Answer:
what
Step-by-step explanation:
Please help I dont get it
Answer:
B. 12cm
Step-by-step explanation:
We can double check by plugging in the number. However, the question trys to trick you, by giving you the diametre, but in order for the formula to work (V=4 /3πr^3), we will divide the diametre by 2 (12 ÷ 2= 6),
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Once we do that, we can double check, when you plug in your numbers your answer will be around 900 (904.78, to be exact, but the question asks for approximate diamtetre).
----------------------------------------------------------------------------------------------------------------
Have a good day :)
(Present value of an ordinary annuity) What is the present value of $2.500 per year for 10 years discounted back to the present at 7 percent? The present value of $2500 per year for 10 years discounted back to the present at 7 percent is : (Round to the nearest cent)
The present value of $2,500 per year for 10 years discounted back to the present at 7 percent is $17,462.03.
To calculate the present value of an ordinary annuity, we can use the formula:
PV = A * [1 - (1 + r)^(-n)] / r,
where PV is the present value, A is the annual payment, r is the discount rate per period, and n is the number of periods.
In this case, the annual payment is $2,500, the discount rate is 7 percent (or 0.07 as a decimal), and the number of periods is 10 years. Plugging in these values into the formula, we can calculate the present value:
PV = $2,500 * [1 - (1 + 0.07)^(-10)] / 0.07 ≈ $17,462.03.
Therefore, the present value of $2,500 per year for 10 years discounted back to the present at 7 percent is approximately $17,462.03. This represents the amount of money needed in the present to be equivalent to receiving $2,500 per year for 10 years with a 7 percent discount rate.
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Law of sines: startfraction sine (uppercase a) over a endfraction = startfraction sine (uppercase b) over b endfraction = startfraction sine (uppercase c) over c endfraction 2.2 units 2.4 units 3.0 units 3.3 units
The possible approximate lengths of b are: 2.3 units and 7.8 units
We know that the law of sines for triangle is:
The ratios of the length of all sides of a triangle to the sine of the respective opposite angles are in proportion.
This means, for triangle ABC,
\(\frac{sin~ A}{a} =\frac{sin~B}{b} =\frac{sin~ C}{c}\)
where a is the length of side BC,
b is the length of side AC,
c is the length of side AB.
For triangle ABC consider an equation from sine law,
\(\frac{sin~ A}{a} =\frac{sin~ C}{c}\)
here, c = 5.4, a = 3.3, and m∠A = 20°
\(\frac{sin~ 20}{3.3} =\frac{sin~ C}{5.4}\\\\\frac{0.3420}{3.3} =\frac{sin~ C}{5.4}\)
0.3420 × 5.4 = 3.3 × sin(C)
sin(C) = 0.5596
∠C = arcsin(0.5596)
∠C = 34.03° OR 145.9°
∠C ≈ 34° OR 146°
We know that the sum of all angles of triangle is 180 degrees.
so, ∠A + ∠B + ∠C = 180°
when m∠C = 34°,
20° + ∠B + 34.03° = 180°
∠B = 125.97°
m∠B = 126°
when m∠C = 146°,
20° + ∠B + 146° = 180°
m∠B = 14°
Now consider equation,
\(\frac{sin~ A}{a} =\frac{sin~ B}{b}\\\\\frac{sin~20^{\circ}}{3.3} =\frac{sin~ 126^{\circ}}{b}\)
b × 0.3420 = 0.8090 × 3.3
b = 7.8 units
when m∠B = 14°,
\(\frac{sin~20^{\circ}}{3.3} =\frac{sin~ 14^{\circ}}{b}\)
b × 0.3420 = 0.2419 × 3.3
b = 2.3 units
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The complete question is:
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction
In ΔABC, c = 5.4, a = 3.3, and measure of angle A = 20 degrees. What are the possible approximate lengths of b? Use the law of sines to find the answer.
2.0 units and 4.6 units
2.1 units and 8.7 units
2.3 units and 7.8 units
2.6 units and 6.6 units
i simply need to know the answer to these questions
The height of the monument is 201 ft
The angle of elevation is 63.6
Sine of B is equal to
b/athe cosine of CCosine of (90 - B)Sine of (90 - C)How to find the height of the monumentThe height of the monument is solved using trigonometry, The angle of elevation is first calculated using cosine
cos (angle of elevation) = 100 / 225
angle of elevation = arc cos (100 / 225)
angle of elevation = 63.612 degrees
The height, h
tan 63.6 = h / 100
h = 100 * tan 63.6
h = 201.449
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40 points! First answer gest brainliest! A 9th grade teacher at a local high school wants to know which subject the 9th grade students in school like the best.
