Convert 15°C to Fahrenheit. Use the formula F = C + 32

A. 33°F
B. 27°F
C. 85°F
D. 59°F

Answer:

-11/3, -2.25, -3/2, 0.5

Step-by-step explanation:

The completed Venn diagram is given below.

Given that, Regular pentagon 1, trapezium 2, parallelogram 3, rhombus 4, scalene triangle 5.

A Venn diagram is a diagram that helps us visualize the logical relationship between sets and their elements and helps us solve examples based on these sets. A Venn diagram typically uses intersecting and non-intersecting circles (although other closed figures like squares may be used) to denote the relationship between sets.

Here, regular pentagon and rhombus have rotational symmetry.

So, complete Venn diagram is given below.

Therefore, the completed Venn diagram is given below.

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Answer:

y=0.25x^2−2x

Step-by-step explanation:

You have to use the disruptive property.

First let's find how many kilometers the jeep traveled, by subtracting the odometer readings:

Now, to find the miles per gallon, we just need to divide the kilometers by the amount of gallons of gasoline:

So Harry got 17.8 miles per gallon with the Jeep.

Answer:

no it is(7,2)

Step-by-step explanation:

Given data

Area of a square = 64 square feet

To find the perimeter of a rectangle, you need the length of its sides.

You can find the length of a square from the area of the square given below.

Use the formula below to find the perimeter.

The perimeter of a square = 4L

= 4 x 8

= 32 feet

The length, width and height of the box for which the box has minimum cost is 400,000 cm, 200,000 cm, and 24,000 cm, respectively. The minimum cost of the box is $192,000.00.

Let the length be x cm and width be x/2 cm.

Therefore, the height h of the planter box would be:

h = 12,000/(x×(x/2))

We want to minimize the cost of the planter box, so the total cost would be:

Cost = (0.06×x²) + (0.04×4xh)

We need to minimize the cost of the planter box, so we must differentiate the cost expression with respect to x and set the differential expression to 0 to find the critical point that minimizes the cost.

dCost/dx = (0.06×2x) + (0.04×4h) = 0

⇒ x = -2h/0.12

Substituting this into the expression for h:

h = 12,000/((-2h/0.12)×((-2h/0.12)/2))

⇒ h = 24,000/h

From this, we can solve for h and find that h = 24,000 cm.

Therefore, the length of the planter box will be x = -48,000/0.12 = -400,000 cm and the width will be x/2 = -200,000 cm.

The minimum cost of the planter box will be:

Cost = (0.06×400,000²) + (0.04×4×24,000) = $192,000.00

Therefore, the length, width and height of the box for which the box has minimum cost is 400,000 cm, 200,000 cm, and 24,000 cm, respectively. The minimum cost of the box is $192,000.00.

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The values of the variables and numbers in radical form are presented as follows;

43a) x > -5

40a) a > 0

44b) x < 0

47e) x > 0

43b) x = The set of all real numbers

44a) The set of all numbers

45 a) x = 14

45 b) x = 0

45 c) x = -1

45 d) x = -4

45 e) x = 1

42 d)x = 5/196

9 e) x = 4

9 f) x = 8

9 a) √(0.6/36) ≈ 0.13

9 h) √((4 - 10)/(0.01)) = i·10·√6

A radical also known as a root is represented using the square root or nth root symbol and is the opposite of an exponent.

43 a) \(\sqrt{x + 5}\)

x + 5 > 0

Therefore, x > -5

40a) ∛a

a > 0

44b) √(-5·x)³

-5·x < 0

x < 0

47e) √(13 - (13 - 2·x))

(13 - (13 - 2·x)) > 0

13 > (13 - 2·x)

0 > -2·x

x > 0

43b) √|x| + 1

x = All real numbers

44 a) √(-2·x)²

√(-2·x)² = -2·x

x = Set of all numbers

45 a) √(x - 5) = 3

(x - 5) = 3² = 9

x = 9 + 5 = 14

45b) √(2·x + 4) = 2

2·x + 4 = 2²

2·x = 2² - 4 = 0

x = 0/2 = 0

45c) √(x·(x + 1)) = 0

(x·(x + 1)) = 0

(x + 1) = 0

x = -1

45 d) √(x + 5) = -1

(x + 5) = (-1)²

x + 5 = 1

x + 5 = 1

x = 1 - 5 = -4

x = -4

45e) √x + x² = 0

√x = -x²

(√x)² = (-x²)² = x⁴

x  = x⁴

1 = x⁴ ÷ x = x³

x = ∛1 = 1

x = 1

42d) \(\sqrt{\dfrac{5}{x} } +3= 17\)

\(\sqrt{\dfrac{5}{x} }= 17-3 =14\)

\(\dfrac{5}{x} }=14^2=196\)

\(x = \dfrac{5}{196}\)

