Define critical inductance for an L-section filter. ​

Answer:

2min

Explanation:

i think it will be clear from photo

Answer: The formula for current is charge/time

so here we have to change subject so we are asked to look for time  

Explanation: so it would be T=Q/I

T=4/2

T=2s

hope this helpss

Answer:

an insurance contract;   transfer risk

Explanation:

Answer:

The distance travelled in the next 5 seconds is 20 m.

Explanation:

The distance travelled is given by the formula,

\(s=ut+\frac{1}{2} at^{2}\)

Where,

u is the initial velocity in m/s

t is the time in s

a is the acceleration in \(m/s^{2}\)

As per the given data,

u= 9 m/s

t= 5 s

a= -2 \(m/s^{2}\) (The negative sign indicates the deceleration)

Substituting the values,

\(s=(9) * (5) +\frac{1}{2} (-2) (5)^{2}\)

=45-25

=20

So, a runner travels 20 m in the next 5 seconds.

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Answer: Mendeleev arranged the elements in his periodic table in order of increasing atomic mass. In the modern periodic table, elements are arranged in order of increasing atomic number

Answer:

625000 J

Explanation:

KE = mv^2/2

= (2000kg*(25m/s^2))/2

= 625000 J

Answer:

E.  All of the Above

Explanation:

By doing any kind of exercise or physical activity, you are increasing your overall health.  Your muscle strengthen because of the jumping and movement of arms.  You are more alert because you have to time each jump right in order to keep going.  By breathing evenly while jumping, you do help your Cardiorespiratory fitness as well.  And of course, you increase your athletic ablility over all with much endurance and practice.

a) The momentum of trolley A before the collision is (2 kg) * (5 m/s) = 10 kg*m/s.

b) The momentum of trolley A after the collision is (2 kg) * (2 m/s) = 4 kg*m/s.

c) The kinetic energy of trolley A before the collision is 1/2 * (2 kg) * (5 m/s)^2 = 25 J.

d) The kinetic energy of trolley A after the collision is 1/2 * (2 kg) * (2 m/s)^2 = 2 J. And the kinetic energy of trolley B after the collision is 1/2 * (3 kg) * (2 m/s)^2 = 3 J.

e) The amount of kinetic energy that is unaccounted for is the difference between the initial kinetic energy of trolley A and the final kinetic energy of trolley A and trolley B. This is 25J - (2J + 3J) = 20 J.

It's important to note that the total momentum of the system is conserved during the collision, meaning that the momentum of trolley A before the collision is equal to the total momentum of trolley A and B after the collision. Also the total kinetic energy of the system is not conserved during the collision as some of the energy is transferred to internal energy of the system and other forms of energy.

The distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.

We can use the equations of motion to solve this problem. The acceleration of the body down the inclined plane can be found using trigonometry:

a = gsin(30°) = (9.8 m/s²)(1/2) = 4.9 m/s²

where g is the acceleration due to gravity.

Using the equation of motion:

s = ut + (1/2)at²

where s is the distance covered, u is the initial velocity (which is zero in this case), and t is the time taken, we can find the distance covered after 15 seconds:

s = (1/2)4.9(15)² = 1102.5 meters

Therefore, the distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.

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Answer:

1450.4 KN\(m^{2}\)

Explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

                        = 800 x 5 x 9.8

                        = 39200

Pressure of oil = 39200 N\(m^{2}\)

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

                                      = 1000 x 8 x 9.8

                                     = 78400

Pressure of water = 78400 N\(m^{2}\)

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

                      = 13600 x 10 x 9.8

                      = 1332800

Pressure of mercury = 1332800 N\(m^{2}\)

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

                                               = 1450400

                                               = 1450.4 KN\(m^{2}\)

Total pressure exerted by the liquids at the base is 1450.4 KN\(m^{2}\).

Explanation:

a.)

Reactants : CO2 (carbondioxide) + H2O (water)

Products : O2 (oxygen) + C6H12O6 (glucose)

b.)

Reactants: Na ( Solid Hydrogen) + H2O (water)

Products: H2 (hydrogen gas) + NaOH (sodium hydroxide)

Baring pneumothorax, this pressure is always lower than atmospheric pressure (that is, negative pressure) is called intrapleural pressure.

Intrapleural pressure refers to the pressure within the pleural cavity, which is the space between the lungs and the chest wall. Under normal conditions, the intrapleural pressure is maintained at a level lower than atmospheric pressure. This negative pressure is crucial for maintaining lung inflation and facilitating the process of breathing.

The negative intrapleural pressure is generated by the opposing forces acting on the lungs and chest wall. The elastic recoil of the lungs tends to collapse them inward, while the elastic recoil of the chest wall tends to expand it outward. These opposing forces create a negative pressure in the pleural cavity, which keeps the lungs expanded and allows for efficient gas exchange during respiration.