Which group of people should make up a sample that will best answer her question?
A. Other 9th grade teachers in her school
B. Parents of 9th graders in her school
C. 9th graders in her school
D. 9th graders in her homeroom
Answer
9th graders in her school
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
A is wrong because the teachers are not in 9th grade.
B is wrong because parents are not in 9th grade
D is wrong because the homeroom does not represent the entirety of 9th grade
Bradley entered the following group of values into the TVM solver of his graphing calculator and N equals 36 I percent equals 0.8 PV equals PMT equals -350 FB equals 0P/Y equals 12 C/Y equals 12 PMT equals N which of these problems could he be trying to solve
The problem that Bradley could he be trying to solve is C. A person can afford a $350-per-month loan payment. If she is
being offered a 3-year loan with an APR of 0.8%, compounded monthly, what is the most money that she can borrow?
How to explain the informationFrom the information, Bradley entered the following group of values into the TVM Solver of his graphing calculator. N = 36; 1% = 0.8; PV =; PMT = -350; FV = 0; P/Y = 12; C/Y = 12; PMT:END.
Based on this, a person can afford a $350-per-month loan payment. If she is being offered a 3-year loan with an APR of 0.8%.
The correct option is C
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Bradley entered the following group of values into the TVM Solver of his
graphing calculator. N = 36; 1% = 0.8; PV =; PMT = -350; FV = 0; P/Y = 12; C/Y
= 12; PMT:END. Which of these problems could he be trying to solve?
O
A. A person can afford a $350-per-month loan payment. If she is
being offered a 36-year loan with an APR of 9.6%, compounded
monthly, what is the most money that she can borrow?
O
B. A person can afford a $350-per-month loan payment. If she is
being offered a 3-year loan with an APR of 9.6%, compounded
monthly, what is the most money that she can borrow?
O
C. A person can afford a $350-per-month loan payment. If she is
being offered a 3-year loan with an APR of 0.8%, compounded
monthly, what is the most money that she can borrow?
D. A person can afford a $350-per-month loan payment. If she is
being offered a 36-year loan with an APR of 0.8%, compounded
find a1 in a geometric series for which sn = 93, r = 2, and n = 5
The first term, a1, in the geometric series is -3.
What is Geometric Series?
A geometric series is a series for which the ratio of two consecutive terms is a constant function of the summation index. The more general case of a ratio and a rational sum-index function produces a series called a hypergeometric series. For the simplest case of a ratio equal to a constant, the terms have the form
To find the first term, a1, in a geometric series given the sum, Sn = 93, the common ratio, r = 2, and the number of terms, n = 5, we can use the formula for the sum of a geometric series:
Sn = a1 * (1 - r^n) / (1 - r)
Plugging in the given values, we have:
93 = a1 * (1 - 2^5) / (1 - 2)
Simplifying the expression:
93 = a1 * (1 - 32) / (-1)
93 = a1 * (-31)
Now we can solve for a1 by dividing both sides of the equation by -31:
a1 = 93 / -31
a1 = -3
Therefore, the first term, a1, in the geometric series is -3.
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At what point do the lines y = 6x – 18 and
y=8x – 32 intersect?
Answer:
(7, 24)
Step-by-step explanation:
Solve the system:
6x - 18 = 8x - 32
2x = 14
x = 7
y = 6(7) - 18
y = 24
If you pick a card from a standard deck find the following probabilities write your answer as a reduce fraction with no spacesP(even number card or face card)P(number card or heart)
Given data:
The given deck of card.
The probability of even number card or face card is,
\(\begin{gathered} P(\text{even or face)=P(E)+P(f)} \\ =\frac{20}{52}+\frac{12}{52} \\ =\frac{32}{52} \\ =\frac{4}{13} \end{gathered}\)Thus, the probability of even number card or face card is 4/13.