9e) \(\sqrt{\dfrac{4}{x} } = 1\)

\(\dfrac{4}{x} } = 1^2\)

x × 1² = 4

x = 4

19f) ∛x - 2 = 0

∛x = 2

x = 2³ = 8

9a) \(\sqrt{\dfrac{0.6}{36} }\)

\(\sqrt{\dfrac{0.6}{36} }\) = \(\sqrt{\dfrac{1}{60} }= \dfrac{\sqrt{15}}{30} \approx 0.13\)

9h) \(\sqrt{\dfrac{4-10}{0.01} }\)

\(\sqrt{\dfrac{4-10}{0.01} }\)= √(-600) = √(-1)·√(600) = i·10·√6

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Answer:

You would multiply 30x15 to get 450miles per tank of gas.

Step-by-step explanation:

The description that most accurate for a Zero-Based Budget is:

b. You put every dollar of your take-home pay into a budget category each month.

A zero-based budget is a budgeting method in which your total income minus your total expenses equals zero. This means that every dollar of your income is assigned a specific purpose, either to be saved or spent on specific expenses. The goal of this method is to ensure that you have accounted for all of your income and that you do not have any leftover funds that are not allocated to a specific purpose. In this sense, option b, "You put every dollar of your take-home pay into a budget category each month" is the most accurate description of a zero-based budget.

A zero-based budget can be applied to any source of income, whether it be a salary, freelance work, rental income, or any other type of income. The key is to allocate every dollar of that income to a specific purpose, such as savings, expenses, or investments, to ensure that all of the income is accounted for. This budgeting method can help individuals and households to better manage their finances by ensuring that they are not overspending and that they have a plan for all of their income.

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Thus, the test for homogeneity follows the same procedures as the test for independence because the assumptions for performing the chi-square test for independence and chi-square test for homogeneity are the same.

The procedures for the chi-square test of homogeneity are the same as for the chi-square test of independence. The data is different for both tests. Tests of independence are used to determine whether there is a significant relationship between two categorical variables from the same population. One population is segmented based on the value of two variables. So there will be a column variable and a row variable.

The chi-square test of homogeneity of proportions can be used to compare population proportions from two or more independent samples, determining whether the frequency counts are distributed identically among different populations.

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Answer:

13 inches

Step-by-step explanation:

in an equilateral triangle all sides had we the same length.

so, the perimeter is simply 3×one triangle side.

and the perimeter of the square is 4×one square side.

x = triangle side length

y = square side length

3x = 4y + 15

x = y + 7

we use the second equation as substitution in the first equation.

3(y + 7) = 4y + 15

3y +21 = 4y + 15

6 = y

x = y + 7 = 6 + 7 = 13 inches

Answer:

the answer for 8) answer= 8

Answer:

4/12 = yellow

3/12 = purple

12/144 = yellow and purple

Step-by-step explanation:

the first two are pretty self explanitory. The last one requires you to multiply the answers of the first two together. Make sure you multiply both the top and the bottom (don't use common denominator here)

Answer:

The answer to this is the 3rd choice which is 1a) 4/12, 1b) 3/12, 1c) 12/144.

Step-by-step explanation:

This is pretty simple. To identify the probability of the yellow marbles, you can find the amount of yellow marbles and the total amount of marbles. You take it as a fraction which would be 4/12.

The total amount of marbles : 3 purple + 5 green + 4 yellow = 12 total marbles

The amount of yellow marbles : 4 yellow

Probability of yellow marbles : 4/12

To identify the probability of the yellow marbles, you can find the amount of purple marbles and the total amount of marbles. You take it as a fraction which would be 3/12.

The total amount of marbles : 3 purple + 5 green + 4 yellow = 12 total marbles

The amount of purple marbles : 3 purple

Probability of purple marbles : 3/12

To identify the probability of both the yellow and purple marbles, you can find the amount of yellow and purple marbles along with the total amount of marbles. Since we know this from the work above, you just need to multiply both probabilities. You take it as a fraction which would be 12/144.

The total amount of marbles : 3 purple + 5 green + 4 yellow = 12 total marbles

The amount of yellow marbles : 4 yellow

The amount of purple marbles : 3 purple

Probability of yellow marbles : 4/12

Probability of purple marbles : 3/12

Probability of both marbles : 12/144

Answer:

\(\frac{6}{5}\)

Step-by-step explanation:

1.Turn the 9 into a fraction

\(\frac{2}{15} *\frac{9}{1}\)

2.factor the bigger numbers.

\(\frac{2}{3*5} *\frac{3*3}{1}\)

3.Cancel out the common factor(3)

\(\frac{2}{5} * \frac{3}{1}\)

4.multiply across

\(\frac{2}{5} *\frac{3}{1} =\frac{6}{5}\)

Answer:

leg = 1

hypotenuse = √2 or 1.41

Step-by-step explanation:

Answer:

43.5 km/h

Step-by-step explanation:

speed= distance

               time

          =   87

               2

           = 43.5km/h

hope it helps

mark me as the brainliest

Answer:

One solution.

