Cryogenic liquid storage. Liquid oxygen is stored in a thin-walled spherical container, 96 cm in diameter, which is further enclosed in a concentric container 100 cm in diameter. The surfaces facing each other at coated with an emittance of only 0.05. The inner surface is at 95 K, and the outer surface is at 280 K.
a. Draw an equivalent electrical circuit.
b. What is the heat exchange [W] between the two surfaces?
Answers
Answer:
The answer is "26.55 V"
Explanation:
Given values:
\(d_i= 0.96m\\d_o= 1m\\\epsilon = 0.05\\T_0= 280k\\T_i= 95k\\\)
For Answer (a) please find the attachment.
Answer (b):
\(q_{i-0}= \frac{\sigma (T_{0}^4)-(T_{i}^4)}{\frac{1-\epsilon i }{\epsilon_{i} A_{i}}+ \frac{1 }{\ f_{i o} A_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0} A_{0}}}\)
\(f_{i0}= 1 \ it \ is \ fully \ inside \ the \ large \ sphero \\\)
\(q_{i-0}= \frac{\sigma A_i (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} - 1+ 1 +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times \frac{A_i}{A_0}}\\\\q_{i-0}= \frac{\sigma A_i (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times (\frac{d_i}{d_0})^2}\\\\q_{i-0}= \frac{\sigma (\pi d^2_i) (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times (\frac{r_i}{r_0})^2}\\\\\)
\(q_{i-0}= \frac{5.67 \times 10^{-8} \times 3.14 \times 9.62 \times 9.62 \times (280^4-94^4)}{\frac{1 }{0.05} +\frac{1-0.05}{0.05} \times (\frac{0.96}{1})^2}\\\\\ After \ solve the \ equation \ the \ answer \ is:\\\\q_{i-0} = 26.55 \ V\)
Related Questions
Engineered lumber should not be used for
A. finger-jointed studs.
B. plywood roof sheathing.
C. composite panel garage doors.
D. items that are in contact with concrete.
Answers
Answer:
Composite panel garage doors
Explanation:
Engineered lumber should not be used for composite panel garage doors. Hence, option C is correct.
What is a Pane lift garage door?Horizontal panels are connected to form a single garage door in panel lift doors, sometimes referred to as sectional doors. These panels have wheels attached to them that are positioned in tracks on either side and guide the door through a reasonably sharp turn to reposition it horizontally above the garage door opening.
Yes, however it's crucial to have a pro take their place for the finest outcomes. It can be unsafe for anybody other than a professional to install garage doors due to their complexity and difficulty.
One of the most affordable solutions on the market is an aluminum garage door. They are available in a variety of design options that can complement the exterior style of your home. Low-cost aluminum garage doors.
Thus, option C is correct.
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In which phase and for what purpose does a construction manager work with various consultants? In the [blank] phase, a construction manager works closely with architects, civil engineers, electrical engineers, and other consultants to prepare a [blank].
Choices for first [blank]
A. design and planning
B. Construction
C. Post construction
Choices for second [blank]
A. draft
B. Sketch
C. Blueprint
Answers
Answer:
a and c
Explanation:
Jay decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jay traveling?
Answers
Answer: jay is traveling at 4 miles per hour :)
Explanation:
technician a says that a macpherson strut typically does not include the spring as part of the strut assembly. technician b says that a modified strut typically does not include the spring as part of the strut assembly. which technician is correct?
Answers
Both technicians are correct.
MacPherson struts are a specific type of independent suspension found on a car's front axle. The McPherson strut replaces the steering rod and performs the functions of suspension and vibration dampening at the same time.
The MacPherson strut, which has a cheap production cost, is still a stunningly efficient solution to combine strength, spring, and stability.
Altered strut It differs from a standard MacPherson system since the coil spring is not an interior component of the strut body. It is primarily used in rear-wheel drive automobiles. The spring in a modified strut is situated between the lower control arm and the car's frame.
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who is the strongest avenger i say hulk but who knows at this point
Answers
Answer:
or is the strongest evenger she hulk
Explanation:
?????????
Answer:
Thor!