The probability of numbered card or heart is,
\(\begin{gathered} P(x)=\frac{36}{52}+\frac{13}{52}-\frac{9}{52} \\ =\frac{40}{52} \\ =\frac{10}{13} \end{gathered}\)Thus, the probability of numbered card or heart is 10/13.
calculate the area, in square units, bounded above by x=25−y−−−−−√−5 and x=y−10 and bounded below by the x-axis.
The area bounded by the curves x = 25 - √(y - 5) and x = y - 10, bounded below by the x-axis, is approximately 324.24 square units.
To calculate the area bounded by the curves x = 25 - √(y - 5) and x = y - 10, bounded below by the x-axis, we need to find the intersection points of the curves and integrate the area between those points.
First, let's find the intersection points by setting the two equations equal to each other:
25 - √(y - 5) = y - 10
To solve this equation, we can square both sides:
(25 - √(y - 5))^2 = (y - 10)^2
Expanding and simplifying, we get:
625 - 50√(y - 5) + y - 5 = y^2 - 20y + 100
Rearranging terms, we have:
y^2 - 20y + 100 - y + 50√(y - 5) - 625 + 5 = 0
Simplifying further:
y^2 - 21y - 520 + 50√(y - 5) = 0
We can solve this equation numerically to find the intersection points using methods such as the Newton-Raphson method or graphing calculators.
Approximate solutions are y ≈ 26.63 and y ≈ -0.378.
To integrate the area, we need to find the limits of integration. Since we are bounded below by the x-axis, the lower limit will be the x-coordinate where the curves intersect the x-axis.
For the curve x = 25 - √(y - 5), we can set x = 0:
0 = 25 - √(y - 5)
Solving for y, we get:
√(y - 5) = 25
y - 5 = 625
y ≈ 630
So
The upper limit of integration will be the y-coordinate where the curves intersect:
y = 26.63
Now, we can integrate the function x = y - 10 from y = 630 to y = 26.63 to find the area:
Area = ∫[630, 26.63] (y - 10) dy
Integrating the function, we get:
Area = [0.5y^2 - 10y] evaluated from 630 to 26.63
Area = (0.5(26.63)^2 - 10(26.63)) - (0.5(630)^2 - 10(630))
Area ≈ 324.24 square units
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Find ABC (GRADE 9 MATH)
B = 2k
A = k√3
C = k
\( \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \)
A path 1 m wide is build around a garden that is a 30-meter square. What is the area taken by the path?
Length of outer boundary =30m
So area of outer boundary =30×30
= 900m²
Length of inner boundary of path=30-1= 29m
Inner area =29×29 =841m²
So area of path is= outer area - inner area
=900- 841
= 59m²
The first terms of a geometric sequence are as follows.
-810,-270,-90
Find the next two terms of this sequence.
Give exact values (not decimal approximations)
The fourth and fifth term of this sequence is -30 and -10 respectively.
Data;
first term (a) = -810common difference (r) = ?Common DifferenceThe common difference in a geometric progression is the ratio between two successive terms.
Let's find the common difference in this sequence
\(r = \frac{-270}{-810} \\r = \frac{1}{3}\)
The nth term of a geometric sequence is given as
\(T_n = ar^n^-^1\\\)
The next two terms of this sequence will be 4th and 5th term.
The fourth term of this sequence is
\(T_4 = ar^4^-^1\\T_4 = -810 * (\frac{1}{3})^3\\ T_4 = -810 * \frac{1}{27}\\ T_4 = -30\)
The fifth term of this sequence is
\(T_5 = ar^5^-^1\\T_5 = -810 * (\frac{1}{3})^4\\T_5 = -810 * \frac{1}{81} \\T_5 = -10\)
The fourth and fifth term of this sequence is -30 and -10 respectively.
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will give brainlist or whatever.
Meredith has $5.10 in quarters and dimes. She has 24 coins in all. How many quarters and how many dimes does she have?
1. Differentiate the function f(x) = ln (81 sin^2 (x)) f’(x) 2. Differentiate the function P(t) = in ( √t2 + 9) p' (t) 3. if x2 + y2 + z2 = 9, dx/dt = B, and dy/dt = 4, find dz/dt when (x,y,z) = (2,2,1)
dz/dt =
First you will get 4dz
I need help and i will give lots of points
the slope of that equation is -3/5
Help ejejsisjensisne ndjzjene Enid we ejsisbenejeusbw
Answer:
its C bro
its have to be 1-sin2x
because (sinx-cosx)² equal sin²x+cos²x-2×sinx×cosx
I need the answer for all them please
Answer:
1. 220
2. 260
3. 1400
4. 5160
Step-by-step explanation:
1. 11 out of 15
300 ÷ 15 = 20
20 x 11 = 220
2. 13 out of 20
400 ÷ 20 = 20
20 x 13 = 260
3. 2 out of 5
3500 ÷ 5 = 700
700 x 2 = 1400
4. 129 out of 300
12000 ÷ 300 = 40
40 x 129 = 5160
An apple tree has 20 apples on it. If 30% of the apples fell off, how many are still on the tree? PLEASE ANSWER WITH THE STEPS AND EXPLANATION TO SOLVE NOT JUST THE ANSWER!! GIVING BRAINLIEST TO WHOEVER GETS IT RIGHT!!
Answer:
14
Step-by-step explanation:
100% is 20
meaning that for every ten percent is two
so if you minus 30% 6 from 100% 20 you get 14
claudia has $\frac{16}{3}$ gallons of paint, $\frac{3}{5}$ gallons of which is red. what fraction of claudia's paint is red?
The fraction 9/80 cannot be simplified further, so that is the final answer.
Claudia has a total of 16/3 gallons of paint, and 3/5 gallons of that amount is red. To determine the fraction of Claudia's paint that is red, we need to express the amount of red paint as a fraction of the total amount of paint.
Let's denote the fraction of red paint as r and the total amount of paint as p.
We know that the amount of red paint is 3/5 gallons, which can be expressed as r = 3/5.
The total amount of paint is 16/3 gallons, which can be expressed as p = 16/3.
To find the fraction of Claudia's paint that is red, we divide the amount of red paint by the total amount of paint:
Fraction of red paint = r/p = (3/5) / (16/3).
To divide fractions, we multiply the numerator of the first fraction by the denominator of the second fraction and the denominator of the first fraction by the numerator of the second fraction:
Fraction of red paint = (3/5) * (3/16) = 9/80.
Therefore, the fraction of Claudia's paint that is red is 9/80.
It's important to note that fractions should be simplified if possible. In this case, the fraction 9/80 cannot be simplified further, so that is the final answer.
In conclusion, the fraction of Claudia's paint that is red is 9/80.
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The power rule for the logarithms states that logbMp = _____ The logarithm of a number with an exponent is the _______ of the exponent and the logarithm of that number.
The power rule for logarithms states that logb(M^p) = p * logb(M). The logarithm of a number with an exponent is the product of the exponent and the logarithm of that number.
The power rule states that logb(M^p) = p * logb(M), where M, b, and p are positive real numbers.
To understand this rule, let's consider an example. Suppose we have log2(8^2). According to the power rule, this is equivalent to 2 * log2(8).
In this case, M is 8, b is 2, and p is 2. The power rule tells us that we can bring the exponent (p) down and multiply it with the logarithm of the base (b) raised to the number (M).
So, log2(8^2) can be simplified as 2 * log2(8), which is 2 * 3 = 6.
In general, the power rule allows us to simplify logarithmic expressions by bringing the exponent down and multiplying it with the logarithm of the base.
This rule is particularly useful when dealing with complex logarithmic expressions and simplifying them to a more manageable form.
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carl's car wash takes a constant time of 4.5 minutes in its automated car wash cycle. autos arrive following a poisson distribution at the rate of 10 per hour. carl wants to know:
Based on the given information, Carl's car wash takes a constant time of 4.5 minutes in its automated car wash cycle. Autos arrive following a Poisson distribution at the rate of 10 per hour. Using this information, Carl can calculate the expected time it would take to wash a car.
The first step is to calculate the average time between car arrivals, which is equal to 60 minutes divided by the arrival rate of 10 cars per hour, giving an average time of 6 minutes per car. Since the wash cycle time is constant at 4.5 minutes, Carl can add these two values together to get an expected wash time of 10.5 minutes per car.
However, it's important to note that this is just an expected time, and there may be variations due to factors such as queue length, equipment malfunctions, or other unforeseen circumstances. Therefore, Carl should regularly monitor his car wash operation and make adjustments as necessary to ensure efficient and consistent service.
In summary, Carl's car wash takes a constant time of 4.5 minutes in its automated car wash cycle, and with autos arriving at a rate of 10 per hour, the expected time it would take to wash a car is 10.5 minutes.