The negative intrapleural pressure is essential for maintaining the integrity of the lungs and promoting their optimal function. However, in the case of pneumothorax, air enters the pleural cavity, equalizing the pressure with atmospheric pressure and leading to a loss of the negative pressure. This can result in lung collapse and difficulty in breathing.

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a) Buoyant force acting on the balloon is 1429.68 N ; b)Net force on the balloon is 1282.53 N.

An upward force exerted by a fluid that opposes the weight of a partially or fully immersed object is called buoyant force.

Given, radius of balloon, r is 3 m ; Mass of balloon with instruments, m = 15 kg ; Acceleration due to gravity, g = 9.81 m/s² and Density of air, ρ  is 1.29 kg/m3

a) Volume of balloon is ;

V= 4/3 π r³

= 4/3 π (3)³

= 113.09 m³

Buoyant force , F = ρ v g

= 1.29 * 113.09 * 9.8

So, F = 1429.68 N

Buoyant force acting on balloon is 1429.68 N

b) Net force acting on the balloon is ;

Fn = F -W

=  1429.68  - ( 15 * 9.81)

= 1429.68  - 147.15

So, Fn = 1282.53 N

Net force on the balloon is 1282.53 N.

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A force of approximately 15,000 N must be applied to the small piston in order to raise a car of mass 1500 kg using a hydraulic lift with a large piston having a radius of 250 cm^2 and a small piston with a radius of 25 cm^2.

A hydraulic lift is a simple machine that uses the principles of Pascal's law to multiply force. According to Pascal's law, pressure applied to a confined fluid is transmitted undiminished to every part of the fluid and to the walls of the container.

In a hydraulic lift, two pistons of different sizes are connected by a tube filled with an incompressible fluid such as oil. When a force is applied to the small piston, it creates a pressure that is transmitted undiminished to every part of the fluid, including the larger piston. The larger piston then exerts a force that is proportional to its area, and this force is applied to the object being lifted.

To calculate the force required to lift a car of mass 1500 kg using a hydraulic lift, we can use the equation: F1/A1 = F2/A2

where F1 is the force applied to the small piston, A1 is the area of the small piston, F2 is the force exerted by the larger piston, and A2 is the area of the larger piston.

In this case, we know that the large piston has a radius of 250 cm^2 and the small piston has a radius of 25 cm^2. Therefore: A2 = πr2

= π(250)^2 = 196,350 cm^2

A1 = πr2

= π(25)^2 = 1,963.5 cm^2

We can rearrange the equation to solve for the force required: F1 = (F2 × A1)/A2

To find F2, we need to find the weight of the car: w = mg

where w is the weight, m is the mass in kg, and g is the acceleration due to gravity (9.81 m/s^2).

w = 1500 kg × 9.81 m/s^2

= 14,715 N (approximately)

F2 is equal to the weight of the car, so:

F2 = 14,715 N

Now we can substitute the values into the equation to find F1: F1 = (F2 × A1)/A2

F1 = (14,715 N × 1,963.5 cm^2)/196,350 cm^2

F1 = 147,150 cmN

Converting to newtons: F1 = 1,471.5 N

Therefore, a force of approximately 15,000 N (rounded to the nearest thousand) must be applied to the small piston in order to raise a car of mass 1500 kg using a hydraulic lift with a large piston having a radius of 250 cm^2 and a small piston with a radius of 25 cm^2.

In conclusion, a hydraulic lift can be used to multiply force by transmitting pressure through a confined fluid. The force applied to the small piston is translated to a larger force at the large piston proportional to its area. If we know the radius of each piston and the mass of the object being lifted, we can calculate the force required. For this example, we can apply this theory to find the force required to lift a car with a mass of 1500 kg using a hydraulic lift with specifically sized pistons, and we find that force to be approximately 15,000 N.

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The average velocity of a man who runs forward at 8 m/s for 9 s and back again at 5 m/s for 3 s after an 8 s break is 7.25 m/s.

The average velocity of the man in this scenario can be found by dividing the total distance traveled by the total time spent moving.

The total distance traveled while running forward is 8 m/s * 9 s = 72 m, and the total distance traveled while running back is 5 m/s * 3 s = 15 m.

The total distance traveled is 72 m + 15 m = 87 m. The total time spent moving is 9 s + 3 s = 12 s.

Therefore, the average velocity is 87 m / 12 s = 7.25 m/s.

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No, not all waves move through various materials at the same pace. The characteristics of the medium itself, the kind of wave, and the frequency of the wave are only a few of the variables.

that affect how quickly a wave moves through a given medium. Sound waves, for instance, go through various materials at varying rates, depending on the density and elasticity of the medium. In general, solids transmit sound more quickly than liquids or gases do. Similar to how sound waves go through various materials at various rates, depending on the refractive index of the medium. Light waves, for example, constantly travel in a vacuum at a constant speed of around 299,792,458 meters per second (or about 186,282 miles per second). Nevertheless, as they go on.

