl_2\) is the limiting reagent as it limits the formation of product and \(Zn\) is the excess reagent.

As 1 mole of \(CuCl_2\) give = 1 mole of \(ZnCl_2\)

Thus 0.052 moles of \(CuCl_2\) give =\(\frac{1}{1}\times 0.052=0.052moles\)  of \(ZnCl_2\)

Mass of \(ZnCl_2=moles\times {\text {Molar mass}}=0.052moles\times 136g/mol=7.07g\)

Thus 7.07 g of \(ZnCl_2\) will be produced from the given masses of both reactants.

4.41 × 10⁻⁴⁵m is the wavelength of the photon and the energy correspond to red color.

The term wavelength is defined as the distance between two identical points that are adjacent crests and troughs.

The SI unit of wavelength is metre mostly represented as m.

The wavelength is mostly represented by λ is the Greek letter lambda.

Given:

E =  4.50x10⁻¹⁹ J/photon

h = Planck constant = 6.626 × 10⁻³⁴

ν = ?

E = hν

ν = E/h

By substituting the values in above question and we get,

= 4.50x10^-19 /  6.626 × 10⁻³⁴

=  0.679 × 10⁻¹⁵

c = 3 × 10⁸

E = hc/λ

λ = hc/E

By substituting the values in above question and we get,

λ = 6.626 × 10⁻³⁴ ×  3 × 10⁸ / 4.50x10⁻¹⁹

λ = 4.41 × 10⁻⁴⁵m

Thus, the wavelength of the photon is 4.41 × 10⁻⁴⁵m and color does this energy correspond to red.

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The Sun-Earth-Moon system is important because it sustains life on Earth, regulates Earth's climate, and influences natural phenomena like tides.

The Sun-Earth-Moon system plays a vital role in supporting and sustaining life on Earth. The Sun is the primary source of energy for our planet, providing heat and light necessary for photosynthesis, the process by which plants convert sunlight into food and oxygen. Sunlight is also crucial for maintaining Earth's temperature and driving weather patterns.

The Moon, as Earth's only natural satellite, contributes to several essential functions. Its gravitational pull creates the tides, which influence coastal ecosystems and shape coastal landscapes.

The Moon's orbit also stabilizes Earth's axial tilt, providing a stable climate for life to thrive. Additionally, the Moon's phases have cultural and historical significance, influencing human activities such as agriculture, navigation, and calendar systems.

The Sun-Earth-Moon system's interactions are responsible for natural phenomena like eclipses, both solar and lunar, which have fascinated humans throughout history and continue to be important for scientific study and exploration.

Understanding these celestial events enhances our knowledge of astrophysics and helps us comprehend the vastness and complexity of the universe.

Furthermore, the study of the Sun-Earth-Moon system provides insights into celestial mechanics, orbital dynamics, and the broader field of planetary science. By examining the interplay between these celestial bodies, scientists can gain a deeper understanding of Earth's place in the universe and explore potential habitable conditions on other celestial bodies.

Overall, the Sun-Earth-Moon system is of immense importance as it sustains life, regulates climate, influences natural phenomena, and provides a platform for scientific exploration and discovery.

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There are approximately 0.00493 moles of N in 0.217 g of N2O.

To determine the number of moles of N in 0.217 g of N2O, we need to convert the mass of N2O to moles using the molar mass of N2O, which is 44.0128 g/mol. We can use the formula:

moles = mass / molar mass

So, moles of N = 0.217 g / 44.0128 g/mol = 0.00493 mol. Therefore, there are approximately 0.00493 moles of N in 0.217 g of N2O.

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Answer:

Option A. LR = N2O4, 45.7g N2 formed

Explanation:

The balanced equation for the reaction is given below:

N2O4(l) + 2N2H4(l) → 3N2(g) + 4H2O(g)

Next, we shall determine the masses of N2O4 and N2H4 that reacted and mass of N2 produced from the balanced equation. This is illustrated below:

Molar mass of N2O4 = 92.02 g/mol

Mass of N2O4 from the balanced equation = 1 x 92.02 = 92.02 g

Molar mass of N2H4 = 32.05 g/mol

Mass of N2H4 from the balanced equation = 2 x 32.05 = 64.1g

Molar mass of N2 = 2x14.01 = 28.02g/mol

Mass of N2 from the balanced equation = 3 x 28.02 = 84.06g

Summary:

From the balanced equation above,

92.02g of N2O4 reacted with 64.1g of N2H4 to produce 84.06g of N2.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

92.02g of N2O4 reacted with 64.1g of N2H4.

Therefore, 50g of N2O4 will react with = (50 x 64.1)/92.02 = 34.83g of N2H4.

From the calculations made above, we can see that only 34.83g out 45g of N2H4 is required to react completely with 50g of N2O4.

Therefore, N2O4 is the limiting reactant and N2H4 is the excess reactant.

Finally, we shall determine the mass of N2 produced from the reaction.

In this case the limiting reactant will be used as it will produce the maximum yield of N2 since all of it is used up in the reaction.

The limiting reactant is N2O4 and the mass N2 produced can be obtained as illustrated below:

From the balanced equation above,

92.02g of N2O4 reacted to produce 84.06g of N2.

Therefore 50g of N2O4 will react to produce = (50 x 84.06)/92.02 = 45.7g of N2.

Therefore, 45.7g of N2 were produced from the reaction.

At the end of the day,

The limiting reactant is N2O4 and 45.7g of N2 were produced from the reaction.

Answer:

a because the x and y value is the same

Answer:

It sounds fine, but it may be a bit too long. It's difficult to shorten things like this, but getting more straight to the point would give it that "catchy" feel.

Explanation: