D Question 5 Calculate the following error formulas for confidence intervals. (.43)(.57) (a) E= 2.03√ 432 (b) E= 1.28 4.36 √42 (a) [Choose ] [Choose ] [Choose ] [Choose ] (b) 4 4 (

a). The number of ways which the company can choose 4 workers from the list of employees is; 2,730 ways.

b). The number of ways the company can choose the workers if 2 labourers and 3 joiners are on holiday is; 700 ways.

It follows from the task content that the number of ways the company can choose 4 workers in each scenario be determined.

a). Since there are 3 labourers, 13 joiners, 10 electricians, and 7 plumbers.

The number of possible ways to choose 4 workers is; ³C₁ × ¹³C₁ × ¹⁰C₁ × ⁷C₁

= 3 × 13 × 10 × 7

= 2,730 ways.

b). Also, when 2 labourers and 3 joiners are absent, it follows that the selection space is now; 1 labourer, 10 joiners, 10 electricians and 7 plumbers.

The number of possible ways is therefore; ¹C₁ × ¹⁰C₁ × ¹⁰C₁ × ⁷C₁

= 1 × 10 × 10 × 7

= 700 ways.

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Therefore, the expression \(t^{(-3/4)}\) in rational form is:

\(B. 1/^4 \sqrt {t^3}\)

What is the exponential function?

An exponential function is a mathematical function of the form:

f(x) = aˣ

where "a" is a constant called the base, and "x" is a variable. Exponential functions can be defined for any base "a", but the most common base is the mathematical constant "e" (approximately 2.71828), known as the natural exponential function.

To write the expression \(t^{(-3/4)}\) in rational form, we need to eliminate the negative exponent.

Recall that a negative exponent can be rewritten as the reciprocal of the positive exponent. In this case,  \(t^{(-3/4)}\) can be written as 1/ \(t^{(-3/4)}\).

Therefore, the expression \(t^{(-3/4)}\)in rational form is:

\(B. 1/^4 \sqrt {t^3}\)

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Therefore , the solution of the given problem of circle comes out to be  ratio of the areas of the smaller and bigger circles is r1: r2.

When observed from this fresh vantage point and a certain distance distant, each airplane part forms a circle. (center). Surfaces and undulating zones that are different from one another make up its structure. Moreover, it revolves equally within the centre in every direction. Every extreme extent is equidistant from the "centre" in any type of circular or constrained double sphere.

Here,

The general connection between the areas of two circles can be established.

The equation A = r2, where r is the circular's radius, determines the area of a circle.

The areas of two circles whose diameters are r1 and r2, r1 being smaller than r2, are as follows:

=> A1 = πr1²

=> A2 = πr2²

We can divide A1 by A2 to get the ratio of the smaller circle's area to the bigger circle's area:

=> A1 / A2 = (πr1²) / (πr2²)

=> r1² / r2²

The ratio of the areas of the smaller and bigger circles is therefore r1: r2. Note that this has been completely reduced.

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The IQR is a more appropriate measure of variability is 60 - 10.5 = 49.5.

The interquartile range (IQR) is a measure of variability that represents the range of the middle 50% of a dataset, calculated as the difference between the third and first quartiles.

According to the given information :

The most appropriate measure of variability to use for the given data is the IQR (Interquartile Range) of 13. The IQR is the range of the middle 50% of the data and is calculated as the difference between the third quartile (Q₃) and the first quartile (Q₁). In this case, Q₁ is the median of the lower half of the data, which is (5 + 5 + 6 + 8 + 10 + 15)/2 = 21/2 = 10.5, and Q₃ is the median of the upper half of the data, which is (20 + 20 + 20 + 20 + 20 + 20)/2 = 120/2 = 60. Thus, the IQR is 60 - 10.5 = 49.5.

The reason the IQR is a more appropriate measure of variability than the range is that the range is sensitive to extreme values, which can distort the picture of the typical spread of the data. In this case, there are several values of 20 that are much higher than the other values, and including them in the calculation of the range would make it appear that the data is more spread out than it actually is. The IQR, on the other hand, is less sensitive to extreme values and is a better representation of the typical spread of the data.

Using the IQR of 13, the charity can better understand the typical range of donations they receive and make informed decisions about their fundraising efforts. For example, if they find that the typical range of donations is between $10.50 and $60, they may want to consider targeting donors who can give larger donations to increase the overall amount of donations they receive. Additionally, they could use this information to set fundraising goals and measure their progress towards achieving them.

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Answer:

Step-by-step explanation:

I've attached a pic, I used y for sin(theta) and x for cos(theta). Shows all steps. See image.

Step 1: use "factoring sum of cubes" to factor the numerator.

Step 2: in the trinomial, in the numerator, rearrange terms to use the sin^2 + cos^2 = 1 .

Step 3: cancel that factor with the denominator.

Answer:

\(\frac{19}{14}x + \frac{97}{56}\)

Step-by-step explanation:

I've written my working in the picture. I hope it's clear. :,)

I've expanded the brackets, simplied the fractions before simplifying them again, having found the common denominators of the constants and x terms.

The correct answer is c. Line graphs show the change in one or more variables progressively across time.

Histograms show the distribution of data, pie charts show the proportions of a whole, bar charts compare categories or groups, and diagrams show the relationships between different elements.

The correct answer is c. Line graphs show the change in one or more variables progressively across time

A histogram is a visual depiction of data distribution in statistics. The histogram is shown as a collection of neighbouring rectangles, where each bar represents a certain type of data. Numerous fields use statistics, which is a branch of mathematics. Frequency, which can be expressed as a table and is known as a frequency distribution, is the repeating of numbers in statistical data.

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Line graphs show the change in one or more variables progressively across time. C

A line graph is a type of chart that displays data as a series of data points connected by straight lines.

The horizontal axis of the graph typically represents time, while the vertical axis represents the value of the variable being measured.

By connecting the data points with lines, a line graph can show the trend or pattern of change in the variable over time.

Line graphs are commonly used in fields such as economics, finance, and science to visualize trends in data over time.

They can be used to identify patterns, compare different variables, or forecast future trends.

In contrast, histograms, pie charts, bar charts, and diagrams are different types of charts that are used to display data in different ways.

Histograms are used to show the distribution of data within a single variable, while pie charts and bar charts are used to compare different categories or groups of data.

Diagrams are used to represent complex systems or relationships, often using visual symbols or icons to represent different components.

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The statement that is true about J and K is that the expected values of J and K will be equal, and the variability of J will be greater than the variability of K. (Option E)

The sample size of J is 40 and sample size of K is 100. According to the central limit theorem if there is a population with mean μ and standard deviation σ and sufficiently large random samples is taken from the population with replacement, then the distribution of the sample means will be approximately normally distributed. Based on the theorem, both J and K will have the same expected value or mean.

As the standard deviation is inversely proportional to the same size, as the sample size increases, the standard deviation and related variability decreases. Hence, the variability of J will be greater than variability of K.

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Answer:

The unit rate is 6.5mph or 6.5 miles per hour.

Step-by-step explanation:

22.75/3.5 = 6.5

The mean and median on a density curve may be very close or even the same, especially for symmetric distributions.

For skewed distributions, the mean and median may be quite different.

On a density curve, the mean and median can be marked as follows:

Mean:

The mean of a density curve represents the average value of the data.

It is also known as the expected value.

The mean is the point at which the density curve would balance if it were made of a solid material.

To mark the mean on a density curve, locate the point where the curve is cut in half by its own weight.

This point is the mean of the distribution.

It can be represented by a vertical line drawn through this point on the x-axis.

Median:

The median of a density curve is the point that divides the area under the curve in half.

It is the point that separates the lower 50% of the data from the upper 50%.

To mark the median on a density curve, locate the point where the curve intersects the horizontal line at the midpoint of the area under the curve.

This point is the median of the distribution.

It can be represented by a vertical line drawn through this point on the x-axis.

In general, the mean is more sensitive to outliers than the median, which makes the median a better measure of central tendency for distributions with extreme values.

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The cylindrical coordinates of (−7, 7, 7) are (√98, -π/4, 7). cylindrical coordinate (−7, 7 3 , 1) is  (14, -π/3, 1).

We must switch from rectangular to cylindrical coordinates in the provided problem. (let r ≥ 0 and 0 ≤ θ ≤ 2π.)

A)(−7, 7, 7)

Given rectangular coordinates(x, y, z) =(−7, 7, 7)

The cylindrical coordinates are (r, θ, z)

As a result, we determine each value of r and θ  separately.

r = √x²+y²

r = √(-7)²+(7)²

r = √49+49

r = √98

θ = tan⁻¹ (y/x)

θ =tan⁻¹  (7/-7)

θ =tan⁻¹  (-1)

θ = -π/4

So cylindrical coordinate = (r, θ, z) = (√98, -π/4, 7)

B) (-7,7√3,1)

Given rectangular coordinates(x, y, z) = (-1,1,1)

The cylindrical coordinates are (r, θ, z)

As a result, we determine each value of r and θ  separately.

r = √x²+y²

r = √(-7)²(7√3)²

r = √49+147

r = √196

r = 14

θ = (y/x)

θ = (7√3/-7)

θ = (-√3)

θ = -π/3

So cylindrical coordinate = (r, θ, z) = (14, -π/3, 1)

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Equivalent fractions are those that equal the same number.

We can apply two methods to find equivalent fractions:

Amplification: we multiply the numerator and the denominator by the same number.

Simplification: we divide the numerator and the denominator by the same number that divides them exactly.

To find out if two fractions are equivalent, we can transform them into a decimal number by dividing the numerator by the denominator.

The fractions two thirds and six ninths are equivalent because they are equivalent to the same decimal number:

\(\begin{gathered} \sf \boxed{ \frac{2}{3}} = 2 \div 3 = 0.666 \\ \\ \sf \boxed{\frac{6}{9}}= 6 \div 9 = 0.666\end{gathered}\)

We can also amplify the first fraction or simplify the second fraction:

\(\begin{gathered} \frac{2}{3} = \frac{2 \times 3}{3 \times 3} = \frac{6}{9} \\ \\ \sf\boxed{ \sf\frac{6}{9}} = \sf \boxed{ \sf\frac{6 \div 3}{9 \div 3} }= \sf \boxed{\frac{2}{3}} \end{gathered}\)

Answer:

Step-by-step explanation:

Ok: There are two steps.

Answer: They are both equivalent

1. Find the common multiple of both 2/3 and 6/9

The common multiple is 9, so increase 3 to the multiple!

2/3,6/9=

6/9,6/9

6/9=6/9 So The Statement is True!

2. Method 2

6/9 is not simplified. To simplify, you need to divide by a common factor.

In this case the common factor is 3.

6/9/3=

2/3=2/3

The statement is TRUE

Answer:

you will be at 61

Step-by-step explanation:

The true statement about the end behavior of f(x) is (b)

The equation of the function is given as;

f(x) = -4x^6 +6x^2-52

The leading coefficient of the above function is

Leading coefficient = -4

-4 is less than 0 i.e. negative

This means that options (a) and (c) are false

Also;

The ends of even functions face the same direction, and not opposite directions.

Hence, the true statement about the end behavior of f(x) is (b)

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Using a system of equations, x + 2y = 103 and x + y = 87, the outer ring is worth 71 points, and the bull's-eye is worth is 16 points.

A system of equations is two or more equations solved simultaneously or concurrently.

A system of equations is also referred to as simultaneous equations because the solutions to the variables can be found at the same time.

                               Katie     Jim

Large outer ring        1           1

Smaller bull's eye     2           1

Total points            103        87

Let the worth of the outer ring = x

Let the worth of the smaller bull's eye = y

Equation 1: x + 2y = 103

Equation 2: x + y = 87

Subtract Equation 2 from Equation 1:

x + 2y = 103

-

x + y = 87

Equation 3: y = 16

Substitute y = 16 in Equation 1:

x + 2(16) = 103

x + 32 = 103

x = 71

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Step-by-step explanation:

I'm assuming this question is multiple choice, as there are several answers. y=x-18 is one, if that's an option. if you gave me the rest of the question, I might be able to help more :)

Answer:

Question 1 is C

Step-by-step explanation:

Answer:

a: top right 1 top left 2 bottom left 3 bottom right 4

c: axis going horizontal is the x axis and the axis going vertical is the y axis

d: origin is the very middle and it is (0,0)

Step-by-step explanation:

L = 1.3245 is  the legnths of the pen's sides .

What is area and perimeter?

Perimeter is the distance around the outside of a shape. Area measures the space inside a shape.

The equation for perimeter is 2L + W = 30 ( I'm assuming that the shed takes up one of the Widths, but you can use the Length if you want, it doesn't matter.)

So W = 30 - 2L.

Area = L x W = L (30 - 2L) = 30L - 2L^2.

This is a quadratic equation, easily graphed as a parabola, with a maximum point at L = 1.3245 .

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Answer: It is the quotient of 21 times and number and 8.

Answer:

The answer is "A"

Step-by-step explanation:

please make me b r a i n l i e s t thx

In a series of transformations, dilation would make two figures similar as opposed to congruent.

Rotation, reflection and translation are known as rigid transformations.

This means they do not change the size or shape of a figure, they simply move it.

These rigid transformations preserve congruence.

Dilation, however, are not rigid transformation, since they change the size of  a shape.

Dilation would not change the shape, just the size: the angle measures would be the same, and the ratio of corresponding sides would be equal to the scale factor used in the dilation.

This would give us a similar, but not congruent.

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Answer:

Answer: Radius is 3 ft

Step-by-step explanation:

Formular:

\({ \boxed{V = \frac{4}{3} \pi {r}^{3} }} \\ \)

substitute:

\(36\pi = \frac{4}{3} \pi {r}^{3} \)

multiply all sides by 3:

\((36\pi \times 3) = ( \frac{4}{3} \pi {r}^{3} ) \times 3 \\ \\ 108\pi = 4\pi {r}^{3} \)

divide all sides by π :

\( \frac{108\pi}{\pi} = \frac{4\pi {r}^{3} }{\pi} \\ \\ 108 = 4 {r}^{3} \)

divide all sides by 4:

\( \frac{108}{4} = \frac{4 {r}^{3} }{4} \\ \\ {r}^{3} = 27\)

take a cube root:

\( \sqrt[3]{ {r}^{3} } = \sqrt[3]{27} \\ r = \sqrt[3]{(3 \times 3 \times 3)} \\ r = \sqrt[3]{ {3}^{3} } \\ \\ r = 3\)

a. To find the present value at t=10, we need to calculate the value of f(t) at t=10. Using the given function f(t) = 500e^(0.04t), we substitute t=10 into the equation:

\(\displaystyle \text{Present value} = f(10) = 500e^{0.04(10)}\)

Simplifying the exponent:

\(\displaystyle \text{Present value} = 500e^{0.4}\)

Evaluating the exponent:

\(\displaystyle \text{Present value} = 500(2.71828^{0.4})\)

Calculating the value inside the parentheses:

\(\displaystyle \text{Present value} = 500(1.49182)\)

Calculating the product:

\(\displaystyle \text{Present value} \approx 745.91\)

Therefore, the present value at t=10 is approximately $745.91.

b. To find the accumulated money flow at t=10, we need to calculate the integral of f(t) from 0 to 10. Using the given function f(t) = 500e^(0.04t), we integrate the function with respect to t:

\(\displaystyle \text{Accumulated money flow} = \int_{0}^{10} 500e^{0.04t} dt\)

Integrating:

\(\displaystyle \text{Accumulated money flow} = 500 \int_{0}^{10} e^{0.04t} dt\)

Using the properties of exponential functions, we can evaluate the integral:

\(\displaystyle \text{Accumulated money flow} = 500 \left[ \frac{{e^{0.04t}}}{{0.04}} \right]_{0}^{10}\)

Simplifying:

\(\displaystyle \text{Accumulated money flow} = 500 \left( \frac{{e^{0.4}}}{{0.04}} - \frac{{e^{0}}}{{0.04}} \right)\)

Calculating the exponential terms:

\(\displaystyle \text{Accumulated money flow} = 500 \left( \frac{{e^{0.4}}}{{0.04}} - \frac{1}{{0.04}} \right)\)

Evaluating the exponential term:

\(\displaystyle \text{Accumulated money flow} = 500 \left( \frac{{1.49182}}{{0.04}} - \frac{1}{{0.04}} \right)\)

Calculating the subtraction:

\(\displaystyle \text{Accumulated money flow} = 500 \left( \frac{{1.49182 - 1}}{{0.04}} \right)\)

Calculating the division:

\(\displaystyle \text{Accumulated money flow} = 500 \times 12.2955\)

Calculating the product:

\(\displaystyle \text{Accumulated money flow} \approx 6147.75\)

Therefore, the accumulated money flow at t=10 is approximately $6147.75.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

540km/hr

Step-by-step explanation:

8.4km/min×60min/km

=8.4/60

=540km/hr

The span of a set of vectors is the set of all possible linear combinations of those vectors. So, if we have vectors v1, v2, …, vm in Rn, then the span of these vectors will be the set of all possible linear combinations of these vectors. This means that any vector in the span can be expressed as a linear combination of v1, v2, …, vm.

Now, to determine whether the span of these vectors is necessarily a subspace of Rn, we need to check the three subspace axioms: closure under addition, closure under scalar multiplication, and contains the zero vector.
Closure under addition: Let u and v be two vectors in span(v1, v2, …, vm). This means that u and v can be expressed as linear combinations of v1, v2, …, vm. Therefore, their sum u + v can also be expressed as a linear combination of v1, v2, …, vm, and so u + v is also in the span. Thus, the span is closed under addition.
Closure under scalar multiplication: Let c be any scalar and let u be any vector in span(v1, v2, …, vm). This means that u can be expressed as a linear combination of v1, v2, …, vm. Therefore, cu can also be expressed as a linear combination of v1, v2, …, vm, and so cu is also in the span. Thus, the span is closed under scalar multiplication.
Contains the zero vector: Since the zero vector can always be expressed as a linear combination of the vectors v1, v2, …, vm (by taking all coefficients to be zero), it follows that the span contains the zero vector.
Therefore, since the span of v1, v2, …, vm satisfies all three subspace axioms, it is necessarily a subspace of Rn.

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Answer:

, hope u understand and happy

Answer:

Oral traditions are things that have been passed down from generations, such as folktales, pieces of art, stories, and more

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

3 to the 2nd power would look like this if you typed it out: 3^2. The ^ symbol refers to an exponent.

3^2

= 3 * 3

= 9

:3))

Answer:

the answer would be 9

Step-by-step explanation:

3² would be expressed as a multiplication like this

3x3

you would get 9

So, your answer is 9.

The statement provides two quantities, A and B, expressed as ratios of positive integers c and d. The relationship between the quantities A and B cannot be determined from the information given.

The statement provides two quantities, A and B, expressed as ratios of positive integers c and d. However, no specific values or constraints are given for c and d. Without knowing the specific values or any relationship between c and d, it is impossible to determine the relationship between A and B.

The relative magnitudes of A and B will depend on the values of c and d. If the value of c is greater than d, then A would be greater than B. Conversely, if the value of d is greater than c, then B would be greater than A. However, without any information about the values of c and d or any relationship between them, we cannot determine the relationship between A and B.

Therefore, based on the given information, the relationship between quantities A and B cannot be determined.

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Answer:

x= -1  

y= -1

Step-by-step explanation:

Answer:

No, No, Yes, No, Yes, Yes

Step-by-step explanation:

A graph is a function if it passes the vertical line test (in other words, every vertical line that can be drawn intersects the graph at no more than one point).

This is because for a function, each input must map onto no more than one output.