Explanation:
In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.
analog to digital conversion in digital electronics
Answers
2. A silo (base not included) is to be constructed in the form of a cylinder surmounted by a hemisphere. The cost of construction per square unit
of surface area is twice as great for the for the hemisphere as it is for the cylindrical side wall. Determine the dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum. Neglect the thickness of the silo and waste in construction.
Answers
An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.
The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;
Height of cylinder = 2 × Radius of cylinderReason:
The given parameters are;
Form of silo = Cylinder surmounted by a hemisphere
Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall
Required:
The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum
Solution:
The fixed volume of the silo, V, can be expressed as follows;
\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)
\(h = \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 }\)Where;
h = The height of the cylinder
r = The radius of the cylinder
The surface area is, Surface Area = 2·π·r·h + 2·π·r²
The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²
Therefore;
\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)
\(C = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)At the minimum value, we have;
\(\dfrac{dC}{dr} =0 = \dfrac{d}{dr} \left(\dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r} \right) = \dfrac{16 \cdot r^3 \cdot \pi - 6 \cdot V}{3 \cdot r^2}\)Which gives;
16·π·r³ = 6·V
\(V = \dfrac{16 \cdot \pi \cdot r^3}{6} = \dfrac{8 \cdot \pi \cdot r^3}{3}\)Which gives;
\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)
h = 2·r
The height of the silo, h = 2 × The radius, 2
Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius
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What is the difference between digital instruments and decimal scaled instruments to measure
Answers
Answer Digital measuring instruments are self-contained devices that automatically present the value of the measured quantity on a digital display. And Decimal Scaled Instruments: Record all digits that you can certainly determine from the scale markings and estimate one more digit. I hope this Helped I´m new to this.
Explanation:
Which of the following statements are true about staying safe while
working around all caught-in caught-between hazards?
Select two answers that apply.
What you should do changes based on hazards you’re exposed to.
You should be aware of any hazards that are present
You should be aware of the only hazards indicated as critical by management
What you should do is the exact same no matter the hazard
Answers
Answer:
What you should do changes based on the hazards you're exposed to.
You should be aware of any hazards that are present.
of what value is the weather depiction chart to the pilot?
Answers
The weather depiction chart is a crucial tool for pilots to gather information about the current weather conditions, assess potential hazards, and make informed decisions before and during the flight.
The weather depiction chart is a valuable tool for pilots as it provides a visual representation of current weather conditions over a wide area. It provides essential information about various weather phenomena that can impact flight safety.
The chart helps pilots to understand the current weather conditions in their flight region. It provides an overview of areas of high and low pressure, fronts, areas of precipitation, cloud cover, and other weather patterns.
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concepts are general ideas you use to organize your experience and, in doing so, bring order and intelligibility to your life. t/f
Answers
The given statement "Concepts are general ideas that you use to organize your experience and, in doing so, bring order and intelligibility to your life. " is true because It is important to understand what concept is and how they are useful in our daily life as it helps us organize our experiences and ideas.
Concepts are general ideas that can be used to classify and organize information. They provide structure and coherence to our perceptions and experiences. When we have a concept, it helps us bring order to our experiences and gives us a framework for understanding new information.
By organizing information into categories, we can more easily remember, process, and communicate it. This can help us make sense of the world around us and navigate our experiences in a meaningful way. In conclusion, concepts are important because they help us make sense of our experiences and the world around us. They provide structure and intelligibility to our lives, allowing us to organize and communicate our ideas and experiences more effectively.
So the statement is true.
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Which of these drum brake systems uses servo action in both directions?
Select one:
O
a. Leading shoe drum brake system
b. Trailing shoe drum brake system
C. Twin leading shoe drum brake system
O
d. Duo-servo drum brake systems
Answers
three methods by which the value of the unknown resistance can be determined
Answers
Answer:
The Meter bridge is the modification of Wheatstone's network used to determine the value of unknown resistance. The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.
What car is this? I thinks its a nissan 240sx but i dont know
Answers
Answer:
your right I had to look a little bit but you are correct
Determine numerical values for each of the three mesh currents as labeled in
the circuit diagram of Fig. 4.58.
Answers
The numerical values for the mesh currents that we have in the question are given as:
1i = 0.9892 = 0.9892 amperei2 = 0.1501 amperei3 = 0.1570 ampereHow to solve for the values of the mesh currentWe first have to write the KVL
2 - 1(i₁ - i₂) + 3 - 5(i₁ - i₃) = 0
We have to expand the equation that we have above
2 - i₁ + i₂ + 3 - 5i₁ + 5i₃ = 0
take like terms
-i₁ - 5i₁ i₂ + 5i₃ = 5
= 6i₁ - i₂ - 5i₃ = 5
-1(i₂ - i₁) - 6 i₂ - 9(i₃ - i2) = 0
after expanding we would have
i₁ - 16i₂ + 9i₃ = 0------- equation 2
-5 (i3 - i1) - 3 - 9(i3 - i2) - 7i3 = 0
5i1 + 9i2 - 2i3 = 3 ------ equation 3
From the equations that we have in 1, 2 and 3, we would solve the system of equations to get
1i = 0.9892 = 0.9892 ampere
i2 = 0.1501 ampere
i3 = 0.1570 ampere
These are the mesh current that are in the labeled diagram.
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A mass of 39 lbm of helium undergoes a process from an initial state of 50 ft3/ lbm and 60°F to a final state of 20 ft3/lbm and 240°F. Determine the entropy change of helium during this process assuming the process is reversible. The gas constant of helium is R = 0.4961 Btu/lbm·R. The constant volume specific heat of helium at room temperature is cv = 0.753 Btu/lbm·R. The entropy change of helium during this process is Btu/R.
Answers
The entropy change of helium during this process is -9 Btu/R
How to solve for the enthropy changeThe formula is given as
\(Change in S = m[Cvln\frac{T_{2} }{T_{1} } + Rln\frac{V_{2} }{V_{1} }\)
Where the variables are M = mass = 39
Cv = specific heat of helium = 0.753
t2 = 240 + 460
T1 = 60 + 460
R = gas constant = 0.4961
V1 = initial state = 50
V2 = final state = 20
we would have to put these values in the formula that we have above
\(39[0.753\frac{240+460}{60+460} +0.4961ln\frac{20}{50}]\)
= -9 Btu/R.
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Which metal is stronger? Tungsten or Titanium?
Answers
Answer:
i believe tungsten is stronger than titanium !
Determine the switchgear size for a 180, 85Watt fluorescent light fittings with control gear losses of 7Watt per fittings and power factor of 0.8.
Answers
Note that the switchgear size should be equal to or greater than the total kVA required to ensure safe and efficient operation.
What is the explanation for the above response?
To determine the switchgear size for the given fluorescent light fittings, we need to calculate the total power consumption of the fittings.
Total power consumption per fitting = 85W + 7W = 92W
Next, we need to convert the power to kVA (kilovolt-ampere) as switchgear is rated in kVA.
Power in kVA = (92W / 1000) / 0.8 power factor = 0.115 kVA
Now, we can calculate the total kVA required for all the fittings:
Total kVA = 0.115 kVA x number of fittings
Once we know the total kVA required, we can select the appropriate size of switchgear that can handle the load. The switchgear size should be equal to or greater than the total kVA required to ensure safe and efficient operation.
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What competitive advantage is there for a company that has kept its general overhead low?
Answers
A company that has kept its general overhead low can have a competitive advantage by being able to offer products or services at lower prices than its competitors.
This can result in higher sales volume and increased market share. Additionally, a company with lower overhead may be able to allocate more resources towards research and development, marketing, or other areas that can further enhance its competitive position. Lower overhead can also make a company more resilient during periods of economic downturn or market disruption, as it may be better able to weather the storm with lower fixed costs.
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4. Workers can be exposed to blood or other potentially infectious materials
(OPIM) if it splashes into their
A. Eye
B. Nose
C. A Mouth
D. All of the above
Answers
exposure incident means a specific eye, mouth, other mucous membrane, non-intact skin, or parenteral contact with blood or other potentially infectious material
In the case of an automobile electric system, the chassis of the vehicle is the ___________ side of the circuit.
Answers
Answer:
ground
Explanation:
In modern cars, the chassis is connected to the negative terminal of the battery, and provides the "ground" or "return" for the circuit.
Answer:
ground
Explanation:
Determine the head loss during backwash for a filter bed consisting of 0.6 m of sand with f = 0.45, 0.4 m gravel, and a pipe lateral under drain with a circular orifice having α = 0.8 and β = 0.05, Vb = 0.8 m/min.
Answers
The head loss during backwash for this filter bed is:
HL = (3.70ρVb2)/(2g[αf + β])
where ρ = density of the fluid (typically water), Vb = backwash velocity, g = acceleration due to gravity, α = orifice discharge coefficient, f = bed porosity, and β = orifice area ratio (orifice area / pipe lateral area).
For the given filter bed, the head loss is equal to:
HL = (3.70*1000*(0.8 m/min)^2)/(2*9.81*(0.8*0.45 + 0.05)) = 0.124m
The head loss during backwash is mostly due to friction loss as the water flows through the filter bed and friction loss is caused by the resistance to flow of the bed particles. The orifice is also a source of head loss due to the sudden expansion of the water from the pipe lateral to the orifice.
What time ----–- the train arrve?
Answers
Technician A says that a wye-wound stator produces more maximum output than the same alternator equipped with a delta-wound stator. Technician B says that an alternator equipped with a delta-wound stator produces more maximum output than a wye-wound stator. Who is right
Answers
The both technicians are correct, but they are referring to different types of maximum output. It's important to understand the differences between these two types of stators and their applications to choose the right one for a specific application.
A wye-wound stator produces more maximum output in terms of maximum line-to-neutral voltage. This is because each phase of the stator winding is connected to a neutral wire, which allows for a higher voltage output compared to a delta-wound stator.
The wye-wound stator is commonly used for applications that require high-voltage output, such as industrial and commercial applications.
On the other hand, an alternator equipped with a delta-wound stator produces more maximum output in terms of maximum current. This is because the delta-wound stator has a lower winding resistance, which allows for a higher current output compared to a wye-wound stator.
The delta-wound stator is commonly used for applications that require high-current output, such as power generation and distribution.
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what are the dimension of the container
Answers
Answer:
Dimensions of a standard container is length 5.440 m 17'10 3/16' width 2.294 m 7'6 1/4' height centimeters 3.237 7'4 1/16'
Explanation:
Standard height for a shipping container is 8 feet 6 inches
Low-voltage lighting systems can be concealed or extended through a building wall, floor, or ceiling without regard to the wiring method used.T/F
Answers
It is true that low-voltage lighting systems can be concealed or extended through a building wall, floor, or ceiling without regard to the wiring method used. Low-voltage lighting systems can be concealed or extended through a building wall, floor, or ceiling without regard to the wiring method used.
This is because low-voltage systems typically operate at a voltage level that poses minimal risk of electrical shock, allowing for more flexibility in wiring methods. Low-voltage lighting systems operate on 12-24 volts, which is significantly lower than standard household voltage. This allows for the wiring to be concealed or extended through walls, floors, or ceilings without the need for conduit or armored cable, which is required for standard voltage wiring. The lower voltage also reduces the risk of electrical shock, making it safer for installation and maintenance. Additionally, low-voltage lighting systems are often more energy-efficient and have a longer lifespan than standard voltage systems. These systems can be hidden or extended to various locations within a building, making them a versatile and convenient option for various lighting installations.
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True, low-voltage lighting systems can indeed be concealed or extended through a building wall, floor, or ceiling without regard to the wiring method used.
This is because low-voltage systems typically have lower safety risks compared to traditional high-voltage systems, allowing for more flexibility in installation.
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which, given an array of integers a of length n returns true when it is possible to create the required pairs
Answers
The objective is to produce a matrix arr has size N, in which the values of the elements at each index are filled in accordance with the guidelines listed below. arr is equal to I - 1) - k).
What does N in computer lingo mean?The input size is indicated by n, and the worst-case growth rate function is represented by O. The Big-O notation is used to categorize algorithms according to how much running time or memory they use as the input increases.
What in technology is an integer?Meaning of Integer (INT) In computer programming, an integer is a data type that is used to describe real figures without fractional values.
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Find the value of the variable resistor R, in the circuit in Fig. P4. 85 that will result in maximum power dissipation in the 62 resistor. (Hint: Hasty conclusions could be hazardous to your career. ) What is the maximum power that can be delivered to the 6 12 resistor?