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The sum of the firstt five terms of a geometric series is 33 and the sum of the first ten terms of the geometric series is -1023. a) Find the common ratio and the first term of the series. b) Find the general term of the series. Simplify your answer.
a. The common ratio is 2.
Given that the sum of the first five terms of the geometric series is 33, we use the formula for the sum of terms of a geometric series, S
Sₙ = a(rⁿ - 1)/(r - 1) where a = first term and r = common ratio
Since n = 5, the first 5 terms, and S₅ = 33
Sₙ = a(rⁿ - 1)/(r - 1)
33 = a(r⁵ - 1)/(r - 1) (1)
Also, when n = 10, the sum of the first 10 terms is S₁₀ = -1023
So, -1023 = a(r¹⁰ - 1)/(r - 1) (2)
Dividing (2) by (1), we have
-1023/33 = a(r¹⁰ - 1)/(r - 1) ÷ a(r⁵ - 1)/(r - 1)
-31 = (r¹⁰ - 1)/(r⁵ - 1)
-31(r⁵ - 1) = r¹⁰ - 1
-31r⁵ + 31 = r¹⁰ - 1
r¹⁰ - 1 + 31r⁵ - 31 = 0
r¹⁰ + 31r⁵ - 32 = 0
Let r⁵ = y
(r⁵)² + 31r⁵ - 32 = 0
y² + 31y - 32 = 0
Factorizing, we have
y² + 32y - y - 32 = 0
y(y + 32) - (y + 32) = 0
(y - 1)(y - 32) = 0
y - 1 = 0 or y - 32 = 0
y = 1 or y = 32
r⁵ = 1 or r⁵ = 32
r = ⁵√1 or r = ⁵√32
r = 1 or r = 2
Since for a geometric series, r ≠ 1, r = 2.
So, the common ratio is 2.
ii. The first term of the series.
The first term of the series is 33/31
Using (1)
33 = a(r⁵ - 1)/(r - 1) (1) where r = 2,
33 = a(2⁵ - 1)/(2 - 1) (1)
33 = a(32 - 1)/1
33 = 31a
a = 33/31
So, the first term of the series is 33/31
b. Find the general term of the series. Simplify your answer.
The general term of the geometric series is (33/62) × 2ⁿ
The general term of a geometric series is Uₙ = arⁿ⁻¹
With a = 33/31 and r = 2,
Uₙ = arⁿ⁻¹
Uₙ = (33/31) × 2ⁿ⁻¹
Uₙ = (33/31) × 2ⁿ/2
Uₙ = (33/62) × 2ⁿ
So, the general term of the geometric series is (33/62) × 2ⁿ
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Which fractions are less than 1/2
Answer:
1/4, 4/10, 3/7, 24/50 are all less than 1/2.
Step-by-step explanation:
How much time will it take your savings to double in value if the interest rate is 3%? What if the interest rate was 8%? Compute both answers by applying the "Rule of 72." Show all work
For an interest rate of 8%, we divide 72 by 8: 72 / 8 = 9. Thus, it would take around 9 years for the savings to double at an interest rate of 8%.
The "Rule of 72" is a quick estimation method to determine the time it takes for an investment or savings to double in value. By dividing 72 by the interest rate, you can obtain an approximation of the doubling time. For an interest rate of 3%, it would take approximately 24 years for the savings to double. For an interest rate of 8%, it would take around 9 years for the savings to double.
To calculate the doubling time using the Rule of 72, divide 72 by the interest rate. This provides an approximation of the number of years it takes for an investment or savings to double in value.
For an interest rate of 3%, we divide 72 by 3: 72 / 3 = 24. Therefore, it would take approximately 24 years for the savings to double.
For an interest rate of 8%, we divide 72 by 8: 72 / 8 = 9. Thus, it would take around 9 years for the savings to double at an interest rate of 8%.
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rewrite each sum in the form a(b+c) using the distributive property and the gcf 6+22
6 + 2 2 = 2 ( 3 + 11 )
60 + 25 = 5 ( 12 + 5 )
In a weighted grading system, students are graded on quizzes, tests, and a project, each with a different weight. Matrix W represents the weights for each kind of work, and matrix G represents the grades for two students, Felipe and Helena.