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The decay of uranium isotopes is used to provide information about the age of earth.

The centripetal acceleration at the point 0.05m from the center of the CD is 72m/s².

The centripetal acceleration of a circular motion is given by,

a = v²/r

Where,

v is the linear velocity,

r is the distance of the particle from the center of the circle,

a is the centripetal acceleration.

The linear velocity is same for each and every particle.

So,

v = √(ar)

If the acceleration at 0.03m is 120m/s², then the acceleration at 0.050m is,

√(120x0.03) = √(a0.05)

a = 72m/s².

So, the acceleration at a distance of 0.050m is 72m/s².

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Mechanical energy can be described as a sum of kinetic and potential energy in an object that is used to do work

In the field of physics, we can describe mechanical energy that is either stored in an object at the time of rest or the energy of an object that is in a particular motion. As kinetic energy is the motion or movement energy and potential energy is the stored energy at rest, hence mechanical energy is the sum of both these energies.

In other words, we can also describe mechanical energy as an energy that is contained in a particular object that allows it to perform a specific work. It depends on the mechanical energy of an object to determine the amount of work it can do.

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Answer:

mechanical energy or A

Explanation:

Hope this helps

Answer:

the wind speed is 39 right now

The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979

To find the magnification of the image, we need to use the formula:

magnification = -v/u,

where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979  (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.

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Answer:

  85.2 N

Explanation:

You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.

Your weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...

  W = k(M/r²) = 710 N

  W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N

Your weight would be 82.5 N.

Answer:

5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps

Explanation:

The plane flies at speed of 160m/s should drop the package when it reaches at a distance of 824m.

A dropped object travels quickly in the direction of the earth's center. Newton's second law states that the net force applied on an object determines its acceleration. If air resistance is small, the gravitational force, which is also known as an object's weight (w), acts as the net force on any falling object.

Free-fall acceleration seems to be another name for gravitational acceleration. Gravitational fields established by masses pull other masses approach them.

\(h = ut + 1/2 gt^2 ; u=0130 = 1/2 \times 9.8 \times t^2t= 5.15sec\)

The packet travel with the time period of 5.15sec

The distance = v x t

                      160m/s x 5.15s = 824m

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Answer:

The fireworks give off heat.

Explanation:

It is true that the blades in a blender rotate at a rate of 6600 rpm. When the motor is turned off during operation, the blades slow to rest in 4.2 s.

As we know that blades are moving at speed of 6200 rpm

so here we can say that

f =  6600 rpm = 6600/ 60 rev/s

f = 110 rev/s

The angular speed is given by

ω  = \(2\pi\)f

ω = \(2\pi *110 =691.4285\)

now it comes to rest after t = 4.2 s

so angular acceleration is given as

\(\alpha\) = Change in angular acceleration / Change in Time

\(\alpha =\) 0 - 691.4285 / 4.2 = - 164.625 \(rad/s^{2}\)

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To calculate the phase angle in a solenoid circuit with resistance (R), source voltage (V), and inductance (L), you can use the concept of impedance and the formulas related to the phase angle in an RL circuit. The phase angle represents the phase difference between the current and voltage in the circuit.

1. Calculate the inductive reactance (XL):

The inductive reactance represents the opposition to the change in current caused by the inductance. It is calculated using the formula:

XL = 2πfL

where f is the frequency of the AC source and L is the inductance of the solenoid.

2. Calculate the total impedance (Z):

The total impedance of the circuit, Z, is the combined effect of resistance and reactance. It is calculated using the formula:

Z = √(R^2 + XL^2)

3. Calculate the phase angle (θ):

The phase angle can be determined using the following formula:

θ = arctan(XL/R)

Note: The phase angle is usually expressed in radians, but it can also be converted to degrees if needed.

By following these steps, you can calculate the phase angle in a solenoid circuit with resistance, source voltage, and inductance.

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A force of μk⋅60N is needed to keep a 60-newton rubber block moving across level, dry asphalt in a straight line at a constant speed.

Radially inward is the direction of the gum when the fan reaches its top speed.

Centripetal acceleration is the type of acceleration that acts on the object with its direction towards the midpoint of the circular motion that the object is revolving in like in the case of the fan with the gum.

It should be kept in mind that centripetal acceleration acts on the body when it is in a constant circular motion albeit the direction changes periodically with the object always acting radially inward.

The centripetal acceleration is given by the formula

= v² / r

Here v = velocity of moving object

r = distance from midpoint/centre of the circular path

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Answer:

9.8

Explanation:

distance=vt

1.40*7=distance

Answer: b the masses will hang higher

Explanation:

F=kx

increasing the spring constant/stiffness means stretch distance is decreased, which causes it to hang higher