Answers
The maximum power that can be delivered to the 6Ω resistor is 2.109W, and the maximum power that can be delivered to the 12Ω resistor is 4.219W.
First, we need to analyze the circuit and find the equivalent resistance seen by the 62Ω resistor. This can be done by combining the resistors in parallel and series:
The 10Ω and 20Ω resistors are in series and can be combined to give an equivalent resistance of 30Ω.
The 40Ω and 50Ω resistors are also in series and can be combined to give an equivalent resistance of 90Ω.
The 30Ω and 90Ω resistors are in parallel, and their equivalent resistance can be found using the formula:
1/Req = 1/30Ω + 1/90Ω
Req = 22.5Ω
So the equivalent resistance seen by the 62Ω resistor is 22.5Ω. To find the value of the variable resistor R that will result in maximum power dissipation in the 62Ω resistor, we need to use the maximum power transfer theorem, which states that maximum power is transferred from a source to a load when the load resistance is equal to the internal resistance of the source.
In this case, the voltage source has an internal resistance of 10Ω, which is in series with the variable resistor R. So the total resistance in the circuit is R + 10Ω. To maximize power dissipation in the 62Ω resistor, we need to make the equivalent resistance seen by the 62Ω resistor equal to R + 10Ω.
Therefore, we set:
R + 10Ω = 22.5Ω
R = 12.5Ω
So the value of the variable resistor R that will result in maximum power dissipation in the 62Ω resistor is 12.5Ω.
To find the maximum power that can be delivered to the 6Ω and 12Ω resistors, we need to calculate the total current in the circuit. We can use Ohm's law to find the voltage across the 30Ω resistor:
V = IR = (60V)/(10Ω + R)
And then use Kirchhoff's voltage law to find the voltage across the 6Ω and 12Ω resistors:
V = (30Ω)(I) + (6Ω)(I) + (12Ω)(I)
Simplifying, we get:
V = 48I
Equating the two expressions for V, we get:
(60V)/(10Ω + R) = 48I
Solving for I, we get:
I = (60V)/(48)(10Ω + R)
The power dissipated in the 6Ω resistor is:
P = I^2R = [(60V)/(48)(10Ω + R)]^2(6Ω)
The power dissipated in the 12Ω resistor is:
P = I^2R = [(60V)/(48)(10Ω + R)]^2(12Ω)
Substituting R = 12.5Ω, we get:
P(6Ω) = 2.109W
P(12Ω) = 4.219W
So the maximum power that can be delivered to the 6Ω resistor is 2.109W, and the maximum power that can be delivered to the 12Ω resistor is 4.219W.
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Engineers design city sidewalks using blocks of concrete separated by a small gap to prevent them from cracking. What property of water is being taken into account for this design
Answers
The property of water is taken into account for designing city sidewalks with gaps between concrete blocks is its tendency to expand when it freezes.
By allowing space for water to expand, engineers prevent cracking and damage to the sidewalk caused by the freezing and expansion of water.
Water has a unique property known as thermal expansion. When water freezes, it undergoes a phase change and expands in volume. This expansion can exert significant force and pressure, leading to the cracking or breaking of surrounding materials.
In the case of city sidewalks, engineers incorporate small gaps or joints between concrete blocks to accommodate the expansion of water during freezing conditions. These gaps provide a controlled space for the water to expand without exerting excessive pressure on the concrete blocks.
By allowing the water to expand into the gaps, the pressure is relieved, reducing the likelihood of cracks or damage to the sidewalk. This design approach helps maintain the structural integrity and longevity of the sidewalk, even in regions with freezing temperatures.
In addition to considering thermal expansion, engineers also consider other factors such as load-bearing capacity, durability, and aesthetic considerations when designing city sidewalks.
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Which of these was not part of the OBD II implementation?
OA. Common Codes
OB. Readiness Monitors
OC. Digital Processing
OD. Standard Terminologies
Answers
The Digital Processing is not part of the OBD II implementation.
What is an OBD II system?OBD II is known to be a kind of acronym for On-Board Diagnostic II. This is known to be the second generation of on-board self-diagnostic equipment that is needed for light- and medium-duty California vehicles.
The OBD-II is said to be a kind of on-board computer that handles emissions, , speed, etc.
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