Q T P
W = [0.40 0.50 0.10] Felipe Helena
G= Q {80 70}
T {60 80}
p { 90 60}
Final grades are represented in a matrix F. If F = WG, what is F?
A. [7174]
B. [7174]
C. [7471]
D. [7471]
For Felipe and Helena's final grades, the solution is option C, [74 71].
How to calculate final grades?Using the given values for Q, T, and P weights and Felipe and Helena's grades, calculate their final grades as follows:
Felipe's final grade:
0.40 x 80 + 0.50 x 60 + 0.10 x 90 = 32 + 30 + 9 = 71
Helena's final grade:
0.40 x 70 + 0.50 x 80 + 0.10 x 60 = 28 + 40 + 6 = 74
To represent the final grades for Felipe and Helena in a matrix F, given formula F = WG, where W = matrix of weights and G = matrix of grades:
[0.40 0.50 0.10] [80 70]
F = WG = [0.40 0.50 0.10] x [60 80]
[0.40 0.50 0.10] [90 60]
Performing matrix multiplication:
[32 + 30 + 9 28 + 40 + 6]
F = WG = [32 + 40 + 6 28 + 40 + 3]
[36 + 25 + 6 36 + 20 + 3]
Simplifying:
[71 74]
F = WG = [78 71]
[67 59]
Therefore, [74 71] for Felipe and Helena's final grades, respectively.
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A store manager kept track of the number of newspapers sold each week over a seven-week period. The results are shown below. \( 87,87,215,154,288,235,231 \) Find the median number of newspapers sold.
The median number of newspapers sold over seven weeks is 223.
The median is the middle score for a data set arranged in order of magnitude. The median is less affected by outliers and skewed data.
The formula for the median is as follows:
Find the median number of newspapers sold. (87, 87, 215, 154, 288, 235, 231)
We'll first arrange the data in ascending order.87, 87, 154, 215, 231, 235, 288
The median is the middle term or the average of the middle two terms. The middle two terms are 215 and 231.
Median = (215 + 231)/2
= 446/2
= 223
In statistics, the median measures the central tendency of a set of data. The median of a set of data is the middle score of that set. The value separates the upper 50% from the lower 50%.
Hence, the median number of newspapers sold over seven weeks is 223.
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A model car is constructed with a scale of 1:15. If the actual car is 12 feet long, which proportion represents the length x of the model car?
The length of the model car based on the information is 0.8 feet.
What is scale?It should be noted that scale simply shows the relationship between a measurement on a model as well as the corresponding measurement on the actual object.
From the information, the model car is constructed with a scale of 1:15.
When the actual car is 12 feet long, the length of the model will be illustrated as x. This will be:
= 1/15 = x / 12
Cross multiply
15x = 1 × 12
15x = 12
Divide
x = 12 / 15
x = 0.8
The length is 0.8 feet.
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Naomi used a rectangle, a square, and a right triangle to form the following figure. What is the area of the shaded region of the figure in square centimeters?
Answer:
102cm²
Step-by-step explanation:
Step 1 find the area of the whole rectangle
Area of a rectangle = width times length
The width of the rectangle is 20 cm and the length is 6cm
So the area = 20 * 6
20 * 6 = 120
Hence the area of the rectangle is 120 square centimeters.
Step 2 Find the area of the square and the triangle
Area of square = s²
where s = side length
The square has a side length of 3 so the area of the square = 3²
3² = 9
Hence, the area of the square is 9cm²
Now to find the area of the triangle
area of a triangle = \(\frac{bh}{2}\) where b = base length and h = height
We are given the height (3 cm, this is given because the square is sharing it's side length with the height of the triangle.)
Now to find the base length
We can find it by subtracting the overall rectangle's width (20cm) by the bottom width (11 cm) and the bottom length of the square ( 3 cm )
so triangle's base length = 20 - 11 - 3
20 - 11 - 3 = 6
so the base length of the triangle is 6 cm
now we plug in the values of the height and the base length into the formula
\(A=\frac{6*3}{2} \\6*3=18\\\frac{18}{2} =9\)
Hence the area of the triangle is 9 cm²
Finally, to find the area of the shaded area, we subtract the area of the triangle and the area of the square from the area of the rectangle
so your answer = 120 - 9 - 9
120 - 9 - 9 = 102
Hence, the area of the shaded region is 102 square centimeters.