Step-by-step explanation:

This question has different coefficients so it has one solution.

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 578 yds

The statement

The length is one more than three times the width is written as

l = 1 + 3w

Substitute the expression into the above formula and solve for the width

That's

578 = 2(1 + 3w) + 2w

578 = 2 + 6w + 2w

8w = 576

Divide both sides by 8

w = 72

Substitute w = 72 into l = 1 + 3w

That's

l = 1 + 3(72)

l = 216 + 1

l = 217

Therefore the dimensions are

length = 217 yd

width = 72 yd

Hope this helps you

The triple integral of the divergence over the region E is equal to the surface integral of F over the boundary surface of E, we have verified the Divergence Theorem for the given vector field F and the region E.

To verify the Divergence Theorem, we need to compute both sides of the equation for the given vector field F and the region E bounded by the paraboloid Z = 4 - X^2 - y^2 and the xy-plane.

First, we compute the divergence of F:

div F = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z

= 4x + 2

Next, we compute the triple integral of the divergence over the region E:

∫∫∫E div F dV = ∫∫∫E (4x + 2) dV

Since the region E is bounded by the xy-plane and the paraboloid, we can integrate over z from 0 to 4 - x^2 - y^2, over y from -√(4 - x^2) to √(4 - x^2), and over x from -2 to 2:

∫∫∫E div F dV = ∫-2^2 ∫-√(4 - x^2)√(4 - x^2) ∫0^4-x^2-y^2 (4x + 2) dz dy dx

= 128/3

Now, we compute the surface integral of F over the boundary surface of E:

∫∫S F dS = ∫∫P F dP + ∫∫D F dD

where P is the surface of the paraboloid and D is the disk at the bottom of E.

On the paraboloid, the normal vector is given by n = (∂f/∂x, ∂f/∂y, -1), where f(x,y) = 4 - x^2 - y^2. Therefore, we have:

∫∫P F dP = ∫-2^2 ∫-√(4 - x^2)√(4 - x^2) (2x^2, 2xy, 4 - x^2 - y^2) ∙ (∂f/∂x, ∂f/∂y, -1) dA

= ∫-2^2 ∫-√(4 - x^2)√(4 - x^2) (2x^2, 2xy, 4 - x^2 - y^2) ∙ (2x, 2y, 1) dA

= 16π/3

On the disk at the bottom, the normal vector is given by n = (0, 0, -1). Therefore, we have:

∫∫D F dD = ∫-2^2 ∫-√(4 - x^2)√(4 - x^2) (2x^2, 2xy, 0) ∙ (0, 0, -1) dA

= 0

Thus, we have:

∫∫S F dS = ∫∫P F dP + ∫∫D F dD = 16π/3 + 0 = 16π/3

Since the triple integral of the divergence over the region E is equal to the surface integral of F over the boundary surface of E, we have verified the Divergence Theorem for the given vector field F and the region E.

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The total surface integral is:

∫∫S F dS = ∫∫S F dS + ∫∫S F dS

= 8π/3 + 0

= 8π/3

To verify the Divergence Theorem, we need to show that the triple integral of the divergence of F over the region E is equal to the surface integral of F over the boundary of E.

First, let's compute the divergence of F:

div F = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z

= 4x + 2y + 3

Next, we'll compute the triple integral of div F over E:

∭E div F dV = ∫∫∫ (4x + 2y + 3) dz dy dx

The region E is bounded by the paraboloid Z = 4 - X^2 - y^2 and the xy-plane. To determine the limits of integration, we need to find the intersection of the paraboloid with the xy-plane:

4 - x^2 - y^2 = 0

x^2 + y^2 = 4

This is the equation of a circle with radius 2 centered at the origin in the xy-plane.

So, the limits of integration are:

x: -2 to 2

y: -√(4 - x^2) to √(4 - x^2)

z: 0 to 4 - x^2 - y^2

∭E div F dV = ∫∫∫ (4x + 2y + 3) dz dy dx

= ∫-2^2 ∫-√(4-x^2)^(√(4-x^2)) ∫0^(4-x^2-y^2) (4x + 2y + 3) dz dy dx

= 32/3

Now, let's compute the surface integral of F over the boundary of E. The boundary of E consists of two parts: the top surface of the paraboloid and the circular disk in the xy-plane.

For the top surface of the paraboloid, we can use the upward-pointing normal vector:

n = (2x, 2y, -1)

For the circular disk in the xy-plane, we can use the upward-pointing normal vector:

n = (0, 0, 1)

The surface integral over the top surface of the paraboloid is:

∫∫S F dS = ∫∫D F(x, y, 4 - x^2 - y^2) ∙ n dA

= ∫∫D (4x + 2y, 2xy, 4 - x^2 - y^2) ∙ (2x, 2y, -1) dA

= ∫∫D (-4x^2 - 4y^2 + 4) dA

= 8π/3

The surface integral over the circular disk in the xy-plane is:

∫∫S F dS = ∫∫D F(x, y, 0) ∙ n dA

= ∫∫D (2x^2, 2xy, 0) ∙ (0, 0, 1) dA

= 0

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The zeroes of polynomial are 43/5 and -3/4.

We have,

4 (3x-2)² -3 (3x-2) (x+5) - 7(x+5)²

simplifying the above expression we get

4 (9x² + 4 -12x ) -3 (3x² + 15x - 2x - 10) - 7(x² + 25 + 10x)

= 36x² - 48x + 16 - 9x² -39x + 30 - 7x² - 175 - 70x

= 20x² -157x -129

Now, solving the quadratic equation we get

x = 43/5 and x= -3/4

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Answer:

Step-by-step explanation:

It is actually fairly simple; just multiple the percentage by the total students, 10.

Cat, Dog: 10% of 10 is 1.

Cat, No Dog: 30% of 10 is 3.

Cat Total: 1+3 = 4.

No Cat, Dog: 40% of 10 is 4.

No Cat, No Dog: 20% of 10 is 2.

No Cat Total: 4+2 = 6.

Dog Total: 4+1 = 5.

No Dog Total: 3+2 = 5.

The cosine form of the function 10sin(wt - 40)  is 10cos(wt - 50).

The cosine form of the function 10sin(wt - 40) can be found using the identity sin(x - y) = sin(x)cos(y) - cos(x)sin(y).

By applying this identity to the given function, we can rewrite it in terms of cosine.

10sin(wt - 40) = 10(sin(wt)cos(40) - cos(wt)sin(40))

Now, we can use the fact that cos(90 - x) = sin(x) and sin(90 - x) = cos(x) to further simplify the expression.

10(sin(wt)cos(40) - cos(wt)sin(40)) = 10(sin(wt)sin(50) + cos(wt)cos(50))

Finally, we can use the identity cos(x + y) = cos(x)cos(y) - sin(x)sin(y) to rewrite the expression in terms of cosine.

10(sin(wt)sin(50) + cos(wt)cos(50)) = 10cos(wt - 50)

Therefore, the cosine form of the function 10sin(wt - 40) is 10cos(wt - 50).

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The correct option: B. 3/x=x/11. is the proportion used to determine the the value of x.

For the stated question:

The pair of sides x and 11 : as well as 3 and x are used to find the proportion.

Thus,

3/x = x/11

It is the correct relation to find the value of x.

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The coordinates of C are (-6, -3)

From the question, we have the following parameters that can be used in our computation:

A = (-9, -5)

B = (6, 5)

m : n = 1 : 4 i.e. 1/5

The coordinate is then calculated as

C = 1/(m + n) * (mx2 + nx1, my2 + ny1)

So, we have

C = 1/5 * (1 * 6 + 4 * -9, 1 * 5 + 4 * -5)

Evaluate

C = (-6, -3)

Hence, the coordinate is (-6, -3)

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Answer:

95

Step-by-step explanation:

The values of the function y=x²-4x+11 is x=2±√-7

You should recall that a Quadratic equations are second-degree algebraic expressions and are of the form ax2 + bx + c = 0.

The given expression is y=x²-4x+11

by completing the square method

x²-4x=-11

Complete the squares on both sides

x²-4x+4=-11+4

(x²-2x) -(2x+4)=-11+4

x(x-2)-2(x-2) =-7

(x-2)² = -7

x-2 = ±√-7

Therefore the value of x=2±√-7

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Answer:

The car will travel approximately 13200  inches

Step-by-step explanation:

Notice that in one revolution, the car travels exactly the length of the tire's circumference, that is: \(2\,\pi\,R\)

Then, in 200 revolutions the car will travel 200 times that amount:

\(200\,(2\,\pi\,R)=400\ \pi\,R\)

So for the given dimension of the tire, and using the approximation \((\pi\approx22/7)\), this distance would be:

\(400\ \pi\,R=400\,\,\frac{22}{7} \,\,10.5\,\,in=13200\,\,in\)

The side lengths of the triangle are CA = 42.0 and BC = 36.4

From the question, we have the following parameters that can be used in our computation:

The triangle

Using the tangent rratio, we have

tan(60) = BC/21

So, we have

BC = 21 * tan(60)

Evaluate

BC = 36.4

Next, we have

CA = √[36.4^2 + 21^2] -- pythagoras theorem

Evaluate

CA = 42.0

Hence, the side lengths are CA = 42.0 and BC = 36.4

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